Since 1980, the population of Trenton, NJ, has been decreasing at a rate of 2.72% per year. The rate of change of the city's population Pt years after 1980, is given by: = -0.0272P dP de A. (4 pts) in 1980 the population of Trenton was 92,124. Write an exponential function that models this situation.

Answer:

Step-by-step explanation:

Midway Island (Midway Atoll) is located in the far northern end of the Hawaiian archipelago.

All of the plastic trash at Midway is believed to have been carried there by ocean currents, from various parts of the world.

The albatross feeds by diving into the ocean and catching fish and squid with its hooked beak.

There are so many dead birds on Midway because they ingest plastic trash, mistaking it for food, and it fills up their stomachs, preventing them from getting proper nutrition.

Albatross adults bring an average of about 5 pounds (2.3 kilograms) of plastic to Midway every year to feed their chicks.

The red coke cap looks like a natural prey/food source of the albatross.

Microplastics are small plastic particles, less than 5 millimeters in size, that are the result of the breakdown of larger plastic products.

The two big problems with plastics are that they do not biodegrade and that they can harm wildlife when ingested or entangled.

Hi! The answer is 2.4. To find the value of the integral from 1 to 5 of f(x) dx, we can use the given information about the integrals from 1 to 7 and from 5 to 7.

Step 1: Use the given information.
We are given that the integral from 1 to 7 of f(x) dx is 8, and the integral from 5 to 7 of f(x) dx is 5.6.

Step 2: Subtract the two integrals.
To find the integral from 1 to 5 of f(x) dx, we can subtract the integral from 5 to 7 from the integral from 1 to 7. This is because the integral from 1 to 5 covers the difference between the two given integrals.

Step 3: Calculate the difference.
So, the integral from 1 to 5 of f(x) dx is the integral from 1 to 7 minus the integral from 5 to 7:
8 - 5.6 = 2.4

Therefore, the integral from 1 to 5 of f(x) dx is 2.4.

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The Volume of Remaining block is  (l w h - 1125) cm³

We have,

Edge of cube = 15 cm

So, Volume of cube

= 15 x 15 x 15

= 1125 cm³

Now, Volume of Remaining block

= Volume of cuboid - Volume of cube

= l w h - 1125 cm³

Here we just have to put the dimension of cuboid in place of l w h.

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Answer:

False

Step-by-step explanation:

In the confidence interval, the population parameter is unknown and the interval is a random variable.

The nonsystematic standard deviation of the equally-weighted portfolio is approximately 0.714.

The APT (Arbitrage Pricing Theory) model is a financial model that attempts to explain the returns of a portfolio based on the risk factors that affect it. In the APT model, the total risk of a portfolio is divided into two components: systematic risk and nonsystematic risk.

Systematic risk is the risk that is common to all assets in the market and cannot be diversified away, while nonsystematic risk is the risk that is unique to a particular asset or group of assets and can be diversified away.

Assuming that the average value of the excess return of a security i (ei) is equal to 25 and there are 50 securities in the equally-weighted portfolio, we can use the following formula to calculate the nonsystematic standard deviation of the portfolio:

σnonsystematic = √[(Σei^2)/n - (Σei/n)^2]

where Σei^2 is the sum of squared excess returns of all securities in the portfolio, Σei is the sum of excess returns of all securities in the portfolio, and n is the number of securities in the portfolio.

Since the portfolio is equally-weighted, each security has the same weight of 1/50. Therefore, the excess return of the portfolio (ep) is given by:

ep = (1/50)Σei

Substituting this into the formula for σnonsystematic, we get:

σnonsystematic = √[(50/49)Σ(ei - ep)^2]

Since the portfolio is equally-weighted, the variance of the excess return of the portfolio is given by:

Var(ep) = Var((1/50)Σei) = (1/50^2)ΣVar(ei) = (1/50^2)Σσi^2

where σi is the standard deviation of the excess return of security i.

Substituting this into the formula for σnonsystematic, we get:

σnonsystematic = √[(50/49)Σ(ei - ep)^2] = √[(50/49)Σei^2/n - Var(ep)]

Since the average value of the excess return of a security i (ei) is equal to 25, we can assume that the mean excess return of the portfolio (ep) is also equal to 25. Therefore, the variance of the excess return of the portfolio (Var(ep)) is given by:

Var(ep) = Var((1/50)Σei) = (1/50^2)ΣVar(ei) = (1/50^2)Σσi^2

Substituting the value of σi = 0 (since it is not given), we get:

Var(ep) = (1/50^2)Σσi^2 = (1/50^2) × 50 × 0 = 0

Substituting this into the formula for σnonsystematic, we get:

σnonsystematic = √[(50/49)Σei^2/n - Var(ep)] = √[(50/49)Σei^2/n]

Substituting the value of n = 50 and the average value of ei = 25, we get:

σnonsystematic = √[(50/49) × 25^2/50] = 5/7 ≈ 0.714

Therefore, the nonsystematic standard deviation of the equally-weighted portfolio is approximately 0.714.

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Spearman's rank correlation coefficient would be an appropriate statistic  for an associational research question.

When the two variables of interest are non-normally distributed and skewed, Spearman's rank correlation coefficient would be an appropriate statistic to use for an associational research question involving the correlation between two non-normally distributed continuous variables.

Spearman's rank correlation coefficient is a nonparametric measure of correlation that is used to assess the strength and direction of association between two ranked variables. It measures the degree to which the rank order of one variable is related to the rank order of another variable, regardless of their actual values.

Unlike Pearson's correlation coefficient, which assumes a linear relationship between the variables and normality of data, Spearman's correlation coefficient is robust to outliers, non-linear relationships, and non-normality of data. It works by converting the data into ranks, which can be used to compute the correlation coefficient.

Therefore, if we have two non-normally distributed, skewed continuous variables and want to examine the association between them, Spearman's rank correlation coefficient would be an appropriate statistic to use.

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The median of the sample data collected by the researcher in the following sample data 512685675124 is 5, which is option (d).

We need to arrange the numbers in ascending or descending order.

1 1 2 2 4 5 5 5 6 6 7 8 (arranged in ascending order)

The middle number is the median. Since there are 12 digits in the given sample data, the median is the average of the 6th and 7th digits.

So, the median is (5 + 5) / 2 = 5

Therefore, median of the sample data collected by the researcher is 5 (Option d).

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Okay, let's break this down step-by-step:

(a) The vacant lot has a frontage of 130 ft. So the x-axis ranges from 0 to 130 ft.

(b) We can consider the upper boundary of the lot as the graph of a function f(x) over the x-interval [0, 130]. So the area of the lot is the integral:

A = ∫0^\130 f(x) dx

(c) We divide [0, 130] into 5 equal subintervals of length 26 ft. So: 0-26 ft, 26-52 ft, 52-78 ft, 78-104 ft, 104-130 ft.

(d) At the midpoint of each subinterval, we measure the distance to the upper boundary. These are:

f(13) = ?

f(39) = ?

f(65) = ?

f(91) = ?

f(117) = ?

(e) To approximate the area using rectangles, we do:

A ≈ (f(13) - 0) * 26 + (f(39) - f(13)) * 26 +

(f(65) - f(39)) * 26 + (f(91) - f(65)) * 26 +

(f(117) - f(91)) * 26 + (130 - f(117)) * 26

(f) If we don't know the actual values of f(x) at the midpoints, we can estimate them. Let's say:

f(13) ≈ 15

f(39) ≈ 35

f(65) ≈ 55

f(91) ≈ 75

f(117) ≈ 95

(g) Plugging these in:

A ≈ (15 - 0) * 26 + (35 - 15) * 26 +

(55 - 35) * 26 + (75 - 55) * 26 +

(95 - 75) * 26 + (130 - 95) * 26 = 33,750 square ft

So the approximate area of the vacant lot is 33,750 square ft.

Please let me know if you have any other questions!

To eliminate the parameter t from the given parametric equations x = 4sin(3t) and y = 4cos(3t), we can use the trigonometric identity sin^2(t) + cos^2(t) = 1.

Squaring both equations, we get: x^2 = 16sin^2(3t) y^2 = 16cos^2(3t) Adding these two equations and using the trigonometric identity, we get: x^2 + y^2 = 16(sin^2(3t) + cos^2(3t)) x^2 + y^2 = 16 Taking the square root of both sides, we get: sqrt(x^2 + y^2) = 4 .

Therefore, the equation that represents the given parametric equations as a single equation in x and y is: x^2 + y^2 = 16 This is the equation of a circle with center at the origin and radius 4.  the equation becomes: (x/4)² + (y/4)² = 1 Finally, we can write the single equation in x and y as: x² + y² = 16.

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Answer:

Step-by-step explanation:

when we find the volume of a cylinder we must know

the radius

the length of the cylinder-L

L^2=11^2+4^2

L^2= 144+16

L=√160

L=4√10 INCHES

                       = 3.14*16*4√10

                       = 3.14*64*2.23*1.41

                       = 632.192528

                       ≈632 CUBIC INCHES

Answer:

9.5T - 85 = 250

Step-by-step explanation:

9.5 being the cost per tablecloth, and subtracting cost of goods.

It evaluates to the following

9.5T - 85 = 250

9.5T = 335

T= 35.263 or 36 Tablecloths.

Answer:

Step-by-step explanation:

15/4 n+5.4

Answer:

Step-by-step explanation:

13x+20

The abbreviated chemical reaction that summarizes RNA polymerase-directed transcription is: RNAp + DNA → mRNA + DNA'.

A chemical reaction is a process that involves the rearrangement of the molecular or ionic structure of a substance, resulting in a change in its chemical properties. During a chemical reaction, atoms are either rearranged within molecules or combined with other molecules to form new products. Chemical reactions are essential for many biological processes and are also used to produce a variety of products, such as medicines, plastics, and food additives. The reactants of a chemical reaction are the original molecules or ions before the reaction takes place, and the products are the molecules or ions formed after the reaction has occurred.

This reaction represents the process by which RNA polymerase binds to the DNA double helix, reads the genetic code, and produces a complementary mRNA molecule. The DNA molecule is then released in its original form (DNA'), allowing for the mRNA molecule to be used in translation.

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The British entrepreneurs than for British corporate managers at a significance level of 0.05.

The two-sample t-test for the difference in means, with unequal variances.

The null hypothesis is

H0: μ1 - μ2 = 0

where μ1 is the population mean number of job changes for British entrepreneurs, and μ2 is the population mean number of job changes for British corporate managers.

The alternative hypothesis is:

Ha: μ1 - μ2 > 0

We will use a significance level of α = 0.05.

The test statistic is:

t = (x1 - x2 - 0) / sqrt[([tex]s1^2[/tex]/n1) + ([tex]s2^2[/tex]/n2)]

Where x1 is the sample mean number of job changes for British entrepreneurs,

x2 is the sample mean number of job changes for British corporate managers,

s1 is the sample standard deviation of job changes for British entrepreneurs,

s2 is the sample standard deviation of job changes for British corporate managers,

n1 is the sample size for British entrepreneurs and

n2 is the sample size for British corporate managers.

Substituting the given values, we get:

t = (1.91 - 0.21 - 0) / sqrt[([tex]1.32^2[/tex]/125) + ([tex]0.53^2[/tex]/86)]

t = 5.46

Using a t-distribution table with degrees of freedom approximated by the smaller of n1 - 1 and n2 - 1.

The critical value for a one-tailed test at α = 0.05 is 1.66. Since our calculated t-value of 5.46 is greater than the critical value of 1.66, we reject the null hypothesis.

Therefore,

We have sufficient evidence to conclude that the mean number of job changes is higher for British entrepreneurs than for British corporate managers at a significance level of 0.05.

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The series converges and the sum of the geometric series is -7/15. The given series is ∑((-7)^(n-1))/(8^n) for n=1 to infinity.

To determine whether the given geometric series is convergent or divergent, and to find its sum if convergent, we need to follow these steps:
1. Identify the geometric series formula:
2. Find the common ratio (r): The common ratio r is the ratio of consecutive terms in the series. In this case, r = (-7)/8.
3. Determine convergence or divergence: A geometric series converges if the absolute value of r is less than 1, and diverges otherwise. In this case, since |(-7)/8| = 7/8 < 1, the series converges.
4. Calculate the sum: Since the series converges, we can use the sum formula for an infinite geometric series: sum = a / (1 - r), where a is the first term of the series. In this case, a = (-7)^(1-1) / (8^1) = 1/8. Therefore, the sum is:
sum = (1/8) / (1 - (-7/8))
sum = (1/8) / (15/8)
sum = 1/15
So, the sum of the given convergent geometric series is 1/15.

This is a geometric series with the first term a = [infinity] (-7)^1-1/8^1 = -7/8 and common ratio r = -7/8.
To determine if the series converges or diverges, we need to check if the absolute value of the common ratio is less than 1.
| -7/8 | = 7/8 < 1
Therefore, the series converges.
To find the sum, we can use the formula:
S = a / (1 - r)
Plugging in the values, we get:
S = (-7/8) / (1 - (-7/8)) = (-7/8) / (15/8) = -7/15
So the sum of the geometric series is -7/15.

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Answer:

answer this question in this photo.

The correct expression representing the value stored in the variable x after executing the given program is: a. 2*3*3*3 This is because the program starts with x having a value of 2 and then multiplies x by 3 four times in a row.

The expression that represents the value stored in the variable x as a result of executing the program is option D: 24*4*4*4. This is because the program starts with the x being assigned the value 2, and then the instruction "XX * 3" is executed 4 times.

This means that the value of x is multiplied by 3, four times in a row. So, the final value of x will be 2 * 3 * 3 * 3 * 3, which simplifies to 24 * 4 * 4 * 4.

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(a) Converges to √2/2.

(b) Converges to 1.

(c) Diverges because the values oscillate.

(d) Diverges because cos(π/7n) approaches infinity.

(a) The given sequence is cos(π/7n), where n = 1, 2, 3, .... As n approaches infinity, π/7n approaches zero. The limit of cos(x) as x approaches zero is √2/2. Hence, the limit of the given sequence is √2/2, and it converges to √2/2.

(b) The given sequence is cos(π/7n), where n = 1, 2, 3, .... As n approaches infinity, π/7n approaches zero. The limit of cos(x) as x approaches zero is 1. Hence, the limit of the given sequence is 1, and it converges to 1.

(c) The given sequence is cos(π/7n), where n = 1, 2, 3, .... As n approaches infinity, π/7n approaches zero. However, the values of cos(π/7n) oscillate between -1 and 1 as n increases. Therefore, the sequence does not converge, and it diverges.

(d) The given sequence is cos(π/7n), where n = 1, 2, 3, .... As n approaches infinity, π/7n approaches zero. However, cos(x) approaches infinity as x approaches π/2 from the left. Since π/7n approaches π/2 as n approaches infinity, cos(π/7n) approaches infinity as well. Therefore, the sequence diverges.

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The perimeter of parallelogram WXYZ is given by the expression 13X - 32 and given that WXYZ is a parallelogram, to determine the lengths of all four sides.

Given that WX = 2XW, XY = X7, and YZ = 3X - 8.

To find the perimeter of parallelogram WXYZ, we need to determine the lengths of all four sides. Calculate the perimeter by summing up the lengths of all four sides.

The perimeter of a polygon is the sum of the lengths of all its sides. In this case, the perimeter P can be calculated as:

P = WX + XY + YZ + ZW

Substituting the given values, we have:

P = 2XW + X7 + 3X - 8 + XW

Since WXYZ is a parallelogram, opposite sides are equal in length. Therefore, we can equate XW to ZY and solve for XW.

XW = YZ = 3X - 8

Substitute the value of XW into the perimeter equation:

P = 2(3X - 8) + X7 + 3X - 8 + XW

Simplifying this expression gives:

P = 6X - 16 + X7 + 3X - 8 + 3X - 8

Combining like terms, gives:

P = 13X - 32

Therefore, the perimeter of parallelogram WXYZ is given by the expression 13X - 32 and given that WXYZ is a parallelogram, to determine the lengths of all four sides.

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The demand equation is  b. D = -25x + 225.

Since the demand equation is linear and involves "x" as the price, and "D" as the number of units, we can use the two points given to determine the equation.

At a price of $1, 200 units are demanded: (1, 200)
At a price of $9, 0 units are demanded: (9, 0)

Now, we can find the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

In this case:

m = (0 - 200) / (9 - 1)
m = -200 / 8
m = -25

Now, we can use one of the points (either point will give the same result) to find the y-intercept (b) by plugging the values into the linear equation:

D = m * x + b

Using the point (1, 200):

200 = -25 * 1 + b
b = 200 + 25
b = 225

Now, we have the demand equation:

D = -25x + 225

So the correct answer is: b. D = -25x + 225.

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The coordinates of B' after the reflection over the line y = -2 are given as follows:

B'(-2, -9).

The original coordinates of B are given as follows:

B(-2,5).

The reflection line is given as follows:

y = -2.

y = -2 is a horizontal line, hence the reflection line is obtained as follows:

Moving 7 units below the line, the coordinates of B' are given as follows:

B'(-2, - 2 - 7) = B'(-2, -9).

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n ≈ 17.128

Perpetuity pays 1 at the end of year 2, 2 at the end of year 3, etc. . . . and 17 at the end of year 18, and after year 18 payments remain constant at level 17.

Let P be the present value of the perpetuity, then we have:

P = 77.1/0.105

P = 734.2857142857142

The present value of the perpetuity is the sum of the present values of each cash flow, so we have:

[tex]P = 1/(1+0.105)^2 + 2/(1+0.105)^3 + ... + n/(1+0.105)^{n+1[/tex]

Using the formula for the sum of a geometric series, we have:

[tex]P = [1/(1-1/(1+0.105))] - [1/(1+0.105)^{n+2}] - [(n+1)/(1+0.105)^{n+1}][/tex]

Simplifying, we get:

[tex]P = 10.5/0.105 - [1/(1+0.105)^{n+2}] - [(n+1)/(1+0.105)^{n+1}][/tex]

Substituting the value of P, we get:

[tex]734.2857142857142 = 100/0.105 - [1/(1+0.105)^{n+2}] - [(n+1)/(1+0.105)^{n+1}][/tex]

Simplifying and solving for n using numerical methods, we get:

n ≈ 17.128

Therefore, the perpetuity pays 1 at the end of year 2, 2 at the end of year 3, etc. . . . and 17 at the end of year 18, and after year 18 payments remain constant at level 17.

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n ≈ 17.128

Perpetuity pays 1 at the end of year 2, 2 at the end of year 3, etc. . . . and 17 at the end of year 18, and after year 18 payments remain constant at level 17.

Let P be the present value of the perpetuity, then we have:

P = 77.1/0.105

P = 734.2857142857142

The present value of the perpetuity is the sum of the present values of each cash flow, so we have:

[tex]P = 1/(1+0.105)^2 + 2/(1+0.105)^3 + ... + n/(1+0.105)^{n+1[/tex]

Using the formula for the sum of a geometric series, we have:

[tex]P = [1/(1-1/(1+0.105))] - [1/(1+0.105)^{n+2}] - [(n+1)/(1+0.105)^{n+1}][/tex]

Simplifying, we get:

[tex]P = 10.5/0.105 - [1/(1+0.105)^{n+2}] - [(n+1)/(1+0.105)^{n+1}][/tex]

Substituting the value of P, we get:

[tex]734.2857142857142 = 100/0.105 - [1/(1+0.105)^{n+2}] - [(n+1)/(1+0.105)^{n+1}][/tex]

Simplifying and solving for n using numerical methods, we get:

n ≈ 17.128

Therefore, the perpetuity pays 1 at the end of year 2, 2 at the end of year 3, etc. . . . and 17 at the end of year 18, and after year 18 payments remain constant at level 17.

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Nothing happened for real.

i think its not a big deal for you but it will be a big deal for your parents ;))))

Use your knowledge of genetic biology and lecture them. Maybe they don't understand.

Just kidding =))))

In short, you may have an optical problem =))))

P/s: don't be furious :'))) it's gonna easy to get old

ok done. Thank to me >:333

The value of L(2) is for recursive definition of Lucas numbers is 3.

According to the given recursive definition of the Lucas numbers, L(2) = 3 since n=2 is the second term in the sequence and its value is defined as 3.
Based on the recursive definition of Lucas numbers L(n) given, let's determine the value of L(2):

L(n) = 1 if n = 1
L(n) = 3 if n = 2
L(n) = L(n - 1) + L(n - 2) if n > 2

Since we're looking for L(2), we can use the second condition in the definition:

L(2) = 3

So, the value of L(2) is 3.

A set of numbers called the Lucas numbers resembles the Fibonacci sequence. The series was researched in the late 19th century by the French mathematician François Édouard Anatole Lucas, who gave it its name.

This is how the Lucas sequence is described:

For n > 1, L(0) = 2 L(1) = 1 L(n) = L(n-1) + L(n-2)

The sequence's initial few numerals are thus:

2, 1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, ...

The Lucas sequence, like the Fibonacci sequence, offers a variety of intriguing mathematical characteristics and linkages to different branches of mathematics. For instance, exactly like in the Fibonacci sequence, the ratio of successive Lucas numbers converges to the golden ratio[tex](1 + \sqrt{5})/2[/tex].

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Using the Tangent-Secant Theorem, the value of x, is calculated in teh figure as: x = 16.

The Tangent-Secant Theorem states that if a tangent and a secant are drawn from an external point to a circle, then the square of the length of the tangent is equal to the product of the lengths of the secant and its external part.

Applying the theorem:

60² = (2x - 5 + 48)(48)

3,600 = (2x + 43)(48)

3,600 = 96x + 2,064

3,600 - 2,064 = 96x

1,536 = 96x

1,536/96 = 96x/96

16 = x

x = 16

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Linear Transformation is occurring here when the vector <-5,2> is transformed and it causes no change which is option B.

What is Linear Transformation?

A transformation in the form T: R n → R m satisfying, is called as the linear transformation. Mainly there are two types of the linear transformation which is zero transformation and identity transformation. T(→x)=→(0) for all →x, this defines the zero transformation and T(→x)=→(x) this defines identity transformation. These transformation are the functions that sends the linear combinations to linear combinations(i.e. by preserving co-efficient). Thus any function is called linear when it preserves coefficients.

Here in this question

(a)Firstly we need to calculate T(-u)= T(5,2) =(2,1)

                                               T(-5)(5,2) = (-5)T(5,2)

                                                -5(2,10) = (-10,-5)

(b) T(-9v)= T(1,3) = (-1,3)

     T((9)(1,3)) = (9).T(1,3)

     (9)(-1,3) = (9,27)

(c) T(-5u+9v)

    T(-5u)+T(9v)

Putting the values from (a) and (b) in the above equation  we get:

(-19, 22) and this is the final answer.

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This given equation dy dt = 2ty +1, y(0) = -3 is separable.

The solution to the initial value problem is h(t) =y(t) = [tex](9/7) t^2 - (9/7) 2^2 e^(-7t) + 238[/tex].

To determine whether the given differential equation is separable, we need to check if it can be written in the form of:
dy/dt = f(t)g(y)
In this case, the equation is dy/dt = 2ty + 1.

We can rearrange it as:
dy/(2ty + 1) = dt
This suggests that the equation is separable, and we can proceed to solve it using integration. Integrating both sides, we get:
[tex]1/2 ln(2ty + 1) = t^{2 + C}[/tex]
where C is the constant of integration. Multiplying both sides by 2 and exponentiating, we obtain:
[tex]2ty + 1 = e^(2t^2 + 2C)[/tex]
Solving for y, we get:
y(t) = [tex](e^(2t^2 + 2C) - 1)/(2t)[/tex]
To find the value of C, we use the initial condition y(0) = -3. Substituting t = 0 and y = -3, we get:
-3 = [tex](e^(2C) - 1)/0[/tex]
This is undefined, which means that the given initial value problem does not have a unique solution. Therefore, the equation is separable, but the initial value problem is ill-posed.
Moving on to the second equation, y'+7y = 9t + 238 with y(2) = 0, we can see that it is a first-order linear equation, which can be solved using an integrating factor. Multiplying both sides by [tex]e^(7t)[/tex], we get:
[tex]e^(7t) y' + 7e^(7t) y = (9t + 238) e^(7t)[/tex]
The left-hand side can be rewritten as:
d/dt [tex](e^(7t) y) = (9t + 238) e^(7t)[/tex]
Integrating both sides with respect to t, we obtain:
[tex]e^(7t) y = (9/7) t^2 e^(7t) + 238 e^(7t) + C[/tex]
where C is the constant of integration. Solving for y, we get:
y(t) = [tex](9/7) t^2 + 238 + Ce^(-7t)[/tex]
Using the initial condition y(2) = 0, we can find the value of C as:
0 = [tex](9/7) 2^2 + 238 + Ce^(-7*2)[/tex]
C =[tex]- (9/7) 2^2 e^(14) - 238[/tex]
Substituting this value of C in the equation for y, we get:
y(t) = [tex](9/7) t^2 - (9/7) 2^2 e^(-7t) + 238[/tex]

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Answer:

I think it's D

Step-by-step explanation:

We are told that the costs of the decorations is $120, which is the money the club has to waste and thus negative (they start at negative money raised). Since we want to recover from this debt, we want to charge each student 10 dollars. As a result, each time we obtain $10 from the students the graph will go up until it passes 0 and thus pays the debt. The money that goes over 0 in the graph thus shows the money raised.

I hope this helps.

Answer:

da forth one

Step-by-step explanation:

[tex]\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{"y" varies inversely with }x^2}{y = \cfrac{k}{x^2}}\hspace{5em}\textit{we also know that} \begin{cases} x=10\\ y=1 \end{cases} \\\\\\ 1=\cfrac{k}{10}\implies 10 = k\hspace{9em}\boxed{y=\cfrac{10}{x^2}} \\\\\\ \textit{when x = 5, what's "y"?}\qquad y=\cfrac{10}{5^2}\implies y=\cfrac{10}{25}\implies y=\cfrac{2}{5}[/tex]