If the perimeter of the regular hexagon equals to the perimeter of an equilateral triangle then the area of the hexagon is 18.
A hexagon can be be known as a polygon that has six sides and angles. Regular hexagons have six equal sides and angles and are composed of six equilateral triangles. first we have to write down the formula for finding the area of a hexagon if you know the side length. Since a regular hexagon is comprised of six equilateral triangles, the formula for finding the area of a hexagon is derived from the formula of finding the area of an equilateral triangle.
Let a be the side of equilateral triangle ∴ [tex]\sqrt{3}[/tex] /4 [tex]a^{2}[/tex] = 12
Perimeter of triangle = 3a = Perimeter of Hexagon
3a=6h ,where h is the side of hexagon.
⇒ h = 1/2 a
The area of the hexagon =6× [tex]\sqrt{3}[/tex]/4 [tex]h^{2}[/tex]
=6× [tex]\sqrt{3}[/tex]/4 . ( a/2 ) 2 = 6/4 ×12
= 18
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The Sports Boosters are selling souvenir cups at the school football games to raise money for new uniforms. Each souvenir cup sells for $2.25. At the first game, the Boosters collected $123.75 from souvenir cups sales. How many cups were sold at the first game?
The number of cups sold at the first game is 55.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
Cost of each souvenir = $2.25
The total amount collected from the souvenir cups sales = $123.75
The number of cups sold at the first game.
= 123.75/2.25
= 55
Thus,
The number of cups sold is 55.
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A bag of marbles contains only yellow and purple marbles. The number of yellow marbles is five times as the purple marbles. The bag contains 138 total marbles. develop a system of equations to represent the situation, determine how many of each color of marble is in the bag
show how you checked your answers
Answer:
23 purple marbles
115 yellow marbles
Step-by-step explanation:
Let y represent the yellow marble
Let p represent the purple marbles
So, we have the equations
y = 5p
Therefore, y + p = 138
5p + p = 138
6p = 138
p = 23 marbles
Now let's put 23 in for the p in the equation to find the number of yellow marbles
y = 5(23)
y = 115 marbles
Noel old 4 carved wooden block at a local fair, earning a total profit of $26. He plan to ell 22 block during the fair. If he ell all the block, how much profit can Noel expect to earn? $
Noel can expect to earn a total profit of $572 if he sells all 22 blocks at the fair. Profit is an important measure of the financial performance of a business.
Profit is the amount of money that is gained from a business activity after all expenses have been paid. It is calculated by subtracting the costs of producing or acquiring a product or service from the revenue generated by selling that product or service.
To find the total profit that Noel can expect to earn from selling all 22 blocks, we need to multiply the profit from each block by the number of blocks he plans to sell.
We can use the following equation to calculate the total profit:
Total profit = Profit per block x Number of blocks
Plugging in the values we know, we get:
Total profit = $26 x 22 = $<<26*22=572>>572
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Find u•v where theta is the angle between u and v
Answer:
88√2 = 124.5 (nearest tenth)
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{6 cm}\underline{Dot Product of two vectors}\\\\$a \cdot b=|a||b| \cos \theta$\\\\where:\\ \phantom{ww}$\bullet$ $|a|$ is the magnitude of vector a. \\ \phantom{ww}$\bullet$ $|b|$ is the magnitude of vector b. \\ \phantom{ww}$\bullet$ $\theta$ is the angle between $a$ and $b$. \\ \end{minipage}}[/tex]
Given:
[tex]|u| = 8[/tex][tex]|v| = 22[/tex][tex]\theta =\dfrac{\pi}{4}[/tex]Substitute the given values into the dot product formula:
[tex]\begin{aligned}\implies u \cdot v &=|u||v| \cos \theta\\\\&=8 \cdot 22 \cdot \cos \left(\dfrac{\pi}{4}\right)\\\\&=176 \cdot \dfrac{\sqrt{2}}{2}\right)\\\\&=88\sqrt{2}\\\\&=124.5\; \sf (nearest\;tenth)\end{aligned}[/tex]
Find the value of x. A B D E C i an irregular pentagon with parallel ide A B and C E. Angle A B D meaure 104 degree. Angle C E D meaure 28 degree. Angle B D E meaure x degree
Angle B D E measure 228 degrees in the irregular pentagon A B D E C.
Polygons that lack equal sides and angles are referred to as irregular polygons. Polygons that are irregular are not regular, in other words. Closed two-dimensional shapes known as polygons are created by connecting three or more line segments. Regular and irregular polygons are two different forms of polygons.
As we know, the Sum of the interior angles of an irregular polygon =
(n − 2) × 180°
{ 'n' = the number of sides of a polygon.}
As given, A B D E C is a pentagon, so
n= 5
The sum of interior angles=
3 X \180= 540
As AB and CE are parallel to each other:
angle BAC=y
angleECA= 180-y
=>the sum of interior angles:
104+x+28+180-y+y= 540
104+x+28+180=540
x+312=540
=> x=228
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Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is bounded by y = 1 − x2 and y = 0; rho(x, y) = 7ky
The mass and center of mass of the lamina is [tex]\frac{8}{15} k, (0, \frac{4}{7} )[/tex]
The mass of a homogenous lamina is given by [tex]$m=\iint_R \delta(x, y) d A$[/tex]
We can rewrite the equation using the limits of integration as [tex]$$m=\int_a^b \int_c^d \delta(x, y) d y d x$,[/tex] where a ≤ x ≤ b and c ≤ y ≤ d.
The objective is to find the mass and center of mass of the lamina that occupies the region D.
From the given equations, we get the limits of integration as -1 ≤ x ≤ 1 and 0 ≤ x ≤ 1-[tex]x^{2}[/tex]. Substitute the known values in the equation.
[tex]$$\begin{aligned}& m=\int_{-1}^1 \int_0^{1-x^2} k y d y d x \\& =\int_{-1}^1 \frac{1}{2} k\left(1-x^2\right)^2 d x \\& =\frac{1}{2} k \int_{-1}^1\left(1+x^4-2 x^2\right) d x \\& =\frac{k}{2}\left[x+\frac{x^5}{5}-2 \frac{x^3}{3}\right]_{-1}^1 \\\\\end{aligned}$$[/tex]
[tex]& =\frac{k}{2}\left[1+\frac{1}{5}-\frac{2}{3}+1+\frac{1}{5}-\frac{2}{3}\right] \\\\& =\frac{k}{2}\left[\frac{16}{15}\right] \\\\& =\frac{8}{15} k[/tex]
Hence, the mass of the lamina as [tex]\frac{8}{15} k[/tex].
The center of mass of the lamina is given by[tex]$(\bar{x}, \bar{y})$[/tex], where [tex]$$\begin{gathered}\bar{x}=\frac{1}{m} \iint_R x \delta(x, y) d A \text { and } \\\bar{y}=\frac{1}{m} \iint_R y \delta(x, y) d A .\end{gathered}$$[/tex]
First, find [tex]$\bar{x}$[/tex] as follows:
[tex]$$\begin{aligned}\bar{x} & =\frac{1}{\frac{8}{15} \mathrm{k}} \int_{-1}^1 \int_0^{1-x^2} k x y d y d x \\& =\frac{1}{\frac{8}{15} \mathrm{k}} \int_{-1}^1 \frac{1}{2} k x\left(1-x^2\right)^2 d x \\= & \frac{15}{8 k} \cdot \frac{k}{2} \int_{-1}^1 x\left(1+x^4-2 x^2\right) d x \\= & \frac{15}{16}\left[\frac{x^2}{2}+\frac{x^6}{6}-2 \frac{x^4}{4}\right]_{-1}^1 \\= & 0\end{aligned}$$[/tex]
Thus, the [tex]$\bar{x}$[/tex]-coordinate of the center of gravity as 0 .
Now, evaluate [tex]$\bar{y}$[/tex].
[tex]& \bar{y}=\frac{1}{\frac{8}{15}} \int_{-1}^1 \int_0^{1-x^2} k y^2 d y d x \\\\& =\frac{1}{\frac{8}{15}} \int_{-1}^1 \frac{1}{3} k\left(1-x^2\right)^3 d x \\\\& =\frac{15}{8 k} \cdot \frac{k}{3} \int_{-1}^1\left(1-x^6-3 x^2+3 x^4\right) d x \\\\& =\frac{15}{24}\left[x-\frac{x^7}{7}-3 \frac{x^3}{3}+3 \frac{x^5}{5}\right]_{-1}^1 \\\\& =\frac{15}{24} \times \frac{32}{35} \\\\& =\frac{4}{7}[/tex]
Hence, the center of gravity of the lamina is ([tex]0, \frac{4}{7}[/tex]).
Therefore, the mass and center of mass of the lamina that occupies the region D is [tex]\frac{8}{15} k[/tex], [tex](0, \frac{4}{7} )[/tex]
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the figure(figure 1) shows the acceleration graph for a particle that starts from rest at t = 0s.
a) The velocity of particle at t=2s is 5m/s
b) The velocity of particle at t=4s is 20m/s
To obtain the function of velocity from the graph we need to find the equation of accleration- time graph
so the equation of accleration is :
a= [tex]\frac{10-0}{4-0}[/tex]t
a= 5/2t
and we know that :
a= [tex]\frac{dv}{dt}[/tex]
=> dv= adt
=> dv= [tex]\frac{5}{2}[/tex] t dt
integrating both side we get:
v= [tex]\frac{5}{4}[/tex][tex]t^2[/tex] +c
where c is constant
it is given that at t=0s it starts from rest so
v=0 at t=0
=> 0 = 0+c
=>c=0
so v=[tex]\frac{5}{4}t^2[/tex] ---- (i)
a) as we have got the equation of velocity with respect to time
we have to find velocity at t=2s
putting t=2s we get
v = 5/4 *4
so velocity of particle at t=2s is 5m/s
b) as we have got the equation of velocity with respect to time
we have to find velocity at t=4s
putting t=4s we get
v = 5/4 *16
so velocity of particle at t=2s is 20m/s
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equation of simple straight line
Complete question:
the figure shows the acceleration graph for a particle given that particle starts from rest at t=0.
determine the velocity of partice at
a)2s
b)4s
Pete was building a doghouse for his dog, Chip. He made the door 36 inches tall. The height of the door was twice the height of the window in the doghouse.
Write an equation to determine the height of the window.
36 = 2h
36 = 2 + h
36 = h − 2
36 equals h over 2
Answer:
36 = 2h
Step-by-step explanation:
Here h represents the heigh
We know that the height of the door was twice the height of the window so that the equation will be
36 = 2h
Wyatt' Ga Mileage
\text{Gallon (\(x\))}Gallon (x) \text{Mile (\(y\))}Mile (y)
55 153153
77 214. 2214. 2
1010 306306
1414 428. 4428. 4
How much farther can Camden' car travel on one gallon of ga than Wyatt' car?
Both automobiles' lines have the equation "y = 3x," and their respective gas mileage is 3 miles per gallon. Wyatt's automobile gets more miles per gallon of gas than Camden's vehicle does.
We must compute the mileage (the distance driven per gallon of fuel) for each automobile using the provided information to determine the difference between the ranges of travel for Camden's and Wyatt's vehicles.
We can determine the miles for Wyatt's automobile using the data points (5, 15) and (7, 21). The equation for the slope of the line connecting these two locations is
(y2 - y1) / (x2 - x1) = (21 - 15) / (7 - 5) = 6/2 = 3
"Y = mx + b" is the equation for the line connecting these two points, where m denotes the line's slope and b its y-intercept. We may determine the equation of the line by adding the values of m as well as the dimensions of one of the endpoints into this equation:
y = 3x + b
15 = 3(5) + b
15 = 15 + b
0 = b
"Y = 3x" is the equation for the line passing thru the points (5, 15) and (7, 21).
We can determine the miles for Camden's automobile using the data points (10, 30) and (14, 42). The equation for the slope of the line connecting these two locations is
(y2 - y1) / (x2 - x1) = (42 - 30) / (14 - 10) = 12/4 = 3
"Y = mx + b" is the equation for the line connecting these two points, where m denotes the line's slope and b its y-intercept. We may determine the equation of the line by incorporating the values of m as well as the dimensions of one of the endpoints into this equation:
y = 3x + b
30 = 3(10) + b
30 = 30 + b
0 = b
"Y = 3x" is the equation for the line passing through the points (10, 30) & (14, 42).
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The question is -
Computes the miles per gallon of your car via the miles traveled and the number of gallons used. Also, if you enter the cost per gallon and how many miles you drive a day, it will estimate your monthly and yearly gas expenses with data points (5, 15) and (7, 21).
This equation has one solution. 5(x – 1) 3x = 7(x 1) what is the solution?
Answer:
send the complete question . there are some missing signs .
The area of the square in the figure below is 16 square inches. Solve for "s", the length of one side. Explain
the solution.
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▪️▪️▪️▪️
▪️▪️▪️▪️
Area = 16 in²
A=S²
A=16
s²=16
Answer:
4
Step-by-step explanation:
[tex]\sqrt{16}[/tex] = 4
The side lengths of the square is 4.
Area = Length times width
Area = 4 x 4
Are = 16
A(-5,1) B(-2,4) C(1,-1)
Translate the triangle 4 units left and 6 units up. PLSSS HELP ME THANK YOU
The triangle after translation will have coordinates A'(-9, 7), B'(-6, 10) and C'(-3, 5)
What are transformations?A transformation is a process that manipulates a polygon or other two-dimensional object on a plane or coordinate system.
Given that, a triangle A(-5,1) B(-2,4) C(1,-1) is being translated 4 units left and 6 units up
To translate the point P(x, y), a units left and b units up, use P'(x-a, y+b).
Therefore, coordinates for A'B'C' are =
A(-5, 1) = A'(-5-4, 1+6) = (-9, 7)
B(-2, 4) = B'(-2-4, 4+6) = (-6, 10)
C(1, -1) = C'(1-4, -1+6) = (-3, 5)
Hence, The triangle after translation will have coordinates A'(-9, 7), B'(-6, 10) and C'(-3, 5)
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a rectangular storage container without a lid is to have a volume of 10 m3. the length of its base is twice the width. material for the base costs $15 per square meter. material for the sides costs $9 per square meter. let w denote the width of the base.
The total cost is $245.31.
Given,
Volume = 10[tex]m^{3}[/tex]
Width = w
Length = 2w
Base area = Length x Width = [tex]2w^{2}[/tex]
Cost of base = $15
Cost of sides = $9
Since the volume is 10[tex]m^{3}[/tex],
Volume = Base Area x Height
Height = [tex]\frac{10}{2w^{2} }[/tex] = [tex]\frac{5}{w^{2} }[/tex]
Cost of making such a container:
Cost of base = [tex]2w^{2}[/tex] x 15 = $[tex]30w^{2}[/tex]
Cost of sides = [(2 x 2w x [tex]\frac{5}{w^{2} }[/tex]) + (2 x w x [tex]\frac{5}{w^{2} }[/tex])] x $9 = $[tex]\frac{270}{w}[/tex]
Overall Cost = Cost of Base + Cost of Sides
f(x) = [tex]30w^{2} + \frac{270}{w}[/tex] = [tex]30(w^{2} + \frac{9}{w})[/tex]
To get the minimum cost, we will have to find the derivative of f(x) and equate it to zero.
d(f(x))/dx = 0
[tex]2w - \frac{9}{w^{2} } = 0\\w^{3} = 4.5 \\w = 1.651m[/tex]
Putting the value of w in f(x),
f(x) = $245.31 (after calculations)
Therefore, the final answer is $245.31.
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sum of two numbers is -11/12 ,one of them is 9/2, find the other
pls answer fasttttttt!!!!
plssssssssssssssssssssssssssssss.
step by step
Answer:
- [tex]\frac{65}{12}[/tex]
Step-by-step explanation:
let the number to be found be n , then
n + [tex]\frac{9}{2}[/tex] = - [tex]\frac{11}{12}[/tex]
multiply through by 12 ( the LCM of 2 and 12 ) to clear rhe fractions
12n + 54 = - 11 ( subtract 54 from both sides )
12n = - 65 ( divide both sides by 12 )
n = - [tex]\frac{65}{12}[/tex]
let r(x) = f(g(x)) and s(x) = g(f(x)), where f and g are shown in the figure. find r'(1) and s'(4).
The value of r'(1) and s'(4) is 0 that can be interpreted with the help of the graph that is given in the question.
Derivative in mathematics, the rate of change of a characteristic with recognize to a variable. Derivatives are essential to the answer of troubles in calculus and differential equations. The essence of calculus is the by-product. The by-product is the immediately price of extrade of a characteristic with recognize to certainly considered one among its variables. This is equal to locating the slope of the tangent line to the characteristic at a point
[tex]r(x) = f(g(x))[/tex]therefore the derivative of r is given by [tex]r'(x) = f'g(x)\times g'(x)[/tex]
[tex]r'(1) = f'(g(1))\times g'(1)[/tex] from the graphs
r'(1) = f'4 \times g'1 = (5/4) \times(0) = 0
Similarly s'(1) = g'(f(1))\times f'(1) from the graphs
f(1)=1.5, f'(1)
=\dfrac{ (3-0)}{(0-2)}
= -3/2 , g'(3/2) = 0
s'(4) = g'(3/2) \times f'(4) = 0(-1.5) = 0
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Complete question:
let r(x) = f(g(x)) and s(x) = g(f(x)), where f and g are shown in the figure. find r'(1) and s'(4).
What is the domain of this function?
f(x) = ²x - 3| + 1 ?
Answer: A.
Step-by-step explanation:
Most of the function f(x) has a domain (- infinity, positive infinity), and the function in the picture is the same. So, the answer is A
the margin of error of a confidence interval is the error from biased sampling methods. t or f
False. The margin of error only accounts for sampling variability (the fact that my sample will be different that many other people's and therefore provide different statistics.
What are statistics and their various forms?Statistics is a technique for interpreting, analyzing, and summarizing data in mathematics. In light of these characteristics, the various statistical types are divided into: Statistics that are descriptive and inferential. We analyze and understand data based on how it is presented, such as through graphs, bar graphs, or tables.
What are the two primary statistical methods?Inferential statistics, which draws conclusions from information using statistical tests like the student's t-test, is one of the two main statistical methods used in data analysis. Descriptive statistics presents data using indices like mean and median.
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please help will give brainliest
The given polygon IJKL is a rectangle. Therefore, option C is the correct answer.
Given that, the polygon IJKL if IJ≅KL, JK≅LI, IJ⊥JK, JK⊥KL, KL⊥LI and LI⊥IJ.
What is a rectangle?A rectangle is a closed two-dimensional figure with four sides. The opposite sides of a rectangle are equal and parallel to each other and all the angles of a rectangle are equal to 90°.
Here, the opposite sides IJ and KL are equal and the opposite sides JK and LI are equal.
Since, all the sides are perpendicular to each other makes an angle 90°
The given polygon IJKL is a rectangle. Therefore, option C is the correct answer.
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Chri want to order DVD over the internet. Each DVD cot $15. 99 and hipping the entire order cot $9. 99. If he can pend no more than $100 , how many DVD could be buy?
Chris can only buy a maximum of 5 DVDs.
What is a division?
The division is a mathematical operation that involves dividing one number (the dividend) by another number (the divisor) to find the quotient. It is represented by the symbol "/" or "÷".
To determine how many DVDs Chris can buy, we need to subtract the cost of shipping from the total amount of money Chris has available and then divide the remaining amount by the cost of each DVD.
First, we subtract the cost of shipping from the total amount of money Chris has available:
$100 - $9.99 = $90.01
Then, we divide the remaining amount by the cost of each DVD:
$90.01 / $15.99 = 5.63
Chris can buy 5 DVDs.
Hence, Chris can only buy a maximum of 5 DVDs.
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(6)/(a^(2))+(5a^(-2))/(3^(-3))
Answer:
[tex]\frac{141}{a^{2} }[/tex]
Step-by-step explanation:
[tex]\frac{6}{a^{2} } + \frac{5a^{-2} }{3^{-3} }[/tex]
[tex]\frac{141}{a^{2} }[/tex]
How do I find the missing side of a triangle ?
Answer: 1. Given two sides
If leg a is the missing side, then transform the equation to the form where a is on one side and take a square root: a = √(c² - b²)
If leg b is unknown, then: b = √(c² - a²)
For hypotenuse c missing, the formula is: c = √(a² + b²)
Planes Q and R are parallel planes. Plane Q contains line a. Plane R contains line b.
Planes Q and R are parallel. Plane Q contains line a and plane R contains line b. Both lines are going the same direction.
If a third plane could be drawn which contains both lines a and b, then
lines a and b must be parallel.
lines a and b cannot be parallel.
lines a and b must be skew.
lines a and b must be perpendicular.
Answer:
lines a and b must be parallel
Answer:(A)
Step-by-step explanation:edge
which of the following is a constant in a mathematical model? a) decision variable. b) parameter. c) objective function. d) constraint. e) none of the answer choices are correct.
Answer:
b). parameter
Step-by-step explanation:
A parameter is a fixed value in the model that is not a decision variable and is not changed during the optimization process. It is used to represent known quantities that are used in the model but are not being optimized. For example, in a linear programming model, the cost of a product may be represented by a parameter, as the cost is not a decision variable and is fixed.
all the sides of a triangle are integers, and the perimeter is 12. how many different possible triangles are there
3 such difference triangle are possible when the perimeter of a triangle 12cm. if the lengths of the three sides are all integers (in cm).
Given that,
The perimeter of a triangle 12cm.if the lengths of the three sides are all integers (in cm).
We have to find how many such difference triangle are possible.
We know that,
Perimeter of the triangle is 12cm.
p=12
a+b+c=12
a+b≥c
b+c≥a
So,
a+b+c≥2c
12≥2c
c≤6
So,
a≤6,b≤6,c≤6
We get,
a=6,b=3,c=3
a=5,b=4,c=3
a=4,b=4,c=4
Therefore, 3 such difference triangle are possible when the perimeter of a triangle 12cm. if the lengths of the three sides are all integers (in cm).
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Jayden’s family has completed 90% percent of the trip. They have traveled 75 miles. How far is the trip?
Answer:
[tex]83\frac{1}{3} miles[/tex]
Step-by-step explanation:
90/100=75/x
90x=100(75)
90x=7500
/90. /90
x=83 1/3 miles
Hopes this helps
1) The domain of a function can BEST be described as which of the following:
a) The set of all y-coordinates
b) The set of all x-coordinates
d) The x-intercepts of one of the functions
c) Where the graph of the two
functions meet
Answer: b) The set of all x-coordinates
Step-by-step explanation:
In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figure.
active attachment
The perimeter of the given composite figure is; 5¹/₂ cm
How to find the perimeter of the composite figure?
To get the perimeter of the given composite figure, what we will do is to dd up the given segment side lengths and we are given the following;
AE + DC = 1¹/₅ cm
AB = 1 ³/₄ cm
DE = 1 ¹/₄ cm
BC = 1 ³/₁₀ cm.
Thus, we can say that the Perimeter is;
Perimeter = AE + DE + DC + BC + AB
Perimeter = (AE + DC) + DE + BC + AB
= 1¹/₅ + 1 ¹/₄ + 1 ³/₁₀ + 1 ³/₄
= (1²/₁₀ + 1³/₁₀) +(1¹/₄ + 1³/₄)
= 2⁵/₁₀ + 3
= 5¹/₂ cm
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what is the entire surd for 8 root 2
what is the entire surd of 5 root 9
what is the entire surd of 6 root 5
what is the entire surd of 3 root 13
help its urgent!!
The entire surds are √128, √225,√180, √117 respectively
What is an entire surd?An entire surd is a surd in which the entire number is under the root sign.
Given here are 8√2,5√9,6√5,3√13
thus their entire roots are 8√2 =√2×64
= √128
again, 5√9 = √9×25
= √225
6√5=√5×36
= √180
Similarly 3√13= √117
Hence, the respective entire surds are √128, √225,√180, √117
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Please help me respond these two questions!!
The score of the 60th percentile on the test is 84.
What is a percentile?The definition of percentile is the percentage that a certain percentage falls beneath. Ben is the fourth-tallest child in a group of 20 kids, whereas 80% of the kids are shorter than you.
Given:
58, 64, 66, 70, 71, 75, 77, 80, 84, 85, 87, 90, 93, 95, 96
Calculate the percentile of score 71 as shown below,
[tex]Percentile = n / N \times 100[/tex]
Here, n is the number of scores below the score of 60th percentile and N is the total number of scores,
60 = n / 15 × 100
n / 15 = 60 / 100
n = 0.6 × 15
n = 9
Thus, the 9th term = 84 is the score of the 60th percentile,
Therefore, the score of the 60th percentile on the test is 84.
To know more about percentile:
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natalie is the creator of better brain, a new mindfulness app for teens. the app currently has 1,262 downloads, and natalie has set a goal of doubling the downloads every month. write an exponential equation in the form y
Answer:
1262(2)^x
Step-by-step explanation: