Two sides of a 90 degree triangle measure 6cm and 8cm, what is the length of the
hypotenuse?
10cm
3.7cm
100cm
14cm
24cm
please help!!!!!
Answer:
10 cm
Step-by-step explanation:
Hyp = [tex]\sqrt{6^{2}+8^{2} } =\sqrt{36+64} =\sqrt{100} =10[/tex]
Hope this helps
a number b times 18 is greater than -10
The number b is b > -5/9
How to determine the number?The statement is given as:
a number b times 18 is greater than -10
This can be represented as:
b * 18 > -10
Divide both sides by 18
b > -10/18
Simplify
b > -5/9
Hence, the number b is b > -5/9
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Which of the following is the correct factorization of the polynomial below x3 - 12
a x+3 x-4
b x-3 x+4
c x+3 x^2-4x+4
d the polynomial is irreducible
Answer:this is all I could find
Step-by-step explanation:
Someone help me please
(a) The gradient is [tex]\frac{40}{5}=\boxed{8}[/tex], and represents the cost of buying one book in dollars.
(b) Draw the line through (0,0) and (20, 130).
(c) Since the gradient of the line representing company B is less (6.5 vs 8), it is better to buy books from company B because they are cheaper.
Fill in the blank. Someone who works 40 hours per week for 50 weeks per year, with two weeks off, would work around __________________hours per year.
Answer:
about 1920
step by step explanation:
40×50weeks=2000hours per year.
40×2weeks(the weeks off) = 80
2000-80= 1920hours per year
A quarter of farmland is too rought to use if two fifth is kept for poultry farms and this leaves 221 areas for planting cash crop.what is the area of farm too rough to use
The area of the farm that is too rough to use is 157.86
What is the area?An object's area is how much space it takes up in two dimensions. In other terms, it's the measurement of the number of unit squares that are completely around the surface of a closed shape.
Let the total area of the farm be x.
Area of the farm, too rough to use=x/4
Area of farm kept for poultry farms=2x/5
Remaining Area=221
Thus,
[tex]x-(\frac{x}{4}+\frac{2}{5}x)=221[/tex]
[tex]\\ x-\frac{13}{20}x=221\\[/tex]
[tex]\frac{7}{20}x=221\\[/tex]
x=631.43
Area of the farm too rough to use= 631.43/4
=157.86
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A recent forest fire near Littleville destroyed four-fifths of the trees in Bigtree National Forest. The
forest covers 4920 km2. There is now about 30 tons of salvageable wood per km2 in the burned area. The
part of the forest that was not destroyed by fire will not be open to the salvagers. Assuming the trees are
evenly distributed throughout the park, about how long will it take to remove all the salvageable wood at
a rate of 53 1/2 tons per day? Round your answer to the nearest whole number.
Step-by-step explanation:
the whole forest is 4920 km².
4/5 if that was destroyed with salvageable wood :
4/5 × 4920 = 3,936 km²
there is 30 tons of salvageable wood per km², so in total :
3936 × 30 = 118,080 tons.
the wood can be removed at av rate of 53.5 tons per day.
how many days until cleaned up ?
as many days as 53.5 fits into the total amount of 118,080 :
118080 / 53.5 = 2,207.102804... days.
so, it will take about 2,207 days to remove all the salvageable wood.
The population of a town was 25,00 people then 3,200 people moved away.What was the percent of decrease
Answer:
-12.8 %
Step-by-step explanation:
-3200 / 25 000 x 100% = - 12.8 %
Answer:
Your answer is -12.8%
Step-by-step explanation:
To calculate the percent decrease, we:
Find the difference between the new value and the original
Divide the number by the original
Multiply by 100 and the % symbol.
The population of the town originally had 25,000. 3,200 people moved away. This means that the new population is 21,800.
21,800-25,000=-3,200
-3,200/25,000=-0.128
-0.128(100)=-12.8%
The towns population decreased by 12.8%.
Hope its helpful!
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In the diagram below, AB and TC are tangent to 0. Which equation could be solved to find x, the measure of AC?
A.1/2(238+58)=x
B.1/2(238-58)=x
C.1/2(238+x)=58
D.1/2(238-x)=58
The equation that could be solved to find x, the measure of AC is 58 = 1/2(238 -x)
Circle theoremThe given diagram shows two intersecting lines tangential to a circle at points A and C.
Using the theorem that states, the measure of the angle at the vertex is equal to the half of the difference of the measure of the intercepted arcs.
Mathematically;
<B = 1/2(arcADC - arcAC)
58 = 1/2(238 -x)
Hence the equation that could be solved to find x, the measure of AC is 58 = 1/2(238 -x)
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In the first quadrant, you start at (6,7) and move 5units down
Answer:
(6,2)
Step-by-step explanation:
If you are looking for the coordinates then that is the correct answer.
Answer:
(6,2)
Step-by-step explanation:
Because the Y axis is vertical so you would move down and subtract 5 from the 7. Your X would stay the same. So the answer will be (6,2)
A cat gave birth to 11 calico kittens and 16 non-calico kittens. What is the ratio of calico kittens to non-calico kittens?
Answer:
11:16
Step-by-step explanation:
Let theta be an angle in quadrant 2 such that cos theta =-3/4. Find the exact values of csc theta and cot theta.
Step-by-step explanation:
Since [tex]cos(\theta) = -\frac{3}{4}[/tex] we can get some information from this. First of all [tex]cos(\theta)[/tex] is defined as [tex]\frac{adjacent}{hypotenuse}[/tex]. So the adjacent side is 3 and the hypotenuse is 4. Using this we can find the opposite side to find [tex]sin(\theta)[/tex] to calculate csc and cot of theta. So using the Pythagorean Theorem we can solve for the missing side. Also I forget to mention we have to calculate the sign of the adjacent side and the hypotenuse. Since you're given that the angle is in quadrant 2, that means the x-value is going to be negative, and the y-value is going to be negative. And the x really represents the adjacent side and the y represents the opposite. So the adjacent side is what's negative. and the opposite is positive
Pythagorean Theorem:
[tex]a^2+b^2=c^2[/tex]
[tex](-3)^2 + b^2 = 4^2[/tex]
[tex]9 + b^2 = 16[/tex]
[tex]b^2 = 7[/tex]
[tex]b = \sqrt{7}[/tex]
So now we can calculate [tex]sin(\theta)[/tex].
[tex]sin(\theta) = \frac{\sqrt{7}}{4}[/tex]
Now to calculate the exact value of csc you simply take the inverse. This gives you [tex]csc(\theta)=\frac{4}{\sqrt{7}}[/tex]. Multiplying both sides by sqrt(7) to rational the denominator gives you [tex]\frac{4\sqrt7}{7}[/tex].
Now to calculate cot(theta) you find the inverse of tan. Tan is defined as [tex]tan(\theta) = \frac{sin(\theta)}{cos(\theta)}[/tex]. So all you do is take the inverse which is [tex]cot(\theta) = \frac{cos(\theta)}{sin(\theta)}[/tex].
Plug values in
[tex]cot(\theta) = \frac{-\frac{3}{4}}{\frac{4\sqrt{7}}{7}}[/tex]
Keep, change, flip
[tex]-\frac{3}{4} * \frac{7}{4\sqrt7}[/tex]
Multiply:
[tex]-\frac{21}{16\sqrt7}[/tex]
Multiply both sides by sqrt(7)
[tex]-\frac{21\sqrt7}{112}[/tex]
This is the value of cot(theta)
in the year 2000 February 26 was a Friday, what day was 8 April the same year??
Please help ill give whoever answers the best the brainliest answer :0
Answer:
The bottom graph
Step-by-step explanation:
It shows that the kid starts 4 meters away and slowly decreases the distance for 8 seconds, pauses for 3, and moves back for 4.
Answer:
the 4th answer option
Step-by-step explanation:
the first one is looking good too, but the difference is to start at 4 meters away.
and the first graph starts at 9 meets away.
so, it is the 4th graph :
starting 4 meters away the person is coming slowly closer and closer for 8 seconds, then stands still for 3 seconds, and then walks away quickly for 4 seconds.
remember, the passing time is on the x-axis moving to the right (bigger and bigger numbers).
while the distance to the person is on the y-axis. and that value can get bigger and smaller.
AREA UNDER A CURVE - GEOMETRY
Recall that the area of a trapezoid is equal to the average of its bases times its height.
For the trapezoids shown here, each base corresponds to the value of [tex]y=2x^2[/tex] when [tex]x[/tex] is one of the endpoints of some interval, while the height is the length of that interval.
On the interval [-2, -1], the trapezoids has bases 2(-2)² = 8 and 2(-1)² = 2, and "height" -1 - (-2) = 1. Then its area is (8 + 2)/2 × 1 = 5.
On the interval [-1, 0], one of the bases is 2(-1)² = 2 and the other is 2(0)² = 0, and the height is again 0 - (-1) = 1. Then the trapezoid's/triangle's area is (2 + 0)/2 × 1 = 1.
Then the total area under the curve [tex]y=2x^2[/tex] on the interval [-2, 0] is approximately 5 + 1 = 6.
Compare this to the actual value of the area given by the definite integral,
[tex]\displaystyle \int_{-2}^0 2x^2 \, dx = \frac{16}3 \approx 5.333\ldots[/tex]
Graph the equation y=−x 2 −8x−7 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.
The graph of the given quadratic function is shown below
Graph of Quadratic equationsFrom the question, we are to graph the given quadratic function.
The given quadratic equation is
y = −x² −8x −7
The graph of the given quadratic function is shown below
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The function g(x) is graphed.
On a coordinate plane, a curved line enters the plane at point (negative 2.3, 5), crosses the x- and y-axis at (0, 0), and leaves the plane at point (2.3, 5).
Which statements about the function are true? Choose three options.
The statements about the function that are true include:
g(0) = 0
g(1) = -1
g(-1) = 1
How to depict the function?From the information, the points include:
(x1, y1) = (-2, 2, 5).
(x2, y2) = (0, 0)
(x3, y3) = (2, 3, 5).
It should be noted that (x2, y2) implies that g(0) = 0. In this case, the statements about the function that are true include g(0) = 0, g(1) = -1, and g(-1) = 1. This is illustrated in ten graph.
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Answer: the answer is b, d, and e.
g(0) = 0
g(1) = 1
g(-1) = 1
Step-by-step explanation:
Side A B is parallel to Side D E in the map below. Triangle A B C. Side A B is 15 feet and side B C is 9 feet. Triangle C D E. Side C D is 6 feet and side D E is x feet. Which proportion solves for the distance between D and E? Start Fraction 9 Over 6 End Fraction = Start Fraction x Over 15 End Fraction Start Fraction 6 Over x End Fraction = Start Fraction 15 Over 9 End Fraction Start Fraction 9 Over 6 End Fraction = Start Fraction 15 Over x End Fraction Start Fraction 6 Over 15 End Fraction = Start Fraction 9 Over x End Fraction
The proportion that solves for the distance between D and E is x/15 = 6/9
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Triangle ABC and CDE are similar triangles, hence the ratio of their corresponding sides are in the same proportion.
Hence:
x/15 = 6/9
The proportion that solves for the distance between D and E is x/15 = 6/9
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What type of reaction is HCl + AgNO3?
Answer:
Double-displacement reaction
Step-by-step explanation:
In double-displacement reaction, aka. double-replacement reaction, the cation of one compound is swapped with the cation of another. They have the general structure:
AB + CD ---> AD + CB
In this case, the silver cation (Ag⁺) from AgNO₃ is swapped with the hydrogen cation (H⁺) of HCl.
The complete balanced equation is:
HCl + AgNO₃ ---> AgCl + HNO₃
here is the histogram of a data distribution. all class widths are 1. which of the following is the closest to the median of this distribution
The value of the median of the distribution is closest to 5.
What is the median?
A histogram is used to represent data graphically. the histogram is made up of rectangles whose area is equal to the frequency of the data and whose width is equal to the class interval.
The median is the number at the center of a dataset when the dataset is arranged in either ascending or descending order.
The numbers arranged in ascending order is : 2, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 6, 6, 7, 7, 8, 9
Median = 5
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Answer:
Step-by-step explanation:
Penny attended a four year state college. She took out a student loan to pay for her tuition and room & board for the four years she was attending the college. Her tuition fees were $6,970 per year, and the cost of her room and board was $11,320 per year. Now that she has graduated, she will have to start paying back her loan. Fortunately, Penny has a grace period of one year before she has to start paying back the loan. Her loan details are as follows: there is a fixed-rate interest of 4.5% and the interest compounds each month. During her one year grace period, interest will accrue on the loan, so that when she has to start paying the loan back she will owe more than what she owes now. Her goal is to be able to payoff the loan in 10 years.
What is the new loan amount after the one-year grace period (remember that interest will accrue on the loan during this initial 12-month period that she is not paying anything back on the loan)? This is the amount that she will be responsible for paying back. (Round your answer to the nearest whole dollar)
Given that she can pay back the loan in full after 10 years of payments, what is the total amount she will end up paying back (both principal and interest that has accrued over the 10 years)? And how much will her monthly payments on the loan be for those 10 years? (Round your answers to the nearest whole dollar)
The loan amount is given as $76521
We first have to calculate the total amount of tuition
6970 x 4 + 11320 x 4
= 73160
a. How to solve for the new loan amount[tex]73160 (1+\frac{\frac{4.5}{100} }{12} )^1^2[/tex]
= 73160 x (1 + 0.00375)¹²
= 76520.95
Hence the new loan amount after agrace period of 1 year = $76521
b. PV = $76521
i = [tex]\frac{4.5/100}{12}[/tex]
= 0.00375
t = 10 years
[tex]PMT[\frac{1-(1+0.00375)^-^1^2^0}{0.0375} ]= 76521[/tex]
pmt = 793. 05
The monthly payment is $793. 05.
In ten years the total payment is 793.05 x 10 x 12
= 95166
Difference = 95166 - 76521
= $18645
In ten years her ,monthly payment on the loan would be $18645.
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A box has dimensions of 2.5 cm by 3.0 cm by 4.0 cm. The volume of the box in milliliters and liters is:
Answer:
30000 milliliters
0.03 liters
Step-by-step explanation:
The volume of the box is 2.5 x 3.0 x 4.0 = 30 cc
There are 1000 ml in 1 cc so 30cc = 30 x 1000 = 30000 ml
There are 1000 cc in 1 liter so 30 cc = 30/1000 = 0.03 liters
The volume of the box is 30 mL or 0.03 L.
What is volume?Volume is a metric magnitude that is defined as the extension in three dimensions of a region of space. Volume is defined as the amount of space occupied by the object or figure in three-dimensional space. Volume is measured in cubic units.
The volume of this prism depends on its three dimensions and is calculated as the multiplication of these dimensions,
Volume= Dimension 1× Dimension 2× Dimension 3
The volume of the box = 2.5 x 3.0 x 4.0 = 30 cc
There are 1000 ml in 1 cc so 30cc = 30 x 1000 = 30000 ml
There are 1000 cc in 1 liter so 30 cc = 30/1000 = 0.03 liters
Hence, the volume of the box is 30 mL or 0.03 L.
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ii) Verify whether the point (1,5) lies on the locus a point which moves so that its distance from x-axis exceeds three times the distance from y-axis by 2.
The locus of the point represented by the equation y = 3•x + 2, indicates that the point (1, 5) is on the locus of the point.
How can the location of the point in relation to the point be found?The distance from the x-axis is the y-value
The distance from the y-axis is the x-value
Therefore;
The equation of the locus of the point is presented as follows;
y = 3•x + 2When x = 1, y = 3 × 1 + 2 = 5
When x = 1, y= 5
Therefore;
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x =x=x, equals
^\circ
∘
degrees
Step-by-step explanation:
x = 145°
we don't even need the upper parallel line with the 35° angle.
it is simply based on the fact that the angles on both sides of 2 intersecting lines have to be the same (just left-right mirrored).
Type the equation for the graph below
Answer:
y = sin3x
Step-by-step explanation:
the equation is of the form y = sinbx
the period of the sine wave is
period = [tex]\frac{2\pi }{b}[/tex] ( b is the coefficient of x )
here period = [tex]\frac{\pi }{3}[/tex] × 2 = [tex]\frac{2\pi }{3}[/tex] , then
[tex]\frac{2\pi }{3}[/tex] = [tex]\frac{2\pi }{b}[/tex] ⇒ b = 3
y = sin3x ← equation of graph
Pls help me I’m so stuck :(
Answer:
B
Step-by-step explanation:
using Pythagoras' identity in the right triangle
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
(x + 1)² + (x + 3)² = (x + 5)² ← expand all factors using FOIL
x² + 2x + 1 + x² + 6x + 9 = x² + 10x + 25 , that is
2x² + 8x + 10 = x² + 10x + 25 ← subtract x² + 10x + 25 from both sides
x² - 2x - 15 = 0 ← in standard form
(x - 5)(x + 3) = 0 ← in factored form
equate each factor to zero and solve for x
x - 5 = 0 ⇒ x = 5
x + 3 = 0 ⇒ x = - 3
however, x > 0 , then x = 5
Answer:
B. 5
Step-by-step explanation:
[tex] \sf{C = \sqrt{ A {}^{2} + B {}^{2} }}[/tex]
[tex]\sf{x + 5 = \sqrt{ {(x + 3)}^{2} + {(x + 1)}^{2} }}[/tex]
[tex]\sf{x + 5 = \sqrt{ {(x {}^{2} + 6x + 9)} + {(x {}^{2} + 2x + 1)}}}[/tex]
[tex]\sf{x + 5 = \sqrt{ {(2x {}^{2} + 8x + 10)}}}[/tex]
[tex]\sf{(x + 5) {}^{2} = { {2x {}^{2} + 8x + 10}}}[/tex]
[tex]\sf{ {x}^{2} + 10x + 25= { {2x {}^{2} + 8x + 10}}}[/tex]
[tex]\sf{0= { {2x {}^{2} \red{ { - x}^{2} } + 8x \red{ - 10x} + 10 \red{ - 25}}}}[/tex]
[tex]\sf{0= x^{2} } - 2x { - 15}[/tex]
[tex]\sf{0= x^{2} } - 2x { - 15}[/tex]
[tex]\sf{0= (x - 5)(x + 3)}[/tex]
[tex] \sf{x_{1} - 5 = 0 }[/tex]
[tex] \sf{x_{1} = 0 + 5 }[/tex]
[tex] \sf{x_{1} = \boxed{5 }}[/tex]
[tex] \sf{x_{2} + 3 = 0 }[/tex]
[tex] \sf{x_{2} = 0 - 3 }[/tex]
[tex] \sf{x_{2} = \boxed{- 3 }}[/tex]
Option B. 5
Having trouble question is in attachment
Answer:
[tex]x=\frac{35}{9} .[/tex]
Step-by-step explanation:
[tex](3\sqrt{3})^{-x+1} =\frac{1}{3}*27^{x-5}\\( \sqrt{3^2*3}) ^{1-x}=\frac{1}{3} *((3)^3)^{x-5}\\(\sqrt{27} )^{1-x}=\frac{1}{3}*3^{3*(x-5)}\\ (\sqrt{3^3})^{1-x} =\frac{1}{3}*3^{3x-15}\\ 3^{\frac{3 }{2}*(1-x)}=\frac{1}{3}*3^{3x-15}\ |*3\\ 3*3^{\frac{3}{2}-\frac{3}{2}x}=3^{3x-15}\\ 3^{1+1,5-1,5}=3^{3x-15}\\ 3^{2,5-1,5x}=3^{3x-15}\ \ \ \ \Rightarrow\\2,5-1,5x=3x-15\\4,5x =17,5\ |*2\\9x=35\ |:9\\x=\frac{35}{9}.[/tex]
KM=
What is the measure of KM?
Help please
Paul needs to find 310% of 72. Which expression should he use?
Step-by-step explanation:
310/100 × 72
= 223.2
using fraction × total
hope you understand.
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Suppose 44% of the students in a university are baseball players. If a sample of 736 students is selected, what is the probability that the sample proportion of baseball players will differ from the population proportion by less than 3%
Required probability is 0.8990
Given that,
p = 0.44
1 - p = 0.56
n = 736
[tex]\mu_\hat{p}} = p = 0.44\\\sigma_\hat{p}} = \frac{p*(1-p)}{n} = \sqrt(\frac{0.44*0.56)}{736} ) =[/tex]0.01830
Converting Normal distribution to standard normal because A normal distribution is determined by two parameters the mean and the variance. A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution. Hence it's easy to work with standard normal distribution.
P(0.14<[tex]\hat{p}[/tex]<0.47) = P((0.41-0.44)/0.01830) < [tex]\frac{\hat{p} - \mu _{\hat{p}} }{\sigma _{\hat{p}} }[/tex]<(0.47-0.44)/0.01830
Using normal algebra we get:
= P(-1.64 < z < 1.64)
= P(z < 1.64) - P(z < -1.64)
= 0.9495 - 0.0505
= 0.8990
Thus, required probability is 0.8990
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