Vector A has a magnitude of 623. What are its west and north components?


A
The problem cannot be solved because vectors at 90 degree angles to the reference system do not have components.

B
0 south, 0 east

C
623 west, 0 north

D
623 north, 0 west

Work done to lift the rock is 6174 Joule.

To find the answer, we need to know about the work done.

Mathematically, work done = force × distance

The gravitational force on the stone = mg

= 210× 9.8= 2058N

Work done= 2058× 3

= 6174 Joule

Thus, we can conclude that the work done to lift the stone is 6174 Joule.

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Answer:

Since velocity is a vector quantity there is no net displacement and the average velocity is zero

(A) is correct

The acceleration of the steel crate, given the data from the question is 6.0 m/s²

Fₙ = Fᵣ - Fբ

Fₙ = 1869 - 480

Fₙ = 1389 N

Fₙ = ma

Divide both sides by m

a = Fₙ / m

a = 1389 / 230

a = 6.0 m/s²

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Answer:

OB. Radio Waves

Explanation:

Radio Waves are wireless transmission of sound messages or info

Answer:

D. 20 N

Explanation:

Force = mass(m) × acceleration due to gravity (g)

Force = 2kg × 10m/s²

Force = 20N

Interference and diffraction are the phenomena that support only the wave theory of light. Options 2 and 3 are correct.

The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.

The phenomenon of interference occurs when two wave pulses are traveling along a string toward each other.

The light wave hypothesis states that light behaves like a wave. Since light is an electromagnetic wave, it may be transmitted without a physical medium.

Light has magnetic and electric fields, much like electromagnetic waves do.

Transverse waves, such as those seen in light waves, oscillate in the same direction as the wave's path. A wave of light may experience interference as well as diffraction as a result of these properties.

All of the remaining options are the light phenomenon.

Hence, options 2 and 3 are correct.

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Answer:

A

Explanation:

At point 'A' the ball is highest to the ground.As the formula of  gravitational potential energy is Eg=MGH, in which 'M' is mass,'H' is height and 'G' is the gravitational pull of earth

A solid cylinder of mass (M=1 kg) and radius R=0.5 m is pivoted at its center The axis of rotation of the cylinder is horizontal. Three small particles of mass (m=0.1 kg) are mounted along its surface as shown in the figure. The system is initially at rest.

Solid cylinders need to be cut or split into small thin rings.

Each ring consists of a thickness dr of length L.

The moments of these thin cylindrical shells should be summed to infinitesimal.

Follow the instructions given.

1st place Use the general moment of inertia equation.

dI = r2 dm

Next, proceed to the dm determination. It is usually given as follows: To get

dm = ρdV

dm, you first need to calculate DV. It is given as follows:

dV = dA L

where dA is the area of ​​the large ring (radius: r + dr) minus the small ring (radius: r). as a result;

Please check the attached file for ta detailed answer.

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Answer: For a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.

Explanation: To find the correct explanation to the question, we have to find more about the pull box housing shielded conductors.

Thus, we can conclude that, for a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.

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The work she on the box will be 40 J. Here the displacement due to the force is height.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Given data;

Force,F = 80 N

height, h = 0.5 m

Work,W = ? J

Here the displacement is height;

W  = F × d

W = F × h

W = 80 N ×  0.5 m

W = 40 Nm

W=40 J

Hence work she on the box will be 40 J.

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The magnitude of the force exerted by the rope on the bucket is 8N.

To find the answer, we need to know about the force.

Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.

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The magnitude of the force exerted by the second wire is 16.5 N.

Apply cosine rule to determine the force on the second wire;

W² = F₁² + F₂² - 2F₁F₂ cos(θ)

where;

(4.3 x 9.8)² = 31²  +  F₂²  - 2(31) F₂(cos 122)

1775.78 = 961  +  F₂²  + 32.85F₂

814.78 = F₂²  + 32.85F₂

F₂²  + 32.85F₂ - 814.78 = 0

Solve the quadratic equation using formula method;

F₂ = 16.5 N

Thus, the magnitude of the force exerted by the second wire is 16.5 N.

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Answer:

1.44 m

Explanation:

Potential energy = mgh

  832                 = 59 * 9.81* h

h = 832/(59*9.81) = 1.44 m

The diver has a mass of 59 kg and a gravitational potential energy of 832 J standing on the diving board. 1.44 meters high, the diver is above the water's surface.

Utilizing mechanical energy conservation, we can estimate the diver's height above the water's surface. The diver has gravitational potential energy at the top of the diving board, which is transformed into kinetic energy when they jump and descend towards the ocean. Each and every ounce of potential energy is changed into kinetic energy at the water's surface.

Given:

Mass of the object (diver) = 59 kg

Acceleration due to gravity = 9.81 m/s²

The height can be computed as:

h = GPE / (m × g)

h = 832 J / (59 kg × 9.81 m/s²)

h = 1.44 meters

Hence, the diver has a mass of 59 kg and a gravitational potential energy of 832 J standing on the diving board. 1.44 meters high, the diver is above the water's surface.

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Using algebra to solve for the the cost of the glass lenses gives the value for cost of glass lenses to be 4.

The cost of the glass lenses is calculated as follows:

Let cost of glass be y

Cost of plastic lenses = 4y

Cost of eye exam and  frames be z.

z + y = 30  (i)

z + 4y = 42 (ii)

(ii) - (i)

3y = 12

y = 4

Inconclusion, the cost of the glass lenses is 4.

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Answer:

Pressure is the force acting normally per unit area.

Force.

Area.

This also proved by formula:

P=F/A.

Also pressure due to liquid depends on density ,gravity and height

An effective display of trend and magnitude is achieved by using a combination of a C)heat map and sparklines.

While the standard chart is designed to expose as a great deal fact as possible and is set off from the float of text, sparklines are meant to be succinct, memorable, and located in which they are mentioned.

A heatmap (or warmness map) is a graphical illustration of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.

A warmth map visualization is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a portfolio.

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A movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

A closed kinetic chain movement is defined as that position where the most distal aspects of a particular extremity are fixed to the earth or another solid object.

In conclusion; a movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

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Answer:

3.038 m/s^2

Explanation:

What we have

m = 6.0 kg

[tex]\mu_{k}[/tex] = 0.20

[tex]\mu_{s}[/tex] = 0.40

[tex]F_{applied}[/tex] = 30 N

Since the situation is that the box has already been pushed, lets get the total net force of both components.

∑Fy = [tex]ma_{y}[/tex] = 0 (bc the normal and weight cancel out each other)

∑Fx = [tex]F_{applied}[/tex] - [tex]f_{k}[/tex] = [tex]ma_{x}[/tex] (We are going to use this equation to find acceleration)

To find the friction force

[tex]f_{k}[/tex] = [tex]\mu_{k}[/tex] * N

[tex]f_{k}[/tex] = .20 * 6.0 kg * 9.81 m/s^2 = 11.772 N

Now we can use ∑Fx equation to actually find the acceleration of the box!

∑Fx = [tex]F_{applied}[/tex] - [tex]f_{k}[/tex] = [tex]ma_{x}[/tex]

Plug it in

30 N - 11.772 N = 6 kg * a

Do the algebra...

a = [tex]\frac{30 N - 11.772 N}{6 kg}[/tex] = 3.038 m/s^2

(a) The initial horizontal velocity of the driver is 10 m/s.

(b) The time taken for him to reach the water is 1.75 s.

(c) The horizontal displacement is 17.5 m.

The initial horizontal velocity of the driver is given as 10 m/s.

h = vy(t) + ¹/₂gt²

where;

h = 0 +  ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 15 / 9.8)

t = 1.75 s

X = Vx(t)

X = 10 x 1.75

X = 17.5 m

Thus, the initial horizontal velocity of the driver is 10 m/s, the time of motion is 1.75 s and the horizontal displacement is 17.5 m.

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Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: [tex]y=2\pi\sqrt{\frac{L}{g}}[/tex] where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

[tex]1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\[/tex]

Evaluate the multiplication in front

[tex]1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}[/tex]

Divide both sides by 6.28

[tex]0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}[/tex]

Square both sides

[tex]0.100 s^2= \frac{L}{9.8 m\backslash s^2}[/tex]

Multiply both sides by m/s^2  (the s^2 will cancel out)

[tex]0.984 m = L[/tex]

Now now let's find the length when it's two seconds

[tex]2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}[/tex]

Divide both sides by 6.28

[tex]0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}[/tex]

Square both sides

[tex]0.101 s^2 = \frac{L}{9.8 m\backslash s^2}[/tex]

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

[tex]0.994 m = L[/tex]

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

the answer should be 0.00988 m

Answer:

The mass of the second student is 60 kg.

Explanation:

Note: It is assumed that radius of piston is 0.23 m and density ρ is 850 kg/m^3 and mass of first student is 55 kg.

There occurs a change in pressure on a piston when some mass is added on the other piston.

This change of mass on the piston is given by the formula,

Δm=ρhA/g

where A is the area of piston.

Given h=35 cm or 0.35 m, change in mass is,

Δm=850*(0.35)*π*(0.23)^2 / 9.8

Δm=5.0 kg

Therefore, the mass of the second student is 55+5=60 Kg

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Answer:

The acceleration of the rifle equals the force that the bullet exerts on the rifle divided by the mass of the rifle. The two forces are equal, but since the mass of the rifle is much greater than the mass of the bullet, the acceleration of the rifle is much less than the bullet's acceleration.

Answer:

The magnetic field through the coil must change.

Explanation:

The approximate magnitude of the force of air resistance is 882 N

The magnitude of the force of air resistance can be obtained as illustrated below:

F = mg

F = 90 × 9.8

F = 882 N

Thus, approximate magnitude of the force of air resistance is 882 N

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Intensity of light emitting from the bulb is 3.5 watt/m².

To find the answer, we need to know about the intensity of the light.

Intensity of light= power/area

Thus, we can conclude that the intensity of light bulb at 1.51 m is 3.5 watt/m².

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Answer:

0.10 m/s

Explanation:

The graph appears to be linear, so the velocity is constant and is represented by the slope of the graph. The slope can be calculating by taking any two points and inputting them into the equation: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] which is essentially rise/run. In this case the slope is really easy to calculate taking the two points of (0, 0) and (10, 1). In this case you can easily see the rise is 1 and the run is 10. So the slope is 1/10. So the average velocity of the object was 0.10 m/s or 1/10 m/s

It means mass can be converted into energy.

I. E. In a nuclear fission, we start of with a greater mass of our rectant, which then decrease due to mass being converted into the (thermal) energy released, in our reaction. Later, being used to produce electricity, for example.

Hope this helps!

The size of the disc will Increase

The hole will enlarge in proportion to the metal if the disc is homogeneous and isotropic (the same in all directions). This is evident because, since the hole's edge is constructed of metal, the thermal expansion equation dL=LdT holds true for all lengths related to the metal, including the circle of the hole. Additionally, if the diameter of the hole increases, so does its circumference.

The analysis becomes more challenging if your disc has distinct areas formed of various metal kinds or if the metal that makes up your disc has an anisotropic crystal structure, meaning that it expands by different amounts in different directions. But given the total change in size is still an expansion, I believe the hole would become bigger in all scenarios.

Hence ,The size of the disc will Increase

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Answer:

The families are thought to form as a result of collisions between asteroids. In many or most cases the parent body was shattered, but there are also several families which resulted from a large cratering event which did not disrupt the parent body (e.g. the Vesta, Pallas, Hygiea, and Massalia families).