what is a chemical germicides that has been formulated for use on the skin and is registered and regulated by the food and drug administration? milady barbering

Answers

Answer 1

Antiseptics is a chemical germicides that has been formulated for use on the skin and is registered and regulated by the food and drug administration.

Chemical germicidesA chemical or chemical combination used to eradicate microorganisms. Any procedure that removes and/or kills microorganisms is referred to as decontamination. The same phrase is also used to remove or neutralize radioactive materials, toxic compounds.A germicide is a substance that may eliminate microorganisms, particularly harmful ones (sometimes known as "germs"). Antiseptics and disinfectants are both considered germicides. Disinfectants are antimicrobials solely administered to inanimate items, whereas antiseptics are germicides applied to live tissue and skin.

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Related Questions

A 0.261 g piece of solid magnesium reacts with gaseous oxygen from the atmosphere to form solid magnesium oxide. in the laboratory a student weighs the mass of the magnesium oxide collected from this reaction as 0.254 g. what is the percent yield ?

Answers

The percent yield of [tex]MgO[/tex] is 58.79%

According to the following balanced reaction, magnesium interacts with oxygen to generate magnesium oxide:

[tex]2Mg + O_2 \rightarrow 2MgO[/tex]

Given mass of solid magnesium = 0.261g

Molar mass of Mg = 24g/mol

Using formula , [tex]Number of moles =\dfrac {mass} {molar mass} = \dfrac {0.261g} {24g/mol} = 0.0108mole[/tex]

We could theoretically make 0.0108 moles of [tex]MgO[/tex] since the reaction yields an equimolar quantity of [tex]MgO[/tex]. It is clear from the above reaction that 2 moles of magnesium result in 2 moles of magnesium oxide.

Hence, mass of [tex]MgO[/tex] = Number of moles [tex]\times[/tex] Molar mass of MgO

mass of [tex]MgO[/tex]  = [tex]0.0108mole \times 40g/mole = 0.432g[/tex]

Percent yield =  [tex]\dfrac{Actual mass of MgO} {Theoretical mass of MgO} \times 100[/tex]

                       =  [tex]\dfrac{0.254} {0.432} \times 100 = 58.79percentage[/tex]

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To all Moderators and Trusted Answerers or Grandmaster answerers please help me!!!

Copied Answer will be reported!​

Answers

You can do different chemical reactions at home, here I will show you 5 reactions you can try:

When the water begins to boil during cooking, a phase change is taking place between liquid water and gaseous water.Foods that contain substances to give flavor, color or help preserve conservation are also undergoing a reaction. Batteries use electrochemical reactions primarily to convert chemical energy into electrical energy.When books have yellowish pages, it is due to a reaction which is the decomposition of the cellulose in the paper.The photosynthesis that the plants in your garden do is also a reaction to make their own food.

MissSpanish

Carbon fiber (CFRC) is generally stronger than steel, however, steel has a density that is about ____ compared to carbon fiber.

Answers

Carbon fiber Vs Steel:

Steel has a density that is about five times more when compared to carbon fiber.

What is Carbon fiber (CFRC):

Carbon is an element that occurs naturally, and carbon fiber is made of this element. Because of its crystalline structure, carbon fiber possesses excellent tensile strength and stiffness capabilities. It is used to create lightweight composite parts that have great strength by wrapping the fiber in a polymer matrix.

What is steel:

Steel has long been a preferred material due to its high elasticity, which is around 200 GPa. Its relative abundance and stiffness have made it a widely used manufacturing material. However, because of its weight and density of around 8 g/cm3, it can be exceedingly difficult on the machines it is intended to protect. This weighs nearly five times as much as carbon fiber materials which would offer an equivalent or higher level of stiffness.

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A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°c. what is the specific heat of aluminum? express the answer to the hundredths place. joules over grams times degrees celsius

Answers

What is the specific heat of aluminum?

The specific heat of aluminum is 0.90J/g°C.

Given:

Heat absorbs = 677 J

Mass of the substance = 10 g

Initial temperature = 50°C

Final temperature = 125°C

Formula used:

Q = m x c x ΔT

which can also be written as,

Q = m x c x ( [tex]T_{final}[/tex] - [tex]T_{initial}[/tex] )

where,

Q = heat absorbs

m = mass of a substance

c = heat capacity of aluminum

[tex]T_{final}[/tex] = Final temperature

[tex]T_{initial}[/tex] = Initial temperature

Now, put all the values in the formula given above to get the specific heat of aluminum,

677g = (10g) x c x (125 - 50)°C

c = 0.9026 J/g°C

c = 0.90 J/g°C

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Answer: 0.90

Explanation:

How many moles of sodium atoms is 5.43 x 10^24 atoms of sodium? *

Answers

Answer:

9.02 moles Na

Explanation:

To find the amount of moles, you need to multiply the given amount by Avogadro's Number. This number allows you to convert from atoms to moles of any substance.

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

5.43 x 10²⁴ atoms Na                    1 mole
--------------------------------  x  ---------------------------------  = 9.02 moles Na
                                             6.022 x 10²³ atoms

4 b + 3 o2 → 2 b2o3 if 8 moles of b and 4 moles of o2 are allowed to react, how many moles of b2o3 can be formed?

Answers

The number of moles of  b2o3 that will be formed is determined as 4 moles.

Limiting reagent

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

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What does the strong nuclear force do?

Answers

The strong force binds quarks together in clusters to make more-familiar subatomic particles, such as protons and neutrons. It also holds together the atomic nucleus and underlies interactions between all particles containing quarks.

2. An almost empty natural gas storage tank contains 2.65 kg of methane gas at 650.5 kPa
and 18.0°C. What is the volume of the storage tank?

Answers

Considering the ideal gas law, the volume of the storage tank is 615.5987 L.

Ideal gas law

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.n is the number of moles of the gas.  

Volume of the storage tank

In this case, you know:

P= 650.5 kPa= 6.42 atm (being 101.325 kPa= 1 atm)V= ?T= 18 °C= 291 K (being 0 C= 273 K)R= 0.082 [tex]\frac{atmL}{molK}[/tex]n= 2.65 kg=  2650 g× [tex]\frac{1 mole}{16 gramos}[/tex]= 165.625 moles (being 16 [tex]\frac{g}{mole}[/tex] the molar mass of the methane)

Replacing in the ideal gas law:

6.42 atm× V = 165.625 moles ×0.082 [tex]\frac{atmL}{molK}[/tex]× 291 K

Solving:

V= [tex]\frac{165.625 moles x0.082 \frac{atmL}{molK}x291 K}{6.42 atm}[/tex]

V= 615.5987 L

Finally, the volume of the storage tank is 615.5987 L.

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An aqueous solution contains
32.7% KCI (weight/weight %).
What is the mole fraction of KCI in
this aqueous solution?
Molar Mass
KCI: 74.55 g/mol
H₂O: 18.016 g/mol
Enter text here
Enter

Answers

Answer:

0.105 KCl

Explanation:

(Step 1)

If the solution is 32.7% KCl, we can assume that there are 32.7 grams KCl in the solution. This means that there would be 67.3 grams H₂O (100% - 32.7% = 67.3%) in the solution.

32.7% KCl = 32.7 g KCl

67.3% H₂O = 67.3 g H₂O

(Step 2)

Now, we need to convert both the solute (KCl) and the solvent (H₂O) into moles. This can be done by multiply the grams of each substance by their molar masses.

32.7 g KCl              1 mole
------------------  x  --------------------  = 0.439 mole KCl
                               74.55 g

67.3 g H₂O           1 mole
------------------  x  -----------------  =  3.74 moles H₂O
                             18.016 g

(Step 3)

Finally, we can calculate the mole fraction of KCl using the following equation. The final answer should have 3 sig figs to match the given value with the lowest amount of sig figs (32.7 g).

                                             moles of solute
Mole Fraction  =  -----------------------------------------------------  
                              moles of solute + moles of solvent

                                            0.439 mole KCl
Mole Fraction  =  ------------------------------------------------------  
                              0.439 mole KCl + 3.74 moles H₂O

Mole Fraction  =  0.105 KCl

particles are always in the state of rest. true or false​

Answers

False

Explanation:

All the time particles are not at rest. Because in different types of matter particles act differently.

In liquid, particles are connected to each other but not they move in different directions.

In solid, particles are tightly connected to each other, there are no gap between them.

Lastly, in case of gas, particles move randomly here and there.

So, we conclude that particles are not always in state of rest.

Hope it help you

Ascorbic acid (Vitamin C) is a diprotic acid, H₂C6H6O6. What is the pH of a 0.10 M
solution? What will be the concentration of C6H6O62-? Ka1 = 7.9 x 105 and Ka2 = 1.6 x 10-12

Answers

The pH of the solution is 1.52 and the concentration of C6H6O62- is 2.2 * 10^-7 M.

What is the concentration of  C6H6O62-?

We know that;

H₂C6H6O6 ⇔HC6H6O6^-(aq)    +   H^+(aq) ----- (1)

Ka1 = 7.9 x 10^-5

Again;

HC6H6O6^-(aq) ⇔ C6H6O6^2-(aq)  +   H^+(aq) ------- (2)

Ka2 = 1.6 x 10^-12

Given that Ka2 <<<< Ka1 we have to apply equation 1 to obtain H^+ hence;

Ka1 = [HC6H6O6^-] [H^+]/[H₂C6H6O6]

Let  [HC6H6O6^-] = [H^+] =x

7.9 x 10^5 =x^2/0.1 - x

But x <<< 0.1 thus;

7.9 x 10^5 =x^2/0.1

x = √7.9 x 10^-5  * 0.1

x = 0.03 M

pH = -log(0.03 M)

pH = 1.52

To obtain  C6H6O6^2-;

Ka2 = [ C6H6O6^2-] [ H^+]/[HC6H6O6^-]

Also;

[ C6H6O6^2-] = [ H^+]= x

Now;

1.6 x 10^-12 = x^2/0.03 -x

But x<<<0.3

Hence;

1.6 x 10^-12 = x^2/0.03

x = √1.6 x 10^-12 * 0.03

x = 2.2 * 10^-7 M

The concentration of C6H6O6^2- is  2.2 * 10^-7 M.

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Compare the atomic sizes of sodium and magnesium. Explain. ​

Answers

Answer:

Sodium atom is larger than Magnesium atom.

Explanation:

Looking at the electronic configurations of Sodium and Magnesium:

[tex]_{11}Na: 1s^2 2s^2 p^6 3s^1\\\\_{12}Mg : 1s^2 2s^2 p^6 3s^2[/tex] ,

we can see that they both have their valence electrons in the 3rd shell.

But because Magnesium has a higher nuclear charge of +12 because of its 12 protons than that of Sodium's +11, the nucleus of Magnesium attracts its outer electrons more strongly than Sodium does. This makes the Magnesium atom smaller.

What is the symbol for temperature?

m

q

T

J

Answers

Answer:

T

Explanation:

m is mass

q is heat

J is energy

A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the pressure is increased to 10.5 atm?

Answers

Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

How many milliliters of an aqueous solution of 0.241 M chromium(II) nitrate is needed to obtain 19.6 grams of the salt

Answers

The volume of the solution (in mL) is 462.1 mL.

Molarity:

The concentration of a solution is calculated in terms of moles of a solute present per liter of the solution. This is known as molarity.

Calculations:

The molarity of the solution is 0.241 M or 0.241 mol/L. The molar mass of chromium (II) nitrate is 176.0 g/mol.

The volume of the solution is calculated as:

Molarity = Mass of chromium (II) nitrate/(Molar mass x Volume)

0.241 mol/L = 19.6 g/(176.0 g/mol x V)

V = 19.6 g/(176.0 g/mol x 0.241 mol/L)

= 0.4621 L

= 462.1 mL

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Anybody know the formula for this?

Answers

Answer:

Cr2H6O7S so this the answer hope its useful

In a test of Charles' law, a gas inside a cylinder with a movable piston is heated to
315°C. The initial volume of gas in the cylinder is 0.30 L at 25°C. What will be the final
volume when the ttemperature is 315°C?

Answers

Answer:

3.78 L

Explanation:

The Charles' Law equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the final volume by plugging the give values into the equation and simplifying.

V₁ = 0.30 L                    V₂ = ? L

T₁ = 25 °C                      T₂ = 315 °C

V₁ / T₁ = V₂ / T₂                                          <----- Charles' Law equation

(0.30 L) / (25 °C) = V₂ / (315 °C)                <------ Insert values

0.012 = V₂ / (315 °C)                                  <----- Divide 25 from 0.30

3.78 = V₂                                                   <----- Multiply both sides by 315

Using the name of the ionic compound, select the appropriate chemical formula. Use the periodic table
that has been provided. Click here to access the common polyatomic ion sheet
Ammonium Phosphate

Answers

The compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

What is an ionic compound?

An ionic compound is  compound that is composed of ions. We know that a poly atomic ion is an ion that contains more than one atom.

Looking at the options that have been provided, we know that the correct formula for the compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

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WILL GIVE BRAINLIEST

Question 9(Multiple Choice Worth 5 points)
(01.02 LC)
Which of the following is true about the weight of an object?
O It remains same for the object.
O It cannot be measured accurately.
O It is a force acting on the object.
O It is always less than the mass of the object.
PLS HELP

Answers

Answer:

It is a force acting on the object.

Explanation:

The answer option which is true about the weight of an object is: C. It is a force acting on the object.

Weight can be defined as the force acting on a physical body or an object as a result of gravity. Also, the weight of an object is measured in Newton.

Mathematically, the weight of an object is given by the formula;

Where;

m is the mass of the object.

g is the acceleration due to gravity.

In conclusion, the weight of an object is the force acting on an object due to gravity.

Which statement about the diagram, if electrons flow from
the right half-cell to the left one through the wire, is true?
The metal on the left oxidizes more easily than the
one on the right.
The metal on the right oxidizes more easily than the
one on the left.
You cannot tell from this system which metal is more
easily oxidized.
solid
Ag
AgNO
solution
Ag electrode
salt bridge
KNO, solution
light bulb
Cd(NO₂
solution
Cd electrode
solid
Cd

Answers

The true statement is that the metal on the right oxidizes more easily than the one on the left.

What is metal oxidization?

Metal oxidation is known to often occur if an ionic chemical reaction is said to take place on a metal's surface at the presence of oxygen.

Note that Electrons often move from the metal to the oxygen molecules in course of this  process and as such The true statement is that the metal on the right oxidizes more easily than the one on the left.

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which of the following measurements are listed in the proper mathematical relationship?

A. P/V=K
B. PV=K
C. PV/T=K
D. V/T=K

Answers

Answer:

PVT upon t is equal to k p is equal to k p v is equal to k p upon t is equal to K2

Explanation:

correct answer is d

The measurement that is listen in proper mathematical relationship is PV=K and V/T =K. Option B and D are correct.

Boyle’s law derived the conditions of the sample of a gas in two different conditional pressure and volume. The initial observation was that the product of a given pressure and volume for the sample of gas at a constant temperature is observed to be constant.

Therefore,

PV= constant

PV=K

The two temperature conditions were thus observed and the equation was elaborated to be,

P₁V₁=P₂V₂

On the other hand, Charle's law state that the volume of a fixed mass of a gas is directly proportional to it's absolute temperature, provided that the pressure remains constant. It is represented as V/T =K

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What is the freezing point, in °C, of
a 0.655 m solution of C4H10 in
benzene?
FP (benzene) = 5.5 °C
Kr(benzene) = 5.12°C/m
[?] °C
Give your answer to the thousandths place.
Freezing Point
Enter

Answers

The freezing point of the solution is - 2.15.

What is the freezing point?

The freezing point is the point at which a liquid is changed to solid. We can use the formula;

ΔT = K m I

ΔT = temperature change

K = freezing constant of benzene

m = molality

i = Van't Hoff factor

Now;

ΔT =  5.12°C/m * 0.655 m  * 1

ΔT = 3.35°C

ΔT = Freezing point of pure benzene - Freezing point of solution  

Freezing point of solution  = ΔT -  Freezing point of pure benzene

= 3.35°C -  5.5 °C = - 2.15

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Answer:

2.143 degrees celsius

Explanation:

what might be a scientific question

Answers

Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

The oxidation number of an element in a compound is equal to the charge the atoms would have if the compound was ___________. Select the correct answer below: ionic covalent molecular

Answers

The oxidation number of an element in a compound is equal to the charge of the atoms if the compound was an ionic compound.

What are types of compounds and how their oxidation number is calculated?

The types of compounds are:

Ionic compoundsCovalent compounds and Molecular compounds

Ionic compounds:

When a metal reacts with a non-metal an ionic compound is formed.The metal and ono-metals share electrons in between them and forms an anion and a cation respectively.The oxidation number of an ionic compound is equal to the charge of the ion.For a polyatomic ion, the sum of the oxidation numbers is equal to the charge of the ion.

Covalent compound:

When non-metals reacts together a covalent compound is formed.They share electrons in between them by forming a covalent bond.The oxidation number of a covalent compound is the charge that results when the electrons are assigned to the more electronegative atom.

Molecular compounds:

Molecular compounds are like the covalent compounds shares a covalent bond in between the atoms.The oxidation number of a molecule is given by gaining or losing of an electron by the atoms in it.

Therefore, the oxidation number of an element in a compound is equal to the charge of the ion that would have if the compound was an ionic compound.

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In molecules, c, h, o, and n atoms usually make __, __, __, and __ bonds respectively

Answers

Answer:   " 4, 1, 2, 3."

_______________
  " In molecules, C, H, O, and N atoms  usually make _4_, _1_, _2_, and  

_3_ bonds, respectively."
_______________
Note the following mnemonic device:

" H O N C " —>  "Honc" if you love molecules!"

  1   2  3  4 ;

{"hydrogen"} H → 1

{"oxygen"} O  → 2

{"nitrogen"} N → 3

{"carbon"} C → 4

___

So:  by using this mnemonic:
H  O  N  C ;

1   2   3   4 ;
___
We can answer the question:
" C, H, O,  N " → in sequence:
" 4,  1,  2,  3 " ;

{just use the corresponding numbers as per the mnemonic device.}.
The answer:  
" 4, 1, 2, 3 ".

Hope this is helpful to you!  Best wishes!

The value of Gfor a reaction conducted at 25C is 2.8 KJ/mol. The equilibrium for a reaction is _____ at this temperature.

Answers

The equilibrium constant of the reaction is 0.323.

Equilibrium constant:

It is expressed as the ratio of concentration of the products to the concentration of reactants. It is represented by K.

The relationship of K with G (Gibbs free energy) is expressed as:

G° = -RTlnK

Here R is the gas constant, T is the temperature.

Calculations:

Convert 25°C to K.

25°C = (25 + 273.15) K

= 298.15 K

Substitute the values in the above expression.

2.8 x 1000 J/mol = -8.314 J/mol.K x 298.15 K x ln(K)

lnK = 2800 J/mol/(-8.314 J/mol.K x 298.15 K)

lnK = -1.13

K = e^-1.13

  = 0.323

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2. How many molecules are contained in 25 L of N₂ at S. T.P.?

Answers

Explanation:

How many nitrogen molecules are in 1 liter of nitrogen gas at STP?

Answer

2

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Pete Gannett

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:

# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

Answer:

6.721 x 10 ^23 molecules

Explanation:

At STP an ideal gas has 22.4 liters per mole

25 liters / 22.4 liters/mole = 1.11607 moles

1.11607 moles *   6.022 x 10^23  molecules/mole = 6.721 x 10^23 molecules

Which is the correct mole ratio of
K PO to KNO in the chemical
reaction
Mg(NO₂)₂ (aq) + K,PO (aq) -->
Mg (PO )₂(aq) + KNO₂(aq)?

Answers

The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3

Balanced equation

3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)

from the balance equation,

The number of mole of K₃PO₃ = 2 molesThe number of mole of KNO₂ = 6 moles

How to determine the mole ratio of K₃PO₃ and KNO₂Number of mole of K₃PO₃ = 2 molesNumber of mole of KNO₂ = 6 molesMole ratio of K₃PO₃ and KNO₂ =?

Mole ratio = mole of K₃PO₃ / mole of KNO₂

Mole ratio of K₃PO₃ and KNO₂ = 2 / 6

Mole ratio of K₃PO₃ and KNO₂ = 1 : 3

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Which of the following statements is true?
A. A high atom economy means that most of the starting materials end up as waste products.
B. The actual yield of a reaction is the amount of product you expected to make.
OC. A reaction with a high percentage yield is an efficient reaction.
D. The percentage yield of a reaction can be over 100%.

Answers

Answer:

B. The actual yield of a reaction is the amount of product you expected to make.

Explanation:

The actual yield of a reaction is the quantity of a product that is obtained from a chemical reaction. Therefore part B is the right solution to our question since it is true that actual yield of a reaction is the amount of product you expected to make.

If a radioactive decay produced 1.26 × 1012 J of energy, how much mass was lost in the reaction?

Answers

The mass lost in the process is 1.4 * 10^-5Kg.

What is the Einstein equation?

The Einstein equation is able to relate the mass lost to the energy that is evolved in a nuclear process.

Given that;

E = Δmc^2

Δm = E/c^2

Δm =  1.26 × 10^12 J/( 3 * 10^8)^2

Δm = 1.4 * 10^-5Kg

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