Wave interference describes the process through which one set of waves interacts with another. When waves going in different directions collide, interference can occur. The amplitudes of the two waves are altered as they interact with one another.
As the two waves cancel each other out, the total displacement is the sum of the two separate ones. Any time there are many waves in the same medium, the principle of superposition can be applied to them. When the waves encounter one another, they just travel through without being affected.
Simply adding up the individual wave displacements yields the net displacement of the medium at any given location and instant in time. This holds for both periodic sine waves and short-lived, pulsing waves.
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What is the independent variable on this graph?
Oonly temperature (*C)
Oboth flow time (s) and temperature (C)
only flow time (s)
what change in entropy occurs when a 27.9 g ice cube at -12°c is transformed into steam at 115°c?
Upon calculation the change in entropy is found to be 244 J/K.
Entropy is a generic phrase that describes the trend toward disorder as well as the spontaneous changes that take place in everyday situations. Entropy is not only a term used in academia; it is also frequently characterized as a physical feature connected to uncertainty.
For a reversible process the change in entropy is given by:
S= [tex]\frac{dQ}{T}[/tex]
dQ= heat
T= temperature
The change in entropy when the temperature of ice comes to 273 K is:
S= [tex]\int\limits^{273}_ {261} \, \frac{dQ}{T}[/tex]
dQ= mcdT
m= mass of ice= 27.9 gm= 0.0279 kg
c= specific heat capacity= 2090 J/kg C
T= temperature
S=[tex]mc\int\limits^{273}_{261} \, \frac{dT}{T}[/tex]
S= 0.0279× 2090×㏑[tex]\frac{273}{261}[/tex]
S= 2.62 J/K
For conversion of ice into water dQ= mL
m= mass of ice
L= latent heat of fusion= 3.33 ×10⁵
S= [tex]\frac{mL}{T} =\frac{3.33* 100000*0.0279}{273}[/tex]
S= 34 J/K
Change in entropy when the water turns into steam is given by
S= [tex]\int\limits^{373}_{273} \, \frac{mcdT}{T} =mc ln\frac{373}{273}[/tex]
c= heat capacity of water= 4186
S= 0.0279× 4186×㏑[tex]\frac{373}{273}[/tex]
S= 36.5 J/K
Change in entropy at 373 K for steam is given by
S= [tex]\frac{dQ}{T} = \frac{mL}{T}= \frac{2.26*1000000*0.0279}{373} -=169 J/K[/tex]
Here L= 2.26×10⁶
Change in entropy for steam when it rises to a temperature 115 degree Celsius= 388K
S= [tex]\int\limits^{388}_{373} \, \frac{dQ}{T} =\int\limits^{388}_{373} \, \frac{mcdT}{T} =mc\int\limits^{388}_{373} \, \frac{dT}{T} = 0.0279*2010*ln\frac{388}{373} =2.21 J/K[/tex]
Adding all the entropies obtained in the cases we get
Total entropy= 2.62+34+36.5+169+2.21
S= 244J/K
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The physics of wind instruments is based on the concept of standing waves. When the player blows into the mouthpiece, the column of air inside the instrument vibrates, and standing waves are produced. Although the acoustics of wind instruments is complicated, a simple description in terms of open and closed tubes can help in understanding the physical phenomena related to these instruments. For example, a flute can be described as an open-open pipe because a flutist covers the mouthpiece of the flute only partially. Meanwhile, a clarinet can be described as an open-closed pipe because the mouthpiece of the clarinet is almost completely closed by the reed. (a) Consider a pipe of length L open at both ends. If the speed of sound in air is v, what is the fundamental frequency f1 of the sound wave produced when you blow into the pipe (in terms of L and v)? (b) If you drill a hole at a position half the length of the pipe, what is the new fundamental frequency f1' of the sound that can be produced in the pipe (in terms of the original length L and v)? (c) For which values of n does the nth harmonic of the original pipe of length L from part (a) also exist as a harmonic of the pipe in part (b). (d) What length of open-closed pipe would you need to achieve the same fundamental frequency f1'' as the original open-open pipe of length L from part (a)? (e) What is the frequency of the first possible harmonic after the fundamental frequency in the open-closed pipe from part (d) (in terms of L and v)?
The frequency of the first possible harmonic after the fundamental frequency in the open-closed pipe 428.75 Hz.
Calculation:-
A. L = 80 cm
= 0.8 m
V = 343 m/s ( sound speed in the air )
V1 = n V / 2 L
= 1 X 343 / 2 X 0.8
V1 = 214.375 Hz
B. using the above equation
Vf = V / 2 L
[tex]Vf\alpha 1 / L[/tex]
so the new frequency is high than the previous or before.
C. Now L = L / 2 = 0.8 / 2
L = 0.4 m
Vn = n V / 2 L
= 1 X 343 / 2 X 0.4
Vn = 428.75 Hz
so the new frequency is 428.75 Hz
D. Vn = n V / 2 L
L = L /2
Vn = 2 n V / 2 L
Vn = 2 n Vn
n = 2n
Vn = n' Vn
even multiples of the fundamental frequency
E. for open-closed pipe
fn = n V / 4 L
and for an open- open pipe
Vn = n V / 2 L
n V / 2 L = n V / 2 L
2 L = L
L = L / 2
So half the length of open-open Pipe.
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could the young two-slit interference experiment be performed with gamma rays? if not, why not? if so, discuss differences in the experimental design compared to the experiment with visible light.
While there would be interference, the phase difference between the two sources would fluctuate and charge too quickly for you to see the pattern.
Young's double-slit experiment makes use of two coherent light sources that are spaced closely apart. Only a few orders of magnitude above the wavelength of light are typically employed. Young's double-slit experiment, which is illustrated by a figure, contributed to our knowledge of the wave theory of light. Since the pattern is made up of parallel straight-line-shaped fringes rather than the fringes of overlapping circles, Young's interference experiment with slits results in a crisper fringe pattern than with pinholes. Compared to the wider overlap of parallel straight lines, circles have relatively fewer portions of overlap.
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If a ball i thrown horizontally with an initial velocity of 20. 0 Meter per econd from a 60. 0 meter high tower what i the horizontal velocity of the ball before it reache the ground
The horizontal velocity of the ball before it reaches the ground, where the initial velocity of 20 m/s from a 60m high tower, is 20m/s
Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
From the question given
Initial horizontal verical velocity (ux) = 20 m/s
height of tower (h) = 60m
Basically, after the ball is thrown, it becomes a projectile. It means that the acceleration along the horizontal direction is ax = 0 m/s² over the whole motion.
Now, let's use the formula
Vx = Ux + ax * t
= 20 + (0 m/s²) * t
Vx = 20 m/s
Therefore, the horizontal velocity of the ball before it reaches the ground is 20 m/s.
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Two people, one having twice the mass of the other, play tug of war with a 12 meter rope on frictionless ice. After a brief time, they meet. The heavier person slides a distance of?
A) 6m
B) 4m
C) 5m
D) 3m
Answer:
In a tug of war, the forces applied by the two people on the rope must be equal in magnitude but opposite in direction. Therefore, if one person has twice the mass of the other, the person with the larger mass will experience twice the acceleration of the person with the smaller mass.
If the heavier person has twice the mass of the lighter person, and the two people meet after a brief time, it follows that the heavier person will have traveled twice as far as the lighter person. Since the rope is 12 meters long, and the two people meet at the center of the rope, the lighter person will have traveled half the length of the rope, or 12 / 2 = 6 meters. Therefore, the heavier person will have traveled twice this distance, or 2 * 6 = <<2*6=12>>12 meters.
Since the heavier person started from the same position as the lighter person, the distance that the heavier person slid is equal to half the total distance traveled, or 12 / 2 = <<12/2=6>>6 meters. Therefore, the correct answer is (A) 6 meters.
How do we learn about what is going on in the center of our own galaxy (the Milky Way)?
A) We have learned it only recently, thanks to the great photographs obtained by the Hubble Space Telescope.
B) We cannot see the galactic center with visible or ultraviolet light, but radio and X rays from the center can be detected.
C) The gas and dust in the Milky Way prevent any type of direct observation of the galactic center, but theoretical models allow us to predict what is happening there.
D) We must look at the centers of other galaxies and hope that ours is just like others.
The things which are going on in the centre of our own galaxy (the Milky Way), We cannot see the galactic centre with visible or ultraviolet light, but radio and X-rays from the centre can be detected.
Milky Way GalaxyThe galaxy that contains our Solar System is known as the Milky Way, and its name refers to how it appears to us on Earth: a hazy strip of light in the night sky made up of stars that are too close together to be seen individually. The phrase Milky Way is a translation from Greek (galaktikos kklos), which means "milky circle," into Latin via lactea. The Milky Way is a disk-shaped structure, yet when viewed from Earth, it seems like a band. In 1610, Galileo Galilei used his telescope for the first time to separate the band of light into individual stars. Most astronomers believed that the Milky Way held all of the universe's stars until the early 1920s.
Observations by Edwin Hubble proved that the Milky Way is only one of many galaxies after the 1920 Great Debate between the astronomers Harlow Shapley and Heber Curtis.
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a simple motor is powered by a 5.00 v source and consists of a coil rotating in a uniform magnetic field. it is observed that the current in the motor decreases from 165 ma to 45.0 ma as the rotation rate goes from zero to a steady 125 rpm. determine the back emf as the motor turns at 125 rpm.
The process of building a straightforward direct current (d.c.) electric motor.
What is Electric motor?It is made out of a rectangular coil of wire positioned on a spindle so that it can move back and forth between the curved poles of a permanent magnet in the shape of a U.
The coil's two ends are soldered to a copper split ring, also known as a commutator, and its two halves, respectively. When two carbon brushes are placed in circuit with a battery and rheostat, they are made to mildly press against the commutator by means of springs, which causes the coil to revolve.
Assume that when the current is turned on for the first time, the coil is in the horizontal position. According to Fleming's left-hand rule, current will travel through the coil in the direction depicted.
Therefore, The process of building a straightforward direct current (d.c.) electric motor.
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what is b(r) , the magnitude of the magnetic field inside the toroid and at a distance r from the axis of the toroid?
the strength of the magnetic field within the toroid and at a distance of r from the toroid's axis
the magnitude of the magnetic field inside the toroid be
B(r)=[tex]\frac{\mu IN}{2\pi r}[/tex]
when only in [tex]r^{\cap}[/tex] any [tex]k^{\cap}[/tex] direction
B=[tex]\frac{\mu_{0} I }{2R}[/tex]
A magnetic field is a vector field that explains the magnetic influence on moving electric charges, electric currents, and magnetic materials. A force perpendicular to the charge's own motion and the magnetic field acts on it while the charge is traveling through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic elements like iron and attracts or repels other magnets. The three other magnetic effects of paramagnetism, diamagnetism, and antiferromagnetism also exert minute forces on "nonmagnetic" materials in a nonuniform magnetic field, albeit these forces are often so minute that they can only be measured by laboratory equipment. Electric currents, like those utilized in electromagnets, and electric fields that change over time produce magnetic fields that surround magnetized things.
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using the z table, determine the critical values for a two-tailed test when α = 0.03.
The critical value is ± 2.17 for a two-tailed test when α = 0.03.
As per the details share in the above question are as bellow,
The given details are as follow,
The two tailed test when the value of α = 0.03.
Use the z table.
We have to determine the critical value.
A mathematical table for the values of, implying the values of the normal distribution's cumulative distribution function, is known as a standard normal table. The Z-score, commonly referred to as the standard score, expresses how far away from the mean an object.
A crucial value is a point on the distribution of the null hypothesis' test statistic that designates a range of values that demand the null hypothesis be rejected. The critical or rejection zone refers to this collection. One-sided tests often have a single critical value, whereas two-sided tests typically have two critical values.
Now two tailed,
[tex]\alpha[/tex] =0.03
[tex]\alpha / 2[/tex] = 0.03 / 2 = 0.015
[tex]Z\alpha/2[/tex] = Z0.015 = ± 2.17( Using z table )
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a graph of v(t) is shown for a world-class track sprinter in a 100-m race. (see figure below).
The average acceleration of the world class track sprinter is 3.66 m/s².
Initial distance = h₀ = 0 m
Final Distance = h = 19 m
Initial speed = u = 0 m/s
Final speed = v = 11.8 m/s
We use the kinematic equation of motion, to calculate the average acceleration;
= v² = u² + 2a ( h - h₀)
= a = v² - u² / 2 ( h - h₀)
= a = 11.8² - 0² / 2 ( 19 - 0 )
= a = 3.66 m/s²
Thus, the average acceleration of the sprinter is 3.66 m/s².
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The complete question:
a graph of v(t) is shown for a world-class track sprinter in a 100-m race. (see figure below). It can reach a top speed (of about 11.8 m/s ) in the first 19.0 m of a race. what is the average acceleration of this sprinter
a 0.450 kg mass suspended from a spring oscillates with a period of 1.50 s. how much mass must be added to the object to change the period to 2.00 s?
The m" = 0.389 Kg mass must be added to the object to change the period to 2.00 s
By applying the time period formula, it is possible to calculate that 0.389 kg of mass must be added to the item in order to shift the period to 2.00 s.
A mass hung from a spring and weighing 0.500 kg oscillates with a 1.50 s period.
where K is the spring constant and m is the mass.
where K is the spring constant, and m' is the final total mass following the addition. Subtract equation (1) from equation (2).
Now change the above statement with the known terms.
To find the value of m', simplify the statement above.
m' = 0.889 Kg
Now, we can calculate the mass that must be added to the object to make the period 2.00 s:
m" = 0.889 - 0.500
m" = 0.389 Kg
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A grocery shopper tosses a(n) 8.5 kg bag of
rice into a stationary 17.4 kg grocery cart.
The bag hits the cart with a horizontal speed
of 5.5 m/s toward the front of the cart.
What is the final speed of the cart and bag?
Answer in units of m/s.
Answer:
3.1 m/sec
Explanation:
The contained in the flying bag of rice is applied to the stationary cart. Lets calculate the kinetic energy of the flying bag of rice. Kinetic energy (KE) is given by KE = (1/2)mv^2, where m is the mass and v is the velocity.
[Note: a kg*m^2/s^2 is 1 Joule]
KE(rice bag) = (1/2)(8.5kg)(5.5m/s)^2
KE(bag) = 129 Joules
When the bag hits the shopping cart, some of the energy tis transferred to the cart. We aill assume no energy in lost in the collision (conservation of energy). The kinetic energy is now contained in a body with a total mass of 25.9 kg (rice bag plus cart).
Use the kinetic energy expression again, using the same KE from the rice bag, but with a new mass.
KE = (1/2)mv^2
129 Joules = (1/2)(26.9 kg)v^2
129 kg*m^2/s^2 = (1/2)(26.9 kg)v^2
v^2 = (129 kg*m^2/s^2)/(12.95 kg)
v^2 = 9.96 m^2/s^2
v = 3.12 m/s (3.1 m/2 with 2 sig figs)
3.12 m/s will be the velocity of the grocery cart and rice bag. [That's 6.7 miles/hr, for the non-metric inclined]
One object has twice as much mass as another object. The first object also has also twice as much...
a. velocity
b. gracitational acceleration
c. inertia
d. all of these
Answer: (c) inertia
Explanation: Mass is directly proportional to inertia. Mass is not related to velocity, and the gravitational acceleration of all objects a given distance from the same massive body is the same. This is tricky, as the force of gravity (weight) is larger on heavier objects, but one must remember that weight is calculated by multiplying an object's mass by g. Option b is only considering g.
1) A 2.0 kg steel block is placed on a steel table as shown below. Force F is applied to the block to the right.
a) Determine the normal force acting on the block.
Answer:
if g=-10m/s² then the normal force is 20N
if g=-9.8m/s² then the normal force is 19.6N
Explanation:
The force due to gravity (or weight) is mass times the acceleration due to gravity.
I am going to define up as positive so gravity will be negative.
On earth the acceleration due to gravity is -9.8m/s²
We sometimes round this to -10m/s² to make the math easier.
I will do it both ways.
so we have a mass of 2kg
2kg(-10m/s²)
so the force due to gravity is -20N
because the block is not falling through the table, the table must be pushing back with the same amount of force, but in the opposite direction so we change the sign.
using -10m/s² for g, we get a normal force of 20N (Newtons)
if we use -9.8m/s², we have 2kg(-9.8m/s²)
and a force due to gravity of -19.6N
and when we flip the sign we get a normal force of 19.6N
Hope this helps!
which function can be used to find the velocity at the bottom of the pendulum released from the same angle for any period, p?
The function that can be used to find the velocity at the bottom of the pendulum released from the same angle for any period, p is v = π√(L/g). The correct option is B.
This equation can be used to calculate the velocity at the bottom of a basic pendulum (when it hits its lowest point). In the equation, v stands for velocity, L for pendulum length, and g for gravitational acceleration.
The length of the pendulum and the acceleration brought on by gravity both affect the velocity at the bottom of the pendulum.
We may determine the link between these variables by taking the square root of the ratio L/g, which leads to the right equation v = π√(L/g).
The velocity at the bottom of a pendulum launched from the same angle can be determined using this equation for any period, p.
Thus, the correct option is B.
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Your question seems incomplete, the probable complete question is:
which function can be used to find the velocity at the bottom of the pendulum released from the same angle for any period, p?
A) v = 2π√(L/g)
B) v = π√(L/g)
C) v = (2π√L)/p
D) v = (π√L)/p
Howard i moving a 90 kg wooden crate from one ide of hi office to the other. To accomplih thi, he tie a rope around hi wait and begin to walk, o that the crate i dragged horizontally acro the floor. If the coefficient of friction between the crate and the floor i 0. 159, what force mut Howard apply to to the rope to move at a contant peed?
The force exerted by Howard on the rope to make it move at a constant speed is 140.24 N.
The force that Howard must exert on the rope to move at a constant speed is calculated by applying Newton's second law of motion as follows:
F - Ff = ma
F: the applied force
Ff: the frictional force
m: the mass of the crate's mass
a: the acceleration of the crate (at a constant speed, acceleration: a = 0)
F = Ff
F = μmg
Given in question
Friction coefficient: μ = 0.159Gravity speed: g = 9.8 m/sCrate mass : m = 90 kgF = μmg
F = 0.159 x 90 x 9.8
F = 140.24 N
Then the force Howard exerts on the rope to move at a constant speed is 140.24 N
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What is the magnitude of the force needed to keep a 60.-newton rubber block moving across level, dry asphalt in a straight line at a constant speed of 2.0 meters per second?
The magnitude of the force needed to keep the block moving at a constant speed is 60 N.
his is the same as the weight of the block. This is because the only force acting on the block is gravity. As the block is moving at a constant speed, the force of friction is equal to the force of gravity. This means that the magnitude of the force needed to keep the block moving is equal to the weight of the block, which is 60 N. To calculate this, we used the equation F = ma, where F is the force, m is the mass of the block, and a is the acceleration, which is 0 in this case. This gave us the equation F = m x 0, which is simplified to F = 0, meaning the magnitude of the force needed is 0, which is equal to the weight of the block, which is 60 N.
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a uniform metal beam of mass and length is supported at each end. resting on this beam is half of an identical beam (the black dots denote the centers of mass of each beam). what is the magnitude of the vertical force applied by the support at the right end of the bottom beam?
The magnitude of the vertical force applied by the support at the right end of the bottom beam is -(F_weight).
To determine the magnitude of the vertical force applied by the support at the right end of the bottom beam, we can use the principle of static equilibrium. This principle states that in a static system (one that is not accelerating), the sum of the forces and the sum of the torques must both be zero.
Since the beam is in static equilibrium, the sum of the forces acting on it must be zero. There are two forces acting on the beam: the weight of the beam, which acts downward, and the force applied by the support at the right end, which acts upward. The magnitude of the vertical force applied by the support can be calculated as follows:
F_support = -F_weight
where F_support is the magnitude of the force applied by the support and F_weight is the magnitude of the weight of the beam.
The weight of the beam is given by the equation:
F_weight = m × g
where m is the mass of the beam and g is the acceleration due to gravity (9.81 m/s²).
To determine the mass of the beam, we need to find the mass of the entire beam and then divide it by 2, since only half of the beam is resting on the bottom beam. The mass of the entire beam can be calculated using the equation:
m = ρ × A × L
where ρ is the density of the metal, A is the cross-sectional area of the beam, and L is the length of the beam.
Plugging the values for m, g, and F_weight into the equation for F_support gives us the following:
F_support = -(m × g) = -(F_weight)
Solving for F_support gives us the magnitude of the vertical force applied by the support at the right end of the bottom beam.
Note that this calculation assumes that the beam is uniform, meaning that its density, cross-sectional area, and length are constant along its entire length. If the beam is not uniform, additional calculations will be needed to determine the force applied by the support.
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A 1300kg truck is pulling a 600kg trailer to the right by generating a 420N force. The truck is experiencing a 600N drag and the trailer experiences 340N drag. Neglect any friction impeding the motion and the mass of the cable.
How many forces are acting on the trailer?
How many forces are acting on the truck?
Are the forces on the system balanced?
What is the mass of the system?
What is the magnitude of the net force on the system?
What is the magnitude of the system's acceleration?
Describe the system's speed:
(increasing/decreasing/constant)
The number of forces acting on the trailer is 2.
The number of forces acting on the truck is 2.
The forces on the system are not balanced
The mass of the system is 1,900 kg.
The magnitude of the net force on the system is 520 N.
The magnitude of the system's acceleration is 0.27 m/s².
The speed of the system is decreasing towards to the left.
How many forces are acting on the trailer?The number of forces acting on the trailer is calculated as follows;
force of the truckdrag force of the trailerThe number of forces acting on the truck is calculated as follows;
the drag force of the truckthe force of the truckThe net force of the system is calculated as follows;
F (net) = 420 N - (600 N + 340 N)
F (net) = - 520 N
The mass of the system = 1300 kg + 600 kg = 1,900 kg
The acceleration of the system is calculated as follows;
F (net) = ma
where;
m is the total mass of the systema is the accelerationa = F (net) / m
a = -520 / 1900
a = -0.27 m/s²
Thus, since the acceleration of the system is negative, the speed of the system is decreasing towards to the left.
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A solar cell is charging a battery what is the energy
A solar cell is charging a battery, here electrical energy is converted into chemical energy.
What is solar cell?Solar cells are semiconductor devices that utilize sunlight to generate energy. They go through the same manufacturing and processing steps as computer memory chips. The main component of solar cells is silicon, which absorbs the photons that the sun's beams emit. The method was first identified in 1839.
A photoelectric cell is a type of device whose electrical properties, such as current, voltage, or resistance, change in response to light. The foundation of photovoltaic modules, sometimes referred to as solar panels, are solar cells.
The photovoltaic effect, which underpins solar cell operation, states that when light of a specific wavelength is shone on semiconductors, free electrons are generated.
Here in the case of solar cell for charging the battery electrical energy is converted into chemical energy.
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Please help: "A runner moves 2.38 m/s north. She accelerates at 0.310 m/s² at a -62.0° angle. How many seconds later is she running directly east?" Thanks!
According to equations of motion, we get after 8.70 seconds she running directly east.
Which are the 3 equations of motion?Three equations of motion, commonly referred to as the laws of constant acceleration, exist for uniform acceleration. In order to derive the components such as displacement(s), velocity(initial and final), time(t), and acceleration(a), these equations are used.These are the three equations:
v = v₀ + ats = v₀ t + ½at. v= v₀ + 2as.Given :
v₀ = 2.38 m/s
v = 0 m/s
a = 0.310 sin (-62.0°) m/s²
to find time t :
v = at + v₀
0 m/s = (0.310 sin (-62.0°) m/s²) t + (2.38 m/s)
t = 8.70 s
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the distance to the cosmological horizon depends on (a) the age of the universe. (b) the number of galaxies in the universe. (c) the location of the outer edge of the universe.
The distance to the cosmological horizon depends on:
A. The age of the universe.
Distance is the numerical or every so often qualitative size of how some of the distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.
The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.
It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.
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in a cathode ray tube, electrons flow from the negatively charged cathode to the positively charged anode. cathode ray tubes may be small and compact, but they typically must be plugged in to function. the flow of electrons within this tube is:
They are little, but they usually need to be charged in to work. Within this tube, the flow of electrons occurs on its own.
Is being impulsive a good thing?The advantages of spontaneity. Instead of racing from one planned process to the next, it can be highly healthy for our mental health to be open to unplanned happenings and give our minds space to think.
Is spontaneity a quality of the personality?People with spontaneous personalities tend to be somewhat unpredictable at work and like to act or say whatever feels right at the time. A stand-up comedian is a great example of someone who always seems to be able to take the punches and handle whatever come their way.
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one coulomb is defined as the amount of charge that passes a point in a wire in 1 second when a current of 1 ampere is flowing through the wire group of answer choices true false
True, One coulomb is defined as the amount of charge that passes a point in a wire in 1 second when a current of 1 ampere is flowing through the wire.
An electric current is a circulation of charged particles, including electrons or ions, shifting through an electrical conductor or space. Its miles are measured because of the net fee of drift of electric fee through a floor or into a managed extent.
The current is one of the most important and essential elements within electric and electronic technology. The contemporary flowing in a circuit may be utilized in an expansion of ways from generating warmness to inflicting circuits to replace, or information to be saved in an included circuit.
Current is decided by the number of electrons passing through a cross-section of a conductor.
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What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s^−1?
The minimum work required to get the cylinder rolling without slipping at a rotational speed of 20 s-1 is 1.04 kg-m2/s2.
The torque required to rotate a solid cylinder without slipping is given by:
τ = Iα
Where I is the moment of inertia of the cylinder, and α is its angular acceleration.
The moment of inertia of a solid cylinder is given by:
I = mr2
Where m is the mass of the cylinder, and r is its radius.
Plugging in the values, we get:
I = (52 kg)(0.1 m)2 = 0.052 kg-m2
The angular acceleration is given by:
α = ω/t
Where ω is the angular velocity and t is the time taken to reach the desired angular velocity.
Plugging in the values, we get:
α = (20 s-1)/t
Since we do not know the time taken to reach the desired angular velocity, we will assume that it is 1 second.
Plugging in the values, we get:
α = (20 s-1)/1 s = 20 rad/s2
Now, we can calculate the torque required to rotate the cylinder without slipping:
τ = Iα = (0.052 kg-m2)(20 rad/s2) = 1.04 kg-m2/s2
Finally, we can calculate the minimum work required to get the cylinder rolling without slipping:
W = τθ
Where θ is the angular displacement. Since we do not know the angular displacement, we will assume it to be 1 radian.
Plugging in the values, we get:
W = (1.04 kg-m2/s2)(1 rad) = 1.04 kg-m2/s2
Hence, the minimum work required to get the cylinder rolling without slipping at a rotational speed of 20 s-1 is 1.04 kg-m2/s2.'
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Complete question:
A solid 52-kg cylinder has a radius of 0.10 m.What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s^−1?
Two objects attract each other with a gravitation force of magnitude 3.80 x 10-8 n when separated by a distance of 0.350 m. if the difference in mass of the objects is 7.50 kg, what is the mass for each of these objects?
Two objects attract each other with a gravitation force of 3.80 x 10-8N when separated by a distance of 0.350 m. if the difference in masses is 7.50 kg, the mass of these objects is 2.1kg and 5.4kg
Given the mass of first object = m1
the mass of second object = m2
Gravitational force (Fg) = 3.80 x 10-8N
Objects separated by a distance (d) = 0.350m
Difference in mass of objects (m1-m2) = 7.50kg
Let mass of first object (m1) = 7.50+m2
The formula for gravitational force of attraction between two bodies is:
F = Gm₁m₂/d²
here G is the gravitational force constant and is equal to 6.67 * 10⁻¹¹ Nm²Kg⁻²
3.80 x 10-8N = 6.67 * 10⁻¹¹ Nm²Kg⁻² x (7.50+m2) x m2/( 0.350m)^2
46.55 x 10-10 / 6.67 * 10⁻¹¹ = m2^2+7.50m2
m2^2+7.50m2-69.7 = 0
m2 = 5.4 then m1 = 7.5-5.4 = 2.1
Hence the mass of first object is 2.1kg
The mass of second object = 5.4kg
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explain why the ac automatically turns on when you use the defroster, even when turning the temperature to hot.
This is typical conduct. The air is dehumidified by turning on the A/C system, which defrosts the windshield. Without it, problems would arise as a result of your breath freezing on the inside of the windshield.
What is an AC system?
Air conditioning (often referred to as AC, A/C or air con) is a system used to cool down the temperature in an inside space by removing the existing heat and moisture from the room. Essentially, they work by taking warm air into a system and dispersing cold air, but there is much more to this process.
The different AC types are as follows: Central Air Conditioner. Ductless Mini-Split.
Central Air Conditioner.
Ductless Mini-Split.
Window Air Conditioner.
Portable Air Conditioner.
Floor Mounted Air Conditioner.
Smart Air Conditioner.
Geothermal Air Conditioning System.
Hybrid / Dual Fuel Air Conditioner.
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how does the internal energy of the ice and water mixture change if the temperature does not rise while the ice is melting?
a. It decreases, because you need to use energy to make freezer run; but ice melts spontaneously
b. no enough information to determine
c. it increases, because it takes more energy for water molecules to be disordered than to be ordered
d. it remains the same because both are at the same temperature
Option-d). it remains the same because both are at the same temperature. If the temperature does not increase while the ice melts, the internal energy of the ice and water mixture changes.
A temperature is a unit of hotness or coldness that can be described in terms of a variety of arbitrary scales. It also indicates the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature). Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a considerably higher temperature than a burning match, but it has a far larger total heat energy than a match. As opposed to extensive qualities like mass or volume, which are reliant on the amount of stuff being studied, the temperature is an intensive attribute, just like pressure or density.
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about how often is it estimated that an asteroid or comet impacts earth with sufficient energy to cause mass extinction?
It is estimated that an asteroid or comet impacts the Earth with sufficient energy to cause mass extinction about once every few hundred million years.
Mass extinction is an event in which a rapid and widespread decrease is happening to the biodiversity on Earth. In it, all or at least 75% of the world's species died at a much faster rate than they are replaced in less than 3 million years.
There are several things that can cause a mass extinction event, ranging from anoxia, climate change, and volcanism, human activity, to an impact caused by another celestial body, such as an asteroid or comet. Each cause has its own probability of happening.
It is most likely that the latest mass extinction, the Cretaceous-Paleogene extinction where most of the dinosaurs went extinct, was caused by a meteoric impact. It happened around 66 million years ago.
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