the electric field at point 4.00 cm from the axis, measured radially outward from the midpoint of the shell.

Answers

Answer 1
the answer is 825.7 m/s.

Related Questions

One train (22,680 kg) moving east at 170 km/h collides with a car (1,200 kg) that was moving north at 5 km/h. They get attached to each other, moving in the direction of the train. What is the final velocity of the objects and the type of collision? If the collision happened in 1.2X10-3 seconds, what was the force? How much kinetic energy was lost?

Answers

The final velocity of the objects is 229.82km/hrSince energy was lost after the collision, the type of collision that occurs is an elastic collision.The required force is 1,090,918,000NThe amount of Kinetic energy lost is 12,401,976.656Joules

According to the law of collision'

m1u1 + m2u2 = (m1+m2)v

Given the following:

m1 = 22,680kg

u1 =170km/h

m2 = 1200kg

u2 = 5km/hr

Get the final velocity "v"

22680(170) + 1200(5) = (22680 + 1200)v

3855600 + 6000 = 12880v

3,861,600 = 12880v

v = 3,861,600/12,880

v = 229.82km/hr

Hence the final velocity of the objects is 229.82km/hr

Since energy was lost after the collision, the type of collision that occurs is an elastic collision.

According to Newton's second law, the formula for calculating the force is expressed as;

F = ma

F = m(v-u)/t

F = 22680+1200(229.82-175)/t

Ft = 23880(54.82)

F = 1,309,101.6/0.0012

F = 1,090,918,000N

Hence the required force is 1,090,918,000N

KE lost = Kinetic energy after collision - Kinetic energy before collision

Kinetic energy after collision = 1/2 * 12880 * 229.82²

Kinetic energy after collision = 340,142,976.656 Jolues

Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²

Kinetic energy before collision = 327,726,000 + 15000

Kinetic energy before collision = 327,741,000

Kinetic energy lost = 340,142,976.656 - 327,741,000 =  12,401,976.656Joules

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While closing a door of mass 10 kg, a student pushes on it with a force of 25 N. As the door is accelerating to close, what
force does the door exert on the student?

A.5n
b.25n
c.250n
d.35n

Answers

Answer:

its 30 n

trust me

An object travelling at 12 m/s has 64.8j of stored kinetic energy. What is the mass of the object, in grams?​

Answers

Answer:

So u divided 12 divided by 64.8 okay

Explanation:

and when I getc the answer that's urs answer

Which of the following is not an aspect of instincts?

Answers

There’s nothing there dude? What

Reflect on your new experiences, what made you uncomfortable and what encouraged you. Did you learn anything new about yourself on the trip? Traveling can help you improve. Think about your journey and if it helped you grow in any way.​

Answers

Answer:

keke

Explanation:

An empty 230 kg elevator accelerates upward
at 1.7 m/s^2
The acceleration of gravity is 9.8 m/s^2.
What is the tension in the cable that lifts
the elevator cab?
Answer in units of N.

Answers

Answer:

7.2 as used in the equation

I don’t get anything that this question is asking me and I need to turn this in quick

Answers

Answer:

Hey there

when they meat they will constructivly interfere, wich means they will become one big wave. After that they will pas right through each other and continue.

I NEED HELP PLZZZZZZ

Answers

Mostly GPE and a little KE since the ball is high up (GPE) and it's also moving (KE) but not as much as it had when you first threw it

The pressure of liquid varies as per it's depth.

Answers

Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.

Explanation:

is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??​

Answers

Answer:

it is potential energy ---- kinetic energy

One of your classmates, in a fit of unrestrained ego, jumps onto a lab table:
a) Draw a qualitative force diagram for the table. Use marks on the vectors to show the balance of forces.
b) Your classmate’s mass is 65 kg and the table weighs 0 N. Calculate the normal force on the table by the floor. Show your work!
c)Find the mass of the table

Answers

The equilibrium condition allows finding the results for the forces of the system are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition

          ∑ F = 0

Where the bold letters indicate vectors, F is the external forces

a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.

b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force

             N = N₁ + N₂ + N₃ + N₄₄

Let's apply the equilibrium condition

                N -  [tex]W_m -w_{table}[/tex] = 0

                N =  [tex]W_m +w_{table}[/tex]

                N = [tex]M_m g + w_{table}[/tex]  

They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N

                N = 65 9.8 + 100

                N = 737 N

c) To calculate the mass of the table we use the relation

                W = [tex]m_{table}[/tex] g

                [tex]m_{table} = \frac{w_{table}}{g}[/tex]

                [tex]m_{tabble}= \frac{100}{9.8}[/tex]  

               [tex]m_{table}[/tex]e = 10.2 kg

In conclusion using the equilibrium condition we can find the results for the forces are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

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PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land

Answers

Answer:

Explanation:

It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.

s = s₀ + v₀t + ½at²

vertical analysis with floor level as origin

0 = 1.2 + 5t + ½(-9.8)t²

0 = 1.2 + 5t - 4.9t²

quadratic formula positive answer

t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))

t = 1.22 s is the flight time

horizontal analysis with launcher as origin

s = 0 + 12(1.22) + ½(0)1.22²

s = 14.6517... 15 m

momentum is conserved it can be transferred but not lost. true or false​

Answers

Answer: False

explanation: because Total momentum is conserved only if the collision can be considered isolated from the influence of net external forces

2. What are the units of mass?

kg
N
m/s
m/s^2
(kg)(m/s)
m
S

Answers

Answer:

Kg

Explanation:

The units of mass are gram (g) , kilograms (Kg)

But SI of mass accepted is Kilograms (Kg)

Answer:

kg

Explanation:

the s.i unit is kilogram

how much kinetic energy is stored in a 1.5 kg object that is moved at 15 m per second​

Answers

Answer:

Explanation:

KE=0.5xM(Vpower2)

=0.5x1.5(15power2)

=168.75

SI units are used for scientific works. Why? ​

Answers

Answer:

SI units are used for scientific works to bring uniformity in measurements all over the world.

A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.

With what speed does the fish leave the water?
What height above the water does it reach?

Answers

Answer:

Explanation:

Velocity will be equal to the area under the curve of the acceleration-time plot.

v = ½(45)(0.075) = 1.6875

v = 1.7 m/s

h = (0² - 1.6875²) / (2(-9.8)) =  0.145288...

h = 15 cm

The U.S. uses a household voltage of 110 V. However, electric stoves and dryers are wired with
220 V lines. Which would cause less damage --plugging a 110 V-rated curling iron into a 220 V
outlet, or a German-made 220 V-rated curling iron into a 110 V outlet? Explain. (Note: 110 and
220 V outlets are made in different shapes so that appliances cannot be accidentally
interchanged.)

Answers

Answer:

In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance

Find the center of the galaxy with Shapley method

Answers

Answer:

Calculating Center

Shapley correctly determined the galactic center of the Milky Way to be located in the constellation of Sagittarius. He did this by mapping out a three-dimensional distribution of the globular clusters.

Explanation:

Mark me the Brainliest..PLS

Calculate the kinetic energy of a 70 kg person moving at a speed of 5m/s

Answers

Answer:

875 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 70 \times {5}^{2} \\ = 35 \times 25 \\ = 875[/tex]

We have the final answer as

875 J

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf 875 \ Joules}}[/tex]

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:

[tex]KE= \frac{1}{2}mv^2[/tex]

The mass of the person is 70 kilograms and they are moving at a speed of 5 meters per second.

m= 70 kg v= 5 m/s

Substitute these values into the formula.

[tex]KE= \frac{1}{2} (70 \ kg )(5 \ m/s)^2[/tex]

Solve the exponent.

(5 m/s)² = 5 m/s * 5 m/s = 25 m²/s²

[tex]KE= \frac{1}{2}(70 \ kg)(25 \ m^2/s^2)[/tex]

Multiply the numbers in parentheses.

[tex]KE= \frac{1}{2} (1750 \ kg*m^2/s^2)[/tex]

Multiply by 1/2 or divide by 2.

[tex]KE= 875 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. So, our answer of 875 kg*m²/s² is equal to 875 Joules.

[tex]KE= 875 \ J[/tex]

The person has 875 Joules of kinetic energy.

An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.​

Answers

Hi there!

On the object, we know that there are two forces working on the object:

-Force due to gravity (Mg)

-Force due to air resistance

Let the positive direction of the force be downwards (direction of the acceleration)

We can write the summation of forces as:

∑F = Mg - Fa

Plug in values. Let g ≈ 10 m/s²

∑F = 30(10) - 50 = 250N

Find the acceleration using the formula:

∑F = m · a

∑F/m = a

Plug in values:

250/30 = 8.33 m/s²

the colour of the shadow of coloured objects is not same as the colour of the objects​

Answers

The colour of the shadow of coloured objects is not same as the colour of the objects

When an opaque item absorbs all of the light falling from a light source, no light is reflected, and the thing appears black. The color of an object's shadow is independent of its hue; it can be red, yellow, green, or black.

21) A charged polyester ball is placed over a charged PVC pipe. The ball, which
has a mass of 1.2 grams, rests 42 cm above the pipe. If the ball and pipe have
the same negative charge, what is the charge on the ball?

Answers

The negative charge on the polyester ball is -1.53 x 10⁻⁶ C.

The given parameters;

mass of the ball, m = 1.2 gdistance between the ball and the pipe = 42 cm = 0.42 m

The gravitational force on the ball is calculated as follows;

F = mg

F = 0.012 x 9.8

F = 0.12 N

The electrostatic force on the ball is calculated as follows;

[tex]F= \frac{kq^2}{r^2} \\\\q^2 = \frac{Fr^2}{k} \\\\q = \sqrt{\frac{0.12 \times (0.42)^2}{9\times 10^9}} \\\\q =+/ -\ \ 1.53 \times 10^{-6} \ C\\\\q =-\ \ 1.53 \times 10^{-6} \ C[/tex]

Thus, the negative charge on the polyester ball is -1.53 x 10⁻⁶ C.

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một vật dao động trong 10 phút thực hiện 500 dao động tính chu kì và tần số dao động

Answers

Answer:

Explanation:

T = 10(60)/500 = 1.2 s

f = 1/T = 0.83 Hz

What happens if the incident beam is perpendicular to the surface (at an angle of 90 degrees)?

Answers

If the ray is perpendicular to the surface, then the incident ray, the reflected ray and the transmitted (refracted) ray all lie along the same line (i.e they are collinear). If the ray is not perpendicular to the surface, then the ray appears to be bent at the surface.

If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?

Answers

H = mc∆T

where, H=heat energy

c = SHC

H = 2*921*(40-20)

H = 36840J

H = 36.84KJ

The energy transferred to it is 36.84KJ

The energy transferred to aluminum from 20°C to 40 °C is equal to 36840 J.

What is the specific heat capacity?

The specific heat capacity can be described as the quantity of heat required to increase the temperature of 1 unit of substance by one degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance.

The mathematical equation is used to calculate the specific heat is equal to:

[tex]Q = m\times C\times \triangle T[/tex]

Given, the mass of the aluminum block, m = 2 Kg

The initial temperature of aluminum, T₁ = 20 °C

The final temperature of the aluminum, T₂ = 40 °C

The specific heat capacity of aluminum, C = 921 J/kg°C

The energy transferred to the aluminum block:

Q = 2 × 921 × (40-20)

Q = 36840 J

Therefore, the energy transferred to aluminum from 20°C to 40°C is  36840 J.

Learn more about specific heat capacity, here:

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#SPJ2

. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mass units)? (3) (b) the mass (in kg) of an aspartame molecule?​

Answers

The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg

Aspartame has the chemical formula C14H18N2O5

C = 12, H = 1, N = 14, O = 16

(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)

                                  = 168 + 18 + 28 + 80

                                    = 294 amu

(b) Mass of 1 molecule of aspartame = mole x molar mass

                                    = 1 x 294

                                        = 294 g

Converting 294 g to kg = 294/1000

                                         = 0.294 kg

More on mole and molar mass can be found here: https://brainly.com/question/6613610

✏️Topic: Comparing Arguments

My reflective journal.

Direction: Supply the sentence below to complete the information askes.

I learned that comparing arguments________________________One example of this is____________. We can use​

Answers

Answer:

WOW ANG HIRAP NG TANONG MO

Explanation:

Di ko yan masasagutan

stay safe

[tex]lol[/tex]

Your new motorcycle weighs 2580 N.
The acceleration of gravity is 9.8 m/s2.
What is its mass?
Answer in units of kg.

Answers

Answer:

answer to your question is 263.26kg

Explanation:

m=f÷a ,m=2580÷9.8=263.26kg

The ruminant stomach has four compartments including the rumen, reticulum, omasum and large intestine,
O True
O False

Answers

Answer:

False

It has four compartments just not including all of those

Explanation:

Ruminant stomachs have four compartments: the rumen, the reticulum, the omasum and the abomasum.Anatomy of the ruminant digestive system includes the mouth, tongue, salivary glands (producing saliva for buffering rumen pH), esophagus, four-compartment stomach (rumen, reticulum, omasum, and abomasum), pancreas, gall bladder, small intestine (duodenum, jejunum, and ileum), and large intestine (cecum, colon, and rectum).

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