Answer:
Negative feedback control of the amplifier is achieved by applying a small part of the output voltage signal at Vout back to the inverting ( – ) input terminal via the feedback resistor
Answer:
The system has parts that sense the amount of output
Explanation:
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What are the main causes of injuries when using forklifts?
The forklift overturning is a very common way of getting injured from a forklift. Overturning the forklift means it tips over onto it's side due to the operator turning it too fast.
Which items are NOT found on a
door?*
5 points
Cladding
Moulding
Weatherstrip
Check Strap
Striker
All of the above
None of the above
Answer:
None of the above cause thats what i put
Which one is NOT a benefit of Shine? 1. Less production downtime 2.Happier employees 3. Improved quality 4. Inventory reduction 5. Customer satisfaction
Answer:
Inventory reduction
Explanation:
Shine is a term that deals with the general cleaning and overall maintenance of the workplace. It is used as a part of an organizational theme involving five steps which are often referred to as 5S and it is basically defined as the mainstay of the visual workplace. They are Sort, Set in order, Shine, Standardize, and Sustain.
Hence, in this situation, considering the option that is not a benefit of Shine the correct answer is "Inventory reduction." This is because Shine is not about reducing the inventory levels. It is Sort and Set-in-Order will help reduce inventory.
The answer choice which is NOT a benefit of Shine is:
D. Inventory reduction
According to the given question, we are asked to show the answer choice which is not a direct benefit of Shine and how Shine is used to increase productivity in an office space.
Shine is a term which is used to refer to the general cleanliness of an office space and is a part of organization which is used to improve quality, make the employees happier, and have a less production downtime, etc
As a result of this, we can see that inventory reduction is not a benefit of Shine.
Therefore, the correct answer is option D
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A company that produces footballs uses a proprietary mixture of ideal gases to inflate their footballs. If the temperature of 230 grams [g] of gas mixture in a 15-liter [L] tank is maintained at 465 degrees Rankine [°R] and the tank is pressurized to 135 pound-force per square inch [psi], what is the molecular weight of the gas mixture in units of grams per mole
Answer:
The molecular weight of the gas mixture is 35.38 g/mol.
Explanation:
The molecular weight of the gas can be found using the following equation:
[tex] M = \frac{m}{n} [/tex]
Where:
m: is the mass = 230 g
n: is the number of moles
First, we need to find the number of moles using Ideal Gas Law:
[tex] PV = nRT [/tex]
Where:
P: is the pressure = 135 psi
V: is the volume = 15 L
R: is the gas constant = 0.082 L*atm/(K*mol)
T: is the temperature = 465 °R (K = R*5/9)
[tex]n = \frac{PV}{RT} = \frac{135 psi*\frac{1 atm}{14.6959 psi}*15 L}{0.082 L*atm/(K*mol)*465*(5/9) K} = 6.50 moles[/tex]
Finally, the molecular weight of the gas is:
[tex] M = \frac{m}{n} = \frac{230 g}{6.50 moles} = 35.38 g/mol [/tex]
Therefore, the molecular weight of the gas mixture is 35.38 g/mol.
I hope it helps you!
what type of diagrams can you create using a compass, a T-square, a triangle, and a protractor?
Answer:
15
Explanation:
A compass may be used to create circles, arcs, bisect lines, angle bisectors, and locate midpoints. By using a compass, a protector is also drawn.
What is the compass?A compass, or more correctly, a pair of compasses, is a tool for technical drawing that may be used to draw arcs or circles. It can also be used as dividers to indicate distances, particularly on maps.
A compass, or more correctly, a pair of compasses, is a tool for technical drawing that may be used to draw arcs or circles. It may also be used as dividers to indicate distances, particularly on maps. Compasses can be used for navigation, mathematics, and other things.
Therefore, a protector is sketched using a compass.
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for high-volume production runs, machining parts from solid material might not be the best choice of manufacturing operations because
Answer:
There are actually multiple types of processes a manufacturer uses, and those can be grouped into four main categories: casting and molding, machining, joining, and shearing and forming.
Explanation:
1. Looking at the case study provided under the Companion Material section, what is the main problem that is addressed in this case study? Maintenance workers painted over the pipes. Engineers lost all of their work because of the flood. The water pipes broke and flooded the space center. There was no paperwork for the maintenance work done on the pipes.
Incomplete question. However, I provided information that could assist you in identifying the main problem or issue addressed in any case study.
Explanation:
First, note that a case study is simply a learning aid that allows one to learn from a real-life scenario.
To determine the main problems of a case study one needs to:
Read the case as many times as possible to become familiar with the message been expressed. For example, by highlighting or underlining the most important facts it can help you to discover the main problem or issue. Check for any facts provided in the case study, by so doing you can identify the most important problems.Thus, by taking these few steps you may be able to determine the main problem in that case study.
The production process of rods from machine "A" yields specimen with the following specs. Mean: µ(LA)=20.00mm, STD: s(LA)=0.50mm. You need to purchase new machine to increase the production capacity and accuracy together. If the new machine "B" will produce half of the total rods, what is the STD, s(LB), that needs to achieve the total STD, s(LT)=0.4mm? Assume Corr(A,B)=0.4
Answer: the standard deviation STD of machine B is s (Lb) = 0.4557
Explanation:
from the given data, machine A and machine B produce half of the rods
Lt = 0.5La + 0.5Lb
so
s² (Lt) = 0.5²s²(La) + 0.5²s²(Lb) + 0.5²(2)Cov (La, Lb)
but Cov (La, Lb) = Corr(La, Lb) s(La) s(Lb) = 0.4s (La) s(Lb)
so we substitute
s²(Lt) = 0.25s² (La) + 0.25s² (Lb) + 0.4s (La) s(Lb)
0.4² = 0.25 (0.5²) + 0.25s² (Lb) + (0.5)0.4(0.5) s(Lb)
0.64 = 0.25 + s²(Lb) + 0.4s(Lb)
s²(Lb) + 0.4s(Lb) - 0.39 = 0
s(Lb) = { -0.4 ± √(0.16 + (4*0.39)) } / 2
s (Lb) = 0.4557
therefore the standard deviation STD of machine B is s (Lb) = 0.4557
Use the diagram to determine total resistance. (Round the FINAL answer to one decimal place.) Note: Use the rated voltage and wattage to determine resistance. Note: Ra and Rb represent the resistance of the wire. The 120 volts of the motor and lamps is their rated voltage and not the actual voltage. I know the answer is 22.7 Ohms. I get very close, but I am not 100%.. I need to be 100%. If you can also: with the same diagram I need the total current as well! Thank you very much.
Answer:
22.6622 Ω ≈ 22.7 Ω5.29516 A ≈ 5.3 AExplanation:
For an electric motor, 1 hp = 746 W, so 1/2 hp = 373 W. Then the total wattage of the load is ...
Pl = 373 +100 +100 +75 = 648 W
The equivalent resistance is ...
R = V^2/P = (120 V)^2/(648 W) = 22 2/9 Ω
Adding the wiring resistance, we get a circuit resistance of ...
22.2222 +0.22 +0.22 = 22.6622 Ω . . . . total circuit resistance
Then the circuit current is ...
120 V/(22.6622 Ω) ≈ 5.29516 A
Circuit resistance is about 22.7 Ω; circuit current is about 5.3 A.
_____
Exact values are 5099/225 ohms and 27000/5099 amps. Of course, these assume the motor and lamps are purely resistive, which they are not.
An eyewash station needs to be located no more than 10 seconds or less than 55 feet away from a work area.
Answer: True is correct
A third-degree burn may look charred and black or dry and white.
Explanation:
How can you safely lift and support a vehicle
Answer:
Place the jack under the part of the vehicle that it should contact when raised. If you're using jack stands, place them near the jack. If you place your jack incorrectly, you can injure your car. To find the proper place to position the jack for your particular vehicle, check your owner's manual.
A picture of a ____ is the label pictogram on a chemical that warms of a product's acute toxicity
Answer:skull and crossbones
Explanation:
. Fume is the product of consumables, base metals, and coatings on metals during arc welding processes (during all cutting, brazing, and welding). A) TrueB) False
Answer:
True
Explanation:
This is true. Welding fumes are a combination of metallic oxides, silicates and also fluorides. the formation of these films are a result of a metal being exposed to heat above its boiling point and a condensation of its vapours into good fine particles. such films are made up of particles from the material that one is welding and also particles from electrode.
A standard carbon resistor has a gold band to indicate + 5% tolerance. If its resistance is 3,500 , what are the upper and lower limits for its resistance? OA . 3495 - 3505 2 OB. 3300 Q - 3600 0 OC. 3325 N - 3675 OD 3450 - 35500
Answer:
C. 3325 Ω - 3675 Ω
Explanation:
5% of 3500 Ω is ...
0.05 × 3500 = 175
The lower limit is this amount less than the nominal value:
3500 -175 = 3325
The upper limit is the nominal value plus the tolerance:
3500 +175 = 3675
The lower and upper limits are 3325 Ω and 3675 Ω, respectively.
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields under a load of 97,944 N. The corresponding gage length = 50.2 mm - this is at the 0.2 percent yield point. The maximum load of 162,699 N is reached at a gage length = 63 mm. If fracture occurs at a gage length of 71 mm, determine the percent elongation in % - enter your answer as a whole number, not as a fraction.
Answer:
The percent elongation in the length of the specimen is 42%
Explanation:
Given that:
The gage length of the original test specimen [tex]L_o[/tex] = 50 mm
The final gage length [tex]L_f[/tex] = 71 mm
The area = 206 mm²
maximum load = 162,699 N
To determine the percent elongation in %, we use the formula:
[tex]\%EL = \dfrac{L_f-L_o}{L_o}\times 100[/tex]
[tex]\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100[/tex]
[tex]\%EL = \dfrac{21 mm}{50 \ mm}\times 100[/tex]
[tex]\%EL = 0.42 \times 100[/tex]
[tex]\mathbf{\%EL = 42 \%}[/tex]
The percent elongation in the length of the specimen is 42%
A sign that has a white background with a
green panel with white lettering is a
a. general information sign
b. safety instruction sign
c. caution sign
d. danger sign
Answer:
A
Explanation:
general information sign
safety is orange
caution is yellow
danger is red
Which of the following was an effect of world war 2 on agricultural industry
Answer:
Option C..Farmers saught new technology to help with the workload
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Most hazardous waste can be disposed of in a landfill. A) TrueB) False
Answer:
This one is false
Explanation:
I just took a test on it..
Most hazardous waste can be disposed of in a landfill. Thus, the above statement is true. Thus, option (A) is correct.
What is the meaning of hazardous waste?A hazardous waste is a waste that has characteristics that make it unsafe or allow it to negatively impact the environment or human health.
Wastes classified as hazardous have characteristics that make them unsafe or potentially damaging to the environment or human health. Liquid, solid, confined gas, and sludge are all examples of hazardous wastes.
Any source that could potentially cause injury, damage, or unfavorable health impacts to someone or something is a hazard.
The majority of hazardous garbage can be dumped in landfills. So, the aforementioned claim is accurate. Therefore, it can be concluded that option (A) is correct.
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This ball is technology too! It can be
rolled, kicked, or thrown. Is that a need
or a want?
That is an example of a want because you don't need the ball.
The easiest way to reduce your exposure to dangerous fumes is to keep your head out of a fume plume, making sure that you're breathing the cleanest air possible.
Answer:
keep your head out of a fume plume
Explanation:
According to the guidelines and precaution procedures of OSHA, an acronym for Occupational Safety and Health Administration in the United States of America stated that The easiest way for an individual to reduce his or her exposure to dangerous fumes is to ensure that such person keeps his or her head out of a fume plume.
Hence, in this situation, the correct answer is "keep your head out of a fume plume"
What is the transfer of energy from one object to another?
Answer:
Kinetic Energy
Explanation:
Energy is transferred from one object to another when a reaction occurs. Energy can be transferred from one object to another as heat, light, and motion.
- The four leading causes of death in the
construction industry include electrical
incidents, struck-by incidents, caught-in or
caught-between incidents, and
a. vehicular incidents
b. falls
C. radiation exposure
d. chemical burns
Solve the compound inequality. 3x − 4 > 5 or 1 − 2x ≥ 7
Five kg of water is contained in a piston–cylinder assembly, initially at 5 bar and 240°C. The water is slowly heated at constant pressure to a final state. The heat transfer for the process is 2660 kJ and kinetic and potential energy effects are negligible. Determine the final volume, in m3, and the work for the process, in kJ.
Answer:
Explanation: that’s the answer! 46kg
Six forces act on a beam that forms part of a building's
frame. The vector sum of the forces is zero. The magnitudes
|FB| = Fel 20 kN, Fc = 16 kN, and (Fpl = 9 kN.
Determine the magnitudes of FA and FG.
Answer:
FA = 13 kN FG = 15.3 kNExplanation:
write each force in terms of magnitude and directions
Fx = F sin Ф
Fy = F cos Ф
where Ф is to be measured from x axis.
∑F at y = o
FAy + FBy + FCy + FDy + FEy + FGy = 0
∑F at x = o
FAx + FBx + FCx + FDx + FEx + FGx = 0
Let
FA = FA sin (110) + FA cos (110)
FB = 20 sin (270) + 20 cos (270)
FC = 16 sin (140) + 16 cos (140)
FD = 9 sin (40) + 9 cos (40)
FE = 20 sin (270) + 20 cos (270)
FG = FG sin (50) + FG cos (50)
add x and y forces:
FAx + FBx + FCx + FDx + FEx + FGx = 0
FAy + FBy + FCy + FDy + FEy + FGy = 0
FA sin (110) + 0 + 16 sin (140) + 9 sin (40) + 0 + FG sin (50) = 0
FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0
FA sin (110) + 0 + 10.285 + 5.785 + 0 + FG sin (50) = 0
FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0
FA sin (110) + 16.070 + FG sin (50) = 0
FA cos (110) - 45.363 + FG cos (50) = 0
solving for FA, and FG
FA = 13 kN
FG = 15.3 kN
From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.
From the diagram, equating the component of the upward forces and the downward forces, we have:
[tex]\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}[/tex] --- (1)
Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:
[tex]\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}[/tex]
If:
[tex]F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN[/tex]
Then, from equation (1), we can have the following:
[tex]\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}[/tex]
collecting like terms;
[tex]\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }[/tex]
[tex]\mathbf{F_a sin 70 + F_gsin 50 =23.93}[/tex] --- (3)
From equation (2);
[tex]\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}[/tex]
collecting like terms:
[tex]\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}[/tex]
[tex]\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}[/tex]
Suppose we equate (3) and (4) together using the elimination method;
[tex]\mathbf{F_a sin 70 + F_gsin 50 =23.93}[/tex] --- (3)
[tex]\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}[/tex]
Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);
Then, we have:
[tex]\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}[/tex]
[tex]\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}[/tex]
Adding both previous equations together, we have:
[tex]\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}[/tex]
[tex]\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}[/tex]
[tex]\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}[/tex]
[tex]\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}[/tex]
[tex]\mathbf{( F_g(0.866)) =(13.23)}[/tex]
[tex]\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}[/tex]
[tex]\mathbf{ F_g =15.28 \ N}[/tex]
Replacing the value of [tex]\mathbf{F_g}[/tex] into equation (3), to solve for [tex]\mathbf{F_a}[/tex], we have:
[tex]\mathbf{F_a sin 70 + F_gsin 50 =23.93}[/tex]
[tex]\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\[/tex]
[tex]\mathbf{F_a =13.01 \ N}[/tex]
Therefore, we can conclude that the magnitudes of [tex]\mathbf{F_a}[/tex] and [tex]\mathbf{F_g}[/tex] are 13.0 N and 15.28 N respectively.
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Steam enters a two-stage adiabatic turbine at 8 MPa and 5008C. It expands in the first stage to a state of 2 MPa and 3508C. Steam is then reheated at constant pressure to a temperature of 5008C before it is routed to the second stage, where it exits at 30 kPa and a quality of 97 percent. The work output of the turbine is 5 MW. Assuming the surroundings to be at 258C, determine the reversible power output and the rate of exergy destruction within this turbine.
Answer:
1) The exergy of destruction is approximately 456.93 kW
2) The reversible power output is approximately 5456.93 kW
Explanation:
1) The given parameters are;
P₁ = 8 MPa
T₁ = 500°C
From which we have;
s₁ = 6.727 kJ/(kg·K)
h₁ = 3399 kJ/kg
P₂ = 2 MPa
T₂ = 350°C
From which we have;
s₂ = 6.958 kJ/(kg·K)
h₂ = 3138 kJ/kg
P₃ = 2 MPa
T₃ = 500°C
From which we have;
s₃ = 7.434 kJ/(kg·K)
h₃ = 3468 kJ/kg
P₄ = 30 KPa
T₄ = 69.09 C (saturation temperature)
From which we have;
h₄ = [tex]h_{f4}[/tex] + x₄×[tex]h_{fg}[/tex] = 289.229 + 0.97*2335.32 = 2554.49 kJ/kg
s₄ = [tex]s_{f4}[/tex] + x₄×[tex]s_{fg}[/tex] = 0.94394 + 0.97*6.8235 ≈ 7.563 kJ/(kg·K)
The exergy of destruction, [tex]\dot X_{dest}[/tex], is given as follows;
[tex]\dot X_{dest}[/tex] = T₀ × [tex]\dot S_{gen}[/tex] = T₀ × [tex]\dot m[/tex] × (s₄ + s₂ - s₁ - s₃)
[tex]\dot X_{dest}[/tex] = T₀ × [tex]\dot W[/tex]×(s₄ + s₂ - s₁ - s₃)/(h₁ + h₃ - h₂ - h₄)
∴ [tex]\dot X_{dest}[/tex] = 298.15 × 5000 × (7.563 + 6.958 - 6.727 - 7.434)/(3399 + 3468 - 3138 - 2554.49) ≈ 456.93 kW
The exergy of destruction ≈ 456.93 kW
2) The reversible power output, [tex]\dot W_{rev}[/tex] = [tex]\dot W_{}[/tex] + [tex]\dot X_{dest}[/tex] ≈ 5000 + 456.93 kW = 5456.93 kW
The reversible power output ≈ 5456.93 kW.
To create an effective study schedule, a student must
guess the amount of time needed for studying.
O write down all activities and commitments.
O allow the same amount of time each day for studying.
O budget periods of time to study daily, even if it is interrupted.
Answer:
B) write down all activities and commitments.
Explanation:
also i found the answer on quizlet hope this works:))
Answer:
write down all activities and commitments.
Explanation:
i had got the same question on my unit test and it was the answer it was right
Explain how engineering and science-related?
Answer:
While scientists study how nature works, engineers create new things, such as products, websites, environments, and experiences. Because engineers and scientists have different objectives, they follow different processes in their work.
Explanation:
You are an engineer working in a auto crash test lab. Some members of your team have raised objections against the use of cadavers in the crashes. No reliable data exists that shows that cadavers produces more accurate data, but many coworkers argue that common suggest they do. Others claim that the use of cadavers as mere instruments for our well-being disrespects those individuals, who have not consented to use their bodies for this purpose. The question of whether to continue to use cadavers in the lab is what kind of issue?
Answer: Application.
Explanation:
The question on wether to contine the use of cadavers in the lab for test is being centered around its application. Cadaver which is same as a corpse or dead body is used in crash site during automobil test in lab, some of this cadavers are been disrespected with their applications in the automobile industries because many didn’t consent to be used in those experiments or test.
__________ use cleaning solutions that eventually become spent and must be disposed of properly
a sump pits
b car washers
c part washers
d tire cleaners
Answer:Part washers
Explanation:
I did it..
The only option that uses cleaning solutions that become spent and must be disposed properly is;
Option C; Parts Washers
To answer this question, let us examine each option;
Option A; Sump Pits; These are basins at the lowest part of specific areas designed to allow all water collected in that basin area to drain into it. This has no business with cleaning solution.
Option B; Car washers; These are like machine dryers used to clean the exterior and interior parts of motor vehicles.
Option C; Part Washers; These are mechanical devices that are designed for cleaning to remove debris, grime, oil dirt, paint, and other substances that could potentially cause contamination from parts in order to get them ready for assembling, packaging, or even coating. They are basically used to clean parts to get them ready for functional use.
Option D; Tire cleaner is just used to clean tire but is not something that becomes spent and should be disposed properly as it is more like a liquid.
The only correct option is Option C.
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