SI units are used for scientific works. Why? ​

Answers

Answer 1

Answer:

SI units are used for scientific works to bring uniformity in measurements all over the world.


Related Questions

A horse trainer records the distance a horse travels during three different trials.

What is the horse's average speed in kilometers per minute?

Answers

The average speed is calculated by doing total distance / total time

4.5 + 9.0 + 13.5 = 27km
15 + 30 + 45 = 90min

27 / 90 = 0.3
The horse’s average speed is 0.3km/min

The horse's average speed in kilometers per minute is equal to 0.3 kilometers per minute.

Given the following data:

Time 1 = 15 minutesTime 2 = 30 minutesTime 3 = 45 minutesDistance 1 = 4.5 kilometersDistance 2 = 9.0 kilometersDistance 3 = 13.5 kilometers

To determine the horse's average speed in kilometers per minute:

First of all, we would find the total time and total distance covered:

For total time:

[tex]Total \;time = 15 + 30+45[/tex]

Total time = 90 minutes

For total distance:

[tex]Total \;time = 4.5 + 9.0+13.5[/tex]

Total time = 27 kilometers.

Mathematically, average speed is given by the formula:

[tex]Average\;speed = \frac{Total\;distance}{Total\;time} \\\\Average\;speed = \frac{27}{90}[/tex]

Average speed = 0.3 kilometers per minute.

Read more on average speed here: https://brainly.com/question/17742679

Một chất điểm chuyển động trong mặt phẳng Oxy với phương trình :
{ = 2 + 10

Answers

Answer:

plz write your questions in English

A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. How fast is the boy going?​

Answers

Answer:

2 m/s

Explanation:

A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. Velocity of boy is 2 m/sec.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question, a 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s.

Using conservation of momentum, velocity = (20*5)/50 = 2 m/sec.

A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. Velocity of boy is 2 m/sec.

To learn more about velocity refer the link:

brainly.com/question/18084516  

#SPJ2

Do you think it wise to make a decision under the influence of an emotion?​

Answers

Answer:

no because It can be a disadvantage for us

Answer:

no

Explanation:

nop it isn't wise to make a decision under the influence of emotion because if you act and make decision From influence of emotion you will gonna regret so think before you make decision

Government has banned the use of plastic bags in some states. Why?​

Answers

Answer:

people throw plastic into the oceon

Explanation:

.when people throw plastic into the ocean mother nature gets hurt because of waste if it continues the see we see today will be dirty if all of humanity throwed all of the plastic and waste in the ocean

Please answer quick!! if you're right I'll mark you brainliest!
the surface gravity on Jupiter Is 2.4 times the of earth what would your weight be on Jupiter if you weighed 110 pounds on earth

Answers

Answer:

The equation would be 2.4 x 110 which is 264

You would weigh 264 on Jupiter

Explanration:

If a car is traveling at 10m/s and then accelerates for 10s at a rate of 0.5m/s^2,what will be final velocity?

Answers

Answer:

[tex]u= 10 \frac{m}{s} \\ t = 10 \: s \\ a = .5 \frac{m}{ {s}^{2} } \\ v = x \\ v = u + at \\ x = 10 + .5 \times 10 \\ x = 10 + 5 \\ x = 15 \frac{m}{s} \\ thank \: you[/tex]

Answer:

15m/s

Explanation:

a=(Vf-Vi)/t

0.5m/s^2=(Vf-10m/s)/10s

when we solve this Vf=15m/s^2

ball (100 grams) is attached by string (ignorable mass) oflength SOcm and is in a ircular motion: If the ball makes 20 round trips (complete oscillations) along the ircular path in 5 seconds (a) Calculate the time period (T) of the ball in S. units: (b) Calculate the angular velocity (0) of the ball in S lunits: (c) Calculate the linear velocity (v) of the ball in S.I units. (d) Calculate the centripetal force (Fc) on the ball in Newtons (N): Scm (e) Calculate the centrifugal force on the ball in Newtons (N) (0) Are the two forces equal

Answers

Answer:

Hdhjdj

Explanation:

A plane is traveling horizontally at a speed u = 40 m/s at a height h =
100m above ground when it drops a package, as shown in the figure.
How long it takes the dropped package to reach the ground and where?

Answers

Answer:

First get the time in the air from

h = gt2/2 ⇒

t = √(2h/g)

Plug in

h = 100 m

g = 9.8 m/s2

and get t in seconds. Then multiply t by the constant horizontal speed.

x = vt

Plug in

v = 40 m/s

t = ? (result from above)

and get x in meters.

(b)

Vertical speed:

v(t) = v0 + gt

Plug in

v0 = 0

g and t from above

and get v(t) in m/s.

(c) It is the same as the initial velocity when released, which is 40 m/s.

(d) The horizontal component is the same as the answer for part (c). The vertical component is the result for part (b), in the downward direction.

An election accelerated through 1 kV possesses de - Broglie wavelength 1. What will be the wavelength of
the same electron, when accelerated through 16kV:
1) 161
2) 41
3) 1/4
4) 116

Answers

Answer:

Correct option is

B

1.7

A

˚

λ=

p

h

=

2mE

h

=

2mqV

h

λ=

2×9.1×10

−31

×1.6×10

−19

×50

6.6×10

−34

=1.72×10

−10

=1.72A

Option B

what would you want individuals and communities to understand to help them avoid negatively affecting climate

Answers

Answer:

ur

Explanation:

mom

HELP PLEASE

......................................................

Answers

The answer is:
8.95 m/s

If you ran at a rate of 300 m/min for 30 minutes, how far would you have run?

Answers

Answer:

9000 m

Explanation:

I multiplied 300 by 30!

Hope this helps :)  

Pls make brainliest :3  

And have an amazing day <3

The three diagrams below show a block of mass m being pulled or pushed at constant acceleration ax along a table with a force P. The coefficient of kinetic friction is k. What is the friction force in each case? Give your answer in terms of the pushing force P, ax, m, and the angle .

Answers

Answer:

Explanation:

1) F = ma

P - Fk = ma

Fk = P - ma

2) F = ma

Pcosθ - Fk = ma

Fk =  Pcosθ - ma

3) F = ma

Pcosθ - Fk = ma

Fk = Pcosθ - ma

These results are not very helpful.

If we are allowed to introduce gravity, more useful information comes out

1) Fk = kmg

2) Fk = k(mg + Fsinθ)

3) Fk = k(mg - Fsinθ)

In this exercise we have to use the decomposition of forces in the blocks, so

1) [tex]F_k = P - ma[/tex]

2) [tex]F_k = Pcos\theta - ma[/tex]

3) [tex]F_k = Pcos\theta - ma[/tex]

Thus, observing these blocks and their respective compositions we will find that:

1)

[tex]F = maP - F_k = maF_k = P - ma[/tex]

2)

[tex]F = maPcos\theta - F_k = maF_k = Pcos\theta - ma[/tex]

3)

[tex]F = maPcos\theta - F_k = maF_k = Pcos\theta - ma[/tex]

See more about forces at brainly.com/question/19734564

Mr. Mangan runs 30 m north and 45 m south. What is his total distance
travelled? What is his displacement?

Answers

Total distance is 65m

What’s the atomic number for magnesium

Answers

Answer:

12

Explanation:

Symbol: Mg

Atomic mass: 24.305 u

Atomic number: 12

Density: 1.738 g/cm³

Suppose an empty grocery cart starts at a rest and rolls downhill in a parking lot. The cart has a maximum speed of 2.2km/s when it hits the side of the store and comes to rest 1.5 min later. If an unbalanced force of 65 N stops the cart, what is the mass of the grocery cart?

Answers

Answer: i dont know

Explanation:

E

A speedboat with a mass of 511 kg (including the driver) is tethered to a fixed buoy by a strong 31.5 m cable. The boat's owner loves high speed, but does not really want to go anywhere. So the owner revs up the boat's engine, makes a lot of noise, and runs the boat in circles around the buoy with the cable supplying all the necessary centripetal force. When the tension of the cable is steady at 13300 N, with what force is the boat's engine pushing the boat? Different physics textbooks treat drag force somewhat differently and use different formulas. For the present purpose, take the water's drag force on the boat to be (450 kg/m)×2, where denotes the boat's speed. Ignore any drag force on the cable.

Answers

Answer:

its is 23.09 kb

Explanation:

i did this awsner

Random sampling is used by researchers to obtain an).

control group

population of interest

representative sample

experimental sample

Plz help

Answers

Answer:

hey there

the correct answer is option ( B ) population of interest

Explanation

A random sample is a subset of individuals randomly selected by researchers to represent an entire group as a whole. The goal is to get a sample of people that is representative of the larger population.

Explanation:

Hope it helps

Have a nice day : )

An airplane flying upward at 39.6m/s and an angle of 30 degree relative to the horizontal releases a ball when it is 287m above the ground. Calculate the time it takes the ball to hit the ground? Calculate the maximum height of the ball? Calculate the horizontal distance the ball travels from the release point to the ground? Neglect any effects due to air resistance.

Answers

Answer:

Assuming the speed of the plane is 39.6 m/s

vy = 39.6 * sin 30 = 19.8 vertical speed

vx = 39.6 * cos 30 = 34.3 m/s

S = vy t - 1/2 a t^2    to calclulate vertical height

-287 = 19.8 t - 4.9 t^2

4.9 t^2 -19.8 t - 287 = 0

I get t = 9.93 for solving the quadratic for time for ball to hit ground

Horizontal distance = 34.3 m/s * 9.93 s = 341 m

With a vertical speed of 19.9 m/s it takes 19.8 / 9.8 = 2.02 s to reach max height

You can again solve a quadratic or use 19.8 / 2 * 2.02 for time to reach vertical height         H = 287 + 20 = 307 m

As a check 307 = 1/2 g t^2 = 4.9 * (9/93 - 2/02)^2 = 307 m  max height

After you know how long the ball is in the air there are several ways to calculate the other values.

A 0.15-kg object is projected vertically into the air with a
velocity of 30. m/s. How high above the ground is the
object after 3.3 seconds?
A 46 m
B 53 m
C 110 m
D 150 m

Answers

Answer:

A

Explanation:

y = 30(3.3) - .5(9.8)(3.3^2)

Which term best describes a question that can be tested?
A. Phenomenon
B. Hypothesis
C. Experiment
D. Observation

Answers

Answer:

Hypothesis

Explanation:

because in science a hypothesis is a guess/question that you test. it can be changed many times

Answer:

C) experiment. Is the answer.

hypothesis is the educated guess about what the result of the experiment is before conducting the experiment.

Observation is what you see and record during the experiment.

Two objects, one of mass 17 kg and the other of mass 31 kg approach each other with the lighter one having a speed of 23 m/s. Determine the velocity of the heavier object if the total combined momentum of the objects is zero.​​

Answers

[tex]\bull\sf m_1=17kg[/tex]

[tex]\bull\sf m_2=31kg[/tex]

[tex]\bull\sf v_1=23m/s[/tex]

[tex]\bull\sf v_2=?[/tex]

According to law of conservation of momentum

[tex]\\ \sf\longmapsto \Delta P=P[/tex]

[tex]\\ \sf\longmapsto m_1v_1=m_2v_2[/tex]

[tex]\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}[/tex]

[tex]\\ \sf\longmapsto v_2=\dfrac{17(23)}{31}[/tex]

[tex]\\ \sf\longmapsto v_2=\dfrac{391}{31}[/tex]

[tex]\\ \sf\longmapsto v_2=12.6m/s[/tex]

Calculate the potential energy of a 1.5 kg hammer that is located at a height of 2 m

Answers

Answer: 29.43 Joules

Explanation:

PE=mgh

PE=potential energy

M=1.5kg

G=9.81m/s^2

H=2m

PE=29.43J

Answer:

[tex]\boxed {\boxed {\sf 29.4 \ J}}[/tex]

Explanation:

Potential energy is the energy an object possesses due to its position. It is calculated using the following formula:

[tex]PE=mgh[/tex]

The mass of the hammer is 1.5 kilograms and its height is 2 meters. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per second squared.

m= 1.5 kg g= 9.8 m/s² h= 2 m

Substitute these values into the formula.

[tex]PE= (1.5 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]

Multiply the numbers together.

[tex]PE=(14.7 \ kg *m/s^2)(2 \ m)[/tex]

[tex]PE=29.4 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 29.4 kg*m²/s² is equal to 29.4 J.

[tex]PE= 29.4 \ J[/tex]

The potential energy of the hammer is 29.4 Joules.

what is the main features of RCCB?​

Answers

Main features of RCCB are:

Both wires phase and neutral are connected through RCCB.Whenever there is any ground fault occurs, then it trips the circuit.The number of current supplies through the line should go back through neutral.These are a very effective type of shock protection.

The potential energy U as a function of the position x of an object is given by U (x) = - 400/x, where U is in joules and x is in meters. The object is released from rest at position x = 30 m and is free to move along the x-axis. When the object has moved a distance of 10 m from its initial position, the magnitude of the force associated with this potential energy function is

Answers

Hi there!

We know that:

F = -dU/dx, so:

U = -400/x

dU/dx = 400/x² (Take the derivative)

F = -dU/dx = -400/x²

Finding the force at 10m away from the starting point (30m), means a position of 40m. So:

F = -400/(40²) = -0.25 N

If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads).
(a)
Calculate the ideal speed in (m/s) to take a 120 m radius curve banked at 15°.
(b)
What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 15.0 km/h?

Answers

Hi there!

(A)

For a banked curve, we know that:

∑F = MgsinФ (force due to gravity)

And:

∑F = mv²/r

The cosine of the centripetal force, mv²/r, is involved in the summation of forces, so:

(mv²/r)cosФ = mgsinФ

Simplify the equation:

(v²/r)cosФ = gsinФ

Divide both sides by cosФ:

(v²/r) = gtanФ

Solve for v:

v = √grtanФ

Plug in given values. g ≈ 9.8 m/s²

v = √(9.8 · 120 · tan(15)) = 17.75 m/s

(b)

Incorporating friction, we now can rewrite the sum of forces. Let's first determine the frictional force acting on the car.

As the horizontal component of the centripetal force is the net force, the vertical component works in the direction of the normal force, so we must include it in the calculation of the frictional force.

First, convert 15 km/h to m/s:

15km / h * 1000 m / 1km * 1 h / 3600 sec = 4.167 m/s

Thus:

∑F = mgsinФ - μ(mgcosФ + (mv²/r)sinФ)

mv²/r = mgsinФ - μ(mgcosФ + (mv²/r)sinФ)

Divide all terms by the mass:

v²/r = gsinФ - μ(gcosФ + (v²/r)sinФ)

Solve for μ:

v²/r - gsinФ = - μ(gcosФ + (v²/r)sinФ)

-(v²/r - gsinФ)/(gcosФ + (v²/r)sinФ)  = μ

Plug in the given values:

μ = 0.25

Explain how plate tectonics have changed Earth's surface over time. (This is a short writing and I need help. I will mark whoever answers first as Brainliest plus I will give 50 points.)​

Answers

Answer:

Plate motions cause mountains to rise where plates push together, or converge, and continents to fracture and oceans to form where plates pull apart, or diverge. The continents are embedded in the plates and drift passively with them, which over millions of years results in significant changes in Earth's geography.

Explanation:

hope it helps ☺️✌️

16. If "team A has 3 of its bocce balls closer to the pallino than any of their opponent's balls, who wins the
frame
How many points do they get for that frame?
How many do their opponents get for that frame?

Answers

Answer:

Team A wins the frame with three points. The opposing team gets zero points for the frame.

Explanation:

A soccer ball accelerates as it rolls down a steep hill and then gradually comes to a stop at the bottom. According to Newton's laws which of the following statements could be
true?
Statement 1: While the ball was rolling down the hill the forces acting on it were unbalanced.
Statement 2: The ball was experiencing balanced forces as it rolled down the hill..
Statement 3: Balanced forces acted on the ball once it reached the botto by m of the hill causing it to stop.
O Statement 1 and 2 are both true.
All three statements are true.
Only Statement 1 is true.
Only Statement 3 is true.
0

Answers

Answer:

Statement 1: While the ball was rolling down the hill the forces acting on it were unbalanced.

Explanation:

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