The Sun reaches the zenith (directly overhead) at midday ___________. Select all the options that make the statement true.
A. everywhere in the Southern Hemisphere on the December solstice
B. on the equator only on the March and September equinoxes
C. on the Arctic circle (66.5°N) on the June solstice
D. on the equator every day
E. everywhere in the Northern Hemisphere on the June solstice
F. everywhere within the tropics (between latitudes 23.5°N and 23.5°S) on two dates each year

Answers

Answer 1

Answer: (option b) on the equator only on the March and September equinoxes

Explanation:One of the abecedarian data of life at Earth’s midlatitudes, where utmost of this book’s compendiums live, is that there are significant variations in the heat we admit from the Sun during the course of the time. We therefore divide the time into seasons, each with its different quantum of sun. The difference between seasons gets more pronounced the further north or south from the ambit we travel, and the seasons in the Southern Hemisphere are the contrary of what we find on the northern half of Earth. With these observed data in mind, let us ask what causes the seasons.

numerous people have believed that the seasons were the result of the changing distance between Earth and the Sun. This sounds reasonable at first it should be colder when Earth is further from the Sun. But the data do n’t bear out this thesis. Although Earth’s route around the Sun is an cirque, its distance from the Sun varies by only about 3. That’s not enough to beget significant variations in the Sun’s heating. To make matters worse for people in North America who hold this thesis, Earth is actually closest to the Sun in January, when the Northern Hemisphere is in the middle of downtime.



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Answer 2

The Sun reaches the zenith (directly overhead) at midday on the equator every day. Therefore, option D is correct.

The relationship between the Sun and the equator also affects the seasons. As the Earth orbits the Sun, its axial tilt causes different parts of the Earth to receive varying amounts of sunlight throughout the year. When the Sun is directly overhead at the Tropic of Cancer during the June solstice, it marks the start of summer in the Northern Hemisphere and winter in the Southern Hemisphere.

Conversely, when the Sun is directly overhead at the Tropic of Capricorn during the December solstice, it marks the start of summer in the Southern Hemisphere and winter in the Northern Hemisphere.

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Related Questions

what aspect of the blackbody spectrum forced planck to propose energy quantization?

Answers

Black body spectrum forced planck to propose energy quantization Radiation occurs at a particular frequency that does not change.

Energy is the ability to perform work in physics. Different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc., can be assumed by it. Two further examples of how energy may be transferred from one body to another are heat and work. Energy is consistently distributed after being given in accordance with its kind. As a result, heat transfer can provide thermal energy while effort can produce mechanical energy. Motion is a property that all forms of energy have in common. When a body is moving, for instance, kinetic energy is present. Due to the device's integration of potential energy, a tensioned item, such a spring or bow, can move even when at rest.

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if the moment of inertia of the shaded area about the a-a' axis is 18e6mm^4 what is the moment of inertia about the b-b' axis

Answers

The moment of inertia about the b-b' axis is 24.6E6 mm^4.

To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.

We are given that the moment of inertia of the shaded area about the A-A' axis is

18E6 mm^4,

and that the area of the shaded region is

A = 6E3 mm^2.

We are also given the distances

ds = 50 mm and d₂ = 10 mm,

which correspond to the distances of the two particles in the shaded region from the B-B' axis.

The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.

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Complete Question:

If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?

Given: A6E3 mm², ds-50 mm, d₂-10 mm

a. none of these answers

B. 21.2E6 mm^4

C  25.2E6 mm^4

D. 26.3E6 mm^4

E. 24.6E6 mm^4

a 29 kg child is coasting at 2.4 m/s over flat ground in a 5.0 kg wagon. the child drops a 1.4 kg ball from the side of the wagon. what is the final speed (in m/s) of the child and wago

Answers

The final speed of child and wagon is 2.503 m/s.

Given that, mass of the child is 29 kg

Mass of the wagon is 5 kg

Initial mass of the child and the wagon mi = 29 + 5 = 34 kg

It is said that the child dropped 1.4 kg ball from the wagon.

So, final mass mf = 29 + 5 - 1.4 = 32.6 kg

From the law of conservation of linear momentum, we know that

Initial momentum = Final momentum

mi * vi = mf * vf

where, vi is the initial velocity

vf is the final velocity

Making vf as subject, we have

vf = (mi * vi)/mf

Initial velocity is given as 2.4 m/s

Placing the values in the above equation, we have

vf = (mi * vi)/mf = (34 * 2.4)/32.6 = 2.503 m/s

Thus, the final speed of child and wagon is 2.503 m/s.

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What is the electric flux through the surface shown in the figure? Assume that E = 340N/C. Express your answer in newton meters squared per coulomb.

Answers

In this case, the electric field is 340 N/C, and the area vector is normal to the surface, so the dot product of the two is 0.

Electric flux is a measure of the amount of electric field that passes through a given area. It is measured in units of coulombs per meter squared (C/m2). Electric flux is important in electric circuits and fields, as it allows for the calculation of electric field strength, current, and other electrical properties. Electric flux is related to the concept of electric field lines, which represent the direction of the electric field at any point.

The electric flux through the surface shown in the figure is 0 N ⋅ m2/C. This is because the electric field is perpendicular to the surface and so no electric flux is passing through it. The electric flux is calculated as the dot product of the electric field and the area vector, and since the two are perpendicular, the result is 0.

Mathematically, electric flux is given by the formula Φ = E · A, where E is the electric field and A is the area vector.

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if you continue to exert this force once the crate starts to slip, what will its acceleration then be?

Answers

a) The maximum force that can be applied horizontally to the crate without moving it is 58.8 N.

b) The magnitude of the acceleration on the crate that starts to slip is  1.96 m/s².

The given problem is based on the concept of friction. If the crate is stationary and maximum horizontal force is applied, maximum static friction will act. If the crate starts sliding, kinetic friction will start to act. Newton's laws can be written in both cases. With the solution, we will get the maximum horizontal force in the first case and the acceleration in the second case.

a) A crate is not moving:

Because the crate is in balance

N = m.g

[tex]F_s[/tex] = Static

[tex]F_s[/tex] < F_max and F_max = μ[tex]_s[/tex]mg

In question:

μ[tex]_s[/tex] = 0.5, m = 12 kg, g = 9.8 m/s

F_max = μ[tex]_s[/tex]mg

F_max = 0.5 x 12 x 9.8

F_max = 58.8 N

b) Crate has started slipping:

F = F[tex]_s[/tex] - F[tex]_k[/tex]

m.a = μ[tex]_s[/tex]mg - μ[tex]_k[/tex]mg

   a = g (μ[tex]_s[/tex] - μ[tex]_k[/tex])

   a = 9.8 (0.5 - 0.3)

   a = 1.96 m/s²

So, crate acceleration has started slipping is 1.96 m/s²

Complete question:

Suppose you have a 120-kg wooden crate resting on a wood floor (μ[tex]_k[/tex]

= 0.3, μ[tex]_s[/tex] = 0.5).

(a) what maximum force can you exert horizontally on the crate without moving it?

(b) if you continue to exert this force once the crate starts to slip, what will the magnitude of its acceleration then be?

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after its most recent delivery, the infamous stork announces the good news. if the sign has a mass of 10.0 kg, then what is the tensional force in each cable?

Answers

To help with the solution, use a sketch and trigonometric functions. the 56.6 Newtons of stress.

An object must not be accelerating in order for it to be in equilibrium. This dictates that the object's net force and torque must both be zero. A spring stretches when a load is hung vertically from it. The amount the spring is stretched determines how much force the spring exerts on the mass. There is a location where the weight and spring force are equal in magnitude but in the opposite direction. The equilibrium position is where you are at this moment.

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An air conditioner uses a compressor to raise the temperature and pressure of _____. A. The outside air
B. The refridgerant
C. The inside air

Answers

Answer:

B. The refridgerant

Explanation:

this allows the refrigerant to absorb or release heat

if c(x) is a cost function, then c'(x) would be called the

Answers

The cost C is defined by the cost function as a function of the quantity x of things. As a result, C(x) is the price of x products. A linear cost function is one that has the formula C(x) = mx + b.

The quantity mx is referred to as the fixed cost, and the intercept b is referred to as the variable cost. The incremental cost per item is measured by the slope m, or marginal cost.

As a result, the relationship between the cost function and the profit function posits that a company cannot alter its profit without also altering its output and overall production costs. The cost function can also be used to calculate the average cost and the marginal cost of production in addition to calculating the overall production cost.

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What is the condition necessary for free fall​

Answers

Answer:

The free fall is a motion that happens when we let something fall from certain height, this motion only happens when the object falls because of its own weight without any initial force or initial velocity, because then we would be talking about a vertical motion.

The free fall is a uniformly accelerated motion that only moves in the vertical axis (“y” axis), with the condition that the initial velocity will always have to be equals to 0 and the acceleration will be the value of the gravity in the place of the motion (9.8m/s). When a free fall motion happens in perfect conditions (this means that there is no air or any other factor that affects the trajectory of the object) the object only moves vertically.

When an object is in free fall, it will star with a 0m/s velocity, but while time passes, the velocity of the object will increase progressively until it impacts the floor or any object that is in its trajectory, this is why, the higher the initial height is, the stronger the impact will be against the floor.

Free Fall Conditions

The trajectory of an object in free fall could be affected by the air masses, an atmospheric phenomenon also known as aerodynamic resistant. In theory an object in free fall only moves vertically, but because of the air masses the trajectory of the object could change, both vertically and horizontally, how much will the air masses affects the object will depend on the weight of the object, if the object is heavier, then the air masses will not affect the object that much.

The condition depends on the property of the material under free fall. For example, if the body has a certain mass as well as charged, it causes a deflection due to Earth's magnetic field. Also the Coriolis effect due to Earth's rotation (when dropped from space to earth) comes into play when the object falls from a much higher altitude.

. consider the 65.0-kg ice skater being pushed by two others shown below. (a) find the direction and magnitude of ftot, the total force exerted on her by the others, given that the magnitudes f1 and f2 are 26.4 n and 18.6 n, respectively. (b) what is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of ftot? (c) what is her acceleration assuming she is already moving in the direction of ftot? (remember that friction always acts in the direction opposite that of motion or attempted motion between surfaces in contact.)

Answers

For the purpose of determining the acceleration, we will employ Newton's second law. F (totally) = ma, a = F(totally) / m, a = 32.0 N / 65.0 kg = 0.492 m/s2. If she starts out motionless and skating on steel blades, her initial acceleration is about 0.492 m/s2.

By magnitude, what do you mean?

"Distance or quantity" is the simplest definition of magnitude. It depicts the amount and direction that even a body travels in either an absolute or comparative perspective.

What is an illustration of magnitude?

Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. In this case, the car is moving faster than the bike by a larger margin.

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at what grazing angle in degrees from the surface will x-rays of wavelength 0.27 nm on a crystal with interatomic spacings between the bragg planes of 0.64 nm result in a first-order interference fringe?

Answers

12.18 degree grazing angle in degrees from the surface will x-rays of wavelength 0.27 nm on a crystal with interatomic spacings between the  planes of 0.64 nm result in a first-order interference fringe.

According to diffraction law

[tex]$\lambda=0.27 \times 10^{-9} \mathrm{~m}$[/tex]

[tex]$$\hat{d}=0.64 \times 10^{-9} \mathrm{~m}$$[/tex]

[tex]\Rightarrow \quad \sin \theta=\frac{\lambda}{2 d}=\frac{0.27 \times 10^{-9}}{2 \times 0.64 \times 10^{-9}}[/tex] = 0.2109375

sin [tex]\theta[/tex] = 0.2109375

[tex]\theta[/tex]= [tex]sin^{-1} (0.2109375)[/tex]

[tex]\theta[/tex]  = 12.18 degree

The grazing angle is the angle formed by the tangent to the earth at the target's location and a line drawn from the sensor to the target's surface.

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rank in order, from largest to smallest, the angular velocities ω1, ω2, and ω3 of these points.

Answers

ω₁ = ω₂ = ω₃ Every particle rotates about the axis of rotation with a constant angular velocity (ω). The rank for velocity is v₃ > v₂ = v₁ because = r and r₁ = r₂<r₃.

A pseudovector used to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity ( or ). (i.e. how quickly an object rotates or revolves relative to a point or axis). The pseudovector's direction is normal to the instantaneous plane of rotation or angular displacement, and its magnitude corresponds to the object's angular speed, or the rate at which it rotates or revolves. The right-hand rule is typically used to specify the direction of angular motion.

The angular velocity comes in two flavors.

Orbital angular velocity, also known as the temporal rate of change of an object's angular location with respect to an origin, is the rate at which a point object revolves about a fixed origin.In contrast to orbital angular velocity, spin angular velocity describes how quickly a rigid body rotates with regard to its center of rotation and is independent of the choice of origin.

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calculate the energy required to lift an elevator and its occupants with a mass of 1000 kg through a vertical distance of 5 m. group of answer choices 49000 j 5000 j 11000 j 2500 j

Answers

The energy required to lift an elevator and its occupants with a mass of 1000 kg through a vertical distance of 5 m is 49000 j .

Calculation :

Work done by any object . will be stored in the form of energy .

Energy stored = Work done = Force * Distance

                                               = Mass * acceleration * Distance

As lift moving up force is acting on it due to gravity,

force = Mass * acceleration due gravity

Energy = Mass * acceleration due gravity* Distance

             = 1000 kg * 9.8 m/sec² * 5m

             = 49000 joule

energy as the ability to do work. Modern civilization is possible because humans have learned to convert energy from one form to another and use it for work.

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an electron volt, ev, is a unit of energy. which is larger, a gev or a mev?

Answers

GeV is 1000 times larger than MeV .

"When an electron crosses a one volt potential, which is measured in electron volts, it gains energy" (eV). An electron volt, or ev, serves as the sign for energy. Electron volts, a measure of energy often used in atomic and nuclear physics, are the amount of energy that an electron (a charged particle carrying one unit of charge) acquires when the electric current at the electron increases by one volt.

Mega electron-volts, or MeVs, are a million times more potent than electron-volts. An electron has an energy of one eV.

When the giga-electron volt, or 109 eV, is initialised, energy is released in units of meV that are equivalent to 3108 ms 1 for every kilogramme of mass that is completely converted to energy.

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a 25 kg bear slides, from rest, 12 m down a lodgepole pine tree, moving with a speed of 5.6 m/s just before hitting the ground. (u) what change occurs in the gravitational potential ener

Answers

The gravitational potential energy of the bear decreases as the bear slides from top to bottom of the pine tree.

Given that,

Mass of the bear = 25 kg

Speed of the bear = 5.6 m/s

Height from which the bear slides = 12 m

Gravitational potential energy depends on the height of the bear. As the bear slides from top to bottom, the height keeps decreasing gradually. The formula for gravitational potential energy is P.E = m* g* h

where, m is the mass of the bear

g is the acceleration due to gravity

h is the height at which the bear stays

From the above relation, it is clear that, potential energy is directly proportional to the height of the object.

Thus, gravitational potential energy of the bear decreases as the bear slides down the pine tree.

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the heat capacity of manganese is 0.480 kj kg-1 k-1. how much energy is required to raise the temperature of 3.00 kg of manganese by 20.0 k?

Answers

The amount of energy required by 3 kilogram of Manganese to raise the temperature by 20 degree kelvin is 28.8 KJ.

The heat capacity of manganese is given to be 0.480 KJ/kg-K.

We have to raise the temperature of 3 kilogram of Manganese by 20 degree kelvins.

We know that the change in heat of the compound is given by the formula,

Q = MC∆T

Where Q is the heat/energy gained,

C is the heat capacity of Manganese,

∆T is the total change in temperature of Manganese.

Putting values in the above relation accordingly,

Q = 0.480 x 3 x 20

Q = 28.8 KJ.

So the energy required to raise the temperature of Manganese by 20 kelvin is 28.8 KJ.

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what is the adjusted ampacity for each of six no. 4/0 thhn copper current-carrying conductors in a single conduit? (given: the ampacity of 4/0 thhn is 260a.)

Answers

The adjusted ampacity for each of the six No. 4/0 THHN copper current-carrying conductors in a single conduit is 220 amps.

This is because the ampacity of 4/0 THHN is 260 amps, but when more than three current-carrying conductors are in the same conduit, they must be derated. To derate, multiply the ampacity by the appropriate factor. In this case, the factor is 0.85, so 260 multiplied by 0.85 gives 220. Additionally, the National Electrical Code requires that the ampacity of the conductor must not be less than the rating of the overcurrent device which is protecting the circuit. In other words, the ampacity of the conductor must not be less than the rating of the fuse or circuit breaker protecting the circuit. This means that the ampacity of the conductors must be 220 amps or greater.

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if the internal energy of a thermodynamic system is increased by j while j of expansion work is done, how much heat was transferred and in which direction, to or from the system?

Answers

U=q+w In other words, heat (q) and work (w) are added to define internal energy (w). Now that you are exerting force on your surroundings to do expansion work, you are losing energy and are aware that x joules of work are being lost by the system.

You may now connect those in and find a heat solution. The symbol on your heat indicates which way the flow was. Positive indicates that internal energy increased, which caused the system to gain heat; negative indicates that internal energy decreased, which caused the system to lose heat if that was the case.

like as U=300 and Work=75

The terms exothermic and endothermic simply denote whether heat is entering or exiting the system. Therefore, in this instance, we may conclude that it is endothermic since it absorbed heat because q ends up being 375, which is positive.

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What is the weight of a 72-kg astronaut on the Moon (g = 1.7 m/s2)?

Answers

W=117.36 N is the weight of a 72-kg astronaut on the Moon (g = 1.7 m/s2)

Equation

W=mg

W=72 kg *1.63 m/s²

W=117.36 N

Weight is force, and the Newton is its unit.

what is an astronaut?

An astronaut is a person who has been trained, outfitted, and sent into space by a human spaceflight programme to work as a commander or crew member on a spaceship. The word astronaut is derived from the Ancient Greek words v (astron), which means "star," and (nautes), which means "sailor." The phrase is occasionally used to refer to anyone who travels into space, including scientists, politicians, media, and tourists, despite the fact that it is typically designated for professional space travellers.

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A pring of force contant 120N/m i acted upon by a contant force of 240N. Calculate the elatic potential energy tored in the pring

Answers

A spring of force constant 120N/m is acted upon by a constant force of 240N. The elastic potential energy stored in the spring is 240 Nm.

The elastic potential energy stored in a spring is given by the formula:

= U = 1/2 x k x x^2

Where U is the elasticity potential energy, k is the force constant of the spring, and x is the displacement of the spring from its equilibrium position. In this case, the force constant of the spring is 120 N/m, and the constant force acting on the spring is 240 N. To find the displacement of the spring, we can use the formula:

= F = k x x

Where F is the force applied to the spring, k is the force constant, and x is the displacement.

Solving for x, we get:

= x = F / k

= 240 N / 120 N/m

= 2 m

Substituting this value for x into the formula for elastic potential energy, we get:

= U = 1/2 x 120 N/m x 2 m^2

= 240 Nm

So the elastic potential energy stored in the spring is 240 Nm.

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a rope goes from one building to another. the distance between the buildings is 12 m, and the rope is tied to each building at a point 8 m and 3 m high above the ground. find the length of the rope.

Answers

By using the Pythagorean Theorem, the Length of the rope is 13 m.

The Pythagorean Theorem states that the square of the length of the hypotenuse (in this case, the rope) is equal to the sum of the square of the lengths of the other two sides (in this case, the distance between the buildings and the difference in heights of the buildings).

The length of the rope can be calculated using the Pythagorean Theorem as:

Length of rope = √(12² + (8-3)²)

Length of rope = √(144 + 25)

Length of rope = √169

Length of rope = 13 m

Therefore, we can calculate the length of the rope by taking the square root of the sum of the squares of the distance between the buildings (12²) and the difference in heights of the buildings (8-3)².

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in the circuit shown in the figure (figure 1), find the magnitude of current in the upper branch.

Answers

0.8 A of current is flown through the upper branch of the circuit shown below:

as shown in the figure the current through lower loop is [tex]I_1+I_2[/tex] and the current through the upper loop is [tex]I_2[/tex].

the kirchoff's loop eqns in lower loop is:

 -4[tex]I_1[/tex] + 5 -[tex]I_1[/tex] - 10([tex]I_1+I_2[/tex]) = 0

=> 2[tex]I_1[/tex] +[tex]I_1[/tex] + 2[tex]I_2[/tex] = 1

=> 3[tex]I_1[/tex] + 2[tex]I_2[/tex] =1    ----- (i)

we have obtanied 1 equation

the kirchoff's loop eqns in upper loop is:

-3[tex]I_2[/tex] +10 -2[tex]I_2[/tex] + [tex]I_1[/tex] - 5 +4[tex]I_1[/tex] = 0

=> - 5  [tex]I_2[/tex] +10+ 5 [tex]I_1[/tex] -5 =0

=> [tex]I_2[/tex] -  [tex]I_1[/tex] =1     -------(ii)

solving equation (i) and equation (ii) we get

[tex]I_1[/tex] = -0.2

here negative sign represents that the current direction is opposite to our assumption.

so     [tex]I_2[/tex] = 1 + [tex]I_1[/tex]

=>     [tex]I_2[/tex] = 0.8A

So the current through the upper branch is 0.8A

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Complete question:

in the circuit shown in the figure , find the magnitude of current in the upper branch.

what is the frequency of damped vibration for a single degree of freedom system with a spring of stiffness k n/m, a mass of m kg and a damping ratio of 0.1?

Answers

The frequency of damped vibration for a single degree of freedom system is Wd = 0.99[tex]\sqrt{\frac{k}{m} }[/tex]

Calculation :

Natural frequency (Wn)= [tex]\sqrt{\frac{k}{m} }[/tex]

Damped frequency (Wd) = Wn[tex]\sqrt{1-s^{2} }[/tex]          (s = damping ratio)

=  Wn[tex]\sqrt{1-0.1^{2} }[/tex]

  = Wd = 0.99[tex]\sqrt{\frac{k}{m} }[/tex]

Frequency is the number of occurrences of a repeating event per unit time. For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events.

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which one of the following conditions would always result in an increase in the internal energy of a system? a. The system loses heat and does work on the surroundings.
b. The system gains heat and does work on the surroundings.
c. The system loses heat and has work done on it by the surroundings.
d. The system gains heat and has work done on it by the surroundings.

Answers

Option D; The system gains heat and has work done on it by the surroundings.

The force required to move an object a predetermined distance is referred to as the work done. It basically measures the amount of energy that is transmitted to or from an object to enable movement. The formula Work = Force Distance can be used to compute work. The joule (J) or Newton-meter (N-m) is the SI unit for work. When we apply a force called "F" to a block, the body moves with an acceleration or, additionally, its speed changes depending on the force's direction. The system's kinetic energy changes depending on whether the speed increases or decreases. Energy must be transformed into something other because, as we know, it cannot be created or destroyed.

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A ball is thrown upward. What is its initial vertical speed? The acceleration of gravity is 9.8 m/s^2 and maximum height is 4.4 m. Neglect air resistance.. Answer in units of m/s.

Answers

The initial velocity of the ball thrown to a maximum height of 4.4 m is 9.29 m/s.

What is velocity?

Velocity is the rate of change of displacement.

To calculate the initial velocity of the ball, we use the formula below.

Formula:

v² = u²+2gs.................Equation 1

Where:

v = Final velocity of the ballu = Initial velocity of the ballg = Acceleration due to gravitys = Maximum height reached by the ball

From the question,

Given:

v = 0 m/s (at the maximum height)g = - 9.8 m/s²s = 4.4 m

Substitute these values into equation 1 and solve for u

0 = u²+(-9.8×2×4.4)0 = u²-86.24u² = 86.24u = √86.24u = 9.29 m/s

Hence, the initial velocity is 9.29 m/s.

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The ball's initial vertical speed is 86.24m/s.

What is the acceleration of gravity?

This refers to the acceleration of a body in free fall under the influence of the earth's gravity. it can be represented as the rate of increase of velocity per unit of time. It is measured in meters per second square, m/s².It can be represented with the letter, g.

Formula for calculating  speed in free fall;

v = 2 * g * h

where,

v= speed / velocity

g = acceleration of gravity

h=  maximum height

Given in the question:

g = 9.8 m/s²

h = 4.4 m.

Substituting the values in the formula we have:

v = 2 * 9.8 m/s² * 4.4 m

v = 86.24m/s.

Hence, the ball's initial vertical speed is 86.24m/s.

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why is the uncertainity principle or the wave nature of particles not significant when looking at macroscopic objects

Answers

The uncertainty principle of the wave nature of particles does not matter as much when looking at macroscopic objects because, unlike microscopic objects, their location and velocity don't change when photons strike them.

The uncertainty principle states that an object's position and velocity can't be measured exactly at the same time. It applies commonly to particles that can only be observed using a microscope. That is because, for objects as small as them, when light strikes them, their location and velocity may get altered.

Macroscopic object, on the other hand, does not get any significant alteration by photons. While they may be altered, the amount is very minuscule that it has hardly any consequence, making the uncertainty principle insignificant for macroscopic objects.

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a 1.6-kg grindstone in the shape of a uniform cylinder of radius 0.20 m acquires a rotational rate of 24 rev/s from rest over a 6.0-s interval at constant angular acceleration. calculate the torque delivered by the motor.

Answers

Stone weight in kilograms, m = 1.6 0.2 m is the radius. The rotational rate torque of a di is = I I

What is the circumference of a shape?

It is the circumference of a circle. A radius can indeed be defined as a line drawn around the circle's perimeter from any point to its center. Depending on whether you know the circle's diameter, circumference, or area, you can calculate the radius using one of three formulas.

How do radius and diameter work?

The diameter of a circle cuts through the center, whereas the radius circumscribes the circle from edge to edge. The size of a circle essentially divides it in two.

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which of these correctly compares the masses of different objects in the universe?

Answers

In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.

Do stars have more mass than planets and less mass than galaxies?

A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.

What is the proper ranking of the universe's elements, from smallest to largest?

Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.

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the figure (figure 1) is a current-versus-potential-difference graph for a material. What is the material's resistance?

Answers

Resistance of material, R = 50 Ω

Ohm's law is one of the most fundamental and significant principles governing electrical circuits. Under the assumption that all physical parameters and temperatures stay constant, Ohm's law asserts that the voltage across a conductor is precisely proportional to the current flowing through it.

The German physicist Georg Ohm, who published a dissertation in 1827 describing measurements of applied voltage and current via basic electrical circuits with different lengths of wire, is credited with giving the rule its name.

Ohm's law, which modifies the connection between the voltage and the current by taking into account the resistance value, is crucial to understanding how electric circuits work.

As per the image attached below,

Using Ohm's Law,

V = I * R

At 100 v, current = 2 A

100 = 2 * R

R = 50 Ω

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The correct image of the questions is attached below:

in a liquid with a density of 1000 kg/m3, longitudinal waves with a frequency of 145 hz are found to have a wavelength of 10.0 m. calculate the bulk modulus of the liquid.

Answers

The bulk modulus of the liquid is  0.25 × [tex]10^{10}[/tex]Pa

Given  ρ = 1000kg/[tex]m^{3}[/tex],n = 145 HZ, λ = 10m

We have velocity of wave v = nλ

v = 145 × 10 = 1450m/s

The velocity of longitudinal wave in a liquid of density ρ  is given by.

V = √K/ρ

K = bulk modulus of liquid

1450 = [tex]\sqrt{K/1000}[/tex]

K = 0.25 × [tex]10^{10}[/tex]Pa

A substance's bulk modulus (sometimes written as "displaystyle K" or "displaystyle B") indicates how resistant it is to compression. It is described as the proportion between an increase in pressure that is infinitesimally small and the ensuing proportional decrease in volume. [1]

Shear and Young's moduli both explain how the material responds (strains) to different types of stress. The former defines how the material responds to shear stress, while the latter describes how the material responds to normal (lengthwise stretching) stress. Only the bulk modulus of a fluid has any significance. The entire generalized Hooke's law must be used to fully describe the behavior of a complex anisotropic solid like wood or paper because the information contained in these three moduli is insufficient.

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