Scott rolled a number cube several times and counted how many times he rolled a 3.

What is the theoretical probability of Scott rolling a 3 if his number cube is fair?

Answer:

4/19

Step-by-step explanation:

Jar a: 3/8

Jar b: 1/11

8+11 = 19

3+1= 4

4/19

Answer:

Hope the picture will help you.....................

The parabola y=x^2 is reflected across the x axis and then scaled vertically by a factor of 1/8 is y = [tex]-\frac{1}{8}[/tex] x².

The general equation of a parabola is: y = a(x-h²2 + k or x = a(y-k)² +h, where (h,k) denotes the vertex.

The standard equation of a regular parabola is y² = 4ax.

The given equation is of parabola : y= x²

Now, we have to reflect across the x- axis and then scaled vertically by a factor 1/8.

When we reflect this parabola in the x-axis and then scaled vertically by a factor of 1/8.

Then, the new equation of parabola be:

  y = [tex]-\frac{1}{8}[/tex] x²

Hence, The parabola y=x² is reflected across the x axis and then scaled vertically by a factor of 1/8 is y = [tex]-\frac{1}{8}[/tex] x².

Learn more about Equation of parabola here:

https://brainly.com/question/4074088

#SPJ1

To solve this problem, we must consider all the trigonometric equations:

 ⇒ (see image below)

Let's examine the diagram:

Thus we can use:

 [tex]cos(A)=\frac{35}{53} \\A= cos^{-1}(\frac{35}{53})\\ A = 48.67[/tex]

Answer: 49 degrees (as rounded)

Hope that helps!

Answer:

  3 1/2 square units

Step-by-step explanation:

For this small triangle whose vertices are on grid points, the use of Pick's theorem will give the area with the least work.

__

Pick's theorem says that the area is ...

  A = i +b/2 -1

where i is the number of grid points inside the boundary, and b is the number of grid points on the boundary.

Here, only the given coordinates are boundary points that are on grid points. (b = 3)

The figure shows us three grid intersections inside the boundary of the triangle. (i = 3)

That means the area is ...

  A = 3 +3/2 -1 = 3 1/2 . . . . square units

_____

Alternate solution

The triangle is bounded by a square 3 units on a side. From that, we can subtract a 2×3 triangle at upper left, a 1×2 triangle at upper right, and a 3×1 triangle at the bottom. That leave a figure area of ...

  A = 3² -1/2(2×3) -1/2(1×2) -1/2(3×1) = 9 -3 -1 -3/2 = 3 1/2 . . . . square units

(The area of a triangle is 1/2bh, where b and h are the base and height of the triangle.)

__

Another alternate solution can be had by using a formula with the vertex coordinates:

  A = 1/2|(x1)(y2 -y3) +(x2)(y3 -y1) +(x3)(y1 -y2)|

  = 1/2|(-8)(3 -5) +(-5)(5 -2) +(-6)(2 -3)| = 1/2|16 -15 +6| = 3 1/2 . . . square units

Answer:

x/3+3=x/8+1/11

x+9/3=11x+8/88

88(x+9)=3(11x+8)

88x+729=33x+24

88x-33x=729-24

55x=705

x=705/55

x=12.80

Answer:

180-108=72   72/2=36 degrees

Step-by-step explanation:

Please ad brainliest

Answer:

[tex]2x - 2y = 24 \\ 2(x - y) = 24 \\ x = 12 + y......eq(1) \\ 4x + 7y = - 40......eq(2) \\ substituting \: the \: value \: of \: x \: in \: eq(2) \\ 4(12 + y) + 7y = - 40 \\ 48 + 4y + 7y = - 40 \\ 11y = - 40 - 48 \\ y = \frac{ - 88}{11} \\ y = - 8 \\ putting \: the \: value \: of \: y \: im \: eq(1) \\ x = 12 - 8 \\ = 4[/tex]

Step-by-step explanation:

3x-2y=24......eqi

x+2y=48........eqii

now solving eq i&ii

4x=72

x=72/4

x=18

now putting the value of x in eqii

18+2y=48

2y=48-18

y=30/2

y=15

Answer:

You infer that mean weight of catfusf in the lake is close to 2.2lbs

Step-by-step explanation:

Because it's a random sample of 50.

By using the second condition, we conclude that there are 23 white roses in the tray.

First, we know that there are a total of 50 roses in the tray, and we have the conditions:

The second statement means that, always that we take 28 roses, at least one of them is white. So, there are 27 roses in the tray that are not white.

Whit that in mind, if the 28th rose must be white, then all the remaining roses in the tray are white, this means that there are:

50 - 27 = 23 white roses.

If you want to learn more about counting.

https://brainly.com/question/11732255

#SPJ1

Step-by-step explanation

Here ...I'm not too sure about the question as you have written

P = 2 ( 1 + 6 ) and ask to solve for L ...

.So I guess the question you have written is wrong .. ...and I guess there should be L in the place of 1.

...So let me correct the question....

P = 2 ( l + 6 )

P = 2l + 12

P - 2l = 12

- 2l = 12 - P

- 2l = - P + 12

Change the sign of both side of the equation...

2l = P + 12

divide both side by the same number...

L = ( P + 12 ) ÷ 2

[tex]l = \frac{1}{2} p - 12 \times \frac{1}{2} \\ [/tex]

Calculate the product of rational numbers...

[tex]l = \frac{1}{2} p - 6 \\ [/tex]

There are 258 ways to color the octagon such that no two adjacent vertices are the same color

The given parameters are:

Since no two adjacent vertices are the same color, we use the following  chromatic polynomial of an octagon equation

Ways = (r - 1)⁸ + (r -1)

Substitute 3 for r

Ways = (3 - 1)⁸ + (3 -1)

Evaluate

Ways = 258

Hence, there are 258 ways to color the octagon

Read more about combination at:

https://brainly.com/question/11732255

#SPJ1

Answer:

................

Step-by-step explanation:

Answer:

38.73 cm

Step-by-step explanation:

Given:

Solution:

S² = (R - r)^2xh^2

(40)^2=(30-20)^2+h^2

1600=(10)^2+h^2

1600-100=h^2

h=√1500

h=10√15

h=38.73 (rounded to the nearest tenth)

Answer:

[tex]2[/tex]

Step-by-step explanation:

[tex] {16}^{ \frac{1}{4} } \: is \: the \: same \: as \\ \\ \sqrt[4]{16} = \sqrt[4]{ {4}^{2} } [/tex]

Note we broke down the 16 into 4 squared*. This is because 4 squared is the same as 16. The four and the two would cancel each other leaving:

[tex] \sqrt[2]{4} \;\\ or \\ \: \sqrt [2]{{2}^{2}} [/tex]

Like before the two and the two would cancel each other out leaving:

[tex]2[/tex]

Answer:

C. 2

Step-by-step explanation:

edge

Answer:

a line segment

Step-by-step explanation:

Answer:

A line segment is part of a line that has two endpoints and is finite in length. A ray is a line segment that extends indefinitely in one direction.

Step-by-step explanation:

hope this helps

Answer:

Min = 1 4/6

Max = 3

Sum = min + max

=> sum = 1 4/6 + 3

=> sum = 4 /4/6

Answer:

4 4/6

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

4 x 9 = 36

36 / 4 = 9

Therefore, 36 is 4 times as much as 9.

[tex]{\sf Hello!}[/tex]

The answer is 36

⇢ 4 × 9 = 36

Answer:

Question 23: 39

Question 24: 10

Question 25: Airline B

Question 26: 20 to 50

Step-by-step explanation:

Answer:

[tex]0 < x < 6[/tex]

Step-by-step explanation:

This question asks to solve an inequality which can be written as:

[tex]\sqrt{x^2-6x+9} < 3[/tex]

Solve for x:

[tex]\sqrt{x^2-6x+9} < 3\\x^2-6x+9 < 9\\x^2-6x < 0\\x(x-6) < 0[/tex]

From here we can deduce that the inequality is [tex]0[/tex] when:

[tex]x = 0[/tex] or [tex]x = 6[/tex]

We can write the solution as:

[tex]0 < x < 6[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 3x - 3x+ 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{}(x - 3) - 3(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3)(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: { (x - 3) {}^{} } [/tex]

Now, we have been given that value of x :

[tex]\qquad \sf  \dashrightarrow \:x < 3[/tex]

So, let's plug the value of x as 3 in the given expression ~

[tex]\qquad \sf  \dashrightarrow \:3 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

Therefore, we can conclude that :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } < 0[/tex]

Value of the expression should be less than 0

Answer:

if this is 4.88/16 then the answer is 0.305.

Answer:

9 / 2 = 4.5

4.5 - 4 = 0.5

Check the picture below.

Answers:

===========================================================

Explanation:

Think of a hexagonal room with n = 6 walls, i.e. the floor is a hexagon with n = 6 sides. The floor and ceiling are parallel to each other, and congruent hexagons. That's 2 faces so far. Then we have another 6 faces to account for the walls. This gives 2+6 = 8 faces of a hexagonal prism.

In more general terms, a prism with a base of n sides will have 2 parallel and congruent base faces, and n walls or lateral faces. This gives n+2 total faces.

------------------------

Let's go back to the hexagonal prism. The floor has 6 sides to it, and so does the ceiling. We have 6+6 = 12 edges so far. Then we have another 6 edges where each of the rectangular walls meet up. That gives 12+6 = 18 edges total of this hexagonal prism room.

For any more general case, each base has n sides. That gives 2n sides so far for just the bases. Then add on another n for the lateral edges and we get 3n total edges.

--------------------------

Once again lets revisit the room with the hexagonal floor and ceiling. The floor has 6 vertices and the ceiling has the same vertex count. Therefore, this prism has 6+6 = 12 vertices.

For the general case, each base has n vertices. There are 2 such identical bases giving 2n vertices total.

---------------------------

One way to check the answer:

We could use Euler's Polyhedron Formula which is

F+V-E = 2

where,

For the hexagonal prism we found

Then notice how

F+V-E = 2

8+12-18 = 2

20-18 = 2

2 = 2

This confirms the formula works for a hexagonal prism.

Now let's check it for the more general case

We found earlier that,

So,

F+V-E = 2

n+2+2n-3n = 2

3n-3n+2 = 2

0n+2 = 2

0+2 = 2

2 = 2

This helps confirm the answer for any prism with the base of n sides.

Answer:

3  1/2

Step-by-step explanation:

So because the fraction in attatched to the whole numbers have the same denominator you can literally just subtract the whole numbers and the fractions. (You do them seperatly) (5-2)=3   (3/4-1/4) = 2/4 or 1/2

You should plot the total distance traveled from the base camp on the x-coordinate while the elevation should be plotted on the y-coordinate.

A graph simply refers to a type of chart which is commonly used to graphically represent data on both the vertical and horizontal lines of a cartesian coordinate (x-coordinate and y-coordinate).

In this scenario, you would plot the total distance traveled from the base camp on the x-coordinate while the elevation of the camps would be plotted on the y-coordinate as shown in the image attached below.

Read more on graphs here: https://brainly.com/question/25799000

#SPJ1

#34.

If one's price be d

#35

So old area=150(100)=15000

New area increase

New area

Option C

#36

Prime numbers inbetween

#37

#38

1hr additional=1.5(2)=3$

Equation is

So

Option A

Answer:

here i have tried 2 question hope it help u

The expression (7+ y) ∙9 is described by its factors and terms as; lt is has two factors and the factor (7+ y) has two terms.

(7 + y) × 9

63 + 9y

The factors are 7 and y and the two terms are 63 + 9y.

Therefore, the correct answer is; lt is has two factors and the factor (7+ y) has two terms.

Learn more about factors:

https://brainly.com/question/723406

#SPJ1

✒️ Equation

••••••••••••••••••••••••••••••••••••••

A. To find the x - intercept, let y = 0.

[tex]\tt \: \: \large \tt \: \begin{array}{|c|} \hline \tt \: 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4x \: - \: 3(0) \: = \: \tt\underline{\blue{ 12 }} \\ \tt4x \: - \: 0 \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ \: x \: = \: 3 }} \\ \\ \tt \: x ↬\: the \: intercept\\ \tt\\ \hline\end{array} \: \\ [/tex]

[tex] \\ [/tex]

To find the y - intercept, let x = 0

[tex]\large \tt \: \begin{array}{|c|} \hline \tt 4x \: - \: 3y \: = \: \tt\underline{\green{ 12 }} \\ \tt 4(0) \: - \: 3y \: = \: \tt\underline{\blue{ 12 }} \\ \tt \: 0 \: - \: 3y \: = \: \tt\underline{\pink{ 12 }} \\ \tt \tt\underline{\red{ y \: = \: - 4 }} \\ \\ \tt \: x ↬\: the \: intercept \\ \ \\ \hline\end{array} \: [/tex]

[tex] \\ [/tex]

B. Replace x with 0 and solve for y. Then replace y with 0 and solve for x.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt y \: - \: intercept: \: y \: = \: \frac{1}{3}(0) \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \tt = \tt\underline{\red{ 0 }} \\ \\ \tt \: x \: and \: y ↬ intercepts: (0,0)\\ \\ \tt \: x \: ↬ \: intercepts: \: 0 = \: \frac{1}{3} x \\ \quad\quad \quad \quad\quad\quad\quad\quad\quad \: \tt \tt\underline{\red{ \: 0 \: = \: x }} \ \\ \\ \hline\end{array} \\ [/tex]

[tex] \\ [/tex]

The equation in b is a linear equation in the form y = mx, where m is any real number. the graph of any equation in the form y = mx is always a line that passes through the origin, which means that both the x - and - y - intercepts are (0,0).

[tex]\large \tt \: \begin{array}{|c|} \hline \tt intercept \: for \: m \: of \: y \: = \: \tt\underline{\red{ mx }} \\ \hline\end{array}[/tex]

[tex] \\ [/tex]

C. Replace y with 0, then solve for the x.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt x ↬ \: intercept : \: 0 \: = \: 2x \: \ + 5 \\ \\ \tt - 5 \: = \: 2x\\ \\ \tt \: \frac{ - 5}{2} \: = \: x\\ \\ \tt \: x \: ↬ \: intercept \ \\ \hline\end{array}[/tex]

Now, replace x with 0, and then solve for y.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt y ↬ \: intercept: \: y \: = \: 2(0) \: + \: 5 \\ \\ \tt \: y \: = \: 0 \: + \: 5 \\ \\ \tt \: y \: = \: 5 \\ \\ \tt y ↬ \: intercept \ \\ \\ \hline\end{array}[/tex]

The equation in 11c is written in the form y = mx + b. note than in the form, when x is replaced by 0 to find the y↬intercept. you are left with the constant b.

[tex]\large \tt \: \begin{array}{|c|} \hline \tt \: the \: y ↬ intercept \: of \: y \: = \: mx \: + \: b \\ \hline\end{array}[/tex]

If the equation is in the form y = mx + b, where m and b are real numbers, then the y ↬intercept is b.

[tex] \\ [/tex]

D. Remember that the graph of y = 6 is horizontally line parallel to the x axis that passes through the y axis at (0,6). since the line is parallel to x axis, it will not incest tha x-axis. Hence, there is no x ↬ intercept.

[tex] \\ \\ \\ [/tex]

[tex]\pmb{(ノ‥)ノ}\qquad\qquad\qquad\qquad\boxed{\tt{[05-12-2022]}} \\ \qquad\qquad\qquad\qquad\qquad\qquad\boxed{\tt{[03:11 \: am]}}[/tex]