Un volcan lanza una roca con una rapidez de 47.5 m/s con un angulo de 39.4° sobre el eje x. La roca toca el suelo a 1750 m por debajo de la altura inicial si se desprecia la resistencia del aire y considerando un valor constante de aceleracion debido a la gravedad de 9.81 m/s¨2 cual es el tiempo en completar la trayectoria

Answers

Answer 1
Responder: 6.1467 segundos

Explicación paso a paso:

El tiempo necesario para completar la trayectoria se conoce como tiempo de vuelo.

Tiempo de vuelo = dónde;

U es la velocidad inicial del cuerpo = 47,5 m / s

es el ángulo de lanzamiento = 39,4 °

g es la aceleración debida a la gravedad = 9,81 m / s²

Sustituyendo los parámetros dados en la fórmula anterior, tendremos;

[tex]T = \dfrac{2(47.5)sin39.4^0}{9.81} \\\\T = \dfrac{95sin39.4^0}{9.81} \\\\T = \dfrac{95*0.6347}{9.81} \\\\T = \dfrac{60.2994}{9.81} \\\\T =6.1467 secs[/tex]

El tiempo necesario para completar la trayectoria es de 6.1467 segundos.


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Step-by-step explanation:

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Answer:

|-2y+5|=2|4y-1|

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answer:

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Answer:

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Answers

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Answers

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Answers

Answer:

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Step-by-step explanation:

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