As a person breathes, during the inhale part of the cycle air moves down the windpipe (bronchus) and through a constriction where the air speed doubles. If the air is traveling 46 cm/s before the constriction and we treat air as an incompressible fluid, determine the pressure drop in the constriction. Use the density of air as 1.29 kg/m3. in Pa

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Answer 1

If the air is traveling 46 cm/s before the constriction and we treat air as an incompressible fluid, the pressure drop in the constriction is 106.8 Pa.

If we treat air as an incompressible fluid, the pressure drop in the constriction can be determined using Bernoulli’s equation. Bernoulli’s equation states that the sum of the pressure, kinetic energy, and potential energy of a fluid stream is constant.

The equation can be expressed as:

P1 + (1/2)ρv12 + ρgh1 = P2 + (1/2)ρv22 + ρgh2

Where P1 and P2 are the pressures before and after the constriction, ρ is the density of the fluid, v1 and v2 are the velocities before and after the constriction, g is the acceleration due to gravity, and h1 and h2 are the heights before and after the constriction.

Given that the air velocity before the constriction is 46 cm/s and the density of air is 1.29 kg/m3, we can calculate the pressure drop in the constriction as follows:

P1 + (1/2)*(1.29 kg/m3)*(46 cm/s)2 + (1.29 kg/m3)*(9.8 m/s2)*h1 = P2 + (1/2)*(1.29 kg/m3)*(92 cm/s)2 + (1.29 kg/m3)*(9.8 m/s2)*h2

Since h1 and h2 are equal and the acceleration due to gravity is constant, we can simplify the equation to:

P1 + (1/2)*(1.29 kg/m3)*(46 cm/s)2 = P2 + (1/2)*(1.29 kg/m3)*(92 cm/s)2

Substituting the given numerical values, we get

P1 + (1/2)*(1.29 kg/m3)*(46 cm/s)2 = P2 + (1/2)*(1.29 kg/m3)*(92 cm/s)2

P1 + 35.6 Pa = P2 + 142.4 Pa

Therefore, the pressure drop in the constriction is 106.8 Pa.

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The three different categories of accelerated movements are uniform acceleration, non-uniform acceleration, and average acceleration. When an object moves in a straight path while experiencing equal-interval increases in velocity, this motion is referred to as having uniform acceleration.

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Which of the following statements is not true of tornadoes?
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A 75 kg man falls off his ladder and hangs motionless from the ceiling by a cord. Determine the net force on the man. (don't forget units)

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The net force on the 75 kg man who falls off his ladder and hangs motionless from the ceiling by a cord is zero.

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The weight of a body is the force of gravity acting on the body. The weight of a body acts downward.

Mathematically, the weight of a body is given below as follows:

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The weight or the force of gravity acting downwards on a 75 kg man that falls off his ladder and hangs motionless from the ceiling by a cord is calculated as follows:

The force of gravity = 75 * 10

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The tension on the cord balances the weight of the man and acts in the opposite direction.

Hence, the tension on the cord is equal to 750 N but in the opposite direction.

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Net force = 750 N - 750 N

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The smallest (straight line) length between a body's starting position and its final location—represented by an arrow pointing from starting spot to final position—is referred to as a brain's displacement when it moves through one position to another.

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The drawings show three examples of the force with which someone pushes against a vertical wall. In each case the magnitude of the pushing force is the same. Rank the normal forces that the wall applies to the pusher in ascending order (smallest first).1st drawing is a medium angle2nd drawing is a small angle3rd drawing is a large angle (almost 90 degrees and perpendicular to the wall)

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The normal forces that the wall applies to the pusher in ascending order are :Normal force in the third drawing (large angle),Normal force in the first drawing (medium angle),Normal force in the second drawing (small angle).

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The magnitude of the normal force is determined by the angle at which the person is pushing against the wall. For a given magnitude of the pushing force, the normal force will be smaller when the angle is larger and larger when the angle is smaller.

In the first drawing, the angle is medium, so the normal force will be between the normal force in the second and third drawings.

In the second drawing, the angle is small, so the normal force will be larger than the normal force in the first drawing and smaller than the normal force in the third drawing.

In the third drawing, the angle is large, so the normal force will be the smallest of the three.

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