Answer:
To determine the percentage decrease in W when x is decreased by 9.75%, we need to first determine the relationship between w and x. Since w is proportional to the square root of x, we can write an equation to represent this relationship as follows:
w = k * √x
where k is the proportionality constant.
If the value of x is decreased by 9.75%, we can write the new value of x as follows:
x' = x * (1 - 0.0975) = x * 0.9025
Substituting this expression for x' into the equation above, we get:
w' = k * √(x * 0.9025)
To determine the percentage decrease in w, we can divide the new value of w by the original value of w and multiply by 100% to get the percentage change, or:
percentage decrease in w = (w' / w) * 100%
Substituting the expressions for w' and w into this equation, we get:
percentage decrease in w = [(k * √(x * 0.9025)) / (k * √x)] * 100%
Simplifying this expression, we get:
percentage decrease in w = (√(0.9025)) * 100%
Since the square root of 0.9025 is approximately 0.95, we can say that the percentage decrease in w is approximately 5%. This means that the value of w decreases by approximately 5% when the value of x decreases by 9.75%.
what formula is used to gain information about an individual data value when the variable is normally distributed?
The formula used to gain information about an individual data value when the variable is normally distributed is called the z-score formula.
It is used to calculate how many standard deviations a value lies above or below the mean of the data set. The formula is:
z-score = (x - μ) / σ
where x is the data value, μ is the mean of the data set, and σ is the standard deviation of the data set.
To find the z-score of an individual data value when the variable is normally distributed, use the z-score formula. This formula subtracts the mean (μ) from the data value (x) and divides by the standard deviation (σ). This calculation will give you the number of standard deviations the data value lies above or below the mean.
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A clothesline rope is 8 feet long. Which of these is another way to express 8 feet?answer choicesa. A/Fb. B/Gc. C/Hd. D/J
As per the concept of unitary method, the another way to express 8 feet is 2 [tex]\frac{2}{3}[/tex] yards.
In math, unitary method is known as a way of finding out the solution of a problem by initially finding out the value of a single unit, and then finding out the essential value by multiplying the single unit value.
Here we have given that a clothesline rope is 8 feet long.
Now we need to find another way to express 8 feet
We know that the formula to convert the measurement it to divide the length by the conversion ratio.
As we know that one yard is equal to 3 feet, then we can use this simple formula to convert is written as
yards = [tex]\frac{feet}{3}[/tex]
Then we have to convert the improper fraction into mixed fraction from, then we get,
2[tex]\frac{2}{3}[/tex] yards
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what to put for 1 and 2
Answer:
Wdym what to put for 1 and 2??
Step-by-step explanation:
there’s no picture on my screen ;-;
a certain bridge is 4,024 feet long. approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile
At a continuous speed of 20 miles per hour, it takes 2 minutes to cross this bridge.
What is a unitary approach?The unitary method is used to calculate the value of a single unit and then multiply that value by itself in order obtain the desired value. Unitary refers to a single, unique, or solitary unit. As a result,
this method's objective is to establish values in terms of a single unit. If a car can drive 44 kilometer two litres of gas, for instance, the unitary approach can be used to calculate how many kilometers it can travel on one litre of gas. The value of a single unit is determined by the unitary technique, and also the value of the required quantity of units can then be calculated using this value.
given,
0.76 miles = (4024/5280) miles
Speed =20 miles per hour
Time: =(Distance / Speed) = (0.76/20)
= 0.038 ( in hours )
into minutes = 2 min
At a continuous speed of 20 miles per hour, it takes 2 minutes to cross this bridge
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question 1: is the null hypothesis rejected or not rejected for an observed p-value of at 0.07 at a significance level of 0.05?
the null hypothesis is rejected for an observed p-value of at 0.07 at a significance level of 0.05.
At a significance level of 0.05, the p-value of 0.07 indicates that the observed value is not statistically significant. As a result, the null hypothesis cannot be disproven.In other words, the observed value is not strong enough to prove that the null hypothesis is false. Therefore, the null hypothesis is not rejected for an observed p-value of 0.07 at the significance level of 0.05.
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Solve the equation.
-5x³+x+2x³=7-3x³
Answer:3.3
Step-by-step explanation:
2.
What are the coordinates of the midpoint of the line
segment with endpoints (2,-5) and (8,3)?
1) (3,-4) 2) (3,-1) 3) (5,-4) 4) (5,-1)
Answer:
4) (5, -1)
Step-by-step explanation:
To find the midpoint, we must average the x coordinates to find the x-coordinate of the midpoint and average the y-coordinates to find the y-coordinate of the midpoint.
Thus, we do:
x-coordinate: [tex]\frac{2 + 8}{2}[/tex] = [tex]\frac{10}{2}[/tex] = [tex]5[/tex]
y-coordinate: [tex]\frac{-5 + 3}{2}[/tex] = [tex]\frac{-2}{2}[/tex] = [tex]-1[/tex]
This means the midpoint has an x-coordinate of 5 and a y-coordinate of -1. This can be expressed as the point (5, -1), which is option 4
A hospital is trying to cut down on emergency room wait times. It is interested in the amount of time patients must wait before being called back to be examined. An investigation committee randomly surveyed 80 patients. The sample mean was 1. 5 hours, with a sample standard deviation of 0. 7 hours. The upper- bound 95% confidence interval is.
In an effort to reduce wait times in the emergency room. Eighty patients were polled at random by the investigating committee. And, the upper-bound 95% confidence interval is found to be 1.64.
For small sample numbers or unidentified changes, the t-distribution is used in statistics to calculate the significance of population parameters.
Given sample mean [tex]\overline{X}[/tex] is 1.5 hours, sample size n is 80, and sample standard deviation s is 0.7 hours. Then, the standard error for the mean is,
[tex]\begin{aligned}SE_x&=\frac{s}{\sqrt{n}}\\&=\frac{0.7}{\sqrt{80}}\\&=0.07826\end{aligned}[/tex]
The degree of freedom is given by, df = n-1 = 80-1 = 79.
From the t-distribution table, [tex]t_{\alpha/2, 79}=1.7735[/tex]
Then, the upper-bound 95% confidence interval is calculated as,
[tex]\begin{aligned}\overline{X}+t_{\alpha,(n-1)}\frac{s}{\sqrt{n}}&\geq \mu\\&=\overline{X}+t_{0.08, 79}\frac{s}{\sqrt{n}}\\&=1.5+1.7735\left(\frac{0.7}{\sqrt{80}}\right)\\&=1.5+1.7735(0.07826)\\&=1.5+0.13879\\&=1.63879\\&\approx1.64\end{aligned}[/tex]
The required answer is 1.64.
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the ages for a random sample of 30 employees at house mart resulted in the following descriptive statistics. the lower and upper limits for a 99% confidence interval would be approximately and ?
The lower and the upper limit for a 99% confidence interval would be approximately 37.51 and 50.03
Here,
Mean = 43.77
Standard deviation (s)= 12.43655
n= 30
So,
CI= mean ± t (s/√n)
= 43.77±2.756(12.43655/√30)
= 43.77±6.26
= 37.51,50.03
So, the lower and upper limit would be 37.51 and 50.03
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Find the values for each box using the image shown
Answer:
answer on the picture..........
if a sum of two real numbers is less than 50, then at least one of the numbers is less than 25.
We may demonstrate via a contrapositive assertion that if the total of two real numbers is less than 50, then at least one of the numbers must be less than 25.
The purpose is to demonstrate the following using contraposition:
Take the negation of the hypothesis and the conclusion to produce the conditional statement's opposite. Create the inverted statement first, then swap the hypothesis and conclusion to create the contrapositive of the conditional statement.
Contrapositive assertions, in other words, result from adding "not" to both component claims and reversing the order of the given conditional statements.
Two real numbers will have a sum that is larger than or equal to 50 if neither of them is smaller than 25.
Assume for all real numbers r and s r≥25, s≥25
By using inequality algebra,
r+s≥25+25
≥50
This demonstrates that two numbers will add up to a value more than or equal to 50 if neither of them is less than 25.
Hence, r + s<50, then r<25, s<25 by contrapositive statement.
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from a point 1.5 mi from a launcch pad at cape canaveral, an observer sights a space shuttle at an angle of elevation of 10 degrees moments after it is launched. after 10 seconds, the angle of elevation is 50 degrees. how far does the space shuttle travel vertically during the 10 second interval? what is the average speed of the space shuttle during that interval?
Answer:
1.523 mi548 mi/hStep-by-step explanation:
Given angles of elevation of 10° and 50° measured 10 seconds apart from an observation point 1.5 miles away, you want to know the vertical change in distance, and the average speed of the shuttle between the two observations.
HeightThe tangent relation tells you ...
Tan = Opposite/Adjacent
Then the height of the shuttle at the observed angles was ...
Opposite = Tan · Adjacent
h1 = tan(10°)·(1.5 mi) ≈ 0.264490 mi
h2 = tan(50°)·(1.5 mi) ≈ 1.787630 mi
Vertical travelThe amount of vertical travel in the 10-second interval was ...
1.787630 mi -0.264490 mi = 1.523240 mi
The space shuttle traveled about 1.523 miles vertically in the 10-second interval.
SpeedIn miles per second, the average speed during that time was about ...
(1.523 mi)/(10 s) = 0.1523 mi/s
In miles per hour, that's about ...
(0.1523 mi/s)(3600 s/h) ≈ 548 mi/h
show your work
please
Answer:
C
Step-by-step explanation:
[tex]\frac{6y }{x^{8} } . \frac{4y}{x^{14} }\\\\\frac{24y^{2} }{x^{8+14} } \\\\\frac{24y^{2} }{x^{22} }[/tex]
Enter the value of x below.
x+4=12
X=?
Suppoe that 19% of people have a dog,24% of people have a cat , and 14% of people have both
19% of people have a dog,24% of people have a cat , and 14% percentage of people have both 62% of people have either a dog or a cat.
To find the percentage of people that have either a dog or a cat, we need to add the percentage of people that have a dog to the percentage of people that have a cat.
19% + 24% = 43%
Therefore, 62% of people have either a dog or a cat.
43% of people have either a dog or a cat, but do not have both. We can find this by subtracting the percentage of people that have both a dog and a cat from the total percentage.
43% - 14% = 29%
Therefore, 29% of people have a dog or a cat, but not both.
The complete question is:
Suppoe that 19% of people have a dog,24% of people have a cat , and 14% of people have both dog and cat.
What percentage of people have either a dog nor a cat?
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The number of cigarettes a person smokes varies inversely with how long they can hold their breath. A person who smokes 10
cigarettes a day can hold their breath for 50 seconds.
Find the (k) constant of variation.
To find the constant of variation in this situation, we need to use the formula for inverse variation, which is:
y = k / x
where y is the number of cigarettes a person smokes, x is the length of time they can hold their breath, and k is the constant of variation.
In this case, we are given that y = 10 cigarettes and x = 50 seconds. We can solve for k by multiplying both sides of the equation by x:
k = y * x
= 10 cigarettes * 50 seconds
= 500
Therefore, the constant of variation in this situation is 500. This means that for every 50 seconds of breath-holding time, a person will smoke approximately 10 cigarettes.
leena consumes 400 calories at breakfast and 350 calories at lunch. she consumes startfraction 2 over 3 endfraction. of her daily calories at dinner. if x represents the calories consumed at dinner, which statements describe the situation? check all that apply.leena consumed 1,500 calories at dinner.the equation startfraction 2 over 3 endfraction left-parenthesis x plus 400 plus 350 right-parenthesis equals x.(x 400 350)
The correct statements are:
1) Leena consumed 1,500 calories at dinner.
2) The equation 2/3(x + 400 + 350) = x
In this question we have been given Leena consumes 400 calories at breakfast and 350 calories at lunch. she consumes 2/3 of her daily calories at dinner.
We need to select a statement that describes the situation if x represents the calories consumed at dinner.
Let x be the calories consumed at dinner.
Leena consumes 400 calories at breakfast and 350 calories at lunch.
So, the daily calories consumed by her:
400 + 350 + x
Given that she consumes 2/3 of her daily calories at dinner.
From given conditions we get an equation,
x = 2/3(x + 400 + 350)
3x = 2(x + 750) ............(multiply both sides by 3)
3x = 2x + 1500
3x - 2x = 2x + 1500 - 2x ...............(subtract 2x from both sides)
x = 1500 calories
Therefore, Leena consumed 1500 calories at dinner.
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find the value of x.
124°
(5x-4)°
I believe the answer is x= 12
If f(2x + 5) = 6x + 19, find fof(2).)
Answer:
x = 4.083
Step-by-step explanation:
6(2x+5)+19=0
12x+30+19=0
12x+49=0
12x=-49
x=4.083
Answer:
f(2x + 5) = 6x + 19
= 6(2x + 5) + 19
= 12x + 30 + 19
= 12x + 49
f(2) = 12x + 49
= 12(2) + 49
= 73
Step-by-step explanation:
heart and star pls <3 brainliest will be appreciated <3(っ◔◡◔)っ -{ elyna s }-on her way home from the school board meeting, kelly fills up her car. she likes the idea of using gasoline with ethanol, but thinks her car can only handle 50% ethanol. at the gas station, she can use regular gas with 15% ethanol or e78 fuel with 78% ethanol. how many gallons of each type of fuel should kelly use if she wants to fill up her car with 9 gallons of fuel containing 50% ethanol? 5 gallons of regular gas with 15% ethanol; 4 gallons of e78 fuel with 78% ethanol 6 gallons of regular gas with 15% ethanol; 3 gallons of e78 fuel with 78% ethanol 4 gallons of regular gas with 15% ethanol; 5 gallons of e78 fuel with 78% ethanol 3 gallons of regular gas with 15% ethanol;
She'll need 4 gallons of 15% ethanol gasoline and 5 gallons of 78% ethanol gasoline.
What is expression?An expression or mathematical expression is a finite collection of symbols that is well-formed according to context-dependent norms.
Here,
The number of gallons required of both kind would be as follows:
4 gallons having 15% ethanol
5 gallons having 78% ethanol
Given that,
The 2 kinds of gases are:
One with 15% ethanol
Other with 78% ethanol
Given that,
The gases(ethanol and gasoline) are diluted in a such a manner that it involves a total of only 50% ethanol.
Number of gallons she wants to use = 9
This shows that only 50% of 9 gallons i.e. 4.5 gallons of ethanol can be used.
Assuming x being the gasoline's measure that is diluted with 15% ethanol.
Now,
The gasoline's measure that is diluted with 78% ethanol would be = 9 - x gallons
Therefore,
x × 15% + (9-x) × 78% = 4.5
On solving, we get
x = 4 gallons
Thus,
The measure of gallons having 15% ethanol = 4
The measure of gallons having 78% ethanol = (9 - x)
= (9 - 4)
= 5 gallons
She will use 4 gallon of 15% ethanol gas and 5 gallon of 78% ethanol gas.
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Respond these question please
The percentile rank of the score 71 on the test is 26.7.
What is a percentile?The value that a specific percentage falls under is known as the percentile. Ben, for instance, is the fourth-tallest child in a group of 20, and eighty percent of the kids are shorter than you.
Given:
58, 64, 66, 70, 71, 75, 77, 80, 84, 85, 87, 90, 93, 95, 96
Calculate the percentile of score 71 as shown below,
[tex]Percentile = n / N \times 100[/tex]
Here, n is the number of scores below 71 and N is the total number of scores,
Percentile = 4 / 15 × 100
Percentile = 0.267 × 100
Percentile = 26.7 percentile
Therefore, the percentile rank of the score 71 on the test is 26.7
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Complete the table to combine like terms when adding Expression One and
Expression Two.
4a
-9
Term from Expression One
14
-3a
10a
5
23
Like Term from Expression Two
DRAG AND DROP
SAN CEM HERE
7a
Expression One
14-3a
Expression Two
7a-9
Combined Term
DRAC
ERE
CHECK
Please help & thank you
If the two expression be 14 - 3a and 7a - 9 then the combined term exists 4a + 5.
What is meant by expression ?A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation. It is possible to multiply, divide, add, or subtract in math. An expression has the following structure: Expression: (Math Operator, Number/Variable, Math Operator).
The addition, subtraction, multiplication, and division mathematical operations are used to create mathematical expressions.
Let the two expression be 14 - 3a and 7a - 9
Expression one - 14 - 3a
Expression two - 7a - 9
Combining both two terms
14 - 3a + (7a - 9) = 14 - 3a + 7a - 9
simplifying the above equation, we get
= (-3a + 7a) + 114 - 9)
= 4a + 5
If the two expression be 14 - 3a and 7a - 9 then the combined term exists 4a + 5.
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Hong runs 4 miles in 30 minutes. At the same rate, how many miles would he run in 48 minutes?
Answer: 6.4 miles
Step-by-step explanation:
Take 30 divided by 4 = 1 mile every 7.5 minutes
Then take 48 divided by 7.5 = 6.4 miles in 48 minutes
Find the lengths of the hypotenuses (x) of the triangle whose legs are given
1) 9cm,12cm
Answer:
15 cm
Step-by-step explanation:
a² + b² = c²
(9 cm)² + (12 cm)² = c²
81 cm² + 144 cm² = c²
225 cm² = c²
c = √(225 cm²)
c = 15 cm
Answer: 15 cm
Which is a solution for the equation y= 6x + 6 (both x and y needed as answer)
The solutions for the given equation is (1, 12), (2, 18), (3, 24), (4, 30) and (5, 36).
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
The given equation is y=6x+6.
The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.
Substitute, x=1, 2, 3, 4, 5,.....
When x=1
y=6x+6
y=12
When x=2
y=6x+6
y=6(2)+6
y=18
When x=3
y=6x+6
y=6(3)+6
y=24
When x=4
y=6x+6
y=6(4)+6
y=30
When x=5
y=6x+6
y=6(5)+6
y=36
Therefore, the solutions for the equation is (1, 12), (2, 18), (3, 24), (4, 30) and (5, 36).
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PLEASE HELP!!! I really need help on this question!
a) The probability that an apple from the tree has a weight greater than 90 grams is of: 0.2514 = 25.14%.
b) i) The p-value of the test is of: 0.0045.
b) ii) The conclusion of the test is given as follows: There is enough evidence to conclude that the mean weight of apples from tree A is greater than the mean weight of apples from tree B, as the p-value of the test is less than the significance level.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation of the weight of the apples are given as follows:
[tex]\mu = 85, \sigma = 7.5[/tex]
The probability that an apple from the tree has a weight greater than 90 grams is one subtracted by the p-value of Z when X = 90, hence:
Z = (90 - 85)/7.5
Z = 0.67
Z = 0.67 has a p-value of 0.7486.
1 - 0.7486 = 0.2514 = 25.14%.
Test hypothesisFor each sample, the mean and the standard error are given as follows:
Tree A: [tex]\mu_A = 86.5, s_A = 1.26[/tex]Tree B: [tex]\mu_B = 82.3, s_B = 1[/tex]Hence, for the distribution of differences, the mean and the standard error are given as follows:
[tex]\mu = \mu_A - \mu_B = 86.5 - 82.3 = 4.2[/tex][tex]s = \sqrt{s_A^2 + s_B^2} = \sqrt{1.26^2 + 1^2} = 1.61[/tex]The test statistic is given by the division of the mean by the standard error of the distribution of differences, hence:
z = 4.2/1.61 = 2.61.
Using the z-table, with z = 2.61, the p-value is of:
0.0045.
As the p-value is less than the significance level, there is enough evidence to conclude that the mean weight of apples from tree A is greater than the mean weight of apples from tree B.
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If a woman making $35,000 a year receives a cost-ofliving increase of 2.9%, what will her new salary be?
Answer:
36,015.
Step-by-step explanation:
To calculate the cost-of-living increase, you would first multiply the current salary by the percentage increase: $35,000 * 0.029 = $1,015.
Then, to find the new salary, you would add the cost-of-living increase to the current salary: $35,000 + $1,015 = $36,015.
So, the woman's new salary would be $36,015 per year.
how do you ensure accurate predictions using data correlation? which are the most effective methods?
The only kind of data generated by observational research is correlations or patterns in the data that have been observed. By using correlations, one variable's value can be used to predict the value of another.
Explanation:
Accurate predictions using data correlation can be ensured by using a variety of methods. Firstly, it is important to ensure that the data is free from errors and is of high quality. This can be done by cleaning and validating the data to remove any inconsistencies and outliers. Secondly, it is important to analyze the data thoroughly and identify any patterns or trends. Furthermore, it is beneficial to use appropriate statistical tests and algorithms such as linear regression, logistic regression, and decision trees to identify the predictive relationships between the variables. Finally, it is important to evaluate the model’s performance to determine the accuracy of the predictions.
The most effective methods for ensuring accurate predictions using data correlation are:
1. Perform Exploratory Data Analysis: Exploratory data analysis is an essential step in any predictive modeling process. It involves exploring the data to identify patterns, trends, and relationships within the data. This helps to identify any potential issues or biases within the data that could affect the accuracy of predictions.
2. Use Statistical Tests: Statistical tests can be used to measure the strength of the relationship between two variables. These tests can help to identify which variables are most strongly correlated with each other and can help to determine which variables should be used in a predictive model.
3. Use Machine Learning Algorithms: Machine learning algorithms can be used to create predictive models that can identify and learn patterns in the data. These algorithms are particularly effective at identifying complex relationships between variables that may not be identified by statistical tests.
4. Validate Predictions: Predictions should always be validated to ensure that they are accurate and reliable. This can be done by comparing the predictions against known outcomes or by testing the model on a separate data set.
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How can you use coordinates, ordered pairs, or equations to graph points or lines on a coordinate plane? Give an example and explain how you use coordinates, ordered pairs, or equations to graph them.
A coordinate system is a two-dimensional number line, for example, two perpendicular number lines or axes.
This is a typical coordinate system:
coordinate plane1
The horizontal axis is called the x-axis and the vertical axis is called the y-axis.
The center of the coordinate system is called the origin. The axes intersect when both x and y are zero. The coordinates of the origin are (0, 0).
An ordered pair contains the coordinates of one point in the coordinate system. That is named by its ordered pair of the form of (x, y).
The first number corresponds to the x-coordinate and the second to the y-coordinate.
To graph a point, we have to draw a dot at the coordinates that correspond to the ordered pair. It is one of the best ways to start at the origin.
The x-coordinate shows how many steps have to take from positive to negative on the x-axis, the same as the y-coordinate tells how to have many steps from positive to negative on the y-axis.
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Draw a circle of radiu 4. 6cm. Draw it' diameter and name it XY. Draw a chord XP and YQ from the end point of it' diameter
A circle of radius 4.6 cm is drawn with its center at the origin. The diameter XY of the circle is also drawn, along with two chords XP and YQ connecting the endpoints of the diameter.
A circle of radius 4.6 cm is drawn with its center at the origin, which is labeled as O. The diameter XY of the circle is also drawn and labeled, with the endpoints X and Y. Two chords XP and YQ are then drawn connecting the endpoints of the diameter. The chord XP starts at X and ends at P, while the chord YQ starts at Y and ends at Q. This diagram demonstrates the idea of a circle and its diameter, as well as how two chords can be drawn from the same two endpoints of a diameter. The circle and its diameter can also be used to calculate the circumference of the circle and the length of the diameter.
Circumference of circle = 2 * π * 4.6 = 28.96 cm
Length of diameter = 2 * 4.6 = 9.2 cm
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