Answer: the standard deviation STD of machine B is s (Lb) = 0.4557
Explanation:
from the given data, machine A and machine B produce half of the rods
Lt = 0.5La + 0.5Lb
so
s² (Lt) = 0.5²s²(La) + 0.5²s²(Lb) + 0.5²(2)Cov (La, Lb)
but Cov (La, Lb) = Corr(La, Lb) s(La) s(Lb) = 0.4s (La) s(Lb)
so we substitute
s²(Lt) = 0.25s² (La) + 0.25s² (Lb) + 0.4s (La) s(Lb)
0.4² = 0.25 (0.5²) + 0.25s² (Lb) + (0.5)0.4(0.5) s(Lb)
0.64 = 0.25 + s²(Lb) + 0.4s(Lb)
s²(Lb) + 0.4s(Lb) - 0.39 = 0
s(Lb) = { -0.4 ± √(0.16 + (4*0.39)) } / 2
s (Lb) = 0.4557
therefore the standard deviation STD of machine B is s (Lb) = 0.4557
- The four leading causes of death in the
construction industry include electrical
incidents, struck-by incidents, caught-in or
caught-between incidents, and
a. vehicular incidents
b. falls
C. radiation exposure
d. chemical burns
Two wooden members of uniform rectangular cross section are joined using a simple glued scarf splice. The maximum allowable shearing stress and maximum allowable normal stress in the glued splice is 50 MPa and 100 MPa, respectively. The cross-section area of the glued member is 400 mm2. (a) What should the value of the angle be to achieve maximum load Fmax? (b) What is the magnitude of the maximum load Fmax?
Answer:
a). α = 26.57
b). Maximum load is 50 .kN
Explanation:
a).
The normal force is given by
N = σ A cosec β
where, σ is the normal stress
A is the cross sectional area
Similarly, shear force is given by
S= τ A cosec β
where, τ is the shearing stress
Now from the figure,
tan β = S/N
= τ/σ
Therefore, [tex]$\beta = \tan^{-1}(2)$[/tex] = 63.43
α = 90 - β = 26.57
b).
The normal force is given by
[tex]$N=(100\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43$[/tex]
[tex]$N=44.78\times 10^3$[/tex] N
We have
[tex]$\Sigma F_y=0$[/tex]
∴ N - F sin β = 0
⇒ F = N / sin β
= [tex]$\frac{44.72\times 10^3}{\sin(63.43)} = 50\times 10^3 N$[/tex]
Similarly,
The shear force is given by
S = τ A cosec β
= [tex]$(50\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43 = 22.36\times 10^3 N$[/tex]
[tex]$\Sigma F_x=0$[/tex]
∴ S - F cos β = 0
⇒ F = S / cos β
[tex]$\frac{22.36\times 10^3}{\cos(63.43)} = 49.99\times 10^3 N$[/tex]
Therefore, force is 50 kN.
This ball is technology too! It can be
rolled, kicked, or thrown. Is that a need
or a want?
That is an example of a want because you don't need the ball.
An eyewash station needs to be located no more than 10 seconds or less than 55 feet away from a work area.
Answer: True is correct
A third-degree burn may look charred and black or dry and white.
Explanation:
Help me for this question
Wheel grinders need be equipped with an
Answer:
wheel guard
Explanation:
to protect our hands and reduce spark
how do you make coke for steel?
1. Looking at the case study provided under the Companion Material section, what is the main problem that is addressed in this case study? Maintenance workers painted over the pipes. Engineers lost all of their work because of the flood. The water pipes broke and flooded the space center. There was no paperwork for the maintenance work done on the pipes.
Incomplete question. However, I provided information that could assist you in identifying the main problem or issue addressed in any case study.
Explanation:
First, note that a case study is simply a learning aid that allows one to learn from a real-life scenario.
To determine the main problems of a case study one needs to:
Read the case as many times as possible to become familiar with the message been expressed. For example, by highlighting or underlining the most important facts it can help you to discover the main problem or issue. Check for any facts provided in the case study, by so doing you can identify the most important problems.Thus, by taking these few steps you may be able to determine the main problem in that case study.
An input voltage of 9.2 V is to be converted into its digital counterpart using an analog-to digital converter. The voltage range is 0 to 16 V. The ADC has 4-bit capacity. Determine: (a) What are the number of quantization levels, resolution, and the maximum quantization error of this ADC
Answer:
ask someone u fool hhhhhhhh
Five kg of water is contained in a piston–cylinder assembly, initially at 5 bar and 240°C. The water is slowly heated at constant pressure to a final state. The heat transfer for the process is 2660 kJ and kinetic and potential energy effects are negligible. Determine the final volume, in m3, and the work for the process, in kJ.
Answer:
Explanation: that’s the answer! 46kg
A boiler is designed to work at 14bar and evaporate 8 kg/s of water. The inlet water to the boiler has a temperature of 400C and at exit the steam is 0.95 dry. The flow velocity at inlet is 10 m/s and at exit 5 m/s and the exit is % m above the elevation at entrance. Determine the quantity of heat required. What is the significance of changes in kinetic and potential energy on the result.
Answer:
Explanation: 2 is thy answer
Which of the following was an effect of world war 2 on agricultural industry
Answer:
Option C..Farmers saught new technology to help with the workload
hope this helped you
please mark as the brainliest (ㆁωㆁ)
You are an engineer working in a auto crash test lab. Some members of your team have raised objections against the use of cadavers in the crashes. No reliable data exists that shows that cadavers produces more accurate data, but many coworkers argue that common suggest they do. Others claim that the use of cadavers as mere instruments for our well-being disrespects those individuals, who have not consented to use their bodies for this purpose. The question of whether to continue to use cadavers in the lab is what kind of issue?
Answer: Application.
Explanation:
The question on wether to contine the use of cadavers in the lab for test is being centered around its application. Cadaver which is same as a corpse or dead body is used in crash site during automobil test in lab, some of this cadavers are been disrespected with their applications in the automobile industries because many didn’t consent to be used in those experiments or test.
You have a piece of film paper that is 3 in x 5 in. You fix it inside the back of a pinhole camera with a focal length of 5.5 in. You want to use it to take a picture of your team’s mascot – a giant guinea pig that just barely fits in a 4 ft. tall cube. The picture will be taken directly in front, from a stool that places the aperture 2 ft. above the ground. You have to determine how far away the camera must be from your mascot to get a good portrait that fills up the whole film paper, without cutting any part of him off. How far apart should the camera and the mascot be to take the portrait? Show your work.
Answer:
In order to take a portrait, the distance of the mascot from the camera should be approximately 7.33 feet
Explanation:
The size of the film paper = 3 in. × 5 in.
The focal length of the camera = 5.5 in.
The height and width of the guinea pig = 4 ft.
The height of the aperture above the ground = 2 ft.
Therefore, we have;
Magnification = Height of image/(Height of object)
Withe the 3 in. wide film, we have;
Magnification = 3 in./(4 ft.) = 3 in./(48 in.) = 0.0625
Magnification = Length of camera/(Distance of object from pin hole)
∴ Length of camera/(Distance of object from pin hole) = 0.0625
Length of camera = Focal length of the camera = 5.5 in.
Therefore;
5.5 in./(Distance of object from pin hole) = 0.0625
Distance of object from pin hole = 5.5/0.0625 = 88 inches = 7.33 ft
Therefore, the camera should be approximately 7.33 ft. from the mascot to take a portrait.
In this exercise we have to use the magnification knowledge to calculate the distance that the photograph should be taken, thus we have to:
Distance of the mascot from the camera should be approximately 7.33 feet
To calculate the best distance to take the photo, we have that some information must be taken into account such as:
Size of the film paper: [tex](3)*(5) in[/tex] Focal length of the camera: [tex]5.5 in[/tex] Height and width of the guinea pig: [tex]4 ft[/tex] Height of the aperture above the ground: [tex]2 ft[/tex]
Therefore, we have that the formula of magnification is:
[tex]Magnification = Height \ of \ image/(Height \ of \ object)[/tex]
With the 3 in wide film, we have;
[tex]Magnification = 3 in/(4 ft) \\= 3 in/(48 in) = 0.0625 in[/tex]
Rewriting the magnification formula as:
[tex]Magnification = Length \ of \ camera/(Distance \ of \ object \ from \ pin \ hole)[/tex]
Substituting the values already known we have the equation will be matched as:
[tex]Length\ of \ camera/(Distance\ of\ object \ from \ pin \ hole) = 0.0625\\Length \ of \ camera = Focal \ length \ of \ the \ camera = 5.5 in.[/tex]
Therefore;
[tex]5.5 /(Distance \ of \ object\ from \ pin\ hole) = 0.0625 in\\Distance \ of \ object\ from \ pin \ hole = 5.5/0.0625\\ = 88 inches = 7.33 ft[/tex]
See more about distance at brainly.com/question/989117
How can you safely lift and support a vehicle
Answer:
Place the jack under the part of the vehicle that it should contact when raised. If you're using jack stands, place them near the jack. If you place your jack incorrectly, you can injure your car. To find the proper place to position the jack for your particular vehicle, check your owner's manual.
You are designing an airplane to carry liquid cargo that will slosh and move side to side in its container. This could make the plane unstable. What type of airfoil would you use for the wing? Why. Answer in a full sentence or more
The easiest way to reduce your exposure to dangerous fumes is to keep your head out of a fume plume, making sure that you're breathing the cleanest air possible.
Answer:
keep your head out of a fume plume
Explanation:
According to the guidelines and precaution procedures of OSHA, an acronym for Occupational Safety and Health Administration in the United States of America stated that The easiest way for an individual to reduce his or her exposure to dangerous fumes is to ensure that such person keeps his or her head out of a fume plume.
Hence, in this situation, the correct answer is "keep your head out of a fume plume"
What is the transfer of energy from one object to another?
Answer:
Kinetic Energy
Explanation:
Energy is transferred from one object to another when a reaction occurs. Energy can be transferred from one object to another as heat, light, and motion.
__________ use cleaning solutions that eventually become spent and must be disposed of properly
a sump pits
b car washers
c part washers
d tire cleaners
Answer:Part washers
Explanation:
I did it..
The only option that uses cleaning solutions that become spent and must be disposed properly is;
Option C; Parts Washers
To answer this question, let us examine each option;
Option A; Sump Pits; These are basins at the lowest part of specific areas designed to allow all water collected in that basin area to drain into it. This has no business with cleaning solution.
Option B; Car washers; These are like machine dryers used to clean the exterior and interior parts of motor vehicles.
Option C; Part Washers; These are mechanical devices that are designed for cleaning to remove debris, grime, oil dirt, paint, and other substances that could potentially cause contamination from parts in order to get them ready for assembling, packaging, or even coating. They are basically used to clean parts to get them ready for functional use.
Option D; Tire cleaner is just used to clean tire but is not something that becomes spent and should be disposed properly as it is more like a liquid.
The only correct option is Option C.
Read more at; https://brainly.com/question/25024807
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields under a load of 97,944 N. The corresponding gage length = 50.2 mm - this is at the 0.2 percent yield point. The maximum load of 162,699 N is reached at a gage length = 63 mm. If fracture occurs at a gage length of 71 mm, determine the percent elongation in % - enter your answer as a whole number, not as a fraction.
Answer:
The percent elongation in the length of the specimen is 42%
Explanation:
Given that:
The gage length of the original test specimen [tex]L_o[/tex] = 50 mm
The final gage length [tex]L_f[/tex] = 71 mm
The area = 206 mm²
maximum load = 162,699 N
To determine the percent elongation in %, we use the formula:
[tex]\%EL = \dfrac{L_f-L_o}{L_o}\times 100[/tex]
[tex]\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100[/tex]
[tex]\%EL = \dfrac{21 mm}{50 \ mm}\times 100[/tex]
[tex]\%EL = 0.42 \times 100[/tex]
[tex]\mathbf{\%EL = 42 \%}[/tex]
The percent elongation in the length of the specimen is 42%
12. You need to be at the lift controls whenever the lift is in motion A) True B)False
the answer to that would be a) true
What are materials engineers trying to discover when they study different materials? Whether or not materials corrode and oxidize how materials perform and deteriorate if certain materials have been used in the past and at which historical ages which metals conduct heat
Answer:
Material engineers study various materials to discover the reason and cause of its existence, the chemical properties, how long it has been there, and how it impacts human life.
Explanation:
Material engineer is an engineering discipline that focuses to improve human life by studying the environment and the various elements or materials it holds.
It uses the power of pure science to test and analysis its findings, documents its features and exposes them to the world. Materials like metals and other elemental forms were all tested by these engineers to determine its history and chemical and biological use.
Answer:
how materials perform and deteriorate
Explanation:
for high-volume production runs, machining parts from solid material might not be the best choice of manufacturing operations because
Answer:
There are actually multiple types of processes a manufacturer uses, and those can be grouped into four main categories: casting and molding, machining, joining, and shearing and forming.
Explanation:
what type of diagrams can you create using a compass, a T-square, a triangle, and a protractor?
Answer:
15
Explanation:
A compass may be used to create circles, arcs, bisect lines, angle bisectors, and locate midpoints. By using a compass, a protector is also drawn.
What is the compass?A compass, or more correctly, a pair of compasses, is a tool for technical drawing that may be used to draw arcs or circles. It can also be used as dividers to indicate distances, particularly on maps.
A compass, or more correctly, a pair of compasses, is a tool for technical drawing that may be used to draw arcs or circles. It may also be used as dividers to indicate distances, particularly on maps. Compasses can be used for navigation, mathematics, and other things.
Therefore, a protector is sketched using a compass.
Learn more about the compass, refer to:
https://brainly.com/question/28136911
#SPJ2
What do we need to build a car?
i need solution for this question please
Select the right answer
Explanation:
the 7th one answer is beacause mercury is bad at sharing electrons
the 8th one's answer is Rhodium
Answer:
1.E aluminum
2.E all
3. Either d or e leaning to e
Block B has a mass of 27g and a density of 0.9 g/mL. What is the volume of block B? Will it float in water? (density of water is 1.0 g/mL) Don't forget the units.
Steam enters a two-stage adiabatic turbine at 8 MPa and 5008C. It expands in the first stage to a state of 2 MPa and 3508C. Steam is then reheated at constant pressure to a temperature of 5008C before it is routed to the second stage, where it exits at 30 kPa and a quality of 97 percent. The work output of the turbine is 5 MW. Assuming the surroundings to be at 258C, determine the reversible power output and the rate of exergy destruction within this turbine.
Answer:
1) The exergy of destruction is approximately 456.93 kW
2) The reversible power output is approximately 5456.93 kW
Explanation:
1) The given parameters are;
P₁ = 8 MPa
T₁ = 500°C
From which we have;
s₁ = 6.727 kJ/(kg·K)
h₁ = 3399 kJ/kg
P₂ = 2 MPa
T₂ = 350°C
From which we have;
s₂ = 6.958 kJ/(kg·K)
h₂ = 3138 kJ/kg
P₃ = 2 MPa
T₃ = 500°C
From which we have;
s₃ = 7.434 kJ/(kg·K)
h₃ = 3468 kJ/kg
P₄ = 30 KPa
T₄ = 69.09 C (saturation temperature)
From which we have;
h₄ = [tex]h_{f4}[/tex] + x₄×[tex]h_{fg}[/tex] = 289.229 + 0.97*2335.32 = 2554.49 kJ/kg
s₄ = [tex]s_{f4}[/tex] + x₄×[tex]s_{fg}[/tex] = 0.94394 + 0.97*6.8235 ≈ 7.563 kJ/(kg·K)
The exergy of destruction, [tex]\dot X_{dest}[/tex], is given as follows;
[tex]\dot X_{dest}[/tex] = T₀ × [tex]\dot S_{gen}[/tex] = T₀ × [tex]\dot m[/tex] × (s₄ + s₂ - s₁ - s₃)
[tex]\dot X_{dest}[/tex] = T₀ × [tex]\dot W[/tex]×(s₄ + s₂ - s₁ - s₃)/(h₁ + h₃ - h₂ - h₄)
∴ [tex]\dot X_{dest}[/tex] = 298.15 × 5000 × (7.563 + 6.958 - 6.727 - 7.434)/(3399 + 3468 - 3138 - 2554.49) ≈ 456.93 kW
The exergy of destruction ≈ 456.93 kW
2) The reversible power output, [tex]\dot W_{rev}[/tex] = [tex]\dot W_{}[/tex] + [tex]\dot X_{dest}[/tex] ≈ 5000 + 456.93 kW = 5456.93 kW
The reversible power output ≈ 5456.93 kW.
What allows negative feedback to control a system
Answer:
Negative feedback control of the amplifier is achieved by applying a small part of the output voltage signal at Vout back to the inverting ( – ) input terminal via the feedback resistor
Answer:
The system has parts that sense the amount of output
Explanation:
Apex cirtified
What is the period if the clock frequency is 3.5 GHz?
Answer:
Period = 0.2857 nanoseconds
Explanation:
We are told that frequency = 3.5 GHz
This is simply 3.5 × 10^(9) Hz
Now, from wave equations, Period is given by the formula;
Period = 1/frequency
Thus;
Period = 1/(3.5 × 10^(9))
Period = 0.2857 × 10^(-9) seconds
From conversions, we can simplify the answer.
1 second = 10^(-9) nanoseconds
Thus, 0.2857 × 10^(-9) seconds = 0.2857 × 10^(-9) × 10^(-9) nanoseconds = 0.2857 nanoseconds