Answer:
Answer: 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.
Explanation:
To calculate the moles of silver formed and the moles of excess reagent left after the reaction, we need to balance the equation first and need to find the limiting and excess reagent.
The balanced chemical equation is:
Zn + 2AgNO3 ---> Zn (NO3)2 +2Ag
By Stoichiometry:
2 moles of Silver nitrate reacts with 1 mole of Zinc metal
So, 6.5 moles of silver nitrate will react with = 1/2 x 6.5 = 3.25 moles of zinc metal
The required amount of zinc metal is less than the given amount of zinc metal, hence, it is considered as an excess reagent.
Therefore, silver nitrate is the limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of silver nitrate produces 2 moles of silver metal
So, 6.5 moles of silver nitrate will produce = 2/2 x 6.5 = 6.5moles of silver metal.
Number of moles of excess reagent left after the completion of reaction = (3.8 - 3.25)moles = 0.55 moles
Hence, 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.
3. as a substitution reaction occurs, the number of electrons shared between
carbon atoms
a) increases
b) decreases
c) remains the same
c) remains the same
In a substitution reaction, number of electrons remain the same.
What is a substitution reaction?
When one functional group in a chemical molecule is replaced by another functional group, the chemical reaction is known as a substitution reaction.
It is also known as single displacement reaction or single replacement reaction.
Example: Iodoethane and water are produced when hydrogen iodide and ethanol combine.
CH₃CH₂OH + HI → CH₃CH₂I + H₂O
In this reaction OH is substituted or replaced by I giving CH₃CH₂I.
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I need help with this ASAP pls
Answer:
2c 1s
Expination: it came by there are 2carbon and 1sulphur
Answer:
2c1s
Explanation:
2c1s make me brainlist
You are a paleontology professor working at a dig site looking for fossils. You come across a deposit that is emitting radiation. Upon further testing you find that the sample is changing from carbon (atomic number 6) into nitrogen (atomic number 7) as radiation is emitted. What type of radiation is it?
A. Gamma
B. Delta
C. Beta
D. Alpha
The type of radiation in this scenario is Beta and is denoted as option C.
What is Beta radiation?This is a high-speed electron which is emitted when the nucleus undergoes a radioactive decay during the process of beta decay.
In this scenario the electron is denoted as e with a superscript and subscript of 0 and -1 respectively which is the reason for the change from carbon to nitrogen.
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Sorry this is a bit long
b. The following reaction takes place in an acidic solution. Use the following steps to balance the equation. (5 points)
Zn(s) + NO3–(aq) Zn2+(aq) + NO(g)
i. Write the reduction and oxidation half-reactions (without electrons). (1 point)
ii. Balance the equations for atoms. Use H2O and H+ to balance O and H. (1 point)
iii. Balance the equations for charge. (1 point)
iv. Equalize charges for the two half-reactions. (1 point)
v. Add the equations and simplify to get a balanced equation. (1 point)
The overall balanced reaction equation is;
4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)
What is the balanced reaction equation?The redox reaction equation is said to be balanced when the number of electron gained is equal to the number of electrons lost.
Now;
1. Reduction and oxidation half-reactions
Zn(s) -----> Zn^2+(aq) + 2e
And
NO3^-(aq) ---->NH4^+(aq) + 3H2O(l)
2. Using the H2O and H+ to balance O and H;
4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)
3. Balancing the electrons lost and gained; 4Zn(s) + 10H^+(aq) + NO3^-(aq) + 8e -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l) + 8e
4. The overall balanced reaction equation is;
4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)
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a. The dissociation constant of the weak acid HF is K₂ = [H][F]. If at equilibrium
Ka
[HF]
the concentrations of H* and F are each 2.6 x 10-3 M and the concentration of
HF is 0.010 M, what is K₂ for HF? (3 points)
Answer:
6.76*10^-4 , or 6.8*10^-4 if you consider sig figs
Explanation:
This is a bit of a confusing question, since it incorrectly states that the acid disassociation constant is simply [H+][F-].
Ka = [H+][F-]/[HF] , so plugging in the values, we get
[tex]K=\frac{[2.6*10^{-3}][2.6*10^{-3}]}{[0.01]}\\K=\frac{[2.6*10^{-3}]^2}{[0.01]}\\K=0.000676=6.76*10^{-4}[/tex]
If we were to use the equation in the question, Ka=[H+][F-], we would get the answer 6.76 * 10^-6 , which is not the Ka for HF
Cold solvents are preferred for recrystallization because Group of answer choices Hot solvents catch fire easily to prevent dissolution of the crystals impurities are expected to have high solubility in cold solvents Cold solvents are cost effective
Crystals impurities are expected to have high solubility in cold solvents. Hence, option C is correct.
What is a cold solvent?Cold solvent cleaning is a process used to remove grease, wax and other impurities from metal and other parts.
The process is also called degreasing. Cold solvents are sprayed onto the dirty part and it is brushed clean.
Once the filtration process is done the collected crystals should be washed with a little more ice-cold solvent to remove final soluble impurities which would otherwise be left on the surface of the crystals.
Hence, option C is correct.
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300 mL of salt solution contains 6.5 grams of NaCl (molecular mass of sodium chloride is 58.44 ul.
What is its molarity?
M=n/V
M=(6.5/58.44) mol : 0.3 L
M=0.371
Answer:
.371 M
Explanation:
Molarity, M, is calculated as moles solute/ liters of solvent
6.5 gms of salt is 6.5 / 58.44 = .111225 moles
300 ml = .3 L
.111225 moles / .3 L = .371 M
What's the difference between a sigma bond and pi (π) bond?
Also, please state the three types of hybridization.
Answer:
Sigma bonds are formed by the Head-to-head overlapping of atomic orbitals while Pi bonds are formed by the lateral overlapping of two atomic orbitals.Types of hybridization:1) sp hybridization.2) sp² hybridization.3) Sp^3 hybridization.Hope this helps.Good luck ✅.A gas at 300 k and 4.0 atm is moved to a new location with a temperature of 250 k. the volume changes from 5.5 l to 2.0 l. what is the pressure of the gas at the new location? use the formula: p1v1 t1 = p2v2 t2
Answer:
9.17 atm
Explanation:
To find the new pressure of the gas, you need to use the following manipulated formula:
P₁V₁ / T₁ = P₂V₂ / T₂
In this formula,
P₁ = initial pressure (atm) P₂ = new pressure (atm)
V₁ = initial volume (L) V₂ = new volume (L)
T₁ = initial temperature (K) T₂ = new temperature (K)
Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.
P₁ = 4.0 atm P₂ = ? atm
V₁ = 5.5 L V₂ = 2.0 L
T₁ = 300 K T₂ = 250 K
P₁V₁ / T₁ = P₂V₂ / T₂ <----- Given formula
(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K) <----- Insert variables
0.073333 = P₂(2.0 L) / (250 K) <----- Simplify left side
18.33333 = P₂(2.0 L) <----- Multiply both sides by 250
9.17 = P₂ <----- Divide both sides by 2.0
Answer:
=> 13.2 atm
Explanation:
From the question, we have question we have been provided with pressure, volume and temperature. Based on these variables, we are supposed to use the combined gas law formula (P1V1T1 = P2V2T2)
At location 1;
P1 = 4.0 atm
V1 = 5.5 L
T1 = 300 K.
At location 2;
P2 = ?
V2 = 2.0 L
T2 = 250 K.
We are required to determine the pressure (P2).
To begin, we make pressure (P2) the subject of in the formula:
P2 = (P1V1T1)/(V2T2) ................ eq. (i)
Then substitute the known values into the eq. (i).
P2 = (4.0 x 5.5 x 300)/(2.0 x 250) atm
= 13.2 atm.
Therefore, the pressure (P2) at location 2 is 13.2 atm.
A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The calorimeter and the water have a combined mass of 250.0 g and an overall specific heat of 1.035 cal/g•°C. The initial temperature of the calorimeter is 10.00°C. The system reaches a final temperature of 11.08°C when the metal is added.
Taking into account the definition of calorimetry, the specific heat of metal is 0.165 [tex]\frac{cal}{gC}[/tex].
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.C is the specific heat substance.ΔT is the temperature variation.Specific heat capacity of the metalIn this case, you know:
For metal:
Mass of metal = 50 gInitial temperature of metal= 45 °CFinal temperature of metal= 11.08 ºCSpecific heat of metal= ?For water:
Mass of water = 250 gInitial temperature of water= 10 ºCFinal temperature of water= 11.08 ºCSpecific heat of water = 1.035 [tex]\frac{cal}{gC}[/tex]Replacing in the expression to calculate heat exchanges:
For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)
For water: Qwater= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× (11.08 C - 10 C)
If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.
Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:
- Qmetal = + Qwater
- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× (11.08 C - 10 C)
Solving:
- Specific heat of metal× 50 g× (-33.92 C)= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× 1.08 C
Specific heat of metal× 1696 g×C= 279.45 cal
Specific heat of metal= [tex]\frac{279.45 cal}{1696 gC}[/tex]
Specific heat of metal= 0.165 [tex]\frac{cal}{gC}[/tex]
Finally, the specific heat of metal is 0.165 [tex]\frac{cal}{gC}[/tex].
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a 3.140 molar solution of NaCl is prepared. how many grams of NaCl are present in a sample containing 3 kg of water
Identify the Bronsted-Lowry base:
the numbers are subscripts.
Group of answer choices
a)KOH
b)BF3
c)KCl
d)Her
Answer:
Bronsted-Lowry's base is A)KOH
KOH
KOH on dissolving in water gives two ions K+ and OH-OH- can accept one H+As it accepts proton it acts as bronsted Lowry baseFerric chloride is being applied for coagulation at a 15.0 MGD surface water treatment plant, at a rate of 195 pounds per day. At this application rate, how many pounds of this chemical will be used in a 30-day month
5850 pounds of this chemical will be used in a 30-day month.
195 pounds per day.
So, 30 days = 195 * 30
= 5850 pounds
Iron(III) chloride is the inorganic compound with the components FeCl 3. additionally known as ferric chloride, it is a commonplace compound of iron inside the +3 oxidation country. The anhydrous compound is crystalline and stable with a melting point of 307.6 °C.
The primary use of ferric chloride is to dispose of impurities in water and for wastewater treatment. Ferric chloride is likewise one of the few water remedy chemical compounds that can sequester odors.
Reasonably poisonous with the aid of ingestion but a strong irritant to the skin and eyes. it's far moderately corrosive and skin touch should be avoided and avoid skin and eye contact.
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Will a real gas ever reach absolute zero? Will an ideal gas ever reach absolute zero? Why or why not? Compose a report that answers these two questions. 125 words.
It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high.
What is the absolute zero?The absolute zero is the temperature at which the movement of all the gas molecules is theoretically believed to cease. At the absolute zero, gas molecules remain at fixed positions because according to the third law of thermodynamics, the entropy of a perfectly ordered system is zero.
It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high such that it is impractical to attain the absolute zero.
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How can the arrangement of furniture in a room influence an individual’s behavior?
a.
The arrangement of furniture in a public room can either encourage or discourage social interaction.
b.
The arrangement of furniture in a room can influence an individual’s attitude toward survival.
c.
An individual’s overall mental health can be severely negatively impacted by the arrangement of furniture in a room.
d.
An individual’s behavior cannot be influenced by the arrangement of furniture in a room.
Please select the best answer from the choices provided
The arrangement of furniture in a public room can either encourage or discourage social interaction. The correct option is A.
What is social interaction?It is the process of exchanging information with others, verbally or otherwise.
The arrangement of furniture in a room filled with people can go a long way to encourage or discourage social interactions.
If physical barriers are put in between two seats such that people can barely see each other, the message may be that very little to no social interaction is allowed.
Without any physical barriers between seats, the message may be that people are free to interact, all other things being equal.
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In forming a molecular compound, each atom should have ______ electrons around it unless there is some specific reasons why this cannot be achieved.
In forming a molecular compound, each atom should have valence electrons around it unless there is some specific reasons why this cannot be achieved.
What is Valence Electrons ?Valence electrons is a negatively charged particle present in the outermost shell of an atom.
Example: Oxygen has 6 valence electrons in its outermost shell, Water has 8 valence electrons.
Thus from the above conclusion we can say that In forming a molecular compound, each atom should have valence electrons around it unless there is some specific reasons why this cannot be achieved.
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3.03 Plate Tectonics
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name
Boundary Type
(C=Convergent, D=Divergent, or T=Transform)
Year Observed
(5, 10, or 20 million years)
Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas
5
Event 1-
20
Event 2-
Location Two
East Africa
5
Event 1-
10
Event 2-
20
Event 3-
Location Three
San Andreas fault zone
5
Event 1-
10
Event 2-
20
Event 3-
Location Four
Aleutian Islands
5
Event 1-
20
Event 2-
Location Five
Mid-Atlantic Ridge
5
Event 1-
10
Event 2-
20
Event 3-
Location Six
Alpine Fault
5
Event 1-
20
Event 2-
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.
The types of geological events or changes that occur at divergent plate boundaries are earthquakes and magma because there is a fault when two plates move away from each other.
The types of geological events or changes that occur at convergent plate boundaries are earthquakes, volcanoes, and the formation of mountains because the tectonic plates are moving towards each other.
The types of geological events or changes that occur at transform plate boundaries are shallow earthquakes, lateral displacement of rock, and a broad zone of crustal deformation.
These geological processes have changed the surface of the earth as they have helped to form ocean basins, and mountain chains, and the formation of glaciers and volcanoes, and earthquakes have changed the underground geology of the earth.
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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the temperature is 298 K.
A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.
What is Combined Gas Law ?This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.
It is expressed as
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
where,
P₁ = first pressure
P₂ = second pressure
V₁ = first volume
V₂ = second volume
T₁ = first temperature
T₂ = second temperature
Now put the values in above expression we get
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
[tex]\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}[/tex]
[tex]P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}[/tex]
P₂ = 1.76 atm
Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.
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Set up the math problem. But don’t do any of it. Just leave your answer as a math expression. Also be sure you’re answering clues all the correct the units symbols.
Answer:
Length = 681 grams / (44.5 grams / kilometers) = (681 / 44.5) kilometers
Explanation:
The diameter is there to throw us off, so ignore that. There is 681 grams of wire, and since there is 44.5 grams of copper per km of wire, and we want to know how many kilometers of wire makes 681 grams, the equation would be X*44.5 = 681, or X = 681/44.5
Also quora's censoring system is terrible i can't even say kilometers by adding the letter s after "km"
At constant pressure, the ratio between the volume expansion of a mole of gas with a high Cp to that of a mole of gas with a low Cp for a given heat input will be
At constant pressure, the ratio between the volume expansion of a mole of gas with a high Cp to that of a mole of gas with a low Cp for a given heat input is Less than 1.
How are Cp and Cv related to one another?The molar heat capacity of a substance is expressed as Cp when the pressure is constant and as Cv when the volume is constant. These two parameters so describe the molar heat capacity at various pressures and temperatures.
Constant Volume and PressureThe first law of thermodynamics states that heat delivered to a system can either be converted into internal energy or used to generate work in the environment. An isochoric process is one in which the volume is constant, whereas an isobaric process is one in which a gas interacts with its surroundings at constant pressure.
Constant PressureAn isobaric process takes place at constant pressure. Since the pressure is constant and the work is denoted by PV, the force applied is constant.
If gas is to expand at an isobaric pressure at a certain pressure, heat must be introduced into the system at a specific rate. For instance, a movable piston in a cylinder keeps the pressure inside the cylinder constant at atmospheric pressure despite the fact that it is isolated from the atmosphere. In other words, a moveable barrier serves as a dynamic link between the system and a constant-pressure reservoir.
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Write the complete chemical formula for the unknown compound.
The complete chemical formula for the unknown compound will be [tex]C_2H_6[/tex]
Chemical formulaThe chemical formula of the compound is [tex]C_2H_x[/tex] and x is supposed to be a whole number.
In the analysis, C = 2.22 moles and H = 6.7 moles
Dividing both by the smallest: C = 1 and H = 3
Thus, the empirical formula of the compound will be [tex]CH_3[/tex]
But since the compound is [tex]C_2H_x[/tex], it means both C and H are multiplied by 2.
The chemical formula will, therefore, be [tex]C_2H_6[/tex]
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Use distributive law evaluate
Answer:
The distributive property of multiplication is used when we need to multiply a number with the sum of two or more addends. The distributive property of multiplication is applicable to addition and subtraction of two or more numbers.
Hope its helpful!
Answer:
The distributive property of multiplication is used when we need to multiply a number with the sum of two or more addends. The distributive property of multiplication is applicable to addition and subtraction of two or more numbers.
Explanation:
enna took an open bowl of leftover mashed potatoes from the refrigerator and noticed a difference in smell. She determined that chemical changes occurred since the potatoes were first placed there.
Which observations most likely led to Jenna’s conclusion?
a change of odor
a decrease in temperature
a change in moisture content
a decrease in mass
2. The force of attraction between the particles is greater in ice than in water.
True or false
Answer:
true
Explanation:
your answer is ture
The statement is true: the force of attraction between particles is greater in ice than in water.
The force of attraction between particles (molecules or atoms) is greater in ice than in water. In the solid state, such as in ice, the particles are closely packed in a regular crystalline structure. The intermolecular forces, specifically hydrogen bonding between water molecules, are strong, leading to a higher force of attraction.
In contrast, in the liquid state, such as in water, the particles have more freedom of movement. The intermolecular forces are still present but are weaker compared to the solid state, resulting in a lower force of attraction between the particles.
Therefore, the statement is true: the force of attraction between particles is greater in ice than in water.
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Samples of this drawing medium have been dated back to 30,000 BCE. Group of answer choices silverpoint charcoal pencil color pencil pastel
Charcoal is the sample of this drawing medium have been dated back to 30,000 BCE and is denoted as option B.
What is Charcoal?This is referred to a black carbon residue which is heated in insufficient oxygen to give it a light weight.
It is used for drawing and has been in existence for as long as 30,000 BCE hence the reason why it is the most appropriate choice.
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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.
Reaction stoichiometryIn first place, the balanced reaction is:
N₂ + 3 H₂ → 2 NH₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
N₂: 1 moleH₂: 3 molesNH₃: 2 molesThe molar mass of the compounds is:
N₂: 14 g/moleH₂: 2 g/moleNH₃: 17 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
N₂: 1 mole ×14 g/mole= 14 gramsH₂: 3 moles ×2 g/mole= 6 gramsNH₃: 2 moles ×17 g/mole=34 gramsMass of NH₃ formedThe following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?
[tex]moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}[/tex]
moles of NH₃= 5.33 moles
Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.
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You have been asked to determine the thermometer correction for a melting point apparatus. You obtain a pure sample of benzoic acid and determine its melting point range carefully. After several trials, you obtain a very sharp melting point of 125.7 degrees celsius. What is the thermometer correction at this temperature
The thermometer correction at this temperature is =125.7 -122.4
=3.3 degrees celsius
(Very pure benzoic acid has a melting point of 122.4 degrees Celsius.)
ThermometerA thermometer is a device used to measure and display temperature. It normally consists of a short, glass tube that is hermetically sealed, graduated, and has a mercury or alcohol bulb at one end that expands and contracts with temperature changes.
Calibration of thermometers:-A significant source of measurement error in melting points could be our thermometer. It is occasionally possible for ordinary laboratory thermometers to be inaccurate and to read temperatures up to 10°C high or low. we should calibrate your thermometer regularly to identify any errors and be able to make adjustments. This will help us avoid this issue.
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What mass of Na2CrO4 is required to precipitate all of the silver ions from 75.0 mL of a 0.100 M solution of AgNO3
The mass of [tex]Na_2CrO_4[/tex] required will be 0.6075 g.
Calculation of mass:
The reaction:
[tex]Na_2CrO_4 + 2AgNO_3 \rightarrow Ag_2CrO_4 + 2NaNO_3[/tex]
Volume of [tex]AgNO_3[/tex] = 75 mL
Concentration of [tex]AgNO_3[/tex] = 0.100 M
Step 1:
Molarity is moles of solute in 1000 mL of the solution.
[tex]M=\frac{n}{V}\times 1000\\\\ n=\frac{M\times V}{1000} \\\\n=\frac{0.100\times 75}{1000}\\\\n= 0.0075[/tex]
Moles of [tex]AgNO_3[/tex] = 0.0075
Step 2:
From the above equation,
2 moles of [tex]AgNO_3[/tex] is precipitated by 1 mole of [tex]Na_2CrO_4[/tex]
So, 0.0075 moles will be precipitated by-
[tex]\frac{1}{2}\times 0.0075[/tex] moles of [tex]Na_2CrO_4[/tex]
= 0.00375 moles of [tex]Na_2CrO_4[/tex]
Step 3:
[tex]mole=\frac{Given \,weight}{Molar\, mass} \\[/tex]
Molar mass of [tex]Na_2CrO_4[/tex] = 162 g/mol
[tex]0.00375=\frac{x}{162} \\x= 0.00375\times 162\\x= 0.6075 g[/tex]
So, Mass of [tex]Na_2CrO_4[/tex] required will be 0.6075 g.
Learn more about Dilution factor here:
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A teacher divides her class into groups and assigns each
group the task of measuring the mass of the same object
three times. The teacher already knows that the mass of
the object is 25 g.
Based on the results each group records, which group makes the most
precise measurements of the object?
O
A. Group C: 32.1 g, 35.0 g, 25.0 g
O
B. Group B: 25.5 g, 25.0 g, 24.8 g
O
C. Group A: 28.5g, 28.4 g, 28.5 g
O D. Group D: 20.0 g, 25.0 g, 30.09
Answer:
Group C
Explanation:
Precision is how close the values are to each other
what is a neutral atom of nitrogen-14
Answer:
You know that nitrogen-14 has 7 protons in the nucleus because it is an isotope of nitrogen, which has an atomic number equal to 7 . Because nitrogen-14 is a neutral atom, the number of protons it has in its nucleus must be equal to the number of electrons that surround its nucleus.