What amount of force is required for a 200 kg grizzly bear to accelerate at 2.5 m/s/
s?

Answers

Answer 1
Dont mind the top part, hope this helped
What Amount Of Force Is Required For A 200 Kg Grizzly Bear To Accelerate At 2.5 M/s/s?

Related Questions

When you mix a solution, the mass of the substances before and after you mix them should be the same.true or false

Answers

Answer:

True

Explanation:

The mixing substances can be taken to be the reactants and the resulting mixture as the product. When the substances change state during mixing, the mass of the substances does not change meaning that the mass of the product will equal the mass of the reactants .This is true due to the law of conservation of mass.

Answer:

TRUE

Explanation:

because blablablabla blablolbleep scientific talk

Charges are of two kinds—negative charges and ________________ charges. __________ amounts of both kinds of charges are found in every piece of matter.

Answers

Answer: the first is positive and second is equal

Explanation:

Answer: 1. Positive

Explanation:

Because there is negative charges and positive charges

PLEASE HELP ASAP 2. Two rocks with a mass of 5 kilograms and 10 kilograms, respectively, fall freely from rest near
the Earth's surface. After 3 seconds of free-fall, compared to the 5-kg rock, the 10-kg rock has
greater...
a. acceleration
b. momentum
c. height
d. velocity
e displacement

Answers

Answer:

i Think momentum

Explanation:

PLEASE HELP ME! IM TIMED

Answers

Answer:

Toothpaste

Because it is viscous

Why can humans float in space but not on Earth?

Answers

Answer/explanation: on earth there is a gravitational pull discovered by sir Isaac Newton when an apple fell on his head. However in space there isn’t any gravity to keep you from drifting off.

Please help! Will mark brainliest!

Answers

Answer:

im pretty sure its d

Explanation:

What is the speed of an eagle that travels 200 meters in 4 seconds? A. 800 m/s2 B. 800 m/s C. 50 m/s2 D. 50 m/s​

Answers

Answer:

The answer is D.

Explanation:

You have to apply distance formula :

[tex]distance = speed \times time[/tex]

[tex]let \: d = 200,t = 4[/tex]

[tex]200 = s \times 4[/tex]

[tex]4s = 200[/tex]

[tex]s = 200 \div 4[/tex]

[tex]s = 50 \: m {s}^{ - 1} [/tex]

Given:-

An eagle travels 200 meters in 4 seconds

To find:-

Speed of the eagle

Solution:-Here

Distance=d=200m

Time=t=4s

As we know

[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]

Substitute the values

[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]

[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]

Hence Correct option is D

what is the KE of a 1.00 kg hammer swinging at 20.0 m/s? 200 Joules
I know the answer I just need help understanding it.

Answers

Answer:

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

If you are test-driving a Bugatti Veyron and you go from 0 m/s to 124 m/s in 3.7 seconds, what was your acceleration? ​

Answers

Answer:

initial velocity (u) = 0 m/s

Final velocity (v) =124 m/s

Time (t) = 3.7 s

acceleration (a) =?

Now

A =V-U /T

= 124-0 /3.7

= 33.51 m/s^2

tarzans mass is 75kg. calculate his weight

Answers

Answer:

75kg=165.346697lbs

Explanation: F A T

Two students are studying for a Science Test. On the table, they had a glass of water and identical cell phones. Both of their phones had run out of battery, therefore they were both charging in the same wall outlet. One student’s charging cord was 3ft and the other student’s charging cord was 9ft. which of the phones charged the fastest using Ohm’s Law. Cite evidence to support your theory.

Answers

Answer:

The student with the 3ft charger

Explanation:

Because the electricity from the 3ft charger has a shorter distance to mooves than the 9ft one

In how many ways can chemical reaction takes place? what are they?​

Answers

Answer:

Chemists classify chemical reactions in a number of ways: by type of product, by types of reactants, by reaction outcome, and by reaction mechanism. Often a given reaction can be placed in two or even three categories, including gas-forming and precipitation reactions.

Explanation:

mark me as brainliest thank you

Integrated Science- 8th grade science
Please Help ASAP!
Its almost the end of semester And I need to fix my grade for science so PLEASE help!
its almost report cards time!

Answers

Answer:

I do believe it is A.

Explanation:

I hope this helps :)

Answer:I believe it is A

Explanation: B just doesn't seem like something an 8th grader would be learning about, and I'm not sure about the other ones.

a motorbike can travel 1000 meters in 10 minutes calculate how car it can travel in 1 sec. ​

Answers

Answer:

1.67meter

Explanation:

if it can travel 1000 meters in 10 minutes, 10 minutes are 600 secs (10×60), 1000÷600 is 1.67

Answer:

HI

Explanation:

Donny, who has a mass of 75.0 kg, is riding at 25.0 m/s in his truck when he suddenly slams on the brakes to avoid hitting a squirrel crossing the road. His seatbelt brings his body to a stop in 0.500 seconds. What force does the seatbelt exert on him?

Answers

Answer:

F = 3750  N

Explanation:

Given that,

Mass of Donny, m = 75 kg

Initial speed, u = 25 m/s

He suddenly slams on the brakes to avoid hitting a squirrel crossing the road, final speed = 0

Time, t = 0.5 s

We need to find the force the seatbelt exert on him. The force is given by :

F = ma

a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{75\times (0-25)}{0.5}\\\\=-3750\ N[/tex]

So, the force is 3750  N.

The force the seatbelt exert on him is 3750 N

Using Newton's third law

f = ma

where

m = mass

a = acceleration

a = v - u / t

where

v = final velocity

u = initial velocity

t = time

Therefore,

f = m(v - u / t)

m = 75 kg

u = 25 m/s

t = 0.500 secs

v = 0 m/s (The car will stop because he applied a brake)

f = 75 × (0 - 25 / 0.5)

f = 75 × -25 / 0.5

f = 75 × -50

f = - 3750

f = 3750 N

read more: https://brainly.com/question/17372829?referrer=searchResults

a cannon launches a 3.0 kg pumpkin with 110J of kinetic energy. what is the pumpkin’s speed?

Answers

Answer:

v = 8.56 [m/s]

Explanation:

The kinetic energy can be calculated by means of the following equation.

[tex]E_{k}=\frac{1}{2}*m*v^{2}[/tex]

where:

m = mass = 3 [kg]

v = velocity [m/s]

Ek = kinetic energy [J]

[tex]110 = \frac{1}{2} *3*(v^{2} )\\v^{2} = 220/3\\v=\sqrt{73.333}\\v=8.56[m/s][/tex]

What is the period of a rotating object if it spins 24 times in 13 seconds?

Answers

Answer:

The period is 0.54 seconds

Explanation:

Period (T)

Is the time required for a rotating object to make one complete revolution around a circular path.

If it takes a time t to complete n revolutions, the period is:

[tex]\displaystyle T=\frac{t}{n}[/tex]

The rotating object spins n=24 times in t=13 seconds, thus its period is:

[tex]\displaystyle T=\frac{13}{24}[/tex]

T = 0.54 sec

The period is 0.54 seconds

STOP WHAT UR DOING!!! TAKE A MOMENT TO THINK ABOUT THESE!!

Cops pulling you over for speeding is like the adult version of teachers telling you not to run in the hallways.

Nothing makes sense, pizzas are round, the boxes we put them in are square and we eat them as triangles.

Some Scooby Doo episodes would be a lot shorter if they just went to the costume store first and asked a couple of questions.

I wonder if my cat thinks the delivery guy is my owner because he gives me food.

enjoy!!

Answers

Answer:

lol

can i have brainllest

Explanation:

Think of this how can a camera have a circler lens but take rectangular photos

Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s. Her friend, Samantha, is making smaller circles with a radius of 6 m but is not skating as quickly, going only 3.8 m/s.

How could each skater increase her centripetal acceleration without changing the size of her path? Explain your reasoning.

Answers

Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.

Explanation:

Find the kinetic energy of a 3.5 kg cat that has a momentum of 0.22 kg • m/s.
A) 3.98 x 10^-5 J
B) 4.32 x 10^-4 J
C) 6.91 x 10^-3 J
D) 7.22 x 10^-2 J

Answers

Answer:

6.19*10^-3 J

Explanation:

Just took the test. Kiss me

A 52 kg person is running 2.5 m/s. What is their momentum?

Answers

Answer:

130kg/ms

Explanation:

given data mass,52kgvelocity,2.5m/smomentum?from momentumM=mv

Mass=52kg

Velocity=2.5m/s

Momentum=?

We know that,

Momentum=Mass × velocity

Or,momentum=52kg× 2.5m/s

Or,momentum=130 kgm/s

So,the momentum is 130 kgm/s.

6th grade science I mark as brainliest.​

Answers

Answer:

Solution:-

Distance =400m

Time=20s

We need to find speed

As we know that

[tex]{\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}[/tex]

Substitute the values

[tex]\LARGE\leadsto\sf speed=\dfrac {400}{20}[/tex]

[tex]\LARGE\leadsto\sf 20m/s[/tex]

A warehouse worker pushed a cart weighing 4.50 kg to the top of an inclined plane. Initially, the cart was 0.670 m above the floor. If the top of the inclined plane is 2.70 m above the floor, calculate the work done by gravity as the worker pushed the cart to the top of the plane.

Answers

Answer:

- 89.523J

Explanation:

We solve the above question using work done(Potential Energy) formula

The formula =

-(mgh)

Where m = Mass = 4.50J

g = Acceleration due to gravity = 9.8m/s²

We are told in the question:

Initially, the cart was 0.670 m above the floor. If the top of the inclined plane is 2.70 m above the floor

Hence, the height =

2.70m - 0.670m = 2.03m

Work done = -(2.03m × 4.5kg× 9.8m/s²)

= - 89.523J

Please do all of i will give you brainlest and thanks to best answer plz do it right

Answers

Answer:

winter solstice i think

Explanation:

Answer:

a/ solar eclipse

Explanation:

because the moon is on the left side of earth

Select three effective methods for helping a friend who is showing self harming behavior

Answers

Answer:

Avoid judging or criticizing your friend.

Let your friend know that you care and want to help

Share the ways you cope with stress and other problems in your life

I had this question


An object starts at 16 m/s with an acceleration of 4.5 m/s? How far does it go in 9.0 seconds?

Answers

648 because 16 times 4.5 is 72 and that times 9 is 648

PLEASE HELP ME IM TIMED

Answers

Yeah it’s the mantle

Calculate the average speed of a runner who runs for 500 meters in 40 second HELP!

Answers

Answer:

12.5

Explanation:

500 divided by 40 = 12.5

A car’s brakes decelerate it at a rate of -2.20 m/s2. If the car is originally travelling at 17 m/s and comes to a stop, then how far, in meters, will the car travel during that time?

Answers

Answer:

x = 65.68 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}^{2}=v_{o}^{2}-2*a*x[/tex]

where:

Vf = final velocity = 0 (comes to stop)

Vo = initial velocity = 17 [m/s]

a = desaceleration = -2.2 [m/s²]

x = displacement [m]

Now replacing, we have:

[tex](0)^{2}=(17)^{2}-2*(2.2)*x\\4.4*x = 289\\x = 65.68 [m][/tex]

A :-) for this question , we should apply
2as = v^2 - u ^2
Given - u = 17 m/s
v = 0 m/s
a = -2.20 m/s^2
Solution -
2as = v^2 - u^2
2 x -2.20 x s = 0^2 - 17^2
s = 0^2 - 17^2 by 2 x -2.20
s = -( 17 x 17 ) by 2 x -2.20
( Cut minus ( - ) and ( - ) )
s = 17 x 17 by 2 x 2.20
s = 289 by 4.4
s = 65.6

.:. The car travelled 65.6 meters.

A book that weighs 5 N sits on a table. What force does the table apply to the book?

Answers

Answer:

E =F.d =[1/2]mv^2

mad = [1/2]mv^2

d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0

So d = at^2/2

F = ma= 20a= 50 , a=5/2 and t=2

so d = [5/2][2^2]/2=5

Explanation:

Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

What is Newton's third law of motion?

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

The given data in the problem is ;

W is the weight of the book sits on table = 5N

N is the normal force on the book

From the equilibrium equation ;

Weight -Normal force on the book  =0

Weight =Normal force on the book

The normal force on the book =5N

Hence the table exerts a force of 5 N on the book in order to be in stable condition.

To learn more about Newton's third law of motion refer to the link;

https://brainly.com/question/1077877

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