the speed of a bobsled is increasing because it has an acceleration of 2.4 m/s2. at a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total 450 n. the combined mass of the bobsled and its riders is 270 kg. (a) What is the magnitude of the force propelling the boblsed forward?
(b) What is the magnitude of the net force that acts on the bobsled?

A pristine nickel surface with a work function of 5.1 eV is exposed to 206 nm light. The photoelectrons released from this surface have a maximum speed of 521.8 x 10^3 m/s.

An electron of the metal can receive photon energy from incident light, which is equal to the planck's constant times the light's frequency.

f = c/∧

assuming that all of the photon energy has been utilized

First in removing electrons from metals (work function)

Second, the leftover is used to furnish the photoelectron with kinetic energy:

V(m) = √2/M(hc/∧)-5.1eV.

where: M = 9.11 x10^3 kg; is the mass of nickel

h = 6.63 x 10 -34 Js; is plancks constant

c = 3 x 10^8 m/s; is the speed of light

∧ = wavelength of light = 206 nm = 206x10-9m

v(m) = (2 x 6.63 x 10-34 x 3 x10^8)/206 x 10-9 x 9.11x10^3 - 5.1 eV

v(m) =  521.8 x 10^3 m/s.

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Without an air resistance, a projectile fired horizontally at 8 km/s from a mountain top will:

All objects with mass or energy are drawn to one another by the basic interaction of gravity. Gravity is by far the weakest of the four fundamental interactions, and is greatly outweighed by the electromagnetic force, the weak interaction, and the strong interaction. As a result, it has little effect on phenomena occurring at the level of subatomic particles. However, gravity is the most significant interaction between objects at the macroscopic level and controls the motion of planets, stars, galaxies, and even light.

Similar to how gravity on the Earth gives weight to the physical objects, the Moon's gravity creates sublunar tides in the oceans (the corresponding antipodal tide is caused by the inertia of the Earth and Moon orbiting one another). Additionally, gravity is a key factor in variety of biological processes, such as gravitropism, which controls plant development, and  fluid movement in multicellular organisms. Research on consequences of weightlessness indicates that the gravity may have an impact on how the immune system and cells differentiate in the human body.

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The force that the table exerts on the box1 is 65.2N

As given in the question we are assuming box 2 and 3 aren't touching.

The forces on box 2 are:

gravitational force

Force of tension

Normal force

The box isn't accelerating so

T + N2 - Fg2 = 0

The forces acting  on the box 3 are:

gravitational force

Tension

Since box 3 isn't accelerating

T - Fg3 = 0

The tension force will be same in both cases so:

Fg3 + N2 - Fg2 = 0

So

N2 = Fg2 -Fg3

N2 = Fg2 - Fg3

= 39-25.3 = 13.7 N

Remember forces are equal and opposite.

Now,

write the equation for the forces which are acting on Block 1

There is the force of gravity

normal force acting from the table and

A force which is equal and is opposite to the normal force on block 2

N1 - F(g1) - N2 = 0

N1 = Fg1 +N2

N1 = 51.5 + 13.7 = 65.2 N

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A capacitor uses an electric field to store the potential electric energy which can be used as a power source when connected to a network.

A capacitor is characterized as a latent part which is utilized for putting away electrical energy. A capacitor is made of two conduits that are isolated by the dielectric material. These dielectric materials are as plates which can aggregate charges. One plate is for a positive charge while the other is for a negative charge.

The energy put away in a capacitor is only the electric possible energy and is connected with the voltage and charge on the capacitor. In the event that the capacitance of a guide is C, it is at first uncharged and it obtains a potential distinction V when associated with a battery. In the event that q is the charge on the plate around then,

q=CV

Therefore,Work done=Vdq

=>dW=(q/C)dq

=>dW=[tex]\int\limits^q_ 0[/tex](q/C)dq

=>dW=(1/2)q²/C

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A transceiver is a combination transmitter/receiver in a single bundle. while the time period normally applies to wireless communications gadgets, it is able to also be used for transmitter/receiver devices in cable or optical fiber structures.

The electricity of the antenna is given by,

The resistance of the antenna is steady, for this reason,

Pa(avy

Now the voltage difference is,

AV = Bjcos8

consequently, the voltage distinction is directly proportional to t

cosine of the angle.

AVecosé (because B and/are constant)

subsequently, the electricity received,

Paces

therefore, if the angle of the willing is 14.three°, then the

acquired electricity by the antennas,

Pm c0s414,3°=0,93899

Paw

93.9%

if the perspective of the inclined is 45°, then the

obtained electricity by means of the antenna is,

SP price a5¢=05

Pan

50%

if the perspective of the inclined is 90°, then the

received energy with the aid of the antennas,

Pn cos? 9%=

Paw

= 0.0%

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The percentage of mechanical energy lost (converted into thermal energy) during the collision will be equal to 95.2%.

Kinetic energy is the term used in physics to describe the force that a moving item has.

It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.

As per the information in the question,

Ball's mass, m₁ = 50 g = 0.05 kg

Speed  = v₀

Brick's Mass, m₂ = 1 kg

Assume the speed of the brick after the collision is v.

Use the equation of the principle of conservation of linear momentum,

[tex]m_1v_o+m_2u_2= v(m_1+m_2)[/tex]

0.5(v₀) + 0 = v(1 + 0.05)

v = (0.05v₀)/1.05

v = 0.048v₀.

Then the total kinetic energy will be:

K.E(initial) = 1/2 × 0.05v₀² + 1/2 × 0.05 × 0²

K.E(initial) = 0.025v₀²

Then,

K.E(final) = 1/2 × (1.05) × (0.048v₀)²

K.E(final) = 0.0012v₀²

So, the amount of mechanical energy lost in collision,

= (0.025v₀² - 0.0012v₀²)/0.025v₀² × 100

= 95.2%.

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This question seems incomplete, the complete question may be:

A 50 g ball of clay traveling at speed vo hits and sticks to a 1.0 kg brick sitting at rest on a frictionless surface. a. Find an expression for the speed of the brick after the collision in terms of vo. b. What percentage of the mechanical energy is lost (i.e. converted to thermal energy) in this collision?

Answer: Finally, we can use this value to find the final velocity of the 15.0 g coin. Since velocity is defined as the change in position over time, and the 15.0 g coin is initially at rest, its final velocity must be equal to its final momentum divided by its mass. Therefore, the final velocity of the 15.0 g coin is 187.5 g cm/s / 15.0 g = 12.5 cm/s. Since the 5.0 g coin is moving to the right and the 15.0 g coin is moving

Explanation: To solve this problem, we can use the conservation of momentum. Momentum is a measure of an object's motion and is defined as the product of its mass and velocity. In an elastic collision, momentum is conserved, meaning that the total momentum of the system before the collision is equal to the total momentum after the collision.

We can use this principle to find the final velocity of the 15.0 g coin. First, we need to calculate the initial momentum of the system. The 5.0 g coin has an initial momentum of 5.0 g * 25.0 cm/s = 125 g cm/s. Since the 15.0 g coin is initially at rest, its initial momentum is 0 g cm/s. The total initial momentum of the system is therefore 125 g cm/s.

After the collision, the 5.0 g coin moves to the left at 12.5 cm/s, so its final momentum is 5.0 g * (-12.5 cm/s) = -62.5 g cm/s. Since momentum is conserved, the final momentum of the system must be equal to the initial momentum of the system, so the final momentum of the 15.0 g coin must be 125 g cm/s - (-62.5 g cm/s) = 187.5 g cm/s.

Finally, we can use this value to find the final velocity of the 15.0 g coin. Since velocity is defined as the change in position over time, and the 15.0 g coin is initially at rest, its final velocity must be equal to its final momentum divided by its mass. Therefore, the final velocity of the 15.0 g coin is 187.5 g cm/s / 15.0 g = 12.5 cm/s. Since the 5.0 g coin is moving to the right and the 15.0 g coin is moving

The amount of labour that gravity does is 28.58J. And the work produced by kinetic friction is -28.58J. A force that acts between moving surfaces is referred to as kinetic friction.

We may determine the slope length or hypotenuse using elementary trigonometry: cos(20) = 2.00. (slope length)

slope length: 2.00 m/cos(20) = 2.13 m

The box covers this distance while moving at a constant speed.

In terms of the forces, the total force parallel to the inclined plane acting on the box is given by the equation: F = W - f = mgsin(20) - f, where f represents friction and W is weight.

Work = Wd = (+13.2N)(2.13m) = 28.58J, which is the amount of work done by the force of kinetic friction.

The force acts in the same direction as the displacement, resulting in work.

The kinetic friction force exerts the following work:

Work= -fd =(-13.42N)(2.13m) = -28.58J

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The sound pressure level where the microphone is located is 1.11mW/m2. 90.46dB of sound energy impinges on the microphone every second. Acoustic intensity, also referred to as sound intensity.

Is the amount of energy carried by sound waves in a direction perpendicular to the region of the wave that they are travelling. The watt per square metro (W/m) is the SI unit of intensity, which also covers sound intensity.

Given,

Sound's force P = 35 W

50 meter's separate the speaker of a mobile phone from its little microphone.

Sound intensity at a cellphone is I = P/A.

I am equal to 35/4*pi*r2 and 35/4*pi*(502).

I = 1.11mW/m^2

The sound pressure level where the microphone is located is b = 10log(I/Io).

b = 10log(0.00111/10-12), b = 90.46 dB.

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a. the force that the mountain climber must exert with her feet in N) on the vertical rock face to remain stationary is 273 N.

b. the minimum coefficient of friction between her shoes and the cliff is 0.268.

What is the term of friction?

The force that prohibits one solid object from traveling across another is known as friction. Static friction, sliding friction, rolling friction, and fluid friction are the four main categories of friction.

a).

Balancing the forces in x-direction,

F cos(15) = T sin(31)

F = T sin(31)/cos(15)     ...... (1)

balancing the forces in y-direction,

T cos(31) + F sin(15) = 52 x 9.8 = 509.6

T cos(31) + (T sin(31)/cos(15)) sin(15) = 509.6

T = (509.6 cos(15))/(cos(31) cos(15) + sin(31) sin(15))

T = 512 N

Force, F = 512 sin(31)/cos(15)

= 273 N

b)

Coefficient of friction,

u = sin(15)/cos(15)

= 0.268

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(a) The maximum height to which Superman can lift the water is 10.32874 m

(b) On the Moon there is no atmosphere so no atmospheric pressure which means when the straw is placed in water water will not rise in the tube.

Pₐ = Atmospheric pressure = 101325 Pa

g = Acceleration due to gravity = 9.81 m/s²

h = Height of water

ρ = Density of water = 1000 kg/m³

If the walls of the tube do not collapse that means that maximum pressure inside will be the atmospheric pressure

Atmospheric pressure is given by

Pₐ = ρgh

height = Pₐ /ρg

h = 101325 / 1000 * 9.81

h = 10.328 m

The maximum height is 10.32874 m.

(b) On the Moon there is no atmosphere so no atmospheric pressure which means when the straw is placed in water water will not rise in the tube.

Therefore, the maximum height to which Superman can lift the water is 10.32874 m.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Superman attempts to drink water through a very long vertical straw. With his great strength, he achieves maximum possible suction. The walls of the tubular straw don't collapse.

(a) Find the maximum height through which he can lift the water.

(b) Still thirsty, the Man of Steel repeats his attempt on the Moon, which has no atmosphere. Find the difference between the water levels inside and outside the straw.]

The correct answer is D. 14.3° toward the front of the car.

When a car accelerates horizontally, the forces acting on a mass hanging from the ceiling will cause the mass to swing in a circular path. The angle that the string makes with the vertical is determined by the centripetal acceleration of the mass, which is given by the equation:

a = v² / r

where a is the centripetal acceleration, v is the velocity of the mass, and r is the radius of the circular path.

In this case, the radius of the circular path is the length of the string (1.2 m), and the velocity of the mass is the velocity of the car (2.5 m/s). Plugging these values into the equation gives us a centripetal acceleration of:

a = (2.5 m/s)² / 1.2 m = 6.25 m/s²

The angle that the string makes with the vertical can be calculated using the tangent function:

tan(A) = a / g

where A is the angle, a is the centripetal acceleration, and g is the acceleration due to gravity (9.81 m/s²).

Plugging in the values for a and g gives us the following:

tan(A) = 6.25 m/s² / 9.81 m/s² = 0.636

Solving for A gives us:

A = [tex]tan^{-1(0.636)}[/tex] = 14.3°

Since the string is hanging toward the front of the car, the angle A is towards the front of the vehicle as well, so the correct answer is D. 14.3° toward the front of the vehicle.

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Force is 436.59 N and the speed is 1.746 kN.

A) Force F = P*A = 0.5*rho*v^2*A = 0.5*1.2*10.5^2*6*1.1 = 436.59 N

B) If v is doubled then F increases by 4 times since F is proportional to the square of the speed.

then F2 = 4*436.59 = 1746.35 N = 1.746 kN

A body can change its condition of rest or motion through the application of force, which is an external agent. It has. both a magnitude. and. a direction. The application of force is the point at which force is applied, and the direction in which the force is applied is referred to as the direction of the force. If motion is conceivable, gravitational forces can separate phases of various densities. One option is widespread melting, but high temperatures are not anticipated for the early Earth (Chapter 2). Sorting as a result of deeply buried ices outgassing is a more likely explanation. Such processes would have altered the moment of inertia, necessitating a modification of angular velocity.

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At the surface, the wind speed is between 13 to 17 knots. At 1 km or 850 MB level, the wind speed is between 48 to 52 knots. Thus, the 0-1 km wind shear is (48 -13) or (52-17) = 35 knots.

At 5 km or 500 MB level, the wind speed is between 68 to 72 knots. Thus, the 0-5 km wind shear is (68-13) or (72-17) = 55 knots.

Wind speed describes how fast air moves past a particular point. This can be averaged over specific time units. B. Miles per hour or instantaneous speed is reported as peak wind speed gust or squall. The wind is the natural movement of air or other gases against the surface of a planet.

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The voltages across the capacitor and inductor may be greater than the input voltage when the circuit is at or close to the resonance. The resistance voltage is 90 degrees behind the inductor voltage.

The VC (t) phasor has an amplitude of VC=I0XC and lags the i(t) phasor by /2 rad. The vL(t) phasor has the amplitude VL=I0XL and trails the i(t) phasor by /2 rad.

In a series LCR circuit, the voltage drop across the inductor or capacitor can, in fact, exceed the applied voltage of the a.c. source. VC or VL may be bigger than V since VC and VL have opposing faces. The RMS current for an applied V = volts RMS voltage is I = x 10 amperes. You may calculate the component voltages by multiplying the current.

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After 2seconds of sending sonar, a ship hears an echo. The depth of the sea is 1500 meters if the sound wave speed in water is 1500 m/s.

Let sea depth equal d.

Considering that the sound wave's water speed (v) is 1500 m/s

The sound must travel to the ocean's bottom before being reflected back to the ship, resulting in a total distance of two dimensions for the sound.

Time (t) = 2s for receiving the echo

Total distance traveled times the speed of sound

1500 m/s is equal to 2d/2s = 1500 m.

Consequently, the water is 1500 meters deep.

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a) D = -4273(x)-2327(y)

b) average speed v = 23.33m/s

c) average velocity V = -13.51m/s  south of west.

In order to find the displacement we have to divide the motion on its X and Y components:

dx1 = 25*2*60min = 3000

dx2 = 30*1*60s/min(cos45) = 1273 m

The total X displacement is the algebraic sum of the movement:

dx = -3000 - 1273 = -4273

We have to do the same on Y:

dy1 = 20*3*60 = 3600

dy2 = 30*1*60(sin45) = 1273

dy = -3600 + 1273 =-2327m

D=-4273(x)-2327(y)

The angle is given by:

α = arctg(dy/dx)

α = 28.57 degrees

That is 28.57 degrees south of west.

the total displacement magnitude is given by:

D = √{(4273) - (2327)}

D= 4865

The average speed is given by:

v = (20*3)+(25*2)(1*60)/6*60

v =23.33 m/s

and the Average velocity is given by:

|v| = 4865/6*60

|v| =13.51 m/s

Therefore, the average velocity is V = -1351 m/s with an angle of 28.57 degrees south of west.

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a) D = -4273(x)-2327(y)

b) average speed v = 23.33m/s

c) average velocity V = -13.51m/s  south of west.

In order to find the displacement we have to divide the motion on its X and Y components:

dx1 = 25*2*60min = 3000

dx2 = 30*1*60s/min(cos45) = 1273 m

The total X displacement is the algebraic sum of the movement:

dx = -3000 - 1273 = -4273

We have to do the same on Y:

dy1 = 20*3*60 = 3600

dy2 = 30*1*60(sin45) = 1273

dy = -3600 + 1273 =-2327m

D=-4273(x)-2327(y)

The angle is given by:

α = arctg(dy/dx)

α = 28.57 degrees

That is 28.57 degrees south of west.

the total displacement magnitude is given by:

D = √{(4273) - (2327)}

D= 4865

The average speed is given by:

v = (20*3)+(25*2)(1*60)/6*60

v =23.33 m/s

and the Average velocity is given by:

|v| = 4865/6*60

|v| =13.51 m/s

Therefore, the average velocity is V = -1351 m/s with an angle of 28.57 degrees south of west.

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The bonds that are broken during the reaction are weaker than the bonds that are formed during the reaction  and ∆Hrxn < 0

For exothermic reaction we know that Hpreducts < Hreactants

∆Hrxn = Hproducts - Hreactants

so, ∆Hrxn ​​​​​​< 0 , Energy is released while bond formation and energy is absorbed while bond breaking. In exothermic reaction energy is released, it indicate in exothermic reaction bonds that formed is stronger than bonds that are broken.

A chemical reaction that releases energy is called an exothermic reaction. A chemical reaction that stores energy is called an endothermic reaction. More energy might be released as products form than the energy needed to break the reactants apart.

Less energy might be released as the products form than the energy needed to break the reactants apart. This chemical reaction stores energy. In other words, it will be an endothermic reaction.

More energy is released during the chemical reaction than is needed to start the chemical reaction. It takes less energy to break the reactant bonds than the energy released as the products form.

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The vector quantity with a magnitude equal to the product of the two equal charges with opposing polarity separated by a distance, d, is defined as the electric dipole moment associated with it.

The distance between the charges and a direction running along the line between the charges from the negative to the positive charge.

Two charges totaling 10.0 C and spaced 2.00 cm apart make up the dipole. The positive charge is further away from the line of charge than the negative charge, and the dipole's axis forms a 35.0° angle with the x-axis.

The dipole will be subject to a force that is Charges 2.0108C separated by a distance of 2.0103m make up an electric dipole. As seen in the picture, it is positioned so that the negative charge is 2.0 cm away from a long line charge with a linear charge density of 4.0104Cm1. The pressure on the Axis.

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By knowing i. the time it takes for Jupiter to orbit the sun and ii. the time it takes for the moon to orbit Jupiter's mass of Jupiter can be determined. Therefore options I and II are correct.

To determine the mass of Jupiter, the student needs information about both Jupiter's orbit around the Sun (I) and the moon's orbit around Jupiter (II).

By knowing the time it takes Jupiter to orbit the Sun (I) and the time it takes for the moon to orbit Jupiter (II), the student can use Kepler's Third Law of Planetary Motion.

This law relates the orbital period and the average distance of a moon from its planet to the mass of the planet.

By knowing both the orbital periods of Jupiter and its moon (I and II) and the average distance between the moon and Jupiter (III is not required), the student can calculate the mass of Jupiter using Kepler's Third Law.

Therefore options I and II are correct.

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Its angular momentum vector of it is O.A. downward-pointing arrow with a clockwise motion and accelerating speed. no rotational (angular) characteristics. an upwardly directed arrow.

1. A negative angular velocity indicates that motion is in the clockwise direction. The object is speeding up because the signs of angular acceleration and velocity are both negative. Thus, turning in a clockwise direction and quickening.

2. The standard acceleration is equal to v2/R. Consequently, none of the rotational (angular parameters)

3. An arrow pointing up represents the top's angular momentum as it spins counterclockwise.

An object's or system of objects' angular momentum is a property that describes its rotational inertia as they move around an axis that may or may not pass through them. Due to its yearly rotation around the Sun and daily rotation about its axis, the Earth has both orbital and spin angular momentum. An accurate explanation of angular momentum necessitates the identification of both a magnitude and a direction because it is a vector quantity. An orbiting object's angular momentum is proportional to its linear momentum, which is the sum of its mass m and linear velocity v, multiplied by the perpendicular distance r from the center of rotation to a line drawn across its instantaneous motion.

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Yes, different metals expand by different amounts for the same rise in temperature. This is because different metals have different coefficients of thermal expansion, which is a measure of how much a material expands when it is heated. This means that when two different metals are heated by the same amount, they will expand by different amounts.

For example, if a metal with a high coefficient of thermal expansion is heated by 10 degrees Celsius, it will expand by a larger amount than a metal with a low coefficient of thermal expansion that is heated by the same amount. This means that different metals will expand by different amounts for the same rise in temperature, depending on their specific properties.

Additionally, the expansion of metals can also be affected by factors such as the initial temperature of the metal and the rate at which it is heated. This means that the expansion of a given metal can also vary depending on the specific conditions under which it is heated. Overall, different metals will expand by different amounts for the same rise in temperature, depending on their specific properties and the conditions under which they are heated.

Given,

          Speed of wind v = 10.5 m/s

          Dimension of plate = 6 m times 1.10 m

          The density of air d = 1.20 kg/m³

Therefore,

         F = (1/2)dv²A

         A = 6(1.10)m²           [From dimension]

         F = (1/2)(1.20)(10.5)²(6)(1.10)

         F = 436.59 N

The force on the window pane is 436.59 N.

(a) if the wind speed is 21 m/s

        F = (1/2)(1.20)(21)²(6)(1.10)        

        F = 1746.36 N

The force on the window pane is 1746.36 N.

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In the operating system's command-line shell, parameters are provided after the program's name. Typically, we define main() with two arguments: a list of command-line arguments and a number representing the number of command-line arguments.

We'll talk about utilizing the Environment class to retrieve and show command-line arguments in this article. Therefore, we use the Environment Class's CommandLine property to do this task. To locate the command line for the active process, utilize this attribute. Message Type: This property returns a string as its return type.

Only the main() method can accept parameters from the command line.

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The correct option is A. Slow down slightly, Before going right, give the right signal, check the driver's outside mirror, and turn your head to the right. On a roadway with several lanes, you are changing lanes in traffic.

On a roadway with several lanes, you are changing lanes in traffic. Maintain the same pace as you begin to turn into the opposite lane. The tracks your vehicle's rear tyres leave when rounding a corner are almost always narrower than the tracks your front tyres leave. To change your course, you can either do a two-point turn, a U-turn, or circle the block counterclockwise. You can most effectively reduce your risk by On a street with multiple lanes, the one you are in is blocked in front of you.

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What is a centripetal force ?

A force could be a force that produces a body follow a incurvate path. Its direction is usually orthogonal to the motion of the body Associate in Nursingd towards the fastened purpose of the fast center of curvature of the path.

A centripetal force is a web force that acts on an object to stay it moving on a circular path.

Centripetal vs Centrifugal Force. the most distinction between centripetal force and force is that solely the previous will actually be delineate as a “force.”

A Merry-go-round.

The Gravitron.

Tetherball.

A construction Swing.

Turning during a car.

Planet Earth.

Discus Throw.

V' = 2V

Centripetal force

F' = m V'2 / r

m( 2V)2 / r

= 4mv2 / r

Hence final centripetal force is 4mv2 / r

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The velocity of water exiting nozzle is 14.2 m/s.

What is velocity ?

It measures how quickly a distance changes. It is the rate at which displacement is changing.

What is pressure?

Pressure is the force applied perpendicularly to an object's surface in relation to the area across which it is dispersed.

New same height so h₂=h₁

new position p₂= 101300 pa and velocity v₂

water density p₂= 1000kg/m

gravity = 9.8m/s

V₁²= 2/p (p₁-p₂)

4+2/1000 ( 20000- 101300 )

=20.14

v₂= [tex]\sqrt{20.14}[/tex]

= 14.2 m/s

Therefore, the velocity of water exiting nozzle is 14.2 m/s.

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The magnitude of the electric field due to the slab at the center of the slab 2 = 0) is rho X³/ 3d²E.

An electric field is a physical field that surrounds a charged particle and exerts a force on all other charged particles in the field, causing them to attract or repel. It also refers to the physical field of a charged particle system.

Calculation:-

The equation can be written as for the slab at centre is E = rho X³/ 3d²E.

An electric field can be defined as the region of space around a charged particle or object in which the charged body experiences a force. For example, Electric fields are created by charges and their components such as capacitors and battery cells. An electric field can be thought of as an electrical property associated with any point in space where some form of electric charge exists.

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The two lamps, the one with a thick filament and one with a thin filament of the same material, are connected in parallel to a battery. The current is the same in both lamps.

The correct option is b

Current is a drift of electrical fee vendors, commonly electrons or electron-poor atoms. The commonplace image for modern is the uppercase letter I. the same old unit is the ampere, symbolized by way of A.

An electric current is a float of charged particles. In metal conductors the charged particles are unfastened electrons. The electrons are free to transport from one ion to another and a internet glide of those electrons in one path is an electric modern-day.

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Answer:

50

Explanation:

100×50÷1000= 50

this is easy question