What is the output of the following java code? int num = 14; while (num <= 32) num = num 10; system.out.println( num );

Answers

Answer 1

The result of the supplied Java code is number 34. num = 10; system.out.println; int num = 14; while (num = 32) num = num 10 ( num ).

In a do while loop, which runs first?

The loop's body (the code block) is indented and surrounded by braces for readability. If only one statement is used in the body of the loop, the braces are not necessary. A loop with an exit condition is the do-while loop. In other words, the loop's body is always run first.

When could employing a for loop be preferable to a while loop?

When you are certain that the loop should run n times, use a for loop.

To know more about Java code visit :-

https://brainly.com/question/5326314

#SPJ4

Related Questions

why is the uefi framework considered to be better than the bios framework? a. it has a better user interface and supports remote troubleshooting. b. it restricts the hardware support to less than 1tb, offering better security than bios. c. it can identify the virus and malware in a device before the system is launched. d. it comes with additional features of os hardening and anti-intrusion systems.

Answers

The UEFI framework, considered to be better than the bios framework, is it can identify the virus and malware in a device before the system is launched. The correct option is c.

What is the UEFI framework?

A computer's firmware and operating system are connected through a software package called UEFI, which is a specification (OS). A quicker boot time is offered by UEFI.

While BIOS contains drive support encoded in its ROM, UEFI has discrete driver support. As a result, changing BIOS firmware might be challenging. Secure Boot, a feature of UEFI security, stops the machine from starting up from untrusted or unsigned apps.

Therefore, the correct option is c. it can identify the virus and malware in a device before the system is launched.

To learn more about UEFI framework, refer to the link:

https://brainly.com/question/17232780

#SPJ1

2. Busy intersection There is a busy intersection between two one-way streets: Main Street and 1st Avenue. Cars passing through the intersection can only pass through one at a time. When multiple cars arrive at the intersection at the same time, two queues can build up - one for each street. Cars are added to the queue in the order at which they arrive. Unfortunately, there is no traffic light to help control traffic when multiple cars arrive at the same time. So, the local residents have devised their own system for determining which car has priority to pass through the intersection: - If in the previous second, no car passed through the intersection, then the first car in the queue for 1 st Avenue goes first. - If in the previous second, a car passed through the intersection on 1st Avenue, then the first car in the queue for
1st
Avenue goes first. - If in the previous second, a car passed through the intersection on Main Street, then the first car in the queue for Main Street goest first. Passing through the intersection takes 1 second. For each car, find the time when they will pass through the intersection. Function Description Complete the function getResult in the editor below. getResult has the following parameters: int arrival [n]: an array of
n
integers where the value at index
i
is the time in seconds when the
i th car arrives at the intersection. If arrival[i]
=
arrival[j] and
i , then car
i
arrives before car
j
. int street[n]: an array of
n
integers where the value at index
i
is the street on which the
t th car is traveling: Street and 1 for 1 st Avenue. Returns:
int[n]:
an array of
n
integers where the value at index
i
is the time when the
i th car will pass through the intersection Constraints -
1≤n≤10 5
-
0≤arrival[i]≤10 9
for
0≤i≤n−1
- arrival[i]
≤
arrival[i
+1]
for
0≤i≤n−2
-
0≤s
street
[i]≤1
for
0≤i≤n−1

Answers

The program that can be used to illustrate the information of busy intersection between two one-way streets is given below.

The program that features the cars will be:

def getResult(arrival, street):

# Write your code here

result = []

# The first car arrives on Main Street at time 0. The first car arrives on 1st Avenue at time 0. The second car arrives on Main Street at time

1. The third car arrives on 1st Avenue at time 5.

time = 0

main_street_queue = []

first_avenue_queue = []

while len(main_street_queue) > 0 or len(first_avenue_queue) > 0:

if len(main_street_queue) == 0:

car_to_add_to_result = first_avenue_queue.pop(0)