URGENT!! ILL GIVE BRAINLIEST!!!! AND 100 POINTS!!!

Answer:

How many were in math only?7

How many were not majoring in computer science?9

How many were not math or computer science?2

Step-by-step explanation:

Total students 25

-math major      13

-Science major 10

_______________

                          2 not majoring in math or CS majors

math major 13 -6 dual majors = 7 major in math only

math major 7+ not math or CS 2 = 9 not majoring in CS

The function formula for f and g are f(t) = $45000+$2100t and g(t) = $45000(1+0.042) to the power of t when Krystal is weighing two job offers from various organizations.

Given that,

Krystal is weighing two job offers from various organizations. She received a $45,000 beginning salary from Company A, with annual raises of $2100. Company B gave her a $45,000 beginning salary with an annual rise of 4.2%. Let f(t) stand for Carissa's pay at the company. Let g(t) stand in for Carissa's pay at Company B at Years after Accepting a Position at Company B, and at Years after Accepting a Position at Company A.

We have to find the function formula for f and g.

We know that,

Company A has

f(t) = $45000+$2100t

And

Company B has

g(t) = $45000(1+0.042) to the power of t.

Therefore, The function formula for f and g are f(t) = $45000+$2100t and g(t) = $45000(1+0.042) to the power of t when Krystal is weighing two job offers from various organizations.

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As per question and the information provided we can compute the solution for both exercises as follows:

Investments are defined as assets bought or invested in with the goal of increasing wealth and setting aside funds from salary or capital gains. The main goal of an investment is to generate additional revenue or to make money on the investment over a certain amount of time.

Exercise (a)

The sequence "an "'s" first five terms are:

[tex]a1 = 6000(1.04) = 6240 [/tex]

[tex]a2 = 6000(1.04) ^2 = 6489.6 [/tex]

[tex]a3 = 6000(1.04)^3 = 6749.184 [/tex]

[tex]a4 = 6000(1.04) ^4 = 7019.151 [/tex]

[tex]a5 = 6000(1.04)^5 = 7299.197[/tex]

Exercise (b)

Because infinity, which is not a finite number, serves as the series's limit as n approaches infinity, the sequence is divergent.

[tex]an = 6000(1.04)^n [/tex]

that is the formula for the nth term of the sequence. As n rises, the value of

[tex](1.04)^n[/tex]

it grows steadily larger, which causes a to grow steadily larger until it approaches infinity. The sequence "an" diverges as a result.

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Answer:

average rate of change = 19

Step-by-step explanation:

the average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

here [ a, b ] = [ 3, 7 ] and y = f(x) , then

f(b) = f(7) = 7² + 9(7) = 49 + 63 = 112

f(a) = f(3) = 3² + 9(3) = 9 + 27 = 36

then

average rate of change = [tex]\frac{112-36}{7-3}[/tex] = [tex]\frac{76}{4}[/tex] = 19

Each equation is expressed and mentioned in its factorized form are given above.

Given are the polynomials along with their factorized forms.

The polynomials along with their correct factorized forms are as follows -

Therefore, each equation is expressed and mentioned in its factorized form are given above.

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The number of buttons that she can wear proudly will be 5.

The ratio is the division of the two numbers.

For example, a/b, where a will be the numerator and b will be the denominator.

Proportion is the relation of a variable with another.

As per the given,

Cost of one button = $0.28

The cost of buttons that she can wear = $1.40

A number of buttons = $1.40/$0.28 = 5

Hence "She will be able to wear five buttons with pride.".

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The hypotheses that can be used to test for a significant difference between the population proportions for the two years is H0 :- P1 = P2

How to calculate the hypotheses?

In math, the process of calculating the hypotheses is to select a statistic based on a sample of fixed size, calculate the value of the statistic for the sample and then reject the null hypothesis if and only if the statistic falls in the critical region.

Here we know that certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. Suppose that in February 2012, a sample of 1,000 adults showed 410 indicating that their financial security was more than fair. In February 2010, a sample of 1,100 adults showed 385 indicating that their financial security was more than fair.

And we need to find the hypotheses that can be used to test for a significant difference between the population proportions for the two years.

Here let us consider P1 refers population proportion saying financial security more than fair in 2012 and P2 refers population proportion saying financial security more than fair in 2010.

As per the definition of the hypotheses, the resulting hypotheses is written as,

=> H0 :- P1 = P2

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Given the above information the amount Yusuf would have more in his account than Arianys is $9,929,539.57

You should be aware that compound interest is sum of money that accrues on the capital over a stated period of time.

The given parameters are:

Arianys investment = $61,000, interest rate 7% compounded continuously

Yusufs investment = $61,000, rate 7% compounded monthly

number of years each 14 years

Arianys investment

Compound interest = [tex]P(1+r)^{t}[/tex] - 1

Applying the figures we have

CI= 61000(1+0.07)¹⁴ - 1

=61000(1.07)¹⁴ -1

CI=$96,290.58

For Yusuf investment

CI=[tex]P(1+\frac{r}{n})^{nt} - 1[/tex]

Applying the figures we have

Ci=61000(1+0.0121)²⁹⁶⁸ -1

Compound Interest = 61000(1.0058)¹⁶⁸ - 1

Simplifying this we have

61000(164.36)

CI=$10,025,830.12

Therefore the amount in Yusufs account more than Arianys account is $(10,025,830.12-96,290.58)

Amount = $9,929,539.57

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the difference of elevation between a and b.Let AB = x, tan 36 = x/111.356 ,x = 111.356 tan 36= 64.39 m and Difference in elevation = 64.39m

We are given that two ridges B and C form a valley with a point A at the bottom part with an elevation difference of 111.356m between the ridges and and angle of elevation of 36 degrees at point A. To find the difference of elevation between A and B, we use the formula of tangent which is tan θ = Opposite/Adjacent. We substitute the values and solve for x, which is the elevation difference between A and B. So the difference in elevation between A and B is 64.39m.

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Answer:

[tex]2x + y \leq 8[/tex]

Step-by-step explanation:

since potatoes cost $2 they are represented as 2x

Carrots cost $1 and are simply y

When comparing the proportions of ethnic groups represented in television commercials on Philadelphia stations to census data, we can use a chi-squared test to see if there is a difference.

Suitable hypotheses for this test include the following: H0: P1 = 0.165, P2 = 0.026, P3 = 0.789, and P4 = 0.019 Ha: at least one P1 to P10, where P1, P2, P3, and P4 represent the proportions of the four main ethnic groups—African, Asian, Caucasian, and Hispanic—in the population.

The test statistic cannot be calculated until we get the predicted frequencies for each group under the null hypothesis. Given that N is the total number of observations and E I is the expected frequency for group I, E I = N * P I provides the expected frequency for each group.

the population percentage for group I is P i.

These equations allow us to determine the anticipated frequencies in the following ways:

E 1 = 69 * 0.165 = 11.485

E 2 = 11 * 0.026 = 0.286

E 3 = 330 * 0.789 = 261.67

E 4 = 8 * 0.019 = 0.152

After that, the chi-squared test statistic is calculated as follows: x2 = ∑_(i=1)4 [(O i - E i)2 / E i], where O i is the observed frequency for group I and E i is the anticipated frequency for group i.

The numbers for the observed and anticipated frequencies are substituted to produce the following equation: x2 = (69 - 11.485)2 / 11.485 + (11 - 0.286)2 / 0.286 + (330 - 261.67)2 / 261.67 + (8 - 0.152)2 / 0.152

= 57.015^2

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The school is 5.43 miles from Diana's house. This is evaluated by using the speed-distance-time relationship.

The ratio of distance to time gives speed to an object.

I.e., S = D/T or D = ST ot T = D/S

It is given that,

Diana walks to her school at a speed of 6 mph.

So, the time taken for her to walk is t1 = d/6 hours

Diana returns home by car at a speed of 35 mph.

So, the time taken for her to return by car is t2 = d/35 hours

But it is given that, she takes 3/4 hours less time for returning by car.

Thus, we can write t2 = t1 - 3/4

⇒ d/35 = d/6 - 3/4

⇒ 3/4 = d/6 - d/35 = d(1/6 - 1/35)

⇒ 3/4 = d(29/210)

⇒ d = (3 × 210)/(4 × 29) = 5.431 miles

On rounding the obtained value to the nearest hundredths is 5.43 miles.

Thus, the distance between Diana's home and her school is 5.43 miles.

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Answer:

Hey

you are correct

18x – 40

Step-by-step explanation:

2( x + 4 (2x – 5) )

= 2( x + 8x – 20)

= 2x + 16x – 40

= 18x – 40

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Have a good day

Answer: 18x-40

Step-by-step explanation: First, you have to isolate the 2, so now it would look like this:

=(2)(x+4(2x−5))

Now, You have to isolate the x, along with the 2 again, so it would look like this:

=(2)(x)+(2)(4(2x−5))

Now, you would combine the like terms of 2x & x, and all the numbers that don't have a variable, so it would look like this:

2x+16x−40

Now, finally, we can combine 2x + 16x, because they are like terms, so that is how we get 18x - 40

I hoped this helped friend!

                                        -Shining Dream

The derivative of the following are:

(a) 36x³ + 72x² + 32x

(b) 2x(2-x²³)³ - 69x²²(2-x²³)(1+x²)

(c) -1/2√x(x+3)² + 2(x+3)(2+√x)

(d) 4x(x⁵+3)⁴ + 20x⁴(2x²+1)(x⁵+3)³

What is a derivative?

The derivative of a function of a real variable in mathematics assesses how sensitively the function's value changes in response to changes in its argument. Calculus's core tool is the derivative.

Here, we have

Given

(a) y = x²(3x + 4)²

Derivative with respect to x and we get

dy/dx = 2x(3x + 4)² + x²(18x + 24)

dy/dx = 36x³ + 72x² + 32x

(b) y = (1+x²) (2 - x²³)³

Derivative with respect to x and we get

dy/dx = 2x(2 - x²³)³ + (1+x²)(-23x²²)3(2 - x²³)²

dy/dx = 2x(2-x²³)³ - 69x²²(2-x²³)(1+x²)

(c) y = (2+√x)(x+3)²

Derivative with respect to x and we get

dy/dx = -1/2√x(x+3)² + (2+√x)2(x+3)

dy/dx = -1/2√x(x+3)² + 2(x+3)(2+√x)

(d) y = (2x² + 1)(x⁵ +3)⁴

Derivative with respect to x and we get

dy/dx = 4x(x⁵ +3)⁴ +  (2x² + 1)4(x⁵ +3)³(5x⁴)

dy/dx = 4x(x⁵+3)⁴ + 20x⁴(2x²+1)(x⁵+3)³

Hence, the derivative of the following are:

(a) 36x³ + 72x² + 32x

(b) 2x(2-x²³)³ - 69x²²(2-x²³)(1+x²)

(c) -1/2√x(x+3)² + 2(x+3)(2+√x)

(d) 4x(x⁵+3)⁴ + 20x⁴(2x²+1)(x⁵+3)³

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The appropriate test to perform is one sample t test

The rejection reason is t statistic less than -2.012 or t statistic more than -2.012

The p value of the test is 0.0292

Firstly,

       As the population standard deviation is unknown and the sample size is more than 30, it is appropriate to use one sample t test for this hypothesis testing

Testing if the mean is changed from 700 levels or not

Null and alternate hypothesis are 700

Degree of freedom,

                       n-1

                      = 48-1

                      = 47

Using alpha level 0.05 and t critical table, we found the following two critical values

t critical values= -2.012 and 2.012

So, the rejection reason is t statistic less than -2.012 or t statistic more than -2.012

Now,

        Population means = 700 hours

        Sample mean = 675 hours

        n = 48

So,

Test statistic= (mean-alternate hypothesis)/(s/√n)

                     = (675-700)/ (77/√48)

                     =-25/11.1140

                     = -2.249

Degree of freedom = n-1

                                  = 48-1  

                                  = 47

With t distribution table for -2.249 and 47 degrees of freedom obtain p value of 0.0292

So, pvalue= 0.0292

Reject null hypothesis since the p value is less than alpha level

So, we conclude that the mean has changed from 700 hours

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Answer:

She packed 6 pairs of pants and 10 shirts.

Step-by-step explanation:

Say the number of pants is x. Then, the number of pants is 2x-2. Now you have the equation:

x+ (2x-2)=16

Solving this equation gives x=6.

Therefore, she packed 6 pairs of pants and 10 shirts.

Answer:

6

Step-by-step explanation:

g(4) tells us that we need to look for the y coordinate when g(x) reaches 4 on the x axis.

6 is the answer

In the following first scenario the conditions for the t-test is not met for the difference in populations mean so the hypothesis test cannot be done.

1)The distribution of time spent at university recreational facilities is considerably skewed to the right in a random sample of 100 university students.

The variable is X, which stands for time spent at the university's leisure facilities.

Because the variable "time" is at least ordinal, this criterion is satisfied.

The sample was drawn at random, hence this requirement is met.

The data is heavily skewed to the right, the normal distribution is symmetrical, and this data set is highly unlikely to have a normal distribution.

2)The distribution of time spent at university recreational facilities is highly skewed to the right for females but not strongly skewed for males in a random sample of 50 university students (37 females and 13 males).

In this scenario, you have two groups of interest, and the variable X: Time spent at the university recreational facilities will be measured for each group.

Because the variable "time" is at least ordinal, this criterion is satisfied.

The samples "male students" and "female students" were randomly taken so this condition tests.

You have two populations of interest in this case. Male university students and female university students are divided into two groups. To use the t-test, both populations must be normal.

The distribution for the females has strongly skewed to the males have a somewhat skewed distribution.

If the distribution of females is substantially skewed, it is impossible for it to be normal.

In this case, a t-test is not appropriate.

3)Because the experimental units are dependent, this is a "paired sample" situation. (Consider the sibling pair's relationship; if they get along well, it is more likely that they will spend time together in the recreational facilities; if their relationship is not so good, it is more likely that the presence of one of the siblings in the facilities will cause the other to spend less time there.)

X will be the variable measured for each member of the "sibling pair": Time spent at university recreational facilities, and the research variable in this case, will be defined by the difference in times measured for both siblings.

The normality condition checks.

so the t-test in this scenario can be applied.

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Answer:

5.2%

Step-by-step explanation:

Nikki can use modern portfolio theory to assess the risk and return behaviors associated with different combinations of assets X and Y.

Modern portfolio theory involves calculating the expected return and risk of a portfolio of assets by analyzing the correlations between the assets. It also looks at the diversification benefits of combining different assets and the impact of adding riskier assets to a portfolio. By quantifying the risk and return behaviors of different portfolios, Nikki can make informed decisions about which portfolios are most suitable for her.Modern portfolio theory is used to assess the risk and return behaviors of different combinations of assets X and Y. It considers correlations between the assets, the diversification benefits of combining them, and the impact of adding riskier assets. By quantifying the risk and return behaviors, Nikki can make informed decisions about which portfolios are most suitable for her.

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Answer:

15.1

Step-by-step explanation:

Step-by-step explanation:

27w - 18 - 5w = 4w - 24 - 8

22w - 18 = 4w - 32

18w = -14

w = -14/18

w = -7/9

The discrete data can be number of legs, number of teeth.

The continuous data can be the length of tail, and the height of dog.

Consider the provided information.

The discrete data is a data whose value is obtained by counting and they can be described by an integer value.

So, the discrete data can be number of legs, number of teeth.

A continuous data is a variable whose value is obtained by measuring.

The continuous data can be the length of tail, and the height of dog.

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10) There is no solution to given the simultaneous equations

11) There is no solution to given the simultaneous equations

15) There is no solution to given the simultaneous equations

10) We are given the simultaneous equations as;

y = -6x - 8

y = -6x + 8

Plug -6x + 8 for y in eq 1 to get;

-6x + 8 = -6x - 8

Since the coefficient of the variable on both sides are equal, then there is no solution to the simultaneous equation.

11) We are given the simultaneous equations as;

3x - y = 6

-3x + y = -6

Add eq 1 to eq 2 to get;

0 = 0

Thus, there is no solution to the simultaneous linear equations.

12) We are given the simultaneous equations as;

9x - 15y = 24   ------(1)

6x - 10y = -16    ------(2)

Multiply eq 2 by 1.5 and eq 1 by 1 to get;

9x - 15y = 24   ------(3)

9x - 15y = -24   -----(4)

When we subtract eq 3 from eq 4, we get;

0 = -48

Thus, no solution exists.

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The advertising revenue model that would best suit the organization needs is  Bidding for ad words.

Given that,

A company has made the decision to employ social media advertising to connect with a certain target population in order to accomplish this. To precisely target the demographic that would be interested in seeing these ads, it wants to purchase a set of keywords. The objective is to increase consumer involvement and exposure rates without violating their privacy.

The Organization investing to buy specific keywords for advertising, when someone searches for some words in a social media search engine, the search engine queries it's users looking for the keyword matches in it's ad group thus displaying the most relevant ad aiming for more exposure.

Therefore, bidding for ad words is the advertising income strategy that would best meet the organization's needs.

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According to the question asked the number of digits with all digits even can be found as:

aₙ = 6ⁿ + 2.3ⁿ + 1(n≥0)

Given:

let the number be aₙ.

The number aₙ equals the number of n permutations at the multiset S

where S = { ∞ 2, ∞ 4, ∞ 6, ∞, 8, ∞ 10} on which 2 and 4 occurs

a non zero even number at times.

The exponential generating function have a₀, a₁, a₂,....aₙ

f'(x) = (1+x²/2! + x⁴/4!+...)ⁿ

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Answer: [tex]\displaystyle d=\sqrt{41} \approx 6.4[/tex]

Step-by-step explanation:

     We will use the distance formula to help us solve (see attached). Let (6, -2) be point one and (1, 2) be point two.

[tex]\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}[/tex]

[tex]\displaystyle d=\sqrt{(1-6)^2 +(2--2)^2}[/tex]

[tex]\displaystyle d=\sqrt{(-5)^2 +(4)^2}[/tex]

[tex]\displaystyle d=\sqrt{25 +16}[/tex]

[tex]\displaystyle d=\sqrt{41} \approx 6.4[/tex]

41 is a prime number, so this is the simplest radical form.

Answer:

  2268π ft³ ≈ 7125 ft³

Step-by-step explanation:

You want the volume of a 22 ft long cylinder capped by a hemisphere 9 ft in radius.

The formula for the volume of a cylinder of radius r and height h is ...

  V = πr²h

The formula for the volume of a hemisphere of radius r is ...

  V = 2/3πr³

The sum of the volumes of the two figures is ...

  Vtotal = πr²h +2/3πr³ = πr²(h +2/3r)

Using the given values for height and radius, we find the volume to be ...

  Vtotal = π(9 ft)²(22 ft + 2/3(9 ft)) = π(9 ft)²(28 ft)

  Vtotal = 2268π ft³ ≈ 7125 ft³

The volume of the composite is about 7125 cubic feet.