Three resonance structures of the given anion are possible. One is given, but it is incomplete. Complete the given structure by adding nonbonding electrons and formal charges. Draw the two remaining resonance structures (in any order), including nonbonding electrons and formal charges. Omit curved arrows.

Answer:

The arguments both for and against allowing genetically altered meats into the United States is explained below in details.

Explanation:

Arguments for and against genetically altered meats:

Answer:

The arguments both for and against allowing genetically altered meats into the United States is explained below in details.

Explanation:

Arguments for and against genetically altered meats:

Supply the Society. By 2050, the world's inhabitants are supposed to increase from today's 7 billion to way beyond 9 billion.

ENVIRONMENTAL RISK.

STRONGER CROPS = LESS PESTICIDES.

REMEMBER WHEN CIGARETTES WERE 'HARMLESS'?

TAMPERING FOR TASTE. ...

BIG BUSINESS EATS SMALL FARMERS.

ENHANCED HEALTH.

NOTHING TASTES BETTER THAN NATURE.

Explanation:

Answer:

The blood sample has [H⁺] that is one million times lower than the [H⁺] of gastric juice.

Explanation:

To know the the correct answer to the question, we obtained obtained the hydrogen ion concentration [H⁺] of the blood and gastric juice. This can be obtained as follow:

For Blood sample:

pH = 7.4

Concentration of Hydrogen ion for blood [H⁺]₁ =?

pH = – Log [H⁺]₁

7.4 = – Log [H⁺]₁

Divide both side by –1

– 7.4 = Log [H⁺]₁

Take the antilog of – 7.4

[H⁺]₁ = Antilog (–7.4)

[H⁺]₁ = 3.98×10¯⁸ M

Thus, the concentration of Hydrogen ion for blood [H⁺]₁ is 3.98×10¯⁸ M

For Gastric juice:

pH = 1.4

Concentration of Hydrogen ion for gastric juice [H⁺]₂ =?

pH = – Log [H⁺]₂

1.4 = – Log [H⁺]₂

Divide both side by –1

– 1.4 = Log [H⁺]₂

Take the antilog of – 1.4

[H⁺]₂ = Antilog (–1.4)

[H⁺]₂ = 3.98×10¯² M

Thus, the concentration of Hydrogen ion for gastric juice [H⁺]₂ is 3.98×10¯² M

Finally, we shall compare the hydrogen ion concentration [H⁺] of the blood and gastric juice. This can be obtained as follow:

Concentration of Hydrogen ion for blood [H⁺]₁ = 3.98×10¯⁸ M

Concentration of Hydrogen ion for gastric juice [H⁺]₂ = 3.98×10¯² M

[H⁺]₁ / [H⁺]₂ = 3.98×10¯⁸ / 3.98×10¯²

[H⁺]₁ / [H⁺]₂ = 1×10¯⁶

Cross multiply

[H⁺]₁ = [H⁺]₂ × 1×10¯⁶

[H⁺]₁ = [H⁺]₂ / 1000000

From the calculations made above, the blood sample has [H⁺] that is one million times lower than the [H⁺] of gastric juice.

Answer:

1.17 M

Explanation:

Step 1: Write the balanced equation

N₂ + 3 H₂ ⇒ 2 NH₃

Step 2: Calculate the rate of disappearance of H₂

We will use the following expression.

rH₂ = - Δ[H₂]/t = - (0.25 M - 0.50 M)/44 s = 0.0057 M/s

Step 3: Calculate the rate of disappearance of N₂

The molar ratio of N₂ to H₂ is 1:3.

0.0057 mol H₂/L.s × 1 mol N₂/3 mol H₂ = 0.0019 mol N₂/L.s

Step 4: Calculate the final concentration of N₂

We will use the following expression.

[N₂] = [N₂]₀ - rN₂ × t

[N₂] = 1.25 mol/L - 0.0019 mol/L.s × 44 s

[N₂] = 1.17 M

Mole measure the number of elementary entities of a given substance that are present in a given sample.  The mass of [tex]N_{2}[/tex]  with 2.28 mol is 63.84g.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. Mole is inversely proportional to the molar mass of respective molecule. 1 mole contains Avogadro number of atoms, ions or molecules. Mole is extensive property as it depends on the quantity of substance.

mole of [tex]N_{2}[/tex] =given mass of [tex]N_{2}[/tex]  ÷molar mass of nitrogen gas

mass of [tex]N_{2}[/tex]= mole of [tex]N_{2}[/tex] ×molar mass of nitrogen gas

mole of [tex]N_{2}[/tex]= 2.28mol

Substituting the values in the formula we get,

mass of [tex]N_{2}[/tex]= 2.28mol ×28g/mole

mass of [tex]N_{2}[/tex]= 2.28mol ×28

mass of [tex]N_{2}[/tex]=63.84g

Therefore the mass of [tex]N_{2}[/tex] is 63.84g with 2.28 mole is 63.84g.

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Answer:

Substance B, boiling point of 105 °C

Explanation:

Non volatile substances have high boiling points

Answer:

Salivation allows the ingestion of food while digestive juices aids breakdown of food and absorption of nutrients.

Explanation:

When food is taken into the mouth, the presence of food triggers a nervous reflex that causes the salivary gland to produce saliva in the mouth. Once the food particles have been ingested the digestive system breaks down the food into smaller components with the aid of the digestive juices.

Answer:

it went under the process known as crystalization

Explanation:

am a chemist

Answer:

its C

Explanation:

1/74.44 * 79.75 = 1.07

The molarity (mol/L) of NaClO in the bleach, given the data is 1.07 mol/L (Option C)

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mass of solute = percent × mass of solution

Mass of NaClO = 7.25% × 1100

Mass of NaClO = 0.0725 × 1100

Mass of NaClO = 79.75 g

Mole = mass / molar mass

Mole of NaClO = 79.75 / 74.44

Mole of NaClO = 1.07 mole

Molarity = mole / Volume

Molarity of NaClO = 1.07 / 1

Molarity of NaClO = 1.07 mol/L

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Answer: She had 96 grapes.

Explanation:

Answer:

taiks

Explanation:

Answer:

This creates destructive interference.

Explanation:

When the two ends meet they will cancel each other out.

Both students are shaking the rope in the upward direction. Hence their crest will meet up and form the constructive  interference pattern. The intensity of the increases.

When two waves moves in phase, their crest or troughs add up and the amplitude of the wave increases. This phenomenon is called constructive interference.

If the two waves are passing out of phase to each other then they undergo destructive interference. The amplitude of the destructive interference pattern reduces from their initial values.

Here, both students are shaking the rope in the upward direction. Thus, they are in moving in phase. Hence their crest will meet up and form the constructive  interference pattern. The intensity of the increases.

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Answer:

See explanation

Explanation:

A substance is classified as polar, nonpolar or ionic based on its behavior.

For the substances identified, there was no difficult in identifying each as  polar, nonpolar, or ionic because since it was quite to easy identify where each belongs by looking out for whether it mixes or dissolves in our experiment.

Every substance in the experiment either mixed or dissolved during the  experiment.

C. The particles that make up material A have more mass than the particles that make up material B.

The correct option is (c) The particles that make up material A have more mass than the particles that make up material B.

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Answer:

a) Total Volume = 46.18 cm³

b) Mole[tex]_{fraction}[/tex] (He)  =  0.8333  

c) Mole[tex]_{fraction}[/tex] (Ne)  =  0.1666

d) Partial Pressure P[tex]_{He}[/tex] = 2648.68 atm

e) Partial Pressure P[tex]_{Ne}[/tex]  = 529.73 atm

f) total pressure of the new laser tube = 3178.41 atm

Explanation:

Given that;

height of of discharge tube h = 1.2 m = 1.2 × 100 = 120cm

diameter of the tube D = 7 mm = 0.7cm

Radius = D/2 = 0.7/2 = 0.35 cm

a) What is the total volume (cm³)?

Volume = πr²h

we substitute

Volume = π × (0.35)² × 120

Volume = 46.18 cm³

b) What is the mole fraction of He?

Mole fraction of Helium will be;

Mole[tex]_{fraction}[/tex] (He) = Moles of He / Total Moles ( He + Ne)

given that;  5 mol He and 1 mol Ne

Mole[tex]_{fraction}[/tex] (He)  =  5 / ( 5 + 1 )

Mole[tex]_{fraction}[/tex] (He)  =  5 / 6

Mole[tex]_{fraction}[/tex] (He)  =  0.8333  

c) What is the mole fraction of Ne?

Mole fraction of Neon will be;

Mole[tex]_{fraction}[/tex] (Ne) = Moles of Ne / Total Moles ( He + Ne)

given that;  5 mol He and 1 mol Ne

Mole[tex]_{fraction}[/tex] (Ne)  =  1 / ( 5 + 1 )

Mole[tex]_{fraction}[/tex] (Ne)  =  1 / 6

Mole[tex]_{fraction}[/tex] (Ne)  =  0.1666

d) d. What is the partial pressure of He (in atm)?

using ideal gas equation;

P[tex]_{He}[/tex] = nRT/V

where n is number or amount of moles( 5 )

R is the universal gas constant ( 0.08205 L-atm.mol⁻¹K⁻¹

T is temperature ( 298.15 K)

And V is the volume; ( 46.18 cm³ = 46.18/1000 = 0.04618 L )

so we substitute  

P[tex]_{He}[/tex] = (5 × 0.08205 × 298.15) / 0.04618

P[tex]_{He}[/tex] = 122.316 / 0.04618

P[tex]_{He}[/tex] = 2648.68 atm

e) What is the partial pressure of Ne (in atm)?

P[tex]_{Ne}[/tex] = (1 × 0.08205 × 298.15) / 0.04618

P[tex]_{Ne}[/tex]  = 24.463 / 0.04618

P[tex]_{Ne}[/tex]  = 529.73 atm

f) What is the total pressure of the new laser tube (in atm)?

total pressure of the new laser tube will be;

= P[tex]_{He}[/tex] + P[tex]_{Ne}[/tex]

= 2648.68 atm + 529.73 atm

= 3178.41 atm

total pressure of the new laser tube = 3178.41 atm

Answer:

Iron(III) Cyanide

Answer:

C₄ H₆ O

Explanation:

The molecular formula of the compound is given as:

            C₈ H₁₂ O₂

The molecular formula of a compound is expresses the true number of atoms within a compound.

The empirical formula gives the simplest ratio of the atoms within a compound.

            Elements             C                      H                            O

  Number of atoms          8                      12                            2

Divide through by a

Common factor                8/2                    12/2                         2/2  

                                           4                         6                              1

The empirical formula therefore is C₄ H₆ O

Answer:

c. KBr .

Explanation:

Hello!

In this case, since electrolytes are substances that are able to carry electric current in the form of electrons via ions, those that are ionic are said to have the greatest capacity to conduct the electricity; in such a way, since SO2, C6H12O6 and CO are non-ionic molecules but covalent, they are not good conductor, therefore the best conductor would be c. KBr as it is an ionic compound due to the electronegativity of the K-Br bond.

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Answer:

11g/mol is the molar mass of X

Explanation:

The freezing point depression occurs in a solvent by the addition of a solute. The equation is:

ΔT = Kf*m*i

Where ΔT is change in freezing point (5.5°C - 0.5°C = 5.0°C)

Freezing point of benzene is 5.5°C

Kf is molal freezing point depression of benzene (5.07°C*kg/mol)

m is molality of the solution in moles/kg of solvent

And i is Van't Hoff factor (1 for all solutes dissolved in benzene)

Replacing to solve molality:

5.0°C = 5.07°C*kg/mol*m*1

0.986mol / kg = molality

As the mass of the solvent is 25.0g = 0.025kg:

0.025kg * (0.986mol/kg) = 0.0247 moles

As molar mass of X is the ratio between mass in grams and moles, the molar mass of X is:

0.271g / 0.0247moles =

Answer:

B. KBr  + F2

Explanation:

In displacement reactions (reactions in which an element replaces another element in a compound) like these, reactive element displaces the less reactive element.

A. NaBr  +  I2  

This reaction will not occur because Iodine is not able to displace bromine from the compound.

B. KBr  + F2

This reaction will occur because flourine is more reactive and hence is able to displace bromine from the reaction.

C. LiF  +  Cl2

This reaction will not occur because chlorine is not able to displace flourine from the compound.

D. NaCl + I2

This reaction will not occur because Iodine is not able to displace Chlorine from the compound.

Answer:

There will be 216,000 energy transfer reactions

90  [tex]O_{2}[/tex] molecules will be formed

Explanation:

since 2400 chlorophyll molecules = ( 1 ) [tex]O_{2}[/tex] molecule

hence there will be 8 photons  absorbed in this process

for 720 absorbed photons

The number of [tex]O_{2}[/tex] molecules formed = 720 / 8 = 90 molecules of [tex]O_{2}[/tex] molecule formed

Total number of resonance energy transfer reactions

( 1 ) [tex]O_{2}[/tex] molecule = 2400 molecules

 hence 90 molecules of [tex]O_{2}[/tex]

= 2400 molecules * 90 molecules

= 216000 energy transfer reactions

Answer:

Explanation:

a )

H₂O₂ (aq) + 2 Fe²⁺ (aq) + 2 H⁺  = 2H20 (l) + 2 Fe³⁺(aq)

Here oxidation number  of Fe is increasing from + 2 to + 3 so it is being oxidized . Hence H₂O₂ is acting as oxidizing agent here .

b )

5 H₂O₂ (aq) + 2 MnO₄⁻¹ (aq) + 6 H⁺ (aq) → 8 H20 (l) + 2 Mn⁺² (aq) + 5O₂ (g)

In this reaction,  oxidation number of Mn is reducing from + 7 to + 2 so it is being reduced . Here H₂O₂ is acting as reducing agent .

Answer:

Number of moles = 0.328 moles.

Explanation:

Given the following data;

Mass = 5.590 g

Molar mass = 17.030 g/mol

To find the number of moles;

[tex] Number \; of \; moles = \frac {mass}{molar mass} [/tex]

Substituting into the equation, we have

[tex] Number \; of \; moles = \frac {5.590}{17.030} [/tex]

Number of moles = 0.328 moles.

Answer:

2

Explanation:

the number of H is 1, it means the only electron is on the energy level (1st level, s-electron). All the elements have 2 s-electrons on the 1st energy level.

Answer:

C2H2

Explanation:

Mass of Carbon in CO2[tex]= (12/44) (20.31)[/tex] grams [tex]= 5.54[/tex] gram

Mass of hydrogen in H2O [tex]= (2/18)(4.26)[/tex] grams [tex]= 0.46[/tex] gram

We will calculate the % of C and H in the sample  

% C [tex]= (5.54/6) * 100 = 92[/tex]%

% H [tex]= (0.46/6)*100 = 7.7[/tex]%

Number of mole of C [tex]= 92/12 = 7.69[/tex]

Number of mole of H [tex]= 7.67/1 = 7.67[/tex]

Fractional share of  C [tex]= 7.69/7.67 = 1[/tex]

Fractional share of  H [tex]= 7.67/7.67 = 1[/tex]

Empirical Formula = CH

Empirical Mass [tex]= 12+1 = 13[/tex]

Molecular mass [tex]= 26[/tex]

Molecular Formula – CHn  

N [tex]= 26/13 = 2[/tex]

Molecular Formula = C2H2

The given question is incomplete. The complete question is:

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:

A. [tex]K(s)+O_2(g)\rightarrow KO_2(s)[/tex]

B. [tex]CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)[/tex]

C. [tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex]

D. [tex]N_2O_2(g)\rightarrow 2NO(g)+O_2(g)[/tex]

Answer: A. [tex]K(s)+O_2(g)\rightarrow KO_2(s)[/tex] : decreases

B. [tex]CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2(g)[/tex] : decreases

C. [tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex]: no change

D. [tex]N_2O_2(g)\rightarrow 2NO(g)+O_2(g)[/tex] : increases

Explanation:

Entropy is defined as the randomness of the system.

Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.

In reaction [tex]K(s)+O_2(g)\rightarrow KO_2(s)[/tex], as gaseous reactant is changed to solid product, entropy decreases.

In reaction [tex]CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)[/tex], as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.

In reaction [tex]CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)[/tex], as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.

In reaction  [tex]N_2O_2(g)\rightarrow 2NO(g)+O_2(g)[/tex] , as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.

Answer:

Maintenance of homeostasis usually involves negative feedback loops. These loops act to oppose the stimulus, or cue, that triggers them.

Answer:

"3.90M" if approximate

Explanation:

if u didn't understood why i converted volume from millilitres to litre then refer defination of Molarity.

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