The figure below shows parallelograms ABCE, PQRS, and TNLM on a coordinate plane.
• Points S, P, Q, and Rare midpoints of ABCE
• T, N, L, and Mare midpoints of PQRS
Write the equation of line ML. Show your work.

Answer:x=8/3  ; y=13/3

Step-by-step explanation: to find the intersection point or the solution of the graph, you need to equate these equations  1) y=5x-9   2) x+y=7 =>  y=7-x x                                                                  equating the equations       5x-9=7-x  => 6x=16 => x=8/3  ; y=13/3  

Answer:

    x            y

    -1           2

    0           3

    1            1

     2          -1

Step-by-step explanation:

Answer:

C < $75.

Step-by-step explanation:

Let C be the charge of a window cleaning service, that cleans all the windows of the house.

Since it charges less than $75. this means

C < $75.

So, this is the required inequality equation.

Answer:

45

Step-by-step explanation:

9x5=45

Answer:

45

Step-by-step explanation:

9t

substitute 5 for t

9(5)

9(5) is the same as 9 * 5

9 * 5 = 45

so when t = 5 the output is 45

Answer:

[tex]x= 23.775.[/tex]

Step-by-step explanation:

[tex]\text{We have} \\\cos(18\textdegree) = \frac{x}{25} \\\Rightarrow x= 25\cos(18\textdegree)\\\Rightarrow x= 25 \times 0.951\\\Rightarrow x= 23.775.[/tex]

Answer:

The Coordinates are (3, 1)

Step-by-step explanation:

Use the substitution method to solve the system of equations.

Let y = x - 2 be Equation 1

Let y = -2x + 7 be Equation 2

We know that the coordinates are (3, 1) because we graphed the slope intercept equations in part one. Its asking to use the substitution method to prove that the coordinates (3, 1) are viable or satisfies both Equation 1 and 2.

The substitution method is nothing but substituting x and y back into the equation to prove that the coordinates are viable.

For this I'll use equation 1 first,

y = x - 2

1 = 3 - 2

So yes, the coordinates (3, 1) satisfy Equation 1

Lets check equation 2 now,

y = -2x + 7

1 = -2*3 + 7

1 = -6 + 7

This is also another equation where the coordinates (3, 1) satisfy equation 2

So this means that the coordinates (3, 1) are viable for both equations

Hope this helps!

Answer:

There is a 50% chance of getting a odd number.

Step-by-step explanation:

1-10 have 5 old numbers and they are 1, 3, 5, 7, and 9.

5/10 = 0.5 = 50%

5 out of 10

Answer:

-10

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

when r = 10

3r = 10 + 5s

3(10) = 10 + 5s

30 = 10 + 5s

30 - 10 = 10 + 5s -10

20 = 5s

20/5 = 5s/5

4 = s

Answer:

No solution because there is no c variable

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

10725

Step-by-step explanation:

C [tex]\frac{2}{c}[/tex] [tex].[/tex] C [tex]\frac{4}{13}[/tex]  =    [tex]\frac{6x5}{2}[/tex]  °      [tex]\frac{13x12x11x10}{4x3x2x1}[/tex]

=  10725

Answer:

I think 2 points

Step-by-step explanation:

I may be wrong bc I suck at algebra. literally who is gonna use algebra ever?

Answer: two points hope it helps

Answer:

15

Step-by-step explanation:

The y- intercept is the value of y on the y-axis where the line crosses.

The line crosses the y- axis at 15 ← y- intercept

Answer:

It is proved .

Step-by-step explanation:

[tex]\alpha +\beta +\gamma =\pi.....(1)\\\\sin\alpha + sin\beta +sin\gamma=4 cos\frac{\alpha}{2}cos\frac{\beta}{2}cos\frac{\gamma}{2}[/tex]

Take LHS

[tex]=sin\alpha + sin\beta +sin\gamma\\\\=2 sin \frac{\alpha +\beta }{2} cos\frac{\alpha -\beta }{2} + sin\gamma\\\\=2 sin\frac{180-\gamma}{2}cos \frac{\alpha - \beta}{2}+2 sin\frac{\gamma}{2}cos\frac{\gamma}{2}\\\\=2 cos\frac{\gamma}{2}cos \frac{\alpha - \beta}{2}+2 sin\frac{\gamma}{2}cos\frac{\gamma}{2}\\\\=2 cos\frac{\gamma}{2}\left [ cos \frac{\alpha - \beta}{2}+sin\frac{180-\alpha-\beta}{2}\\ \right ]\\\\=2 cos\frac{\gamma}{2}\times 2 cos\frac{\alpha}{2}cos\frac{\beta}{2}\\[/tex]

[tex]=4 cos\frac{\alpha}{2}cos\frac{\beta}{2}cos\frac{\gamma}{2}[/tex]

Hence proved.

Answer:

8d + 6b = 55

2d + 9b = 32.50

Step-by-step explanation:

let 'd' = # dog bowls

let 'b' + # bones

Rhonda:  8d + 6b = 55

Kelly:  2d + 9b = 32.50

we can multiply Kelly's equation by -4 to eliminate the 'd' terms:

Kelly: -4(2d + 9b) = 32.5(-4)

-8d - 36b = -130

now add the above equation to Rhonda's equation:

  -8d - 36b = -130

+  8d + 6b = 55

-30b = -75

b = 2.50

now we can use either equation and substitute 2.5 for 'b' to find 'd'

2d + 9(2.5) = 32.5

2d + 22.5 = 32.5

2d = 10

d = 5

Answer:

AB = A'B', AD = A'D', CD = C'D', CB = C'B'

Step-by-step explanation:

There is more then one way to give this problem a solution. The point of the question is to explain or provide an argument that will prove that the square ABCD is the same as A'B'C'D.

The way to prove it is by saying that the sides are equal, meaning the answer I provided above, by claiming that side AB is also equal to A'B', and so forth with all four sides.

Answer:

The angle is 60°

Step-by-step explanation:

A supplement angle is the angle whose sum is equal to 180°.

The supplement angle = 180° - x

A complement angle is the angle whose sum is equal to 90°.

The complement angle = 90° - x

Given,

supplement angle = 4 × complement angle

(180° - x) = 4 × (90° - x)

180° - x = 360° - 4x

4x - x = 360° - 180°

3x = 180°

x = 60°

The supplement angle = 180° - x

⇒ 180° - 60°

⇒ 120°

The complement angle = 90° - x

⇒ 90° - 60°

⇒ 30°

Answer:

The angle is 60 degrees.

Step-by-step explanation:

Let the angle be x.

Then its supplement = 180-x.

Its complement = 90-x, so we have the equation:

180 - x = 4(90 - x)

180 - x = 360 - 4x

-x + 4x = 360 - 180

3x = 180

x= 60 degrees.

Answer:

1550m^3

Step-by-step explanation:

Volume of the prism= 7750m^3

Factor of dilated prism= 1/5

7750×1/5= 1550m^3

Answer:

1/4

Step-by-step explanation:

Add the three amounts:

25 ml + 30 ml + 45 ml = 100 ml

These three amounts make 100 ml of fruit cocktail.

The amount of orange juice is 25 ml.

The fraction of orange juice is

(25 ml)/(100 ml) = 25/100 = 1/4

Answer: 1/4

Answer:

D)

Step-by-step explanation:

All sides are congruent because all sides are the same.

Hope this helps!

-kiniwih426

Given:

The given equation is:

[tex]y=-4x+3[/tex]

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

[tex]y=mx+b[/tex]

Where, m is slope and b is y-intercept.

We have,

[tex]y=-4x+3[/tex]

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

[tex]m\times (-4)=-1[/tex]

[tex]m=\dfrac{-1}{-4}[/tex]

[tex]m=\dfrac{1}{4}[/tex]

The slope of required line is [tex]m=\dfrac{1}{4}[/tex] and it passes through the point (4,-1). So, the equation of the line is:

[tex]y-(-1)=\dfrac{1}{4}(x-4)[/tex]

[tex]y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}[/tex]

[tex]y=\dfrac{1}{4}x-1-1[/tex]

[tex]y=\dfrac{1}{4}x-2[/tex]

Therefore, the equation of the required line is [tex]y=\dfrac{1}{4}x-2[/tex].

Answer:

[tex]5x^2-9x-1[/tex]

Step-by-step explanation:

f - g

[tex]=5x^2-4x -(5x+1)\\\\=5x^2-4x-5x-1\\\\=5x^2-9x-1[/tex]

Answer:

1256cm^2

Step-by-step explanation:

The area of a circle is πr^2.

The radius is half of the diameter, so it's 20 cm.

A=3.14*(20cm)^2

A=3.14*400cm^2

A=1256cm^2

Answer:

[tex]\text{C) } y=1[/tex]

Step-by-step explanation:

A asymptote represents a control for a function where the function will never touch. We see that as the [tex]y[/tex] approaches 1, [tex]x[/tex] approaches infinity, from either direction. However, the function never touches nor crosses the line [tex]y=1[/tex], and never will. Thus, the horizontal asymptote is located at [tex]y=1[/tex].

y=0 is correct answer but is not in the selection.

Step-by-step explanation:

SOLUTION

For these solutions, we will use \displaystyle f\left(x\right)=\frac{p\left(x\right)}{q\left(x\right)}, q\left(x\right)\ne 0f(x)=

q(x)

p(x)

,q(x)≠0.

\displaystyle g\left(x\right)=\frac{6{x}^{3}-10x}{2{x}^{3}+5{x}^{2}}g(x)=

2x

3

+5x

2

6x

3

−10x

: The degree of \displaystyle p=\text{degree of } q=3p=degree of q=3, so we can find the horizontal asymptote by taking the ratio of the leading terms. There is a horizontal asymptote at \displaystyle y=\frac{6}{2}y=

2

6

or \displaystyle y=3y=3.

\displaystyle h\left(x\right)=\frac{{x}^{2}-4x+1}{x+2}h(x)=

x+2

x

2

−4x+1

: The degree of \displaystyle p=2p=2 and degree of \displaystyle q=1q=1. Since \displaystyle p>qp>q by 1, there is a slant asymptote found at \displaystyle \frac{{x}^{2}-4x+1}{x+2}

x+2

x

2

−4x+1

.

Synthetic division of the polynomial x^2-4x+1 by x+2 in which it only contains the coefficients of each polynomial.

The quotient is \displaystyle x - 6x−6 and the remainder is 13. There is a slant asymptote at \displaystyle y=x - 6y=x−6.

\displaystyle k\left(x\right)=\frac{{x}^{2}+4x}{{x}^{3}-8}k(x)=

x

3

−8

x

2

+4x

: The degree of \displaystyle p=2\text{ }<p=2 < degree of \displaystyle q=3q=3, so there is a horizontal asymptote y = 0.

Answer:

11)

complimentary angle

b = 90 - 65

b = 25º

12)

supplementary angle

b = 180 - 117

b = 63º

13)

360º in a circle

b = 360 - 244 -23

b = 93º

14)

vertical angle

b = 46º