what is the ansss??? btw this is a practice assignment.

What Is The Ansss??? Btw This Is A Practice Assignment.

Answers

Answer 1

A) Check the graph below, please. B) Horizontal translation to the left in 2 units. C) Vertical shift 4 units

1) Given that we have the function h(x) = |x+2| and g(x)= |x| + 4

A) Let's set a pair of tables, and pick 3 arbitrary values for x and then plug into each one

h(x) = |x+2|

x | y = |x+2|

-1 | 1 y =|-1 +2| = |1| = 1

0 | 2 y =|0+2| = |2| = 2

1 | 3 y =|1+2| = |1| = 1

g(x) =|x| + 4

x | y

-1 | 5

0 | 4

1 | 5

Let's plot those absolute value functions:

B) Considering the parent function f(x) =|x| we can notice that h(x) is a translation to the left, in two units. This we can see better this way:

Note that f(x) is in red, and h(x) in pink or light red.

C) Considering that f(x) = |x| we can see that g(x) = is a vertical shift 4 units up.

What Is The Ansss??? Btw This Is A Practice Assignment.
What Is The Ansss??? Btw This Is A Practice Assignment.
What Is The Ansss??? Btw This Is A Practice Assignment.

Related Questions

Mary's dog weighs 25 pounds. How many ounces does the dog weigh? Remember, there are 16 ounces in a pound.

Answers

Answer:

400

Step-by-step explanation:

4 x 10^, 20^2

Answer:

25 pounds  16 ounces = 6400

Step-by-step explanation:

Danielle earns $36.80 for 4 hours of yardwork. How much does Danielle earn for 10 hours of yardwork?

Answers

first find out what she earns per hour by dividing 36.80 by 4 which is 9.20 then multiply that by 10 and the answer is $92

Precalc please help Answers:A. 5 sin 60°/sin 70°B. 5/sin 50° sin 70°C. 5/sin 50°D. 5 sin 50°/sin 70°

Answers

step 1

Find out the measure of angle P

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

P+Q+R=180 degrees

substitute given values

P+70+60=180

P=180-130

P=50 degrees

step 2

Applying the law of sines

QR/sin P=PR/sin 70

substitute given values

QR/ sin 50=5/sin 70

QR=(5/sin 70)*sin 50

the answer is option D

=
If P = 3+5+7+9+...+99 and Q = 7+9+11+13+...+101 are sums of arithmetic sequences, determine which is
greater, P or Q, and by how much.

Answers

Answer:

Q is greater than P by 291

Step-by-step explanation:

The terms of these Arithmetic Sequences are odd natural numbers, because their common difference is 2

And, sum of 'n' odd natural numbers starting from 1 = n²

P = 99² - (1) = 9800

Q = 101² - (1 + 3 + 5) = 10192

Q - P = 291

Which of the following expressions is equivalent to 3x(2+5y)

Answers

Answer:

[tex]15xy+6x[/tex]

Questlon 14 of 25 What is the slope of the line containing (-3, 1) and (1, -2)? O A. A - 3 O B. 4 O c. - 3 4 O D. SUBMIT

Answers

Answer:

C - 3/4

Step-by-step explanation:

Log z 2 + log 2x

pahelp po

Answers

answer is 1.2, log(2) + log(2X)

Victoria's speedboat can travel 105 miles upstream against a 4-mph current in the same amount of time it travels 125 miles downstream with a 4-mph current. Find the speed of Victoria's boat.

Answers

Recall that:

[tex]\text{ time }=\frac{\text{ distance}}{\text{ speed}}[/tex]

Let Victoria's speed be v.

Therefore, Victoria's resultant speed upstream is v - 4 and her resultant speed downstream is v + 4.

Hence the time of journey upstream is given by:

[tex]\frac{105}{v-4}[/tex]

And the time of journey downstream is given by:

[tex]\frac{125}{v+4}[/tex]

Since the time of journey upstream is the same as the time of journey downstream, it follows that:

[tex]\begin{gathered} \frac{105}{v-4}=\frac{125}{v+4} \\ \text{ Divide both sides by }5: \\ \frac{21}{v-4}=\frac{25}{v+4} \\ \text{ Cross-multiplying, we have:} \\ 21(v+4)=25(v-4) \\ \text{ Expanding the expressions, we have:} \\ 21v+84=25v-100 \\ 25v-21v=100+84 \\ 4v=184 \\ v=\frac{184}{4}=46 \end{gathered}[/tex]

Therefore, Victoria's speed is 46 mph

What is the quotient in simplest form? State any restrictions on the variable.see image

Answers

we have the expression

[tex]\frac{z^2-4}{z-3}\div\frac{z+2}{z^2+z-12}[/tex]

Multiply in cross

[tex]\frac{(z^2-4)(z^2+z-12)}{(z-3)(z+2)}[/tex]

Simplify

z^2-4=(z+2)(z-2) -----> difference of squares

z^2+z-12=(z+4)(z-3)

substitute in the above expression

[tex]\frac{\mleft(z+2\mright)\mleft(z-2\mright)\mleft(z+4\mright)\mleft(z-3\mright)}{(z-3)(z+2)}[/tex]

Simplify

[tex](z-2)(z+4)[/tex]

Simplify (z9z−3)−2.

1 over z raised to the twelfth power

1 over z raised to the sixth power

−z^12

−z^6

Answers

Answer:

A. 1 over z raised to the twelfth power

Step-by-step explanation:

Hope this helps! :))
Please tell me if this is incorrect

Answer:

1 over z raised to the twelfth power

Step-by-step explanation:

4x - 2y = 8Solve for yy = 4x + 8y = -2x + 4y = 2x - 4y = -x

Answers

This question has to do with the change in the subject of the formula.

So we will proceed thus:

[tex]\begin{gathered} 4x-2y=8 \\ \text{Making y the subject of formula will give:} \\ \end{gathered}[/tex][tex]\begin{gathered} 4x-8=2y \\ \text{Divide both sides by 2} \\ \frac{4x-8}{2}=\frac{2y}{2} \\ 2x-4=y \end{gathered}[/tex]

The correct answer, therefore, is the third option:

[tex]y=2x-4[/tex]

12–23. Tony Ring wants to attend Northeast College. He will need $60,000 4 years from today. Assume Tony’s bank pays 12% interest compounded semiannually. What must Tony deposit today so he will have $60,000 in4 years?

Answers

Answer:

See below

Step-by-step explanation:

Period = 1/2 year    total 4years = 8 periods

i = interest per period in decimal form = .12/2 = .06

initial deposit = ?

Final value = 60 000

60 000 = ? ( 1 + .06)^8

? = 37644.74

Simplify the expression.Can you help me with this one. I'm stuck at 12^x4 - 15x^2

Answers

Simplify the given expression as shown below

[tex]\begin{gathered} 3x(4x^4-5x)=3x*4x^4+3x(-5x)=12x^5+(-15x^2) \\ =12x^5-15x^2 \end{gathered}[/tex]Therefore, the answer is 12x^5-15x^2

Please help!!!!!!!!!!!

Answers

They are similar because they share one same angle and both have a angle with the same degree

A company prices its tornado insurance using the following assumptions:
• In any calendar year, there can be at most one tornado.
• In any calendar year, the probability of a tornado is 0.09.
• The number of tornadoes in any calendar year is independent of the number of tornados in any other calendar year.
Using the company's assumptions, calculate the probability that there are fewer than 2 tornadoes in a 14-year period.Round your answer to 4 decimals.

Answers

The probability that there are fewer than 3 tornadoes in a 14-year period is 0.992333

Let x = number of tornados

n = 14

p = 0.03

There are just two outcomes that can occur in these independent, fixed trials, and the success probability is 0.03

Consequently, we may determine the probability using the binomial distribution.

Here we want to find P( X < 3) = P( X < = 3-1) = P(X <=2)

Using Excel:

P( X <=2) = "=BINOMDIST(2,14,0.03,1)" = 0.992333

Be aware that the default Excel command to find binomial probabilities that are less than or equal is  "=BINOMDIST(x, n, p, 1)"

Therefore, 0.9923333 percent of the time there won't be more than 3 tornadoes in a 14-year period.

To know more about Probability, refer to this link:

https://brainly.com/question/12629667

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What value is equivalent to (8+2)2 + (6 − 4) × 3?

Answers

Answer:

26

Step-by-step explanation:

PEMDAS

8 + 2 = 10

6 - 4 = 2

10 x 2 = 20

2 x 3 = 6

20 + 6 = 26

PLS HELP ME WITH THIS

you need to use the y=mx+b

Answers

Hello!

What is a slope-intercept line:

 [tex]y = mx + b[/tex]

m: slope

            [tex]slope = \dfrac{y_2-y_1}{x_2-x_1} =\frac{-4--2}{3-0} =-\dfrac{2}{3}[/tex]

y-intercept or point whose x-coordinate is '0'

           ==> value of y-intercept is '-2'

Thus the equation is [tex]y=-\dfrac{2}{3}x-2[/tex]

Hope that helps!

Answer: y=-2/3x-2

Step-by-step explanation:

1) Draw a triangle from one point to the next point.

For this example, I will use (-3,0) and (0,-2).

You can see that the number goes down 2 and right 3. From this, you can conclude that the rate is -2/3 using the equation rise/run.

2) Find the y-intercept

Looking at the graph, you can find that the y-intercept is (0,-2).

3) Fill in the y=mx+b

y=-2/3x-2

In the expression 7^4 = 2,401, the value of the____ is 7.A. BaseB. PowerC. exponent

Answers

Answer:

The value of the base is 7 (option A)

Explanation:

Given:

[tex]7^4\text{ = 2401}[/tex]

To find:

To complefe the sentence by ill ingthe blanks

In powers and exponents:

[tex]For\text{ }a^b:\text{ a = base, b = exponent}[/tex][tex]\begin{gathered} Applying\text{ same principle:} \\ 7^4:\text{ Base = 7, exponent = 4} \end{gathered}[/tex]

The value of the base is 7 (option A)

PLEASE HURRY IM SO CONFUSED

What is the product of (−4)(23)(−7)?

Answers

Answer:

644

Step-by-step explanation:

-4x23=-92

-92x-7=644

i hope this helped :)

A cone has a radious of 5inches and a height of 10.125inches.What is the volume of the cone in inch rounded to the nearest tenth?

Answers

Answer:

264.9 in³

Explanation:

The volume of a cone can be calculated using the following equation:

[tex]V=\frac{\pi\cdot r^2\cdot h}{3}[/tex]

Where π is approximately 3.14, r is the radius of the cone and h is the height.

So, replacing r by 5 in and h by 10.125 in, we get:

[tex]\begin{gathered} V=\frac{3.14\cdot(5)^2\cdot(10.125)}{3} \\ V=\frac{3.14\cdot25\cdot10.125}{3} \\ V=\frac{794.8}{3} \\ V=264.9 \end{gathered}[/tex]

Therefore, the volume of the cone is 264.9 in³

You put together allowance money and head toward a distant planet forsome routine experiments on alien life forms. You abduct 12 aliens from thestrange planet, and you capture the internal body temperature of each(harmlessly of course). That data is presented above. Does this species ofaliens have an average internal body temperature less than that of the humanaverage of 98.6°F?

Answers

Solution

The mean of the internal body temperature of the 12 abducted aliens is given by;

[tex]\frac{96.8+98.3+97.6+98.5+97.5+97.5+98.5+65.6+95.4+98+97.4}{12}=87.14<98.6[/tex]

Describe a series of transformations Matt can perform to device if the two windows are congruent

Answers

Answer:

the transformation matt can from A

Find the area of a square with a diagonal that measures 4 square root of 2

Answers

Let's draw the figure to better understand the scenario:

Let,

s = the measure of the sides of the square

For us to be able to determine the area, let's first find out the measure of its side.

We will be using the Pythagorean Theorem:

[tex]\text{ a}^2+b^2=c^2[/tex][tex]\text{ s}^2+\text{ s}^2=(4\sqrt[]{2})^2[/tex][tex]\text{ 2s}^2=32[/tex][tex]\text{ }\frac{\text{2s}^2}{2}=\frac{32}{2}[/tex][tex]\text{ }\sqrt{\text{s}^2}=\sqrt{16}[/tex][tex]\text{ s = 16}[/tex]

Let's now determine the area of the square:

[tex]\text{ Area = s}^2[/tex][tex]\text{ = 4}^2[/tex][tex]\text{Area = 16}[/tex]

Therefore, the area of the square is 16.

You pick a card at random, put it back, and then pick another card at random.
4 5 6 7
What is the probability of picking a 7 and then picking an odd number?
Simplify your answer and write it as a fraction or whole number.

Answers

Answer:  1/8

=======================================================

Explanation:

A = probability of picking a 7

A = 1/4 since one card is labeled "7" out of four cards total

B = probability of picking an odd number

B = 2/4 = 1/2 because there are 2 cards that are odd (5 and 7) out of 4 cards total.

C = A*B = probability events A and B happen

C = (1/4)*(1/2)

C = 1/8

This only works when we put the first card back, which means each event is independent.

Given the Frequency Distribution: (SHOW WORK)
Find the:
(A) Range
(B) Mean
(C) Mode
(D) Median
(E) Variance
(F) Standard Deviation of This Sample

Answers

The measures of the frequency distribution is;

(A) Range = 7

(B) Mean = 29

(C) Mode = 12

(D) Median = 29

(E) Variance = 7.612

(F) Standard Deviation = 2.759

How to solve frequency distribution?

A) The range of a frequency distribution is;

Range = Highest Value - Lowest Value

Thus;

Range = 32 - 25

Range = 7

B) Mean is expressed as;

x' = ∑fx/∑f

x' = [(25 * 4) + (26 * 6) + (28 * 6) + (30 * 4) + (32 * 12)]

x' = 928/32

x' = 29

C) Mode is the value with the highest frequency and so in this case;

Mode = 12

D) Median is the middle term when arranged from lowest to highest. In this case, it is the 16.5th term. Thus; Median = (28 + 30)/2 = 29

E) Variance = 7.612

F) The standard deviation is;

σ = √Variance

σ = 2.759

Read more about Frequency distribution at; https://brainly.com/question/27820465

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Which equation represents a line which is parallel to the line y=8x-4?A x+8y=-16B x-8y=-40C y-8x=-1D 8x+y=3

Answers

Two parallel lines has the same slope.

The given line:

[tex]y=8x-4[/tex]

Is written in the form y=mx+b where m is the slope.

The slope is 8

To find the parallel line you need to write the given options in the form y=mx+b by solving y, as follow:

[tex]\begin{gathered} A \\ x+8y=-16 \\ 8y=-x-16 \\ y=-\frac{1}{8}x-\frac{16}{8} \\ \\ y=-\frac{1}{8}x-2 \end{gathered}[/tex]

Slope is -1/8 (it is not parallel to given line)

_______________

[tex]\begin{gathered} B \\ x-8y=-40 \\ -8y=-x-40 \\ y=\frac{-x}{-8}-\frac{40}{-8} \\ \\ y=\frac{1}{8}x+5 \end{gathered}[/tex]

Slope is 1/8 (it is not parallel to given line)

________________

[tex]\begin{gathered} C \\ y-8x=-1 \\ y=8x-1 \end{gathered}[/tex]Slope is 8 (It is parallel to given line)___________[tex]\begin{gathered} D \\ 8x+y=3 \\ y=-8x+3 \end{gathered}[/tex]

Slope is -8 (it is not parallel to given line)

Then, as given line and line in option C have the same slope (8) they are parallel lines

I only need the answer
THANK YOU!!

Answers

Answers:

[tex]\cos(\theta) = \frac{-3\sqrt{5}}{7}\\\\\tan(\theta) = -\frac{2}{3\sqrt{5}} = -\frac{2\sqrt{5}}{15}\\\\\csc(\theta) = \frac{7}{2}\\\\\sec(\theta) = -\frac{7}{3\sqrt{5}} = -\frac{7\sqrt{5}}{15}\\\\\cot(\theta) = \frac{-3\sqrt{5}}{2}\\\\[/tex]

=================================================

Explanation:

We're given that [tex]\sin(\theta) = \frac{2}{7}\\\\[/tex]

Plug that into the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1\\\\[/tex] and solve for cosine to find that [tex]\cos(\theta) = \frac{-3\sqrt{5}}{7}\\\\[/tex]

I skipped steps in solving so let me know if you need to see them.

Keep in mind that cosine is negative in quadrant 2

------------------

Once you've determined cosine, divide sine over cosine to get tangent

[tex]\tan(\theta) = \sin(\theta) \div \cos(\theta)\\\\\tan(\theta) = \frac{2}{7} \div \frac{-3\sqrt{5}}{7}\\\\\tan(\theta) = \frac{2}{7} \times -\frac{7}{3\sqrt{5}}\\\\\tan(\theta) = -\frac{2*7}{7*3\sqrt{5}}\\\\\tan(\theta) = -\frac{2}{3\sqrt{5}}\\\\\tan(\theta) = -\frac{2\sqrt{5}}{3\sqrt{5}*\sqrt{5}}\\\\\tan(\theta) = -\frac{2\sqrt{5}}{3*5}\\\\\tan(\theta) = -\frac{2\sqrt{5}}{15}\\\\[/tex]

------------------

To determine cosecant, we apply the reciprocal to sine.

[tex]\sin(\theta) = \frac{2}{7} \to \csc(\theta) = \frac{1}{\sin(\theta)} = \frac{7}{2}\\\\[/tex]

Similarly, secant is the reciprocal of cosine

[tex]\cos(\theta) = \frac{-3\sqrt{5}}{7} \to \sec(\theta) = \frac{1}{\cos(\theta)} = -\frac{7}{3\sqrt{5}} = -\frac{7\sqrt{5}}{15}\\\\[/tex]

Depending on your teacher, rationalizing the denominator may be optional.

Lastly, cotangent is the reciprocal of tangent

[tex]\tan(\theta) = -\frac{2}{3\sqrt{5}}\to \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{-3\sqrt{5}}{2}[/tex]

------------------

Side notes:

Sine and cosecant are the only things positive in Q2

Everything else (cosine, tangent, secant, cotangent) are negative in Q2.

how many ways can nine trophies be arranged on a shelf

Answers

we know that

There are: 9 ways to put the first trophy.

8 ways to put the second trophy after putting the first one.

7 ways to put the third trophy after putting the second one.

6 ways .............the third one

5 ways --------> the fourth

4 ways------> 5

3 ways -----> 6

2 ways ----> 7

1 ways-----> 8

therefore

n!

where n=9

9!=9*8*7*6*5*4*4*2*1

9!=362,880

the answer is

362,880 ways

Divide and simplify 7/8 ÷ -13/7

Answers

7/8x-7/13 = -49/104 and that is its simplest form

Hi, I need help differentiating using the product rule, thanks

Answers

Differentiate using the product rule:

g. We take out the constant:

[tex]4\frac{dy}{dx}\left(x\left(3x-2\right)^5\right)[/tex]

So:

[tex]=4\left(\frac{d}{dx}\left(x\right)\left(3x-2\right)^5+\frac{d}{dx}\left(\left(3x-2\right)^5\right)x\right)[/tex]

Now

[tex]\begin{gathered} \frac{d}{dx}\left(x\right)=1 \\ \frac{d}{dx}\left(\left(3x-2\right)^5\right)=5(3x-2)^4\cdot\frac{d}{dx}\left(\left(3x-2\right)^5\right)=5\left(3x-2\right)^4\cdot\:3=15\left(3x-2\right)^4 \end{gathered}[/tex]

Substituting the derivatives found:

[tex]=4\left(1\cdot\left(3x-2\right)^5+15\left(3x-2\right)^4x\right)[/tex]

Simplify:

[tex]=4\left(\left(3x-2\right)^5+15x\left(3x-2\right)^4\right)[/tex]

Answer:

[tex]=4\left(\left(3x-2\right)^5+15x\left(3x-2\right)^4\right)[/tex]

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