Stars that have ejected a planetary nebula go on to become white dwarfs. supernovae. protostars. red giants.

2N is the frictional force by the floor on the box.

[tex]F=mA[/tex]

where,

F = Horizontal force

m = Mass

a = Acceleration

But, a = 0 as Constant speed = 0 acceleration.

       v = constant

Hence, there should be no net force. The frictional force is opposing the girl's force and should be equal to one another.

Frictional force = 2N

Therefore, the horizontal force applied by a small girl on the box is equal to the frictional force by the floor on the box.

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The charge of the wire is 180 C.

The term charge is defined as the product of the current and the time taken. Thus we can write that;

Q = It

Q = charge

I = current

t = time

Hence;

Q = 3 A * 1 * 60 s = 180 C

Thus the charge of the wire is 180 C

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Answer:

you havent given the full question

but im guessing momentum

momentum is the quantity of motion of a moving body, measured as a product of its mass and velocity or the impetus gained by a moving object.

Explanation:

as the child is pushed, it gathers momentum as its weight allows it be pushed forward, and the velocity is the speed driven by the amount of force the parent pushes on the child whilst they are swinging. The momentum is the result of this action

the equation that links these factors together are

p = mv

p = momentum

m = mass

v = velocity

hope i got it right ._.

The equation which describes the sum of the two vectors plotted is x + 4y; option A.

A vector is a quantity that has both magnitude and direction.

From the graph:

a = (-2,3)

b = (1,4)

Vector, OA = -2x + 3y

Vector, AB = 3x + y

Using the triangular law of the vector addition;

r = -2x + 3y + 3x + y

r = x + 4y

In conclusion, the triangular law of vector addition is useful in adding vectors.

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Answer:

Special metal hangers or stirrups called joist hangers are used when joist must be flush with the bottom of the girder or beam.

Explanation:

Thus, special metal hangers or stirrups called joist hangers are used when joist must be flush with the bottom of the girder or beam.

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Answer:

D. It is a guess about how something in nature happens.

Explanation:

Nature is not controlled by anyone else, so people have to guess in order to know if something happend in nature.

Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)

The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

I2(edge) = 1/3 (m*L^2)

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The cost of boiling 500 cm³ of water using the 3 KW Kettle is 1.35p

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = Energy (E) / time (t)

P = E / t

E = Pt

E = 3 × 0.05

E = 0.15 KWh

Cost = Energy × cost per unit

Cost = 0.15 × 9

Cost = 1.35p

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The current in the second wire is 1.37 A.

The current in the second wire is calculated from the magnetic force between the two wires.

F/L = (μI₁I₂)/(2πr)

where;

μI₁I₂ = (F/L 2πr)

I₂  = ((F/L 2πr) / (μI₁)

I₂  = (7.7 x ⁻⁵ x 2π x 0.082)/(4π x 10⁻⁷ x 23)

I₂  = 1.37 A

Thus, the current in the second wire is 1.37 A.

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The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.

An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.

When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.

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Answer:

b) combine

Explanation:

The energy from the sun is due to Nuclear Fusion where lighter nuclei combine to form heavier and stable nuclei this releasing a lot of energy in this process.

Howdy,

B. Thermal and light.

Answer:

Gravitational Potential Energy = Mass*Gravity*Height.

GPE = 852 * 9.8 * 3.2

GPE = 26718.72 Newtons.

Answer:

I = M R^2 is the moment of inertia about a point that is a distance R from the center of mass (uniform distributed mass).

The moment  of inertia about the center of a sphere is 2 / 5 M R^2.

By the parallel axis theorem the moment of inertia about a point on the rim of the sphere is  I = 2/5 M R^2 + M R^2 = 7/5 M R^2

I = 7/5 * 20 kg * .2^2 m = 1.12 kg m^2

Answer: Horizontal Speed = 4.6 m/s

              Vertical Speed = 1.7 m/s

Explanation:

Jumper's velocity = 5 m/s

Angle = 20 degrees

the angle is theta, so theta = 20 degrees

Theta is the angle between the hypothenuse and the adjacent side.

The horizontal side will be the adjacent side, and the vertical side will be the opposite side.

The hypothenuse = 5 m/s

First, let's calculate the adjacent side (horizontal speed)

We have cosine of theta, which is equal to adjacent side / hypothenuse

So, [tex]cos(20) = adjacent/5[/tex]

Multiply 5 on both sides, to get the 5 on the right side canceled.

5cos(20) = adjacent side.

4.6 = adjacent side

Horizontal Speed = 4.6 m/s

Now, let's calculate the vertical speed.

To do that, we need to calculate the opposite side.

We can calculate the opposite side with the help of sin.

The sin of theta equals to opposite side / hypothenuse

[tex]sin(20)=opposite/5[/tex]

We do the same thing, multiply 5 on both sides.

5sin(20) = opposite

1.7 = opposite

Vertical Speed = 1.7 m/s

Hope I Helped!

The coefficient of aerial expansion for metal b is one-fourth of the coefficient of aerial expansion for metal a.

Note: Most probably your question was to find the relation between the coefficient of aerial expansion for metal a and metal b.

Coefficient of linear expansion:

The ratio of the change in length of a solid to its original length when there is a unit change in temperature at constant pressure is called the coefficient of linear expansion. It is given by the formula,

α=ΔL/(Lo*ΔT)

where α is the coefficient of linear expansion,  ΔL is the change in length Lo is the original length, and ΔT is the change in temperature.

Coefficient of aerial expansion:

The ratio of the change in surface area of a solid to its original surface area when there is a unit change in temperature at constant pressure is called the coefficient of aerial expansion. It is given by the formula,

β=ΔA/(Ao*ΔT)

where β is the coefficient of aerial expansion,  ΔA is the change in surface area, Ao is the original surface area, and ΔT is the change in temperature.

Relation between α and β:

The relation between the coefficient of linear expansion and aerial expansion is given by the formula,

β=2α

Given that metal a has a coefficient of linear expansion four times that of  metal b. It can be written.

α₁=4α₂

where α₁ is the coefficient of linear expansion for metal a and α₂ is the coefficient of linear expansion for metal b.

Then from the above relation, the ratio of the coefficient of aerial expansion β₁ and β₂ for metal a and metal b respectively is,

β₁/ β₂ = 2*(α₁)÷(2*(α₂))

β₁/ β₂= 2*(4α₂)÷(2*(α₂))

β₁/ β₂=4

β₂= β₁/4

Therefore, the coefficient of areal expansion of metal b is one-fourth of the coefficient of aerial expansion of metal a.

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Answer:

F = M a = M v^2 / R

If v is increased by three the force will be increased by nine,

C) is correct

Compensation may be provided, and a temporary residence provided, to the family so that they may make necessary adjustments to their living arrangements and other work-related matters. Even if it's not the nicest way to go about things, it's the most effective.

Generally, Money given to a successful plaintiff in civil litigation is known as "compensatory damages." Damage awards are handed out by the civil justice system.

In conclusion, Engineers have a responsibility to find optimal solutions that satisfy the demands of the public in a manner that is both practical and beneficial to the progress of the country as a whole. In this case, forcing the farm family to relocate would be very difficult and upsetting for them, but it would be quite useful for the community as a whole if a road were to be constructed.

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Answer:

Q/4πε0 [1/R - 1/√R2+d2]

Explanation:

Q/4πε0 [1/R - 1/√R2+d2] is the answer

explanation is attached.

toppr

The applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.

We have that the force for situation 'a' is on an angle of inclination of 25° with the book of ice.

Thus,

Applied force = mg × sine of angle of inclination

Where mass, m = 50kg

g = acceleration due to gravity = 10m/s^2

Applied force = 50 × 10 × sin 25

Applied force = 50 × 10 × 0. 4226

Applied force = 211. 31 Newton

For situation 'b', the mass of block is adjacent to the book of ice, thus

Applied force = mg × cos of angle of inclination

Applied force = 50 × 10 × cos 25

Applied force = 50 × 10 × 0. 9063

Applied force = 453. 15 Newton

Thus, the applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.

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C. The object with the larger radius has a faster tangential speed.

Tangential speed is the linear component of the speed of any object which is moving along a circular path.

v = ωr

where;

If both object the same center point, they will have the same angular speed but different tangential speed due to their location from the center point.

Thus, the object with the larger radius has a faster tangential speed.

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The amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.

The amplitude of the wave travelling at the given frequency and power is calculated as follows;

U = (¹/₂)(T/v²)(ω²)(A²)(v)

U = (¹/₂)(T/v)(ω²)(A²)

U = (¹/₂)(T/v)(2πf)²(A²)

where;

Thus, the amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.

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Answer:

the maximum height reached by the object from where it was launched is 0.4591 m

Explanation:

initial speed of the object, u= 3 m/s

The velocity at the maximum height will always be 0.

Therefore,  final velocity, v= 0 m/s  

Using the Newton's  equation of motion,

v^2 - u^2 = 2*g*h(max)

0 - u^2= 2*g*h(max)

h(max) = -u^2 /2* g

where g is the gravitational acceleration.

g= - 9.8 m/s^2

substituting the values in equation,

h(max)= - (3*3) / 2*(-9.8)

h(max) =  0.4591 m

the maximum height reached by the object from where it was launched is 0.4591 m

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Answer:

Period is proportional to (L / g)^1/2

Only the length of the string and the force of gravity will affect the motion of a simple pendulum.

The time period of a pendulum depends on the length of pendulum, acceleration due to gravity and to some extends its amplitude also.

A simple pendulum is a suspended body with one of its end fixed on a support and it is free to swing back and forth. The equation for the time period of simple pendulum is written as:

[tex]\rm T = 2\pi \sqrt{ \frac{l}{g} }[/tex]

Hence, the factors which affects the time period of pendulum are length  and acceleration due to gravity g. This time period of the pendulum is the time taken to cover one complete oscillation.

Up to some extend the amplitude of the swing may affect the time period. However, mass has no effect on the period of a simple pendulum.

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The angular acceleration of the drill is 2687.5 rev/s2

Given that operating speed of drill machine is 387000 rpm and the time given is 2.4s

We need to find the angular acceleration of the drill

Angular Acceleration is defined as the time rate of change of angular velocity.

The angular acceleration is also known as rotational acceleration.

It is a quantitative expression of the change in angular velocity per unit time.

The formula of angular acceleration is α =Δω/Δt

To find angular acceleration

α =Δω/Δt

Where Δω is the change in angular velocity

Δt is the change in time

Substituting the value  We get ,

  [tex]= \frac{387*10^3*1/60}{2.4}[/tex]

Therefore ,

α = 2687.5 rev/s2

Hence the angular acceleration is 2687.5 rev/s2

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The new resistance will be 9R

A longer wire should have a higher electrical resistance than a wire with a bigger cross section, and vice versa. The electrical resistance of a wire should also be affected by the material from which it is formed.

The resistance of a wire is R = ρL/A. The volume of a wire is LA. If L increases by 3, then A must decrease by 3 in order for the volume to remain constant. If L increases by 3 and A decreases by 3, then L/A increases by 9 .

Hence the new resistance will be 9R    

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The potential energy of the spring is 6.75 J

The elastic potential energy stored in the spring is given by the equation:

[tex]E= \frac{1}{2} kx^2[/tex]

where;

k is the spring constant

x is the compression/stretching of the string

In this problem, we have the spring as follows:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting in the equation, we get

[tex]E=\frac{1}{2} (150) (0.3)^2[/tex]

[tex]E=6.75J[/tex]

Therefore. the elastic potential energy stored in the spring is 6.75J .

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The kinetic energy of the ball at the highest point of its motion is equal to 90.2 Joules.

Given the following data:

Mass of baseball = 0.150 kg

Speed of baseball = 40.0 m/s

V = v Cos(θ)

V= v cos 30

V= 40 x 0.867

V=34.68 m/s

K.E =1/2 MV^2

K.E= 1/2 x 0.150 x 34.68^2

K.E= 90.2 Joules.

Kinetic energy is a type of energy that an object or particle has due to its motion. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy.

Kinetic energy has three subcategories: vibration, rotation, and translation. Naturally, the oscillating kinetic energy is caused by a vibrating object. Rotational kinetic energy is generated by moving an object, and translational kinetic energy is caused by the collision of an object.

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