B) Calculate the maximum force of static friction that could exist in this system.

The formula for horizontal distance is x = Vx * t, where t is the time. The formula for vertical distance from the ground is y = h + Vy * t - g * t2 / 2, where g is the acceleration of gravity.

What is the free fall equation?

Where g is the acceleration of gravity, vf is equal to g * t. On Earth, the value of g is 9.8 m/s/s. The velocity of the object after being dropped from rest for any given period of time can be calculated using the aforementioned equation.

How is height determined?

At the spot where the ruler, book, or other flat object meets your head, lightly mark the wall with a pencil. Measure the distance from the floor to the mark on the wall using a tape measure, preferably one made of metal that will stay straight.

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If the collision is perfectly inelastic, the speed of the car and the gorilla travel after the collision is 14.9m/s.

Perfectly inelastic collision, also known as completely inelastic collision is one in which the maximum amount of kinetic energy has been lost during a collision, making it the most extreme case of an inelastic collision.

From the question given

mass of gorilla man, m = 500lb - 500 * 0.4536 = 226.8kg

Initial speed of the car, u = 50mph = 50 * 0.447 = 22.35 m/s

mass of the car, M = 454.5kg

applying conservation of momentum formula :
(m + M) * V = M * u

(226.8 + 454.5) * V = 454.5 * 22.35

681.3V = 10,158.075

V = 14.9m/s

Therefore, the speed of the car and the gorilla travel after the collision is 14.9 m/s.

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The final speed of the bus after reaching the top is equal to 16 m/s. Therefore, option (2) is correct.

Equations of motion can be utilized to define the concept of the motion of a body such as the velocity, time, position, and acceleration of a body several times.

The three equations of motion  can be shown as follows:

[tex]v = u + at\\S = ut +(1/2) at^2\\v^2-u^2= 2aS[/tex]

Given, the initial speed of the bus, u = 0m/s

The  distance covered by the bus, S = 85 m

The acceleration in the bus, a = 1.5 m/s²

We can determine the final velocity of the bus from the third equation of motion:

v² - u² = 2aS

v² -0 = 2 ×1.5 × 85

v² =  255

v = 15.97 ≈ 16 m/s

Therefore, the final speed of the bus is 16 m/s.

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In a free-fall experiment, the average time of fall of the ball is 0.550 seconds. Its height is 1.48 meters.

The equation of motion is given by
s = ut + 1/2 . at²

Where:

s = distance

a = acceleration

u = initial velocity

t = time

In the free fall motion, the initial velocity is zero and the acceleration is equal to g or acceleration due to gravity. The distance is equal to height. Hence,

h = 1/2 . gt²

In the given problem:

t = 0.550 s

Hence, the height of the object is:

h = 1/2 x 9,8 x 0.55²

 = 1.48 meters

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The quantity of heat released is -11.30 kJ

First, we have to calculate the number of moles of water.

Molar mass of water = 18 g/mole

Moles of water = 0.278 mole

ΔH= -q/n

heat of vaporization = 40.66 kJ/mol

we have to find the heat absorbed/released

n = number of moles of water

40.66 = q/ 0.278

q = -11.30 KJ

Heat is taken during the vaporization process, but it is released during the condensation step.

What is heat of vaporization?

The heat of vaporisation (Hvap), also known as enthalpy of vaporisation, is determined by the quantity of enthalpy (heat energy) necessary to change a liquid substance into a gas or vapour. Joules per mole (J/mol) or, in some cases, calories are used to measure it (C). Because enthalpy must constantly be added to a system in order to evaporate a liquid, the heat of vaporisation always has a positive value. The likelihood that the molecules will separate from the liquid and turn into a gas increases as their kinetic energy increases.

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Yes it is true  ,A broad group of actions with the intention of assisting others includes helping, sharing, providing comfort, contributing or volunteering, and cooperating.

Research on prosocial conduct has looked at the potential causes and effects of these behaviors as well as the various reasons that might be at play. Prosocial Behavior's Type 3. The factors. Actions that "benefit other people or society as a whole," such as assisting, sharing, contributing, cooperating, and volunteering, are considered prosocial conduct, also known as "voluntary behavior intended to benefit another." Evidence demonstrates that prosociality is essential to social groupings' wellbeing on a variety of measures. Empathy has significant evolutionary roots and is a powerful motivator of prosocial action. Children benefit from the development of desirable qualities fostered by prosocial activity.

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5 times the light beam shown in the figure reflect from the top mirror.

The assumption we must make in this situation is that the angles of incidence and reflection will be equal. We can observe from the illustration that the angle of incidence is [tex]$15^{\circ}$[/tex].

Provided that there are 68 cm in the vertical direction. This allows us to calculate the horizontal distance traveled by light before it reflects off the bottom mirror at a half-length.

[tex]x & =68 \mathrm{~cm} \times \tan 15^{\circ}[/tex]

=18.36 cm

The number of x lengths that may fit within a 168 cm length is,

[tex]k & =\frac{168 \mathrm{~cm}}{18.36 \mathrm{~cm}}[/tex]

=9.15

[tex]& \approx 9[/tex]

There will be reflections from the top mirror nine times out of ten, and the bottom mirror nine times out of ten.

Hence, number of reflections the top mirror is 5

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Note:- The question could be as bellow,

How many times does the light beam shown in the figure reflect from the top mirror? (figure 1)

Answer:

Explanation:  for circular motion centripetal force is involves

as we know, F= mass× acceleration

F= mv²/ r

r = radius

v = 2πr/ t

here t = time and v = velocity/ speed

as we know v= d/ t= 2πr/t

therefore F = m×(2πr/t)²/r

Option B; In a mechanical wave, the restoring force is the force that actually causes the oscillation opposite the direction of the displacement from equilibrium.

Oscillation is the repeating or periodic oscillation of a quantity, often in time, around a central value (often an equilibrium point) or between two or more states. A swinging pendulum and alternating current are two common examples of oscillation. Physics can employ oscillations to simulate intricate interactions, as those between atoms.

The beating of the human heart (for circulation), business cycles in economics, predator-prey population cycles in ecology, geothermal geysers in geology, the vibration of the strings in guitars and other string instruments, the periodic firing of nerve cells in the brain, and the periodic swelling of Cepheid variable stars in astronomy are just a few examples of the dynamic systems that exhibit oscillations in nearly every branch of science.

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The focal length be placed to obtain an image on the screen f>10cm. When an object is placed between F and a concave mirror, the image will appear behind the mirror, enlarged, and upright.

The focal length of your lens is the distance (in millimeters) between its point of convergence and the sensor or film used to capture the image. How much of the scene your camera can record depends on the focal length of your film or digital camera lens. The focal length of a narrow lens in air is the separation between the lens's primary plane and its center. The focal length of a converging lens is positive and determines how far a collimated light beam must travel to focus on a single point.

If a screen image is to be created, v=u=40

Additionally, v 1 u 1 = f 1

Using the equations above, one can write f 1 = 40+u 1 u 1.

​So, u 2 + 40 u + 40 f = 0.

As a result, the determinant of the equation 0, there is no such u.

Consequently, 40 2 4(1)(40f)0

hence, f>10cm

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The collision shown in the figure is A) completely inelastic.

Velocity is a physical quantity that expresses the rate and direction of a moving object. It is the speed of an object in a particular direction. It is a vector quantity that is measured in meters per second (m/s). Velocity can also be described as the rate of change of an object's position with respect to time. It is an important concept in physics and is used to calculate the motion of objects.

This is because the kinetic energy of the system is not conserved, as the velocities of the blocks after the collision are lower than before. The masses of the blocks are not relevant, as the collision is completely inelastic regardless of their mass. Therefore, the collision is characterized by a decrease in kinetic energy and is not possible if momentum is to be conserved.

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When a mass of sunken lead is resting against the bottom in a glass of water, and put it in a small boat of negligible mass, then float the boat in the water; what will happen is: The floating lead displaces a volume of water whose weight equals the lead's weight, and the sunken lead displaces a volume of water equal the lead's own volume. So, the correct answers are option A and D.

This is happened because according to Archimede's Principle which states that a body immersed in a fluid experiences an upthrust equal to the weight of the fluid displaced, and this is fundamental to the equilibrium of a body floating in still water.

Mass is the amount of matter which an object contains. The more matter something has, the more it will weigh. For example, a horse has more matter in it than a cat thus, its mass is heavier. The size of something does not determine how much matter an object has.

Mass (symbolized m) is a dimensionless quantity representing the amount of matter in a particle or object. The standard unit of mass in the International System (SI) is the kilogram (kg).

In physics, mass is a quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance which a body of matter offers to a change in its speed or position upon the application of a force.

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If the star's apparent magnitude is found to be 14.8, how far away is 1000 parsecs.

calculation:-

subtract absolute from apparent to get DM:

14.8 - 4.8 = 10

divide DM by 5:

10/5 = 2

raise 10 to that power:

10^2 = 100

multiple products by 10 parsecs:

10 x 100 parsecs = 1000 parsecs

The apparent magnitude of a celestial object such as B. A star or galaxy is the brightness measured by an observer at a given distance from the object. The shorter the distance between the observer and the object, the greater the apparent brightness.Two stars of the same visual magnitude A and B. The apparent magnitude depends on the position of the observer. Different observers give different measurements.

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The acceleration is -1.5m/s.

What is acceleration?

The speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples.

What is speed ?

Speed is defined as the ratio of distance to the amount of time it took to cover that distance.

speed= distance/ time

s= 4.6m/s

d=60m

4.6= 60/t

4.6t= 60

t= 13.04 seconds

acceleration= (the change in velocity/speed)/(time) this is the same as a=Δv/t

a= unkown

Δv= (final speed - initial speed) =  3.1m/s - 4.6m/s=  -1.5m/s

Therefore, the acceleration is -1.5m/s.

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the ratio of the masses of the two ropes is 0.51

Calculation :

For a rope, the speed of standing wave is given as

[tex]v = \sqrt{\frac{T}{m/L} }[/tex]

Here, as T  and L is same for both the ropes

v1 = 1.4v2

as v1 /v2 = sqrt(m2/m1)

1.4 = sqrt(m2/m1)

m1/m2  = 0.51

the ratio of the masses of the two ropes is 0.51

Mass is an inherent property of an object. Mass is a standard mechanical quantity. Until the discovery of atomic physics and particle physics, it was traditionally thought to be related to the amount of matter in the physical body. are found to have different masses for the same amount of matter. Mass has several definitions in modern physics that are conceptually different but physically equivalent

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If the five identical bulbs shown in the figure are glowing and the battery provided is ideal then the order of brightness of the bulbs from brightest to dimmest is P > S = T > Q = R.

The energy is dissipated when the current flows through a resistor. The rate of the dissipated energy is the power. It is given as=

= P = ΔV(R) / R

The bulbs are identical, so the resistance will be the same. Calculating the voltage for each bulb. The combination ST is in parallel with the other branch. So, the voltage across the right branch and the middle branch is the same ∈.

For the right branch, the voltage is divided by the two resistors i.e S and T, so the voltage is =

= ΔV(S) = ΔV(T) = ∈/2

Since voltage is same, they will have same brightness.

For the middle branch, the total voltage is ∈, but the combination QR has resistance less than bulb P. So, the bulb P has larger voltage than combination QR. Hence, the voltage of P = 2∈/3 while the combination QR has the voltage of ∈/3.

Thus,

ΔV(P) > ΔV(S) = ΔV(T) > ΔV(Q) = ΔV(R)

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A leaf floating up and down in a pond is an example of a longitudinal wave that is False.

Particle motion is perpendicular to energy motion. Shear waves exhibit wave polarization that longitudinal waves do not. There is a distinct peak-to-valley movement. The node remains stationary. Here you can touch standing waves with a rope without disturbing the waves.

The position on the standing wave of maximum amplitude is known as the antinode. Antinodes occur halfway between nodes. Standing waves are undesirable. Some of the energy is reflected off the ends of the line and actually travels up the line.

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The acceleration caused by gravity is 1.2 x 1012 m/s2, while the speed of the star is 6.3 x 104 m/s.

(a) Assuming the star's radius (R) is 19 km, = 19 x 10^3 meters

Rotation Duration (T) = 1 s

The star's mass (m) is 1.98 x 10^30 kg.

The star's velocity is determined by (v) = 2πr/T, where

v = 2x3.14x19x 10^3/1 = 11.93 x10^4 m/s.

Consequently, the star's speed is 11.93 x 10^4 m/s

(b) We are aware that the gravitational acceleration can be calculated as follows:

g = Gm/r^2, where G is the gravitational constant and equals

6.67 * 10^11 x1.98 x 10^30/ (19 x 10^3)^2

g = 3.65x10^33 m/s2.

Gravitational acceleration is therefore equal to 3.65x10^33 m/s2.

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When a terminal side of an angle in a standard position lies along one of the axes, it is called a quadrantal angle.

If an angle's vertex is at the origin and one of its rays is on the positive x-axis, it is said to be in the standard position.

The starting side refers to the ray on the x-axis, while the terminal side refers to the other ray.

The side that isn't the starting side is known as the terminal side of an angle when it is represented in an angle standard position.

Starting at (1, 0), measure the angle on the unit circle in degrees or radians to get the terminal point (move counter clockwise if the angle is positive and clockwise if the angle is negative.)

The terminal point is the coordinate of the terminus.

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The magnitude of its momentum just before it hits the ground is 0.88kg m/s

Momentum is the product of the mass of the body and its velocity. A vector quantity that has magnitude and direction. If m is the mass of an object and v is its velocity (which is also a vector quantity), then the object's momentum p is:  

p=mv

In the International System of Units (SI), the unit of measure for momentum is the kilogram meter per second (kg m/s), which is equivalent to the Newton second.(F=ma)

Final velocity:

v^2= u^2+2as

v^2=0+ 2(g) h

v= √(2gh) =√(2×9.8×2.0)

v=6.26 m/s

Momentum:

p=mv =0.14×6.26

p= 0.876= 0.88 kg m/s

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The speed of the rock as a function of time is that is v(0) as the speed of the rock as a function of time.

{Newton's Second Law}}According to Newton's Second Law, the net force acting on a body is - mg-kv −mg+kv=−ma⇒mDV =mg−kv

Integrate (1) to get -k1 ∫mg-kv−kdv =m 1 ∫ger

-k 1 [ln(mg−kv)]=meters

t+c.

ln(mg−kv)= meters−kt−kC.

mg−kv=exp(−c/k)exp(−kt/m)

kv=mg−C exp(−kt/m)

v=k mg-C1exp(−kt/m)

Use the initial conditions to get \dfrac{3mg}{k}=\dfrac{mg-C}=-2mg}k3mgmg-C⇒C. = -2mg

The final form of (6) is

v=\dfrac{mg+2mg\exp(-kt/m)}{k}

v=kmg+2mgexp(−kt/m).

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A refracting telescope is a telescope that uses lenses and refraction to redirect light in order to magnify distant objects.

A reflecting telescope uses reflection off of mirrors in order to magnify. A refracting telescope uses lenses. A reflecting telescope uses broadly speaking mirrors, in particular for the primary few optical elements. Astronomical telescopes are generally reflecting because it’s a whole lot less difficult to scale mirrors to big sizes.

consider it in terms of how your eye works. while your student is bigger in darker situations, it collects greater mild allowing you to peer fainter things. That aperture for maximum humans is set 7mm at the biggest.

A telescope, via the truth that it has a good larger aperture than your eye, collects even extra mild than your eye can. So even a 50mm telescope is amassing a long way greater mild than your eye on my own at just 7mm diameter. and then eyepiece focuses that light for your eye to study.

So with greater aperture, fainter gadgets - which includes stars, galaxies and nebulae - can be visible.

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A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. The ratio of their kinetic energies (truck to car) is 0.485

The formulas for the momentum and the kinetic energy are:

p = m . v

Ek = 1/2 . mv²

Where:

p = momentum

m = mass

Ek = kinetic energy

v = speed or velocity

Ek = 1/2 . mv² = 1/2 . mv . v

                      = 1/2 . p . v

Since p or momentum of both vehicles are the same, hence, the ratio of their kinetic energies is

Ek_truck : Ek_car = v_truck : v_car

In the given problem:

m_truck = 2268 kg

m_car = 1100 kg

Both have the same momentum, hence,

m_truck x v_truck = m_car x v_car

v_truck / v_car = m_car / m_truck

                         = 1100 / 2268 = 0.485

Therefore,

Ek_truck / Ek_car = v_truck / v_car = 0.485

Your question is incomplete, but most probably your question was:

A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. If the same horizontal net force were exerted on both vehicles, pushing them from rest over the same distance, what is the ratio of their final kinetic energies? (ratio: truck to car)

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Answer:

30000kg.m/s

Explanation:

two cars mass 1000

first moving with 45m/s

second moving with 15m/s

find the total magnitude of momentum = ?

momentum formula=mv

so,

mass is common

mass(v1 -v2)

putting the value

1000(45-15)

30000kg.m/s

The shape of an object can affect how it interacts with light in several ways.

First, the shape of an object can determine how light is reflected off of its surface. A smooth, curved surface will reflect light in a more diffuse manner, producing a soft, even reflection. A rough, uneven surface will scatter light in many different directions, producing a more irregular reflection.

Second, the shape of an object can also affect how light is absorbed by the object. An object with a highly absorbent surface will absorb more light than an object with a less absorbent surface. This is why black objects tend to absorb more light and heat than white objects, which tend to reflect more light.

Finally, the shape of an object can affect how light passes through it. An object with a transparent or translucent surface will allow light to pass through it, while an object with an opaque surface will block the passage of light. The shape of the object can also affect how light is refracted, or bent, as it passes through the object. An object with a curved surface, such as a lens, will refract light in a specific manner, while a flat surface will not.

True, if the charge remains stationary, the compass will not deflect, but if the charge moves, the compass will deflect.

Charge is the bodily assets of count number that reasons charged be counted to experience a force whilst located in an electromagnetic area. Electric powered rate can be fantastic or bad. Like expenses repel every different and not like expenses entice each other.

Charge is the physical belongings of remember that reasons it to revel in a pressure whilst positioned in an electromagnetic area. High-quality and negative electric powered prices are the two varieties of costs generally carried through rate carriers, protons and electrons. Electricity is created by way of the motion of costs.

Charges are of  sorts: tremendous and terrible, typically carried by fee vendors protons and electrons. Examples of the sorts of costs are subatomic debris or the debris of depend: Protons are undoubtedly charged. Electrons are negatively charged.

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The mechanical advantage of Owen’s pulley system is determined as  2.

Mechanical advantage is also known as force ratio, it determines the ratio of output force to input force.

It can also be expressed as the ratio of load to to effort applied in overcoming the load.

M.A = load / effort

The given parameters include;

M.A = 160 N / 80 N

M.A = 2

Thus, the mechanical advantage of a machine is the ratio of output force to input force.

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The momentum during the collision is conserved. Hence, the total initial momentum is equal to the total final momentum. Therefore, the initial velocity of the car with a mass of 3250 Kg was, 2.05 m/s.

Momentum of a body is the product of its mass and velocity. Momentum is a vector quantity having both magnitude and direction.

The momentum during a collision is conserved. Thus,the sum of initial momentum of the colliding  bodies is equal to the final momentum of the combined mass.

Given that, mass of car 1 = 2150 Kg

velocity = 10 m/s

Momentum = mass × velocity.

= 10 m/s × 2150 Kg = 21500 kg m/s.

Mass of car 2 = 3250 kg

the combined mass = 3250  + 2150 = 5400 Kg

final velocity = 5.22 m/s

final velocity = 5400 Kg × 5.22 = 28188 kg m/s .

momentum of car 1 + momentum of car 2 = 281888 kg m/s

21500 kg m/s + (3400 Kg × V) = 281888 kg m/s

v = 2.05 m/s.

Therefore, the initial velocity of the car with a mass of 3250 Kg is 2.05 kg m/s.

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Your question is incomplete. But your complete question probably was:

A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What was the initial speed of car with 3250 kg mass.

The nut slips away horizontally at a speed of 2.0 m/s. if the nut lands at a horizontal distance of 8.6 m. The squirrel is on a limb of a tree with the height of 90.6 m above the ground.

The nut experienced a projectile motion. The equation of motion can be divided into vertical and horizontal components below:

- Horizontal motion: the velocity is constant.

s = v x t

Where:

s = distance

v = velocity = speed = 2 m/s

t = time

Hence,

8.6 = 2 t

t = 8.6/2 = 4.3 s

- Vertical motion: it is a free fall motion

h = 1/2 . gt²

Where:

h = height

g = acceleration due to gravity = 9.8 m/s²

Hence,

h = 1/2 x 9.8 x 4.3²

  = 90.6 m

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Answer:

  12.5 A

Explanation:

You want the current intensity in an iron wire 3.14 m long with a radius of 0.5 mm connected to a 5V battery, given the resistivity of iron is 10^-7 Ω·m.

The resistance of the wire is proportional to wire length, and inversely proportional to area:

  R = ρl/A

  R = (10^-7 Ω·m)(3.14 m)/(3.14·(0.5·10^-3 m)²) = (1/.25)·10^-1 Ω = 0.4 Ω

The current is given by Ohm's law:

  I = V/R

  I = (5 v)/(0.4 Ω) = 12.5 A

The current intensity is 12.5 amperes.

__

Additional comment

The resistivity of iron is 1.0·10⁻⁷ Ω·m, so we presume the 10-72.m in the problem statement is an error in picture-to-text translation.