The cost to produce a batch of granola bars is approximately Normally distributed with a mean of $7.19 and a standard deviation of $0.86. If a random sample of 12 batches of granola bars is selected, what is the probability that the mean cost will be more than $7.00?


0.2220

0.2339

0.7653

0.7780

Answers

Answer 1

Answer:

0.7780

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

We have that [tex]\mu = 7.19, \sigma = 0.86[/tex]

Sample of 12:

[tex]n = 12, s = \frac{0.86}{\sqrt{12}} = 0.2483[/tex]

What is the probability that the mean cost will be more than $7.00?

This is 1 subtracted by the pvalue of Z when X = 7. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{7 - 7.19}{0.2483}[/tex]

[tex]Z = -0.765[/tex]

[tex]Z = -0.765[/tex] has a pvalue of 0.222

1 - 0.222 = 0.778

So the answer is 0.7780


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The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The expression is given below.

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Answers

Answer:

Population.

Step-by-step explanation:

Population can be defined as a collection or set of units or entities from whom we got the data.

This ultimately implies that, a population is the larger set from which other units can be picked from.

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An aircraft seam requires 20 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.) (a) If 16% of all seams need reworking, what is the probability that a rivet is defective

Answers

Answer:

probability that a rivet is defective is 0.00868

Step-by-step explanation:

given data

rivets = 20

all seam need reworking P = 16% = 0.16

solution

we consider here probability of a defective rivet = p

and 0.16 = P [Seam needs reworking) = P (at least one rivet in the seam is defective)

so that for non-defective = 1 - P [all the rivets are non-defective]

and that will be here as = 1 - P [rivet 1 is non-defective, rivet 2 is non-defective, rivet 3 is non-defective,...............,rivet 20 is non-defective]

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[tex]0.84^{\frac{1}{20}}[/tex] = 1 - p

solve it we get

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so, probability that a rivet is defective is 0.00868

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

the proportion of people who are sick after two weeks is 33.2%

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