what are effects of high gravity on blood pressure, blood circulatory system, size of lungs, bone fragility and density​

Answers

Answer 1

Answer:

Explanation:

On return to Earth, gravity once again “pulls” the blood and fluids into the abdomen and legs. The loss of blood volume, combined with atrophy of the heart and blood vessels that can occur in space, reduces the ability to regulate a drop in blood pressure that happens when we stand on Earth.


Related Questions

A rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 90.4 kg, including her space suit.

Answers

The normal force is 2820.48N in the negative y direction.

According to Newton's second law of motion,

Force = mass × acceleration

F = m×A

Note that rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s² .

The rocket accelerates upwards, hence the acceleration will be negative because it defies gravity's law (it keeps going into space without coming down)

Acceleration of the rocket = -31.2m/s²

Mass of the astronaut = 90.4kg

Normal force acting on the astronaut = -31.2 × 90.4kg

                                                                 = -2820.48N

Therefore, the normal force is 2820.48N in the negative y direction.

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What was the initial speed of a car if its speed is 40 m/s after 5 seconds of accelerating at -4 m/s²?
A. 50 m/s
B. 60 m/s
C. 25 m/s
D. 20 m/s

Answers

Answer:

[tex]\huge\boxed{\sf V_i=60 \ m/s}[/tex]

Explanation:

Given Data:

Final speed = [tex]V_f[/tex] = 40 m/s

Time = t = 5 s

Acceleration = a = -4 m/s²

Required:

Initial velocity = [tex]V_i[/tex] = ?

Formula:

[tex]\displaystyle a = \frac{V_f-V_i}{t}[/tex]

Solution:

Put the givens in the above formula

[tex]\displaystyle -4=\frac{40 - V_i}{5} \\\\Multiply \ -5 \ to \ both \ sides\\\\-4 \times 5 = 40 - V_i\\\\-20 =40-V_i\\\\Subtract \ 40 \ to \ both \ sides\\\\-20-40=-V_i\\\\-60\ m/s=-V_i\\\\60 \ m/s = V_i\\\\V_i=60 \ m/s\\\\\rule[225]{225}{2}[/tex]

With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 50 m

Answers

The speed with which the ball must be thrown vertically from ground level to rise to a height of 50 m is 31.305 m/s.

Given values:

Maximum height reached from ground level, h_max = 50 m

Final velocity of the ball, v = 0 m/s

Calculation of initial speed of the ball:

Step 1:

Using Newton's third equation of motion, we get:

v² = u² + 2as

where, v is the final velocity of ball

           u is initial velocity of the ball

           a is acceleration of ball

           s is the maximum height attained by the ball

Step 2:

Here, the acceleration of the ball will be given as:

a = -g

  = -9.8 m/s²

where, g is acceleration due to gravity

Applying this value in above equation we get:

v² = u² - 2gh_max

Re-arranging above equation, we get:

u² = v² + 2gh_max

u  =√(v² + 2gh_max)

Step 3:

Applying values in above equation we get:

u  =√((0 m/s)² + 2(9.8 m/s²)(50 m)

   =√980

   = 31.305 m/s

Therefore, the speed with which the ball must be thrown from ground level is 31.305 m/s in order to reach a maximum vertical height of 50 m.

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You travel in a circle, whose circumstances is 8 kilometers, at an average speed 8 kilometers/hour. If you stop at the same point you started from what is your average velocity

Answers

Answer:

The Average Velocity is 2.22m/s.

Explanation:

Average Velocity = displacement(m) ÷ time(s)

8km = 8000m

8km/hr = 2.22m/s

Finding Time

Time = distance÷speed

Time = 8000m ÷ 2.22m/s = 3603.6s = 3604s

Finding Average Velocity

Average Velocity = displacement ÷ time

Average Velocity = 8000m ÷ 3604s

Average Velocity = 2.22m/s

Therefore the Average Velocity is 2.22m/s.

Different asteroids reflect different percentages of the light falling on them. This is due to the fact that they have different:

Answers

Due to the Composition, different asteroids reflect different percentages of the light falling on them.

What are Asteroids:

Asteroids are small, rocky objects that orbit the Sun. Although asteroids orbit the Sun like planets, they are much smaller than planets. Asteroids are generally made up of rocky material, metals and their size are large in  comparison to comets. Asteroid belt is found between Jupiter and Mars.

Composition of Asteroids:

Most of the asteroids in the Main Belt are made of rock and stone. The remaining asteroids are made up of a mix of these, along with carbon-rich materials. Some of the more distant asteroids tend to contain more ices.

We determine reflectivity of asteroids by comparing the brightness of light in the visible spectrum to the brightness of light in the infrared spectrum. The light shining from asteroids is reflected sunlight.

Hence we can say that,

Due to the Composition, different asteroids reflect different percentages of the light falling on them.

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Nora's hair dryer is 64% efficient. If 1000 J of energy is supplied to the hair dryer, how much energy will it transfer usefully to Nora's hair?

Answers

Answer:

The hair dryer will transfer 640J of energy usefully to Nora’s hair.

Explanation:

Efficiency = output/input × 100%

Data

Efficiency = 64%

Energy input = 1000J

Energy output = ?

Efficiency = Energy output/Energy input × 100%

64% = Energy output /1000J × 100%

Divide both sides by 100%

0.64 = Energy output/1000J

Energy output = 0.64 × 1000J

Efficiency output = 640J

Therefore the hair dryer will transfer 640J of energy usefully to Nora’s hair.

Consider a blimp that can be approximated as a 3-m diameter, 8-m long ellipsoid and is connected to the ground. On a windless day, the rope tension due to the net buoyancy effect is measured to be 120 N. Determine the rope tension when there are 50 km/h winds blowing along the blimp (parallel to the blimp axis).

Answers

Step 1 of 6

Diameter of the blimp,

Length of the blimp,

Rope tension,

The velocity of the wind,

Step 2 of 6

The drag force acting on the blimp can be calculated using the formula given below,

(1)

Where,  is the drag coefficient is the density of air.

A is the frontal area of the blimp.

V is the velocity of the wind.

Step 3 of 6

The frontal area of the parachute,

Here,

Substitute the value in the above equation.

The drag coefficient for the balloon is,

Step 4 of 6

From the table properties of air,

The density of air at 1atm pressure and  is,

The velocity of air,

Step 5 of 6

Now, substitute all the known values in equation (1)

Step 6 of 6

Now, rope tension is the sum of rope tension due to the buoyancy effect and the force due to the wind blowing.

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A steel needle when placed carefully on water can be made to float.when the detergent is added to the water it sink.explain the observation

Answers

Answer:

The surface tension of plain water can cause a needle to float.

Evidently, the addition of detergent to the water reduces the surface tension of the liquid causing the needle to sink.

When we add detergent to water, the surface tension of water immediately decreases, then the surface tension cannot balance the blade and it will sink.

What is Surface tension?

Surface tension is defined as the phenomenon that occurs when the surface of a liquid is in contact with another phase which may also be a liquid. Liquids obtain the least possible surface area while the surface of the liquid behaves like an elastic sheet.

Surface tension depends not only on the forces of attraction between particles within a given liquid but also on the forces of attraction of the solid, liquid or gas in contact with it where energy is responsible for the occurrence of surface tension, which can be thought of as approximately equal to the work or energy required to remove a surface layer of molecules in a unit area.

When we add soap to water, the surface tension of the water decreases to the point where the surface tension is no longer strong enough to "float" the needle.

Thus, when we add detergent to water, the surface tension of water immediately decreases, then the surface tension cannot balance the blade and it will sink.

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A 450-kg sports car accelerates from rest to 100 m/s in 20.0 s. What magnitude force does a 90.0 kg passenger experience during the acceleration

Answers

Magnitude of force experienced by the 90Kg passenger is 450N.

To find the answer, we need to know about the pseudo force.

What's the pseudo force experienced by a passenger traveling in a vehicle?When a passenger inside a vehicle, it experiences pseudo force in the opposite direction of motion of the vehicle.The pseudo force= mass of the passenger × acceleration of the vehicleWhat's the acceleration of the vehicle when it achieves a speed of 100 m/s from rest in 20s?Acceleration= Change in velocity/timeHere, change in velocity= 100m/s and time = 20sSo, acceleration= 100/20= 5m/s²What's the pseudo force experienced by the 90Kg passenger?

Pseudo force= 90×5=450N.

Thus, we can conclude that the force experienced by the passenger is 450N.

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Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly because of the electrostatic charge on the hairspray droplets. If two drops of hairspray repel each other with a force of 9 x 10^-9 N at a distance of 0.07 cm ( 7 x 10^ -4 m), what is the charge on each of the equally charged drops of hairspray?


Please show the steps as well. Written out, if possible.

Answers

The charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C

What is Columb's law?

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Similar charges repel each other, whereas charges that are opposed attract each other.

Given data;

Electric force,F = 9 × 10 ⁻⁹ N

Distance between charges,d = 7 × 10⁻⁴ m

Chrge,q₁ = q₂ =q C

From Columb's law;

[tex]\rm F = K \frac{q_1q_2}{d^2} \\\\ 9 \times 10^{-9} = 9 \times 10^9 \frac{q^2}{(7 \times 10^{-4})^2} \\\\ q^2 = 4.9 \times 10^{-25} \\\\ q = 7 \times 10^{-13} \ C[/tex]

Hence the charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C

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If a baseball pitcher throws a fastball at a horizontal speed of 160 km/h, how long does the ball take to reach home plate 18.4 m away

Answers

Answer: 0.000115 seconds

Explanation: how I got this is by first converting the meters to kilometers then I had 160 km/h and 0.0184 km away so then you do 0.0184 divided by 160 (0.0184 / 160) and get 0.000115 seconds.

A ball of mass 200 g rolls along the ground at a speed of 5.2 m/s. Calculate the kinetic energy of the ball. Give your answer to two significant figures.

Answers

Answer:

Kinetic Energy = 2.7J

Explanation:

Conversion :

200g = 0.2kg

Kinetic Energy = ½ × mass × (velocity)²

Kinetic Energy = ½ × 0.2kg × (5.2m/)

Kinetic energy = ½ × 0.2kg × 27.04m²/

Kinetic Energy = 2.7J

The right answer is "2.7 J"

Answer explanation:

Remember to convert grams to kilograms first by dividing by 1000.

Kinetic energy

= 1/2 × mass × speed2

= 1/2 × 0.2 kg × (5.2 m/s)^2

= 2.7 J (to 2 sig. fig.)

Hope it helps ✨✨

A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. the ball bounces off the bat with a speed of 49 meters/second in the opposite direction. what is the impulse? a. 4.32 newton∙seconds b. 7.25 newton∙seconds c. 8.23 newton∙seconds d. 9.42 newton∙seconds e. 13.5 newton∙seconds

Answers

The impulse is 13.5 N-s.

As we know that impulse is a sudden force acting on a body for a short time interval is called Impulse.

                                Δp = FΔt  

Mathematically, the change in momentum will equal impulse.

                                Δp = mΔv

                   →           Δp =  0.145(49-(-44))

                   →           Δp = 0.145(93)

                               Δp =  13.5 Newton-second

Thus, option (e) is correct.

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Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which child has the larger tangential speed

Answers

Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.

Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.

What is the angular velocity?In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).It's the revolution per second.The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,

                              [tex]w=V/r[/tex]

How to solve the question?We know that the expression for the tangential velocity as,

                               [tex]V=wr[/tex]

In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.The maximum will the value of V, if the r maximizes.Thus, child A with greater distance will have larger tangential speed.

Thus, we can conclude that, child A with greater distance will have larger tangential speed.

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What type of system would allow light and air to enter and exit? A. Connected
B. Closed C. Isolated D. Open

Answers

Answer:

An open system.

Explanation:

An isolated system allows the exchange of neither energy nor matter with the surroundings. A closed system allows the exchange of energy, but not matter. An open system allows the exchange of both energy and matter.

Notice that in this question, light (electromagnetic wave) is a form of energy. The entry and exit of light allows this system to exchange energy with its surroundings- just as how the earth receives energy from the sun. Additionally, this system could exchange energy with its surroundings through the exchange of matter (in particular, air) with its surroundings.

Thus, the system in this question is an open system.

I would say D. A open system

The engine of a 1560-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road. Is your answer realistic

Answers

The time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road is 7.73 seconds.

Mass of the engine = 1500 kg

Power rating = 75 kW = 75,000 W

Final speed = 100 km/hr =  = 27.78 m/s

v₁ = 0

Power = Work done ÷ Time

Work done = Final energy - Initial energy

=1/2 x 1560 x 27.78^2 = 1/2 x 1560 x 0^2\

= 578703.72 J

Thus,

75,000 = 578703.70 ÷ time=7.72 seconds.

Work is done every time a force moves something over a distance. By multiplying the force by the distance traveled in the direction of the force, you can calculate the energy transferred or the work done. Energy transmitted = work completed = force x distance traveled in the direction of the force.

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The Viking spacecraft observed several features on Mars that, at first, appeared to be artificially crafted. After further study the features were primarily naturally occurring phenomena resulting from _____ on the Martian surface.

Answers

Answer:

Erosion of the surface of Mars.

Explanation:

The surface of Mars have features which were formed as a result of the erosion of the surface of the Mars.

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A 2280 kg car, moving at 24.2 m/s, runs into a car that has a mass of 2180 kg
and is moving at 15.3 m/s in the same direction. The cars stick together after
the collision. Assuming momentum is conserved, what is their final velocity?
OA. 18.6 m/s
OB. 17.2 m/s
O C. 19.8 m/s
OD. 16.7 m/s

Answers

Answer:

The answer is C.19.8 m/s because it's their common velocity after the collision of the two cars.

Explanation:

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look at the attachment above ☝️ and if you have any questions you're welcome.

A force of 15 n is applied to a spring, causing it to stretch 0.3 m. what is the spring constant for this particular spring? n/m

Answers

Answer:

-50N/m

Explanation:

Force , F = 15N

Displacement , x = 0.3m

Spring constant , K = ?

K = -F/x

K = -15N/0.3m

K = -50N/m

Answer: 50 N/m

Explanation:

Edge 2022

Vector A has a magnitude of 623. What are its west and north components?


A
The problem cannot be solved because vectors at 90 degree angles to the reference system do not have components.

B
0 south, 0 east

C
623 west, 0 north

D
623 north, 0 west

Answers

Answer:

D) 623 N

Explanation:

The vectors' direction is in the North And when we try to take Y and X components Cos(90°) is Zero ... So the X (West) component will be zero

A key falls from a bridge that is 43 m above the water. It falls directly into a model boat, moving with constant velocity, that is 17 m from the point of impact when the key is released. What is the speed of the boat

Answers

The speed of the boat is 4 m/s.

The system for pace is speed = distance ÷ time.

To work out what the devices are for pace, you want to understand the gadgets for distance and time. In this case, distance is in meters (m) and time is in seconds (s), so the gadgets could be in meters according to second (m/s).

To resolve for speed or price use the components for pace, s = d/t which means that pace equals distance divided through time.

The pace is a manner of measuring how quickly something is transferring or being performed, or something moving speedily. An example of speed is a vehicle being driven 45 miles in keeping with the hour. An instance of velocity is a person cleaning a room in 10 minutes. An example of velocity is how quickly a jaguar runs.

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If a car moving at 15 m/s skids to a stop after 20 m, how far will it skid if it is moving at 45 m/s? Assume that the braking force is constant. Group of answer choices 50 m 20 m 180 m 90 m 120 m

Answers

The car will skid at 80m

As we know that In mechanics, acceleration is the rate of change of the velocity of an object with respect to time.

It is a vector quantity

The velocity is the distance covered by an object per unit time

Given

Initial velocity (u) = 15m/s

Final Velocity (v) = 0m/s

Distance (s) = 20 m

Deceleration (a) =?

Now we know that ,

v² = u² + 2as

Substituting the value

0² = 15² + (2)*(a)*(20)

0 = 225 + 40a

Collecting the  like terms

0 – 235 = 40a

–225 = 40a

To find the value of a divide  both side 40

a = –225 / 50

a = –5.625 m/s²

Determination of the distance

Deceleration (a) = –5.625 m/s²

Initial velocity (u) = 30 m/s

Final velocity (v) = 0 m/s

Distance (s) =?

v² = u² + 2as

0² = 30² +(2 × –5.625 × s)

0 = 900 – 11.25s

Collecting  like terms

0 – 900 = –11.25s

–900 = –11.25s

To find the value of s divide both side by –11.25

s = –900 / –11.25

s = 80 m

Hence the car will skid 80 m

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16/07/2021 23
question 9 of 10
homework
which movement will require the greatest amount of work to be
done?

this activity is
a force of 10n moving an object a distance of 3.0 m
b*
assessment
percentage
a force of 10n moving an object a distance of 5.0m
a force of 15n moving an object a distance of 3.0m
c attempts
a force of 15n moving an object a distance of 5.0m

Answers

D.  The movement that will require the greatest amount of work to be

done is a force of 15n moving an object a distance of 5.0m (75 J).

What is work done?

Work is said to be done when an applied force moves an object over a given distance.

W = Fd

where;

F is the applied forced is the displacement of the object

A force of 10n moving an object a distance of 3.0 m

W = 10 x 3 = 30 J

A force of 10n moving an object a distance of 5.0m

W = 10 x 5 = 50 J

A force of 15n moving an object a distance of 3.0m

W = 15 x 3 = 45 J

A  force of 15n moving an object a distance of 5.0m

W = 15 x 5 = 75 J

Thus, the movement that will require the greatest amount of work to be

done is a force of 15n moving an object a distance of 5.0m (75 J).

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A dentist holds a small mirror 1.9

cm from a patient’s tooth. The image

formed is upright and 5

times as largeas the object. (a) Is

the image real or virtual? (b) What

is the focal length of the mirror? Is it

concave or convex? (c) If the mirror

is moved closer to the tooth, does the

image get larger or smaller? (d) For

what range of object distances does

the mirror produce an upright image?​

Answers

Answer:

follow me for legitimate answer… oh? U don’t like the feeling of people stealing ur points huh?! Well theirs a taste of your own medicine

Explanation:

Write an argument of any one
Do you think parallel universes exist?
or
Do you think portals exist?

Answers

I do think parallel universes exist. There are now some scientific theories that support the idea of parallel universes beyond our own. However, the multiverse theory remains one of the most controversial theories in science.Our universe is unimaginably big. Hundreds of billions, if not trillions, of galaxies(opens in new tab) spin through space, each containing billions or trillions of stars(opens in new tab). Some researchers studying models of the universe speculate that the universe's diameter could be 7 billion light-years(opens in new tab) across. Others think it could be infinite.

u might never know. It might or might not exist in conclusion.

If the plates are pulled twice as far apart, but are kept connected to the battery, the electric field between the plates will be

Answers

Electric field between two parallel plates will be halved as it was before.

What is the electric field between two plates:

The electric field lines of two parallel plates can be represented by straight lines perpendicular to both plates surfaces while carrying arrows that point from +Q plate A toward -Q plate B.

we know that,

The electric field between plates:

E=V / d

where,

V is battery voltage

d is separation distance between plates.

now If the plates are pulled twice as far apart, but are kept connected to the battery,

the separation distance becomes,

d' = 2d

so the new electric field will be:

E' = V / d'

substituting the values,

E' = V / ( 2d )

E' = 1/2 ( V /d )

E' = 1/2 E

hence we can conclude that

Electric field between plates will be halved as it was before.

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An object weighing 2.7n while in air and 1.2n when completely immersed in water.find the relative density of the object

Answers

Answer:

1.8 = relative density (there are no units for relative density)

Explanation:

It displaces water equal to it's volume and gets buoyancy equal to that amount of water

2.7 - 1.2  = 1.5  N  of buoyancy

density of water = 1 gm /cc

 1.5 N = m (9.81)

    m of water displaced = .1529 kg

             152.9 cc of water will produce this buoyancy....this is the volume of the object

   

find mass of object     2.7 = m (9.81)     shows m = .2752 kg = 272.5 gm

density = mass/ volume = 272.5 / 152.9 = 1.8 gm / cc

Relative to water (which is 1 gm / cc) the relative density is 1.8

  ====> it is 1.8 times denser than water and will sink when in water....

What is the instantaneous velocity of a freely falling object 14 s after it is released from a position of rest

Answers

The instantaneous velocity of the object is 137.2 m/s along the downward direction.

Instantaneous velocity: The velocity of an object at a particular instant of time is called the instantaneous velocity.

Note: The y-axis is taken along the upward direction so acceleration due to gravity will be negative.

Any object that is falling freely is acted upon by gravity. The first equation of motion gives the relationship between initial velocity, the velocity at time t, time, and acceleration. The equation is,

v=u+at

where v is the velocity at time t, u is the initial velocity, t is the time, and g is the acceleration due to gravity. Since the object starts from rest, its initial velocity is zero.

For the given case, u=0, a=-9.8 m/s^2 and t=14 s. Put the values in the equation to get the instantaneous velocity of the object at t=14 s.

v=0+(-9.8)(14)

v=-137.2 m/s

The negative sign indicates the object is falling downward.

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In a test run, a rocket-powered car is driving down a test track at a constant speed when the rockets are fired. it then accelerates at 4 m/s2 for 8.0 s covering a distance of 224 m. at what speed was the car travelling when the rockets were fired?

Answers

With the use of the second equation of motion formula, the speed the car travelled when the rockets were fired is 12 m/s.

Speed in a Linear Motion

Linear motion depicts movement in a straight line. While speed is the distance travelled per time taken.

Given that In a test run, a rocket-powered car is driving down a test track at a constant speed when the rockets are fired. it then accelerates at 4 m/s2 for 8.0 s covering a distance of 224 m.

The given parameters are;

Accelerates a = 4 m/s2Time t = 8sDistance s = 224m

The speed the car travelled when the rockets were fired can be calculated by using the below formula

s = ut + 1/2a[tex]t^{2}[/tex]

Substitute all the parameters into the formula

224 = 8u + 1/2 x 4 x [tex]8^{2}[/tex]

224 =8u + 2 x 64

224 = 8u + 128

224 - 128 = 8u

8u = 96

u = 96/8

u = 12 m/s

Therefore, the speed the car travelled when the rockets were fired is 12 m/s.

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According to dr. Ed coyle, the fda does not regulate dietary supplements. When is it acceptable for a high school athlete to include dietary supplements in their diets?.

Answers

If not jeopardizing their emotional mental or physical health a dietary supplement is okay to use when filling nutritional gaps in a diet for people who may be vegetarian, vegan, pregnant or anyone else who needs higher levels of a certain nutrition

Athletes that energy drinks are not appropriate for hydration or as dietary supplements.

When should athletes use supplements?

Vitamins and minerals are recommended when an athlete has low blood values, a medical condition that may lead to poor absorption of nutrients, or other potential nutrition/eating challenges.

As per the question

FDA doesn't regulate dietary supplements

Dietary supplement companies must ensure their products are safe before marketing and comply with other labeling and quality requirements, such as good manufacturing practices.

The FDA inspects facilities for compliance and monitors adverse event reports.

Dietary supplements should be used only upon the advice of one’s health care provider for health-related reasons – not for the purpose of gaining a possible competitive advantage.

They recommend that coaches, athletic directors, and other school personnel develop strategies that address the prevalence and growing concerns of using dietary supplements. Such strategies may include conversations with athletes and their parents about the potential dangers of dietary supplement use.

Athletes should be encouraged to pursue their athletic goals through hard work, appropriate rest and good nutrition, not unsubstantiated dietary shortcuts.

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