Select the Moon and use the Info view to determine which of the following statements is correct. The Last Quarter Moon.... rises near noon and sets near midnight. rises at about 6am and sets at about 6pm. rises near midnight and sets near midday. rises and sets at the same time as the Sun. Submit Your Answer

Answers

Answer 1

Answer: The correct statement is that the Last Quarter Moon (rises near midnight and sets near midday).

Explanation:

Phases of the moon also called the LUNAR PHASE can be defined as the different shades of illumination on the moon as seen from the earth. The moon is the natural satellite of the earth that illuminates upon reflection of light from the sun. This means it doesn't have power to shine on its own. When carefully observed, there are times it gets dark and beings to glow brighter over a period of time. This occurs because as the moon completes its four weeks lunar cycle round the earth, how much of its face we see illuminated by sunlight depends on the angle the Sun makes with the Moon.

There are 8 main types of the moon phases these includes:

--> New moon: This is when the moon is not visible to the earth because it's between the earth and the sun. It rises at sunrise and sets at sunset.

--> The waxing crescent: At this phase the moon gets brighter and illuminated from the sun that a crescent shape is seen.

--> First quarter: this occurs one week after the new moon. The moon rises at noon and sets at midnight.

--> The waxing gibbous: This occurs after the first quarter phase where more than half of the lit part of the moon is seen.

--> Full moon: This occurs when the moon and the sun are opposite each other. That is way it is said to rise at sunset and sets at sun rise.

--> The waning gibbous: this occurs when more than half of the lit part of the moon gradually becomes darker

--> Third quarter ( Last Quarter): The moon rises at midnight and sets at noon. This occurs a week after the full moon.

--> The waning crescent: This occurs after the last quarter phase where a very thin fading crescent shaped moon is seen, just before the Moon is invisible again at the start of the cycle, the new moon.


Related Questions

In an Ohmic conductor when voltage is increased what happens to
current?

Answers

Answer: If you increase the voltage across a component, there will be more current in the component .

You are moving a wagon with a friend's help you push on the left side of the wagon with 25 of force while your friend pulls from the right side of the wagon with a force of 15N,
What is the net force?

Answers

Answer:

10N to the left side towards you

Explanation:

The net force is the resultant force that acts on a body.

Force is a push or pull on a body.    

 Push to left side  = 25N

 Pull to the right  = 15N

Net force  = Push to left side   -  Pull to the right  = 25N  - 15N

 Net force  = 10N to the left side towards you

The net force is therefore 10N to the left side towards you

A chocolate chip cookie is an example of a (2 points) a homogeneous mixture b heterogeneous mixture c suspension d colloid

Answers

Answer:

I think it is heterogeneous mixture. have a good day

Answer:

heterogeneous mixture

Explanation:

i took the test

if you watch football let me know who you think is going to win super bowl 55 and what do you think the score going to be Kansas city chiefs or tampa bay buccaneers

Answers

Answer:

I think the bucs are gonna win because Tom Brady is on their team and it's rigged

but maybe I'm just thinking negatively lol

I don’t know much rlly but what this person said

It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of 390 m the field has magnitude 60.0 N/C. At an altitude of 240 m, the magnitude is 100 N/C. Find the net amount of charge contained in a cube 150 m on edge, with horizontal faces at altitudes of 240 and 390 m. Neglect the curvature of Earth.

Answers

Answer:

[tex]q=7.965*10^-^6C[/tex]

Explanation:

From the question we are told that

Altitude of  [tex]d_1 390m[/tex]

Magnitude[tex]M_1=60.0 N/C[/tex]

Altitude of [tex]d_2=240 m[/tex]

Magnitude is [tex]M_2= 100 N/C[/tex]

Distance of cube [tex]d_c=150 m[/tex]

Generally the flux [tex]\phi[/tex] is mathematical given as

 [tex]\phi=60(150)^2cos180+100(150)^2*cos0[/tex]

 [tex]\phi=-9*10^5[/tex]

Generally Quantity of charge  q is mathematically given as

 [tex]q=\varepsilon _0 *\phi[/tex]

 [tex]q=8.85*10^-^1^2 *9*10^5[/tex]

 [tex]q=7.965*10^-^6C[/tex]

Which of the following has kinetic energy? (1 point)

Answers

Ans:

C

Explanation:

because it is moving down the stairs

A spring travelling down a flight of stairs has kinetic energy.

What is Kinetic energy?

Since it is moving, it would be a spring moving down a set of steps. A stretched spring, a compressed spring, and a spring at the top of a set of steps are all in motion.

Kinetic energy is a type of power that a moving object or particle possesses.

An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion.

Therefore, A spring travelling down a flight of stairs has kinetic energy.

To learn more about Kinetic energy, refer to the link:

https://brainly.com/question/26472013

#SPJ5

1. What average force is exerted on a 25 g egg by a bed sheet if the egg hits the sheet at 4 m/s and takes

0.2 s to stop?

Answers

Answer:

F = -0.5 N

Explanation:

Given that,

Mass of an egg, m = 25 g = 0.025 kg

Initial speed, u = 4 m/s

Final speed, v = 0 (it stops)

Time, t = 0.2 s

We need to find the average force exerted on the egg. The force is given by :

F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.025\times (0-4)}{0.2}\\\\F=-0.5\ N[/tex]

So, the average force exerted on the egg is (-0.5 N).

Which of the following do not involve a direction?
Check all that apply.
A. Velocity
B. Distance
C. Time
D. Acceleration

Answers

Distance and time I think

25 points!


A 6 kg object accelerates from 5 m•s to 25 m•s in 30 seconds. What was the net force acting on the
object? Give your answer in Newtons to one significant figure and without a unit.

(Show Work)

Answers

Answer:

6N

Explanation:

Given parameters:

Mass of object  = 6kg

Initial velocity  = 5m/s

Final velocity  = 25m/s

Time  = 30s

Unknown:

Net force acting on the object  = ?

Solution:

From Newton's second law of motion:

   Force  = mass x acceleration

Acceleration is the rate of change of velocity with time

  Acceleration  = [tex]\frac{Final velocity - Initial velocity }{time}[/tex]  

  Force  = mass x  [tex]\frac{Final velocity - Initial velocity }{time}[/tex]  

So;

 Force  = 6 x [tex]\frac{25 - 5}{30}[/tex]    = 6N

The pressure at the bottom of a cylindrical container with a cross-sectional area of 45.5 cm2 and holding a fluid of density 420 kg/m3 is 115 kPa. (a) Determine the depth of the fluid. How is the pressure on the bottom of the container related to atmospheric pressure and the pressure due to the depth of the fluid

Answers

Answer:

3.33 m

Explanation:

Pressure is the distributed force applied to the surface of an object per unit area. The force is applied perpendicular to the surface of the object. The SI unit of pressure is N/m² or Pa.

Hydrostatic pressure is the pressure that a fluid exerts at a point due to the force of gravity.

The relationship between  pressure on the bottom of the container,  atmospheric pressure and the pressure due to the depth of the fluid is given by:

[tex]P_{bottom}-P_{atm}=P_{depth}\\\\where\ P_{bottom}=pressure\ at\ the \ fluid\ bottom,\ P_{atm}=atmospheric\ pressure\\P_{depth}=pressure\ due\ to\ fluid\ depth=\rho gh. \ Hence:\\\\P_{bottom}-P_{atm}=\rho gh\\\\Given \ that\ P_{bottom}=115\ kPa=115*10^3\ Pa, let\ us\ assume\ P_{atm}=101\ kPa=101*10^3\ Pa,\rho=420\ kg/m^3,g=acceleration\ due\ to \ gravity=10\ m/s^2.\\\\Therefore:\\\\115*10^3-101*10^3=420*10*h\\\\14*10^3=4200h\\\\h=3.33\ m\\\\[/tex]

I need help with questions b and d, that’s all.

Thank you.

Answers

b).  The power depends on the RATE at which work is done.  

Power = (Work or Energy) / (time)

So to calculate it, you have to know how much work is done AND how much time that takes.

In part (a), you calculated the amount of work it takes to lift the car from the ground to Point-A.  But the question doesn't tell us anywhere how much time that takes.  So there's NO WAY to calculate the power needed to do it.

The more power is used, the faster the car is lifted.  The less power is used, the slower the car creeps up the first hill.  If the people in the car have a lot of time to sit and wait, the car can be dragged from the ground up to Point-A with a very very very small power ... you could do it with a hamster on a treadmill.  That would just take a long time, but it could be done if the power is small enough.

Without knowing the time, we can't calculate the power.

...

d).  Kinetic energy = (1/2) · (mass) · (speed squared)

On the way up, the car stops when it reaches point-A.  

On the way down, the car leaves point-A from "rest".

WHILE it's at point-A, it has no speed.  So it has no (zero) kinetic energy.

A student is measuring the mass of 20 paper clips using an electronic balance that measures to the thousandths of a gram. The balance displays the value for the mass of the paper clips: 20.120 g. Which of the values would be acceptable ways to record this mass in a lab notebook

Answers

The question is incomplete, the complete question is;

A student is measuring the mass of 20 paper clips using an electric balance that measures to the thousandths of a gram. The balance displays the following values for the mass of the paper clip: 20.120 g.

Which of the following choices would be acceptable ways to record this mass on a lab report? Select all that apply.

a) 20g

b) 20.1 g

c) 20.12 g

d) 20.120g

e) 20.1200g

Answer:

d) 20.120g

Explanation:

We have been told in the question that the electronic balance measures the mass of the paper clips to thousandths of a gram.

This implies that the value of mass is measured to the third decimal place.

If we look at the options, 20.120 g is the measurement of the mass to thousandths of a gram hence that is the correct answer to the question.

A hazard sign has 3 identical

parallelogram-shaped stripes as shown.

Charles must outline each stripe with

reflective tape. Is one roll of 144 inches

of tape enough to finish the job?

Answers

Answer and Explanation: To know how much tape he will need, we have to calculate the perimeter of each parallelogram-shaped stripe.

Perimeter is the sum of all the sides of a figure.

For a parallelogram:

P = 2*length + 2*width

So, we need to determine width and length of the stripe.

Width is 3 inches. Length is the hypotenuse of the right triangle, whose sides are 6 and 18 inches. Then, length is

[tex]h=\sqrt{18^{2}+6^{2}}[/tex]

[tex]h=\sqrt{360}[/tex]

h = 19 in

Perimeter of the first stripe is

P = (2*19) + (2*3)

P = 44 inches

The hazard sign has 3 stripes. So total perimeter is

[tex]P_{t}=[/tex] 44 + 44 + 44

[tex]P_{t}=[/tex] 132 inches

To outline the parallelogram-shaped stripes, Charles need a total of 132 inches of tape. Since one roll has 144 inches, he will have enough tape to finish the job.

A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave perspective, the antenna is a circular aperture through which the microwaves diffract. What is the diameter of the radar beam at a distance of 30 km

Answers

Answer:

915m

Hope this helps.

F=9 N, a=3 m/s², m=?

Answers

Answer:

3kg

Explanation:

Given parameters:

Force  = 9N

Acceleration  = 3m/s²

Unknown:

Mass = ?

Solution:

From Newton's second law of motion:

        Force  = mass x acceleration

So;

             9  = mass x 3

             mass  = 3kg

what is the weight in Newtons of a ball with a mass of 7.77 kg?

Answers

Answer:

76.1N

Explanation:

Given parameters:

Mass of the ball  = 7.77kg

Unknow:

Weight of balloon  = ?

Solution:

Weight is the vertical force applied on a body.

  Weight = mass x acceleration due gravity

So;

  Weight  = mass x acceleration due to gravity

So;

 Weight  = 7.77 x 9.8  = 76.1N

which type of electromagnetic radiation is most likely to cause skin cancer as a result of sun exposure over time?​

Answers

Answer:

Ultraviolet radiation

Explanation:

The type of electromagnetic radiation most likely to cause skin cancer as a result of sun exposure overtime is the ultraviolet radiation.

Electromagnetic radiation occurs with a broad spectrum starting from gamma rays to the radio waves.

From one end to the other, their energy decreases as the wavelength increases.

Within this broad spectrum, the ultraviolet rays which are before the visible rays are very energetic and can cause skin cancer.

Answer:

ultraviolet i think sorry if im wrong :/

Explanation:

What do you think about the attached scenario?

Answers

It’s blank I can’t even see it, 10/10

The bowling ball has starts out at rest (0= speed m/s) at the top of the building (height 40 m). How much potential energy does the ball have?

How much Kinetic energy does the bowling ball have?

How much total energy (Potential energy & Kinetic) does the bowling ball have?

Of the bowling ball's total energy, is more in the form of potential or kinetic energy?

Answers

Answer:

it has 40 potential/ 20 kinetic energy/ do the math

Explanation:

energy

Which of the following is an action-at-a-distance force? friction tension gravity air resistance

Answers

Answer:

Action-at-a-Distance Forces. Frictional Force. Gravitational Force. Tension Force ... The force of gravity on earth is always equal to the weight of the object as ... The friction force is the force exerted by a surface as an object moves across it or ... The force of air resistance is often observed to oppose the motion of an object

Explanation:

Answer:

I believe the answer is gravity.

Explanation:

Because with friction you need to be rubbing multiple object together, in tension two objects must be pulling against each other, and in air resistance the air must be touching the object either pushing or pulling it. While in gravity the mass of an object is pulling another object toward it, the objects don't have to be touching each other making it an at-a-distance force.

3. A 200-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. a. Determine the change in momentum of the ball.. b. If the ball is in contact with the floor for 0.02 ms (milliseconds), what is the average force applied to the ball

Answers

Answer:

Explanation:

A 200-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. a. Determine the change in momentum of the ball.. b. If the ball is in contact with the floor for 0.02 ms (milliseconds), what is the average force applied to the ball

Given data

mass= 200g= 0.2kg

initial velocity= 2.5m/s

final velocity= 2m/s

time= 0.02ms

time= 0.00002 seconds

ΔP= mΔv

ΔP= 0.2*2.5-2

ΔP= 0.2*0.5

ΔP=0.1kgm/s

F= mv/t

F=0.1/0.00002

F=5000N

A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at rest. (a) Find the velocity of each object after the collision. -6.67 Correct: Your answer is correct. cm/s (5.00 g object) 13.33 Correct: Your answer is correct. cm/s (10.0 g object) (b) Find the fraction of the initial kinetic energy transferred to the 10.0 g object. 88.44 Correct: Your answer is correct. %

Answers

Answer:

a) [tex]v_{1f}=-6.67\: cm/s[/tex]

[tex]v_{2f}=13.33\: cm/s[/tex]

b) [tex]n=88.84\: \%[/tex]  

Explanation:

a) Applying the conservation of momentum, we have:

[tex]p_{i}=p_{f}[/tex]

p(i) is the initial momentum. In our case is due to the 5 g object.

p(f) is the final momentum. Here, both objects contribute.

[tex]m_{1i}v_{1i}=m_{1f}v_{1f}+m_{2f}v_{2f}[/tex]  

Where:

m(1) is 5 gm(1) is 10 gv(1i) is the initial velocity 20 cm/s or 0.2 m/s

To find both final velocities we will need another equation, let's use the conservation of kinetic energy.

[tex]m_{1i}v_{1i}^{2}=m_{1f}v_{1f}^{2}+m_{2f}v_{2f}^{2}[/tex]  

So we have a system of equations:

[tex]5*0.2=5v_{1f}+10v_{2f}[/tex]  (1)

[tex]5*0.2^{2}=5v_{1f}^{2}+10v_{2f}^{2}[/tex] (2)

Solving this system we get:            

[tex]v_{1f}=-6.67\: cm/s[/tex]

[tex]v_{2f}=13.33\: cm/s[/tex]

b) The  fraction of the initial kinetic energy transferred is:

[tex]n=\frac{m_{2}v_{2f}^{2}}{m_{1}v_{1i}^{2}}[/tex]

[tex]n=\frac{10*13.33^{2}}{5*20^{2}}[/tex]

[tex]n=88.84\: \%[/tex]

I hope it helps you!                                        

A particle has a velocity that is 90.% of the speed of light. If the wavelength of the particle is 1.5 x 10^-15 m, calculate the mass of the particle

Answers

Answer:

[tex]m=1.63\times 10^{-27}\ kg[/tex]

Explanation:

The velocity of a particle is 90% of the speed of light.

The wavelength of the particle is [tex]1.5\times 10^{-15}\ m[/tex]

We need to find the mass of the particle.

The formula for the wavelength of a particle is given by :

[tex]\lambda=\dfrac{h}{mv}[/tex]

h is Planck's constant

v is 90% of speed of light

m is mass of the particle

[tex]m=\dfrac{h}{\lambda v}\\\\m=\dfrac{6.63\times 10^{-34}}{1.5\times 10^{-15}\times 0.9\times 3\times 10^8}\\\\m=1.63\times 10^{-27}\ kg[/tex]

So, the mass of the particle is [tex]1.63\times 10^{-27}\ kg[/tex].

calculate ine gravitational potential energy of the ball using pe=m×g×h.(use g=9.8 n/kg)


A 4.0-kilogram ball held 1.5 meters above the floor has ________ joules of potential energy​

Answers

Answer:

58.8J

Explanation:

Given parameters;

Mass of ball  = 4kg

Height above the floor  = 1.5m

g  = 9.8n/kg

Unknown:

Potential energy  = ?

Solution:

The potential energy of a body is the energy due to the position of the body.

It is mathematically expressed as:

  Potential energy = mass x acceleration due to gravity x height

  Potential energy  = 4 x 9.8 x 1.5  = 58.8J

Required
Momentum
The magnitude of the momentum of an object is 64 kg*m/s. If the velocity of the
object is doubled, what will be the magnitude of the momentum of the object? *
32 kg*m/s
64 kg*m/s
128 kg*m/s
256 kg*m/s

Answers

Answer:

C) 128 kg*m/s

Explanation:

When you double something you multiply it by 2 most of the time. 64*2=128 or you can add it 64+64=128. Hope this helps.

The process of braking or accelerating an automobile in heavy traffic is highly complex, requiring the skillful use of both feedback and feedforward mechanisms to drive safely. Consider a controlled variable as the distance between you and the car in front of you, with some specified distance as a set point. Name one feedback and one feedforward control mechanisms would keep you at that distance, and prevent you from colliding with the car in front of you

Answers

Answer:

A feedback mechanism is the constant measurement of the distance between the two vehicles and with this the calculation of the speed between them

An anticipated control mechanism is using the vehicle's acceleration and its deceleration to calculate the future speed and their distances,

Explanation:

For this exercise, the feedback and control mechanisms must be directly related to the kinematic relationships,

It is assumed that the vehicle speed (taken from the speedometer) and the braking capacity (given by the brake manufacturer) are known in the form of negative acceleration,

A feedback mechanism is the constant measurement of the distance between the two vehicles and with this the calculation of the speed between them, for which we know the acceleration that exists. This would be a correct mechanism, in general we can adjust to an error between the sedated distance and the real one, so when they have very different give a maximum acceleration and in decreasing it as the differences between the distances decrease.

An anticipated control mechanism is using the vehicle's acceleration and its deceleration to calculate the future speed and their distances, so we would know the amount of acceleration necessary to reach the optimal distance between the two vehicles.

A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 3.1 ss for the boat to travel from its highest point to its lowest, a total distance of 0.55 mm. The fisherman sees that the wave crests are spaced 4.2 mm apart.
A. How fast are the waves traveling?
B. What is the amplitude of each wave?
C. If the total vertical distance traveled by the boat were 0.500, but the other data remained the same, how fast are the waves traveling?
D. If the total vertical distance traveled by the boat were 0.500, but the other data remained the same, what is the amplitude of each wave?

Answers

Answer:

Explanation:

It takes 3.1 s for the boat to travel from its highest point to its lowest, so the period of oscillation

T = 2 x 3.1 = 6.2 s

frequency of wave n = 1 / T = .1613 per sec

Amplitude of oscillation = .55/2 = .275 mm

The fisherman sees that the wave crests are spaced 4.2 mm apart. so wavelength of wave λ = 4.2 mm .

A ) velocity of wave v = n λ

.1613 x 4.2 = .677 mm /s

B ) Amplitude of wave = .275 mm

C ) The vertical distance determines only the amplitude which does not affect the velocity , so velocity will remain unchanged .

D ) Amplitude of wave depends only on the vertical displacement .

The amplitude will become .5 / 2 = .25 mm .

Water flows through a first pipe of diameter 3 inches. If it is desired to use another pipe for the same flow rate such that the velocity head in the second pipe is twice the velocity head in the first pipe, determine the diameter of the second pipe.

Answers

Answer:

the diameter of the second pipe is 2.52 in

Explanation:  

Given the data in the question;

We know that; the rate of flow is the same;

so

Av1 = Av2

v ∝ √h

[tex]\frac{A1}{A2}[/tex] = [tex]\frac{V2}{V1}[/tex]

[tex]\frac{A1}{A2}[/tex]  = √(  [tex]\frac{h2}{h1}[/tex] )

( π/4.D1² / π/4.D2² ) = √(  [tex]\frac{h2}{h1}[/tex] )

( D1² / D2² ) =  √(  [tex]\frac{2h1}{h1}[/tex] ) since second is double of first

so

( D1² / D2² ) =  √(  [tex]\frac{2}{1}[/tex] )  

3² / D2² =  √2

D2²√2  = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer distance

Please show working

Answers

Distance = (speed) x (time)

Car A: Distance = (8 m/s) x (43 s)  =  344 meters

Car B: Distance = (7 m/s) x (50 s)  =  350 meters

350 meters is a longer distance than 344 meters.

Car-B traveled a longer distance than Car-A did.

Answer:

[tex]\boxed {\boxed {\sf Car \ B : 350 \ meters }}[/tex]

Explanation:

Distance is equal to the product of speed and time.

[tex]d=s*t[/tex]

1. Car A

Car A has a speed of 8 meters per second and travels for 43 seconds.

[tex]s= 8 \ m/s \\t= 43 \ s[/tex]

Substitute the values into the formula.

[tex]d= 8 \ m/s *43 \ s[/tex]

Multiply and note that the seconds will cancel out.

[tex]d= 8 \ m*43= 344 \ m[/tex]

2. Car B

Car B has a speed of 7 meters per second and travels for 50 seconds.

[tex]s= 7 \ m/s \\t= 50 \ s[/tex]

Substitute the values in and multiply.

[tex]d= 7 \ m/s * 50 \ s[/tex]

[tex]d= 7 \ m * 50 = 350 \ m[/tex]

350 meters is a longer distance than 344 meters, so Car B traveled the longer distance.

why do players choose to follow the unconventional route of kicking down the middle

Answers

Answer:

My biggest reason is to make it a habit. Even if the ball goes into the endzone it is a live ball and the offensive players must down the ball. Don't leave any room for "I thought he downed it" or "I thought I heard the whistle" just run to the ball always.

If the players slow down and the returner takes it out of the end zone it could be a big return. Players are on a full sprint for 40+ yards sometimes and instead of breaking down, they choose to contine through the goal line to slow down at a decreased rate (possibly limiting a muscle pull injury).

Other Questions
You deposit $2200 in a bank account. Find the balance after 4 years if the account pays 2% annual interest compounded daily What's this thing???? Sara had $108 to spend on 8 books. After buying them she had $12 left. Let b represent the cost of each book. Which equation represents this situation? Please help! Its so confusing A rocket travels 4500 meters in 150 seconds. What is its average speed? Current assets for two different companies at fiscal year-end are listed here. One is a manufacturer, Rayzer Skis Mfg., and the other, Sunrise Foods, is a grocery distribution company. Account Company 1 Company 2 Cash $ 13,000 $ 11,000 Raw materials inventory 46,750 Merchandise inventory 49,750 Work in process inventory 34,000 Finished goods inventory 54,000 Accounts receivable, net 58,000 72,000 Prepaid expenses 2,500 500 Required: 1. Identify which set of numbers relates to the manufacturer and which to the merchandiser. 2a. & 2b. Prepare the current asset section for each company from this information. Which of the following is NOT something a Greaser would wear?From the outsiders! ASAPA) Long hairB) Short hairC) Leather jacketsD) Shirts out Danielle is solving math fast facts at a proportional rate. She completes 35 fast facts in 5 minutes. Read each statement below and decide whether it is true or false. Select all that are true. Show your work in the sketch feature. A. The constant of proportionality is 17 and it represents that in 17of a minute she can complete 1 fast factB. The constant of proportionality is 7 and it represents that she can complete 7 fast facts in 1 minuteC. If she completed 63 fast facts, she was doing math for 9 minutesD. If she was doing math for 14 minutes, she completed 2 fast facts During the Lincoln County War, President Hayes declared a state of __________ in New Mexico, saying that most of the states government officials were corrupt and the state seemed to be lawless. ABCD is a parallelogram. If mZCDA = 63, then mZABC = _?_ The diagram is not to scale. The sum of the squares of two numbers is 26. The difference of the twonumbers is 4. Find the two numbers. The prophetic leaders attempt to gather support to overthrow various imperial powers in the hope of restarting a holy or perfect society ? The measure of an angle is 17.3. What is the measure of its complementary angle? Which of the following elements is used by your body? A) aluminum B) helium C) calcium D) all of the above NEED HELP ASAP Make a table that relates the length and width of a rectangle with a constant area of 100 square feet. Which of the following represents a difference between socialism and communism?A.Socialism requires central control of all productive resources; communism does not.B.Socialism may allow some free market practices; communism does not.C.Socialism emphasizes the equal distribution of wealth; communism does not.D.Socialism depends on authoritarian government; communism does not. If f(x) =4^x-8 and g(x)=5x+6find (f-g)(x) Find X. Round to the nearest tenth please help! -4y + 3x - 2x - 5y - 4Combining like terms Common lit story : Two Famous Friends Which statement best captures the authors purpose in the text?A. The article shows how Jefferson and Adams disagreements negatively impacted both their friendship and America.B. The article encourages readers to resolve whatever problems they might have with a close friend.C. The article illustrates how difficult it is to maintain close relations with people of opposing views.D.The article emphasizes that true friendship can survive extreme disagreements, like the one between Jefferson and Adams.