Can someone help me out on this problem and show work please

This shows that if s is doubled and h tripled, then V multiplied by 12

Given the formula below expressed as:

V = s²h

If s is doubled and h tripled, the new volume will ne:

V1 = (2s)² * 3h

V2 = 4s² * 3h

V2 = 12s²h

V2 = 12V

This shows that if s is doubled and h tripled, then V multiplied by 12

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The value of x is 8 mm.

Similar Figures are the figures in which all the sides of one figure are in same ratio with the other side.

Two figures are given which are similar to each other .

When two figures are in ratio a:b then Area will be in ratio a² : b²

Area of figure 1 = 22 sq.mm

Area of figure 2 = 352 sq.mm

A1 :A2 = 22 /352

a² : b² = 1 / 16

a:b = 1/4

Therefore the bigger figure is 4 times the small figure .

The 4mm side will be 16 mm in the larger figure

The difference will be the value of x

x = 24 -16 = 8 mm

Therefore the value of x is 8 mm.

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Answer:

x = 8

Step-by-step explanation:

Similar shapes are dilations of each other using a scale factor.

As the area of both figures has been given, the scale factor that maps the green figure to the yellow figure can be calculated:

[tex]\implies \textsf{Scale factor (area)} = \dfrac{\textsf{area of yellow figure}}{\textsf{area of green figure}} = \sf \dfrac{352}{22} = 16[/tex]

Area is measured in square units. Therefore, to find the scale factor for length, square root the scale factor for area:

[tex]\begin{aligned}\implies \textsf{Scale factor (length)} & = \sf \sqrt{\textsf{Scale factor for area}} \\ & =\sf \sqrt{16}\\ & = \sf 4 \end{aligned}[/tex]

Use the found scale factor for length to find the perimeter of the yellow figure:

[tex]\begin{aligned} \sf \implies \textsf{Perimeter (yellow fig)} & = \sf \textsf{perimeter (green fig)} \times scale\:factor \\ & = \sf 26 \times 4 \\ & = \sf 104\: mm \end{aligned}[/tex]

Find the missing horizontal lengths of the yellow figure by using the corresponding length of the green figure:

⇒ 4 mm × 4 = 16 mm

⇒ 24 mm - 16 mm = 8 mm

Let the height of the yellow figure be y.

⇒ 24 + 8 + 16 + y + x + (y - x) = perimeter

⇒ 48 + 2y = 104

⇒ 2y = 56

⇒ y = 28 mm

Divide the yellow figure into two rectangles (see attachment).

To find x, sum the areas of the rectangles and equate to 352:

⇒ 224 + 16x = total area

⇒ 224 + 16x = 352

⇒ 16x = 128

⇒ x = 8

Answer:

         (8b − 1)b = 8b*b - 1*b

                        = 8b2 - b

Step-by-step explanation:

Hence the expression (8b − 1)b=8b2 - b.

The value of x in the triangle will be 30°

Let the base angles be x. The vertex angle will be:

= 2(x + x) = 4x

Since the sum of the angles in a triangle is 180°, therefore, 4x + x + x = 180°

6x = 180°

x = 180°/6

x = 30°

Therefore, the angles are 30°, 30°, and 120°. This makes up 180°.

Complete question:

In an isosceles triangle, the vertex angle is twice the sum of the base angles. Fund the angles of the triangle.

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Answer:

`1) 2.5cm, 2)1.25inches 3)2.25inches 4)1.25inches

Step-by-step explanation:

1) This is a centimeter rule, one small line represents 0.1cm and 1 long line represent 1cm, the line in between two long lines represent 0.5 cm

As you can see from A to B, is 2 cm + 0.5cm = 2.5cm.

2)This is found on the other side of rulers, inches.

1 small line represent 0.25 inches, line in between 2 long lines is 0.5 inches.

From S to T, is 1 inch + 0.25 inches = 1.25inches

3)Similar to Question 2.

Length of Pencil= 2 inches + 0.25 inches = 2.25 inches

4)This is a more detailed inch rule.

But length of heart shape = 1 inch + 0.25 inches = 1.25 inches

Answer:

See proof below

Step-by-step explanation:

Given [tex]\triangle ADE \cong \triangle CBD[/tex]

Then, [tex]\angle AED \cong \angle CFB[/tex] because corresponding parts of congruent triangles are congruent.

Since [tex]\angle AED \text{ and } \angle DEB \text{ form a linear pair}[/tex], by the linear pair postulate, [tex]\angle AED \text{ and } \angle DEB \text{ are supplementary}[/tex].

Similarly, [tex]\angle CFB \text{ and } \angle BFD \text{ form a linear pair}[/tex], so by the linear pair postulate,  [tex]\angle CFB \text{ and } \angle BFD \text{ are supplementary}[/tex].

By the Congruent supplements theorem, since [tex]\angle AED \text{ and } \angle DEB \text{ are supplementary}[/tex], [tex]\angle CFB \text{ and } \angle BFD \text{ are supplementary}[/tex], and [tex]\angle AED \cong \angle CFB[/tex] , then [tex]\angle DEB \cong \angle BFD[/tex]. (note, this is one pair of opposite angles inside quadrilateral DFBE)

Recalling that [tex]\overline {ED} \text{ bisects } \angle ADC, \text{ and } \overline {FB} \text{ bisects } \angle ABC[/tex], then, [tex]\angle ADE \cong \angle CDE[/tex], and [tex]\angle CBF \cong \angle FBA[/tex] by definition of angle bisector.

Note that [tex]\angle ADE \cong \angle CBF[/tex] because corresponding parts of congruent triangles are congruent.

Also, note that [tex]\angle EDF \cong \angle EDC[/tex] and [tex]\angle FBA \cong \angle FBE[/tex] because B, E, A are colinear, and D, F, C are colinear.

So, by the transitive property of angle congruence, [tex]\angle EDF \cong \angle FBE[/tex]  (This is the other pair of opposite angles inside quadrilateral DFBE)

So, since both pairs of opposite angles are congruent, quadrilateral DFBE is a parallelogram, by a theorem about quadrilateral properties (your book may or may not have a name for it.  It may just have a number).

The First graph does not have an initial Value

The second graph's solution is (3, -4)

A quadratic graph is a pictorial representation of quadratic functions.

It shows the relationship between a variable on the x-axis and a variable on the y-axis.

Analysis:

The First graph did not either start from the x or y-axis so it does not have an initial value.

The second graph each mark is 0.5 on both axes so the point of intersection of the two graphs is the solution of the graphs which the x- value is 3 and the y-value is -4.

Therefore (3, -4) is the solution of the graph.

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There is a significant value in the difference in the value of the car after nine years

The table of values is given as:

Years     1     2     3

Car 1 17,390 16,346.60 15,365.80

Car 2 17,500 16,500 15,500

The values of car 1 have a common ratio of 0.94; this is calculated by dividing the terms of the function

The common ratio implies that the function of car 1 is a geometric function.

The values of car 2 have a common difference of -1000.

The common difference implies that the function of car 2 is a linear function.

Car 1

In (a), we have:

Common ratio, r = 0.94

The initial value is given as:

a = 18,500

So, the function of car 1 is

f(x) = 18500 * 0.94^x

Car 2

In (a), we have:

Common difference, d = -1000

The initial value is given as:

a = 18,500

So, the function of car 2 is

f(x) = 18500 - 1000x

This means that

x = 9

So, we have:

Car 1

f(9) = 18500 * 0.94^9

f(9) = 10600

Car 2

f(9) = 18500 - 1000 *9

f(9) = 9500

10600 is greater than 9500

Hence, there is a significant value in the difference in the value of the car after nine years

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Answer:

The area of the shape is 68 cm².

Step-by-step explanation:

We have to calculate the areas of the rectangle and triangle separately, and then add them together.

• Area of rectangle = length × breadth

                                = 30 cm × 2 cm

                                = 60 cm²

• Area of triangle = [tex]\frac{1}{2}[/tex] × base × perpendicular height

                             = [tex]\frac{1}{2}[/tex] × 2 cm × 8 cm

                             = 8 cm²

Adding the areas together = 60 cm² + 8 cm²

                                             = 68 cm²

Step-by-step explanation:

the area of a parallelogram is

baseline × height

which is in our case

9 × 7 = 63 m²

Answer:

ayo give the other guy brainilest

Step-by-step explanation:

Answer:

yes , y = - 3.3x

Step-by-step explanation:

if y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation , then

k = [tex]\frac{y}{x}[/tex]

checking k for each ordered pair in the table

[tex]\frac{-6.6}{2}[/tex] = - 3.3

[tex]\frac{-9.9}{3}[/tex] = - 3.3

[tex]\frac{-13.2}{4}[/tex] = - 3.3

[tex]\frac{-16.5}{5}[/tex] = - 3.3

thus k = - 3.3

so y varies directly with x and the equation of direct variation is

y = - 3.3x

Answer:

24 km/h and 17 km/h

Step-by-step explanation:

We know that when two cyclists are traveling together, they will meet in the same time as if one cyclist with the combined speed of the two cyclists travelled the whole length. We don't know the speeds of the cyclists, so let's assign the one with the slower speed "x", and the one with the faster speed "x+7" the combined speeds is "2x+7"

Since the speed = distance / time, we can plug in the values

2x+7=205/5
2x+7=41
2x=34
x=17
We substitute x into the equation for the speed of the cyclists

Cyclist 1's speed: x, so their speed is 17 km/h
Cyclist 2's speed: x+7, so their speed is 17 + 7, or 24 km/h

Answer:

The initial value in the word problem is the output value when input value is set to zero.

Step-by-step explanation:

Answer: [tex][-3,7][/tex]

Step-by-step explanation:

The range of a function is the set of y-values.

By summing the areas of minor rectangles and triangles, the area of the irregular polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.

In this problem we have to determine the area of a irregular polygon, whose calculation is defined as a sum of the areas of triangles and rectangles. To determine the combination of squares and triangles, we need first to plot the vertices and construct the figure on a Cartesian plane.

The area of the irregular figure is:

A = (5) · (7) + 0.5 · 2² + 0.5 · (2) · (5)

A = 35 + 2 + 5

A = 42

By summing the areas of minor rectangles and triangles, the area of the irregular polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.

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The probability that the number of people who show up will exceed the capacity of the plane is 0.002607722

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

The probability that x people show up follows a binomial distribution,

[tex]P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}[/tex]

Here, n represents the number of booked people and p represents the probability that a person shows up.

Then, the probability that x people show up is:

[tex]P(x)=\frac{78!}{x!(78-x)!}*0.90^{x}*(1-0.90)^{78-x}[/tex]

So, the probability that the number of people who show up will exceed the capacity of the plane is:

P(x>76) = P(77) + P(78)

Where P(77) and P(78) are calculated as follows:

[tex]P(77)=\frac{78!}{77!(78-77)!}* 0.90^{77}* (1-0.90)^{78-77} \\ =78*0.00029969*0.10\\ =0.0023375[/tex]

[tex]P(78)=\frac{78!}{78!(78-78)!}* 0.90^{78}* (1-0.90)^{78-78} \\ =1*0.00026972*1\\ =0.00026972[/tex]

Finally, P(x>76) is:

[tex]P(x > 76) = 0.0023375 + 0.00026972\\=0.002607722[/tex]

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The value of A and B are -10x and -4 respectively.

Division involves gathering a number of expressions into smaller forms.

The quotient is represented by the expression

Quotient= Dividend /Divisor

We have the value of the Dividend from the division table given in the question

Dividend of the Operation= A

Divisor of the Operation=2

Quotient of the Operation= -5x

As we know Quotient= Dividend /Divisor

So, -5x= A/2

multiplying 2 on both sides

⇒(-5x)2= A/2*2

⇒ A= -10x

Similarly, We have the value of the Dividend from the division table given in the question

Dividend of the Operation= B

Divisor of the Operation=2

Quotient of the Operation = -2

As we know Quotient= Dividend /Divisor

So, -2= B/2

multiplying 2 on both sides

⇒(-2)2= AB2*2

⇒ B= -4

Therefore the value of A and B are -10x and -4 respectively.

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LM=XY, then LM-GH= XY - GH and this illustrates the subtraction property of equality.

It should be noted that the subtraction property of equality simply implies that when the same number is subtracted form both sides, then the two sides will still remain equal.

In this case, when LM=XY, then LM-GH= XY - GH. This illustrates the subtraction property.

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A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. An isosceles triangle is one with two equal-length sides.

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.

In ΔBAD and ΔBDC,

m∠ADB = m∠CDB {Given}

BD = BD {Common side in two triangles}

AD ≅ DC {Given}

Using the ASA postulate the two triangles are congruent. Therefore,

m∠BAD= m∠BCD.........equation 1

m∠ABD= m∠CBD

In ΔADC, AD ≅ DC {Given}, therefore, the triangle is an isosceles triangle. Thus,

m∠DAE = m∠DCE.......equation 2

Adding two of the equation 1 and 2,

m∠BAD + m∠DAE = m∠DCE + m∠BCD

∠BAC = ∠BCA

Since in ΔABC, ∠BAC = ∠BCA therefore, the triangle is an isosceles triangle, thus, AB = BC,

BE is the common side between ΔAEB and ΔCEB

Also, m∠ABD= m∠CBD

Therefore, ΔAEB ≅ ΔCEB

Now as ΔAEB ≅ ΔCEB, therefore, AE=EC,

Thus, BE is the median of the isosceles triangle ABC, and for an isosceles triangle, the median opposite to the non-common sides is the perpendicular bisector to the opposite side.

Hence, BD⊥AC.

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Answer:

[tex]f(x) = (x-12)(x-1)[/tex]

Step-by-step explanation:

So when you have a quadratic equation it can usually be expressed as: [tex]a(x-b)(x-c)[/tex] where b and x are the roots of the equation. Since it's just asking for a function whose zeroes are 12 and 1, I'm assuming it doesn't care about the stretch/compression (value of a determines that), so I'll just assume a=1. if 12 and 1 are zeroes, that means it makes one of the factors equal to 0 because is x-b = 0 then no matter the value of x-c the value of y is 0 because 0 * (x-c) will be 0. So the equation becomes [tex]f(x) = (x-12)(x-1)[/tex] plugging in 12 or 1 as x will make one of the factors 0 thus making f(x) equal to 0

Answer:

Based on the number of coins in the jar, the probability that Nina would not pick a penny or dime is a. 0.36.

The cost of the entire trip to the Cross family should they use the two cars is c. $107.07.

This can be found as:

= Number of quarters, and nickels) / (Number of quarters, nickels, dimes, and pennies)

= (13 + 18) / (13 + 25 + 18 + 30)

= 0.36

= Cost of gas to first car + Cost of gas to second car

= (450/18 x 2.49) + (450 / 25 x 2.49)

= 62.25 + 44.82

= $107.07

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Nicolai would get worth of 13958.62 in five years for an 8% rate of return.

The net gain or loss of an investment over a given period stated as a percentage of the investment's starting cost is known as a rate of return (RoR).

Any type of investment instrument, including real estate, bonds, equities, and fine art, can be subject to a rate of return.

You determine the percentage change from the start of the period to the end when computing the rate of return.

Initial amount=9500

Rate of return=8%

Amount after 5 years=[tex]9500*(1+\frac{8}{100}) ^{5}[/tex]

                                    [tex]=9500*(\frac{108}{100} )^{5}[/tex]

                                   [tex]\\=13958.62[/tex]

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Answer:

Step-by-step explanation:

The is a factor of -3 which makes a vertical stretch on the y-axis of the original f(x) equation making a new g(x) equation.

g(x) = a * f(b(x-h)) + k

a - vertical stretch/shrink y-axis

b - horizontal stretch/shirink x-axis

h - horizontal shift right/left

k - vertical shift up/down.

Desmos

Answer:

D: 4(2a+3)=8a+3

Step-by-step explanation:

4x2a = 8a and 4x3 = 12

Answer:

just saying this so other can get brainliest

Step-by-step explanation:

d

Considering the given exponential function, we have that:

An exponential function is modeled by:

[tex]y = ab^x[/tex].

In which:

When x = 0, y = 1, hence the initial value is of 1. When x changes by 1, y changes by 1/3, hence the base is of 1/3. Exponential functions have no restrictions, hence the domain is of all real values.

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Answer:

On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. It goes through (2, one-ninth), (1, one-third), (0, 1), and (negative 1, 3).

Analyze the graph of the exponential decay function.

The initial value is

✔ 1

The base, or rate of change, is

✔ 1/3

The domain is

✔ all real numbers

Step-by-step explanation:

The decay factor of the equation given in the task content is; 0.87.

According to the task content; the equation given is; y = 453(0.87)^4.

By comparison with exponential decay functions, it follows that the decay factor from the equation given is; 0.87 which insinuates that the factor of change after each decay is 0.87.

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Answer:

1)

Let the number of guests = x

∴ Pin hall total charge = 500 + 15x

Bloom place total charge = 350 + 18x

2)

The charges are equal.

∴  500 + 15x = 350 + 18x

⇒ 150 = 3x

⇒ 50 = x

∴ x = 50

This means that the charges for both halls will be equal when there are 50 guests.