Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.
Coulomb's LawCharged bodies experience a force of attraction or repulsion on approach.
From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.
From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
[tex]F=k\frac{Qq}{d^{2} }[/tex]
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ [tex]\frac{Nm^{2} }{C^{2} }[/tex].The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
Force between two balloonsIn this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.
Replacing in the Coulomb's Law, you get:
[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }[/tex]
Solving:
[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }[/tex]
[tex]F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }[/tex]
F= 9.216×10⁻⁸ N
Finally, the force between the two ballons is 9.216×10⁻⁸ N.
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You fire a projectile 35° above horizontal with an initial velocity of 200m/s. It lands in a valley 300m below the launch point. What is the time of flight of the projectile, and what is the range of projectile?
Answer:
See below
Explanation:
Vertical component of initial velocity = 200 sin 35° = 114.72 m/s
then use position formula a = 9.81 m/s^2
0 = 300 + 114.72 t - 1/2 (9.81)(t^2)
use quadratic formula with a = - 4.905 b = 114.72 c = 300
to find t = 25.76 seconds
To find the range
( horizontal distance the projectile lands from launch point)
Horizontal component of initial velocity 200 cos 35 = 163.83 m/s
( it flies horizontally at this speed for 25.76 seconds <==found above)
163.83 m/s * 25.76 s = 4220.3 meters
a train travels 8.81 m/s in a -51.0 direction. the train accelerates 2.23 subtext1
The horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is 6.85 m/s.
Horizontal component of the train's speed
The horizontal component of the train's speed is calculated as follows;
Vx = V cosθ
where;
V is the speed of the trainθ is the direction of the train.Vx = 8.81 m/s x cos(51)
Vx = 5.54 m/s
Vertical component's of the train's speedVy = 8.81 m/s x sin(51)
Vy = 6.85 m/s
Thus, the horizontal component of the train's speed is 5.54 m/s and the vertical component's of the train's speed is 6.85 m/s.
The complete question is below:
a train travels 8.81 m/s in a -51.0 direction. the train accelerates 2.23 m/s². Find the horizontal and vertical component of the train's speed.
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A butcher has a beam balance and masses 0.5kg and 2kg .How would he measure 1.5 kg of meat on the beam balance at once.
The butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.
What is a beam balance?A beam balance can be defined as an apparatus which comprises a lever with two (2) equal arms and a bowl (pan) that is suspended from each arm, so as to measure the mass of an object.
In this scenario, the butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.
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Three containers are filled with water to the same level. Identical marbles are dropped into all the three containers. In which container will the water level be the highest?
a. P
b. Q
c. R
d. The level will be the same in all the three containers.
Answer:
P
Explanation:
,............................................ I have. a doubt too on D
a barber wants to setup a saloon in a measuring length of 3m by 3m. He has a simple wooden chairs,3 large mirror and one bulb. Using the knowledge of shadows and reflection, advice the barber on how to arrange a good saloon using the only item he has. Without adding more source of light, how can he enhance the lighting system in his saloon?
According to the information, it can be inferred that the best way to distribute the chairs and mirrors is to put the light system on a wall and put the 3 mirrors and chairs in front of the light as shown in the image.
How to distribute the objects to take advantage of the light from the bulb?To take advantage of the light from the bulb for the three chairs and the three mirrors, the objects must be placed in such a way that all three receive enough light to be able to carry out the work of cutting the hair.
So, the best option would be to put the bulb in the middle of a wall, and place a chair and mirror in front of the bulb. The other two chairs should be located one on each side of the centered chair and the mirrors in front of each chair.
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It takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed of the earth?
angular speed = 7.29x10^-5 rad/s
Assume the earth is spherical. Relative to someone on the rotation axis, what is the linear speed of an object on the surface if the radius vector from the center of the earth to the object makes an angle of 49.0° with the axis of rotation. The radius of the earth is 6.37×103 km.
linear speed = 3.51 x 10^2 m/s
* What is the acceleration of the object on the surface of the earth in the previous problem?
Answer: See below
Explanation:
Part (a):
The angular speed of the Earth can be calculated as,
[tex]\omega &= \dfrac{{2\pi }}{T}\\ \omega &= \dfrac{{2\pi }}{{\left( {23 \times 3600} \right)\left( {56 \times 60} \right) + 4}}\\ \omega &= 7.29 \times {10^{ - 5}}\;{\rm{rad/s}}[/tex]
Part (b):
The linear velocity of the object can be calculated as,
[tex]v &= \omega r\sin \theta \\ v &= \left( {7.29 \times {{10}^{ - 5}}} \right)\left( {6.37 \times {{10}^6}} \right)\sin 47^\circ \\ v &= 339.62\;{\rm{m/s}}[/tex]
Part (c):
The acceleration of the object can be calculated as,
[tex]a &= \dfrac{{{v^2}}}{{r\sin \theta }}\\ a &= \dfrac{{{{339.62}^2}}}{{6.37 \times {{10}^6}\sin 47^\circ }}\\ a &= 0.024\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}[/tex]
power is measured in units of watts what are watts ?
Answer:
the watt is the unit of power or radiant flax
I need a super tragic past for my desired reality, the reality I'm going to is Naruto.
Thanks
To create a tragic past for your character, you would have to write a plot that shows a sad ending to a good story.
What is a Tragic Story?This refers to a type of story that has negative emotions such as sadness, death, etc.
Hence, we can see that for example, you could write about two lovers and how despite all the struggles they faced, eventually died in mysterious circumstances.
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A 21.0 kg uniform beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
If the angle between the beam and the cable is θ = 66.0° what is the tension in the cable?
What is the vertical component of the force exerted by the hi.nge on the beam?
The tension in the cable is 112.64 N and the vertical component of the force exerted by the hi.nge on the beam is 93.16 N.
Tension in the cableApply the principle of moment and calculate the tension in the cable;
Clockwise torque = TL sinθ
Anticlockwise torque = ¹/₂WL
TL sinθ = ¹/₂WL
T sinθ = ¹/₂W
T = (W)/(2 sinθ)
T = (21 x 9.8)/(2 x sin66)
T = 112.64 N
Vertical component of the forceT + F = W
F = W - T
F = (9.8 x 21) - 112.64
F = 93.16 N
Thus, the tension in the cable is 112.64 N and the vertical component of the force exerted by the hi.nge on the beam is 93.16 N.
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Peter arranged the two circuits shown below. P, Q R and S are blocks of four different materials.
Based on the given information, which of the four materials is an insulator?
a. P
b. Q
c. R
d. S
Material P does not always lead to the glowing of the bulb hence the material P is an insulator.
What is an insulator?The term insulator refers to an object that does not permit current to pass through it. Insulators include materials such as wood, plastic etc.
Looking at the two circuits, we can see that the material P does not always lead to the glowing of the bulb hence the material P is an insulator.
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In order to ensure a message is understood requires:
a. Speaking clearly
b. Speaking concisely
c. Not allowing body language to portray a different message
d. All of the above
Order to ensure a message is understood requires all four option is needed.
The option will be D.All of the above.
What is a good communication skill?
The sender is the person who is trying to communicate a message.The challenge is that since the receiver’s education and experience may be very different from the sender's, words often have different meanings.While we may carefully choose the words to speak, words alone represent a small percentage. communication is only verbal the most important element of communicationWhen encountering a noise, take steps to reduce the distraction.
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A force of 1.5 × 102 n is exerted on a charge of 1.4 × 10–7 c that is traveling at an angle of 75° to a magnetic field. if the charge is moving at 1.3 × 106 m/s, what is the magnetic field strength?
The magnetic field strength = 8.5 x 10² T.
Solution :
the magnetic force Fm is given by
Fm= q V B sinθ
q= charge=1.4 x 10⁻⁷ C
v= velocity= 1.3 x 10⁶ m/s
B= magnetic field strength
Fm= magnetic force= 1.5 x 10² N
θ=75°
so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75
B=8.5 x 10² T
Magnetic field strength: The definition of H is H = B/μ − M, where B is the magnetic flux density, a measure of the actual magnetic field within a material considered as a concentration of magnetic field lines, or flux, per unit cross-sectional area; μ is the magnetic permeability; and M is the magnetization.
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Answer: 8.5 × 10^2 T
Explanation: Edge2020
identify the solute and solvent in a solution made of 15g of oxygen and 5g
of helium
Taking into account the definition of solvent and solute, helium is the solute and oxygen is the solvent.
Definition of solute and solventThe solution is a homogeneous mixture of two or more components that have the same chemical and physical properties in a single phase. A solution is made up of two main components: the solute and the solvent.
That is, the solute and the solvent are the components of a chemical solution, that is, of a homogeneous mixture that occurs when one or more substances are dissolved in another substance.
The solute is the substance that dissolves in a solution. In solution, the solute is usually found in a lower proportion than the solvent.
Solvent is the substance in which a solute dissolves, resulting in a chemical solution. Generally, the solvent is the component that is found in the highest proportion in the solution. It will always be the solvent who will determine the state of the matter that will have the solution.
Solute ans solvent in this caseIn this case, you consider that the solute is the component in less quantity and the solvent is the major component.
You know that a solution made of 15 g of oxygen and 5 g of helium. Then, helium is the solute and oxygen is the solvent.
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The stem of thermometer is made by thick glass and the bulb is made by thin glass, Why?
Answer:
The reason is to allow the thermometer to respond relatively quickly, and relatively accurately. The glass contains the liquid being used in the thermometer, but if it is too thick, then it will not pass heat as quickly, and it will absorb some of the heat from whatever is being measured.
Explanation:
˙˚ʚ(´◡`)ɞ˚˙
You add chocolate syrup to a glass of milk and stir it. The resulting chocolate milk would be classified as:
A. Homogeneous mixture
B. Element
C. Heterogeneous mixture
D. Compound
A 60kg man jumps off a 30 foot building. Assuming he falls from rest and there is negligible air resistance, how long will it take him to reach the ground?
Answer:
1.37 seconds before.... splat !
Explanation:
y = y0 + v0 t + 1/2 a t^2 y0 = 30 y = 0
v0 = 0 ( from rest)
a = - 32.2 ft/s^2
0 = 30 - 1/2 * 32.2 * t^2
t=1.366 seconds Note that mass is irrelevant.
More than 700 people in the United States have been infected with monkeypox virus American vector: the epidemic is spreading like a snowball.
Answer: I don't understand if it is a question
Explanation:
More than 700 people in the United States have been infected with monkeypox virus American vector: the epidemic is spreading like a snowball.
2 red and 2 blue overlapping balls in the center are surrounded by a green, fuzzy, circular cloud with a white line running through it. 2 green balls sit on the white line, and a line leading a bracket around the balls is labeled A. A line leading to a bracket overlapping the white line is labeled B. Which is a characteristic of the part of the atom marked "B”? It is very dense. It has a large mass. It is negatively charged. It is where neutrons move.
A characteristic of the part of the atom marked "B” is that it has a large mass. Option B. This is further explained below.
What is atom?Generally, Atom, the lowest possible unit into which matter may be split without releasing electrically charged particles.
In conclusion, the protons and neutrons are represented by the red and white spheres, respectively. Since it indicates both protons and neutrons, the line preceding the bracket around the balls (designated A) stands in for the atom's nucleus.The mass of the "B" section of the atom is very high.
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Answer:
it's b
Explanation:
i did the ed quiz
Please help me answer this
An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
The magnitude of the tension in the lower rope is 12.8 N. Calculate the magnitude of the tension in the upper rope.
The tension in the upper rope is determined as 50.53 N.
Tension in the upper rope
The tension in the upper rope is calculated as follows;
T(u) = T(d)+ mg
where;
T(u) is tension in upper ropeT(d) is tension in lower ropeT(u) = 12.8 N + 3.85(9.8)
T(u) = 50.53 N
Thus, the tension in the upper rope is determined as 50.53 N.
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What quadrant will the resultant be in if the horizontal component is positive and the vertical component is
negative?
Answer:
Quadrant IV
Explanation:
In Quadrant IV, x is positive, and y is negative.
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The intensity of sound waves is linearly proportional to ?
You are able to hear sounds from farther away on a cool night because sound waves are refracted toward ?
When the trough of one wave collides at the same time & place of the crest of an identical wave?
A water heater is rated at 200w ( 200 Joules/sec). How long will the heater take to provide 60,000 joules to heat up a sample of water?
A sample of 100g of 0 Celsius ice is heated up until the sample totally becomes 0 Celsius water ( solid /liquid phase change occurs in this case).What is the total amount of heat provided to the ice sample?( Latent heat of fusion of water /ice is =79.8 cal/g)?
The amount of heat required to increase the temperature of 100g of water rom 20 Celsius ( specified heat of water =4184 JC-1*kg-1)?
When water vapor condense into liquid water?
(1) The intensity of a sound wave is linearly proportional to the change in the pressure squared.
(2) You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.
(3) When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.
(4) The time taken for the heater to provide the energy is 300 secs.
(5) The total amount of heat provided to the ice sample is 7,980 cal.
(6) The amount of heat required to increase the temperature of water is 33,472 J.
Intensity of soundThe intensity of a sound wave is linearly proportional to the change in the pressure squared and inversely proportional to the density and the speed.
Refraction of sound wavesYou are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.
Destructive inferenceWhen the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.
Time taken for the heater to provide the energyE = Power x Time
t = E/P
t = 60,000/200
t = 300 secs
Total amount of heat provided to the ice sampleQ = 79.8 cal/g x 100 g
Q = 7,980 cal
Amount of heat required to increase the temperature of waterQ = 0.1 kg x 4184 J/kgC x (100 - 20)
When water vapor condense into liquid water, temperature = 100⁰C
Q = 33,472 J
Thus, the intensity of a sound wave is linearly proportional to the change in the pressure squared.
You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.The time taken for the heater to provide the energy is 300 secs.The total amount of heat provided to the ice sample is 7,980 cal.The amount of heat required to increase the temperature of water is 33,472 J.Learn more about intensity of sound here: https://brainly.com/question/17062836
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A roller coaster has a mass of 450 kg. It sits at the top of a hill with height 49
m. If it drops from this hill, how fast is it going when it reaches the bottom?
Answer:
Approximately [tex]31\; {\rm m\cdot s^{-1}}[/tex] assuming that there is no friction on the rollercoaster, and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Explanation:
Make use of the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex], where:
[tex]v[/tex] is the final velocity of the moving object,[tex]u[/tex] is the initial velocity of the object,[tex]a[/tex] is the acceleration of the object, and[tex]x[/tex] is the displacement of the object.If there is no friction on the rollercoaster, the acceleration of the rollercoaster would be equal in magnitude to the gravitational field strength, [tex]g[/tex]:
[tex]a = g = 9.81\; {\rm m \cdot s^{-2}}[/tex].
The initial velocity of this rollercoaster is [tex]0\; {\rm m\cdot s^{-1}}[/tex] (that is, [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]) since the rollercoaster was initially stationary. The displacement of this rollercoaster would be [tex]x = 49\; {\rm m}[/tex] (same as the height of the hill.)
Rearrange the equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find an expression for the final velocity [tex]v[/tex] of this rollercoaster:
[tex]\begin{aligned}v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 9.81\; {\rm m\cdot s^{-2} \times 49\; {\rm m} + (0\; \rm m\cdot s^{-1}})^{2}}\\ &\approx 31\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
what is scalar product of A and B , if vector product of A and B is zero
Answer:
A^2+B^2 is the scalar product of A and B
Answer:
Scalar product is equal to the magnitude a vector a times the projection of a onto vector B,
A^2+B^2.A boat moving at 5 km/h to cross a river in which the current is flowing at 3km/h. in what direction should the boat head to reach a point on the other bank of the river directly opposite its starting point?
The boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.
We must understand the issue with the river crossing in order to identify the solution.
How can I determine the angle at which my boat should be travelling against the current to reach the other bank?Let's assume that a boat traveling at velocity Vb is navigating a river with width d and flow Vr.The boat's movement against the current to reach the opposite shore from its starting point will then be in the direction of,[tex]\alpha =sin^{-1}(\frac{V_R}{V_B} )[/tex]
First, using the provided information, we may create a flow diagram for this issue.It is evident from the diagram that the angle will be,[tex]\alpha =sin{-1}(\frac{3}{5} )[/tex]
Thus, we can deduce that the boat will move in a direction that is 36.86 degrees away from the velocity vector as it attempts to reach the opposite bank from where it started.
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You place a book of mass 5.00 kg against a vertical wall. You apply a constant force F⃗ to the book, where F = 96.0 N and the force is at angle of 60.0∘ above the horizontal. The coefficient of kinetic friction between the book and the wall is 0.300.
If the book is initially at rest, what is its speed after it has traveled 0.400 m up the wall.
The speed after it has traveled 0.400 m up the wall will be 1.77 m/sec.
What is the work-energy theorem?From the work-energy theorem, it is stated that the net work done is equal to the change in the kinetic energy.
Given data;
Mass of book,m =5.00
Force,F = 96.0 N
Θ is the angle above the horizontal = 60°
The coefficient of kinetic friction between the book and the wall is μ =0.300.
R is the normal reaction
W₁ = Fd cosΘ
W₁=(96.0 N) (0.4 m) in 60°
W₁= 33.25 J
Work done by gravity is,
W₂ = mgdcos180°
W₂ = (5.00 kg) (9.81 m/s²)(0.4 m) cos180°
W₂ = -19.6J
The Normal force on the book by the wall is,
N = FcosΘ
N = (96 N) cos 60°
N=48 J
Work done by friction is;
W₃=μkRdcos180°
W₃=0.3)(48 J)(0.4 m) cos180°
W₃ =-5.76 J
The net work done is;
W =W₁+W₂+W₃
W=33.25-19.6-5.76
W=7.89 N
From the work-energy theorem, we have
W = ΔK
[tex]\rm W = \frac{1}{2} mv^2 - 0[/tex]
The speed is;
[tex]\rm v = \sqrt \frac{2 W}{m} \\\ v = \sqrt{\frac{2 \times 7.89} {5.00}}\\\\ v = 1.77 \ m/sec[/tex]
Hence, the speed after it has traveled 0.400 m up the wall will be 1.77 m/sec.
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a steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to which it must be heated in order to fit the shaft. the initial temperature is 20 deg C and the coefficient of linear expansion is 15x10^-6 per degrees celcius. calculate the stress and forced induced in the ring
okay so the stress and forced induced I can do that but the first part is confusing me because there is no final temperature.
The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.
Linear expansivity
The temperature to which it must be heated in order to fit the shaft is calculated as follows;
[tex]\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}[/tex]
where;
ΔT is change in temperatureΔL is change in length = 50.04 mm - 50 mm = 0.04 mmα is coefficient of linear expansionL is original lengthΔT = (0.04)/(50 x 15 x 10⁻⁶)
ΔT = 53.3 ⁰C
Final temperatureT₂ - T₁ = ΔT
T₂ = ΔT + T₁
where;
T₂ is final temperatureT₁ is initial temperatureT₂ = 53.3 + 20
T₂ = 73.33 ⁰C
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A bug and a city bus have a head-on collision. Is the force the bug exerts on the bus greater than, less than, or the same as the force the bus exerts on the bug? Explain. What happens to the velocity of the bus and the bug after the collision?
Answer:
Force of bug is less than the force that the bus exerts on the bug
Explanation:
Force = MA. bus has more mass so more force and bug has a lot less mass than bus. Bug accelerates in whatever direction the bus is going and the bus is not affected.
What is the length of the y-component of the vector plotted below?
The length of the y-component of the vector plotted below is 1 unit.
We know this because this vector can be descomposed in two vectors (blue) that form an angle of 90° beetween them. The measures of this vectors must be able to form a right-angle triangle with the descomposed vector (see image).
An extended body (not shown in the figure) has its center of mass at the origin of the reference frame. In the case below give the direction for the torque τ with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r.
Options are:
X
-Y
Z
-Z
The direction of torque τ this method is mathematically given as
D=X
Option A is correct.
What is the direction of torque?Generally, the equation for torque is mathematically given as
τ = r X F
Hence to decipher the torque direction with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r
We utilize our right hand.Place our right-hand fingers along the path of rPlace our right-hand palm on F Then slowly we sweep r into F.The path or direction of the thumb will provide the direction of the torque.In conclusion, the direction of this method is
D=X Option A.
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