The common _____ of two rays that make an angle is called the vertex.
your answer goes here

The effectiveness depends on your score of working.

How effective is it to go to your manager to request others take on some activities?

Certainty implies, indeed, that favorable things will happen and uncertainty  implies favorable things won't happen.

If we go to our manager, requesting that others should take some activities. It certainly depends upon the our score in the office. if we are hard working than in situations manager could approve our request and if our score is low or we are not a hard worker than result may no be in our favor.

Thus, the effectiveness depends on your score of working.

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The original value of the piece of equipment is 700000

The resale value is given as:

V=700,000e^(-0.02t)

The original value is when t = 0.

So, we have:

V=700,000e^(-0.02 *0)

Evaluate the product

V=700,000e^0

This gives

V=700,000 * 1

Evaluate

V=700000

Hence, the original value of the piece of equipment is 700000

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Answer:

2^25

Step-by-step explanation:

Given

On first day bag contained 1 kernels

on second bag contained 2 kernels of corn

on third day bag contained 4 kernels of corn

on n th day bag contains 2n-1  kernels of corn

thus on 26 th day bag contains 2^26= 2^25=33,554,432 kernel

Each kernel weigh  0.07 gm

Therefore 2^25  kernels weighs = 2^25 x 0.07

Therefore on 26 th day 2^25 kernel weighs 23,488.1024 kg

93. Perimeter = 34cm

94. Perimeter = 72. 27mm

95. Perimeter = 22in

96. Perimeter = 56m

97. Volume = 512 in³

98. Volume = 72 in³

99. Volume = 154 cm³

100. Volume = 3, 309. 42 mm³

93. Note that the diagram is a trapezium

Perimeter = a + b + c + d

a = 15 , b = 5 , c = 5 , d = 9

Perimeter = 15 + 5 + 5 + 9 = 34cm

94. Note that the diagram is a circle

Perimeter of a circle = 2 πr

Given diameter = 23mm

Radius = diameter/2

Radius = 23/ 2 = 11. 5mm

Perimeter = 2 × 3. 142 × 11. 5 = 72. 27 mm

95. Note that the shape is a rectangle

Perimeter of a rectangle = 2 (length + width)

Length = 5 in

width = 6 in

Perimeter = 2( 5 + 6)

Perimeter = 2 × 11 = 22 in

96. The shape is a rectangle

Perimeter of a rectangle = 2 (length + width)

Length = 10m , width = 19m

Perimeter = 2( 10+ 19) = 2 × 29 = 58m

97. Volume of a cube = side by power of 3

Volume = 8³

Volume = 512 cm³

98. Volume of a Cuboid =  length × breadth × height

Volume = 3 × 2 × 12

Volume = 72 in³

99. Volume of a sphere = πr² [tex]\frac{h}{3}[/tex]

radius = 7cm , height = 3cm

Volume = [tex]\frac{22}{7}[/tex] × [tex]7^{2}[/tex] ×[tex]\frac{3}{3}[/tex]

Volume = [tex]22[/tex] × [tex]7[/tex] × [tex]1[/tex]

Volume = 154 cm³

100. Volume of a cone = πr²h

radius = 9mm, height = 13mm

Volume = [tex]\frac{22}{7}[/tex] × [tex]9[/tex] × 9 × 13

Volume = [tex]\frac{23166}{7}[/tex]

Volume = 3, 309. 42 mm³

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Answer:

394.13cm²

Step-by-step explanation:

Formula: The area of a circle is found by A = πr²

Given:

Plug in:

A = πr² → A = (3.142)(11.2)²

            → A = (3.142)(125.44)

            → A = 394.13248

"2 decimal places",  round up to 394.13

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Answer:

22

Step-by-step explanation:

Hello!

We can convert it into slope-intercept form.

Slope - Intercept Form: [tex]y = mx +b[/tex]

The y-intercept of the line is 22.

Answer:

68

Step-by-step explanation:

I did it and it was right

Answer:

10.  Left 5

11.   Horizontal stretch by a factor of 5

12.  Horizontal reflection

Step-by-step explanation:

Transformations of Graphs (functions) is the process by which a function is moved or resized to produce a variation of the original (parent) function.

Transformations

For a > 0

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]

[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]

[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

Identify the transformations that take the parent function to the given function.

Question 10

[tex]\textsf{Parent function}: \quad f(x)=x^3[/tex]

[tex]\textsf{Given function}: \quad f(x)=(x+5)^3[/tex]

Comparing the parent function with the given function, we can see that 5 has been added to the x-value of the parent function.

Therefore, the transformation is:

[tex]f(x+5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units left}[/tex]

Question 11

[tex]\textsf{Parent function}: \quad f(x)=x^3[/tex]

[tex]\textsf{Given function}: \quad f(x)=\left(\dfrac{1}{5}x\right)^3[/tex]

Comparing the parent function with the given function, we can see that the x-value of the parent function has been multiplied by ¹/₅.

Therefore, the transformation is:

[tex]y=f\left(\dfrac{1}{5}x\right) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{\frac{1}{5}}[/tex][tex]\textsf{As }\dfrac{1}{\frac{1}{5}}=5 \implies \textsf{horizontal stretch by a factor of 5}[/tex]

Question 12

[tex]\textsf{Parent function}: \quad f(x)=x^3[/tex]

[tex]\textsf{Given function}: \quad f(x)=(-x)^3[/tex]

Comparing the parent function with the given function, we can see that the x-value of the parent function has been multiplied by -1.

Therefore, the transformation is:

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

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the transformation from f(x) to g(x) is (c) the graph of g(x) is horizontal compression of the graph f(x) by a factor of 1/3 and a reflection across the x-axis.

The functions are given as:

f(x) =x^3

g(x) = -(3x)^3

The minus sign in g(x) = -(3x)^3 implies that the function f(x) is reflected across the x-axis

The 3 in g(x) = -(3x)^3 implies that the function f(x) is stretched horizontally by 1/3

Hence, the transformation from f(x) to g(x) is (c)

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Answer: 16

Step-by-step explanation: 112 is equal to the product of 7 and Raj's score. Therefore, Raj's score score is 112 divided by 7 which is 16.

Answer:

Raj´s score = 16

Step-by-step explanation:

112 = 7R

R = Raj´s score

112/7 = R

R = 16

Answer:

194.935

Step-by-step explanation:

149.95×30%=44.985

149.95+44.985=194.935 new price

[tex]\angle R[/tex] and [tex]\angle S[/tex] are supplementary by the same-side interior angles theorem, and [tex]\angle S \cong \angle T[/tex] because of the properties of an isosceles trapezoid, meaning that [tex]\angle R[/tex] and [tex]\angle T[/tex] are supplementary.

[tex]4x+11+2x-5=180\\\\6x+6=180\\\\6x=174\\\\x=\boxed{29}\\\\\implies m\angle S=m\angle T=2(29)-5=\boxed{53^{\circ}}[/tex]

Answer:

A centimeters.

Step-by-step explanation:

The average rate, in miles per hour, of the rail portion of the trip is; D: 75

Since exactly 1/3 of the distance travelled was by rail, then we can say that;

(1/3) * (90) = 30 miles

We are told that part of the trip took 1/5 of the travel time. Thus;

Time it takes to travel that distance is:

(1/5) * (2) = 2/5 of an hour

Average rate is;

30/(2/5) = 150/2 = 75 mph

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The polygon with 128.57° as every interior angle is a septagon.

If the interior angle = 128. 57°

Using ( n-2) × 180 = sum of interior angles

Let's say n= 7

We have that,

(7-2) × 180 = 900

Let's find out the polygon

= 7 × 128.57

= 900

A polygon with seven sides is a septagon

Thus, the polygon with 128.57° as every interior angle is a septagon.

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Answer:

the law of cosines with ABC

Answer:

D. 5^6

Step-by-step explanation:

[tex]5^2*5^4\\5^2^+^4\\5^6[/tex]

Answer:

[tex] \log_x y = \dfrac{1}{2} [/tex]

Step-by-step explanation:

[tex] \sqrt{x} = y [/tex]

[tex] x^\frac{1}{2} = y [/tex]

[tex] \log_x y = \dfrac{1}{2} [/tex]

Answer:

Step-by-step explanation:

Comment

A: Gravity always pulls downward towards (to keep it simple) the earth's center. The answer is not A.

C: If you are interested in upward motion, Friction is not going to be the answer. What will the rocket rub against to make it go up?

D: Centripetal Force has to do with circular motion, The rocket generally is not thought of as going in a circle. Not D.

Answer: B. A chemical reaction can be directed so the energy will force an upward motion.

The ratio of circle to triangles is; 3:4 and the number of circles which should be added to make the ratio 1:1 is; 3.

It follows from the task content that the total number of circles and triangles in all 4 rows and can be counted and concluded as; 9 and 12 respectively.

Hence, the ratio of circles to triangles is 9 to 12 and in its simplest form is; 3:4.

However, to make the ratio 1:1, the number of circles and triangles must be equal. Hence, 3 circles must be added to make the ratio 1:1.

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I think it is 49123.52

Step-by-step explanation:

Answer:

ight so distribute the 4 so you get 4x+4 then subtract 4 from 8 which leaves you with 4x=4 divide by 4 and you get 1

Step-by-step explanation:

[tex]\bf{4(x+1)=8}[/tex]

Divide both sides by 4.

[tex]\bf{x+1=\dfrac{8}{4} }[/tex]

Divide 8 by 4 to get 2.

[tex]\bf{x+1=2}[/tex]

Subtract 1 from both sides.

[tex]\bf{x=2-1 }[/tex]

Subtract 1 from 2 to get 1.

[tex]\bf{x=1 \ \ \to \ \ \ Answer}[/tex]

Let x=1.

[tex]\bf{4\times(1+1)=8 \ \ \to \ \ \ [Add] }[/tex]

[tex]\bf{4\times2=8 \ \ \to \ \ \ [Multiply]}[/tex]

[tex]\bf{8=8 \ \ \to \ \ \ [Equality \ holds] }[/tex]

Checked ✅

Considering the stem-and-leaf plot, the range of the data-set is given as follows:

C. 45,79

The stem-and-leaf plot lists all the measures in a data-set, with the first number as the key, for example:

4|5 = 45.

Considering the key format, the smallest value in this problem is 4|5 = 45, and the highest is 7|9 = 79, hence the range is given by:

C. 45,79

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Answer:

there is no x-intercept

Step-by-step explanation:

The graph of the equation y = -1 is a horizontal line that passes through (0, -1). The line is parallel to the x-axis. It never intersects the x-axis. There is no x-intercept.

Answer:

[tex]\displaystyle \frac{\pi}{6}[/tex]

Explanation:

According to the unit circle, [tex]\displaystyle \frac{\pi}{3}[/tex] and [tex]\displaystyle \frac{\pi}{6}[/tex] are the radian measures you are looking for because all y-coordinates are associated with the sine function, so when evaluating, you will arrive at this:

[tex]\displaystyle \boxed{\frac{\pi}{3}} = \frac{\pi}{3} - \frac{\pi}{6}[/tex]

I am joyous to assist you at any time.

Answer:

  2448 ft²

Step-by-step explanation:

The surface area of the triangular prism is the sum of the areas of the triangular bases and the lateral area of the rectangular faces.

The two right triangle bases together form a rectangle that is 24 ft wide and 18 ft tall. The total base area is ...

  A = (24 ft)(18 ft) = 432 ft²

The rectangular faces of the prism are each 28 ft wide and have a total width of 18 +24 +30 = 72 ft. Their total area is ...

  LA = (28 ft)(72 ft) = 2016 ft²

The sum of the base area and lateral area is ...

  total area = (432 ft²) +(2016 ft²) = 2448 ft²

The surface area of the triangular prism is 2448 ft².

__

Additional comment

The area formula for the triangular base is ...

  A = 1/2bh . . . . . . area of one triangle with base b and height h

Then the area of the two congruent triangular bases is ...

  A = 2(1/2bh) = bh

This is the formula we used above. It skips the work of dividing by 2, then multiplying by 2 again.

The probability that there'll be no defective will be 0.504.

Probability of A being defective = 0.2.

Probability of B being defective = 0.1

Probability of C being defective = 0.3.

The probability that there will be no defective will be:

= (1 - 0.2) × (1 - 0.1) × (1 - 0.3)

= 0.8 × 0.9 × 0.7

= 0.504

The probability that there'll be no defect is 0.504.

The probability that there'll be at least two defective part will be:

= (0.2 × 0.1) + (0.2 × 0.3) + (0.1 × 0.3)

= 0.02 + 0.06 + 0.03

= 0.11

The probability that there'll be at least two defects is 0.11.

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Limit, can be defined as the every nearby  the value of a variable for a function exists, is called limits|

⇒ [tex]\lim_{h \to0 \zero} 46x^11+32xh^3+6x^15h+23[/tex]

When putting  h = 0

⇒  [tex]46x^11+23[/tex]

Thus, the value of a function of its limit is given by [tex]46x^11+23[/tex]

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