Chemistry College

Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 193 Ca(g)→Ca (g) e− 590 2O(g)→O2(g) - 498 O(g) e−→O−(g) -141 O−(g) e−→O2−(g) 878 Ca(s) 12O2(g)→CaO(s) -635 Ca2 (g) O2−(g)→CaO(s) - 3414
A.1010 kJ
B.1508 kJ C.-1514 kJ D.-3027 kJ E.1757 kJ

Answers

Answer 1

The second ionization energy of Calcium is A)1010 kJ.So,correct option is A.

We have some data like

the enthalpy of formation of calcium oxide(CaO) as   -635 kJ,the first ionization energy of calcium  IE₁= 590 kJ,the first electron affinity energy of oxygen EA₁ = -141 kJ,the dissociation energy of oxygen DE = 249 kJ,the second electron affinity of oxygen EA₂ = 878 kJ,the lattice energy of calcium oxide(CaO) U = -3414 kJ

For calculating the second ionization of calcium we need to write down the proper Born-Haber cycle equation which is

Δ[tex]H_f[/tex]= SE + IE₁ + IE₂ + DE + EA₁ + EA₂ + LE

=>-635KJ=590KJ+(-141KJ)+IE₂ + 249KJ+878KJ-(-3414KJ)

=>IE₂= - 590KJ + (-141)KJ  - 249KJ  - 878KJ + 3414KJ  -635KJ

=>IE₂= -2352KJ + 3414KJ + 52KJ

=>IE₂=1010KJ

Hence, our required  second ionization energy of Calcium is A)1010 kJ.

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Related Questions


A carbon atom has a relative atomic mass of
13.3. 60% of the carbon atom has a mass
number of 12.7, 30% of the carbon atom has a
mass number of 13.6, whilst the remaining 10%
has a mass number which is not known.
Calculate the mass number of the carbon isotope
which is 10% of the Carbon 13.3 atom.
Give your answer to 1 decimal place.

Answers

According to the claim, the carbon isotope that is 10% of something like the carbon 13.3 molecule has a mass number of 15.1.

Where can you find carbon?

The majority of carbon is kept in reservoirs, or sources, such rocks and sediments; the remaining portion is kept in the atmosphere, the seas, and living things. Through the respiration of both and animals, carbon is returned to the atmosphere. Burning things like wood, oil, and gas also releases it.

Briefing:

Since all carbon isotopes have an equal atomic mass of 13.3,

(0.60 * 13.3) + (0.3 * 12.7) + (0.1 * x) = 13.3

11.79 + 0.1x = 13.3

x = 15.1

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In a double replacement reaction, why will two metals not combine with each other when products are formed

Answers

In a double replacement reaction, two metals will not combine with each other when products are formed because the metals form positive ions that do not attract.

The correct option is C.

What is a double replacement reaction?

A double replacement reaction is a reaction in which there is an exchange of radicals between two compounds when a solution of the compounds is mixed together.

In a double replacement reaction, a precipitate is always formed when the two solutions of the compounds are mixed together.

During a double replacement reaction, the metallic ions exchange their negative radicals to form new compounds.

In accordance with the law of charges, similar charges do not attract each other, hence, the opposite ions of the metals and the negative radicals are attracted to each other.

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Calculate the percent composition of H3PO4

Answers

The percent composition of hydrogen, phosphorous and oxygen in phosphoric acid is 3.06 %,31.60%,65.31 % respectively.

What is percent composition?

Percent composition is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage composition percent weight by volume and percent volume by volume .

Percent composition of hydrogen=3/97.99×100=3.06%.

Percent composition of phosphorous=30.97/97.99×100=31.60%

Percent composition of oxygen=64/97.99×100=65.31%

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How to recover Aluminum from brass through melting

Answers

Answer:

you can do so by pouring it into a vibrating seperator

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