What do you think is the common link between each of the phenomena shown?

Answer:

A: dry air

Explanation:

Trust me this is right, I’m doing the exam rn and if its not right I will come back and edit this.

Answer:

guy above me is right

Explanation:

100% on quiz

Answer:

The scientist classify the types of soil based on the texture of the soil, the type of Rock from which they are formed and the type of organisms which live in the soil. For example red soil is formed by the weathering of reddish type of Rock which is found in that territory.

Explanation: google and me.....hope this helps

One factor which scientists used to classify orders of is Soil texture

Soil texture is a classification strategy that scientists used to determine soil classes orders based on their physical texture.

Soil texture and soil structure are unique properties of the soil that will have a great effect on the behavior of soils, such as water holding capacity, nutrient retention and supply, drainage, and nutrient leaching.

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Answer:

large object to small objects

Answer:

The answer is C or warm objects to cool objects

Explanation:

Heat is the thermal energy flows from one substance to another when the substances differ in temperature. When you drink hot chocolate the heat from the liquid will flow to your mouth.

Answer:

I don't know

Explanation:

just wanna talk because I am getting bored.

Answer:

B)

takes mechanical energy and makes it electrical

Explanation:

Answer:

The given substance is cast iron.

Explanation:

Given data:

Mass of substance = 50 g

Heat absorbed = 23000 J

Initial temperature = 250°C

Final temperature = 1250°C

Which metal is this = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 1250°C -  250°C

ΔT = 1000°C

23000 j = 50 g ×c ×1000 °C

23000 J = 50,000 g. °C×c

c = 23000 J /50,000 g. °C

c = 0.46 J/g.°C

The given substance is cast iron.

Explanation:

"A homogeneous mixture has the same proportions of its components throughout any given sample and is also referred to as a solution. Conversely, a heterogeneous mixture has components of which proportions vary throughout the sample."

- Wikipedia

ありがとう私は本当にこの励ましが必要でした :)

Answer: H2O and NH3 are polar molecules. H2 is a nonpolar molecule but the H-H bond is also nonpolar.

Therefore, the best choice is CCl4. Although the C-Cl bond is polar due to electronegativity differences, the molecule itself is nonpolar because the net dipole moments cancel out, given its tetrahedral molecular structure.

Explanation:

Answer:

CO2

Explanation:

Answer:

Mass = 2.16 g

Explanation:

Given data:

Number of molecules of F₂ = 3.45 × 10²²

Mass in gram = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

3.45 × 10²² molecules ×1 mol / 6.022 × 10²³ molecules

0.57× 10⁻¹  mol

0.057 mol

Mass in gram :

Mass = number of moles × molar mass

Mass = 0.057 mol × 37.9 g/mol

Mass = 2.16 g

Answer:

[tex]\Delta S=900\frac{J}{K}[/tex]

Explanation:

Hello!

In this case, since the information is not missing, the following one will be used as it is found on similar problems:

[tex]\Delta h=26.7kJ/mol\\T_b=34.6\°C\\m=769.0g[/tex]

In such a way, we use the following equation to compute the entropy:

[tex]\Delta S=\frac{n\Delta h}{T_b}[/tex]

Whereas n (moles) are computed by using its molar mass (74.14 g/mol) as follows:

[tex]n=769.0g*\frac{1mol}{74.14g}=10.4mol[/tex]

[tex]\Delta S=\frac{10.4mol*26.7\frac{kJ}{ml} }{(34.6+273.15)K}\\\\\Delta S=0.900 \frac{kJ}{K} \\\\\Delta S=900\frac{J}{K}[/tex]

Best regards!

Answer:

V₂ = 90.42 L

Explanation:

Given data:

Initial volume = 21.4 L

Initial pressure = 681 mmHg (681/760=0.89 atm)

Initial temperature = 42.3 °C (42.3 +273 = 315.3 K)

Final temperature = 221°C (221+273 = 494 K)

Final volume = ?

Final pressure = 248 mmHg(248/760 =0.33 atm)

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂/T₁P₂

V₂ = 0.89 atm × 21.4 L × 494 K / 315.3 K × 0.33 atm

V₂ = 9408.72 L /104.05

V₂ = 90.42 L

Answer:

The main purpose for converting numbers into scientific notation is to make calculations with surpisingly large or small numbers less complicated. Since zeros are not used to place the decimal point, all of the digits in a number in scientific notation are meaningful and easier to read. Hope this helps!

Explanation:

Answer:

because it is not a rock and it is not thick so it can float

Explanation:

because it is thin and light

Answer:

D.

Explanation:

makes most sense for this question. when you're using the same amount of power over a longer period–you're bound to have less of it over time.

Answer:

a. 2.41 g

Explanation:

First we calculate the number of lithium ion moles (Li⁺) in the solution, multiplying the concentration times the volume:

500 mL ⇒ 500 / 1000 = 0.500 L

Then we convert moles of Li⁺ to moles of Li₃PO₄, keeping in mind that for each mole of Li₃PO₄ there are 3 Li⁺ moles:

Finally we convert Li₃PO₄ moles to grams, using its molar mass:

The mass of lithium phosphate, Li₃PO₄ required to prepare the solution is 2.41 g

The correct answer to the question is Option A. 2.41 g

We'll begin by calculating the concentration of Li₃PO₄. This can be obtained as follow:

Li₃PO₄(aq) —> 3Li⁺(aq) + PO₄³¯(aq)

From the balanced equation above,

3 moles of Li⁺ is present in 1 mole of Li₃PO₄.

Therefore,

0.125 M Li⁺ will be present in = 0.125 / 3 = 0.0417 M Li₃PO₄.

Thus, the concentration of Li₃PO₄ is 0.0417 M

Molarity of Li₃PO₄ = 0.0417 M

Volume = 0.5 L

Mole = Molarity x Volume

Mole of Li₃PO₄ = 0.0417 × 0.5

Mole of Li₃PO₄ = 0.02085 mole

Molar mass of Li₃PO₄ = (3×7) + 31 + (16×4) = 116 g/mol

Mass = mole × molar mass

Mass of Li₃PO₄ = 0.02085 × 116

Thus, the mass of Li₃PO₄ required to prepare the solution is 2.41 g

The correct answer to the question is Option A. 2.41 g

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Answer:

1.209g of MgO participates

Explanation:

In this problem, we have 0.030 moles of MgO that participates in a particular reaction.

And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.

To convert moles to grams we need to use molar mass of the compound:

1 atom of Mg has a molar mass of 24.3g/mol

1 atom of O has a molar mass of 16g/mol

That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol

And mass of 0.030 moles of MgO is:

0.030 moles MgO * (40.3g/mol) =

Answer:

Yes, the correct answer is C) Ear Canal

Explanation:

Answer:

I think the answer is letter C

Answer:

You did not provide any details about the experiment, nor provided any answers for us from which to choose "the best answer" from. Please refine your question next time.

Explanation:

Answer:

Solvent

Explanation:

Answer: 143*tank temperature/tank pressure L

Explanation: too few data. Need to know the pressure and what if any, temperature change.

tank volume = (tank temp/tank pressure)*(500*200/700) = 143*tank temp/tank pressure L

At constant temperature, (500*700)/tank temp

e.g. at 1400mm Hg, 500*700/1400 = 250L

The answer to your question are X-Rays.

We use this all the time when we have broken bones in our skeletal system!

Answer:

it would be x-rays

Explanation:

The rate constant : b. 1/ M² · s

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.  

For A + B  ---> C + D

Can be formulated:

[tex]\large{\boxed{\boxed{\bold{v~=~k.[A]^a[B]^b}}}[/tex]

where

v = reaction speed, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

Units of the rate constant - k depend on rate law, so it is unique for the specific reaction

So for the rate law :

Δ[C]/ΔT = k[A]²[B] , the units are :

[tex]\tt \dfrac{M}{s}=k\times M^2\times M\\\\k=\dfrac{M/s}{M^2\times M}\\\\k=\dfrac{1}{M^2.s}[/tex]

The empirical formula of vitamin A : C₂₀H₃₀O

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

mol ratio of C : H : O ⇒

[tex]\tt \dfrac{83.85}{12}\div \dfrac{10.56}{1}\div \dfrac{5.58}{16}\\\\6.9875\div 10.56\div 0.34875\rightarrow divide~by~smallest(0.34875)\\\\20\div 30\div 1[/tex]

Answer:

distillation

Explanation:

i did the assignment

Answer:

distillation

Explanation:

Answer:

joe.......

Explanation:

mama......

Answer:

see explanation

Explanation:

If we look at the structures of each of the compounds we can be able to deduce the accurate hybridization of each of the atoms listed.

Looking at ClNO - we can see that the nitrogen atom is linked to oxygen by a double bond and linked to chlorine by a single bond retaining a lone pair on nitrogen. Hence the nitrogen is in sp2 hybridized state.

For ClOCl, the compound has a sp3 hybridized oxygen atom linked to two chlorine atoms as expected retaining two lone pairs on oxygen.

For NCOH, the carbon atom is doubly bonded to oxygen hence it is sp2 hybridized.

Answer:

A) Label 2 (Sp2)

B) Label 3 (Sp3)

C) Label 1 (Sp)

Explanation:

A) Have 7 Lone Pairs (LP) to place. 1 on N. 1 becomes a double bond. Double bonds count as 1 Electron Group. Same for single bond and LP. Add these to get 3. 3 coresponds for SP2

B) 8LP. 2LP on O. 2 bonds to O. Add to get 4. 4-> Sp3

C) 5LP. C O bond is double. single bond to N. Add to get 2-> Sp