The diameter of a circle is 170 inches. The circle has two chords of length 26 inches. What is the distance from each chord to the center of the circle?

The solution to the linear function M(x) = 180 is of x = -5.

The linear function equation is the slope-intercept form. Thus, it is expressed as f(x) = mx + b where m is the slope and b is the y-intercept of the line.

In this problem, the function is defined as follows:

M(x) = 120 - 12x.

M(x) represents the balance remaining on the gift card after x movie tickets priced at $12 are purchased.

The domain of the situation is given as follows:

x ≥ 0. {discrete}

As the number of tickets cannot assume negative neither decimal values.

The equation is:

M(x) = 180.

The solution is calculated as:

120 - 12x = 180

12x = -60

x = -60/12

x = -5.

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The solution is,  the surface area of the parallelepiped is:444 cm²

Here, we have,

Area of parallelogram = a*h

                                     = 10*3

                                     = 30   ,

there are 2 such parallelograms in the prism

2 faces are rectangles with sides 12 and 6 ,

Area of this face is 12*6=72,  there are 2 such faces

we have,

2 faces are rectangles with sides 12 and 10

Area of this face is 12*10=120,  

there are 2 such faces

the surface area of the parallelepiped is:

2*30+2*72+2*120

= 444 cm²

Hence, The solution is,  the surface area of the parallelepiped is:444 cm²

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There are 5 markers in each cup

Nicholas splits 27 green markers equally into 9 cups

Hence the number of green markers in one cup is

= 27/9

= 3

He then spilt 18 yellow markers equally into the same 9 cups

The number of yellow markers in one cup is

= 18/9

= 2

The total number of markers in each cup is

= 3 + 2

= 5

Hence there are 5 markers in each cup

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The measure of the angle in degrees is approximately 713 degrees. Note that this result is greater than 360 degrees because the angle is not a standard angle in a plane but a measure in three-dimensional space.

Since 1/360th of the circumference of the circle is 0.5 cm long, the circumference of the circle is 360 times longer, or 180 cm long.

The arc subtended by the angle is 79 cm long, which is a fraction of the entire circumference. To find the angle in degrees, we need to convert the arc length to an angle measure using the formula:

angle measure = (arc length / circumference) x 360 degrees

Substituting the values we know, we get:

angle measure = (79 cm / 180 cm) x 360 degrees

Simplifying the fraction, we get:

angle measure = 1.9833 x 360 degrees

Rounding to the nearest degree, we get:

angle measure ≈ 713 degrees

Therefore, the measure of the angle in degrees is approximately 713 degrees. Note that this result is greater than 360 degrees because the angle is not a standard angle in a plane but a measure in three-dimensional space.

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he would fit the child size

his height is 145cm and we want to convert it  into inches so the formula is

length/2.54=

145cm/2.54=57.08in

so juan is 57.08 inches, so he fits the child size.

Answer:

Step-by-step explanation:

539.22 dollars

The measures of the other two angles in the parallelogram are both 143 degrees.

A parallelogram is a quadrilateral with two sides that are parallel to one another. A parallelogram has equal-length opposite sides and equal-length opposite angles. The internal angles that are extra to the transversal on the same side. A parallelogram's total interior angles add up to 360 degrees.

A parallelogram is formed by the junction of two parallel lines, and its opposite angles are equal.

Then, there are two 35 degree angles. Two further angles that are equivalent are noted: A parallelogram's angles add up to 360 degrees. Following that, x+x+37+37=360

2x=360-74

2x=286

x=143.

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The probability that the first student who enters the room will be assigned to the front row is 4/15.

The probability of an event is calculated by dividing the total number of possible outcomes by the number of possible outcomes.

given that ,

A classroom is arranged with 8 seats in the front row 10 seats in the middle row and 12 seats

The total number of seats in the classroom is 8 + 10 + 12 = 30.

There are thirty seats to choose from because there is only one student entering the room.

However, we want to determine the likelihood that the student will be assigned to one of the eight seats in the front row.

Therefore, the probability of assigning the front row to the first student who enters the room is:

P(front row) = 8/30

Simplifying this fraction gives:

P(front row) = 4/15

As a result, there is a probability of 4/15, or roughly 0.267, that the first student who enters the room will be assigned to the front row.

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Answer:

The domain of h is

[tex] - 7 \leqslant x \leqslant 7[/tex]

Choice A is correct.

Answer:

c

Step-by-step explanation:

The probability of hitting the black circle inside the target is approximately 0.0314.

The probability of hitting the white portion of the target is approximately 0.686.

Part A:

The black circle has a diameter of 2 units, which means it has a radius of 1 unit. The area of the circle is πr^2, which is π(1)^2 or π square units. The area of the white square is 10 x 10 or 100 square units.

The probability of hitting the black circle inside the target is the ratio of the area of the circle to the area of the square, which is π/100 or approximately 0.0314. This probability is closer to 0 because the circle is much smaller than the square, and the likelihood of hitting the exact center of the circle is low.

Part B:

The white portion of the target is the area of the square minus the area of the black circle, which is 100 - π square units.

The probability of hitting the white portion of the target is the ratio of the area of the white portion to the area of the square, which is (100-π)/100 or approximately 0.686.

This probability is closer to 1 because the white portion of the target is much larger than the black circle, and there are many possible areas of the square that could be hit.

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The mean and standard deviation of a sampling distribution of sample means with sample size 249 are 71 and approximately 1.267 respectively when the population has a mean of 71 and standard deviation of 20.

We know that, if the population has mean [tex]=\mu[/tex] and standard deviation [tex]=\sigma[/tex] and if the sampling distribution has sample size of n then

mean of the sampling distribution will be [tex](\mu_{\bar{x}})=\mu[/tex]

and the standard deviation of sampling distribution will be [tex](\sigma_{\bar{x}})=\frac{\sigma}{\sqrt{n}}[/tex]

Here in this problem,

Mean of the population [tex](\mu)[/tex] = 71

Standard Deviation of the population [tex](\sigma)[/tex] = 20

And the sample size of the sampling distribution (n) = 249

So, the mean of sampling distribution [tex](\mu_{\bar{x}})=\mu[/tex] = 71

Standard Deviation of sampling distribution [tex](\sigma_{\bar{x}})=\frac{\sigma}{\sqrt{n}}=\frac{20}{\sqrt{249}} \approx 1.267[/tex] (Correct up to three decimal places)

Hence, the mean and standard deviation of the sampling distribution of sample means with sample size 249 are 71 and 1.267 (approximately) respectively.

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The radius of the base of the cone-shaped block is approximately 10.69 inches.

We can use the formula for the volume of a cone to find the radius of its base. The volume of a cone is given by the formula  :

V = (1/3)πr^2h

Where

We know that the volume of the cone-shaped block is 125 cubic inches, and we know the height is the same for all blocks. So we can solve for the radius:

125 = (1/3)πr^2h

125 = (1/3)πr^2h

375 = πr^2h

r^2 = 375/π

r ≈ 10.69

So we can conclude that the radius of the base of the cone-shaped block is approximately 10.69 inches.

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According to the Equation, the provided question's conclusion is that the object strikes the top of the tree in roughly 4 seconds.

An equation is a mathematical statement that demonstrates the equality of two expressions and is typically denoted by the equals symbol (=). Equations can be used to solve issues and make predictions as well as to express a wide variety of mathematical relationships.

The formula for the distance travelled by an object under constant acceleration can be used to solve this issue:

d = 1/2 * g * t²

where:

The distance travelled is d.

Gravitational acceleration (g) is around 32.2 feet per second squared.

T is the passing of time

Since the object is being dropped in this scenario, we know that its initial height is 0 feet and its ending height is 44 feet. For the duration of the trip, we may construct the following equation:

The required time is t seconds.

h(t) = 44

Simplifying:

-16t² + 300 = 44

16t² = 300 - 44

t² = 256/16

t² = 16

When both sides are squared:

t = 4 seconds

The time it takes for the object to strike the tree's top is therefore 4 seconds.

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The complete question is,

Let's say the object lands 44 feet above the ground, at the top of a tree. You may calculate the number of seconds after being dropped by writing and solving an equation.

The account value after forty (40) years is approximately $2,789,525.

We can use the formula for future value of an annuity to solve this problem:

FV = PMT * ((1 + r)^n - 1) / r

where FV is the future value, PMT is the annual deposit amount, r is the annual interest rate, and n is the number of periods (years in this case).

For the first year, the deposit amount is $3,000, so:

FV1 = 3000 * (1 + 0.0835)^40 = $65,470.22

For the subsequent years, the deposit amount increases by $300, so:

PMT = 3000 + 300 + 300 + ... = 3000 + 300 * 39 = $15,300

Using this value for PMT, we can calculate the future value for the remaining 39 years:

FV2 = 15300 * ((1 + 0.0835)^39 - 1) / 0.0835 = $2,724,054.54

Adding the two future values together, we get the total account value after forty years:

FV = FV1 + FV2 = $2,789,524.76

Therefore, the account value after forty years is approximately $2,789,525.

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There is enough proof that the mean raw score for the school's applicants is more than 30 at a significance level of α = 0.01, therefore we reject the null hypothesis.

The null hypothesis H0: μ ≤ 30 mean raw score for the school's applicants is less than or equal to 30 and the alternative hypothesis Ha: μ > 30

We can utilize a one-tailed t-test since we don't know the population standard deviation and our sample size is less than 30. The test statistic is evaluated

t = (x' - μ) / (s / √n)

here
x'= sample mean = 31,
μ = hypothesized population mean = 30,
s =  standard deviation = 2.5,
n = sample size = 50.

t = (31 - 30) / (2.5 / √50)
= 3.16

Applying  t-distribution table with degrees of freedom (df) = n - 1 = 49 and a significance level of α = 0.01, we find that the critical value is
t-critical = 2.404.

The calculated t-value (3.16) is greater than our critical value (2.404), we reject the null hypothesis since there is enough evidence to support the student's claim that the mean raw score for the school's applicants is more than 30 at a significance level of α = 0.01.

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After solving the given angles we can conclude that ∠4 is (D) 140° respectively.

Two rays that have a common terminal and are referred to as the angle's sides and vertices, respectively, make up an angle in Euclidean geometry.

Two rays can form angles in the plane where they are positioned.

Angles are also produced when two planes intersect.

These are what are known as dihedral angles.

Acute, obtuse, right, straight, reflex and full rotation are examples of basic angles.

So, according to the given image, we know that:

∠ 1 + ∠ 2 = 180

Then,

(3x + 20) + x = 180

4x + 20 = 180

4x = 180 - 20

4x = 160

x = 160 / 4

x = 40

We got that:

∠ 1 = ∠ 4

∠ 2 = ∠ 3

Simply substitute for x and solve if ∠1 = ∠4:

3x + 20 = 3(40) + 20 = 120 + 20 = 140

Therefore, after solving the given angles we can conclude that ∠4 is (D) 140° respectively.

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The collection of "high mountains of Nepal" is subjective and not well-defined, it may or may not be a set depending on the criteria specified, and to express it as a well-defined collection.

a) It is not a well-defined collection because the term "high mountains of Nepal" is subjective and does not have a clear definition. What one person considers high might be different from what another person considers high.

b) It is not necessarily a set, depending on how the collection is specified. If the collection is specified using clear criteria (such as mountains over a certain height), then it could be a set.

However, if the collection is just described using vague language like "high mountains of Nepal," then it is not necessarily a set.

c) In order to articulate it as a precise collection, we may define a precise standard for what constitutes a "high mountain of Nepal." As an illustration, we could say that any peak in Nepal that rises higher than 7,000 meters qualifies as a high mountain there.

With this precise definition, we could then pinpoint a trio of Nepalese mountains.

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Answer:

21.5

Step-by-step explanation:

1. Line the numbers from least to greatest:

20, 20, 21, 22, 23, 26

2. cross off one from one side then the other

(ex: 20, 20, 21, 22, 23, 26 --> 20, 21, 22, 23 --> 21, 22)

3. the number left is the median, but if there are 2 numbers left do step 4 and 5

4. find the middle of the 2 numbers (ex: 21 and 22's middle is 21.5)

5. The middle of the those 2 numbers is the median (which in this case is 21.5)

For the experiment of birth of children,

a) Sample space is S = { G, BG, BBG, BBBG, BBBB}.

b) The probability for each of the simple events in the sample space, 0.5, 0.25, 0.125, 0.0625 and 0.0625.

c) The probability distribution function for X is 0.5, 0.25, 0.125, 0.0625 and 0.0625.

d) The table form of probability density function is present in above figure.

We have a woman who decides to have children until she has first a baby girl or until she has four children, which event occurred.

a) Sample space is S = { G, BG, BBG, BBBG, BBBB} where G and B represents the birth of baby boy and baby girl.

b) Since, birth become independent so P( B) = P( G) = 0.5. Using multiplcation rule, the probability for each of the simple events, P( G) = 0.5

P( BG) = P( B) P(G) = 0.25

P( BBG) = P(B)× P(B)× P(G) = 0.125

P( BBBG) = P(B)× P(B)× P(B) ×P(G)

= 0.0625

P( BBBB) = P(B)× P(B)× P(B) ×P(B)= 0.0625

c) Let X be a variable such that it denotes number of children. So, X can take value from set { 1,2,3,4}.

The probability of a girl child is for each birth = 0.5

Therefore, P( X = 1) = { only 1 girl} = P( G)

= 0.5

P(X = 2) = { one boy and one girl } = P( BG) = P(B) P(G) = 0.25

P( X = 3) = { two boys one girl } = P( BBG) = 0.125

P( X = 4) = { three boys one girl or four all boys } = P( BBBG) + P( BBBB) = 0.0625 + 0.0625

= 0.125

So, the above values of probability distribution function for random variable X.

d) A table form picture of the probability distribution function for X is present in above figure. Hence, the required table is known.

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a) option 4-t test for one mean.

b) Null hypothesis: μ_Shadyside - μ_Oakland <= 0 (Mean monthly rent of apartments in Shadyside is not higher than in Oakland).

Alternative hypothesis: μ_Shadyside - μ_Oakland > 0 (Mean monthly rent of apartments in Shadyside is higher than in Oakland).

a) The most appropriate statistical test for this scenario would be (vi) test for two independent means, also known as two-sample t-test. This test is used to compare the means of two independent samples to determine if they are significantly different from each other. In this case, we are comparing the mean monthly rent of apartments in Shadyside and Oakland, and we have two independent samples.

b) The appropriate hypotheses for the two-sample t-test are as follows:

Null hypothesis: The mean monthly rent of apartments in Shadyside is equal to the mean monthly rent of apartments in Oakland.

Alternative hypothesis: The mean monthly rent of apartments in Shadyside is greater than the mean monthly rent of apartments in Oakland.

Symbolically, the null hypothesis can be represented as H0: µ1 = µ2, where µ1 and µ2 represent the population means of monthly rent in Shadyside and Oakland, respectively.

The alternative hypothesis can be represented as Ha: µ1 > µ2, indicating that the population mean of monthly rent in Shadyside is greater than the population mean of monthly rent in Oakland

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Answer:

1 6/7 is about 2, so 9 1/2 - 1 6/7 is about

7 1/2.

Each leg of the triangle has a length of 5√(2) units

Since the triangle is 45-45-90, each of the two legs has the same length, which we'll call x. By the Pythagorean theorem, we know that:

x² + x² = h²

Simplifying this equation, we get:

2x² = h²

To solve for x, we can divide both sides by 2 and then take the square root:

x = h / √(2)

This tells us that each leg of a 45-45-90 triangle is equal to the hypotenuse divided by the square root of 2.

Let's say you have a 45-45-90 triangle with a hypotenuse of length 10. To find the length of each leg, you would use the formula:

x = h / √(2)

Substituting h = 10, we get:

x = 10 / √(2)

To simplify this expression, we can rationalize the denominator by multiplying both the numerator and denominator by √(2):

x = (10 / √(2)) * (√(2) / √(2))

= 10√(2) / 2

= 5√(2)

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The smallest rational number among all the given numbers is equal to 0.2345678.

The rational number are equal to,

-√5 , (1/4), √25 , -√27 , 0.2345678

First simplify each of the given numbers we have,

√5 is an irrational number,

so it is not rational.

1/4 is a rational number.

√25 = 5,

which is a rational number.

-√27 = -3√3,

which is an irrational number, so it is not rational.

0.2345678 is a rational number.

Arrange the rational number in ascending order to get the smallest rational number .

Value of 1/4 = 0.25

0.2345678 < 0.25 < 5

Therefore, the smallest rational number among the given options is 0.2345678.

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Perry como fans fifty-six percent of respondents to an online poll said that they were perry como fans. if 982 randomly selected people responded to this poll.

By use the sample proportion to estimate the true proportion of all local residents who are Perry Como fans.

Let p be the true proportion of all local residents who are Perry Como fans. Then, the sample proportion is 0.56 and the sample size is n = 982.

We construct a 95% confidence interval for p by using the formula

Sample proportion ± z*standard error

Where z is the critical value from the standard normal distribution for a 95% confidence level, which is 1.96. The standard error is the estimated standard deviation of the sample proportion which is defined as

[tex]\sqrt{p*(1-p)/n} \\}[/tex]

By putting the values we get

Standard error = [tex]\sqrt{0.56*(1-0.56)/982)[/tex] = 0.018.

95% confidence interval = 0.56 ± 1.96*0.018 = (0.525, 0.595).

Hence, we can say with 95% confidence that the true proportion of all local residents who are Perry Como fans is between 0.525 and 0.595.

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The solution shown in the graph is (-4, 0)

Here we have a system of equations graphed, the solutions of the system are all the points where the graphs of the functions (lines in this case) do intercept.

Then, in this case the solution is where the lines red and blue intercept, that happens at the point (-4, 0).

So that is the solution of the system of equations.

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No, tripling the length of time for the investment does not double the interest earned with compound interest.

When interest is compounded, the interest earned depends not only on the length of time, but also on the interest rate and the number of compounding periods.

For example, if an investment of $100 earns 5% annual interest compounded annually for 1 year, the interest earned would be:

Interest = $100 x 0.05 = $5

If the same investment is compounded for 2 years instead of 1, the interest earned would be:

Interest = $100 x (1 + 0.05)^2 - $100 = $10.25

As we can see, doubling the length of time for the investment does not double the interest earned with compound interest.

The interest earned depends on the interest rate and the number of compounding periods as well.

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The correct graph for the given data is given by option The bar graph x axis labeled sport and the y axis labeled number of students, with each having value as basketball -17, baseball-12, soccer - 27, and tennis - 44.

Because the data shows discrete categories (sports) and their related frequencies, the correct graph is a bar graph (number of students).

The x-axis is to be named "Sports" to represent the various sports (Basketball, Baseball, Soccer, and Tennis), and the y-axis has to be labelled "Number of Students" to reflect the frequency. The graph's bars will show the frequency of each sport, with the heights of the bars giving the number of students who identified each sport as their favourite. The right values for the bars should be based on the data provided:

[tex]Basketball: 17\\Baseball: 12\\Soccer: 27\\Tennis: 44[/tex]

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Thus, we may estimate that there were 557 principals present at the meeting.

A mathematical comparison of two numbers is called a percentage. These figures frequently serve as a comparison between various objects or individuals. Take the scenario where you entered a crowded room as an example.

52/70 = 0.743 or 74.3%

Applying this ratio to the total number of attendees, we can extrapolate the proportion of principals at the conference, assuming that it is reflective of the conference as a whole:

Total principals at conference = Proportion of principals x Total number of attendees

Total principals at conference = 0.743 x 750

Total principals at conference ≈ 557

As a result, we may estimate that there were 557 principals present at the meeting.

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Answer: We can use the properties of the normal distribution to solve both parts of this problem.

a) The number of months with sales greater than 100 is a binomial random variable with parameters n = the number of months and p = the probability of a single month having sales greater than 100. Since each month is an independent normal random variable, we can use the standard normal distribution to find this probability. Let X be the number of months with sales greater than 100. Then:

X ~ Binomial(n, p)

where n is the number of months and p is given by:

p = P(X_i > 100) = P(Z > (100 - a) / a)

where Z is a standard normal random variable.

Using the binomial probability formula, the probability of exactly k months having sales greater than 100 is:

P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)

So the probability of exactly 3 months having sales greater than 100 is:

P(X = 3) = (n choose 3) * p^3 * (1 - p)^(n - 3)

= (12 choose 3) * P(Z > (100 - a) / a)^3 * [1 - P(Z > (100 - a) / a)]^(12 - 3)

b) The total sales in the next 12 months is a normal random variable with mean 12a and standard deviation sqrt(12)a. Let Y be the total sales in the next 12 months. Then:

Y ~ Normal(12a, sqrt(12)a)

The probability of the total sales being greater than some value x can be found by standardizing Y and using the standard normal distribution:

P(Y > x) = P((Y - 12a) / (sqrt(12)a) > (x - 12a) / (sqrt(12)a))

= P(Z > (x - 12a) / (sqrt(12)a))

where Z is a standard normal random variable. So the probability of the total sales in the next 12 months being greater than 1500 is:

P(Y > 1500) = P(Z > (1500 - 12a) / (sqrt(12)a))

Step-by-step explanation: