The three diagrams below show a block of mass m being pulled or pushed at constant acceleration ax along a table with a force P. The coefficient of kinetic friction is k. What is the friction force in each case? Give your answer in terms of the pushing force P, ax, m, and the angle .

Answer:

it is b or c

Explanation:

Answer:

The answer is B I did the test.

Explanation:

I hope it helps!

Answer:

true

Explanation:

The conservation of energy allows finding the result of the velocity of the body 2 when it reaches the ground is:

          v = 6.32 m / s

Given parameters

To find

The conservation of energy is one of the most important principles of physics, it establishes that if there is no friction force, the mechanical energy is conserved at all points, where the mechanical energy is the sum of the kinetic energy plus the different potential energies.

Let's write the energy at two points before we drop the system.

     Em₀ = U₁ + U₂

Where potential energy is

    U = m g y

They indicate that body 1 is on the ground and body 2 is at a height .

      y₂ = 8 m

      Em₀ = m₂ g y₂

Let's write the energy of the system for when body 2 is reaching the ground

       [tex]Em_f[/tex] = K₂ + K₁ + U₂ + U₁

At this moment body 2 is reaching the ground, its height is zero and the height of body 1 is y₁ = 8 m. Since the two bodies are joined by the rope, they must have the same speed..

      [tex]Em_f[/tex] = ½ (m₁ + m₂) v² + m₁ g y₁

As there is no friction, the energy is conserved.

      Em₀ = Em_f

      m₂ g y₂ = ½ (m₁ + m₂) v² + m₁ g y₁

The rope is inextensible, the heights are equal.

       y₁ = y₂ = y = 8.0 m

      v² = [tex]\frac{m2-m1}{m2+m1} \ 2g y[/tex]  

Let's calculate.

       [tex]v^2 =\frac{22.9-13.6}{ 22.9+13.6} \ 2 \ 9.8 \ 8 \\ v = \sqrt{39.95}[/tex]

      v = 6.32 m / s

In conclusion using the conservation of energy we can find the result of the velocity when the body 2 reaches the ground is:

          v = 6.32 m / s

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Answer:

If a ray of light hits the surface of a sheet of glass, some light will be reflected by the surface of the glass. However, much of the light will pass through the glass, because glass is transparent. ... This 'bending of a ray of light' when it passes from one substance into another substance is called refraction.

Explanation:

6

Explanation:

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La distancia que el bote se desplaza rio abajo es 44.5 metros.

Debemos recordar que la velocidad en cada eje es independiente de la velocidad en el otro eje. Tambien recordar que:

distancia = velocidad*tiempo.

Esto quiere decir que si el bote se mueve a 8m/s de un extremo al otro del rio, esta velocidad en esta dirección se va a mantener.

Entonces el tiempo que tarda en viajar 89 metros (el ancho del rio) a una velocidad de 8m/s es:

T = (89 m)/(8m/s) = 11.125 segundos.

Ahora notamos que durante esos 11.125 segundos el bote tambien se mueve siguiendo el flujo del rio, a una velocidad de 4.0 m/s, entonces la distancia que el bote se desplaza rio abajo es:

D = 11.125s*4.0m/s = 44.5 metros

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Answer:

Steps and solution in the attached pictureSteps and solution in the attached picture.

Explanation:

Steps and solution in the attached pictureSteps and solution in the attached picture.

The velocity of the second ball just after it is struck will be 9.091 m/s.

To quantify the effect of force acting over time to change the momentum of an object is referred to as impulse.

To calculate the velocity in the given scenario,

Given that,

mV=1.5

[tex]V=\frac{impulse}{mass}[/tex]

[tex]V=\frac{1.5}{0.165}[/tex]

V=9.091 m/s

Thus, the velocity will be 9.091 m/s.

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Answer:

Radiation is the transfer of energy through waves (electromagnetic radiation) or fast traveling particles (particulate radiation). Radiation can be in the form of heat, sound and light. Radiation can be felt or seen like light or detected through special instruments like X-ray. Radiation from a hot object is shorter..

Explanation:

Answer:

I think it A. Average kinetic energy of

Explanation:

In solids, the molecules are very close together and the attraction between the molecules are great. This causes a substance to have a structure in which the molecules have little freedom to move, as you would see in the case of ice. In the case of a liquid, the molecules are closely spaced, though not as closely spaced as a solid, they have more freedom to move and the intermolecular forces are weaker that that of a solid. Thus a liquid can flow, unlike a solid. Now in a gas, the molecules are sufficiently far apart that there are little to no attractive forces. Because of this a gas can easily be compressed and take the shape of the container.

Now as you heat a solid turning it into a liquid, you increase the kinetic energy of its molecules, moving them further apart until the forces of attraction are reduced to allow it to flow freely. Keep in mind the forces of attraction still exists. Now as you heat a liquid, turning it into a gas, the kinetic energy of the molecules are increased to a point where there are no forces of attraction between the molecules.

The energy required to completely separate the molecules, moving from liquid to gas, is much greater than if you were just to reduce their separation, solid to liquid. Hence the reason why the latent heat of vapourization is greater that the latent heat of fusion.

Answer:

D. and A

Explanation:

logical thought is base on functional fixedness; mental sets while creative problem solving uses insight; algorithms.

[tex]\bull\sf Torque=\tau=20.0\times 10^{-9}Nm[/tex]

[tex]\bull\sf \theta=30°[/tex]

[tex]\bull\sf E=9.0\times C.m=9.0\times 10^{-12}N/C[/tex]

Now we know

[tex]\\ \sf\longmapsto \tau=pEsin\theta[/tex]

[tex]\\ \sf\longmapsto p=\dfrac{\tau}{Esin\theta}[/tex]

[tex]\\ \sf\longmapsto p=\dfrac{20\times 10^{-9}}{9\times 10^{-12}\times sin30}[/tex]

[tex]\\ \sf\longmapsto p=\dfrac{20\times 10^{-9}}{9\times 10^{-12}\times \dfrac{1}{2}}[/tex]

[tex]\\ \sf\longmapsto p=\dfrac{20\times 10^{-9}}{9\times 10^{-12}}\times 2[/tex]

[tex]\\ \sf\longmapsto p=4.4\times 10^3N/C[/tex]

The magnitude of the externla electric field is 4,444.44 N/C.

The magnitude of the charge is 3.1 x 10⁻¹² C.

The magnitude of the externla electric field is calculated as follows;

EPsinθ = τ

where;

[tex]E = \frac{\tau}{P sin(\theta)} \\\\E = \frac{20 \times 10^{-9}}{9\times 10^{-12} \times sin(30)} \\\\E = 4,444.44 \ N/C[/tex]

The magnitude of the charge is calculated as follows;

[tex]E = \frac{kQ}{r^2} \\\\Q = \frac{Er^2}{k} \\\\Q = \frac{(4,444.44) \times (2.5 \times 10^{-3})^2}{(9\times 10^9)} \\\\Q = 3.1 \times 10^{-12} \ C[/tex]

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Hi there!

We can use the following equation to solve for displacement:

vf² = vi² + 2ad, where:

vf = final velocity

vi = initial velocity

a = acceleration

d = displacement

Since the car will come to rest, vf = 0, so:

0 = vi² + 2ad

Plug in the given values:

0 = 25² + 2(-5)d (Breaking is a negative acceleration in this instance)

Solve:

0 = 25² - 10d

10d = 625

d = 62.5m

Subtract from the total distance from the car to the tree:

65 - 62.5 = 2.5m

Answer:

uuuugggghhhhhhhhggggffffffffffffff

Answer:

The geocentric model could not fully explain these changes in the appearance of the inferior planets (the planets between the Earth and the Sun). Furthermore, Galileo's observations of Jupiter's moons made it clear that celestial bodies do move about centers other than the Earth.

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The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

For copper metal, the quantity of heat transferred is calculated as;

[tex]Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w ) = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t[/tex]

The change in heat energy for copper metal;

[tex]\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t[/tex]

For aluminum metal, the quantity of heat transferred is calculated as;

[tex]Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w) = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t[/tex]

The change in heat energy for aluminum metal ;

[tex]\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t[/tex]

Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

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Answer:velocity - decreases

acceleration remains constant

Explanation:

Notice that both strings have the same length, so they form an isosceles triangle, which means the angles they make with the ceiling are congruent.

If this angle has measure θ, then the angle between the two strings T₁ and T₂ has measure 180° - 2θ. This is because the interior angles of any triangle sum to 180°.

By the law of cosines, we have

(1 m)² = (0.87 m)² + (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)

Solve for θ :

(1 m)² = 2 (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)

(1 m)² / (2 (0.87 m)²) = 1 - cos(180° - 2θ)

cos(180° - 2θ) = 1 - (1 m)² / (2 (0.87 m)²)

cos(180° - 2θ) ≈ 0.3394

180° - 2θ = arccos(0.3394)

180° - 2θ ≈ 70.159°

2θ ≈ 109.841°

θ ≈ 54.9205° ≈ 55°

Answer:

hey i dont know what it is

Explanation:

Answer:

YEAH THE PERSON ABOVE ME IS RIGHT MARK

THEM BRAINLIST

Answer:

It will take 0.46 seconds to reach home plate by ball.

Explanation:

Answer:

The tension must be equal to the weight of the bob plus the centripetal force that is provided at eth end of the motion.

h = L (1 - cos theta)  where h is the height to which the bob is raised

cos 5.730 = .995

h = .005 L

Also    1/2 m v^2 = m g h    speed of the bob at the bottom

v^2 = 2 g h = .01 g L    where 2 h = .01 L

v^2 / L = .01 g

m v^2 / L = .010 g m = .07 g    since m = 7

Total tension = m g (1 + .07) = 1.07 m g

T = 9.807 * 1.07 * 7 = 73.45 kg m / s^2

Explanation:

2. v=fλ

_______________________

What is the variable?

~the price is the variable.

What happens to demand?

~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.

Hope this helps- have a good day bro cya)

I agree with the other answer

What is the variable?

~the price is the variable.

What happens to demand?

~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.

Answer:

a glass of water. a loaf of bread. a bar of soap.a packet of juice. a pinch of salt.

Explanation:

that's all I know

the scientific method is described as self-correcting and cyclical therefore it ain't linear but cyclic.

Hope this helped you- have a good day bro cya)

In the above pic question is similar like that only

Answer:

The gravitational force between the two objects is weak because their masses are small

c) melting of ice candy is an physical change

hope it helps

Answer:

30 km/h

Explanation:

V=S:t

speed=length:time

150:5=30

Answer:

hpqfie

Explanation:

wdq i love math WOOOOO

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Isolation and reduction of variables in an experiment is a way to reduce administrative efforts, costs and delusions occur.

An experiment is a technique used to prove or disprove a theory, or to test the efficacy or probability of something that has never been done before.

Experiments reveal cause-and-effect relationships by illustrating what happens when a specific component is changed.

Experiments have a wide range of goals and scales, but they always rely on a repeatable technique and rational interpretation of the outcomes. Natural experimental research is also available.

If you can plan a control group, you will be much better off. It increases the expense of the experiment by a factor of two and may cause delusions.

Furthermore, it doubles the administrative effort. However, it provides the most reliable and straightforward method for calculating significance,

By comparison, taking into consideration the deviations of each of the two groups of data that arise.

In many circumstances, a control group is required for analysis when you wish to look at certain lag periods or increases in addition to the final result.

Hence isolation and reduction of variables in an experiment are much more important to reduce.

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