Answer:
Refraction
Explanation:
When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.
Two spherical objects have masses of 8.1 x 10^2kg and 4x.5 10^8kg. The gravitational attraction between them is 1.9 x 10^-3 N.
Let's see
We need distance between them?
[tex]\\ \rm\Rrightarrow F=\dfrac{GMm}{r^2}[/tex]
[tex]\\ \rm\Rrightarrow r^2=\dfrac{GMm}{F}[/tex]
[tex]\\ \rm\Rrightarrow r^2=\dfrac{6.673\times 10^{-11}\times 8.1\times 10^2\times 4.5\times 10^8kg}{1.9\times 10^{-3}}[/tex]
[tex]\\ \rm\Rrightarrow r^2=128.02\times 10^{2}[/tex]
[tex]\\ \rm\Rrightarrow r^2=12802[/tex]
[tex]\\ \rm\Rrightarrow r=\sqrt{12802}[/tex]
[tex]\\ \rm\Rrightarrow r=113.14m[/tex]
Vector V is 448 m long in a
224° direction. Vector Wis
336 m long in a 75.9°
direction.
Find the direction of their
vector sum.
The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m toward + x.
What is a vector?A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.
The following are the x and y axes for the supplied vector:
Vector V in x direction;
[tex]\rm V_x = Vcos \theta \\\\ V_x = 448cos(224^0)\\\\ Vx = -322.26[/tex]
Vector V in y direction;
[tex]\rm V_y = Vsin \theta\\\\ V_y = 448 \times sin224^0\\\\ V_y = -311.2[/tex]
Vector W in x direction;
[tex]\rm W_x = 336 \times cos(75.9^0)\\\\ W_x = 81.86[/tex]
Vector W in y direction;
[tex]\rm W_y = 336 \times sin75.9\\\\\ W_y = 325.88[/tex]
The resultant vector in the x direction is;
∑X = -322.26 + 81.86
∑X == -240.4
The resultant vector in the y direction is;
∑Y = -311.2 + 325.88
∑Y = 14.68
The resultant vector is found as;
[tex]\rm R =\sqrt{(-240.4)^2+(14.68)^2} \\\\R = 240.84 \ m[/tex]
Hence, the direction of their vector sum is 240.84 toward +x-axis.
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What is the period of oscillation for a pendulum that completes 3.00 cycles every 2.00 s?
Answer:
[tex]\huge\boxed{\sf T = 0.67\ seconds}[/tex]
Explanation:
Given Data:
Cycles = c = 3 cycles
Time = t = 2 seconds
Required:
Time period = T = ?
Formula:
1) f = c/t
2) T = 1/f
Solution:
Finding frequency first:
f = c / t
f = 3/2
f = 1.5 Hz
Now, finding period:
T = 1/f
T = 1 / 1.5
T = 0.67 seconds
[tex]\rule[225]{225}{2}[/tex]
what is the difference between 1 Newton/ metre² and 1 Pascal
Explain !!
Answer:
One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.
Explanation:
A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?
Answer:
0.315C
Explanation:
Force/Electric field
7520N/23900C
What is the Einstein Rosen Bridge Theory? Is it possible why or why not? (IN YOUR OWN WORDS ANYTHING ELSE WILL BE DELETED)
That states that the blackhole ends are working like bridges between one space to another.
And you can travel through them in 5-10s The distance is thousands of lightyears but we can travel it..This may be possible
Arrangement is used to increase the resistance in a circuit.
Resistors connected in parallel
Resistors connected in alternate
Resistors connected in series
Resistors connected in combination
Answer:
Resistors connected in series
A proton has a charge , what gives it a charge?
Answer:
The charge is believed to be from the charge of the quarks that make up the nucleons (protons and neutrons). A proton is made of two Up quarks, with 2/3 positive charge each and one Down Quark with a negative 1/3 charge (2/3 + 2/3 + -1/3 = 1).
Explanation:
Hope this helps :)
73. Integrated Concepts
An electron microscope produces electrons with a 2.00-pm wavelength. If these are passed through a 1.00-nm single slit, at what angle will the first diffraction minimum be found?
The angle will the first diffraction minimum be found will be 0.034895°.
What is diffraction grating?A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.
The equation of diffraction grating is given as
[tex]\rm d= \frac{m \lambda}{sin \theta }[/tex]
The angle between the incident ray and the point of the occurrence of the diffraction is found as;
[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \lambda= (2.0))(\frac{1.00 \times 10^{-12}}{1\ pm} )\\\\\ \lambda=2.00 \times 10^{-12}[/tex]
The angle will the first diffraction minimum be found is;
[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \theta = sin^{-1}(\frac{1 \times 2.000 \times 10^{-12}}{1\times 10^{-12}} )\\\\\ \theta= 0.0348995^0[/tex]
Hence,the angle will the first diffraction minimum be found will be 0.034895°.
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PLEASE HELP
Which of the following is best determined by applying the principles of
relativity and uncertainty, rather than Newtonian physics?
A. The speed of a truck
B. The length of an object at rest
C. The position of a bird flying overhead
D. The position of an electron
By applying the principles of relativity and uncertainty, rather than Newtonian physics, the position of an electron is best determined. The correct option is D.
What is principle of uncertainty?It states that position and the velocity of an object can't be measured exactly at the same time. One of them may have the approximate value, using the principle of uncertainty.
Every object is moving relative to some frame of reference. So, exact velocity and at what position an object is, can't be find by theory of Newtonian physics. Speed of a truck, length of object at rest and position of a flying bird flying overhead can be found using the Newtonian physics.
An electron is very minute particle whose velocity is unpredictable at any location. So, the position of an electron is best determined by the theory of relativity and uncertainty.
Thus, The correct option is D.
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The units of Work, Energy and power are________ ________units.
Answer:
the units of work and energy is joule and unit of power is Watt
What is the length of the shortest pipe closed on one end and open at the other end that will have a fundamental frequency of 0.060 kHz on a day when the speed of sound is 340 m/s?
An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before
takeoff?
A. 1.6 x 103 meters
B. 1.7 x 103 meters
C. 3.1 x 103 meters
D. 3.3 x 103 meters
Answer:
A
Explanation:
d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m ~ 1.6 x 10^3
A certain FM radio station broadcasts electromag-
netic waves at a frequency of 60,050,000 Hz. These
waves travel at a velocity of 30,000,000 m/s. What is
the wavelength of these radio waves?
v = λ x f
λ = v/f f=v/λ
Answer:
0.5 m
Explanation:
To find wavelength (λ) : apply the formula
λ = wave speed (v) / frequency (f)Solving :
λ = 30,000,000 m/s / 60,050,000 Hzλ = 0.5 m (approximately)PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works
We will take it Cm
Scale factor
1km=10^5cmSo
1cm=10^{-5}km#Mercury
580cmVen us
1080cmEarth
1500cmMars
2280cmJupiter
7780cmSaturn
14300cm#Uranus
28700cmNeptune
45000cmExplain the mechanism of hearing
Explanation:
The pinna collects the sound waves and conducts them to the auditory canal. Sound waves struck at the ear drum and set it into vibration. Eustachian tube equalizes the pressure on either side of the ear drum and thus allows it to vibrate freely. Ear drum transmits the vibrations to ear ossicles.
Select the correct answer. Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two objects is reduced in half, what will be the changed force of attraction between them? A. 2.5 newtons B. 10 newtons C. 15 newtons D. 20 newtons E. 25 newtons
This question involves the concept of Newton's Law of Gravitation.
The force of attraction will be changed to "D. 20 Newtons".
What is Newton's Law of Gravitation?According to Newton's Law of Gravitation, the gravitational force of attraction between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically,
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]
where,
F = force = 5 NG = Gravitatational constantm₁ = mass of first objectm₂ = mass of second objectr = distance between objectsNow, reducing the distance by half, we get:
[tex]F'=\frac{Gm_1m_2}{(\frac{r}{2})^2}\\\\F'=4\frac{Gm_1m_2}{r^2}\\\\F'=4F\\F'=4(5\ N)[/tex]
F' = 20 N
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Answer:
See image
Explanation:
Plato
A tree is at a distance of 50 meters from a place on earth. From this place, the Angle of the tree's peak is 30. Find out the height of the tree.
sine's law
h/sin 30 = 50/sin 60
h/0.5 = 50/(0.5√3)
h=28.9 m
a 90 N force is applied to a 65 kg mass. the mass will accelerate at
F=m.a
a = F/m
a = 90/65
a = 1.385 m/s²
Answer:
solution
here,
Explanation:
weight = 90N
mass=65kg
acceleration due to gravity (g)=??
Now,
w=m×g
90=65×g
90/65=g
:g=1.38m/s^2
Venus and Earth may be regarded as behaving as black bodies. The mean temperature at the surface of Venus is about 600 K and at the surface of Earth is about 300 K. Which of the following is the best estimate for the ratio \frac{\text{power radiated per unit area on Earth}}{\text{power radiated per unit area onVenus}} power radiated per unit area onVenus power radiated per unit area on Earth
The best estimate for the ratio of Power radiated per unit Area on Earth and Power radiated per unit Area on Venus is 1/16. The correct option is D.
What is power radiated?Power radiated is directly proportional to the fourth power of Temperature at the surface and also to the cross-section area.
P = σ A T⁴
For 600 K at Venus, σ A T⁴ = σ A (600)⁴
For 300 K at Earth , σ A T⁴ = σ A (300)⁴
Comparing, we get
[σ A (300)⁴/ σ A (600)⁴ ] = 1/16
Thus, the the best estimate for the ratio is 1/16. The correct option is D.
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2.25 A car's speed is 30m/s, then it slows down in rate 6m/s2, after 4 seconds its speed will be ..... m/s
Answer:
A
Explanation:
Applying the First Equation of Motion :
⇒ v = u + at
⇒ v = 30 + (-6)(4)
⇒ v = 30 - 24
⇒ v = 6 m/s
Compute g at a height of 7 RE above the surface of Earth (RE=6.4E+6m, ME=6.0E+24kg).
The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
What is acceleration due to gravity?It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.
The acceleration due to gravity is related to the distance as
g =GM/R²
where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
Given is the height R = 7 x 6.4 x 10⁶ m and mass of Earth M = 6 x 10²⁴ kg
Substitute the values into the expression to find the acceleration due to gravity.
g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²
g = 8.933 m/s²
Thus, the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
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what is the main function of a diode
Answer:
acts as a one-way switch for current
What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?
Answer:
1.48kg
Explanation:
Here,
potential energy (P.E) = 29j
height (h) = 2m
acceleration due to gravity(g) =
[tex]9.8m {s}^{ - 2} [/tex]
mass(m) = ?
we know,
P.E = mgh
or, 29 = m×9.8×2
or, 29/19.6 = m
or,m = 1.48kg
Two differences between science activities carried out in a science laboratory and those carried out side of science laboratory.
Please answer quickly for brainliest
In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.
In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.
What is science laboratory?The science lab is a place where the experiments related to the science background are performed with the use of apparatus.
The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.
Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.
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You take a trip to Oklahoma City. The turnpike between Tulsa and OKC
is 90 miles long. You drive slowly for an hour and forty-five minutes, stop
at the rest area for fifteen minutes, then drive very fast from the rest
area to the City, arriving an hour after you left the rest area.
What was your average speed for the trip?
[tex]speed_{avg} = \frac{Σ\:distance}{ total\: time}[/tex]
So, according to the question:
distance = 90 miles
time = 1h 45min + 15 min + 1h = 3h
[tex]Therefore:\\ speed_{avg} = \frac{90}{3} mph \\ = \boxed {30 \: mph}[/tex]
if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity
Answer:
3 m/s
Explanation:
Average velocity = Initial velocity + Final velocity / 2
Solving :
⇒ Average velocity = 2 + 4 / 2
⇒ Average velocity = 6/2
⇒ Average velocity = 3 m/s
if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity
Solution:AV = 2 + 4 / 2AV = 6/2AV = 6 ÷ 2AV = 3m/sSo the average velocity is 3ms.
How do you think animals are affected by seasonal change?
Answer:
Animals follow the seasons very closely. Changes in the length of the day or temperature affect the animals' hormone production and cause them to behave according to the season. For that reason, animals instinctively know when it's time for them to mate, build a nest, fly south or stock up on food for the winter.
Dodgems A has a mass of 120 kg, is initially moving to the right at a speed of 10 m/s. It collides with Dodgems B, which has a mass of 160 kg, moving to the right at a speed of 7 m/s. After collision, Dodgems A continues to move to the right but with a speed of 5 m/s. What is the speed of Dodgems B after collision?
Answer:
10.75 m/s
Explanation:
let velocity of Dodgems b be y
law of conservation of momentum
120 x 10 + 160 x 7=120x5+ 160 x y
1200+1120 = 600 + 160 x y
160y = 1720
y = 10.75 m/s
A spherical convex mirror has a radius of 30 cm. An object with a height of 0.30 m is placed 20 cm from the mirror. Note that in +/- sign conventions, f is negative (–) if the mirror is a convex mirror. a. Calculate the image distance. b. Calculate the image height. c. Calculate the magnification. d. Summarize the properties of the image formed in terms of its LOST (location, orientation, size, and type). e. Draw the set-up using graphical methods (ray diagramming). Apply scale drawing. Make sure that your illustration matches well with what you have calculated and presented in a-d.
a)A spherical convex mirror form the image at image distance is 8.57cm.
b) Mirror forms the image of height is 12.855 cm.
c)The magnification of the spherical convex lens is 0.4285.
What is convex mirror?The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.
The focal length of convex lens, f = R/2
Given , the radius of mirror is R =30cm, the focal length will be
f =30cm/2 = 15cm
a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.
1/15 = 1/20 + 1/v
v= 8.57 cm
Thus, the image distance is 8.57cm.
b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.
Substitute the values into the expression, we get the image height as
h(image) = 8.57/20 x 30
h(image) = 12.855 cm
Thus, the image height is 12.855 cm.
c) The magnification is the ratio of image height to the object height.
Putting the values, we have
= 12.855/30
= 0.4285
Thus, the magnification is 0.4285.
d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.
e) The setup drawing is attached.
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