Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected over x = −2. N′(1, 2), M′(−2, 1), O′(−1, 3) N′(−5, −6), M′(−2, −5), O′(−3, −7) N′(−5, 0), M′(−2, −1), O′(−3, 1) N′(9, 2), M′(6, 1), O′(7, 3)

The angle of depression at which Beatrice sees the boat is given as follows:

x = 6.65º.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

For the angle, we have that:

Hence the angle is obtained applying the tangent ratio as follows:

tan(x) = 70/600

x = arctan(70/600)

x = 6.65º.

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The angle of depression at which Beatrice sees the boat is given as follows:

x = 6.65º.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

For the angle, we have that:

Hence the angle is obtained applying the tangent ratio as follows:

tan(x) = 70/600

x = arctan(70/600)

x = 6.65º.

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The investment will be worth approximately $3,326 after 9 years.

The interest that is paid on both the initial investment and any interest that has been paid on that investment in previous periods is called compound interest.

The investment's future value can be determined using the formula for compound interest:

[tex]A = P * (1 + \frac{r}{n})^{nt}[/tex]

where, A = future value of the investment, P = principal (initial investment), r = annual interest rate, n = number of times, interest compounded per year, and t = number of years.

In this case, given values:

P = $2200 (the initial investment or principal)

r = 4.7% (the annual interest rate expressed as a decimal)

n = 1 (interest is compounded annually)

t = 9 (the investment is held for 9 years)

putting the values,

[tex]A = 2200 * (1 + \frac{0.047}{1} )^{1*9}[/tex]

[tex]A = 2200 * (1.047)^9[/tex]

A = $3326.16

Therefore, the investment will be worth approximately $3326 after 9 years.

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The investment will be worth approximately $3,326 after 9 years.

The interest that is paid on both the initial investment and any interest that has been paid on that investment in previous periods is called compound interest.

The investment's future value can be determined using the formula for compound interest:

[tex]A = P * (1 + \frac{r}{n})^{nt}[/tex]

where, A = future value of the investment, P = principal (initial investment), r = annual interest rate, n = number of times, interest compounded per year, and t = number of years.

In this case, given values:

P = $2200 (the initial investment or principal)

r = 4.7% (the annual interest rate expressed as a decimal)

n = 1 (interest is compounded annually)

t = 9 (the investment is held for 9 years)

putting the values,

[tex]A = 2200 * (1 + \frac{0.047}{1} )^{1*9}[/tex]

[tex]A = 2200 * (1.047)^9[/tex]

A = $3326.16

Therefore, the investment will be worth approximately $3326 after 9 years.

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Answer:

A

Step-by-step explanation:

The correct option is A) μoverbar(x)= 2; σoverbar(x)= 75.

Answer: 4/21

Step-by-step explanation: 1 1/3 =4/3 3 1/2x2= 7

The width of the rectangular section of Clark's backyard is 3.9 meters.

Area of the rectangular section is 11.31 sq meters.

length of rectangular section is 2.9 meters.

For a rectangular section the formula for area is equal to the product of length and width of the rectangular section.

                  Area = length * width

Rectangle: It is a 4 sided structure with two equal opposite sides It also has 4 right angles and sum of all angles is equal to 360°.

here,

                 width = [tex]\frac{area}{length}[/tex] = [tex]\frac{11.31}{2.9} =3.9[/tex] meters.

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There are a total of 8 pieces on the outer edge with only one frosted side.

We have,

If Sally has frosted the top and all sides but not the bottom of the cake, then each piece will have one frosted side (the top) and three unfrosted sides (the bottom and two sides).

Out of the 9 pieces, only the pieces on the outer edge will have exactly one frosted side.

If we count the number of pieces on the outer edge, we can determine how many pieces are frosted on only one side.

For a cube-shaped cake, there are 8 pieces on the outer edge.

To see why, imagine slicing off the corners of the cube to create a smaller cube inside.

Each of the 6 faces of the smaller cube will have a piece missing from the corner.

Therefore, there are 6 pieces on the outer edge of the larger cube, and each of these pieces can be divided into two smaller pieces (with one frosted side each) by cutting along the diagonal.

This gives a total of 12 pieces, but we need to subtract the 4 corner pieces that have two frosted sides each.

So there are a total of 8 pieces on the outer edge with only one frosted side.

Therefore,

There are a total of 8 pieces on the outer edge with only one frosted side.

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There are a total of 8 pieces on the outer edge with only one frosted side.

We have,

If Sally has frosted the top and all sides but not the bottom of the cake, then each piece will have one frosted side (the top) and three unfrosted sides (the bottom and two sides).

Out of the 9 pieces, only the pieces on the outer edge will have exactly one frosted side.

If we count the number of pieces on the outer edge, we can determine how many pieces are frosted on only one side.

For a cube-shaped cake, there are 8 pieces on the outer edge.

To see why, imagine slicing off the corners of the cube to create a smaller cube inside.

Each of the 6 faces of the smaller cube will have a piece missing from the corner.

Therefore, there are 6 pieces on the outer edge of the larger cube, and each of these pieces can be divided into two smaller pieces (with one frosted side each) by cutting along the diagonal.

This gives a total of 12 pieces, but we need to subtract the 4 corner pieces that have two frosted sides each.

So there are a total of 8 pieces on the outer edge with only one frosted side.

Therefore,

There are a total of 8 pieces on the outer edge with only one frosted side.

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The production of biodiesel would be the least likely to impact the price of electricity. Biodiesel is not commonly used as a fuel source for electricity generation, so changes in its production would not significantly affect the overall supply and demand of electricity. On the other hand, the price of a barrel of oil, the cost of a ton of coal, and a fire in a gas pipeline could all impact the price of electricity, as these are commonly used fuel sources for electricity generation.

The number of scoops of seeds needed to fill three bird feeders is 13 1/7 scoops of seeds .

To calculate the total seed quantity required to fill all three feeders, begin by computing the volume for the first two dispensers: each can hold 5 and five-twelfths cups of seeds.

Next, this text assumes an understanding that one scoop of seeds holds approximately 1 and one-sixth cups of product. Using this information, we determine how many scoops are needed to satisfy all three bird feeders' capacity.

By multiplying the first fraction's value with the reciprocal of the second fraction helps you divide fractions accurately:

(46 / 3) x (6 / 7) = (46 x 6) / (3 x 7) = 276 / 21

276 / 21 = 13 3/21

13 3/21 = 13 1/7 scoops

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The total of the debit side of the unadjusted trial balance is $25,650.

We have,

To find the total of the debit side of the unadjusted trial balance,

We need to add up the debit balances of all the accounts listed.

i.e

Accounts Receivable, Cash, Common Stock, Equipment, Insurance Expenses, Land, Notes Receivable, Prepaid Insurance, Rent Expenses, Salaries, and Wages Expense are all debit accounts.

Notes Payable is a credit account, so we subtract it from the total.

Service Revenue and Retained Earnings do not have balances, as they are not accounts that are included in the trial balance.

Now,

The total of the debit side of the unadjusted trial balance is:

= $5,100 + $1,760 + $1,760 + $6,280 + $4,600 + $5,500 + $430 + $1,430 + $430 + $3,760

= $30,050

Subtracting Notes Payable of $4,400.

= $30,050 - $4,400

= $25,650

Therefore,

The total of the debit side of the unadjusted trial balance is $25,650.

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The length of the base is 15 feet and the height is 12 feet.

The three line fragments are known as the sides of the triangle, while the three places where they converge are known as the vertices of the triangle.

Let suppose, base of the triangle = x

Then, according to the problem, the height of the triangle is x - 3.

We know the area of triangle is,

[tex]A = \frac{1}{2}*b*h[/tex]  ;   here A is the area, h is the height and b is the base.

Put the given values,

[tex]90 = \frac{1}{2} *(x)*(x-3)[/tex]

Multiplying both sides by 2:

180 = x² - 3x

x² - 3x - 180 = 0

(x - 15)(x + 12) = 0

Therefore, either x - 15 = 0 or x + 12 = 0.

If x - 15 = 0, then x = 15, which is the length of the base of the triangle.

If x + 12 = 0, then x = -12, which is not a valid solution since the length of a side of a triangle cannot be negative.

Therefore, the length of the base of the triangle is 15 feet.

The height of the triangle (x - 3), so the height is: (15 - 3) = 12 feet.

Hence, the length of the base is 15 feet and the height is 12 feet.

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The value of the inequality is g≤2.5

In mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.

The given inequality is 4g≤10

To solve the inequality, divided bo sides of the inequality by the coefficient of g which is 4

This gives the value

4g/g≤10/4

⇒ that g = 2.5

Therefore the value of the inequality is g≤2.5

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The key features of the sinusoidal function are calculated below

The function y = tan(1/3x) is a tangent function with a period of π/b, where b is the coefficient of x in the argument of the tangent function.

In this case, b = 1/3, so the period is π/(1/3) = 3π.

The interval for the principal cycle is the range of x-values that produce one complete cycle of the tangent function.

Since the tangent function has vertical asymptotes at x = (2n+1)π/2 for all integers n, we can find the interval for the principal cycle by finding the smallest interval that contains one complete cycle and does not contain any vertical asymptotes.

To find the interval for the principal cycle, we first note that the tangent function has a vertical asymptote at x = π/2.

Therefore, we can start the interval at x = π/2 and then move to the right until we complete one cycle and reach the next vertical asymptote.

Since the period is 3π, the next vertical asymptote is at x = π/2 + 3π = 7π/2.

Therefore, the interval for the principal cycle is [π/2, 7π/2].

To find the equations of the vertical asymptotes, we use the formula x = (2n+1)π/2 for all integers n.

Therefore, the equations of the vertical asymptotes are x = π/2 + nπ for all integers n.

The center point of the principal cycle is the midpoint between the x-values of the endpoints of the interval.

Therefore, the center point is (π/2 + 7π/2)/2 = 4π/2 = 2π.

The halfway points of the principal cycle are the points where the tangent function takes on half of its maximum and minimum values.

Since the maximum and minimum values of the tangent function are ±∞, we can instead find the points where the tangent function is zero.

The tangent function is zero at x = nπ for all integers n, so the halfway points of the principal cycle are (π, 0) and (3π, 0).

The graph is attached

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The value of arctan(√2) for the equation tan(x/2 - π/2) = √2 in the form x=π +πn is given by arctan(√2) = π/4 + πn, where n is an integer.

Equation is equal to,

tan(x/2 - π/2) = √2

By using the identity for tangent of half angle,

tan(x/2 - π/2)

= 1/cot(x/2 - π/2)

= 1/(-tan(x/2))

So the equation becomes,

1/(-tan(x/2)) = √2

Multiplying both sides by -1, we get,

tan(x/2) = -1/√2

            = -√2/2

Now use the inverse tangent function (arctan) to find x/2,

arctan(-√2/2) = -π/4

Since x/2 - π/2 = -π/4, we have,

⇒ x/2 = -π/4 + π/2

         = π/4

The solutions for x are x = π/2 + 2πn, where n is an integer.

Now let us find the value of arctan(√2),

arctan(√2) is the angle whose tangent is √2.

Since tan(π/4) = √2, we have,

arctan(√2) = π/4 + πn, where n is an integer.

Therefore, the value of arctan(√2) in the form x=π +πn is equal to

arctan(√2) = π/4 + πn, where n is an integer.

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Frank used a total of 2 14/15 gallons of gas on Saturday and Sunday combined.

To find the total amount of gas Frank used on both days, we need to add the amount of gas he used on Saturday and Sunday.

First, we need to make sure that both quantities are in the same form. We can convert the mixed number 2 1/3 to an improper fraction by multiplying the whole number by the denominator and adding the numerator. This gives us:

2 1/3 = (2 x 3 + 1)/3 = 7/3

Next, we can add the two quantities by finding a common denominator. The lowest common denominator for 3 and 5 is 15. So, we can write:

7/3 gallons + 3 2/5 gallons = (35/15 + 9/15) gallons

= 44/15 gallons

To simplify the answer, we can express the mixed number as a whole number and a proper fraction by dividing the numerator by the denominator. This gives us:

44/15 = 2 14/15

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Answer:Supplementary

Step-by-step explanation:

The two angles add up to 180

Answer:

supplementary since 136+44= 180 and any angles that sum up to 180 are supplementary

The measure of angle C is given as follows:

C = 106.6º.

The Law of Cosines is a trigonometric formula that relates the lengths of the sides of a triangle to the cosine of one of its angles. It is also known as the Cosine Rule.

The Law of Cosines states that for any triangle with sides a, b, and c and angle C opposite to side c, the following equation holds true:

c^2 = a^2 + b^2 - 2ab cos(C)

The side of length 9 is opposite to the angle C, hence the equation is given as follows:

9² = 4² + 7² - 2 x 4 x 7 x cos(C)

56cos(C) = -16

cos(C) = -16/56

C = arccos(-16/56)

C = 106.6º.

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The value of the angle C of the given triangle using law of cosines is: C = 106.6°

We usually make use of the Law of Cosines, if only one of which is missing: three sides and one angle. Thus, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.

This could be in the form of:

c² = a² + b² - 2ab Cos C

From the given triangles, we have:

a = 4

b = 7

c = 9

Thus:

9² = 4² + 7² - 2(4 * 7)cos C

81 = 16 + 49 - 56 cos C

56 cos C = -16

cos C = -16/56

cos C = -0.2857

C = cos⁻¹0.2857

C = 106.6°

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The average rate of change of the function f(x) = x² on the interval [3, 3 + h] is given as follows:

h + 6.

The average rate of change of a function is given by the change in the output of the function divided by the change in the input of the function.

The function in this problem is given as follows:

f(x) = x².

Then the outputs are obtained as follows:

The change in the output is given as follows:

h² + 6h + 9 - 9 = h² + 6h.

The change in the input is given as follows:

3 + h - 3 = h.

Hence the rate is:

r = (h² + 6h)/h.

r = h(h + 6)/h

r = h + 6.

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The value of the thickness of each record if the volume of the carton is 100π is,

⇒ 2.78 inches

We have to given that;

Karen can fit 25 vinyl records of diameter 12 in. inside a cylindrical carton with the same diameter.

We know that;

Volume of cylinder is,

⇒ V = πr²h

Hence, We get;

100π = π × (12/2)² × h

100 = 36h

h = 100 / 36

h = 50/18

h = 2.78 inches

Thus, The value of the thickness of each record if the volume of the carton is 100π is,

⇒ 2.78 inches

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Answer:

96

Step-by-step explanation:

8 times 12 = 96

Answer:

When x = -3:

h(-3) = 9 * (2/3)^(-3)

When x = -2:

h(-2) = 9 * (2/3)^(-2)

When x = -1:

h(-1) = 9 * (2/3)^(-1)

When x = 0:

h(0) = 9 * (2/3)^0

When x = 1:

h(1) = 9 * (2/3)^1

When x = 2:

h(2) = 9 * (2/3)^2

When x = 3:

h(3) = 9 * (2/3)^3

Step-by-step explanation:

I think it is this

If glass contains 320 cm³ of milk, the mass of the milk is 330 g, the density of the milk is approximately 1031 kg/m³.

Density is defined as the mass per unit volume of a substance. To find the density of milk in kg/m³, we need to convert the given volume and mass to the appropriate units.

First, we need to convert the volume from cm³ to m³. Since 1 m = 100 cm, 1 m³ = (100 cm)³ = 1,000,000 cm³. Therefore, we can convert 320 cm³ to m³ by dividing by 1,000,000:

320 cm³ ÷ 1,000,000 = 0.00032 m³

Next, we need to convert the mass from grams to kilograms. Since 1 kg = 1000 g, we can convert 330 g to kg by dividing by 1000:

330 g ÷ 1000 = 0.33 kg

Now that we have both the mass and volume in appropriate units, we can calculate the density by dividing the mass by the volume:

Density = mass ÷ volume = 0.33 kg ÷ 0.00032 m³ ≈ 1031 kg/m³

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The area of the figure is 45 square millimeters.

What is Area?

Area is a measure of the size or extent of a two-dimensional surface or shape. It is usually expressed in square units such as square meters , square feet , square centimeters , square inches , etc. The area of a shape or surface can be calculated by multiplying the length of one side or dimension by the length of an adjacent side or dimension, or by using specific formulas depending on the shape.

The figure can be broken down into a rectangle (5 mm x 7 mm) and two right triangles (with legs 2 mm and 3 mm, respectively).

Area of rectangle = length x width = 5 mm x 7 mm = 35 square mm

Area of each triangle = 1/2 x base x height = 1/2 x 2 mm x 4 mm = 4 square mm

1/2 x 3 mm x 4 mm = 6 square mm

Total area of the figure = area of rectangle + area of two triangles = 35 square mm + 4 square mm + 6 square mm = 45 square mm.

Therefore, the area of the figure is 45 square millimeters.

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It will take 14.14 seconds for the object to return to the ground.

We know that the height is modeled by the quadratic equation:

h(t)=-5t^2+120t+17

The object will return to the ground when its height is zero, so we only need to solve the quadratic equation:

0 = -5t^2+120t+17

Using the quadratic formula we will get.

[tex]t = \frac{-120 \pm \sqrt{120^2 - 4*-5*17} }{2*-5} \\\\t = \frac{-120 \pm 121.4 }{-10}[/tex]

We only care for the positive solution:

t = (-120 - 121.4)/-10 = 14.14

It will take 14.14 seconds.

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Complete question:

"The height of an object is launched into the air given by the function h(t)=-5t^2+120t+17 where t is the time in seconds. How long takes for the object to hit the ground?"

The size of the payments that must be deposited at the beginning of each 6-month period in an account that pays 9.6%, compounded semiannually, is PMT ≈ $1,757.23

FV = PMT * [(1 + r)^nt - 1] / r

(1 + r)^nt = (1 + 0.048)^(2 * 19)

= (1.048)^38

= 5.0989

$150,000 = PMT * [(5.0989 - 1) / 0.048]

$150,000 = PMT * 4.0989 / 0.048

$150,000 ≈ PMT * 85.4146

Now, divide both sides by 85.4146 to find the value of PMT:

PMT ≈ $150,000 / 85.4146

PMT ≈ $1,757.23

The size of the payments that must be deposited at the beginning of each 6-month period in an account that pays 9.6%, compounded semiannually, is PMT ≈ $1,757.23

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Answer:

Step-by-step explanation:

it's (y2-y2)/(x2-x1) slope

=14/3

Answer:

Yes, point A on the graph represents a pair of possible values of m and w because it satisfies the equation w = 2.5m + 5.

To confirm this, we can substitute m = 20 into the equation to get:

w = 2.5(20) + 5

w = 50 + 5

w = 55

So the coordinates of point A are (20, 55), which represents a possible value of m and w that satisfies the equation.

Answer:

1. 62

Step-by-step explanation:

The answers are A = 46% and B = 20%.

Given that, a table of data, each cell in the table shows the number of cars in that category.

A) The probability that the car's total repair cost is less than $10000 =

86 / (86+35+67) x 100 = 86/188 x 100 = 46%

B) The probability that the car's purchase was more than $40,000 =

40 / (40+86+71) x 100 = 40/197 x 100 = 20%

Hence, the answers are A = 46% and B = 20%.

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Answer:

--------------------------

We are given the slope and a point on the line.

Use the point-slope equation to find the equation of the line:

Substitute -6 for m and 1 for x₁ and -2 for y₁:

The matching choice is C.