Answer:
This question appears incomplete
Explanation:
The question appears incomplete. However, a thrust can be described as a force or a push. A cart can be described as a vehicle (usually with two wheels) that is used to transport load from one point/place to another.
Newton first law of motion (law of inertia) states that a body will continue to be in a state of rest or if in motion, remains in motion (at constant velocity) unless acted upon by an external force. Hence, a cart will continue to be in a state of rest unless acted on by an external force which can be exerted by animals or humans (depending on the type of cart).
What is the dependent variable in this hypothesis?
After finding that objects of the same mass do not
always float or submerge the same way in a tub of
liquid, Alexis wrote a new hypothesis to test objects that
have the same mass.
o the mass of the object
O the surface area of the object
O the amount of water displaced
O the height at which the object floats
If the surface area of an object increases, then it
will float higher in the tub, because the object
would need to displace more liquid in order to sink
all the way down.
Answer:
The height at wich the object floats
Explain
took on edge 2020
Answer:
the height at which the object floats
Edge 2021
The position of a particle
Answer:
vector
Explanation:
The position of a particle is vector
What is the magnitude of the thrust force before the cart is released?Express your answer in newtons using three significant figures.
Answer:
Hello your question is incomplete below are missing parts
In this video, a small cart that has a mass of 600 grams rests on a table top. There is a fan on top of the cart, blowing air backwards at a steady rate. A stretched spring is attached to the back of the cart by a string, holding it in place. A scale, marked off in newtons, is positioned next to the spring and a small dot at the end of the spring indicates the magnitude of the spring force. The spring and scale together is called a “dynamometer.” Before the cart is released from the spring, the dynamometer reads approximately 1.9 newtons. The video is recorded at 60 frames per second, resulting in playback motion 2 times slower than normal. A frame counter indicates the current frame. A horizontal distance scale, marked off in centimeters, is also shown on the video. While the cart is at rest, the front edge of the front wheel is at the zero of the scale.
At frame 245, the string that attaches the cart to the spring is cut, releasing the cart, and it begins to roll forward. Using the distance scale, the position of the front edge of the front wheel can be tracked with
time. The following table indicates the position at different frames.
Frame Position (cm)
245 0.0
251 1.9
257 6.0
263 13.9
269 24.6
275 38.4
281 55.1
287 75.0
Answer : 1.9 N
Explanation:
The magnitude of the thrust force before the cart is released can be calculated as :
60 fbs = 1 frame = 1/60 secs
therefore 6 frames = 1 / 10 secs
F fam = F spring = 1.9 N
Note: F thrust = F fam = 1.9 N
what role do control groups play
Answer:
Control groups let the one who is expermenting compare the effect of the varibles in the expermental group.
Explanation:
A nucleus with a mass number of 64 has a mean radius of about: _________.
A. 4.8 fm.
B. 19 fm.
C. 77 fm.
D. 260 fm.
E. 2.6 × 10 5 fm
Answer:
The correct option is A
Explanation:
From the question we are told that
The mass number is [tex]A= 64[/tex]
Generally the mean radius is mathematically evaluated as
[tex]R = R_o A^{\frac{1}{3} }[/tex]
Here [tex]R_o[/tex] is a constant with a value [tex]R_o =1.2*10^{-15}[/tex]
So
[tex]R = 1.2*10^{-15} * 64^{\frac{1}{3} }[/tex]
[tex]R = 4.8 *10^{-15} [/tex]
[tex]R = 4.8\ fm [/tex]
The mean radius of a nucleus with the given mass number is 4.8 fm.
Hence, Option A. 4.8 fm is the correct answer.
Given the data in the question;
Mass number of nucleus; [tex]A = 64[/tex]
Mean radius; [tex]R =\ ?[/tex]
The volume of the nucleus is directly proportional to the total number of nucleons.
The radius of a nucleus, R, is approximately:
[tex]R = R_oA^{\frac{1}{3} }[/tex]
Where R is the radius, R₀ is constant for all nuclei ([tex]1.2*10^{-15}m \ or\ 1.2fm[/tex] ) and A is the mass number.
We substitute our values into the equation
[tex]R = 1.2fm\ *\ 64^{\frac{1}{3} }\\\\R = 1.2fm\ *\ 4\\\\R = 4.8 fm[/tex]
The mean radius of a nucleus with the given mass number is 4.8 fm.
Hence, Option A. 4.8 fm is the correct answer.
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Which of the following statements about slope is NOT true?
Explanation:
did you upload a picture?
What is the mass of the cube
Density is 40 g/cm3
Length of the side= 2 cm
Answer:
80
Explanation:
because of the denstiy formula
Complete the sentence with the word "element" or "compound." O is a(n) and H2O2 is a(n)
Answer:
O is an element whilst H2O2 is a compound.
Explanation:
O is an element. You can find it on the periodic table. H2O2 is composed of both H and O. Thus, H2O2 is a compound.
The O is a(n) element and [tex]H_{2} O_{2}[/tex] is a(n) compound.
What is element?All facets of a species of atoms with a specific count of protons in its nuclei are referred to as chemical elements, such as the pure substance made exclusively of the that species.
What is compound?A compound comprises a substance created by the chemical fusion of two or more components.
Therefore, the O is a(n) element and [tex]H_{2} O_{2}[/tex] is a(n) compound.
To know more about compound and element.
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A box measures 3.12 ft in length, 0.0455 yd in width and 7.87 inches in height. Since volume can be found using length x width x height, find the volume in cubic centimeters. Now find the volume in gallons.
Explanation:
This problem is on units conversion
given the dimensions
3.12 ft in length,
0.0455 yd in width and
7.87 inches in height
we have to convert to cm first
3.12 ft to cm=
1 ft-------30.48cm
3.12--------x
x=95.09cm
0.0455 yd to cm
0.0455yd ft to cm=
1 yd-------91.44cm
0.0455--------x
x=4.16cm
7.87 in to cm
1 in-------2.54cm
7.87--------x
x=19.98cm
the volume is =95.09cm*4.16cm*19.98cm
volume= 7907.45cm^3
the volume in gallon is
1 cm^3------0.000264172gal
7907.45cm^3-------x
x=7907.45*0.000264172
x=2.088gallons
A runner completes the 300-meter dash in 38 seconds. What is the speed of the runner? Round your answer the answer to the nearest tenth.
Answer:
speed = 7.9 m/s
Explanation:
speed = total distance / time taken
speed = 300 / 38
speed = 7.89473684 m/s
to the nearest tenth
speed = 7.9 m/s
If horizontal velocity is 5 m/s, and vertical velocity is 8 m/s, what is the magnitude of the resultant velocity?
Answer:
40 m/s
Explanation:
What is the volume of a marble with a diameter of 3.0
Explanation:
You can solve for volume using radius or diameter.
Sphere Volume = 4/3 • π • r³ = ( π •d³)/6
We're given the diameter so let's use that.
Volume = PI * d^3 / 6
Volume = 3.14159 * 3.0^3 / 6
Volume = 3.14159 * 9 / 2
Volume = 14.137 cubic centimeters
A highway curve with radius R = 274 m is to be banked so that a car traveling v = 25.0 m/s will not skid sideways even in the absence of friction. At what angle should the curve be banked? 2. what is the correct equation for the sum of the forces in the x direction? What is the correct equation for the sum of the forces in the y direction? A. ΣFx:−Nsinθ=mv2/R; ΣFy:Ncosθ−mg=0 B. ΣFx:−Ncosθ=−mv2/R; ΣFy:Nsinθ−mg=0 C. ΣFx:Nsinθ=mv2/R; ΣFy:Ncosθ+mg=0 D. ΣFx:−Nsinθ=mv2/R; ΣFy:Ncosθ=0 E. ΣFx:−Nsinθ=−mv2/R; ΣFy:Ncosθ−mg=0
Answer:
A) θ = 13.1º , B) E
Explanation:
A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.
In this reference system the only force that we must decompose is the Normal one, let's use trigonometry
sin θ = Nₓ / N
cos θ = [tex]N_{y}[/tex] / N
Nₓ = N sin θ
Ny = N cos θ
x-axis (radial)
Nₓ = m a
where the acceleration is centripetal
a = v² / R
we substitute
-N sin θ = -m v² / R (1)
the negative sign indicates that the force and acceleration towards the center of the circle
y-axis (Vertical)
Ny - W = 0
N cos θ = mg
N = mg / cos θ
we substitute in 1
mg / cos θ sin θ = m v² / R
g tan θ = v² / R
θ = tan⁻¹ (v² / gR)
we calculate
θ = tan⁻¹ (25² / 9.8 274)
θ = 13.1º
B) when comparing the equations the correct one is E
The foundation of psychology is?
Case Studies
O Experiments
O Research
O Analysis
Answer:
Case Studies
Explanation:
A case study in psychology is a descriptive research approach used to obtain in-depth information about a person, group, or phenomenon.Case studies use techniques such as personal interviews, direct observation, psychometric tests, and archival records to gather information.
(b) If you decrease the length of the pendulum by 25%, how does the new period TN compare to the old period T?
Answer:
The new period will be reduced by 50%
Explanation:
The period of pendulum is given by;
[tex]T= 2\pi\sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{T}{2\pi} )^2 = {\frac{L}{g}}\\\\\frac{T^2}{4\pi ^2} = {\frac{L}{g}}\\\\T^2(\frac{g}{4\pi ^2}) = L\\\\ \frac{g}{4\pi ^2}= \frac{L}{T^2}\\\\\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}[/tex]
When the length is decreased by 25%, the new length L₂ is given by;
L₂ = 25/100(L₁)
L₂ = 0.25L₁
[tex]\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{T_1^2L_2}{L_1} \\\\T_N^2 = \frac{T^2(0.25L_1)}{L_1}\\\\ T_N^2 =0.25T^2\\\\T_N = \sqrt{0.25T^2}}\\\\T_N = 0.5 T[/tex]
Thus, the new period will be reduced by 50%
The x vector component of a displacement vector has a magnitude of 94.8 m and points along the negative x axis. The y vector component has a magnitude of 149 m and points along the negative y axis. Find (a) the magnitude and (b) direction of . Specify the direction as a positive angle with respect to the negative x axis.
Answer:
We use pythagorean theorem
So that
r = √(x² + y²)
r = √(94.8)² + (-149)² )
r =√ 9682.6 + 22201
= 178.6
direction we use
စ = tan^-1(98.4/149)
= tan^-1 (0.6604)°
how to find range with height and velocity
Answer:
[tex]R= \frac{ v_ i\: ^2\:\times sin\:20}{g}[/tex]
Explanation:
- When a mixture contains substances that are not evenly mixed, it is called?
Answer: Heterogenous mixture
Explanation:
A heterogeneous mixture in which the components of the mixture are not evenly mixed or uniform, allowing one to identify the different constituents of each components and enable the mixture to be separated physically.
Examples of heterogeneous mixtures includes
-- sand and nails
---rice and beans
--- water and oil
Another type of mixture is the homogeneous mixture in which all the components are evenly mixed causing that each components cannot be visible with the eye and therefore separated chemically.
Fossil fuels like gasoline or coal are examples of
Answer:
Nonrenewable Resources
Answer:
fossil fuels
Explanation:
the graph shows position versus time for an object moving with the constant acceleration. what is the final velocity of the object at t=10s? assume the initial velocity at the origin is 1 m/s.
3.32 m/s
4.0 m/s
3.0 m/s
3.8 m/s
Answer:
3.0 m/s
Explanation:
The equation of motion for constant acceleration (a) is ...
[tex]x(t)=\dfrac{1}{2}at^2 +v_0t+x_0[/tex]
The problem statement tells us v₀ = 1, and we read from the graph that x₀=1. We also read from the graph that x(10) = 21. Filling these values into the equation, we can find a and x'(10).
[tex]21 = \dfrac{1}{2}a(10^2)+1(10)+1\\\\10=50a\qquad\text{subtract 11}\\\\a=\dfrac{1}{5}\\\\x'(t)=at+v_0\\\\x'(10)=\dfrac{1}{5}\cdot 10+1=3.0[/tex]
The final velocity of the object at t=10 s is about 3.0 m/s.
_____
Comment on the graph
We note this graph better represents increasing acceleration than it does constant acceleration. x(2) = 3.4 per the equation. It is graphed as about 4.
Answer:
thanks for de points
Explanation:
Hitting a ball off a tee would be considered which of the following?
A.
A closed serial skill
B.
An open continuous skill
C.
An open discrete skill
D.
A closed discrete skill
What is the ultimate source of energy for an ecosystem?
Answer:
Obviously the answer is Sun...
You are jogging with a velocity of 2 meters/second to the west, when you feel thirsty and stops to drink water after 5 seconds. First find your velocity the moment you stopped running. Then, find your acceleration during that motion. What are the units for acceleration? What is the direction of acceleration in this motion? Show your work.
Answer:
The velocity when the runner stopped is v =0 m/s
The acceleration is [tex]a = 0.4 \ m/s [/tex]
Explanation:
From the question we are told that
The initial velocity is [tex]u = 2 \ m/s[/tex]
The time taken is [tex]t = 5 \ s[/tex]
Generally from the question we are told that the person stopped running so the person velocity at that moment is v =0 m/s
Now the acceleration is mathematically represented as
[tex]a = \frac{v - u}{t}[/tex]
=> [tex]a = \frac{0 - 2}{5}[/tex]
=> [tex]a = 0.4 \ m/s [/tex]
during which stage do you have sleepwalking and sleeptalking
A. stage 2
B. stage 4
C. REM
D. stage 1
1. Looking at the planet vs. eccentricity table, which two planets have the greatest eccentricity?
Answer:
Pluto & Mercury
Explanation:
Pluto's eccentricity is 0.248
Mercury's eccentricity is 0.206
A brick is lying on a table in a state of static equilibrium. If the mass of the brick is 7.52 kilograms, what is the normal force exerted by the table on the brick? A. -73.7 newtons B. 73.7 newtons C. 80.7 newtons D. 7.52 newtons E. 8.07 newtons
The answer is OPTION B : 73.7 N
Answer:
B
Explanation:
Air conditioners operate on the same principle as refrigerators. Consider an air conditioner that has 7.00 kg of refrigerant flowing through its circuit each cycle. The refrigerant enters the evaporator coils in phase equilibrium, with 54.0 % of its mass as liquid and the rest as vapor. It flows through the evaporator at a constant pressure and when it reaches the compressor 95% of its mass is vapor. In each cycle, how much heat Qc is absorbed by the refrigerant while it is in the evaporator? The heat of vaporization of the refrigerant is 1.50×105 J/kg
Answer:
5.15J
Explanation:
First. 54% of the 7kg refrigerant is liquid
So we find mass of vapour at inlet generator
M1 = ( 1-0.54)*7= 3.2kg
At compressor mass of vapour will be
M2= 0.95*7= 6.7kg
So the Mass of vapour at exit generator is
M2-M1= 3.5kg
So to find heat absorbed by refrigerant in evaporation
Its using
Q= mh
°= 3.5x 1.50×10^5 J/kg
=5.15J
Jesse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is 0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number. N
Answer:
224.6 N
Explanation:
We can use first the formula to calculate the centripetal acceleration, given by:
[tex]a_c=\frac{v_t^2}{R}[/tex]
where the Vt is the tangential velocity, and R is the radius of the circular motion.
Then, for our case we have:
[tex]a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}[/tex]
And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:
[tex]F_c=11 \,*\,20.42\,N = 224.6\,\,N[/tex]
Answer:
225 N
Explanation:
Just answered the question
I'm confused, and I can't seem to get this question right. someone please help. Only two forces act on an object (mass = 5.00 kg), as in the drawing. (F = 55.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object. (Drawing: 45 degrees, Fx is 40 N)
Answer:
17.6 m/s², 26.2° above x axis
Explanation:
Apply Newton's second law.
Sum of forces in the x direction:
∑Fₓ = ma
40 N + 55.0 N cos 45° = (5.00 kg) aₓ
aₓ = 15.8 m/s²
Sum of forces in the y direction:
∑Fᵧ = ma
55.0 N sin 45° = (5.00 kg) aᵧ
aᵧ = 7.78 m/s²
Use Pythagorean theorem to find the magnitude of the resultant.
a² = aₓ² + aᵧ²
a² = (15.8 m/s²)² + (7.78 m/s²)²
a = 17.6 m/s²
Use trigonometry to find the angle.
tan θ = aᵧ / aₓ
tan θ = (7.78 m/s²) / (15.8 m/s²)
θ = 26.2°
If an automobile with a velocity of 4.0 m/s accelerates at a rate of 4.0 m/s2
for 2.5 s, what is the final velocity?
Answer:
V=u+at
=4+4*2.5
=14m/s
Explanation:
Initial velocity =4m/s
acceleration =4m/(second) squared
time =2.5 seconds
v=u+at
v=4+4*2.5
v=14m/s