The option that is shown to be congruent by a sequence of reflections and translations is Option B: Triangle ABC and Triangle MNO
Option C: Triangle JKL and Triangle PQR can be shown to be congruent by a single rotation.How are they congruent?Note that:
If ∆MNO can be gotten from ∆ABC then ∆MNO ≅ ∆ABC
To solve for Reflection (x axis), it will be:
The coordinate note for the reflection is (x, y) will be: (x,-y)
Since ∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).
Then the reflections will be:
M(-9, -4)- M1(-9,4)
N(-3, -4)- N1(-3,4)
O(-3,-15)-O1(-3,15)
To solve for Reflection (y axis), it will be:
The coordinate note for the Reflection is (x,y) will be (-x,y)
Since ∆M1N1O1 = M1(-9, 4), N1(-3, 4), and O1(-3, 15).
Then M1(-9, -4) - M2(9,4)
N1(-3, -4) - N2(3,4)
O1(-3,-15)- O2(3,15)
To solve for Translation
The coordinate note for the Translation is (x,y) will be (x+2,y+2)
Since ∆M2N2O2 = M2(9,4), N2(3,4), and O2(3, 15).
Then M2(9, 4) - M3(11,6)=A
N2(3,4) - N3(5,6)=B
O2(3,15) - O3(5,17)=C
Hence ∆MNO ≅ ∆ABC
To know the congruent by a single rotation.
If ∆JKL can be gotten from ∆PQR
Then ∆JKL ≅ ∆PQR
For Rotation of 90 degree in an anticlockwise position, then:
The coordinate note for the Rotation is (x,y) will be (-y, x)
So, ∆JKL = J(17, -2), K(12, -2), and L(12, 7).
J(17, -2)- J1(2,17)
K(12, -2) - K1(2,12)
L(12,7) - L1(-7,12)
To solve for translation
The coordinate note for the translation is (x,y) will be (x+10,y-14)
Then ∆J1K1L1 = J1(2, 17), K1(2, 12), and L1(-7, 12).
Hence J1(2, 17) - J2(12,3) = P
K1(2, 12)- K2(12,-2) = Q
L1(-7, 12)- L2(3,-2) = R
So, ∆JKL ≅ ∆PQR.
So therefore, The option that is shown to be congruent by a sequence of reflections and translations is Option B: Triangle ABC and Triangle MNO
Option C: Triangle JKL and Triangle PQR can be shown to be congruent by a single rotation.See options below
___ can be shown to be congruent by a sequence of reflections and translations.
1)Pick one to go with the sentence.
a Triangle ABC and Triangle XYZ
b Triangle ABC and Triangle MNO
c Triangle JKL and Triangle ABC
d Triangle PQR and Triangle XYZ
___ can be shown to be congruent by a single rotation.
Pick one to go with the sentence.
a Triangle ABC and Triangle XYZ
b Triangle PQR and Triangle XYZ
c Triangle JKL and Triangle PQR
d Triangle JKL and Triangle XYZ
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What is the value of this subject when a =2 and b= -3?
a^3-b^3/5
Answer:
7
Step-by-step explanation:
a^3 = 2^3 = 8
b^3 = -3^3 = -27
(8 - (-27))/5= (8+27)/5 =35/5=7
How are evidence and counterexamples used in proofs . In a direct proof evidence is used to blank .on the other hand a counterexample is a single example that blank
Evidence is used in proofs to support a claim.
What is an evidence?It should be noted that evidence simply means a claim that's is used to support a proposition that's it's true.
In this case, evidence is used in proofs to support a claim. On the other hand, counterexample is used to disprove a theory.
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Need asap pls correct answer
Answer: B. G(x) = (x-5)^2
Step-by-step explanation:
This will shift the graph 5 units right
Find the length of line segments (4,6) and (5,2)
Answer: [tex]\displaystyle d=\sqrt{1 7}\;\text{or about 4.123 units}[/tex]
Step-by-step explanation:
We can use the distance formula to solve. Let (4, 6) be point one and (5, 2) be point two.
[tex]\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}[/tex]
[tex]\displaystyle d=\sqrt{(5-4)^2 +(2-6)^2}[/tex]
[tex]\displaystyle d=\sqrt{(1)^2 +(-4)^2}[/tex]
[tex]\displaystyle d=\sqrt{1 +16}[/tex]
[tex]\displaystyle d=\sqrt{1 7}[/tex]
30 mi / h = ____ ft / min
a.
2640
c.
880
b.
264
d.
2112
Answer:
A. 2640
Step-by-step explanation:
44 feet per second 30 miles per hour is 2640 feet per minute
A cube shaped suitcase has a length of 3x + 2 units. What is an expression for its area of the
base?
Answer:
[tex]\huge\boxed{\sf 9x^2+12x+4 \ units^2}[/tex]
Step-by-step explanation:
Given that,
Length of cube = l = 3x + 2 units
Base Area:[tex]= l \times l\\\\= (3x+2)(3x+2)\\\\= 3x(3x+2)+2(3x+2)\\\\= 9x^2+6x+6x+4\\\\= 9x^2+12x+4 \ units^2\\\\\rule[225]{225}{2}[/tex]
Which recursive formula can be used to generate the sequence shown, where f(1) = 9.6 and n > 1?
9.6, –4.8, 2.4, –1.2, 0.6, ...
f(n + 1) = (–0.5)f(n)
f(n + 1) = (0.5)f(n)
f(n + 1) = f(0.5n)
f(n + 1) = f(–0.5n)
Answer: f(n + 1) = (–0.5)f(n)
Step-by-step explanation:
This is a geometric series with common ratio -0.5.
Lee is staying at a hotel. The cost of the first night is $240. The cost for each night after that is $210. Let y represent the total cost of staying at the hotel for x nights. Which type of sequence does the situation represent
A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.
F(1) = 240 +210
F(2) = 240 +2(210)
F(3) = 240+3(210)
.
.
.
.
F(x)= 240 +210x.
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Find the length of the hypotenuse on the following right triangle.
Answer:
Step-by-step explanation:
2x - 5y = 2
3x + 2y = -16
Answer:
(-4,-2)
Step-by-step explanation:
Isolate x:
2x - 5y = 2
2x = 5y + 2
x = 5/2y + 1
Substitute and solve for y:
3(5/2y + 1) + 2y = -16
15/2y + 3 + 2y = -16
7.5y + 2y = -16 - 3
9.5y = -19
y = -2
Substitute and solve for x:
2x - 5y = 2
2x - 5(-2) = 2
2x + 10 = 2
2x = -8
x = -4
Miguel plans on retiring in 16 years, and he wants to double his money by that time. He's contacted various banks, looking for a CD that compounds interest monthly, and to calculate what annual interest rate he needs, he is using the rule of 72. (3 points: Part I – 1 point; Part II – 1 point; Part III – 1 point)
Part I: What is the rule of 72? To represent the annual interest rate, use r.
Part II: What equation can Miguel set up to solve for the annual interest rate he needs to double his money by the time he retires?
Part III: What annual interest rate does Miguel need to double his money by the time he retires?
The rule of 72 is a rule of thumb that is used to determine the doubling time for an investment given the annual interest rate.
The equation Miguel needs to set up is r = 72/16.
The interest rate is 4.5%.
What is the rule of 72?
The rule of 72 is used to determine the time it would take an investment to double in value. The doubling time is determined by dividing 72 by the interest rate.
Number of years it would take an investment to double = 72 / interest rate
n = 72 / r
r = 72 / n
72 / 16 = 4.5%
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Betty and Jane have the same number of coins. Betty
sorts her coins in groups of 6, with no coins left over.
Jane sorts her coins in groups of 8, with no coins left
over. What is the least possible number of coins that each
of them has?
Using the least common multiple, it is found that the least possible number of coins that each of them has is of 24.
What is the least possible number of coins that they have?They have the same number of coins, with Betty sorting the coins in groups of 6 and Jane sorting the coins in groups of 8, and none of them having coins remaining.
Thus, the least possible number of coins they have is the least common multiple of 6 and 8, found factoring both these numbers into prime factors, as is done below:
6 - 8|2
3 - 4|2
3 - 2|2
3 - 1|3
1
Hence the least common multiple of 6 and 8 is given by:
lcm(6,8) = 2 x 2 x 2 x 3 = 2³ x 3 = 24.
Thus, it is found that the least possible number of coins that each of them has is of 24.
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-80 +77 show work ...........
Answer:
157
Step-by-step explanation:
-80 is a negative number. 77 is a even number. Since your adding a negative number with a even number. You answer will be even.
-80
+70
———
157
I hope I’ve helped you here’s a link to help you https://www.purplemath.com/modules/negative2.htm
What is the answer to this pythagoras question?
The length of the segment AB will be equal to 9.848 units.
What is the Pythagorean theorem?It states that in the right-angle triangle the hypotenuse square is equal to the sum of the square of the other two sides.
The length of segment AB will be calculated as:-
Points are A(1,7) and B(10,3)
AB = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]
AB = [tex]\sqrt{(10-1)^2+(3-7)^2}[/tex]
AB = √(81+16)
AB = √97
AB = 9.848
Therefore the length of the segment AB will be equal to 9.848 units.
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The values of x and y vary directly and one pair of values are given. Write an equation that relates x and y.
x=2, y=5
The equation that relates x and y is y = 2.5x.
How to solve variation?
The values of x and y vary directly. Therefore,
y α x
where
x and y are the variable.Hence,
y = kx
where
k = constant of proportionality.Therefore,
x = 2
y = 5
5 = 2k
k = 5 / 2
k = 2.5
Hence, the equation that relates x and y are as follows;
y = 2.5x
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(Round answers to
the nearest hundredth.)
Answer:
28.31
Step-by-step explanation:
So in this case you're going to need to use the law of sines which essentially states that: [tex]\frac{a}{sinA}=\frac{b}{sinB}[/tex] which should apply to any of the sides. the lowercase a and b are the opposite sides of the angles A and B. In this example the angle A is given and C is given, but not in the text. Since you have the right angle thing in the diagram, angle C is a right angle (90 degrees).
Given information:
[tex]\angle A = 32\\a=15\\\angle C = 90 \text{(the right angle symbol in the diagram of the triangle)}[/tex]
Law of sines equation:
[tex]\frac{a}{sinA}=\frac{b}{sinB} \text{ can be applied to any two sides }[/tex]
Plug in known information:
[tex]\frac{15}{sin(32)}=\frac{c}{sin (90)}[/tex]
since sin(90) = 1, simplify the fraction
[tex]\frac{15}{sin(32)} = c[/tex]
Calculate sin(32)
[tex]\frac{15}{0.530}\approx c[/tex]
Divide
[tex]28.306\approx c[/tex]
If you haven't learned law of sines yet and don't quite understand why it works you can also use the definition of tan to find what b equals and then use the Pythagorean Theorem to solve for c
tan is defined as: [tex]\frac{opposite}{adjacent}[/tex]
[tex]tan(32)=\frac{15}{b}[/tex]
now multiply both sides by b
[tex]b * tan(32)=15[/tex]
Divide both sides by tan 32
[tex]b = \frac{15}{tan(32)}[/tex]
[tex]b\approx 24.005[/tex]
Now use the Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]
[tex](24.005)^2+15^2=c^2\\[/tex]
Square known values
[tex]576.241+225=c^2[/tex]
Add the values
[tex]801.241 = c^2[/tex]
take the square root of both sides
[tex]28.306\approx c[/tex]
Rounding to the nearest hundredth gives you 28.31
SM052VGS2E
Consider these four powers.
(-4)⁰
3⁰
10⁰
(3) º
4
What do these powers have in common?
The four powers have zero (0) in common
IndicesFrom the question, we are to determine what the four powers have in common
In the question, we can observe that the four powers have 0 in common.
The value of each of the expressions is 1.
Hence, the four powers have zero (0) in common.
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Triangles Q R S and T U V are shown. Triangle Q R S is translated across S Q and then is shifted down and to the right to form triangle T U V.
Can a translation and a reflection map TriangleQRS to TriangleTUV? Explain why or why not.
No, the triangles are not congruent.
Yes, a translation mapping vertex Q to vertex T and a reflection across the line containing QS will map
△QRS to △TUV.
No, the triangles are obtuse.
Yes, a translation mapping vertex S to vertex T and a reflection across the line containing RS will map
△QRS to △TUV.
Yes, a translation mapping vertex Q to vertex T and a reflection across the line containing QS will map △QRS to △TUV.
What is translation?A translation is a type of transformation that takes each point in a figure and slides it the same distance in the same direction.
Given:
△QRS and △TUV is translated across SQ and then is shifted down and to the right to form △TUV.
So, translation mapping vertex Q to vertex T is done and a reflection across the line containing QS will map △QRS to △TUV.
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Answer:
B
Step-by-step explanation:
That's what the other person is saying
Find ST. Help me please. Thank you :)
The value of ST is 3
How to solve for ST?The given parameters are:
RT = 8
RS = 5
To calculate ST, we make use of the following straight line theorem
RT = RS + ST
This gives
8 = 5 + ST
Subtract 5 from both sides
ST = 3
Hence, the value of ST is 3
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jacqueline works on math 7/12 hours everyday . how many hours did she work on math after 24 day
Answer:
14
Step-by-step explanation:
24/12=2
(2)7=14 hours
For the regular hexagon below, if BC = 9 m and AP = 8 m, find it's area.
A number is equal to the sum of half a second number and 3. The first number is also equal to the sum of one-
quarter of the second number and 5. The situation can be represented by using the graph below, where x
represents the second number.
16-
14-
12
10
8
-22-
8 10 12 14 16 x
Which equations represent the situation?
The equation that represents the situation are x = 1/2 y + 3 and x = 1/4y + 5
System of equation
Let the first number be x and the second number be y. If a number is equal to the sum of half a second number and 3, this is expressed as;
x = 1/2 y + 3
For the second equation;
The first number is equal to the sum of one- quarter of the second number and 5
x = 1/4y + 5
Hence the equation that represents the situation are x = 1/2 y + 3 and x = 1/4y + 5
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Jon, Dave, and Kevin collected rocks at the beach. Each boy collected 25 rocks. How many rocks did the boys collect in all?
By taking the product between the number of boys and the number of rocks that each gets, we conclude that they collected 75 rocks.
How many rocks did the boys collect in all?
We know that there are 3 boys, and each boy collected 25 rocks.
If we take the product between the number of boys and the number of rocks that each boy collected, we get:
R = 3*25 rocks = 75 rocks.
We conclude that the boys collected 75 rocks in total.
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What is the least amount of integers you must pick in order to be sure that at least two of them have the same remainder when divided by 15
There are exactly 15 remainders modulo 15 and they are 0,1,2,…,14.
It is given that at least two of them should have the same remainder when divided by 15.
Division algorithm.
Let aa be an integer and d a positive integer. Then there are unique integers q and r with [tex]0\leq r < d[/tex] such that [tex]a=dq+r[/tex]
q is called the quotient and r is called the remainder
q=a div d
r=a mod d
Pigeonhole principle If k is a positive integer and k+1or more objects are placed into k boxes, then there is at least one box containing two or more objects.
Hence, there are exactly 15 remainders modulo 15 and they are 0,1,2,…,14.
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answer pleaseeeeeeeeeeeeeee
Answer:
A. Square
Step-by-step explanation:
Hope this helps!
Please mark brainliest! Thanks!
what is the answer?
please help
Answer:
Slope = 1/3
Step-by-step explanation:
Slope:Pick any two points. (-1,-2) ; (2,-1)[tex]\sf \ x_1=-1 ; \ y_1=-2\\\\ x_2 = 2 ; \ y_2=-1[/tex]
Find the slope using the formula.[tex]\sf \boxed{\bf \ Slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf = \dfrac{-1-[-2]}{2-[-1]}\\\\ =\dfrac{-1+2}{2+1}\\\\= \dfrac{1}{3}[/tex]
help me please i dont understand
20 points
Answer:
50 [tex]cm^{2}[/tex]
Step-by-step explanation:
Area of a trapezoid: [tex]\frac{a+b}{2} h[/tex]
[tex]\frac{a+b}{2} h[/tex]
= [tex]\frac{14+6}{2} (5)[/tex]
= [tex]\frac{20}{2} (5)[/tex]
= [tex]10(5)[/tex]
= 50 sq. cm
Analyze the diagram below.
Which statements regarding the diagram are correct? Check all that apply.
ST ≅ ST by the reflexive property.
∠RWS ≅ ∠UWT because they are vertical angles.
△RWS ≅ △UWT by AAS.
△RST ≅ △UST by SAS.
∠WTU ≅ ∠WSR because CPCTC.
Based on the relevant congruent theorems, all of the statements are correct except: D. △RST ≅ △UST by SAS.
What is the AAS Congruence Theorem?Two triangles that have two pairs of corresponding congruent angles and a pair of corresponding non-included congruence angles are proven to be congruent by the AAS congruence theorem.
Thus, △RWS ≅ △UWT by AAS because they have two pairs of corresponding congruent angles and a pair of corresponding non-included congruence angles.
△RST cannot be proven to be congruent to △UST by SAS because there is no sufficient information.
Based on the reflexive property, ST ≅ ST. Also, using the CPCTC, all parts of the two congruent triangles are equal, therefore, ∠WTU ≅ ∠WSR.
The only statement that is incorrect is: D. △RST ≅ △UST by SAS.
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Answer:
A, B, C and E
Step-by-step explanation:
Which rectangular equation represents the parametric equations x = t²-4 and y = 2t?
Oy = 2(x² + 4)
* y = 2(x² - 4)
Oy = 2√x+4
O y = 2√√x-4
Answer:
[tex]\displaystyle{y=2\sqrt{x+4}}[/tex]
Step-by-step explanation:
We are given parametric equations of:
[tex]\displaystyle{x=t^2-4}[/tex] and [tex]\displaystyle{y=2t}[/tex]
Isolate t-variable in [tex]\displaystyle{x=t^2-4}[/tex] first by adding both sides by 4:
[tex]\displaystyle{x+4=t^2-4+4}\\\\\displaystyle{x+4=t^2}[/tex]
Square root both sides then write plus-minus:
[tex]\displaystyle{\sqrt{x+4}=\sqrt{t^2}}\\\\\displaystyle{t=\pm \sqrt{x+4}}[/tex]
Since the choice determines y-term as a function and only positive t-value exists, substitute only [tex]\displaystyle{t=\sqrt{x+4}}[/tex] in [tex]\displaystyle{y=2t}[/tex].
Therefore, the answer is [tex]\displaystyle{y=2\sqrt{x+4}}[/tex]
Answer:
c
Step-by-step explanation:
can someone help me with this? I’ll mark you brainliest
The point (0, 0) lies in the shaded region and satisfies the solution for the inequality y ≥ 3x - 2
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Given the inequality y ≥ 3x - 2, since the point (0, 0) lies on the shaded region, hence:
0 ≥ 3(0) - 2
0 ≥ -2
The point (0, 0) satisfies the solution for the inequality y ≥ 3x - 2
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