Stars that have ejected a planetary nebula go on to become white
dwarfs.
As we know planetary nebula is a type of glowing shell of ionized gases and there are various stages for the formation of stars. Stars are formed when dispersed matter in gaseous form starts coalescing together under the force of gravity into a compact object. Gravity continuously tries to shrink the object and during this process, the density and temperature inside the star rises.
The fate of the star depends critically on its mass. For stars with mass less than 1.4 solar masses of sun collapse into an extremely dense compact object called "white dwarf". Electron degeneracy pressure is responsible for counterbalancing the inward gravitational force in "white dwarf".
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A car travels around a curve. What can you say about the centripetal force if the velocity is tripled?
Group of answer choices
A) Nothing - there is no information on the mass of the car.
B) Nothing - there is no information on the radius of the curve.
C) The centripetal force will increase by a factor of nine
D) The centripetal force will increase by a factor of three.
Answer:
F = M a = M v^2 / R
If v is increased by three the force will be increased by nine,
C) is correct
Which equation describes the sum of the two vectors plotted below?
A. r=x+ý
B. r = x + 4y
C. r= 2x 1 3y
D. r 4X+ ý
The equation which describes the sum of the two vectors plotted is x + 4y; option A.
What is a vector?A vector is a quantity that has both magnitude and direction.
From the graph:
a = (-2,3)
b = (1,4)
Vector, OA = -2x + 3y
Vector, AB = 3x + y
Using the triangular law of the vector addition;
r = -2x + 3y + 3x + y
r = x + 4y
In conclusion, the triangular law of vector addition is useful in adding vectors.
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Energy released by the sun results from the process where atomic nuclei
a) none of these
b) combine
c) both of these
d) break apart
Answer:
b) combine
Explanation:
The energy from the sun is due to Nuclear Fusion where lighter nuclei combine to form heavier and stable nuclei this releasing a lot of energy in this process.
A car engine changes chemical energy into what types of energy? A. Mechanical and thermal B. Thermal and light C. Mechanical and nuclear D. Electromagnetic and mechanical A car engine changes chemical energy into what types of energy ? A. Mechanical and thermal B. Thermal and light C. Mechanical and nuclear D. Electromagnetic and mechanical
Howdy,
B. Thermal and light.
Which of the following is true about a theory?
A. It is almost always controversial among scientists.
B. It is the first step toward scientific knowledge
OC. It will be modified or replaced.
D. It is a guess about how something in nature happens.
Answer:
D. It is a guess about how something in nature happens.
Explanation:
Nature is not controlled by anyone else, so people have to guess in order to know if something happend in nature.
If a mineral contains only atoms of oxygen and a metal, it is most likely
O an oxide.
O a sulfate.
a phosphate.
a silicate.
Two vertical parallel straight wires carry currents upward and are separated by 8.2 cm. Wire 1 exerts a force on the other wire of 7.7 X 10-5 N/m and is carrying a current of 23.0 A. What is the current in the other wire
The current in the second wire is 1.37 A.
Current in the second wireThe current in the second wire is calculated from the magnetic force between the two wires.
F/L = (μI₁I₂)/(2πr)
where;
μ is permeability of free spaceI₂ is current in the second wireF/L is force per unit lengthr is the distance between the two wiresμI₁I₂ = (F/L 2πr)
I₂ = ((F/L 2πr) / (μI₁)
I₂ = (7.7 x ⁻⁵ x 2π x 0.082)/(4π x 10⁻⁷ x 23)
I₂ = 1.37 A
Thus, the current in the second wire is 1.37 A.
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What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subscript of 1, e.i. I1 = ) What is this value of the moment of inertia when the person is on the edge of the merry-go-round?
Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)
The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)
Moment of Inertia refers to:
the quantity expressed by the body resisting angular acceleration.It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)
here We note that the,
In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.
The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:
I(edge) = I (center of mass) + md^2
d be the distance from an axis through the object’s center of mass to a new axis.
I2(edge) = 1/3 (m*L^2)
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You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In joules, how much elastic potential energy is stored in the spring
The potential energy of the spring is 6.75 J
The elastic potential energy stored in the spring is given by the equation:
[tex]E= \frac{1}{2} kx^2[/tex]
where;
k is the spring constant
x is the compression/stretching of the string
In this problem, we have the spring as follows:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting in the equation, we get
[tex]E=\frac{1}{2} (150) (0.3)^2[/tex]
[tex]E=6.75J[/tex]
Therefore. the elastic potential energy stored in the spring is 6.75J .
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A baseball outfielder throws a 0.150-kg baseball at a speed of 40.0 m/s and an initial angle of 30.08 to the horizontal. What is the kinetic energy of the baseball at the highest point of its trajectory
The kinetic energy of the ball at the highest point of its motion is equal to 90.2 Joules.
Given the following data:
Mass of baseball = 0.150 kg
Speed of baseball = 40.0 m/s
V = v Cos(θ)
V= v cos 30
V= 40 x 0.867
V=34.68 m/s
K.E =1/2 MV^2
K.E= 1/2 x 0.150 x 34.68^2
K.E= 90.2 Joules.
Kinetic energy is a type of energy that an object or particle has due to its motion. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy.
Kinetic energy has three subcategories: vibration, rotation, and translation. Naturally, the oscillating kinetic energy is caused by a vibrating object. Rotational kinetic energy is generated by moving an object, and translational kinetic energy is caused by the collision of an object.
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Metal a has acofficient of linear expantion that is four times the cofficient of linear expantion of meta b. how does their cofficient of areal expantion of metalb, compare?
The coefficient of aerial expansion for metal b is one-fourth of the coefficient of aerial expansion for metal a.
Note: Most probably your question was to find the relation between the coefficient of aerial expansion for metal a and metal b.
Coefficient of linear expansion:
The ratio of the change in length of a solid to its original length when there is a unit change in temperature at constant pressure is called the coefficient of linear expansion. It is given by the formula,
α=ΔL/(Lo*ΔT)
where α is the coefficient of linear expansion, ΔL is the change in length Lo is the original length, and ΔT is the change in temperature.
Coefficient of aerial expansion:
The ratio of the change in surface area of a solid to its original surface area when there is a unit change in temperature at constant pressure is called the coefficient of aerial expansion. It is given by the formula,
β=ΔA/(Ao*ΔT)
where β is the coefficient of aerial expansion, ΔA is the change in surface area, Ao is the original surface area, and ΔT is the change in temperature.
Relation between α and β:
The relation between the coefficient of linear expansion and aerial expansion is given by the formula,
β=2α
Given that metal a has a coefficient of linear expansion four times that of metal b. It can be written.
α₁=4α₂
where α₁ is the coefficient of linear expansion for metal a and α₂ is the coefficient of linear expansion for metal b.
Then from the above relation, the ratio of the coefficient of aerial expansion β₁ and β₂ for metal a and metal b respectively is,
β₁/ β₂ = 2*(α₁)÷(2*(α₂))
β₁/ β₂= 2*(4α₂)÷(2*(α₂))
β₁/ β₂=4
β₂= β₁/4
Therefore, the coefficient of areal expansion of metal b is one-fourth of the coefficient of aerial expansion of metal a.
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A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Acceleration due to gravity is g = 9.8
m/g2
Answer:
Gravitational Potential Energy = Mass*Gravity*Height.
GPE = 852 * 9.8 * 3.2
GPE = 26718.72 Newtons.
Two thin wires rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are +q and –q. The potential difference between the centres of the two rings is
Answer:
Q/4πε0 [1/R - 1/√R2+d2]
Explanation:
Q/4πε0 [1/R - 1/√R2+d2] is the answer
explanation is attached.
toppr
A leaf fell from a tree branch. The path it followed is shown in the diagram below.
Which of these best describes why the leaf fell in a crooked path instead of straight down?
The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.
What is an air current?An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.
When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.
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a child is stationary on a swing. The child is given a push by a parent and the child starts swinging
Answer:
you havent given the full question
but im guessing momentum
momentum is the quantity of motion of a moving body, measured as a product of its mass and velocity or the impetus gained by a moving object.
Explanation:
as the child is pushed, it gathers momentum as its weight allows it be pushed forward, and the velocity is the speed driven by the amount of force the parent pushes on the child whilst they are swinging. The momentum is the result of this action
the equation that links these factors together are
p = mv
p = momentum
m = mass
v = velocity
hope i got it right ._.
Please help :/
Two objects have the same center point of the circle, but are located at different positions away from the center point. Each object is moving with uniform circular motion. Which would describe the tangential speed of the objects?
A) both objects would have the same tangential speed
B) the object with the smaller radius has a faster tangential speed
C) the object with the larger radius has a faster tangential speed
D) both objects would have oscillating tangential speeds
C. The object with the larger radius has a faster tangential speed.
What is tangential speed?
Tangential speed is the linear component of the speed of any object which is moving along a circular path.
v = ωr
where;
ω is angular speedr is the radius of the circular pathIf both object the same center point, they will have the same angular speed but different tangential speed due to their location from the center point.
Thus, the object with the larger radius has a faster tangential speed.
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The period of a pendulum depends on _____. Select all that apply. The period of a pendulum depends on _____. Select all that apply. its mass the string length the amplitude of the motion gravity the value of the pendulum constant
Answer:
Period is proportional to (L / g)^1/2
Only the length of the string and the force of gravity will affect the motion of a simple pendulum.
The time period of a pendulum depends on the length of pendulum, acceleration due to gravity and to some extends its amplitude also.
What is simple pendulum?A simple pendulum is a suspended body with one of its end fixed on a support and it is free to swing back and forth. The equation for the time period of simple pendulum is written as:
[tex]\rm T = 2\pi \sqrt{ \frac{l}{g} }[/tex]
Hence, the factors which affects the time period of pendulum are length and acceleration due to gravity g. This time period of the pendulum is the time taken to cover one complete oscillation.
Up to some extend the amplitude of the swing may affect the time period. However, mass has no effect on the period of a simple pendulum.
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A small girl applies a horizontal force of 2 Newtons to a 10-Newton box which slides across the floor with a constant speed of 3 m/s. What is the frictional force, in Newtons, by the floor on the box
2N is the frictional force by the floor on the box.
According, Newton's 2nd law[tex]F=mA[/tex]
where,
F = Horizontal force
m = Mass
a = Acceleration
But, a = 0 as Constant speed = 0 acceleration.
v = constant
Hence, there should be no net force. The frictional force is opposing the girl's force and should be equal to one another.
Frictional force = 2N
Therefore, the horizontal force applied by a small girl on the box is equal to the frictional force by the floor on the box.
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special metal hangers or stirrips called joist hangers are used when joist must be _____ the bottom of the grider or beam
Answer:
Special metal hangers or stirrups called joist hangers are used when joist must be flush with the bottom of the girder or beam.
Explanation:
A joist hanger also known as a beam hanger is a mechanical device which is used to fasten joists and rafters.The rafters are the carried members to beams and headers are the carrying members.Thus, special metal hangers or stirrups called joist hangers are used when joist must be flush with the bottom of the girder or beam.
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A cylindrical metal rod has a resistance R . If both its length and its diameter are tripled, its new resistance will be:
The new resistance will be 9R
A longer wire should have a higher electrical resistance than a wire with a bigger cross section, and vice versa. The electrical resistance of a wire should also be affected by the material from which it is formed.
The resistance of a wire is R = ρL/A. The volume of a wire is LA. If L increases by 3, then A must decrease by 3 in order for the volume to remain constant. If L increases by 3 and A decreases by 3, then L/A increases by 9 .
Hence the new resistance will be 9R
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What must the amplitude of a traveling wave of frequency 72.0 Hz be in order for the average power carried by the wave to be 0.363 W
The amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.
Amplitude of the wave
The amplitude of the wave travelling at the given frequency and power is calculated as follows;
U = (¹/₂)(T/v²)(ω²)(A²)(v)
U = (¹/₂)(T/v)(ω²)(A²)
U = (¹/₂)(T/v)(2πf)²(A²)
where;
U is the average power of the waveT is the tension in the wireω angular frequency of the waveA is amplitude of the wavev is the speed of the wavef is frequency of the waveThus, the amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.
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What do you mean by focus in science
The info below shows three kettles with their powers and the time they take to boil 500cm3 of water. If electricity costs 9p per unit, how much does it cost to boil 500cm3 of water using the 3kW kettle?
Kettle 1= 3mins =3kW
Kettle 2= 3.5mins= 2.2kW
Kettle 3=4.5mins=1.4kW
The cost of boiling 500 cm³ of water using the 3 KW Kettle is 1.35p
What is power?This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = Energy (E) / time (t)
P = E / t
How to determine the energyPower (P) = 3 KWTime (t) = 3 mins = 3 / 60 = 0.05 hEnergy (E) =?E = Pt
E = 3 × 0.05
E = 0.15 KWh
How to determine the costEnergy (E) = 0.15 KWhCost per unit = 9pCost =?Cost = Energy × cost per unit
Cost = 0.15 × 9
Cost = 1.35p
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A person has a choice of either pushing or pulling a book of ice with a mass of 50kg at a constant velocity. Assuming a coefficient of friction on 0.2 and pushing or pulling at the angle depicted, calculate the applied force needed for situations (a) and (b).
The applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.
How to determine the applied forceWe have that the force for situation 'a' is on an angle of inclination of 25° with the book of ice.
Thus,
Applied force = mg × sine of angle of inclination
Where mass, m = 50kg
g = acceleration due to gravity = 10m/s^2
Applied force = 50 × 10 × sin 25
Applied force = 50 × 10 × 0. 4226
Applied force = 211. 31 Newton
For situation 'b', the mass of block is adjacent to the book of ice, thus
Applied force = mg × cos of angle of inclination
Applied force = 50 × 10 × cos 25
Applied force = 50 × 10 × 0. 9063
Applied force = 453. 15 Newton
Thus, the applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.
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Suppose you are an engineer building a road across a mountain. From a prudential point of view, it would be easier and cheaper to build it through a family’s farm. This option would require compelling the family to move, which would be an extreme hardship for them. From a moral point of view, the family should be allowed to stay on their farm. Which view should take precedence?
Compensation may be provided, and a temporary residence provided, to the family so that they may make necessary adjustments to their living arrangements and other work-related matters. Even if it's not the nicest way to go about things, it's the most effective.
What is compensation due to damages?
Generally, Money given to a successful plaintiff in civil litigation is known as "compensatory damages." Damage awards are handed out by the civil justice system.
In conclusion, Engineers have a responsibility to find optimal solutions that satisfy the demands of the public in a manner that is both practical and beneficial to the progress of the country as a whole. In this case, forcing the farm family to relocate would be very difficult and upsetting for them, but it would be quite useful for the community as a whole if a road were to be constructed.
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The current in a wire is 3 a . calculate the charge that flows through the wire in 1 minute
The charge of the wire is 180 C.
What is a charge?The term charge is defined as the product of the current and the time taken. Thus we can write that;
Q = It
Q = charge
I = current
t = time
Hence;
Q = 3 A * 1 * 60 s = 180 C
Thus the charge of the wire is 180 C
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An object is launched upwards at an initial speed of 3 m/s. What is the maximum height reached by the object from where it was launched
Answer:
the maximum height reached by the object from where it was launched is 0.4591 m
Explanation:
initial speed of the object, u= 3 m/s
The velocity at the maximum height will always be 0.
Therefore, final velocity, v= 0 m/s
Using the Newton's equation of motion,
v^2 - u^2 = 2*g*h(max)
0 - u^2= 2*g*h(max)
h(max) = -u^2 /2* g
where g is the gravitational acceleration.
g= - 9.8 m/s^2
substituting the values in equation,
h(max)= - (3*3) / 2*(-9.8)
h(max) = 0.4591 m
the maximum height reached by the object from where it was launched is 0.4591 m
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A dentist using a dental drill brings it from rest to maximum operating speed of 387,000 rpm in 2.4 s. Assume that the drill accelerates at a constant rate during this time. (a) What is the angular acceleration of the drill in rev/s2
The angular acceleration of the drill is 2687.5 rev/s2
Given that operating speed of drill machine is 387000 rpm and the time given is 2.4s
We need to find the angular acceleration of the drill
Angular Acceleration is defined as the time rate of change of angular velocity.
The angular acceleration is also known as rotational acceleration.
It is a quantitative expression of the change in angular velocity per unit time.
The formula of angular acceleration is α =Δω/Δt
To find angular acceleration
α =Δω/Δt
Where Δω is the change in angular velocity
Δt is the change in time
Substituting the value We get ,
[tex]= \frac{387*10^3*1/60}{2.4}[/tex]
Therefore ,
α = 2687.5 rev/s2
Hence the angular acceleration is 2687.5 rev/s2
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A track & field jumper goes into the long jump with a speed of 5.0 m/s at an angle of 20⁰ above the horizontal. what is the jumper's horizontal speed as they jump? what is their vertical speed?
Answer: Horizontal Speed = 4.6 m/s
Vertical Speed = 1.7 m/s
Explanation:
Jumper's velocity = 5 m/s
Angle = 20 degrees
the angle is theta, so theta = 20 degrees
Theta is the angle between the hypothenuse and the adjacent side.
The horizontal side will be the adjacent side, and the vertical side will be the opposite side.
The hypothenuse = 5 m/s
First, let's calculate the adjacent side (horizontal speed)
We have cosine of theta, which is equal to adjacent side / hypothenuse
So, [tex]cos(20) = adjacent/5[/tex]
Multiply 5 on both sides, to get the 5 on the right side canceled.
5cos(20) = adjacent side.
4.6 = adjacent side
Horizontal Speed = 4.6 m/s
Now, let's calculate the vertical speed.
To do that, we need to calculate the opposite side.
We can calculate the opposite side with the help of sin.
The sin of theta equals to opposite side / hypothenuse
[tex]sin(20)=opposite/5[/tex]
We do the same thing, multiply 5 on both sides.
5sin(20) = opposite
1.7 = opposite
Vertical Speed = 1.7 m/s
Hope I Helped!
What is the mass moment of inertia of a 20kg sphere with a radius of 0.2m about a point on the sphere's perimeter
Answer:
I = M R^2 is the moment of inertia about a point that is a distance R from the center of mass (uniform distributed mass).
The moment of inertia about the center of a sphere is 2 / 5 M R^2.
By the parallel axis theorem the moment of inertia about a point on the rim of the sphere is I = 2/5 M R^2 + M R^2 = 7/5 M R^2
I = 7/5 * 20 kg * .2^2 m = 1.12 kg m^2