There are 50 workers onsite at a large construction project. Six of them are left-handed, and the rest are not. Suppose that the project manager randomly selects 222 workers (without replacement).
What is the probability that NEITHER of the workers selected are left-handed?

Answers

Answer 1

Answer: 88%

Explanation:

6 out of 50 as a percentage is 12.00% out of 100.00%

So 100.00% Subtracted by 12.00% equals 88.00% or 88%


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