The value of tangent AB as calculated from the given data is 14.4.
The tangents to the circle as given are PA and PB.
Let the point of intersection of PO and AB be X.
PA = 12
OA = 9
As given that the triangle is right angled we can use hypotenuse theorem to calculate PO,
PO = √ PA² + OA²
= √ 144 + 81
= 15
Now , the given triangles are similar because,
AX / AO = PA / PO
AX / 9 = 12 / 15
Therefore, the value of X is,
X = 7.2
Now we know that AB's midpoint is X,
Hence , AB = 2X = 14.4
Tangent is known as a point which passes through a circle only at one single point A circle can have infinite tangents.
To learn more about tangents
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Need help with this question.
9514 1404 393
Answer:
643.72 m²
Step-by-step explanation:
The area is the sum of the areas of the parts. The figure can be divided into a triangle and a semicircle.
The formula for the area of the triangle is ...
A = 1/2bh
For the given base of 28 m and height of 24 m, the area is ...
A = 1/2(28 m)(24 m) = 336 m²
__
The area of a semicircle is given by the formula ...
A = (π/8)d² . . . . for diameter d
The given diameter is 28 m, so the area is about ...
A = (3.14/8)(28 m)² = 307.72 m²
__
Then the total area of the figure is ...
total area = triangle area + semicircle area
total area = 336 m² +307.72 m² = 643.72 m²
Let {u1,u2,u3} be an orthonormal basis for an inner product space V. If
v=au1+bu2+cu3
is so that ∥v∥=42, v is orthogonal to u3, and ⟨v,u2⟩=−42, find the possible values for a, b, and c.
• ||v|| = 42, which is to say
||v||² = 〈v, v 〉
… = 〈a u₁ + b u₂ + c u₃, a u₁ + b u₂ + c u₃〉
… = a ² 〈u₁, u₁〉 + b ² 〈u₂, u₂〉 + c ² 〈u₃, u₃〉 + 2(ab 〈u₁, u₂〉 + ac 〈u₁, u₃〉 + bc 〈u₂, u₃〉)
… = a ² ||u₁||² + b ² ||u₂||² + c ² ||u₃||²
[since each vector in the basis for V is orthogonal to any other vector in the basis, and 〈x, x〉 = ||x||² for any vector x ]
42² = a ² + b ² + c ²
[since each vector in the basis has unit length]
42 = √(a ² + b ² + c ²)
• v is orthogonal to u₃, so 〈v, u₃〉 = 0. Expanding v gives the relation
〈v, u₃〉 = 〈a u₁ + b u₂ + c u₃, u₃〉
… = a 〈u₁, u₃〉 + b 〈u₂, u₃〉 + c 〈u₃, u₃〉
… = c ||u₃||²
… = c
which gives c = 0, and so
42 = √(a ² + b ²)
• Lastly, 〈v, u₂〉 = -42, which means
〈v, u₂〉 = 〈a u₁ + b u₂ + c u₃, u₂〉
… = a 〈u₁, u₂〉 + b 〈u₂, u₂〉 + c 〈u₃, u₂〉
… = b ||u₂||²
… = b
so that b = -42. Then
42 = √(a ² + (-42)²) → a = 0
So we have a = 0, b = -42, and c = 0.
The required values are, [tex]a=0,b=-42 ,c=0[/tex]
Given,
[tex]v=au_1+bu_2+cu_3[/tex]
[tex]\left\| V\right\|=42[/tex]
Computation:
Since, [tex]v[/tex] is orthogonal to [tex]u_3[/tex] then we have,
[tex]\left<v,u_3 \right> =0\\\left< v,u_2\right> =-42[/tex]
Then,
[tex]\left\| V\right\|^2=\left<v,v \right>\\=\left<au_1+bu_2+cu_3,au_1+bu_2+cu_3 \right>\\=a_2\left\|u_1 \right\|^2+b_2\left\|u_2 \right\|^2+c_2\left\|u_3 \right\|^2\\=a^2+b^2+c^2\\=a^2+b^2+c^2=42^2[/tex]
As we know,
[tex]a=\left<v_1u_1 \right>\\b=\left< v_1u_2\right>= -42\\c=\left<v_1u_3 \right> =0[/tex]
[tex]a_2+b_2+c_2=42\\a=0[/tex]
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Hey y’all answers in the picture ABC or D. Plz help
Answer:
D
Step-by-step explanation:
Lets use the the chart. The (5,9) if the 5 was doubled that it would equal to 10. Now you subract 1 from it making it 9.
please someone answer this
Answer:
option 2.
the others are simultaneous equations in two unknowns but 7x-2y have the same value and the value can't be two different things at once
what is the measure of A, in degrees, in the figure shown?
Answer:
[tex]12.7[/tex]
Step-by-step explanation:
[tex]180 - 167.3 = 12.7 \\ < angle \: on\: a \: stright \: line \: is \: 180[/tex]
I pick a ball from a bag, replace it and then pick
another. I keep doing this until I have chosen 40 balls. If I picked out 12 yellow balls, estimate the probability of not picking out a yellow ball.
Answer:
It should be 50%
Step-by-step explanation:
It should be 50% because there are 12 yellow balls, so it should be 50%.
Hope it helps you
The table below is comparing level of education achieved to the rate of unemployment and the median weekly earnings in 2008. Based on the information provided, the unemployment rate decreases the most when moving between which two consecutive educational levels?
Answer:
"less than high school" and" high school graduate".
Answer:
The table below is comparing level of education achieved to the rate of unemployment and the median weekly earnings in 2008. Based on the information provided, the unemployment rate decreases the most when moving between which two consecutive educational levels?
a.
“Less than high school” and “High School Graduate” <<<<<<<CORRECT
b.
“High school graduate” and “Some college, no degree”
c.
“Associate degree” and “Bachelor’s degree”
d.
“Professional degree” and “Doctoral degree”
Step-by-step explanation:
Edge2021
HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Answer:
6/13
Step-by-step explanation:
Watch help
In APQR, PR is extended through point R to point S,
m_QRS = (4x – 15)°, m_RPQ = (x + 1), and
mZPQR = (x - 2)°. Find mZRPQ.
Answer:
m∠RPQ = 8°
Step-by-step explanation:
m∠QRS = 4x - 15
m∠RPQ = x + 1
m∠PQR = x - 2
m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS
m∠QRS = m∠RPQ + m∠PQR {Exterior angle property of triangle}
4x - 15 = x +1 + x - 2
4x - 15 = x + x + 1-2 {Combine like terms}
4x - 15 = 2x - 1 {Subtract 2x from both sides}
4x - 2x - 15 = - 1
2x - 15 = - 1 {Add 15 to both sides}
2x = -1 + 15
2x = 14 {Divide both sides by 2}
x = 14/2
x = 7
m∠RPQ = x + 1 = 7 + 1 = 8°
Answer: x+1 =(7)+1=8
Step-by-step explanation:
Suppose 60% of a large group of animals is infected with a particular disease. What is the probability that at least 2 animals are infected in a sample of size 5?
0.0870
0.3174
0.913
0.6826
Answer:
0.6826
Step-by-step explanation:
Probabilities are used to determine the chances of events.
The probability that at least 2 animals are infected is (c) 0.913
The proportion of the animal infected is given as:
[tex]p =60\%[/tex]
The probability is then calculated using the following binomial equation
[tex]P(x) = ^nC_xp^x(1-p)^{n-x}[/tex]
In this case,
[tex]n = 2[/tex]
To calculate the probability that at least 2 animals are infected, we start by calculating the probability that not up to 2 animals are infected.
So, we have:
[tex]P(x<2) =P(0) + P(1)[/tex]
This gives
[tex]P(x<2) = ^5C_0 \times (60\%)^0 \times (1-60\%)^{5-0}+ ^5C_1 \times (60\%)^1 \times (1-60\%)^{5-1}[/tex]
Simplify
[tex]P(x<2) = 1 \times (60\%)^0 \times (40\%)^{5}+ 5 \times (60\%) \times (40\%)^{4}[/tex]
[tex]P(x<2) = 0.08704[/tex]
Using the complement rule, we have:
[tex]P(x \ge 2) = 1 - P(x<2)[/tex]
So, we have:
[tex]P(x \ge 2) = 1 - 0.08704[/tex]
[tex]P(x \ge 2) = 0.91296[/tex]
Approximate
[tex]P(x \ge 2) = 0.913[/tex]
Hence, the probability is (c) 0.913
Read more about probabilities at:
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Space shuttle Challengerexploded because of O-ring failure shortly after it was launched. O-ring damage and temperature at time of launch for the 23 space shuttle flights that preceded the Challenger. The data is reproduced below.
Flights with O-ring damage 43 57 58 63 70 70 75
Flights with no O-ring damage 66 67 67 67 68 69 70 70 72 73 75 76 76 78 79 81
Is the mean launch temperature for flights with O-ring damage significantly less than for flights with no O-ring damage? Use 5% level of significance.
Solution :
The null and the alternate hypothesis can be stated as :
Null hypothesis
[tex]$H_0:\mu_1 \geq \mu_2$[/tex]
Alternate hypothesis
[tex]$H_a:\mu_1 \leq \mu_2$[/tex]
We known;
[tex]$\overline x_1=\frac{\sum_{i=1}^n X_i}{n_1}$[/tex]
[tex]$=\frac{43+....+75}{7}$[/tex]
= 62.286
[tex]$\overline x_2=\frac{\sum_{i=1}^n X_i}{n_2}$[/tex]
[tex]$=\frac{66+....+81}{16}$[/tex]
= 72.125
[tex]$s_1^2=\frac{\sum_{i=1}^n(X_i- \overline X_1)^2}{n_1-1}$[/tex]
[tex]$=\frac{(43-65.5)^2+....+(75-65.5)^2}{7-1}$[/tex]
= 116.571
[tex]$s_2^2=\frac{\sum_{i=1}^n(X_i- \overline X_2)^2}{n_2-1}$[/tex]
[tex]$=\frac{(66-72.13)^2+....+(81-72.13)^2}{16-1}$[/tex]
= 23.45
Therefore, calculating the test statics :
[tex]$t=\frac{\overline x_1 - \overline x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}$[/tex]
[tex]$t=\frac{62.29-72.125}{\sqrt{\frac{116.571}{7}+\frac{23.45}{16}}}$[/tex]
[tex]$t=\frac{-9.839}{4.2566}$[/tex]
= -2.312
Now calculating the P-value for the test as follows :
P=T.DIST(t, df)
[tex]$df=\frac{\left(\frac{s_1^2}{n_1}+\frac{s^2_2}{n_2}\right)^2}{\frac{1}{n_1-1}\left(\frac{s^2_X}{n_1}\right)^2+\frac{1}{n_2-1}\left(\frac{s^2_Y}{n_2}\right)^2}$[/tex]
[tex]$df=\frac{\left(\frac{116.571}{7}+\frac{23.45}{16}\right)^2}{\frac{1}{7-1}\left(\frac{116.571}{7}\right)^2+\frac{1}{16-1}\left(\frac{23.45}{16}\right)^2}$[/tex]
[tex]$=\frac{328.2868}{46.36395}$[/tex]
[tex]$\approx 7$[/tex]
P=T.DIST(t, df)
=T.DIST(-2.31, 7)
= 0.0270
Thus, the [tex]$\text{P-value}$[/tex] of the test is P = 0.0270 is [tex]$\text{less}$[/tex] than the level of significance [tex]$\alpha= 0.05$[/tex]. Hence the researcher can reject the null hypothesis.
Conclusion: The mean launch temperature for the flights with O ring damages less than that for the flights with no O rings.
Joseph and Molly each have coin collections. Joseph starts with 15 coins in his collection and adds 25 coins each month. Molly starts with 25 coins in her collection and adds 25 coins each month. How many coins would Joseph have after 3 months?
Answer:
Joseph has 90 coins after 3 months
Step-by-step explanation:
Joseph: 25x + 15
Molly: 25x + 25
x = 3
Joseph: 25(3) + 15 = 90
Aiden calculated that their family used 20% of their monthly income for food, and 15% of the money spent on food was spent on snacks. If they spent $45 on snacks, what is their monthly income?
Answer:
There monthly income is 300$
Janae solved the equation 3.67 = c − 2.13 , and found the value for c. Janae's solution was c =1.54 Do you agree or disagree with her solution. Explain. Show your work. plzzz help me ill give yo a brainlyiest
Answer:
Solution;
given equation : 3.67 = c - 2.13
On solving equation, we get
c = 3.67 +2.13
c = 5.8
Hence, Janae solution is incorrect. So I disagree.
Answer: No because the answer is c =5.8 or 5.80
Step-by-step explanation:
Add 2.13 to both sides. 3.67 + 2.13 = 5.80
HURRY! What is the circumference of the circle below? Use 3.14 for π.
Answer:
2.14 divided by 5 x 2 is the ansewer
Step-by-step explanation:
In a clothing store, 65% of the customers buy a shirt, 30% of the customers buy a pair of pants, and 20% of the customers buy both a shirt and a pair of pants. I’m f a customer is chosen at random, what is the probability that he or she buys a shirt or a pair of pants?
Answer:
The Answer will be (0.75)
Find x if these are similar
Answer:
C) 28
Step-by-step explanation:
RSTV = WXYZ
WX = x
[tex]\frac{RS}{VR} =\frac{WX}{ZW} \\\\\frac{7}{3} =\frac{x}{12} \\\\3x=84\\x=28[/tex]
Jada is standing 10 feet from the base of a tree and spot a nest sitting on a branch.the angle of elevation from the ground where she standing to the nest 55.find the height of the nest
Answer:
Hence, the height of the tree is 14.3 feet.
Determine which point is part of the solution set to the following
system of inequalities: f(x) < x + 4; f(x) > - X-3; and f(x) < 5.
(0,0)
(-60)
(-3, 4)
(4,6)
Solve for x.
Enter the solutions from least to greatest.
(2x + 4)(3x − 2) = 0
lesser x =
greater x =
Answer:
lesser x = -2, greater x = 2/3
Step-by-step explanation:
(2x+4)= 0 ---> bring 4 to the other side
2x=-4 ----> divide by 2 on both sides
x= -4/2 = -2 ----> simplify
(3x-2)= 0 ----> bring the 2 to the other side
3x=2 ----> divide by three on both sides
x=2/3
hope this helps!
Solve (z + 6)2 = 5
{−6±5‾√}
{6±5‾√}
{5‾√±−6}
{−6+5‾√,6−5‾√}
9514 1404 393
Answer:
(a) -6±√5
Step-by-step explanation:
(z +6)^2 = 5 . . . . . given
z +6 = ±√5 . . . . . take the square root
z = -6 ±√5 . . . . . . subtract 6
I need help please fast .................
Answer:
I have no idea what sohcahtoa is but:
tan 50.1° = x/5
1.196 = x/5
multiply both sides of the equation by 5:
x = 5.98
Solve this expression: (2-i)(-3+i)
Answer:
-5+5i
Step-by-step explanation:
Answer:
D on edge
Step-by-step explanation:
-5+5i
What is the value of the angle marked with x?
Answer:
132
Step-by-step explanation: I'm not very sure tho
the probability that a student takes spanish is 70%. The probability that a student takes spanish and they are a freshman is 30% what is the probability that a randomly selected student is a freshman given that he/she takes spanish
30%....................................
Answer: At Kennedy Middle School, the probability that a student takes Technology and Spanish is 0.087. The probability that a student takes Technology is 0.68
Step-by-step explanation: u divide
This data shows the number of sit-ups done by 27 students in a gym class.
58 62 49 52 75 86 88 54 56 61 85 48 77 60
47 58 62 73 78 69 65 84 59 67 53 84 50
Which histogram represents the data?
Answer:
C
Step-by-step explanation:
None of the others have the correct data like C
A 33 gram sample of a substance that's
used for drug research has a k-value of
0.1124.
Find the substances half life and the round your answer to the nearest 10th
9514 1404 393
Answer:
6.2
Step-by-step explanation:
We presume your "k-value" is the k in the exponential decay term ...
e^(-kt) . . . where t is the number of time units
This is 1/2 when ...
ln(1/2) = -kt
t = ln(1/2)/(-k) = ln(2)/k
t = 0.69315/0.1124 ≈ 6.2
The half life is about 6.2 time units.
Find the slope of the line (2,6) and (-2,-4)
In the triangle below,
x = [ ? ] cm. Round to the
nearest tenth.
15 cm
х
350
9.00
y
Answer:
x=8.6
Step-by-step explanation:
x=8.6
In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each point using values of rr such that r≥0 and values of θ such that 0≤θ<2π. Visually check your answers to ensure they make sense.
(x,y)=(2,5) corresponds to (r,θ)=
(x,y)=(−3,3) corresponds to (r,θ)=
(x,y)=(−5,−3.5) corresponds to (r,θ)=
(x,y)=(0,−5.4)corresponds to (r,θ)=
Step-by-step explanation:
We have cartisean points. We are trying to find polar points.
We can find r by applying the pythagorean theorem to the x value and y values.
[tex]r {}^{2} = {x}^{2} + {y}^{2} [/tex]
And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.
[tex] \tan(x) = \frac{y}{x} [/tex]
Remeber since we are trying to find the angle measure, use inverse tan function
[tex] \tan {}^{ - 1} ( \frac{y}{x} ) = [/tex]
Answers For 2,5
[tex] {2}^{2} + {5}^{2} = \sqrt{29} = 5.4[/tex]
So r=sqr root of 29
[tex] \tan {}^{ - 1} ( \frac{5}{2} ) = 68[/tex]
So the answer is (sqr root of 29,68).
For -3,3
[tex] { -3 }^{2} + {3}^{2} = \sqrt{18} = 3 \sqrt{2} [/tex]
[tex] \tan {}^{ - 1} ( \frac{3}{ - 3} ) = - 45[/tex]
Use the identity
[tex] \tan(x) = \tan(x + \pi) [/tex]
So that means
[tex] \tan(x) = 135[/tex]
So our points are
(3 times sqr root of 2, 135)
For 5,-3.5
[tex] {5}^{2} + {3.5}^{2} = \sqrt{37.25} [/tex]
[tex] \tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} ) = 35[/tex]
So our points are (sqr root of 37.25, 35)
For (0,-5.4)
[tex] {0}^{2} + { - 5.4}^{2} = \sqrt{} 29.16 = 5.4[/tex]
So r=5.4
[tex] \tan {}^{ - 1} (0) = undefined[/tex]
So our points are (5.4, undefined)