find the elasticity of the demand function 2p 3q = 90 at the price p = 15

The largest value that A×B/A-B can have is 780.

To arrive at this answer, we can begin by rewriting the expression as A + (AB)/(A - B). We can then use some algebraic manipulation to find the maximum value of this expression. First, we can rewrite the expression as (A^2 - AB + AB)/(A - B), which simplifies it to A + (AB)/(A - B). Next, we can rewrite the expression as A - B + 2B + (2AB)/(A - B), which simplifies to (A - B) + 2B + (2AB)/(A - B). Finally, we can rewrite the expression as 2B + (2AB)/(A - B) + (A - B), which is equivalent to 2(B + (AB)/(A - B)).

Since A and B are distinct counting numbers, the largest possible value of B is 39, and the largest possible value of A is 40. Therefore, the largest possible value of (AB)/(A - B) is (40*39)/(40-39) = 1560. Plugging this value into the expression for 2(B + (AB)/(A - B)) gives us 2(B + 1560), and since B is at its maximum value of 39, the largest possible value of the entire expression is 2(39 + 1560) = 780.

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The largest value that A×B/A-B can have is 780.

To arrive at this answer, we can begin by rewriting the expression as A + (AB)/(A - B). We can then use some algebraic manipulation to find the maximum value of this expression. First, we can rewrite the expression as (A^2 - AB + AB)/(A - B), which simplifies it to A + (AB)/(A - B). Next, we can rewrite the expression as A - B + 2B + (2AB)/(A - B), which simplifies to (A - B) + 2B + (2AB)/(A - B). Finally, we can rewrite the expression as 2B + (2AB)/(A - B) + (A - B), which is equivalent to 2(B + (AB)/(A - B)).

Since A and B are distinct counting numbers, the largest possible value of B is 39, and the largest possible value of A is 40. Therefore, the largest possible value of (AB)/(A - B) is (40*39)/(40-39) = 1560. Plugging this value into the expression for 2(B + (AB)/(A - B)) gives us 2(B + 1560), and since B is at its maximum value of 39, the largest possible value of the entire expression is 2(39 + 1560) = 780.

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Answer:- Since the determinant D is negative, we can infer that the stationary point P(10, 20) is a saddle point for the function z = f(x, y).

on the given information for the function z = f(x, y) at the point P(10, 20), we know that f_x = f_y = 0, f_xx = 4, f_yy = -2, and f_xy = 4. From this, we can infer the following:

1. Since f_x = f_y = 0, it means that the function has a stationary point at P(10, 20), as the partial derivatives with respect to x and y are both zero.

2. To determine the type of stationary point, we can examine the second-order partial derivatives. We use the determinant of the Hessian matrix, which is calculated as:

D = (f_xx)(f_yy) - (f_xy)^2

Substitute the given values:

D = (4)(-2) - (4)^2 = -8 - 16 = -24

Since the determinant D is negative, we can infer that the stationary point P(10, 20) is a saddle point for the function z = f(x, y).

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The properties of an open set:

The properties of a closed set:

An open set is a set in which every point is surrounded by a neighborhood that lies entirely within the set. Therefore, an open set cannot have any boundary points. This is why the empty set and the whole space are considered open sets. Additionally, any union of open sets must also be open because any point within the union must be in at least one of the open sets, and hence not on the boundary.

On the other hand, a closed set is a set that includes all its boundary points, which means it can contain its limit points as well. This is why the empty set and the whole space are considered closed sets. Moreover, the intersection of any collection of closed sets must also be closed because any point within the intersection must be in every closed set, and hence on the boundary of each set.

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Answer:pe120

Step-by-step explanation:b is the real so round to the nearest hundred

To show that (0,0) is a critical point for both functions, we need to find the gradient and set it equal to the zero vector:

∇f(x1, x2) = [2x1, 3x[tex]2^2[/tex]] = [0,0]

∇g(x1, x2) = [2x1, 4x[tex]2^3[/tex]] = [0,0]

Solving these systems of equations yields (x1, x2) = (0,0), indicating that (0,0) is a critical point for both functions.

Next, we need to compute the Hessians of f and g at (0,0):

Hf(x1, x2) = [2 0; 0 6x²]

Hf(0,0) = [2 0; 0 0]

Hg(x1, x2) = [2 0; 0 12x²]

Hg(0,0) = [2 0; 0 0]

Both Hessians have a zero eigenvalue, indicating that they are positive semi-definite.

To determine if (0,0) is a local/global minimizer for f and g, we need to examine the behavior of these functions near (0,0).

For f, the second partial derivative with respect to x1 is positive, but the second partial derivative with respect to x2 is zero. This means that near (0,0), the function f has a "valley" in the x2 direction and increases without bound as we move away from (0,0) in this direction. Therefore, (0,0) is not a local minimizer for f.

For g, both second partial derivatives are positive, indicating that g has a local minimum at (0,0). Since the Hessian is positive semi-definite, this minimum is also a global minimum. Therefore, (0,0) is a local and global minimizer for g.

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Henry will make $115 in 5 hours

Henry made $207 in 9 hours

The first step is to calculate the amount the Henry will make in 1 hour

207= 9

x= 1

cross multiply both sides

9x= 207

x= 207/9

x= 23

The amount made in 5 hours can be calculated as follows

$23= 1 hour

y= 5 hours

cross multiply

y= 23 × 5

y= 115

Hence Henry will make $115 in 5 hours

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The inverse Laplace transform of F(s)=e^(-7s) / (s^2+2s−2) is f(t) = (1/2)*e^(t-1)sinh(√3t).

B. To find the inverse Laplace transform of F(s), we first need to factor the denominator of F(s) using the quadratic formula:

s^2 + 2s - 2 = 0

s = (-2 ± √(2^2 - 4(1)(-2))) / (2(1))

s = (-2 ± √12) / 2

s = -1 ± √3

Therefore, we can write:

F(s) = e^(-7s) / [(s - (-1 + √3))(s - (-1 - √3))]

Next, we use partial fraction decomposition to express F(s) in terms of simpler fractions:

F(s) = A / (s - (-1 + √3)) + B / (s - (-1 - √3))

Multiplying both sides by the denominator of F(s), we get:

e^(-7s) = A(s - (-1 - √3)) + B(s - (-1 + √3))

To solve for A and B, we substitute s = -1 + √3 and s = -1 - √3 into the equation above, respectively:

e^(-7(-1 + √3)) = A((-1 + √3) - (-1 - √3))

e^(-7(-1 - √3)) = B((-1 - √3) - (-1 + √3))

Simplifying the equations, we get:

e^(7 + 7√3) = 2A√3

e^(7 - 7√3) = -2B√3

Solving for A and B, we obtain:

A = e^(7 + 7√3) / (4√3)

B = -e^(7 - 7√3) / (4√3)

Therefore, we can write:

F(s) = e^(-7s) / [(s - (-1 + √3))(s - (-1 - √3))]

F(s) = [e^(7 + 7√3) / (4√3)] / (s - (-1 + √3)) - [e^(7 - 7√3) / (4√3)] / (s - (-1 - √3))

Now we can use the following inverse Laplace transform formula:

L^-1{1/(s - a)} = e^(at)

L^-1{1/[(s - a)(s - b)]} = (1/(b-a)) * [e^(at) - e^(bt)]

Using the formula above and simplifying, we get:

f(t) = (1/2)*e^(t-1)sinh(√3t)

Therefore, the inverse Laplace transform of  Function F(s) is f(t) = (1/2)*e^(t-1)sinh(√3t).

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Using the point-slope form of a linear equation, the correct option is d. y = 2x - 7.

A linear equation is an equation in which the highest power of the variable (usually represented as 'x') is 1. It represents a straight line on a coordinate plane. The general form of a linear equation is:

y = mx + b

According to the given information:

The equation of the line that passes through the points (7, -7) and (6, -5) can be found using the point-slope form of a linear equation, which is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope of the line.

First, let's find the slope (m) using the given points:

m = (y2 - y1) / (x2 - x1)

Plugging in the values for (x1, y1) = (7, -7) and (x2, y2) = (6, -5):

m = (-5 - (-7)) / (6 - 7)

= 2 / -1

= -2

So, the slope of the line is -2.

Now, let's plug the slope and one of the given points (7, -7) into the point-slope form:

y - (-7) = -2(x - 7)

Simplifying, we get:

y + 7 = -2x + 14

Rearranging the equation to the standard form, we get:

2x + y = 7

Comparing this with the provided answer choices, we can see that the correct equation is:  d. y = 2x - 7

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Answer:

d

Step-by-step explanation:

The value of stickers does Jenny have is, 108

We have to given that;

Benny has 60 stickers. He is going to swap 3/4 of his stickers with Jenny.

And, Jenny says that the amount of stickers that she is swapping is only 5/12 of her total amount of stickers.

Hence, We can formulate;

Amount of stickers for Jenny is,

⇒ 3/4 of 60

⇒ 45

And, Let total amount of stickers = x

Hence, We get;

5/12 of x = 45

5x = 12 × 45

x = 12 × 9

x = 108

Thus, The value of stickers does Jenny have is, 108

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We would need approximately 194,819 coulombs of charge to electroplate 35.0 grams of chromium.

Coulomb The SI unit for the amount of charge is the coulomb. The charge carried by 6.24 x 10 unit charges is one coulomb because one electron has an elementary charge, e, of 1.602 x coulombs.

The balanced chemical formula for chromium electroplating is:

Cr3+ + 3e- → Cr

A mole of Cr3+ ions must be reduced to a mole of chromium metal in order to reach this equation, which states that three moles of electrons are needed.

Chromium has a molar mass of about 52 g/mol. Thus, the following is required to electroplate 35.0 grammes of chromium:

n = mass/molar mass = 35.0 g/52 g/mol = 0.673 mol

Since one mole of Cr3+ ions must be reduced by three moles of electrons, we require:

3 × 0.673 mol = 2.019 mol of electrons

Finally, we can use the Faraday constant to convert moles of electrons to coulombs of charge:

1 F = 96,485 C/mol e-

Consequently, the coulombs needed to electroplate 35.0 grammes of chromium are as follows:

2.019 mol × 96,485 C/mol e- = 194,819 C

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A 90% confidence interval is then constructed from this information, which yields (0.5251, 0.8082). The question asks which of the following is a correct interpretation of this interval.

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The exact area of the surface obtained by rotating the curve about the x-axis is (4/3)π (2^(3/2) - 1).

To find the exact area of the surface obtained by rotating the curve defined by x = 6t − 2t^3, y = 6t^2 about the x-axis, we can use the formula:

A = 2π ∫a^b y √(1 + (dy/dx)^2) dt

where a and b are the limits of integration and dy/dx can be expressed in terms of t using the parameter equations.

First, let's find dy/dx:

dy/dx = (dy/dt)/(dx/dt) = (12t)/(6 - 6t^2) = 2t/(1 - t^2)

Next, we can substitute y and dy/dx into the formula for A:

A = 2π ∫0^1 6t^2 √(1 + (2t/(1 - t^2))^2) dt

Simplifying the expression under the square root:

1 + (2t/(1 - t^2))^2 = 1 + 4t^2/(1 - 2t^2 + t^4) = (1 + t^2)^2/(1 - 2t^2 + t^4)

Substituting back into the integral:

A = 2π ∫0^1 6t^2 (1 + t^2)/(1 - 2t^2 + t^4)^(1/2) dt

We can simplify the denominator using the identity (a^2 - b^2) = (a + b)(a - b):

1 - 2t^2 + t^4 = (1 - t^2)^2 - (t^2)^2 = (1 - t^2 - t^2)(1 - t^2 + t^2) = (1 - 2t^2)(1 + t^2)

Substituting back into the integral:

A = 2π ∫0^1 6t^2 (1 + t^2)/((1 - 2t^2)(1 + t^2))^(1/2) dt

We can cancel out the factor of (1 + t^2) in the denominator with the numerator:

A = 2π ∫0^1 6t^2 (1 + t^2)/(1 - 2t^2)^(1/2) dt

Next, we

can use the substitution u = 1 - 2t^2, du/dt = -4t, to simplify the integral:

A = 2π ∫1^(-1) (3/4) (1 - u)^(1/2) du

Making the substitution v = 1 - u, dv = -du, we can further simplify the integral:

A = 2π ∫0^2 (3/4) v^(1/2) dv

Evaluating the integral, we get:

A = 2π [2v^(3/2)/3]_0^2 = (4/3)π (2^(3/2) - 1)

Therefore, the exact area of the surface obtained by rotating the curve about the x-axis is (4/3)π (2^(3/2) - 1).

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The area under the standard normal curve to the left of z = -0.96 is approximately 0.1685.

To find the area under the standard normal curve to the left of z = -0.96, follow these steps,
1. Locate z = -0.96 on the horizontal axis of the standard normal curve. The standard normal curve is a bell-shaped curve with a mean of 0 and a standard deviation of 1.
2. Use a z-table, which provides the areas under the standard normal curve, to look up the area corresponding to z = -0.96. You can find a z-table in a statistics textbook or online.
3. Locate the row and column in the z-table that correspond to z = -0.96. The row will have -0.9, and the column will have 0.06. The intersection of this row and column will give you the area to the left of z = -0.96.
4. Read the area from the table and round it to four decimal places if necessary.

The area under the standard normal curve to the left of z = -0.96 is approximately 0.1685.

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The exact length of the curve is approximately 4.697 units.

To find the exact length of the curve, we need to use the formula:
L = ∫[a,b] [tex]\sqrt{[dx/dt]^2}  + [dy/dt]^2[/tex] dt
Where a and b are the limits of t, dx/dt and dy/dt are the derivatives of x and y with respect to t.
In this case, we have:
x = et − t
y = 4et⁄2 = 2et
So, dx/dt = [tex]e^t[/tex] - 1 and dy/dt =[tex]2e^t[/tex].
Substituting these values into the formula, we get:
L = ∫[0,2] √[tex](e^t - 1)^2[/tex] + [tex](2e^t)^2[/tex] dt
L = ∫[0,2] √([tex]e^{(2t)}[/tex] - [tex]2e^t[/tex] + 1 + [tex]4e^{(2t)}[/tex]) dt
L = ∫[0,2] √([tex]5e^{(2t)}[/tex] - [tex]2e^t[/tex] + 1) dt
This integral cannot be solved analytically, so we need to use numerical methods to approximate the value of L. One such method is Simpson's rule, which gives the:
L ≈ 4.697

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Since C can be any constant, all of the answer choices are true. Therefore, the correct answer is (d) all of these choices are true

The integral of the density function over its entire domain must equal 1 for it to be a legitimate density function. Let's set up the integral and solve for x:

∫ f(x) dx = ∫ 0.25 dx = 0.25x + C

Setting this equal to 1, we get:

0.25x + C = 1

0.25x = 1 - C

x = 4 - 4C

This means that x can take on any value in the interval [4-4C, 4+4C] and still have a legitimate density function. Since C can be any constant, all of the answer choices are true. Therefore, the correct answer is (d) all of these choices are true.

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Answer:

There are 144 cubes in total. So 144÷36= 4 layers this is the answer.

Step-by-step explanation:

(a) N = Unable to determine
(b) Mean = 11.531 (rounded to three decimal places)
(c) P = 0.1515 (rounded to four decimal places)

To fill in the missing numbers for (a) through (c) in the MINITAB output for a hypothesis test of a population mean:

We will use the given information and formulas.

(a) N = X / SE Mean
N = X / 0.2767

(b) Mean = (Upper Bound - Z * SE Mean) / Confidence Level
Mean = (10.6699 - (-1.03) * 0.2767) / 0.95

(c) P = Given Z value
P = -1.03

Now, let's calculate the values:

(a) N = X / 0.2767
We have the equation N = X / 0.2767, but we don't have the value of X. Unfortunately, we cannot find N without X.

(b) Mean = (10.6699 - (-1.03) * 0.2767) / 0.95
Mean = (10.6699 + 0.2849) / 0.95
Mean = 10.9548 / 0.95
Mean = 11.531

(c) P = -1.03
P-value is always positive, so we convert the given Z value to the P-value using a Z-table or calculator.
P ≈ 0.1515

So, we have:
(a) N = Unable to determine
(b) Mean = 11.531 (rounded to three decimal places)
(c) P = 0.1515 (rounded to four decimal places)

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Answer:

Step-by-step explanation:

7/6x=140

x=140*6/7

x=120

By using the Midpoint Theorem and the SAS postulate, we have proven that DE is parallel to BC and that BC is congruent to DE in the quadrilateral ABCA. (option a)

To prove that DE is parallel to BC, we need to show that the corresponding angles are equal. Since E is the midpoint of AC, we can use the Midpoint Theorem to show that AE is equal to EC. Similarly, since D is the midpoint of BA, we can use the Midpoint Theorem to show that AD is equal to DB.

Now we have two triangles, ADE and BDC, with corresponding sides that are equal. Specifically, we know that AD = DB, DE = DC, and angle A is equal to angle B. Using the Side-Angle-Side (SAS) postulate, we can conclude that the two triangles are congruent. This means that the corresponding angles of the triangles are equal, and therefore, DE is parallel to BC.

To prove that BC is congruent to DE, we need to show that the corresponding sides are equal. Since we have already shown that DE = DC, we just need to show that BC = CD. Using the Midpoint Theorem, we know that E is the midpoint of AC, which means that AE = EC. Adding AD to both sides of the equation, we get:

AE + AD = EC + AD

AD + DE = BC

Since AD = DB and DE = DC, we can substitute those values into the equation to get:

DB + DC = BC

Since D is the midpoint of BA, we know that DB + DC = BC. Therefore, we have shown that BC is congruent to DE.

Hence the correct option is (a).

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The required answer is the table V and the pt() function in R both use the t-distribution to approximate the P-value for a given test statistic and degrees of freedom.

For the given hypothesis test H0: μ = 10 against H1: μ <10 with variance unknown and n = 20, the value of the test statistic is t0 = 1.25.
Modern hypothesis testing is an inconsistent hybrid of the formulation, methods and terminology developed in the early 20th century.

He modern version of hypothesis testing is a hybrid of the two approaches that resulted from confusion by writers of statistical textbooks (as predicted by Fisher) beginning in the 1940.

a. To approximate the P-value using Table V, we need to determine the degrees of freedom (df). Since n = 20, df = n-1 = 19. Using Table V, we find the P-value for t0 = 1.25 and df = 19 to be approximately 0.113.

b. To compute the P-value using R, we can use the pt() function with the arguments t0 and df, where df = n-1. The code and output are as follows:

> t0 <- 1.25
> df <- 19
> p_value <- pt(t0, df, lower.tail = TRUE)
> p_value
[1] 0.1133356

c. Yes, the answer in part b agrees with the answer in part a. Both methods approximate the P-value to be approximately 0.113. This is because.

Table V and the pt() function in R both use the t-distribution to approximate the P-value for a given test statistic and degrees of freedom.

a. To approximate the P-value using Table V, we need to look for the t-distribution table with 19 degrees of freedom (df = n - 1 = 20 - 1 = 19). Locate the row with df = 19 and find the closest value to t0 = 1.25 in that row. The corresponding value in the top row (P-value) is the approximate P-value for this hypothesis test.

b. To compute the P-value using R, you can use the following code:

```R
t0 <- 1.25
df <- 19
p_value <- pt(t0, df, lower.tail = FALSE)
p_value
```
l hypothesis test is a method of statistical inference used to decide whether the data at hand sufficiently support a particular hypothesis. Hypothesis testing allows us to make probabilistic statements about population parameters.
The `pt` function calculates the P-value for the t-distribution with the given degrees of freedom and test statistic. `lower.tail = FALSE` is used because we are testing for H1: μ < 10.

c. Compare the P-value obtained from Table V (part a) and the P-value computed using R (part b). If the values are close, it means both methods agree and provide a consistent result. Small discrepancies might be due to the approximation of the P-value in the table, as the table has limited values compared to the continuous calculations done by R.

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Answer: 0.25 or 25%

Step-by-step explanation: The probability of getting heads in a coin flip is 0.5, or 50%. In order to account for the two times we flip the coin, we multiply that by two. 0.5(2)=0.25 or 25%.

Step-by-step explanation:

Two flips has  2^2 = 4 possible outcomes

  ONE of which is   Heads - Heads

    one out of 4     =   1/4 = .25

H H

H T

T H

T T

a. True, the two normal distributions have the same spread because they both have a standard deviation of 3.7.

b. False, the two normal distributions are not centered at the same place because their means are -2 and 6, respectively.

a. True, the two normal distributions have the same spread. The spread of a normal distribution is determined by its standard deviation. In this case, both distributions have a standard deviation of 3.7, which means they have the same spread.

b. False, the two normal distributions are not centered at the same place. The center of a normal distribution is represented by its mean. The first distribution has a mean of -2, and the second distribution has a mean of 6. Since the means are different, they are not centered at the same place.

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Step-by-step explanation:

To compare the distances of 2 miles, 4,800 feet, and 4,400 yards, we need to convert all the distances to the same unit. Let's choose feet as the common unit.

1 mile = 5,280 feet (by definition)

2 miles = 10,560 feet (since 2 miles x 5,280 feet/mile = 10,560 feet)

1 yard = 3 feet (by definition)

4,400 yards = 4,400 x 3 feet/yard = 13,200 feet

Now that we have all distances in feet, we can order them from least to greatest:

2 miles = 10,560 feet

4,400 yards = 13,200 feet

4,800 feet = 4,800 feet

Therefore, the order from least to greatest is: 4,800 feet, 2 miles, 4,400 yards.

Note that it is always important to keep track of the units when comparing or combining quantities.

The value of the constant c that makes f(x) a probability density function is 2/9

In order for the function f(x) to be a probability density function, it must satisfy the following two conditions:
1. f(x) is non-negative for all x.
2. The area under the curve of f(x) over the entire range of x must be equal to 1.

From the given function, we can see that f(x) is non-negative for all x, since it is defined as zero for x less than zero and as cx for x between 0 and 3.To determine the value of the constant c that makes f(x) a probability density function, we need to find the value of c that makes the area under the curve equal to 1.

The area under the curve of f(x) from x = 0 to x = 3 can be found by taking the definite integral:
∫(0 to 3) cx dx = [c/2 * x^2] from 0 to 3 = 9c/2

For f(x) to be a probability density function, this area must be equal to 1:
9c/2 = 1

Solving for c, we get:
c = 2/9
Therefore, the value of the constant c that makes f(x) a probability density function is 2/9.

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Answer:

32 miles

Step-by-step explanation:

9 + 9 + 7 + 7 = 32

Helping in the name of Jesus.

The sequence converges, and its limit is 7/8.

To determine whether the sequence converges or diverges, we can use the limit comparison test. We will compare the given sequence to a known sequence whose convergence behavior is known.

Let bn = 1/n. Then, we have lim (an/bn) = lim ((7n+2)/(8n) * n/1) = 7/8. Since 0 < 7/8 < infinity, and the series of bn converges (by the p-series test), we can conclude that the series of an converges as well.

To find the limit, we can use direct substitution: lim (7n+2)/(8n) = 7/8. Therefore, the sequence converges to 7/8.

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Answer:JL-12

KJ-11

Step-by-step explanation:

Answer:

LK = 50.911 which is approximate to 51

JK = 58.78 which is approximate to 58.8

Step-by-step explanation:

we can find JL by using tan so

tan(60°) = opposite/adjecent

tan(60°) =JL/12√6 when u criscross it you will get

tan(60°) ×12√6 =JL

JL=50.911 ~ 51

we can find Jk by using cos

so

cos(60°) =(12√6)/Jk

cos(60°)×Jk = 12√6

(12√6)/cos (60°) = Jk

Jk = 58.78 ~ 58.8

We can solve for c1 and c2 using these initial conditions, but we cannot determine y_p(t) without more information about g(t).

The given differential equation is:

4y'' + 4y' + 17y = g(t)

where y(0) = 0 and y'(0) = 0.

This is a second-order linear differential equation with constant coefficients. To solve this, we first find the characteristic equation:

4r^2 + 4r + 17 = 0

Using the quadratic formula, we get:

r = (-4 ± sqrt(4^2 - 4(4)(17))) / (2(4))

r = (-4 ± sqrt(-48)) / 8

r = (-1 ± i sqrt(3)) / 2

The characteristic roots are complex and conjugate, so the solution to the homogeneous equation is:

y_h(t) = c1 e^(-t/2) cos((sqrt(3)/2)t) + c2 e^(-t/2) sin((sqrt(3)/2)t)

To find the particular solution, we need to determine the form of g(t). Without more information about g(t), we cannot determine a particular solution. Therefore, we write:

y(t) = y_h(t) + y_p(t)

where y_p(t) is the particular solution.

Since y(0) = 0 and y'(0) = 0, we have:

0 = y(0) = y_h(0) + y_p(0)

0 = y'(0) = (-1/2)c1 + (sqrt(3)/2)c2 + y_p'(0)

We can solve for c1 and c2 using these initial conditions, but we cannot determine y_p(t) without more information about g(t).

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The linear approximation l(x) near x = 9 for the function f(x) = 1/x is:
l(x) = 1/9 - (1/81)(x - 9).

To find the linear approximation l(x) to y = f(x) near x = a for the function f(x) = 1/x, where a = 9, follow these steps,

1. Calculate the function value at a: f(a) = f(9) = 1/9.
2. Calculate the derivative of f(x) with respect to x: f'(x) = -1/x^2.
3. Calculate the derivative value at a: f'(a) = f'(9) = -1/81.
4. Formulate the linear approximation l(x) using the point-slope form of a linear equation: l(x) = f(a) + f'(a) * (x - a).

By substituting the values calculated in steps 1-3 into step 4, the linear approximation l(x) near x = 9 for the function f(x) = 1/x is,

l(x) = 1/9 - (1/81)(x - 9).

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