The amount in pounds of Type A coffee used is 36 pounds.
Using equation to find the number of pounds?Type A coffee costs Susan $5.45 per pound, and type B coffee
costs $4.05 per pound.
Therefore,
Let x = the number of pounds of Type A coffee.
total pounds = x + 3x
total cost = 5.45(x) + 3x(4.05)
633.60 = 5.45(x) + 3x(4.05)
633.60 = 5.45x + 12.15x
633.60 = 17.6x
divide both sides by 17.6
x = 633.60 / 17.6
x = 36
Pounds of Type A coffee used = 36 pounds
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given triangle abc, ab =bc=ac area of triangle abc 25 sq root 3 divide 4 cm. find the perimeter of abc tirangle
Answer:
[tex]\boxed{Circuit_{\Delta ABC} = 15~cm }[/tex]
Step-by-step explanation:
The ABC triangle is an equilateral triangle.
[tex]\mid AB\mid = \mid BC\mid = \mid AC\mid[/tex]
The drawing in the attachment.
I am entering meaningfully:
a - side length of an equilateral triangle
[tex]a=\mid AB\mid = \mid BC\mid = \mid AC\mid[/tex]
[tex]P_{\Delta} =\dfrac{a^{2} \sqrt{3} }{4}[/tex] - equilateral triangle area formula
[tex]P_{\Delta} =\dfrac{25 \sqrt{3} }{4}~~\land~~P_{\Delta} =\dfrac{a^{2} \sqrt{3} }{4}~~\Rightarrow~~\dfrac{a^{2} \sqrt{3} }{4}=\dfrac{25 \sqrt{3} }{4}\\\\\\\dfrac{a^{2} \sqrt{3} }{4}=\dfrac{25 \sqrt{3} }{4}~~\mid~~\div ~~\dfrac{\sqrt{3} }{4} \\\\\\\dfrac{a^{2} \sqrt{3} }{4}\cdot \dfrac{4}{\sqrt{3} } =\dfrac{25 \sqrt{3} }{4}\cdot \dfrac{4}{\sqrt{3} } \\\\a^{2} =25~~\\\\a^{2} =5^{2} ~~\land~~a > 0~~\Rightarrow~~\boxed{a=5~cm}\\\\\\[/tex]
[tex]Circuit_{\Delta ABC} =a+a+a\\\\Circuit_{\Delta ABC} =3a~~\land~~a=5~cm\\\\\boxed{Circuit_{\Delta ABC} =3\cdot 5 = 15~cm }[/tex]
The perimeter of the triangle ABC is 15.I'm lazy and dont feel like doing math myself. So pls help me!
Answer:
55
Step-by-step explanation:
[tex] \frac{n(n + 1)}{2} \\ n = 10 \\ substitutig \\ \frac{10(10 + 1)}{2} \\ \\ \frac{10(11)}{2} \\ \\ \frac{110}{2} = 55 [/tex]
Consider the equality xy=k. Write the following inverse proportion: y is inversely proportional to x. When y = 6, x = 3.
3/1 =k/6
1/6 = k/3
6/1 = 1/6
The correct expression for the inverse proportion is k/6 = 3/1
Inverse proportionsGiven the inequality xy = k
If y is inversely proportional to x, then;
y = k/x
Given that y = 6, and x = 3, then;
6 = k/3
Swap
k/3 = 6
k/6 = 3/1
Hence the correct expression for the inverse proportion is k/6 = 3/1
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estion
Kenneth has a bird feeder which gets visited by an average of 15 birds every 2 hours during daylight hours. What is the
probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours? (Round your
answer to three decimal places.)
Using the Poisson distribution, it is found that there is a 0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.
What is the Poisson distribution?In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
x is the number of successese = 2.71828 is the Euler number[tex]\mu[/tex] is the mean in the given interval.Considering the average of 15 birds every 2 hours during daylight hours, the mean for a 45-minute period is given by:
[tex]\mu = 15 \times \frac{45}{120} = 5.625[/tex]
The probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours is given by:
[tex]P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)[/tex]
In which:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-5.625}(5.625)^{0}}{(0)!} = 0.004[/tex]
[tex]P(X = 1) = \frac{e^{-5.625}(5.625)^{1}}{(1)!} = 0.02[/tex]
[tex]P(X = 2) = \frac{e^{-5.625}(5.625)^{2}}{(2)!} = 0.057[/tex]
[tex]P(X = 3) = \frac{e^{-5.625}(5.625)^{3}}{(3)!} = 0.107[/tex]
[tex]P(X = 4) = \frac{e^{-5.625}(5.625)^{4}}{(4)!} = 0.150[/tex]
[tex]P(X = 5) = \frac{e^{-5.625}(5.625)^{5}}{(5)!} = 0.169[/tex]
Then:
[tex]P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.004 + 0.02 + 0.057 + 0.107 + 0.15 + 0.169 = 0.507[/tex]
0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.
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Question 6 (Essay Worth 10 points)
(05.01 HC)
Monogram Masters advertises on its website that 92% of customer orders are received within five working days. They performed an audit from a random sample
of 200 of the 3,000 orders that month and it shows 175 orders were received on time.
Part A: Can we use a normal approximation? Explain. (5 points)
Part B: If Monogram Masters customers really receive 92% of its orders within five working days, what is the probability that the proportion in the random sample
of 200 orders is the same as the proportion found in the audit sample or less? (5 points)
Considering the problem described, we have that:
a) The normal distribution can be used, as both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
b) There is a 0.0132 = 1.32% probability that proportion in the random sample of 200 orders is the same as the proportion found in the audit sample or less.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with [tex]\mu = np, \sigma = \sqrt{np(1-p)}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].The parameters of the binomial distribution are:
n = 2000, p = 0.92.
Hence:
np = 200 x 0.92 = 184.n(1-p) = 200 x 0.08 = 16.Since both [tex]np \geq 10, n(1 - p) \geq 10[/tex], a normal approximation can be used. The mean and the standard deviation of the approximation are given as follows:
[tex]\mu = np = 200 \times 0.92 = 184[/tex].[tex]\sigma = \sqrt{np(1 - p)} = \sqrt{200 \times 0.92 \times 0.08} = 3.8367[/tex]The probability that proportion in the random sample of 200 orders is the same as the proportion found in the audit sample or less, using continuity correction, is P(X < 175.5), which is the p-value of Z when X = 175.5, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{175.5 - 184}{3.8367}[/tex]
Z = -2.22.
Z = -2.22 has a p-value of 0.0132.
0.0132 = 1.32% probability that proportion in the random sample of 200 orders is the same as the proportion found in the audit sample or less.
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a circle and triangle can intersect in a) a point b) a circle c) a triangle d) a line
A circle and a triangle can intersect in a point.
What is intersection at a point?
This refers to the fact that two lines are able to meet at a given point. The point where they meet is the point of intersection.
A circle is known to be able to intersect with a triangle in three different ways and at one point.
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What does x³+y³+z³ equal
Answer:
there is no ans that is the ans
Answer:
x³ + y³ + z³ = [ (x +y +z)(x² + y² + z² -xy - yz - xz) ] + 3xyz
Step-by-step explanation:
x³ + y³ + z³ = [ (x +y +z)(x² + y² + z² -xy - yz - xz) ] + 3xyz
In the following exercises, multiply the binomials. Use any method.
265. (6pq − 3)(4pq − 5)
Answer:
24p^2q^2 - 42pq + 15
Step-by-step explanation:
Answer:
Hence the expression [tex]$$(6pq-3)(4pq-5)=24p^2q^2-42pq+15$$[/tex]
Step-by-step explanation:
Explanation
The given expression is (6pq-3)(4 p q-5).We have to multiply the given expression.Multiply the (6 p q-3) by -5, multiply the (6 p q-3) by 4pq then add like terms.[tex]$$\begin{matrix}{} & {} & {} & {} & 6pq & - & 3 \\ \times & {} & {} & {} & 4pq & - & 5 \\ \end{matrix}$$[/tex]
_________________
[tex]$$\begin{matrix}{} & {} & {} & - & 30pq & + & 15 \\ {} & {} & 24{{p}^2}{{q}^2} & - & 12pq & {} & {} \\ \end{matrix}$$[/tex]
___________________
[tex]$$\begin{matrix}{} & {} & 24{{p}^2}{{q}^2} & - & 42pq & + & 15 \\ \end{matrix}$$[/tex]
Probabilities that are based on short-run relative frequencies are called what?.
Answer:Empirical probabilities.
PLS MARK ME AS BRAINLY
From the diagram below, we can tell that ____.
Select one:
a.
the two triangles are congruent
b.
the two triangles are similar by SAS
c.
the two triangles are similar by SSS
d.
the two triangles are not similar
Answer:
b) The two triangles are similar by SAS
Step-by-step explanation:
From the diagram below, we can tell that
b. the two triangles are similar by SASWhat is SAS similarity?SAS similarity (Side-Angle-Side similarity) is a criterion used to determine whether two triangles are similar.
It states that if two sides of one triangle are proportional to two sides of another triangle, and the included angles between these sides are congruent, then the two triangles are similar.
In other words, if in two triangles, the ratio of the lengths of corresponding sides is equal, and the included angles between these sides are congruent, then the two triangles are considered similar.
The corresponding angles are congruent and the sides are in proportion
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help me out with this question and i’ll give you brainly!!!
Answer:
the widths of the wire :)
Step-by-step explanation:
Which graph represents the solution to the compound inequality?
–2x + 4 ≤ 8 and –2x + 4 > –6
The graph which represents the solution to the compound inequality is; -2 ≤ x < 5.
Which graph represents the solution to the compound inequality?The inequalities given in the task content can be solved as follows;
For –2x + 4 ≤ 8
-2x ≤ 8 -4
x >= -2
For –2x + 4 > –6
–2x > –6 -4
x < 5
Hence, the graph which represents the solution to the compound inequality is; -2 ≤ x < 5.
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Which number line correctly shows 0.8+ 0.3?
O
O
CO
0 01 02 03 04 05 06 07 08 09 11 12 13
0 0.1 0.2 0.3 04 05 06 07 08 09 11 12 13
0 01 02 03 04 05 06 07 08 09 1 11 12 131
0 01 02 03 04 05 06 0
08 09
31
Answer:
the second one I think, as it is clearer and makes more sense
The jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.
What is a number line?A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.
The expression is given below.
⇒ 0.8 + 0.3
The sign of both terms are similar that is positive.
If the sign of the number is positive, then we move rightward. Similarly, if the sign of the number is negative, then we move leftward.
First, the jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.
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Evaluate x4 + 4x3 - 2x2 + 11x - 6 for x = 3
Step-by-step explanation:
[tex]f(x) = {x}^{4} + 4 {x}^{3} - 2 {x}^{2} + 11x - 6[/tex]
[tex]f(3) = {3}^{4} + 4. {3}^{3} - 2. {3}^{2} + 11.3 - 6[/tex]
[tex]f(3) = 81 + 4.27 - 2.9 + 33 - 6[/tex]
[tex]f(3) = 81 + 108 - 18 + 33 - 6[/tex]
[tex]f(3) = 198[/tex]
Answer:
198Step-by-step explanation:
x4 + 4x3 - 2x2 + 11x - 6 for x = 3
3^4 + 4 * 3^3 - 2 * 3^2 + 11 * 3 - 6 =
81 + 4 * 27 - 2 * 9 + 11 * 3 - 6 =
81 + 108 - 18 + 33 - 6 =
198
In triangle QRS, QR = 8 and RS = 5. Which expresses all possible lengths of side QS?
QS = 13
5 < QS < 8
QS > 13
3 < QS < 13
Answer:
3 < QS < 13.
I just did it on edge
The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side. The length of QS can lie between 3 < QS < 13.
What is the triangle inequality theorem?The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side.
Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,
(a+b) > c(b+c) > a(c+a) > bHere, we have,
As per the given law of triangle inequality, the sum of the two sides of the triangle is greater than the third side.
x + 8 > 5
x > -3
x + 5 > 8
x > 3
8 + 5 > x
13 > x
Hence, In triangle QRS the length of QS can lie between 3 < QS < 13.
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Given: ∠TUW ≅ ∠SRW; RS ≅ TU
Prove: ∠RST ≅ ∠UTS
Triangles R W S and U W T connect at point W. A line is drawn to connect points S and T. Another line is drawn from point R to point V and down to point U. Sides S R and T U are congruent. Angles S R W and W U T are congruent.
Complete the paragraph proof:
It is given that ∠TUW ≅ ∠SRW and RS ≅ TU. Because ∠RWS and ∠UWT are vertical angles and vertical angles are congruent, ∠RWS ≅ ∠UWT. Then, by AAS, △TUW ≅ △SRW. Because CPCTC, SW ≅ TW and WU ≅ RW. Because of the definition of congruence, SW = TW and WU = RW. If we add those equations together, SW + WU = TW + RW. Because of segment addition, SW + WU = SU and TW + RW = TR. Then by substitution, SU = TR. If segments are equal, then they are congruent, so SU ≅ TR. Because of
, △TRS ≅ △SUT, and because of
, ∠RST ≅ ∠UTS.
The information about the triangle shows that
TRS ≅ △SUT because of SAS, CPCTC.
How to explain the triangle?It should be noted that from the information given, W is the intersection point of line segments TS and RU.
Also, RWS and UWT are equal because they're vertical angles.
Therefore, by AAS, TUW and SRW are equal. Also, TRS ≅ △SUT because of SAS, CPCTC.
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Answer: SAS and CPCTC
Step-by-step explanation:
Because of SAS, △TRS ≅ △SUT, and because of CPCTC, ∠RST ≅ ∠UTS.
Trust me!
If you are working on Edge the answer is correct. The proof is down below. I hope someone finds this helpful.
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If two-thirds of a number is diminished by 8, the result is 32
Answer:
60
Step-by-step explanation:
Let's call the number A.
We are told that:
(2/3)A - 8 = 32
Multiply both sides by 3 and rearrange:
3*[(2/3)A - 8 = 32]
2A - 24 = 96
2A = 120
A = 60
CHECK:
Does (2/3) of 60 minus 8 equal 32?
(2/3)*(60) = 40
40 - 8 = 32
YES
The number is 60
Which of the following rational numbers is equivalent to a repeating decimal? a. 24/60 b. 30/64 c. 29/50 d. 35/60
Answer:
answer is D. 35/60
Step-by-step explanation:
35 divided by 60 is = 0.583333
which is a repeating decimal
Among the options, only a rational number (35/60) is equivalent to a repeating decimal. The correct answer is option (d).
To identify which of the given rational numbers is equivalent to a repeating decimal, we need to check their decimal representations.
a. 24/60 = 2/5 = 0.4 (terminating decimal, not repeating)
b. 30/64 = 15/32 = 0.46875 (terminating decimal, not repeating)
c. 29/50 = 0.58 (terminating decimal, not repeating)
d. 35/60 = 7/12 = 0.583333... (repeating decimal, as 3 repeats infinitely)
Among the options, only option d (35/60) is equivalent to a repeating decimal.
The repeating decimal representation is 0.583333... where the digit 3 repeats indefinitely.
This can be represented as 0.58(3).
The correct answer is option (d).
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Martin used 15 gallons to cement to lay sidewalk 50 feet in length. how many gallons of cement were used per foot
Answer:
0.3 gallon
Step-by-step explanation:
To do this problem, we must divide the amount of cement by the number of feet to see how much cement he used for each foot.
15/50 = 0.3 gallon
Answer:
0.3 gallons per foot
Step-by-step explanation:
We know that he used 15 gallons of cement for 50 feet.
We want to find the amount per foot or the amount per each 1 foot.
So we have to divide the 15 gallons by the 50 feet.
15 / 50 = 0.3 gallons per foot.
How many eight-character passwords can be formed with the 26 letters in the English alphabet, each of which can be in uppercase or lowercase, and the 10 digits
The number of possible passwords is 26^4 * 10^4.
We will make 4 picks from each category (letters and numbers).
We can duplicate them (i.e., pick each character more than once.)
so, for your 4 picks from the letters, you'll have
26 * 26 * 26 * 26 = 26^4 possible selections.
For each of these, you'll have 4 picks from the digits. Similar reasoning, this works out to
10^4 combinations of digits.
This means you'll have 26^4 * 10^4
Possible combinations of 4 letters and 4 digits, and, for each of these, you now need to work out how many unique ways to arrange them.
We will have 8 possible choices for the 1st character, 7 for the second, 6 for the third, etc. This works out to 8!
different orderings for each of your
26^4 * 10^4
The number of possible passwords is 26^4 * 10^4.
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y=1x^(2)+10x+22 line of symmetry
Answer:
x = -5
Step-by-step explanation:
We can use the below formula to find the line of symmetry.
( x - a )² + b
Here,
line of symmetry = +a
Vertex = +b
And now let us take a look at the given equation.
y = x² + 10x + 22
To find the line of symmetry from the given equation we have to make the given equation as the given formula.
Let us use the completing square method for that.
y = x² + 10x + 22
Put zero instead of y.
x² + 10x + 22 = 0
x² + 10x = -22
x² + 10x + 25 = -22 + 25
( x + 5 )² = 3
( x + 5 )² -3 = 0
Therefore,
line of symmetry of the line is = -5
∴ x = -5
An arithmetic sequence has this recursive formula:
a₁ = 5
an = an-1-4
What is the explicit formula for this sequence?
Answer:
[tex]a_n = 5 + (n-1)(-4)[/tex]
Step-by-step explanation:
So the explicit formula is generally defined as [tex]a_n = a_1 + d(n-1)[/tex]. where d is essentially the "slope", basically how much it's changing from term to term. anyways if you look at the recursive formula you'll notice it's taking the previous term and subtracting 4. This is what d is going to be, -4 and since a_1 is given you plug that in as well. This gives you the equation
[tex]a_n = 5 -4(n-1)[/tex] which can also be written as [tex]a_n = 5 + (n-1)(-4)[/tex]
Which segment is a reflection of segment AB over the line x = 1?
Line segment C D
Line segment E F
Line segment G H
Line segment I J
The reflection of segment AB over the line x = 1, will be the line segment EF. Then the correct option is B.
What is a transformation of geometry?A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.
Reflection does not change the size and shape of the geometry.
The line segment AB is given.
Then the reflection of segment AB over the line x = 1, will be the line segment EF.
Then the correct option is B.
The missing diagram is given below.
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Answer:
its BStep-by-step explanation:
Reflecting a Line Segment Across the X-axis or Y-axis
Step 1: Identify the endpoints of the line segment.
Step 2: Reflect the endpoints of the line segment.
Step 3: Connect the reflected endpoints in a straight line to form the reflected line segment.
A reflection across line moves each point to such that line is the perpendicular bisector of the segment connecting
Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
a < b+c2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
b < a+c2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
c < a+b2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Volume=
What is the volume?
Help please
Answer: 5.22
Step-by-step explanation:
The apothem = 87 cm = 0.87 m.
Using the formula [tex]A=\frac{1}{2}ap[/tex] to find the area of the base, where a is the apothem and p is the perimeter, we get [tex]A=\frac{1}{2}(0.87)(6)=2.61[/tex]
So, using the formula [tex]V=Bh[/tex], we get the volume to be [tex]2.61(2)=5.22 \text{ m}^{3}[/tex]
The curve through the ordered pairs (0, 10), (1, 5), and (2, 2.5) can be represented by the function f(x) = 10(0.5). What
is the multiplicative rate of change of the function?
The multiplicative rate of change of the exponential function is 0.5.
How to analyze an exponential function
In this problem we have three that are part of a exponential function, whose form is shown below:
[tex]y = a\cdot r^{x}[/tex] (1)
Where:
a - Initial valuer - Rate of changeWe notice that for Δx = 1, the value of y is halved. Hence, the multiplicative rate of change of the exponential function is 0.5.
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The circumference of C is 72 cm. What is the length of AB.
the minor arc
Answer:
9cm
Step-by-step explanation:
The CIRCUMFERENCE OF A CIRCLE is the distance round the circle.
It has the formular 2πr.
were r = radius
C = 2πr
72 = 2 × 3.142 × r
72 = 6.284r
dividing bothsides by 6.284
r = 72/ 6.284
r = 11.457
AB is an arc.
Lenght of an arc
[tex] \frac{ \alpha }{360} \times 2\pi \: r \\ \\ \frac{45}{360} \times 2 \times 3.142 \times 11.457 \\ \\ \frac{45}{360} \times 71.995 \\ \\ = 8.999 \\ \\ = 9cm[/tex]
what is the answer to this?
The gradient of the given graph is 1.5
Calculating GradientFrom the question, we are to determine the gradient of the graph
Gradient is given by the formula
[tex]m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
Where m is the gradient
Picking the points (-2, -2) and (2, 4) on the line
Then,
x₁ = -2
y₁ = -2
x₂ = 2
y₂ = 4
Putting the parameters into the equation, we get
[tex]m = \frac{4--2}{2--2}[/tex]
[tex]m = \frac{4+2}{2+2}[/tex]
[tex]m = \frac{6}{4}[/tex]
m = 1.5
Hence, the gradient of the given graph is 1.5
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The mean number of people per day visiting a museum in July was 140. If 20 more people each day visited the museum in august what was the mean number of people per day visiting in august
Answer:
80
Step-by-step explanation:
mean = 140+20=160
160/2
= 80
Answer: 160
Step-by-step explanation:
Just took it
Find the value of:
(3/4)²
a.9/16
b.6/8
c.6/4
d.9/4
Answer:
a
Step-by-step explanation:
(3/4) to the power of 2 means to multiply it by itself and so, 3/4 times itself is 9/16
Answer:
This is a - [tex]\dfrac{9}{16}[/tex]Step-by-step explanation:
Hello
[tex]\large\displaystyle\text{$\begin{gathered} \sf Apply \ the \ third \ exponent \ rule-: \bigg(\dfrac{x}{y}\bigg)^m=\dfrac{x^m}{y^m} \end{gathered}$}}[/tex]
Solve-:
[tex]\large\displaystyle\text{$\begin{gathered} \sf \bigg(\dfrac{x}{y}\bigg)^2= \dfrac{3^2} {4^2} =\boxed{\sf{\frac{9}{16}}} \end{gathered}$ }}[/tex]
[tex]\pmb{\tt{done \ !!}}[/tex]
[tex]\orange\hspace{300pt}\above2[/tex]