There are 50 workers onsite at a large construction project. Six of them are left-handed, and the rest are not. Suppose that the project manager randomly selects 222 workers (without replacement).
What is the probability that NEITHER of the workers selected are left-handed?
Answers
Answer 1
Answer: 88%
Explanation:
6 out of 50 as a percentage is 12.00% out of 100.00%
So 100.00% Subtracted by 12.00% equals 88.00% or 88%