The weight of a person on Earth is 67.0 N. If the gravitational acceleration on the moon is 1.62 m/s2, calculate the person’s weight on the moon.
Group of answer choices

A) 56.0 N

B) 11.0 N

C) 108 N

D) 4.00 N

Answers

Answer 1

Answer:

[tex] \large{ \boxed{ \tt{b) \: 11.0 \: N}}}[/tex]

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The Weight Of A Person On Earth Is 67.0 N. If The Gravitational Acceleration On The Moon Is 1.62 M/s2,

Related Questions

Block X and Y are attached to each other by a light rope and can slide along a horizontal

surface. Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of

friction on blocks X and Y is 8.0 N and 4.0 N respectively. Find the action-reaction forces

that the blocks exert on each other if an applied force of 40 N [right] acts on block per the

illustration below




please answer asap

Answers

the action-reaction forces that the blocks exert on each other will 13 N and 22N

Force on a Horizontal Plane

Force is the product of mass and acceleration. There will be constant acceleration on both object X and Y.

Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,

We are given that:

Mass of block X = 10 KgMass of block Y = 5 KgApplied force = 40 NMagnitude of friction on X block = 8NMagnitude of friction on Y block = 4 N

With the use of the formula below,

F - [tex]F_{r}[/tex] = ma

Where

F = force applied[tex]F_{r}[/tex] = frictional forcem = massa = acceleration

The acceleration will be;

40 - (8 + 4) = (10 + 5)a

40 - 12 = 15 a

28 = 15a

a = 28/15

a = 1.8667 m/[tex]s^{2}[/tex]

The tension between the two blocks will be

Force applied-frictional force on X-tension = mass of X × acceleration

That is,

F - [tex]F_{r}[/tex] = ma

40-8-T = 10 × 1.8667

32 - T = 18.667

T = 32 - 18.667

T = 13.33 N

The opposite reaction will be

F - 8 = 10 x 1.8667

F - 4 = 18.67

F = 18.67 + 4

F = 22.67 N

Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N

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A sky diver, mass 90 kg, reaches a terminal velocity of 60 m/s. What is the approximate magnitude of the force of air resistance?.

Answers

The approximate magnitude of the force of air resistance is 882 N

Data obtained from the questionMass (m) = 90 KgTerminal velocity = 60 m/sForce (F) =?

How to determine the force

The magnitude of the force of air resistance can be obtained as illustrated below:

Mass (m) = 90 KgAcceleration due to gravity (g) = 9.8 m/s²Force (F) =?

F = mg

F = 90 × 9.8

F = 882 N

Thus, approximate magnitude of the force of air resistance is 882 N

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The deflection angle of the laser beam as it exits the prism is 22. 6º. If the prism had been made of glass instead of polystyrene plastic, what would the deflection angle have been?.

Answers

Need help on this as well!!!!

10) What is the total energy of a 450-g mass that is attached to a horizontal spring with a force constant of 260 N/m and oscillates along a frictionless horizontal surface with amplitude of 8.0 cm

Answers

Answer:

E = 1/2 * k x^2 is the energy stored in the spring

E = 1/2 * 260 N/m * .08^2 m = .832 Joules

The _________ system produces electrical power while the engine is running to operate all the electrical components and recharge the battery

Answers

Answer:

kinetic energy and potential and electrical energy

Explanation:

it will be need to maintain the motion of the vehicle and produce electrical energy

A driver jumped from a top of a 15-meter-high cliff down to the water below. if he moved with an initial horizontal velocity of 10m/s

a.) Find his Vx or horizontal Velocity

b.) Calculate the time it took him to reach the water

c.) How many meters will his range or horizontal displacement

Given:

Formula:

Solution:

Final Answer:
.

Hi please help I need it bc I'm still confuse

Answers

(a) The initial horizontal velocity of the driver is 10 m/s.

(b) The time taken for him to reach the water is 1.75 s.

(c) The horizontal displacement is 17.5 m.

Horizontal velocity of the driver (Vx)

The initial horizontal velocity of the driver is given as 10 m/s.

Time of motion of the driver

h = vy(t) + ¹/₂gt²

where;

vy is initial vertical velocityt is time of motionh is height of fall

h = 0 +  ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 15 / 9.8)

t = 1.75 s

Horizontal displacement of the driver

X = Vx(t)

X = 10 x 1.75

X = 17.5 m

Thus, the initial horizontal velocity of the driver is 10 m/s, the time of motion is 1.75 s and the horizontal displacement is 17.5 m.

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what are the types of waves

Answers

Waves come in two kinds, longitudinal and transverse. Transverse waves are like those on water, with the surface going up and down, and longitudinal waves are like of those of sound, consisting of alternating compressions and rarefactions in a medium

i hope this helps :)

A 12.5 g clothesline is stretched with a tension of 22.1 n between two poles 7.66 m apart. the frequency of the fundamental and the second harmonic are 7.60 hz and 15.2 hz respectively.

Answers

(a) Fundamental frequency of clothesline is 6.98Hz.

(b) Frequency of second harmonic is 13.98Hz.

The wave velocity expression is,

        v = √T / √μ

here, T is tension μ is mass per unit length

     v = √22.1 / √(12.5×10⁻³/7.66)

     v = 116.37 m/s

    For the fundamental frequency,

                  v = fλ

     116.37 m/s= 7.6 ×λ

         λ = 15.31 m

     For the second Harmonic,

          λ₂=  v/ f₂ = 116.37 / 15.2 = 7.66 m

     Now consider mass is increased

             μ= 14.8 × 10⁻³ / 7.66

                v = √T / √μ

                v = √22.1 / √14.80 × 10⁻³/7.66

                v = 106.95 m/s

          Fundamental harmonic,

                f₁ = v/λ₁ = 106.95 / 15.31 = 6.98 Hz

                f₂= v/ λ₂ = 106.95 / 7.65 = 13.98 Hz

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[Your question is incomplete, but most probably your full question was-

a) What is the frequency of the fundamental harmonic for a clothesline with a mass of 14.8 g?

(b) What is the frequency of the second harmonic for a clothesline with a mass of 14.8 g?]

What is the current in a 10 ohm resistor ?

Answers

Answer:

c option 22.0A

Explanation:

V=IR

I=R/V

Pls give full explanation!

Answers

1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²

2. The part that shows the body is coming to rest the last 2 hours (CDF)

3. The distance travelled in the first 2 hours is 40 Km

1. How to determine the accelerated motion

Acceleration is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

From the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.

The acceleration can be obtained as followed:

Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = ?

a = (v – u) / t

a = (40 – 0) / 2

a = 20 Km/h²

2. How to determine the part showing the body is coming to rest

From the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.

3. How to determine the distance travelled in the first 2 hours Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = 20 Km/h²Distance (s) = ?

v² = u² + 2as

v² = 2as

s = v² / 2a

s = 40² / (2 × 20)

s = 40 Km

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4 . A negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it . ( a ) what is the unknown charge ( magnitude and sign ) ? ( b ) what are the magnitude and direction of the force that the unknown charge exert charge exerts on the -0.450 charge ?​

Answers

(a) The unknown charge kept at distance 0.250m directly below  -0.450 charge is  2.315 x 10⁻¹² C.

(b) The magnitude of the force is 29.16 x 10¹² N.

What is electrostatic force?

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .

In equation of the magnitude of force, only the magnitude of charges are taken.

Substituting the values into the expression ,we get the charge

0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.

b)Let the unknown charge be  0.450C to exert on -450C.

Substituting the values into the expression ,we get the electrostatic force

F = kq₁q₂/r²

F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the force is 29.16 x 10¹² N.

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write any three uses of solution in our daily life ​

Answers

Answer:

इअग्सिव्ह्ह्व्य्वुव्व्ह्विहेधेइएह

Explanation:

ह्य्स्स्येउ?स्य्ग्स्झ्स

do banked curves help car make turns more softly​

Answers

Bank turned help drivers maintain speed they keep the car from skidding

Answer:

yes

Explanation:

banked curve :

is a road that looks like the top part of a race track

its looks elevated

often seen in bicycle race track (velodrome)

Banking the curve can help keep cars from skidding. When the curve is banked, the centripetal force can be supplied by the horizontal component of the normal force.

sfuca

what is forward and downward speed

Answers

Forward and downward speed are referred to as acceleration and deceleration respectively.

What is Acceleration?

This is the rate at which an object gains speed with respect to time with its unit being meter per second square(m/s²).

Objects in constant speed are said to have a uniform motion. The downward speed is known as deceleration which involves the object losing speed to return to a state of rest.

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A student is conducting an experiment that involves adding hydrochloric acid to various minerals to detect if they have carbonates in them. the student holds a mineral up and adds hydrochloric acid to it. the acid runs down the side and onto the student’s hand causing irritation and a minor burn. if they had done a risk assessment first, how would this situation be different?

Answers

If they had done a risk assessment first "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it"

What is hydrochloric acid?

An aqueous solution of hydrogen chloride HCl that is a strong corrosive irritating acid, is normally present in dilute form in gastric juice, and is widely used in industry and in the laboratory.

Maintain a safe distance between your hands and your body, mouth, eyes, as well as a face when utilizing lab supplies and chemicals.

If they had done a risk assessment first "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it"

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A wave traveling in a string has a wavelength of 35 cm, an amplitude of 8. 4 cm, and a period of 1. 2 s. What is the speed of this wave?.

Answers

0.29 m/s is the speed of this wave.

How can we determine a wave's speed?

Given: The wave's traveling wavelength is () = 35 cm

The wave's period (t) is 1.2 seconds.

The wave's frequency is 0.833 Hz.

We must ascertain a wave's wave speed.

Formula for wave speed is 35 x 0.833 (wavelength x frequency).

= 29.167 cm/sec

= 0.29 m/sec

As a result, the wave's speed is 0.29 m/s.

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An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. it flies up to its nest in a tree at a height of 25 m. how much gravitational potential energy did the eagle gain? 221 j 882 j 1103 j 1323 j

Answers

882J of gravitational potential energy is gained by the eagle.

Here, we have been provided with data-

mass, m = 4.5 kg

height, h = 25 m

We have to find the gravitational potential energy.

In the question, it is given that the eagle is at a height of 5m and it flies from there 20 m more to reach its nest.

So, gravitational potential energy is given as

P.E = m x g x h

P.E = 4.5 × 9.8 × 20

P.E =  882J

Thus, the correct option is (b).

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Answer:

b

Explanation:

its b

A driver, traveling at 22.0 m/s, slows down her car and stops. What work is done by the friction force against the wheels if the mass of the car is 1500 kg? Group of answer choices -3.6 x 105 joules None of the above 3.6 x 106 joules -4.5 x 106 joules 4.5 x 105 joules

Answers

-3.6× 10^5J is the Work done by friction force

Work done = force × distance

v^2 = u^ +2as

u= 22m/s

a =10m/s^2

When the car stops the final velocity (v) =0

0= 22^2 +2×10×s

s = -484/20

s =-24.2m

Work done = force × distance

Force = mass × acceleration

Work done = 1500×10× -24.2

= -3.6×10^5J

Hence the Work done is -3.6×10^5J

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What is the amount of matter in a substance?​

Answers

Answer:

mass

Explanation:

Mass (M) is the measure of the amount of matter in an object. Mass is measured in grams (g). Mass is measured on a balance by comparing the object against other objects with known masses.

Answer:

Mass is the amount of matter in a substance

Anybody else play genshin??

I’m bored and don’t feel like doing hw (also my ar is 24 )

Answers

Answer:

no sorry

Explanation:

Answer:

yes i play genshin

Explanation:

ignore how this is a year late...what server r u on ?im on america and europe!!!!!!!!!!!!(≧∇≦)

A bar is 20 cm long. a 100 g mass is placed on one end and a 150 g mass on the other. where is the balance point of the bar.

Answers

The balance point of the bar from the 100 g mass is 12 cm.

Balanced point of the bar

Apply principle of moment as follows;

Let the balance point from 100 g mass = x

Clockwise moment = anti clockwise moment

100x = 150(20 - x)

100x = 3,000 - 150x

250x = 3000

x = 3000/250

x = 12 cm

Thus, the balance point of the bar from the 100 g mass is 12 cm.

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A moving car has a kinetic energy of 0.3 MJ. If the car's speed decreases two times, its new kinetic energy will be

Answers

New kinetic energy:

If the initial kinetic energy of a car is 0.3 MJ and the speed of the car decreased two times then the new kinetic energy will be 0.075 MJ.

The calculation for kinetic energy:

Step-1:

It is given that the car has a kinetic energy of 0.3 MJ. It is required to find the new kinetic energy when the car's speed decreases two times from its initial speed.

Let the mass of the car is m and the initial speed of the car is v.

It is known that the kinetic energy is calculated as,

[tex]\text{K.E}=\frac{1}{2}\times \text{mass}\times\text{speed}^2[/tex]

Therefore the initial kinetic energy is the car is,

[tex]\text{K.E}_1=\frac{1}{2}\times \text{m}\times\text{v}^2[/tex]

Step-2:

The speed of the car is decreased two times. Thus the speed becomes v/2. Therefore the final kinetic energy is the car is,

[tex]\text{K.E}_2&=\frac{1}{2}\times \text{m}\times(\frac{v}{2})^2\\&=\frac{1}{4}\times\frac{1}{2}\times \text{m}\times\text{v}^2\\&=\frac{1}{4}\times\text{K.E}_1\\&=\frac{1}{4}\times {0.3}\text{ MJ}\\&=0.075 \text{MJ}[/tex]

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A pendulum can be simply made of a suspended string tied to a weight. If the length of string is measured to be 1 m and the weight is measured to be 0.5 kg, determine its period of oscillation and its frequency of oscillation. Does its period depend on the weight tied to the string?

Answers

The time period of the pendulum is 2 sec, and the frequency will be 0.5 and will on depend on weight of the object.

The time period of a basic pendulum is defined as the time it takes to complete one full oscillation and is indicated by the letter "T".

This concept of frequency leads to the simplest frequency formula

Frequency = 1 / T.

T signifies the time it takes to complete one wave cycle in seconds, while f denotes frequency.

The formula for time period of simple pendulum is

Time Period = 2π√(l/g)

As we can see there is no mass term in the formula, Hence we can say that the time period of simple pendulum will not depend on mass or weight of the object tied to the string.

We have given length as 1 m

Time Period = 2π√(1/9.8)

Time Period = 2π×0.319

Time Period = 2 seconds

Time of the Simple Pendulum is 2 seconds.

Frequency = 1 / Time period

Frequency = 1 / 2

Frequency = 0.5 1/second

Frequency of the Simple Pendulum is 0.5

So we can conclude that the Time period of Simple pendulum is 2π√(l/g) and as we can see there is no term of mass, means the simple pendulum will not be depend on mass or weight. The time period came out to be 2 seconds and the frequency came out to be 0.5.

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Only 25% of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter

Answers

Answer: Only 25% of the intensity of a polarized light wave passes through a polarizing filter. Then the angle between the electric field and the axis of the filter will be 60 degrees.

Explanation: To find the answer of the problem given, we have to know about the Malu's law of polarization.

What is Malu's law of polarization?This law states that, when a beam of completely polarized light is passed through an analyzer, then then intensity I of the transmitted light varies directly as the square of the angle [tex]\alpha[/tex] between the transmission direction of the polarizer and the analyzer.The expression for this law will be,

                                         [tex]I=I_0cos\alpha[/tex]

Where, I₀ is the maximum intensity of the transmitted light through the polarizer.How to solve the problem?From the question, it is clear that, the 25% of the intensity of a polarized light wave passes through the filter.

                                        [tex]\frac{I}{I_0} =0.25\\[/tex]

Thus, the angle between electric field and the axis of the filter is,

                                        [tex]cos^2\alpha =0.25\\cos\alpha =\sqrt{0.25} =0.5\\\alpha =cos^-1(0.5)=60 degrees[/tex]

Thus, we can conclude that, the angle between the electric field and the axis of the filter will be 60 degrees.

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A 4.30 kg sign hangs from two wires. The
left wire exerts a 31.0 N force at 122°.
What is the magnitude of the force exerted
by the second wire?
F₁"
*W
magnitude (N)
F2
Enter

Answers

The magnitude of the force exerted by the second wire is 16.5 N.

Resultant of the forces

Apply cosine rule to determine the force on the second wire;

W² = F₁² + F₂² - 2F₁F₂ cos(θ)

where;

W is the suspended weightθ is the angle between the two wires

(4.3 x 9.8)² = 31²  +  F₂²  - 2(31) F₂(cos 122)

1775.78 = 961  +  F₂²  + 32.85F₂

814.78 = F₂²  + 32.85F₂

F₂²  + 32.85F₂ - 814.78 = 0

Solve the quadratic equation using formula method;

F₂ = 16.5 N

Thus, the magnitude of the force exerted by the second wire is 16.5 N.

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A sled having a certain initial speed on a horizontal surface comes to rest after traveling 20 m. If the coefficient of kinetic friction between the object and the surface is 0.20, what was the initial speed of the object

Answers

The initial speed of the object was 6.26 m/s.

Acceleration of the sled, a = -g*μk

= -9.8*0.2

= -1.96 m/s^2

Let u is the initial speed and v is the final speed.

Applying, v^2 - u^2 = 2*a*d

0^2 - u^2 = 2*(-1.96)*10

u = sqrt(2*1.96*10)

= 6.26 m/s

The kinetic friction coefficient μok is the ratio of the friction force to the normal pressure experienced by a body moving on a dry, non-easy floor. The determination of μok may be achieved quite appropriately through an alternative creative mechanism described with the aid of Timoshenko

The coefficient of friction (fr) is quite a number that is the ratio of the resistive force of friction (Fr) divided with the aid of the everyday or perpendicular force (N) pushing the items collectively. it is represented by the equation: fr = Fr/N.

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What type of resistance training equipment has a fixed range of motion? Chains Resistance bands Free weights Weight machines

Answers

Chains are the type of resistance training equipment which has a fixed range of motion.

What is Resistance?

This is a type of force which restricts the motion of an object thereby slowering it down.

Chains help to build stamina and power though varying the loads in a fixed range of motion. This is why it was chosen as the most appropriate choice.

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How do the accelerations of the rifle and bullet compare?

Answers

Answer:

The acceleration of the rifle equals the force that the bullet exerts on the rifle divided by the mass of the rifle. The two forces are equal, but since the mass of the rifle is much greater than the mass of the bullet, the acceleration of the rifle is much less than the bullet's acceleration.

A backpack has a mass of 8 kg. It is lifted and given 54.9 J of gravitational
potential energy. How high is it lifted? Acceleration due to gravity is g = 9.8
m/s2

Answers

The height is 0.70 meters

The formula for gravitational potential energy is

= mgh

m= mass, g= acceleration due to gravity, h= height

54.9= 8 × 9.8 × h

54.9= 78.4h

h= 54.9/78.4

= 0.70 meters

Hence the height at which the bacpack was lifted is 0.70 meters


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Answer:

its 0.7m

Explanation:

A movement that keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement? Open kinetic chain movement Lateral kinetic chain movement Dynamic kinetic chain movement Closed kinetic chain movement

Answers

A movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

What is a closed kinetic chain movement?

A closed kinetic chain movement is defined as that position where the most distal aspects of a particular extremity are fixed to the earth or another solid object.

In conclusion; a movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

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In a __________ elimination, the base extracts a proton and the leaving group leaves simultaneously. In a __________ process, the leaving group leaves ___________ the base abstracts a proton. g Can someone help me out on this problem and show work please Given f(x) = -5x + 2, determine each of the following:a) f(-1)b) f^-1(7)c) f^-1(-43) Select the correct answer. Suppose that 3 boys and 2 girls go to the theatre and occupy 5 seats in a row. In how many ways can they be seated if all 3 boys sit together? In a compare and contrast paragraph, a conclusion should: a. say that both things are the same c. both of these b. say which one is better d. none of these Please select the best answer from the choices provided A B C D find the midpoint of the segment with endpoints at (-2,1) and (0,9) using (x1+x2,y1+y2) The firm negotiates a new agreement with its workers for lower wages. The ATC curve should be __________ and the AFC curve should be __________ after the agreement goes into effect. Men and Women are two sides of a coin justify the statement in your own words ? Write an equation in slope-intercept form of the line containing the points (3,-1) and (6, 7).=x-9y=x-7y = -x +9y = 3x - 11 Which expression is equivalent to (43) (what is the following product?(27 + 36) (55 +43)? An outline severes as a bridge which two stages Write the domain and range of g using interval notation. Read the quotation from song of myself. I loafe and invite my soul, i lean and loafe at my ease observing a spear of summer grass. How do these lines reflect the poets general style?. Desarrollar por el metodo de reduccion: 1. si: { 3x+ 2y = 26 { 5x - y = 26 hallar: e= x +y Given the functions f and g below, find f(g(0)). Question 14 of 20Read this excerpt from The Grapes of WrathSome of the owner men were kind because they hatedwhat they had to do, and some of them were angrybecause they hated to be cruel, and some of them werecold because they had long ago found that one could notbe an owner unless one were cold.Which rhetorical technique does it best exemplify?A. ParallelismOB. AlliterationOC. UnderstatementOD. ConnotationSUBMIT Find the area of the shaded region. 3. What historical examples did Douglass draw upon to support his advocacy for black suffrage? 10. What is a paradox?An author or character says one thing but means something else A statement or situation that seems to be contradictory but actually presents a truthThe audience or readers knows or understands something that a character does not know An inconsistency between what the audience or reader expects and what actually happens Employees often attend trainings and read policies. They endure these, but do not internalize them. What should be your first step in getting your employees to appreciate the importance of data privacy?