The vector sum of the forces acting on the beam is zero, and the sum of the moments about the left end of the beam is zero. (a) Determine the forces and and the couple (b) Determine the sum of the moments about the right end of the beam. (c) If you represent the 600-N force, the 200-N force, and the 30 N-m couple by a force F acting at the left end of the
Answers
This question is incomplete, the complete question is;
The vector sum of the forces acting on the beam is zero, and the sum of the moments about the left end of the beam is zero.
(a) Determine the forces and and the couple
(b) Determine the sum of the moments about the right end of the beam.
(c) If you represent the 600-N force, the 200-N force, and the 30 N-m couple by a force F acting at the left end of the beam and a couple M, what is F and M?
Answer:
a)
the x-component of the force at A is [tex]A_{x}[/tex] = 0
the y-component of the force at A is [tex]A_{y}[/tex] = 400 N
the couple acting at A is; [tex]M_{A}[/tex] = 146 N-m
b)
the sum of the momentum about the right end of the beam is; ∑[tex]M_{R}[/tex] = 0
c)
the equivalent force acting at the left end is; F = -400J ( N)
the couple acting at the left end is; M = - 146 N-m
Explanation:
Given that;
The sum of the forces acting on the beam is zero ∑f = 0
Sum of the moments about the left end of the beam is also zero ∑[tex]M_{L}[/tex] = 0
Vector force acting at A, [tex]F_{A}[/tex] = [tex]A_{x}i[/tex] + [tex]A_{y}j[/tex]
Now, From the image, we have;
a)
∑f = 0
[tex]F_{A}[/tex] - 600j + 200j = 0i + 0j
[tex]A_{x}i[/tex] + [tex]A_{y}j[/tex] - 600j + 200j = 0i + 0j
[tex]A_{x}i[/tex] + ([tex]A_{y}[/tex] - 400)j = 0i + 0j
now by equating i- coefficients'
[tex]A_{x}[/tex] = 0
so, the x-component of the force at A is [tex]A_{x}[/tex] = 0
also by equating j-coefficient
[tex]A_{y}[/tex] - 400 = 0
[tex]A_{y}[/tex] = 400 N
hence, the y-component of the force at A is [tex]A_{y}[/tex] = 400 N
we also have;
∑[tex]M_{L}[/tex] = 0
[tex]M_{A}[/tex] - ( 30 N-m ) - ( 0.380 m )( 600 N ) + ( 0.560 m )( 200 N ) = 0
[tex]M_{A}[/tex] - 30 N-m - 228 N-m + 112 Nm = 0
[tex]M_{A}[/tex] - 146 N-m = 0
[tex]M_{A}[/tex] = 146 N-m
Therefore, the couple acting at A is; [tex]M_{A}[/tex] = 146 N-m
b)
The sum of the moments about right end of the beam is;
∑[tex]M_{R}[/tex] = (0.180 m)(600N) - (30 N-m) - ( 0.56 m)([tex]A_{y}[/tex] ) + [tex]M_{A}[/tex]
∑[tex]M_{R}[/tex] = (108 N-m) - (30 N-m) - ( 0.56 m)(400 N ) + 146 N-m
∑[tex]M_{R}[/tex] = (108 N-m) - (30 N-m) - ( 224 N-m ) + 146 N-m
∑[tex]M_{R}[/tex] = 0
Therefore, the sum of the momentum about the right end of the beam is; ∑[tex]M_{R}[/tex] = 0
c)
The 600-N force, the 200-N force and the 30 N-m couple by a force F which is acting at the left end of the beam and a couple M.
The equivalent force at the left end will be;
F = -600j + 200j (N)
F = -400J ( N)
Therefore, the equivalent force acting at the left end is; F = -400J ( N)
Also couple acting at the left end
M = -(30 N-m) + (0.560 m)( 200N) - ( 0.380 m)( 600 N)
M = -(30 N-m) + (112 N-m) - ( 228 N-m))
M = 112 N-m - 258 N-m
M = - 146 N-m
Therefore, the couple acting at the left end is; M = - 146 N-m
Related Questions
Why is deforestation a serious global environment problem
Answers
Answer:
we all know that deforestation is when tress are cut down but this may cause cardio dioxide to go up into the atmosphere and this may cause the rise in sea level and temperates tend to fluctuate
Explanation:
I'm just that smart yah dig
An atom undergoes nuclear decay, but its atomic number is not changed.
What type of nuclear decay did the atom undergo?
A. Gamma decay
B. Beta decay
C. Nuclear fission
D. Alpha decay
Answers
Answer:
A. Gamma decay
Explanation:
A form of nuclear decay in which the atomic number is unchanged is a gamma decay.
The atom has undergone a gamma decay.
In a gamma decay, no changes occur to the mass and atomic number of the substance.
Gamma rays have zero atomic and mass numbers. When they cause decay, they cause no change to the mass and atomic numbers. They simply produce gamma rays during such reactions and these rays are very energetic.What energy store is in the hammer
BEFORE it hits the nail?
Answers
Answer:
mechanical energy
Explanation:
when raised up has potential energy
Answer:
potential energy
Explanation:
potential energy
Two objects moving at the same speed can have different velocities.
True or False
Answers
Answer:
True
Explanation:
Objects have the same velocity only if they are moving at the same speed and in the same direction.
Describe the position of the sun, moon, and earth during a new moon and a full moon.
During a new moon, (erase this and insert your answer describing how the earth, moon, and sun are aligned).
During a full moon (erase this and insert your answer describing how the earth, moon, and sun are aligned).
Why do we experience the different phases of the moon?
We experience the different phases of the moon because
Answers
Answer:
* he new moon phase when the position is Sun - Moon - Earth,
* have of the Full Moon when the position is Sun - Earth - Moon,
*All the phases of the moon are governed by the movement of the Moon around the Earth.
Explanation:
In the solar system, the planets revolve around the sun, which is much more massive, in the case of the Earth it is more massive than its satellite, therefore the Moon revolves around the Earth in a period of approximately 28 days.
It is said that the moon is in the new moon phase when the position is Sun - Moon - Earth, so the moon cannot be seen
It is in the phase of the Full Moon when the position is
Sun - Earth - Moon, in this case the moon can be observed by the light reflected from it.
All the phases of the moon are governed by the movement of the Moon around the Earth.
What kind of scattering (Rayleigh, Mie, or non-selective) would you expect to be most important when radiation of the specified wavelength encounters the following natural or anthropogenic particles?
Wavelength O2molecules Smoke particles Cloud droplets Rain droplets
(size 10-10m) (size 0.3 mm) (size 20 mm) (size 3 mm)
200 nm
0.6 mm
10 mm
1.0 mm
1.0 km
Answers
Answer:
hello your question is not properly arranged attached below is the arranged table and solution
answer : attached table below
Explanation:
Given data:
02 molecules size = 10^-10m
smoke particles size = 0.3 mm
cloud droplets size = 20 mm
Rain droplets size = 3 mm
Attached below is a table showing the kind of scattering that is expected to occur at various wave lengths
Note : For Rayleigh scattering the wave particle is smaller than the wave length while for Non-selective scattering the wave particle is greater than the wavelength.
and For Mie scattering the wavelength is the same as the wavelength.
what is momentum of a train that is 60,000 kg that is moving at velocity of 17m/s?
explain your answer
Answers
=60000 x 17
=1020kgm/s
How could a change in straight line motion due to unbalanced forces be predicted from an understanding of inertia?
Answers
Answer:
If the force goes in the direction of movement, the speed must increase and if the net force goes in the opposite direction, the speed must decrease.
Explanation:
The principle of inertia or Newton's first law states that every body remains static or with constant velocity if there is no net force acting on it.
Based on this principle, if we have a net force, the velocity of the body changes by having an unbalanced force acting.
If the force goes in the direction of movement, the speed must increase and if the net force goes in the opposite direction, the speed must decrease.
The bowling ball has starts out at rest (0= speed m/s) at the top of the building (height 40 m). How much potential energy does the ball have?
How much Kinetic energy does the bowling ball have?
How much total energy (Potential energy & Kinetic) does the bowling ball have?
Of the bowling ball's total energy, is more in the form of potential or kinetic energy?
Answers
Answer:
it has 40 potential/ 20 kinetic energy/ do the math
Explanation:
energy
what is energy? list the three mechanical forms of energy and their associated equations.
Answers
Answer:
See the explanation below.
Explanation:
Energy is the ability of bodies to perform work and produce changes in themselves or other bodies.
There are several types of energy, but let's talk specifically about mechanical energy.
Mechanical energy is associated or subdivided into kinetic, potential, and elastic energies.
Kinetic energy
[tex]E_{kin}=\frac{1}{2}*m*v^{2}[/tex]
Potential energy
[tex]E_{pot}=m*g*h[/tex]
Elastic Energy
[tex]E_{elas}=\frac{1}{2} *k*x^{2}[/tex]
An open 1-m-diameter tank contains water at a depth of 0.7 m when at rest. As the tank is rotated about its vertical axis the center of the fluid surface is depressed. At what angular velocity
Answers
Answer:
Explanation:
To find the angular velocity of the tank at which the bottom of the tank is exposed
From the information given:
At rest, the initial volume of the tank is:
[tex]V_i = \pi R^2 h_i --- (1)[/tex]
where;
height h which is the height for the free surface in a rotating tank is expressed as:
[tex]h = \dfrac{\omega^2 r^2}{2g} + C[/tex]
at the bottom surface of the tank;
r = 0, h = 0
∴
[tex]h = \dfrac{\omega^2 r^2}{2g} + C[/tex]
0 = 0 + C
C = 0
Thus; the free surface height in a rotating tank is:
[tex]h=\dfrac{\omega^2 r^2}{2g} --- (2)[/tex]
Now; the volume of the water when the tank is rotating is:
dV = 2π × r × h × dr
Taking the integral on both sides;
[tex]\int \limits ^{V_f}_{0} \ dV = \int \limits ^R_0 \times 2 \pi \times r \times h \ dr[/tex]
replacing the value of h in equation (2); we have:
[tex]V_f} = \int \limits ^R_0 \times 2 \pi \times r \times ( \dfrac{\omega ^2 r^2}{2g} ) \ dr[/tex]
[tex]V_f = \dfrac{ \pi \omega ^2}{g} \int \limits ^R_0 \ r^3 \ dr[/tex]
[tex]V_f = \dfrac{ \pi \omega ^2}{g} \Big [ \dfrac{r^4}{4} \Big]^R_0[/tex]
[tex]V_f = \dfrac{ \pi \omega ^2}{g} \Big [ \dfrac{R^4}{4} \Big] --- (3)[/tex]
Since the volume of the water when it is at rest and when the angular speed rotates at an angular speed is equal.
Then [tex]V_f = V_i[/tex]
Replacing equation (1) and (3)
[tex]\dfrac{\pi \omega^2}{g}( \dfrac{R^4}{4}) = \pi R^2 h_i[/tex]
[tex]\omega^2 = \dfrac{4g \times h_i }{R^2}[/tex]
[tex]\omega =\sqrt{ \dfrac{4g \times h_i }{R^2}}[/tex]
[tex]\omega = \sqrt{\dfrac{4 \times 9.81 \ m/s^2 \times 0.7 \ m}{(0.5)^2} }[/tex]
[tex]\omega = \sqrt{109.87 }[/tex]
[tex]\mathbf{\omega = 10.48 \ rad/s}[/tex]
Finally, the angular velocity of the tank at which the bottom of the tank is exposed = 10.48 rad/s
The impulse given to a body of mass 1.5 kg, is 6.0 kg • m•s? If the body was initially at rest what will its resulting kinetic energy be? Give your answer in J without units.
(Show Work)
Answers
Answer:
108J
Explanation:
Given parameters:
Mass the body = 1.5kg
Impulse = 6kgm/s
Initial velocity = 0m/s
Unknown:
Kinetic energy of the body = ?
Solution:
The kinetic energy of a body is the energy due to the motion of the body.
To solve this problem, we use the expression below:
K.E = [tex]\frac{1}{2}[/tex] m (V - U)²
m is the mass
V is the final velocity
U is the initial velocity
From;
Impulse = m V
6 = 1.5 x V
V = [tex]\frac{6}{1.5}[/tex] = 4m/s
So;
K.E = [tex]\frac{1}{2}[/tex] x 6 x (6 - 0)² = 108J
Why does the sky change colors at sunset?
The atmosphere reflects colors.
The atmosphere bends light.
The sun changes colors.
Answers
The sky changes colors at sunset because the atmosphere ABSORBS some colors of light more than other colors.
The second choice ("The atmosphere bends light") is a correct statement, but it's not the reason that the sky changes colors at sunset.
Answer:
The atmosphere bends light.
Explanation:
I got the test, and passed! =)
Like charges will exert a force of
a. positive
b. negative
c. attraction
d. repulsion
e. neutral
Answers
Answer:
D- Repulsion
Explanation:
A positively charged object will exert a repulsive force upon a second positively charged object.
What do I know about dance movements?
Answers
Answer:
Hi lol
Explanation:
follow me lol
sarivigakarthi this is my account...
A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at rest. (a) Find the velocity of each object after the collision. -6.67 Correct: Your answer is correct. cm/s (5.00 g object) 13.33 Correct: Your answer is correct. cm/s (10.0 g object) (b) Find the fraction of the initial kinetic energy transferred to the 10.0 g object. 88.44 Correct: Your answer is correct. %
Answers
Answer:
a) [tex]v_{1f}=-6.67\: cm/s[/tex]
[tex]v_{2f}=13.33\: cm/s[/tex]
b) [tex]n=88.84\: \%[/tex]
Explanation:
a) Applying the conservation of momentum, we have:
[tex]p_{i}=p_{f}[/tex]
p(i) is the initial momentum. In our case is due to the 5 g object.
p(f) is the final momentum. Here, both objects contribute.
[tex]m_{1i}v_{1i}=m_{1f}v_{1f}+m_{2f}v_{2f}[/tex]
Where:
m(1) is 5 gm(1) is 10 gv(1i) is the initial velocity 20 cm/s or 0.2 m/sTo find both final velocities we will need another equation, let's use the conservation of kinetic energy.
[tex]m_{1i}v_{1i}^{2}=m_{1f}v_{1f}^{2}+m_{2f}v_{2f}^{2}[/tex]
So we have a system of equations:
[tex]5*0.2=5v_{1f}+10v_{2f}[/tex] (1)
[tex]5*0.2^{2}=5v_{1f}^{2}+10v_{2f}^{2}[/tex] (2)
Solving this system we get:
[tex]v_{1f}=-6.67\: cm/s[/tex]
[tex]v_{2f}=13.33\: cm/s[/tex]
b) The fraction of the initial kinetic energy transferred is:
[tex]n=\frac{m_{2}v_{2f}^{2}}{m_{1}v_{1i}^{2}}[/tex]
[tex]n=\frac{10*13.33^{2}}{5*20^{2}}[/tex]
[tex]n=88.84\: \%[/tex]
I hope it helps you!
What is the 59th element
Answers
Answer:
The 59th element is Praseodymium it's symbol is Pr.
What happens to kinetic energy when you decrease the velocity of a moving object?
Answers
. A string with both ends held fixed is vibrating in its third harmonic. The waves have a speed of 192 m>s and a frequency of 240 Hz. The amplitude of the standing wave at an antinode is 0.400 cm. (a) Calculate the amplitude at points on the string a distance of (i) 40.0 cm; (ii) 20.0 cm; and (iii) 10.0 cm from the left end of the string. (b) At each point in part (a), how much time does it take the string to go from its largest upward displacement to its largest downward displacement
Answers
Answer:
Explanation:
The formula holding the relationship between wavelength and frequency of a wave can be expressed as:
[tex]\lambda = \dfrac{v}{f}[/tex]
where;
[tex]\lambda =[/tex] wavelength
v = speed
f = frequency
Given that:
v = 192 m/s and f = 240Hz
Then;
[tex]\lambda = \dfrac{192 \ m/s}{240 \ Hz}[/tex]
[tex]\lambda = 0.800 \ m[/tex]
Now, to estimate the respective amplitude of the string, we need to approach it by using the concept of wave equation which is:
y = A sin kx
here;
A = amplitude of the standing wave
k = wave number
x = maximum displacement
y = distance from center
recall that:
[tex]k = \dfrac{2 \pi}{\lambda}[/tex]
∴
[tex]y = A sin \dfrac{2 \pi}{\lambda }x[/tex]
Now;
for A = 0.400 cm ; [tex]\lambda[/tex] = 0.800 m ; k = 40 cm
Then;
[tex]y =(0.400 \ cm ) \ sin \dfrac{2 \pi}{0.800 m }\times (40 \ cm \times \dfrac{10^{-2} \ m}{1 \ cm } )[/tex]
y = 0.400 sin π
y = 0 cm
At distance 40 cm; the amplitude = 0 cm
Thus, it is a node.
For k = 20cm
Then:
[tex]y =(0.400 \ cm ) \ sin \dfrac{2 \pi}{0.800 m }\times (20 \ cm \times \dfrac{10^{-2} \ m}{1 \ cm } )[/tex]
y = 0.400 sin π/2
y = 0.400 cm
At distance 20 cm; the amplitude = 0.400 cm
Thus, it is antinode.
For k = 10cm
Then:
[tex]y =(0.400 \ cm ) \ sin \dfrac{2 \pi}{0.800 m }\times (10 \ cm \times \dfrac{10^{-2} \ m}{1 \ cm } )[/tex]
4y = 0.400 sin π/2
y = 0.283 cm
At distance 10 cm; the amplitude = 0.283 cm
b)
The required time taken to go through the displacement( i.e. from largest upward to downward) is the time required to cover half of the wavelength.
This is expressed as:
[tex]T = \dfrac{1}{2} \times \dfrac{1}{f}[/tex]
[tex]T= \dfrac{1}{2} \times \dfrac{1}{240 \ Hz}[/tex]
T = 0.00208
T = 2.08 × 10⁻³ s
A Boeing 787 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the engines give the plane a constant acceleration of 1.9 m/s2. The plane then travels a distance of 1700 m down the runway before lifting off. How long does it take from the application of the acceleration until the plane lifts off, becoming airborne
Answers
Answer:
39.26 s
Explanation:
From the question given above, the following data were obtainedb
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Distance travelled (s) = 1700 m
Time (t) =?
Next, we shall determine the final velocity of the plane. This can be obtained as follow:
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Distance travelled (s) = 1700 m
Final velocity (v) =?
v² = u² + 2as
v² = 6² + (2 × 1.9 × 1700)
v² = 36 + 6460
v² = 6496
Take the square root of both side
v = √6496
v = 80.6 m/s
Finally, we shall determine the time taken before the plane lifts off. This can be obtained as follow:
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Final velocity (v) = 80.6 m/s
Time (t) =?
v = u + at
80.6 = 6 + 1.9t
Collect like terms
80.6 – 6 = 1.9t
74.6 = 1.9t
Divide both side by 1.9
t = 74.6 / 1.9
t = 39.26 s
This, it will take 39.26 s before the plane lifts off.
a graduated cylinder.measures 15.3 mL. Convert this measurement to DaL
Answers:
A. 0.0153
B. 0.00153
C. 0.000153
D. 0.153
Answers
Answer:
0.000153DaL
Explanation:
We have been given:
15.3mL to convert to DaL
DaL is a unit of volume which indicates a decaliter.
This implies that;
1 Da L = 1 x 10²L
So:
1 mL = 1 x 10⁻³L
So 15.3mL will give 15.3 x 10⁻³L
So;
1 x 10²L = 1 DaL
15.3 x 10⁻³L will give [tex]\frac{15.3 x 10^{-3} }{1 x 10^{2} }[/tex] = 15.3 x 10⁻⁵DaL
Therefore, this is 0.000153DaL
What is the work required to stretch a spring with a spring constant k of 2500 N/m by 8 cm?
Answers
Answer:
the work required to stretch the spring is 8 J.
Explanation:
Given;
spring constant, k = 2500 N/m
extension of the spring, x = 8 cm = 0.08 m
The work required to stretch the spring is calculated as;
[tex]W = \frac{1}{2} kx^2\\\\W = \frac{1}{2} \times 2500 \times 0.08^2\\\\W = 8 \ J[/tex]
Therefore, the work required to stretch the spring is 8 J.
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Part APart complete How far does the elevator move while accelerating to full speed from rest? Express your answer with the appropriate units. 12.5 m Previous Answers Correct Part B How long does it take to make the complete trip from bottom to top? Express your answer with the appropriate units.
Answers
Answer:
45 s .
Explanation:
The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .
displacement s = ?
acceleration a = 1 m /s²
Final speed v = 5 m/s
initial speed u = 0
v² = u² + 2as
5² = 0 + 2 x 1 x s
s = 12.5 m
B) Let time of acceleration or deceleration be t
v = u + a t
5 = 0 + 1 t
t = 5 s
Similarly displacement during deceleration = 12.5 m
Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) = 175 m .
velocity of uniform motion = 5 m /s
time during which there was uniform velocity = 175 / 5 = 35 s
Total time = 5 + 35 + 5 = 45 s .
I want the answer, Due Today
Answers
Answer:
The process of distillation begins with heating a liquid to boiling point. The liquid evaporates, forming a vapor. The vapor is then cooled, usually by passing it through pipes or tubes at a lower temperature. The cooled vapor then condenses, forming a distillate
I hope it helps mate
I will always help you understand your assignments
enjoy your day
#Caprainpower
How much work is done in pushing a 10kg box, 2.0m to the right
with a force of 20.0N?
Answers
Answer:
40J
Explanation:
Given parameters:
Mass of box = 10kg
distance moved = 2m
Force applied = 20N
Unknown:
Work done in pushing the box = ?
Solution:
The work done in moving a body is a function of the force applied to move it through a particular distance.
Work done = Force x distance
So;
Work done = 20 x 2 = 40J
On March 27, 2004, the United States successfully tested the hypersonic X-43A scramjet, which flew at Mach 7.0 (seven times the speed of sound) for 11 seconds. (A scramjet gets its oxygen directly from the air, rather than from fuel.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Swim competition. Part A At this rate, how many minutes would it take such a scramjet to carry passengers the approximately 5000 kmkm from San Francisco to New York? (Use 331 m/sm/s for the speed of soun
Answers
Answer:
Explanation:
Speed of sound = 331 m /s
speed of jet = 7 .00 Mach = 7 times speed of sound
= 7 x 331 = 2317 m /s
distance to be covered = 5000 x 1000 = 5 x 10⁶ m
Time taken = distance / speed of jet
= 5 x 10⁶ / 2317
= 2.158 x 10³ s
= 35.96 minutes .
Which statements correctly describe the formula or name of a compound? Select all that apply.
A. The formula of nitrogen trifluoride is NF 3
OB. The formula of ammonia is NH3
OC. The name of AlF3 is trialuminum fluoride.
D. The formula of calcium chloride is cach,
DE The name of Lise is lithium selenate.
F. The formula of dinitrogen monoxide is NO
G. The formula of sulfur trioxide is so
H. The formula of magnesium hydroxide is Mg(OH)2
Answers
Answer:
The formula of nitrogen trifluoride is NF 3
The formula of ammonia is NH3
The formula of magnesium hydroxide is Mg(OH)2
Explanation:
The formula of a compound refers to the correct representation of the compound using appropriate chemical symbols.
The formula of a compound is derived from the symbols of its constituent elements. The formula of the compound must correctly show the number of atoms of each element in one formula unit of the compound.
In the answer section, the correct names or formulas of some compounds have been shown
Answer:
A. The formula of nitrogen trifluoride is NF3.
B. The formula of ammonia is NH3.
D. The formula of calcium chloride is CaCI2.
H. The formula of magnesium hydroxide is Mg(OH)2.
Explanation:
What do you think about the attached scenario?
Answers
Match each vocabulary word with the correct definition. 1. measure of how quickly velocity is changing 2. speed in a given direction 3. force that resists moving one object against another 4. measure of the pull of gravity on an object 5. tendency of an object to resist a change in motion 6. size friction acceleration velocity magnitude inertia weight friction
Answers
1. measure of how quickly velocity is changing . . . acceleration
2. speed in a given direction . . . velocity
3. force that resists moving one object against another . . . friction
4. measure of the pull of gravity on an object . . . weight
5. tendency of an object to resist a change in motion . . . inertia
6. size . . . magnitude
1. measure of how quickly velocity is changing is acceleration.
2. speed in a given direction is velocity.
3. force that resists moving one object against another is friction.
4. measure of the pull of gravity on an object is weight.
5. tendency of an object to resist a change in motion is inertia.
What is acceleration?Acceleration has the term used in mechanics to describe the pace at which the velocity of an object varies over time. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it.
It is a vector quantity with an SI unit is m/s² and the dimension formula is LT⁻². A massive body will accelerate or alter its velocity at a constant rate when a constant force is applied to it, according to Newton's second law. In the simplest case, when a force is applied to an object at rest, it accelerates in the force's direction.
Therefore, 1. measure of how quickly velocity is changing is acceleration.
2. speed in a given direction is velocity.
3. force that resists moving one object against another is friction.
4. measure of the pull of gravity on an object is weight.
5. tendency of an object to resist a change in motion is inertia.
Learn more about friction on:
https://brainly.com/question/13000653
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How much work does a 50.0kg person do in walking up one flight of stairs, equivalent to 3.0m?
Answers
Answer:
1470J
Explanation:
Given parameters:
Mass of the person = 50kg
height = 3m
Unknown:
Work done = ?
Solution:
To solve this problem, we use the expression below:
Work done = mass x acceleration due gravity x height
So;
Work done = 50 x 9.8 x 3 = 1470J