What is the gradient of the graph shown?

What Is The Gradient Of The Graph Shown?

Answers

Answer 1

Answer:

1

Step-by-step explanation:

What Is The Gradient Of The Graph Shown?

Related Questions

What is the approximate value of x in the diagram below? (Hint: You will need
to use one of the trigonometric ratios given in the table.)

Answers

Answer:

B. 39.59

Step-by-step explanation:

So 43 degrees, you know the length of the opposite side (27) and the angle (43 degrees), the only unknown is the hypotenuse. So you're looking for a trigonometric ratio that uses the angle (all of them do, except technically the inverse don't), the opposite side, and the hypotenuse. Sine is defined as [tex]\frac{opposite}{hypotenuse}[/tex]. So let's plug in known values:

[tex]sin(43) = \frac{27}{x}[/tex]

Multiply both sides by x

[tex]sin(43) * x = 27[/tex]

divide both sides by sin(43)

[tex]x=\frac{27}{sin(43)}[/tex]

Normally I would use a calculator, but in this case I'll use the approximation given in the problem of 0.682

[tex]x=\frac{27}{0.682}[/tex]

simplify the fraction

[tex]x\approx39.59[/tex]

Please answer with everything needed i appreciate everyones help:)

Answers

Answer:

at 5 mins Holly traveled 2 miles. At 10 mins Holly traveled 4 miles. from there on she stayed there for 10 mins then went on her way. At 30 mins she traveled 5 1/2 miles. when she hit 35 mins she hit her destination then went back home.

Step-by-step explanation:

pretty simple

Population dynamics must consider the number of individuals that are lost per unit of time, also called the

Answers

Population dynamics must consider the number of individuals that are lost per unit of time, also called the mortality rate.

Mortality, or mortality, is a measure of the number of deaths (generally or due to a particular cause) in a particular population, scaled to the size of that population per unit of time.

The relative incidence of deaths in a particular population over a particular time period. Often expressed as the rate of human deaths or wildlife deaths from environmental hazards during a public health crisis. The highest mortality rate for patients over the age of 80 was during the last flu season.

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Name the marked angle in 2 different ways

Answers

The 2 different angles you can name are <UVT and <VST. Hope this helps and please mark brainlist

is 6x^5 + 3x^4 + 1^3
a fifth-degree polynomial with three terms in standard form

Answers

The statement is true, it is a polynomial of degree 5 with 3 terms.

Is the statement true?

A polynomial is of the form:

[tex]p(x) = a_n*x^n + ... + a_0[/tex]

Where the degree is the maximum exponent of the polynomial, in this case, is n.

The given polynomial is:

[tex]p(x) = 6x^5 + 3x^4 + x^3[/tex]

So, the maximum exponent is 5, which means that the degree of the polynomial is 5.

And it has 3 terms, so the statement is true.

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A shop sold white, pink and red T-shirts. 24% of the T-shirts were white. There were 198 more pink than white T-shirts. The remaining 114 T-shirts were red. How many pink T-shirts were there

Answers

Number of pink T-shirts was 342

How to solve it?

Given: 24% of the T-shirts were white

Let, total number of T-shirts be x

According to question,

Total number of white T-shirts = 24x/100

Total number of pink T-shirt =  24x/100+ 198

Total number of red T-shirts = 114

According to the question:

24x/100+24x/100+ 198 + 114 = x

312 = x - 48x/100

312 = 52x/100

x = (312*100)/52

x = 600

so Number of pink T-shirts :

=(24*600)/100+198

= 144 + 198

= 342

Hence total Number of pink T-shirts was 342.

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Can't seem to solve this one

Answers

Answer:

.88

Step-by-step explanation:

[tex] \sqrt{.7775} = .88[/tex]

The standard deviation is the square root of the variance.

This linear function has the domain (-2, -1, 0, 1, 2). find the range or output of. h(x)=2x+3

Answers

The linear function h(x) = 2x + 3, with the domain {-2, -1, 0, 1, 2}, has the range {-1, 1, 3, 5, 7}.

To find the range, we substitute each value of the domain for x, in the linear function h(x) = 2x + 3, as follows:

For the domain value, x = -2:

h(-2) = 2(-2) + 3,

or, h(-2) = -4 + 3,

or, h(-2) = -1.

Therefore, for the domain value, x = -2, the range value h(-2) is -1.

For the domain value, x = -1:

h(-1) = 2(-1) + 3,

or, h(-1) = -2 + 3,

or, h(-1) = 1.

Therefore, for the domain value, x = -1, the range value h(-1) is 1.

For the domain value, x = 0:

h(0) = 2(0) + 3,

or, h(0) = 0 + 3,

or, h(0) = 3.

Therefore, for the domain value, x = 0, the range value h(0) is 3.

For the domain value, x = 1:

h(1) = 2(1) + 3,

or, h(1) = 2 + 3,

or, h(1) = 5.

Therefore, for the domain value, x = 1, the range value h(1) is 5.

For the domain value, x = 2:

h(2) = 2(2) + 3,

or, h(2) = 4 + 3,

or, h(2) = 7.

Therefore, for the domain value, x = 2, the range value h(2) is 7.

Therefore, the linear function h(x) = 2x + 3, with the domain {-2, -1, 0, 1, 2}, has the range {-1, 1, 3, 5, 7}.

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The triangles are congruent by SSS or HL.

Triangles P Q R and S T U are shown. Triangle P Q R is reflected across Q R and then is shifted up and to the right to form triangle S T U.

Which transformation(s) can map TrianglePQR onto TriangleSTU?
translation only
rotation only
rotation, then reflection
reflection, then translation

Answers

From the information given about  the triangle, the transformation that can map Triangle PQR onto Triangle STU is D. reflection, then translation.

What is a congruent triangle?

Congruent triangles are known as triangles that have the same size, shape and angles.

It is also important to note that the transformation that can map Triangle PQR onto Triangle STU is reflection, then translation. This is so because it is a vital to form of congruent triangles.

There, the transformation that can map triangle PQR onto triangle STU is reflection, then translation. Option D

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Answer:

reflection, then translation

Step-by-step explanation:

The answer above is correct.

i need help with this ASAP i've been stuck on this question for a while

Answers

Answer:

B. 8

Step-by-step explanation:

Triangle's weight is equal to the sphere's weight.

Total of 16 blocks. Since the triangle's weight is equal to the sphere's, the weight will be half of the blocks.

Divide 2 from 16.

16/2=8

The triangle's weight is equal to 8 blocks.

Hope this helps!

If not, I am sorry.

Quick algebra 1 question for 50 points!


Only answer if you know the answer, Tysm!

Answers

A)

[tex]revenue = selling \: price \times quantity \: sold[/tex]

[tex]m(t) = 3t[/tex]

B)Since we only have 75 tickets to sell, the domain is:t ε [ 0 , 75 ]

Range: (extra)m ε [ 0 , 225 ]

#1

M(t)=3t

Because

revenue=sold price×no of items

#2

The restriction is of 75tickets and the tickets can't be negative

so

0≤t≤75

Domain

[0,75]

During the two hours of the morning rush from 8 a.m. to 10 a.m., 100 customers per hour arrive at the coffee shop. The coffee shop has a capacity of 0.8 minutes per customers. What is the number of customers waiting at 10 a.m.

Answers

So, 40 Customers are waiting at 10 A.M.

According to statement

Number of customers arrives at coffee shop per hour = 100

Capacity of shop for per minute per customer = 0.8 minute

Capacity of shop for customers per hour = 80

Find number of customers are by

Queue growth rate = Demand - Capacity

Put the values in the formula and find the growth rate

So,

Queue growth rate= 100 - 80 = 20.

Length of queue at 10 a.m. = 2 × 20 = 40.

So, 40 Customers are waiting at 10 A.M.

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HELP HELP HELP
Just a quick question for 100 points! :)

Answers

Answer:

see attached graphs

Step-by-step explanation:

Transformations

For a > 0

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]

[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]

[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

Parent function:  [tex]f(x) = x[/tex]

Each transformation is a transformation of the parent function only:

Translation of 4 units down

[tex]\implies f(x)-4=x-4[/tex]

[tex]\implies y=x-4[/tex]

A stretch by a factor of 3

[tex]\implies 3f(x)=3x[/tex]

[tex]\implies y=3x[/tex]

A reflection and a translation 1 unit up

[tex]\implies f(-x)+1=-x+1[/tex]

[tex]\implies y=-x+1[/tex]

a) If x and 125° are adjacent angles in linear pair, find xº [with proper process]​

Answers

Answer:

x=55°

Step-by-step explanation:

x=180°-125°

x=55°

Which term describes the line segment that connects a vertex of a triangle to a point on the line containing the oppostie side, so that the line segment is perpendicular to that line?

Answers

Answer:

90 degree and the angle sides

Solve for x -6x > 17 Give your answer as an improper fraction in its simplest form. ​

Answers

Answer:

Answer: x ≤ q - 17/6.

Step-by-step explanation:

Divide both sides of the inequality by the coefficient of variable

(2 StartRoot 7 EndRoot + 3 StartRoot 6 EndRoot) (5 StartRoot 2 EndRoot + 4 StartRoot 3 EndRoot)

Answers

4 squared is the answer to this equations

WILL GIVE BRAINLIEST
I NEED TO FIND X AND Y

Answers

Answer:

x = 3

y = 2

Step-by-step explanation:

Equations

7x - 7y = 7                            

-4x - 7y = - 26                          Multiply both sides of the equation by - 1

-1(-4x - 7y = - 26)

4x + 7y = 26

Solution

Add the two equations together

7x - 7y = 7      

4x + 7y = 26

11x = 33                                  Divide by 11

11x/11 = 33/11

x = 3

4x + 7y= 26                           Use this equation to solve for y. Use x = 3

4*3 + 7y = 26                        Combine the left

12 + 7y = 26                          Subtract 12 from both sides

12 - 12 + 7y = 26 - 12            Combine

7y = 14                                  Divide by 7

7y/7 = 14/7

y = 2  

how many Jamaican dollars are equivalent to US $135 , if US =$1 - JA $87.50

Answers

11812.5 Jamaican dollars is equivalent to $135

How to determine the amount?

The conversion rate is given as:

$1 = JA 87.50

Multiply both sides of the conversion rate by 135

135 * $1 = JA 87.50 * 135

Evaluate the product

$135  = JA 11812.5

Hence, 11812.5 Jamaican dollars is equivalent to $135

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There are 8 flavors of cupcakes on the dessert menu. You are asked to choose 3 flavors of cupcakes out of the 10 on the menu. How many differnet combinations of 3 cupcakes are there if order does not matter

Answers

There are 80 different combinations of 3 cupcakes are there if order does not matter

How to determine the combination?

The given parameters are:

Flavors = 10

Flavors to choose = 3

The number of combination is calculated using:

[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]

This gives

[tex]^{10}C_3 = \frac{10!}{7!3!}[/tex]

Expand

[tex]^{10}C_3 = \frac{10 * 9 * 8 * 7!}{7!3 * 2 * 1}[/tex]

Evaluate quotient

[tex]^{10}C_3 = 80[/tex]

Hence, there are 80 different combinations of 3 cupcakes are there if order does not matter

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On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The number b varies directly with the number a. For example b = 2a equals negative 2 and StartFraction 3 Over 4 EndFraction. when a = –2a equals negative 2 and StartFraction 3 Over 4 EndFraction.. Which equation represents this direct variation between a and b?

b = –a
–b = –a
b – a = 0
b(–a) = 0

Answers

Option 1. The equation that represents the direct variation that exists between a and b is b = –a.

How to find the direct variation here

The direct variation is of this form y ∝ x

This gives the equation

y = kx

The constant is k

From our question we have

b ∝ a so b = ka

b = [tex]2\frac{3}{4}[/tex]

a = [tex]-2\frac{3}{4}[/tex]

Remember that b = ka

[tex]2\frac{3}{4} = -2\frac{3}{4} k[/tex]

This would cancel out to

1 = -k

or k = -1

Hence the equation would be written as

b = -a

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Solve 56-10x≥ 20 + 8x.
O A. x≥ 2
OB. x2-2
OC. x≤2
OD. x≤-2

Answers

Answer:

[tex]\huge\boxed{\sf x\leq 2}[/tex]

Step-by-step explanation:

Given inequality:

[tex]56-10x\geq 20+8x\\\\Subtract \ 20 \ from \ both \ sides\\\\56-20-10x\geq 8x\\\\36-10x\geq 8x\\\\Add \ 10x \ to \ both \ sides\\\\36\geq 8x+10x\\\\36\geq 18x\\\\Divide \ 18 \ to \ both \ sides\\\\2 \geq x\\\\OR\\\\x\leq 2\\\\\rule[225]{225}{2}[/tex]

[tex]\bf{56-10x\geq 20+8x }[/tex]

Subtract 8x on both sides.

[tex]\bf{56-10x-8x\geq 20 }[/tex]

Combine −10x and −8x to get −18x.

[tex]\bf{56-18x\geq 20 }[/tex]

Subtract 56 from both sides.

[tex]\bf{-18x\geq 20-56 }[/tex]

Subtract 56 from 20 to get −36.

[tex]\bf{-18x\geq -36 }[/tex]

Divide both sides by −18. Since −18 is <0, the inequality direction is changed.

[tex]\bf{x\leq \dfrac{-36}{-18} }[/tex]

Divide −36 by −18 to get 2.

[tex]\bf{x\leq 2 \ \ \to \ \ \ Answer}[/tex]

We conclude that the correct option is "C".

{ Pisces04 }

Construct a confidence interval for p1-p2 at the given level of confidence.
x1=30, n1=235, x2=39, n2=294, 90 ​% confidence

Answers

Using the z-distribution, the 90% confidence interval for the difference of proportions is given by: (-0.0534, 0.0434).

What is the mean and the standard error for the distribution of differences?

For each sample, the mean and the standard error are given as follows:

[tex]p_1 = \frac{30}{235} = 0.1277, s_1 = \sqrt{\frac{0.1277(0.8723)}{235}} = 0.0218[/tex].[tex]p_2 = \frac{39}{294} = 0.1327, s_1 = \sqrt{\frac{0.1327(0.8673)}{294}} = 0.0198[/tex].

For the distribution of differences, they are given by:

[tex]\overline{p} = p_1 - p_2 = 0.1277 - 0.1327 = -0.005[/tex].[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{0.0218^2 + 0.0198^2} = 0.0294[/tex]

What is the confidence interval?

The interval is given by:

[tex]\overline{p} \pm zs[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

Hence the bounds of the interval are:

[tex]\overline{p} - zs = -0.005 - 1.645(0.0294) = -0.0534[/tex]

[tex]\overline{p} + zs = -0.005 + 1.645(0.0294) = 0.0434[/tex]

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Alicia walked 3 m east and then 6 m north. How far is she from the starting point?

Answers

Answer:

6.708 miles

Step-by-step explanation:

She walked 3 miles to the right, and 6 miles up. The shortest route she could take back to her starting point is a diagonal, which we can solve for using the Pythagorean theorem, a^2 + b^2 = c^2. We're solving for c.

9 + 36 = c^2

c^2 = 45

c = 6.708

Brainliest, please :)

What reason represents the same ratio as for every 12 apples, 9 of them are green?

4: 3

6: 8

9:16

3: 4

Answers

Answer:

4:3

Step-by-step explanation:

If you divide both 12 and 9 by 3 (the smallest number they can both be divided by), you get 4 and 3. the ratio is for every 4 apples, 3 would be green. So 4:3

What should be subtracted from 5/8 to make it -1​

Answers

Answer:

13/8

Step-by-step explanation:

let the number be x

5/8 - x = -1

-x = -1 - 5/8

-x = - 13/8

x = 13/8

5/8- 13/8 = -1

Answer:

13/8

Step-by-step explanation:

5/8 - x = -1   where x is the number to be found.

- x = -1 - 5/8

x = 5/8 + 1

   = 13/8.

[tex]3x+9+2x=x-2x-3[/tex]

Answers

9+5x=-x-3
9+6x=-3
6x=-12
X=-2

Answer:

Step-by-step explanation:

Equation

3x + 9 + 2x = x - 2x - 3              

Solution

Combine all the like terms.

3x+2x+9 =  x - 2x - 3

5x + 9 = -x - 3                            Add x to both sides of the equation

5x+x +9 = -x+x -3                      Combine

6x + 9 = - 3                                Subtract 9 from both sides of the equation

6x+9-9 = - 3-9                           Combine

6x = -12                                      Divide both sides by 6

6x/6 = -12/6

x = - 2

Answer x = - 2

can someone help me with this

Answers

Considering the given graph of the function, we have that:

Function Notation: f(1) = -3.Ordered pair: (1,-3).Verbal statement: If x is equal to -1, then the value of f(x) is equal to -3.How to find the numeric value of a function looking at it's graph?

To find the numeric value of the function, we get a value of x(horizontal axis), and then look at the corresponding value y(vertical axis), then y = f(x).

In the graph of this function, we have that when x = 1, y = -3, hence:

Function Notation: f(1) = -3.Ordered pair: (1,-3).Verbal statement: If x is equal to -1, then the value of f(x) is equal to -3.

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Please help me( ´人` )
The following diagram shows a quadrant OPQ in the sector ORST with centre O and a radius of 21 cm.

Given Q is the midpoint of OR, calculate the area, in cm², of the shaded region.

A 285.025
B 308.045
C 365.075
D 410.025​

Answers

Answer:

D

Step-by-step explanation:

First let's list down the formulas we will be using.

Area of Quadrant = 1/4 x Area of Circle

= [tex]\frac{1}{4} \pi r^{2}[/tex]

Area of Part of a circle = (θ/360)[tex]\pi r^{2}[/tex]

First, we will find Angle QOT.

Angle QOT = 360 - 231 = 129

Area of ORST = [tex]\frac{129}{360} \pi (21)^{2} \\=\frac{6321}{40} \pi cm^{2}[/tex]

Next we know that, Q is midpoint of OR, therefore OQ = QR

and OQ = 0.5 * OR

OQ = 0.5 * 21 = 10.5cm = radius of Quadrant QOP

Area of Quadrant QOP = [tex]\frac{1}{4} \pi (10.5)^{2} \\=\frac{441}{16} \pi cm^{2}[/tex]

Lastly,

Area of Shaded Region = Area of ORST - Area of Quadrant QOP

= [tex]\frac{6321}{40} \pi -\frac{441}{16} \pi \\= 409.86cm^{2}[/tex]

Similar to the other question you asked, choose the closes answer as there might be some rounding differences. I kept it in fractions as it will ensure maximum precision.

Triangle A C B is cut by bisector C D. The lengths of sides A C and C B are congruent.

CD bisects ∠ACB. Which statements must be true? Check all that apply.
AD = BD
AC = CD
m∠ACD = m∠BCD
m∠CDA = m∠CDB
m∠DCA = m∠DAC

Answers

The statements that are true are AD = BD  , m∠ACD = m∠BCD , m∠CDA = m∠CDB , Option A , C and D

What is a Triangle ?

A triangle is a polygon with three sides , angles and vertices.

It is given a Δ ACB

CD is the angle bisector of ∠ACB

AC ≅ CB

To determine which statement are true

First it has to be proved that Δ DCB is congruent to Δ ACD

In the triangles

AC = CB (Given )

∠ACD =  ∠DCB (CD is the angle bisector of ∠ACB)

DC = DC ( Common side )

thus Δ DCB is congruent to Δ ACD

Therefore the following statements are true

AD = BD (CPCTC)

m∠ACD = m∠BCD (CPCTC)

m∠CDA = m∠CDB (CPCTC)

Therefore Option A , C and D are the statements that are true .

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Answer:

Step-by-step explanation:

a,c,d

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