the vibrations of a transverse wave move in a direction a. along the direction of wave travel. b. at right angles to the direction of wave travel. c. that changes with speed. d. opposite to the velocity.

The moment of inertia about the b-b' axis is 24.6E6 mm^4.

To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.

We are given that the moment of inertia of the shaded area about the A-A' axis is

and that the area of the shaded region is

We are also given the distances

which correspond to the distances of the two particles in the shaded region from the B-B' axis.

The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.

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Complete Question:

If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?

Given: A6E3 mm², ds-50 mm, d₂-10 mm

a. none of these answers

B. 21.2E6 mm^4

C  25.2E6 mm^4

D. 26.3E6 mm^4

E. 24.6E6 mm^4

The amount of energy required by 3 kilogram of Manganese to raise the temperature by 20 degree kelvin is 28.8 KJ.

The heat capacity of manganese is given to be 0.480 KJ/kg-K.

We have to raise the temperature of 3 kilogram of Manganese by 20 degree kelvins.

We know that the change in heat of the compound is given by the formula,

Q = MC∆T

Where Q is the heat/energy gained,

C is the heat capacity of Manganese,

∆T is the total change in temperature of Manganese.

Putting values in the above relation accordingly,

Q = 0.480 x 3 x 20

Q = 28.8 KJ.

So the energy required to raise the temperature of Manganese by 20 kelvin is 28.8 KJ.

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The total work done by the woman is 1000J.

The work done by a force is defined as the product of the displacement component of the force and the magnitude of that displacement. method. Work can be calculated by multiplying the force and the displacement in the direction of the force as

When a person pushes against a wall the displacement of the wall is zero because the wall does not move when a force is applied to it. The work done by a force is the product of the component of the force applied to the body in the direction of displacement and displacement.

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The wavelengths are listed below in ascending order from left to right. Gamma rays, X-rays, UV, visible, infrared, microwaves, and radio waves are all types of radiation.

The electric field and magnetic field combine to form the numerous waves that make up the electromagnetic spectrum. The electromagnetic wave is considered to have both wave and particle behavior.

The wavelength and frequency of electromagnetic waves are essentially determined by the wave's particle-like components, known as photons, which carry the wave's energy. The term "electromagnetic spectrum" refers to the class of electromagnetic waves.

In order of increasing wavelength, electromagnetic waves include gamma rays, x-rays, ultraviolet, visible, infrared, microwaves, and radio waves.

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Her average acceleration (in m/s2) during this time is  8.5 mph / sec².

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

V 1 = 41

V 2 = 18

time = 2.7 seconds

Acceleration = V2 - V1 / time

                      = 18 - 41 / 2.7

                       = 23 /2.7

                       = 8.5 mph / sec²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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The power of flash light is [tex]2.36*10^{-9}\ W[/tex] when light emits [tex]1.4*10^{10}[/tex] photons of wavelength is 490nm for 2.4 seconds.

The fundamental particle of light is both mundane and surprising. What physicists refer to as photons, laypeople may simply refer to as light. Photons are the smallest possible packets of electromagnetic energy as quanta of light.

Given,

The wavelength of photon = 490 nm

Number of photons, n= [tex]1.4*10^{10}[/tex]

The flash light lasts for time ,t =2.4 s

The energy of a single photon can be determined by formula,

[tex]E=\frac{hc}{\lambda}\\\\[/tex]

Where,

h= planck's constant = [tex]6.62*10^{-34}[/tex]

c=speed of light = [tex]3*10^8 m/s[/tex]

\lambda = wavelength of light =490 nm = [tex]490*10^{-9}m[/tex]

[tex]E=\frac{6.62*10^{-34}*3*10^8}{490*10^{-9}}\\\\E=4.05*10^{-19}\ J[/tex]

Then the energy for n photons will be [tex]nE=1.4*10^{10}*4.05*10^{-19}[/tex]

The power of the n photons can be determined by formula,

[tex]P=n*E*t\\\\P=1.4*10^{10}*4.05*10^{-19}\\\\P=2.36*10^{-9}\ W[/tex]

Thus, the power of the flash light is [tex]2.36*10^{-9}\ W[/tex]

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The gravitational potential energy of the bear decreases as the bear slides from top to bottom of the pine tree.

Given that,

Mass of the bear = 25 kg

Speed of the bear = 5.6 m/s

Height from which the bear slides = 12 m

Gravitational potential energy depends on the height of the bear. As the bear slides from top to bottom, the height keeps decreasing gradually. The formula for gravitational potential energy is P.E = m* g* h

where, m is the mass of the bear

g is the acceleration due to gravity

h is the height at which the bear stays

From the above relation, it is clear that, potential energy is directly proportional to the height of the object.

Thus, gravitational potential energy of the bear decreases as the bear slides down the pine tree.

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The velocity of the child is 3.36 m/s. Then, the distance it covered is 14 meters. The radius from the centre is then, 2.24 m.

Centripetal acceleration is the acceleration of a body moving through a circular paths. It is the rate of change of its angular velocity.

The acceleration of the child = 0.80 ms/²

time  = 4.2 s

velocity = time interval × acceleration

             = 4.2 s ×  0.80 ms/²= 3.36 m/s.

Then the distance covered  = velocity × time

= 3.36 m/s × 4.2 = 14.22 m.

This is the circumference of the circular path which is equal to 2πR.

The distance from the centre = radius of the path.

2πR = 14.22 m

R = 2.24 m

Therefore, the child will be 2.24 m far from the center of the ride.

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The statement that is not true about magnetic field line is that they are always from north to south inside the magnet.

When a bar magnet is observed closely in the presence of the small metal granules.

We can observe a pattern, the magnetic field lines are always from north to south outside the magnet.

But when we talk about inside the magnet the direction of the magnetic field lines are from South to North.

Magnetic lines forms a loop like shape outside the magnet the direction of which is given by a tangent drawn to the curve of the magnetic field line.

The direction of the magnetic field line is tangential at the curves.

So the only statement that is not true about the magnetic field lines are that they are from north to south inside the magnet.

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The wavelength of the sound heard by a stationary listner located est of the truck is  0.332 m

F = fο (V/V - Vs) ,Doppler effect

  = 950 (340 / 340 -24) = 1022.25 HZ

λ = V / F = 340 / 1022.25 = 0.332 m

Everything in sound is a vibration. The larynx (voice box) of a person, the string of a guitar, or the loudspeakers on your radio all need to vibrate in order to produce sound. When sound waves move away from their source, vibrating particles knock into other vibrating particles, which in turn causes those other particles to vibrate and knock into still more particles, and so on. Our eardrums vibrate in response to air vibrations, and these vibrations are then transformed into nerve signals and delivered to our brains, which enable us to perceive sound. Similar to this, microphones translate air vibrations into electrical signals after detecting them.

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An element of atomic number 88 decays radioactively to an element of atomic number 82 six beta-minus particles.

Isotopes are atoms that share the same atomic number but have various neutron numbers, which change their mass numbers. The standard atomic weight of an element is determined by the average isotopic mass of an isotopic mixture for that element in a specific environment on Earth (referred to as the relative atomic mass; see monoisotopic elements). Less than three-quarters of naturally occurring elements are isotope mixtures (see monoisotopic elements). In the 19th century, chemists were able to measure the amounts of the elements based on their relative atomic weights to hydrogen. Prior to the modern synthesis of concepts from physics and chemistry, an element's numerical position in the periodic table, which at the time was roughly in the following order, was all that the customary symbol Z represented.

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Answer:

1/4

Explanation:

(2,3)=(x1, y1)

(6,4)=(x2,y2)

Then,

Slope=(y2-y1)/(x2-x1)

=1/4

If the ball exits the track while undergoing an acceleration of 3g, 55.4m away from the base of the track does the block land

Acceleration ac = V²/R = 3g

V = √3gR

By using kinematic equation for vertical motion of ball,

S = u t  + 1/2 gt²

S = 2R, U = 0

t = √4R/g

Horizontal distance is given by

D = vt = √3gR × √4R/g

D = 2√3 R

D = 55.4m

To get the equation for the horizontal distance, one can rearrange the slope percent equation. Divide both sides by run to rewrite the equation's terms. The slope percent is applied to both sides. Horizontal distance is calculated as run = (rise 100) / slope%. When two points are separated by a horizontal distance, the slope is zero percent.

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On the earth's surface, an object weighs 432N. At a height of 3R above earth's surface, its weight will be 27N

Given the weight on surface of earth (F) = 432N

let radius of earth be R

Height increased (h) = 3R

Weight at certain height of 3R = F2

We know that  the force due to gravity decreases by the square of the radius.

From the formula: g1 = g(R/R+h)^2

g1 = g(R/R+3R)^2 = g(1/4)^2

g1 = g/16

We know that Force(F) = mg

Force at a height of 3R from surface of earth = F2

F2 = mg1 =mg/16 = F/16

Weight at this height = 432/16 = 27N

Hence the weight of object at a height of 3R from surface of earth is 27N

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An electron in the first Bohr orbit has a kinetic energy of 13.6 eV. A tiny, positively charged nucleus is around by rotating, negatively charged electrons in set orbits, according to the Bohr Atomic Model.

The Bohr model postulates that the electrons orbit the nucleus at fixed energy levels and also concluded that electron has more energy if it is located away from the nucleus whereas the electrons have less energy if located near the nucleus.

Bohr proposed that electrons do not radiate energy as they orbit nucleus, but exist in state of constant energy that is called stationary states. Bohr's work was based on the emission spectra of hydrogen.

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The puck is moving at an angle of 51 degrees from the x-axis.

As we can see from the graph of the question the value of x component of velocity  [tex]v_{x}[/tex] is nearly 24 cm/s and the value of y component of velocity [tex]v_{y}[/tex] is constant throughout the journey of puck and is equal to 30cm/s. For any instant of time the direction is given by the slope of the graph tanθ which is equal to the y component divided by the x component.

At the instant when t= 3s

[tex]v_{x}= 24 cm/s\\v_{y}= 30 cm/s\\[/tex]

Direction is given by the slope of the graph  

tanθ= [tex]\frac{v_{y} }{v_{x} } = \frac{30}{24}[/tex]=  1.25

θ= 51 degrees from x-axis (in anti-clockwise manner)

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Since the second energy level has more energy than the first, the electron must gain energy to travel from n = 1 to n = 2. To increase to the second energy level, it must gain (-3.4) - (-13.6) = 10.2 eV of energy.

By absorbing light, the electron can obtain the energy it requires. The electrons in an atom revolve around the nucleus. Small, negatively charged particles known as electrons move in a circular orbit around the nucleus. They are unable to move around at will in any location. Depending on their energy levels, their revolution is limited to certain orbits. Energy levels are nothing more than the electrons' set distances from an atom's nucleus. The electron shell is another name for the energy levels. An electron can migrate across energy levels, but it cannot remain in one energy level while in another.

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Wavelengths of sound waves fall within such obstacles and are easily diffracted.

Sound waves have higher wavelengths, which are comparable in dimension to opaque encounters in our everyday life. Thus, diffraction effects are more visible in sound waves than in light waves. Sound waves have much longer wavelengths than visible light waves.

Wavelength is the distance between identical points in adjacent cycles of a waveform signal propagating in space or along a wire. In wireless systems, this length is usually expressed in meters, centimeters, or millimeters. Wavelength is the distance between two wave crests and the same for wave troughs.

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The period of a sine or cosine function is given by 2Pi/b.

For the function given by y = sin(bx-c), c/b represents the phase shift of the graph of the function.

A period is the amount of time between two waves, whereas a periodic function is one whose values recur at regular intervals or periods. In other terms, a periodic function is one whose values recur after a specific interval.

If we have f (a + m) = f (a), then a function f will be periodic with period m for every m > 0.

It demonstrates that after an interval of "m," the values of the function f(a) remain the same.

One may state that the function f repeats all of its values after every interval of "m."

Phase shift merely denotes that the two signals are, at any given time, at different positions in their cycle.

Phase shift, which depicts how each wave moves through its cycle, is measured as the angle (in degrees or radians) between two points on a circle at the same moment.

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Due to the fundamental differences between these two galaxy types, galaxies cannot evolve from elliptical to spiral (or spiral to elliptical).

For example, in contrast to spiral galaxies, which include gas and dust as well as hot, bright O and B type stars, elliptical galaxies are devoid of visible gas and dust and hot, brilliant stars.

A galaxy with an elliptical shape and a uniform brightness distribution is called an elliptical galaxy (no spiral arms). Elliptical galaxies are stretched galaxies with an elliptical shape, according to astronomical physics. The light is distributed evenly and smoothly throughout this type of galaxy, which is typically composed of old stars.

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A. You have decreased the sound intensity by 0.01 factor if you install special sound-reflecting windows that lower the level of sound intensity by 20.0 dB.

B. No, Instead, if you cut the intensity in half, there is no difference in the sound intensity level (measured in dB).

To calculate the sound intensity reduction factor, use the relationship between loudness and intensity. Calculate the change in sound intensity using the reduced intensity. The following chart shows the relationship between the change in loudness and the level of sound intensity.

dl = 10log(I/I1)

Here, dl represents the change in loudness, I represents sound intensity, and I1 represents the reference sound intensity in air.

I =(I1/2)

(A) The following is the expression for a reduction in sound volume:

10log*(I/I1) divided by 20 equals dl.

(I/I1)

The negative symbol denotes a drop in sound volume.

log(I/I1) = -20/10

I/I1 = 10^(-20)

I/I1 = 1/100

I/I1 = 0.01

The reduction is thus 0.01 as a result.

B) The initial and ending values of the sound intensity parameters affect how loud the sound is. Sound is louder and its waves are more intense. Loudness increases by 10 times for every 10dB increase in sound intensity. The intensity is reduced by a factor of two from its initial value, hence the change in sound intensity is negative. The strength of the ear's perception of sound is referred to as sound loudness.

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The electric force between two or more charged objects depends on the charge and the distance between the charged objects

Coulomb's law states that the force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Coulomb's law shows the relationship between the force , charge and the distance between the bodies

therefore F= kq1q2/r²

where q1 is the charge of body 1 and q2 is the charge of body 2. r is the distance between them and k is called electrostatics constant which have a value of 9,×10⁹ Nm²/C²

Therefore what can affect the force between two charges are the product of the charge of the two bodies and the distance between the two charge.

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The unstretched length so that it does not allow the block to leave the surface until θ= 60° is L = 4.574 ft.

Given:

The weight of the block W = 2 lb

The initial velocity of the block v_i = 0

The stiffness of the spring k = 2 lb/ft

The radius of the cylindrical surface r = 2 ft

Compute the velocity of the block at θ= 60°. Use Newton's second equation of motion in direction normal to the surface.

= F_n = m X a_n

Where, a_n is the centripetal acceleration or normal component of acceleration as follows:

= a_n = v²_2 / r

Substitute:

= F_n = m*v²2 / r

Where, F_n normal force acting on block by the surface is:

= F_n = W X cos(θ)

Substitute:

W*cos(θ) = m*v^2_2 / r

v_2 = sqrt ( r*g*cos(θ) )

Plug in the values:

v²_2 = 2 X 32.2 X cos(60)

v²_2 = 32.2 (ft/s)²

Apply the conservation of energy between points A and B where θ= 60° :

T_A + V_A = T_B + V_B

Where,

T_A : Kinetic energy of the block at initial position = 0

V_A: potential energy of the block initial position

V_A = 0.5 X k X x_A²

x_A = 2 X π- L           ( L is the original length )

V_A = 0.5X 2 X (2 X πi - L)² =

= (2 X pi - L)²

T_B = 0.5 X W/g X v_2² =

= 0.5 X 2 / 32.2 X 32.2 = 1

V_B = 0.5 X k X x_B² + W X 2 X cos(60)

and, x_B = 2 X 0.75 X π - L             ( L is the original length )

V_B = 0.5 X 2 X (1.5 X π - L)² + 2 X 1

= 2 + ( 1.5 X π- L )²

Input the respective energies back in to the conservation expression:

= 0 + (2π - L)² = 1 + 2 + ( 1.5π - L )²

= 4π² - 4πL + L² = 3 + 2.25π² - 3πL + L²

= πL = 1.75π² - 3

= L = 4.574 ft

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The complete question;

the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s. The 2-lb block is released from rest at A and slides down along the smooth cylindrical surface. Of the attached spring has a stiffness k = 2 lb/ft. Determine its unstretched length so that it does not allow the block to leave the surface until θ= 60°.

A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2

Given the input pressure (P1) = 1200Pa

Output force (F2) = 800N

We know that P= F/A where A is area of cross section

Let the input force be F1 and area is A1

Then by pascals law we say that:

F1/A1 = F2/A2

1200 = 800/A2 (since P1= F1/A1)

A2 = 8/12 = 0.67m^2

Hence the area of other side = 0.67m^2

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The value of the damping constant of the tuning fork will be equal to the value 0.23 s⁻¹.

The equation for the damping of harmonic system is expressed as

y = Xe^(-Ct) sin(ωt)

where Xe^(-Ct) = A that is amplitude and C is the damping constant.

If we assume that at time = t the value of A = K and at time = t + 6 the value of A = K/4 then the expression for amplitude will be

K = Xe^(-Ct)

K/4 = Xe^(-C(t + 6))

On dividing the two equations we get

4 = e^(6C)

Taking natural log on both sides we get

ln(4) = 6C

=> C = 1/6 ln(4)

=> C = 0.23 s⁻¹

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The faster runner is the mouse.

Kinetic energy is the type of energy carried by any moving object or subatomic particle. Any object or particle in motion possesses kinetic energy. Kinetic energy manifests itself in many everyday phenomena, such as walking, throwing a baseball, dropping a crumb, traveling through an electric field, etc. Only things in motion can store kinetic energy, hence a still object has none.

Potential energy is held by inanimate objects like rocks and plants. A body's potential energy is transformed into kinetic energy whenever a force, such as gravity, acts upon it and sends it into motion. For example, stretching a rubber band stores energy as elastic potential, which is then converted to motion when the band is released from its stretched state.

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Answer:

Main sequence star: (b) burns hydration as its primary fuel.

Explanation:

In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.

A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.

Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.

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The power radiated by the sun is 3.93* 10²⁶W.

What is power ?

Work rate or energy delivery time is expressed as W/t, where W is the quantity of work completed or energy delivered, and t is the time interval.

What is intensity ?

Intensity is the amount of energy a wave carries over a surface of a particular area in a unit of time, and it is the same as the energy density times the wave speed. The most popular unit of measurement is watts per square metre. The strength and size of a wave affect its frequency.

The main concept used to solve this problem is power emitted by radiation.

Initially, find the surface area covered by the sun’s radiation using the formula of area of a sphere. Then, use the expression of power to find the power radiated by sun.

The surface area of a sphere can be written as follows:

A= 4πr²

Here, r is the radius.

The power emitted by radiation can be calculated by using the following expression:

P= IA

Here, I is the intensity and A is the area.

Step: 1

The surface area of a sphere can be written as follows:

A= 4πr²

Substitute

1.5*10⁻¹¹m

for r in the above expression.

A=4π ( 1.5*10¹¹M ) ²

= 2.8274*10²³m²

The sun emits radiation in all the directions around it and in a uniform way. This means that the level of intensity of the radiation reaching earth will be same for all the objects which are placed at the same distances from the sun. that is, the surface area of the sphere of radius as the distance between sun and earth will get same intensity of the radiation emitted by the sun.

Use the expression of power to find the power radiated by sun.

Step: 2

The power emitted by radiation can be calculated by using the following expression;

P= IA

Substitute

1390W/m²

for I and

2.8274*10²³m²

for A in the above expression.

P= (1390W/ m²) ( 2.87274*10²³m²)

= 3.93*10²⁶W

The radiation emitted from the sun is spread over large spherical surfaces, so the energy per unit square meter decreases as the radii of the spherical surface increases. The far the planet from the sun, the smaller will be the energy per unit square meter.

Therefore, the power radiated by the sun is 3.93* 10²⁶W.

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When the highest and lowest frequency of a circuit is given then bandwidth is  calculated as 9100 Hz.

Maximum amount of data transmitted over an internet connection in given amount of time is known as bandwidth. Bandwidth is actually the volume of information that can be sent over a connection in a measured amount of time.

In signal processing, bandwidth describes difference between upper and lower frequencies in transmission signals. The measurement of bandwidth of a signal is done in hertz (Hz).

Given highest frequency of circuit is 10 kHz

= 10000 Hz

and lowest frequency of circuit is 900 Hz

Bandwidth = 10000 Hz -900 Hz

So, Bandwidth = 9100 Hz.

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