Climate changes will primarily hurt poor people in warm places, but climate changes are primarily being caused by wealthier people in colder places.
Most climate scientists agree that the root cause of the current trend in global warming is the anthropogenic expansion of greenhouse gases as the atmosphere traps heat radiating from the Earth into space. I agree. Certain gases in the atmosphere prevent heat from escaping.
The production of electricity and heat from burning fossil fuels accounts for the majority of global emissions. Most electricity is still produced by burning coal, oil, or gas. Carbon dioxide and nitrous oxide are powerful greenhouse gases that coat the earth and trap the sun's heat. As a result, the amount of carbon dioxide in the atmosphere is increasing rapidly.
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The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa.
What is the gauge pressure at point B?
At point B, the gauge pressure is 22 kPa.
Calculation:
Given gauge pressure is 50 kPa.
Diameter is 3.0cm
speed is 2.0m/s
the gauge pressure is 22 kPa.
How can you figure out a point's gauge pressure?Pg denotes gauge pressure, which is related to absolute pressure as follows: Pa is the local atmospheric pressure, and pg is equal to p - pa. Example: 32.0 psi is the tire pressure as measured by an automobile tire gauge. 14.2 psi is the atmospheric pressure in the area.
What is a point's gauge pressure?In order to calculate gauge pressure, atmospheric (ambient) pressure is subtracted from absolute pressure. A scenario where the absolute pressure is higher than the atmospheric pressure is referred to as positive overpressure, and a situation where the absolute pressure is lower than the atmospheric pressure is referred to as negative overpressure.
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Incomplete question:
The 3.0-cm diameter water line shown at right splits into two 1.0-cm diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa. What is the gauge pressure at point B?
A)12 kPa B)22 kPa C)29 kPa D)38 kPa E)42 kPa
as the sun rotates, an individual sunspot can be tracked across its face. from eastern to western limb, this takes about as the sun rotates, an individual sunspot can be tracked across its face. from eastern to western limb, this takes about 12 hours. a week. two weeks. a month. 5.5 years.
A specific sunspot can be followed as it moves over the Sun's surface as it revolves. This takes approximately from eastern to western limb.
While moving over the Earth-side of the sun, super sunspot AR2192 generated 10 major solar flares, six of which were X-class and four of which were above M5-class. These photos from NASA's SDO, taken between October 17 and October 29, 2014, show a sunspot that is the largest since November 1990 moving across the front of the sun. Try restarting your device if playback doesn't start right away. These photos from NASA's SDO, taken between October 17 and October 29, 2014, show a sunspot that is the largest since November 1990 moving across the front of the sun. Try restarting your device if playback doesn't start right away. Your watched videos might be added to.
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A uniform conducting rod is fixed and allowed to pivot about its center, as shown in the figure. A uniform, positively charged conducting sphere is brought near the upper end of the rod, and the rod rotates clockwise. The rod is then reset to the position shown. The sphere is then brought to point X near the lower end of the rod, and the rod rotates counterclockwise. Which of the following could be true of the charge on the rod? Select two answers.
The rod is positively charged.
The rod is uncharged.
The rod has no net charge until the sphere is brought near it.
The rod is negatively charged.
The correct answers are: a) The rod is negatively charged and d) The rod is positively charged.
When the sphere is brought near the upper end of the rod and the rod rotates clockwise, this indicates that the sphere has a positive charge.
When the sphere is brought to point X near the lower end of the rod and the rod rotates counterclockwise, this also indicates that the sphere has a positive charge.
The other two options are not correct. The rod is not uncharged, because it has a charge when the sphere is brought near it. The rod also does not have no net charge until the sphere is brought near it, because it has a charge when the sphere is brought near it.
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the figure shows the net force exerted on the satellite by the moon and the direction of the tangential velocity of the satellite at time t0. which of the following statements is true regarding the motion of the satellite?
The statement which is true regarding the motion of the satellite is D) The tangential velocity of the satellite does not remain constant.
Any object in orbit around the earth, the sun, or another large body is considered a satellite.
The satellite is able to maintain orbital motion even as gravity pulls it inward thanks to its tangential velocity. The necessary centripetal force is provided by gravitational attraction.
Newton was the first to say that a projectile launched with sufficient speed would actually orbit the earth.
The satellite moves faster when it is close to the earth and slows down while moving away to the top of the ellipse.
The question is incomplete. The complete question is ' A) The gravitational force exerted on the satellite by the moon will increase after time t0.
B) The satellite accelerates in a direction that is parallel to the direction of the tangential velocity.
C) The satellite will move toward the moon after time t0.
D) The tangential velocity of the satellite does not remain constant.'
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In the engine of a locomotive, a cylindrical piece known as a piston oscillates in SHM in a cylinder head (cylindrical chamber) with an angular frequency of 180rev/min. Its stroke (twice the amplitude) is 0.76m. What is its maximum speed?
A cylindrical component known as a piston oscillates in the cylinder head (cylindrical chamber) of a locomotive's engine. 0.76 meters is the stroke, which is twice the amplitude. Its greatest speed is 7.2m/s.
We use v[tex]_{m}[/tex] =ωx[tex]_{m}[/tex]=2πfx[tex]_{m}[/tex], where the frequency is 180/(60s)=3.0Hz and the amplitude is half the stroke, or x[tex]_{m}[/tex]=0.38m. Thus,
v[tex]_{m}[/tex]=2π(3.0Hz)(0.38m)=7.2m/s.
A piston is a disc or short cylinder that fits snugly inside an engine cylinder and imparts motion to a pump or a liquid or gas by moving up and down against it. Pneumatic and hydraulic cylinders, reciprocating engines, reciprocating pumps, gas compressors, and other related devices all have pistons. It is the moving part that has a cylinder around it and piston rings that seal the gas tightness.
To transfer force from the expanding gas in the cylinder to the crankshaft via a piston rod and/or connecting rod is the function of a piston rod and/or connecting rod in an engine.
The processes of intake, compression, combustion, and exhaust are all four-stroke operations in automobile engines.
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a satellite of mass m is in an elliptical orbit around the earth, which has mass me and radius re. the orbit varies from a closest approach of distance a at point a to maximum distance of b from the center of the earth at point b. at point a, the speed of the satellite is vo. assume that the gravitational potential energy ug = 0 when masses are an infinite distance apart. Express your answers in terms of a, b, m, Me, Re, vo, and G.
a. Determine the total energy of the satellite when it is at A. b. What is the magnitude of the angular momentum of the satellite about the center of the Earth when it is at A? c. Determine the velocity of the satellite as it passes point B in its orbit.
The velocity of the satellite as it passes point B in its orbit is vᵇ = v₀a/b
The angular momentum of a inflexible item is described as the made of the moment of inertia and the angular velocity. it's miles analogous to linear momentum and is challenge to the essential constraints of the conservation of angular momentum principle if there's no outside torque at the item.
The belongings of any rotating object given by using moment of inertia times angular velocity. it's miles the assets of a rotating frame given by way of the fabricated from the instant of inertia and the angular speed of the rotating object.
(a) the total energy of the satellite when it is at A:-
E = PE + KE = - G*Me*M/a + 1/2mv₀²
(b) the magnitude of the angular momentum of the satellite about the center of the Earth when it is at A:-
L = mvr = mv₀a
(c) Conservation of angular momentum gives,
mv₀a = mvᵇb, or vᵇ = v₀a/b
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9. a solid metal ball of radius 1.3 cm bearing a charge of 6.2 nc is located near to and along the midline of a hollow uniformly charged plastic rod of radius 1.9 cm and length 12.5 m bearing a uniformly distributed charge of 7.1 nc (see the figure) on its outer surface. the distance between the center of the rod and the center of the ball is 25.5 cm.
Since a metal ball is considered a solid sphere So the electric field inside the metal ball is given by E = (p/3∈₀)r
Where r is the distance from the center and rho is charge density. Hence at the center r = 0
Then electric field
E = (p/3∈₀) x 0 = 0 N/C
Hence electric field at the center of the metal ball is due to its own charge only being 0N/C.
An electrical property is associated with any point in space when some form of electric charge is present. The magnitude and direction of the electric field are represented by the value of E and are called field strength or electric field strength or simply electric field.
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In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the following expression, where x is in centimeters and t is in seconds.x=(4.00cm)cos(3t+π/6)(a) At t=0, find the position of the piston.(b) What is its velocity?(c) What is its acceleration?(d) Find the period and amplitude of the motion.
The position of the piston is 3.785 cm. The velocity of the piston is -2.585 cm/s. The acceleration of the piston is −15.14 cm/s The period of piston is 3.14 s and the amplitude of piston is 4 cm.
It is a kind of periodic motion bounded between two extreme points. For example, Oscillation of Simple Pendulum, Spring-Mass System. The object will keep on moving between two extreme points about a fixed point is called the mean position (or) equilibrium position along any path.
(a) The equation for the piston's position is given as
= x=(4.00 cm)cos(3t+6π )
At t=0,
= x =(4.00 cm)cos(6π )
= x = 3.785 cm
(b) Differentiating the equation for position with respect to time gives us the piston's velocity:
= v = dt/dx = −(8.0 cm/s)sin(2t+ 6π )
At t=0,
= v = dt/dx = −(8.0 cm/s)sin(6π )
= v = -2.585 cm/s
(c) Differentiating again gives its acceleration:
= a = dv/ dt =−(16.0 cm/s 2 )cos(2t+ 6π )
At t=0,
= a = −(16.0 cm/s 2 )cos(6π )
= a = −15.14 cm/s
(d) The period of motion is = T
= T = ω/2π
= T = 2/2π
= T = 3.14 s
and,
The amplitude directly from the equation for x =
= A = 4 cm
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ucy has three sources of sound that produce pure tones with wavelengths of 36 cm , 60 cm , and 92 cm . she also has an assortment of narrow tubes that are closed off at one end but open at the other. after experimenting, lucy notices that each tone will resonate with tubes of some lengths but not with others.for each wavelength, determine which tube lengths, if any, will resonate with sound of that wavelength.
The tubes with lengths of 15, 45, and 75 cm are found to resonate with this wavelength. Additionally, resonance is seen for tubes with lengths of 25 and 75 cm and 31 and 93 cm.
For this reason, at the place where the tube is closed, we have a node, and at the open point, we have a belly; in this case, the fundamental wave is = 4L. To determine the length of the tube that has resonance, we must establish the natural frequencies of the tubes.
The following resonance, known as the first harmonic, is 3 = 4L / 3.
The next fifth harmonic resonance is 5 = 4L / 5, and we can see that its general form is n= 4L / n, where n = 1, 3, and 5.
Let's apply these terms to the issue at hand.
Start with the wavelength that is the shortest.
Lam equals 60 cm.
Let's determine the length of the tube this harmonica provides.
L = λ n / 4
n = 1 L = 60 will yield the shortest tube length. 1/4\s L = 15 cm
For n = 3 L = 60 3/4\s L = 45 cm
For n = 5 L = 60 5/4\s L = 75 cm
For n = 7 L = 60 7/4\s L = 105cm
We can see that the harmonics 1, 3 and 5 of the tubes with lengths 15, 45, and 75 resonate with this wavelength.
b) λ = 100 cm
For n = 1 L = 100 1/4\s L = 25 cm
For n = 3 L = 100 3/4\s L = 75 cm
For n = 5 L = 100 5/4\s L = 125 cm
There is resonance in the fundamental and third ammonium frequencies for lengths of 25 and 75 cm. L = 124 1/4 L = 31 cm
In the case of the second resonance, L = 124 3/4 L = 93 cm.
For tubes with lengths of 31 and 93 cm, resonance occurs in the fundamental and third harmonics.
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The speed of a sound wave in air depends on
A) its wavelength.
B) All of the above choices are correct.
C) None of the above choices are correct.
D) the air temperature.
E) its frequency.
Option C. None of the above choices are correct, A sound wave in air moves at a certain speed depending on its frequency. None of the wavelengths above it. all the aforementioned air temperatures. ambient temperature.
Under the same physical conditions, the speed of sound is constant for all frequencies in a particular medium. Since the distance covered by the sound wave in a given amount of time is what determines the speed of sound, it can be calculated using the following formula: where v is the velocity, is the sound wave's wavelength, and f is the frequency. Since the distance covered by the sound wave in a given amount of time determines the speed of sound, the following formula can be used to calculate it: Where v is the speed, is the sound wave's wavelength, and f is the frequency.
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a) Traveling waves propagate with a fixed speed usuallydenoted as v(but sometimes c). The waves are called _______________ if their waveformrepeats every time interval T.
The fundamental relationship among frequency, wavelength, andvelocity is
v = f \lambda.
This relationship may be visualized as follows: In 1 s, f\cdot(1\;{\rm s}) cycles of the wave move past an observer. In thissame second the wavetrain moves a distance v\cdot(1\;{\rm s}).
c) If the velocity of the wave remains constant, then as thefrequency of the wave is increased, the wavelength___________.
d) The difference between the frequency f and the frequency omega is that fis measured in cycles per second or hertz (abbreviated Hz) whereasthe units for \omega are _______ per second.
e) Find an expression for the period of a wave T in terms of other kinematic variables.
f) What is the relationship between omega and f?
g) What is the simplest relationship between the angularwavenumber kand just one of the other kinematic variables?
The waves are called periodic wave if waveform repeats in time interval T. A wave is said to be periodic if its duration of transmission is infinity. In a periodic wave wavelength and frequency is regulated. In a given time interval the wave completes one cycle.
For a periodic wave the wave function is y(x,t) = A sin2(x -vt) .The term 2 scales the wave to the natural period of the sin function. The term A gives the amplitude of the wave which is the maximum displacement of the wave.
If the velocity of the wave remains constant, then as the frequency of the wave is increased, the wavelength decreases
The phase difference between any two points on a wave is found as follows:-At P1 the phase is 1 = kx1- t1 +,
At P2 the phase is 2 = kx2- t2 +.
So the phase difference is = 2-1 = k(x2 - x1)- (t2 - t1) The wave speed is given by:- v=k=2f2/=f
Examples of periodic wave can be seen in:-
1.Electromagnetic wave in optical fibre
2.Sound from a guitar string
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star a is 5l ight years away an identiccal star of the absolute luminosity star b is 10 light years away compare tehir relative apparent brightness
In terms of the amount of light years energy received, star A should appear 100 times brighter than star B. This is due to the fact that received energy diminishes according to squared distance.
How far apart are two stars from one another?Contact binaries are binary star systems with members whose distance from one another is so great that their outer envelopes actually touch. This structure can actually be rather stable, with typical lifetimes measured in millions or even billions of years, which may surprise you.
How do we figure out how far away the stars are from Earth?When the Earth is at the other end of the star's orbit, six months later, astronomers take another measurement of the star's position. This results in a base line that is equal to the sum of the two angles used to measure the star and the double distance from Earth to the Sun's center (about 300,000,000 km). The distance to a nearby star can be calculated using these three variables in a very straightforward trigonometric manner.
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A concave mirror with a focal length of 40 cm. How far should the mirror be
held from his face in order to give an image of two-fold magnification
The mirror should be held at a distance of 60cm
What is Magnification?Magnification is defined as the ratio of the height of image to the height of object. It can also be defined as the ratio of distance of image from mirror or lens to the distance of object from lens.
Magnification is given as v/u . where v is the image distance and u is the object distance.
therefore 2 = v/u
v = 2u
from the mirror formula
1/f = 1/v+ 1/u . where F is the focal length
represent 2u for v
1/f = 1/2u + I/u
1/f = 3/2u
1/40 = 3/2u
2u = 120
divide both sides by 2
u = 120/2
u = 60cm
therefore the object distance is 60cm. This means that to have a double sized image , the distance from the mirror and his face must be 60cm.
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Vinegar is a solution of acetic acid in water. Which term best describes water in this solution?
Answer:
Solvent
Explanation:
In a solution of vinegar, water is the solvent. A solvent is a substance that dissolves another substance (in this case, acetic acid) to form a solution. The substance that is dissolved is called the solute. In the case of vinegar, the solute is acetic acid and the solvent is water.
A 64 kg box is pushed at a constant speed up a frictionless plane for a distance of 18 m by a force parallel to the plane. If the plane makes an angle of 24 degrees above the horizontal, how much work was done?
1500 j,1200j,4600j,2900j,8800j
4600 j work is done.
To find the amount of work done, the equation for work must be used. This equation is Work = Force x Distance. Force is equal to the mass of the box multiplied by the acceleration due to gravity, and the distance is 18 meters. The angle of 24 degrees above the horizontal must also be taken into account, therefore the cosine of 24 degrees must be used. The mass of the box is 64 kg and the acceleration due to gravity is 9.8 m/s2. After plugging in all the values, the work done is 4600 J.
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A block of mass 2kg starts from rest sliding down a rough inclined plane making an angle of 60⁰ with the horizontal length of plane in 8m it takes 4 second to return the bottom find the cofficent of kinetic friction
The force applied on the body that is on the inclined plane is given as, F=mgsinθ, F=2×9.8×sin30 =9.8N and f=μmgcosθ f=0.7×2×9.8cos30 =11.88N.
What is limiting friction?Any increase in the moving force will result in slippage; limiting friction only exists when the moving force and the force opposing motion are equal.
The limiting frictional force is independent of the area of contact and proportional to the normal reaction between the contacting surfaces.
The amount of friction that can be produced when two static surfaces come into touch. A motion will start as soon as the force applied to the two surfaces surpasses the limiting friction. The normal response force and the coefficient of limiting friction are combined to get the limiting friction for two dry surfaces.
Therefore, The force applied on the body that is on the inclined plane is given as, F=mgsinθ, F=2×9.8×sin30 =9.8N and f=μmgcosθ f=0.7×2×9.8cos30 =11.88N.
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A circular saw is powered by a motor. When the saw is used to cut wood, the wood exerts a torque of 0.80N on the saw blade. If the blade rotates with a constant angular velocity of 20 rad/s the work done on the blade by the motor in 1.0 minis:
A. 0
B. 480 J
C. 960 J
D. 1400 J
J E. 1800 J
If the blade rotates with a constant angular velocity of 20 rad/s the work done on the blade by the motor in 1.0 min IS 960 J.
A torque is a force that causes rotation. Tells how effective force is at twisting or rotating an object.
Conditions for Equilibrium is that when FNet = 0 Translational EQ (Center of Mass) tNet = 0 Rotational EQ (True for any axis). Choose axis of rotation wisely to make problems easier, But as long as you’re consistent everything will be okay.
Gravitational Force Weight = mg, acts as force at center of mass, Torque about pivot due to gravity t = mgd, object not in static equilibrium.
As we know,
work = torque x angular displacement
θ = ωt
θ = 20 x 60
θ = 1200rad
hence,
work = 0.80 x 1200
W = 960J
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if the ball is released from rest at a height of 0.91 m above the bottom of the track on the no-slip side, what is its angular speed when it is on the frictionless side of the track? assume the ball is a solid sphere of radius 2.1 cm and mass 0.14 kg .(figure 1)How high does the ball rise on the frictionless side?
Angular speed when it is on the frictionless side of the track is 89.7 rad/s
Given that, mass, m=0.14 kg
Ball is released. from rest. at a height. of, h= 0.83 m
Solid sphere of radius, R = 3.8 cm
=0.038 m
From the conservation of energy
ΔK = ΔU
1/2 mv2 + 1/2 Iω2 = mgh
Here, I=2/5MR2 , v=Rω
1/2 mv2 + 1/2 (2/5mR2)(v/R)2 =mgh
1/2 [v2 +2/5 v2] =gh
7/10 v2 = gh
0.7v2 = gh
v =√ [gh / (0.7) ]
=√ [(9.8 m/s2)(0.83 m) / (0.7) ]
= 3.408 m/s
Consequently, angular speed on the frictionless side of the rail,
ω = v/R
= (3.408 m/s)/(0.038 m)
= 89.7 rad/s
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observe the above block diagram. consider 43.8440 rad/s/v to be the steady state value (also known as dc gain), and 0.0310 sec to be the ol time constant. the tach sensitivity is given by 0.0250 v/(rad/s). for a gain of 1.0000, the closed loop time constant , in seconds, is
The closed loop time constant , in seconds, is Vo(t) = (410/9 – 205/4 e-t + 205/36 e-9t) u(t).
What is steady state ?
The term "steady-state" refers to the condition in which a conductor can no longer absorb heat. During this stage, the temperature stabilizes. The heat, however, is constantly lost to the environment.
What is time constant ?
A first-order, linear time-invariant (LTI) system's reaction to a step input is characterized by a parameter known as the time constant, which is typically represented by the Greek letter tau. A first-order LTI system's primary defining attribute is its time constant.
Vin(s) 2/s+1 205/s+9 vo(s)
W(s) /Vin(s) = 2x205/(s+1) (s+9)
For step response
Vin(s) = 1/s
Vo (s) = 410/s (s) (s+9)
Using partial fraction method
Vo(s) = A/s + B/s+1 + C/s+9 - (1)
A= 410/(s+1) (s+9)|s=0 = 410/(0+1) (0+9) = 410/9
A= 410/9
B= 410/s(s+9) |s=-1 = 410/(-1) (=1+9) = -205/4
B = -205/4
C= 410/(s) (s+1)|s = -9 = 410/(-9) (-9+1) = 205/36
C=205/36
Substitute value of A,B and C in eq (1)
Vo(s) = 410/9s – 205/4(s+1) + 2052/36(s+9)
Apply inverse la place transform both side
L-1 (Vo(s) ) = L-1(410/9s) – L-1(205/4(s+1) ) + L-1 (205/36(s+9)
Vo(t) = 410/9 L-1 (1/s) -205/4 L-1 (1/s+1) + 205/36 L-1(1/(s+9))
Vo(t) = 410/9u(t) -205/4 e-t u(t) + 205/36 e-9t u (t)
Vo(t) = (410/9 – 205/4 e-t + 205/36 e-9t) u(t)
Therefore, the closed loop time constant , in seconds, is Vo(t) = (410/9 – 205/4 e-t + 205/36 e-9t) u(t).
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Disk A has a weight of 5 lb and Disk B has a weight of 10 lb. If no slipping occurs between them,
determine the couple moment M which must be applied to Disk A to give it an angular acceleration of 4 rad/s
2
. Radius A is 0.5 ft. Radius B is 0.75 ft.
The couple moment M = 0.233 lb.ft
Given,
The weight of disc A = 5 lb
The radius of disc A = 0.5 ft
The weight of disc B = 10 lb
The radius of disc B = 0.75 ft
Angular acceleration of disc A = 4 rad/s²
Let,
The couple moment = M
Disc A:
∑[tex]M_{A} = I_{A} \alpha_{A}[/tex]
M - F(0.5) = (1/2)(5/32.2)(0.5)²(4)
2M - F = 0.078 ..........................(1)
Disc B:
∑[tex]M_{B} =I_{B} \alpha _{B}[/tex]
F = (1/2)(10/32.2)(0.75)²[tex]\alpha _{B}[/tex] .............(2)
[tex]r_{A} \alpha _{A} =r_{B} \alpha _{B}[/tex]
0.5(4) = (0.75)[tex]\alpha_{B}[/tex] .....................................(3)
By solving equations (1), (2), and (3) we get
M = 0.233 lb.ft
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On the surface of the moon, gravity is 1.6m/s^2. An astronaut has a mass of 90kg.
(a) Calculate his weight on earth.
(b) State his mass when on the moon.
(c) Calculate his weight on the moon.
Answer:
Hope this helps.
Explanation:
(a) To calculate the astronaut's weight on Earth, you can use the formula for weight, which is W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s^2. So the astronaut's weight on Earth would be W = 90 kg * 9.8 m/s^2 = <<90*9.8=882>>882 N.
(b) The astronaut's mass when on the moon is the same as it is on Earth, which is 90 kg.
(c) To calculate the astronaut's weight on the moon, you can use the same formula as before, but with the acceleration due to gravity on the moon, which is 1.6 m/s^2. The astronaut's weight on the moon would be W = 90 kg * 1.6 m/s^2 = <<90*1.6=144>>144 N.
the potential difference across the terminals of a battery is 8.20 v when there is a current of 1.55 a in the battery from the negative to the positive terminal. when the current is 3.52 a in the reverse direction, the potential difference becomes 10.40 v.
potential difference across the terminals of a battery is 8.2
V when there is a current of 1.54A in the battery from the negative to the positive terminal. When the current is 3.49A in the reverse direction, the potential difference becomes 9.2V
A-What is the internal resistance of the battery?
B-What is the emf of the battery?
The battery's emf is 8.87V and its internal resistance is 0.43. The internal resistance of the battery is 0.19, and its emf is 8.49 V.
1).
8.2=E−1.55r
10.40=E+3.52r
Solving these two equations we get
r=0.43Ω and E=8.87V
2).
8.2=E−1.54r
9.2=E+3.49r
Solving these two equations we get
r=0.19Ω and E=8.49V
The opposition a substance provides to the flow of electrical current is referred to as resistance. The capital letter R is used to symbolize it. The ohm, frequently written as a word and occasionally represented by the uppercase Greek letter omega, is the commonly used unit of resistance.
A component's resistance is one ohm when a one-volt potential difference (voltage) is present across it and an electric current of one ampere flows through it. (See Ohm's law for further information on how current, resistance, and voltage are related.)
Generally speaking, the current in a direct-current (DC) electrical circuit is inversely proportional to the resistance while the supplied voltage is held constant.
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what's the effect of gravity on the balance?
Answer:
Explanation:
The lower your center of gravity, the easier it is to keep your balance. If you're sitting on a chair, you can lean over more than if you're standing up. With your center of gravity low, you can lean further to one side or the other without creating enough turning force to tip you over.
consider a rocket that has a specific heat ratio of 1.25 and a nozzle area ratio of 10:1. the stagnation pressure is 400 psi. using the plots below, estimate the design altitude for the rocket.
The points of the design altitude for the rocket, when the stagnation pressure is of 400 psi, using given plots will be :-
The Exit velocity and Pressure in the case of a rocket motor are 1290m/s and 8.1 atm respectively. The C* and thrust propellant calculations are based on certain formulas.
Exit velocity is v_e = sqrt((2 * C_p * 3000 K) / (1.25 - 1)) * sqrt((1.25 + 1) / 2) * (1 - (p_e / 60 atm) ^ ((1.25 - 1) / 1.25)) = 1290 m/s.Exit pressure is p_e = 60 atm * ((2 / (1.25 + 1)) * (1 - (1290 m/s / sqrt((1.25 + 1) / 2 * C_p * 3000 K)) / (1 - (p_e / 60 atm) ^ ((1.25 - 1) / 1.25)))) ^ (1.25 / (1.25 - 1)) = 8.1 atm. This is the pressure at the nozzle exit.To calculate c* for the propellant, we can use the equation c* = sqrt(1.25 * 8.314 J/mol-K * 3000 K / 18) = 654.3 m/s.To calculate the mass flow rate for the rocket, we find that m_dot = 60 atm * (pi * (5 cm / 2)^2 / 4) * 654.3 m/s / sqrt(3000 K) = 4.1 kg/s.To calculate the thrust of the rocket, we can use the equation that F= 4.1 kg/s * 1290 m/s + (8.1 atm * (pi * (30 cm / 2)^2 / 4) - 60 atm * (pi * (5 cm / 2)^2 / 4)) = 45600 N. This is the thrust produced by the rocket at sea level.To calculate the thrust coefficient of the rocket motor, we can use the equation C_F = (2 / (1.25 + 1)) * (1 - (1290 m/s / sqrt((1.25 + 1) / 2 * C_p * 3000 K)) / (1 - (8.1 atm / 60 atm) ^ ((1.25 - 1) / 1.25))) = 0.8. This is the thrust coefficient of the rocket motor.To calculate the effective exhaust velocity of the rocket motor, we can use the equation v_e, eff = v_e + g * Isp, where v_e, eff is the effective exhaust velocity, v_e is the exit velocity, g is the acceleration due to gravity, and Isp is the specific impulse. At sea level, g = 9.8 m/s^2.The specific impulse of the rocket motor is given by the equation Isp = (1.25 * 8.314 J/mol * K * 3000 K) / (9.8 m/s^2 * 18 g/mol) = 279 s.The effective exhaust velocity of the rocket motor is v_e, eff = 1290 m/s + 9.8 m/s^2 * 279 s = 36660 m/s. This is the effective exhaust velocity of the rocket motor when fired at sea level.To calculate the thrust of the rocket motor, we can use the equation F = 8.1 atm * 28.3 cm^2 * 1290 m/s = 3.1 * 10^6 N.To calculate the thrust coefficient, we can use the equation C_F = 3.1 * 10^6 N / (8.1 atm * 0.2 cm^2) = 0.16.To calculate the effective exhaust velocity of the rocket motor when fired in space, we can use the equation v_e = sqrt((2 * C_p * 3000 K) / (1.25 - 1)) * sqrt((1.25 + 1) / 2) * (1 - (0 / 60 atm) ^ ((1.25 - 1) / 1.25)) * sqrt(1 - ((18 / 18) ^ 2)) = 1290 m/s.To calculate the specific impulse of the rocket motor, we can use the equation I_sp = 1290 m/s / 9.8 m/s^2 = 131 s. This is the specific impulse of the rocket motor when fired in space.Therefore, these are the points of the design altitude for the rocket, when the stagnation pressure is of 400 psi, using given plots.
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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Consider a rocket motor equipped with a nozzle in which the stagnation conditions are 3000 K and 60 atm. The specific heat ratio is 1.25 and the molecular weight of the propellant is 18. The nozzle throat diameter is 5 cm and the nozzle exit diameter is 30 cm. a. Calculate the exit velocity b. Calculate the exit pressure c. Calculate c* for this propellant d. Calculate the mass flow rate for the rocket e. If the rocket is fired at sea level, calculate the thrust. f. If the rocket is fired at sea level, calculate the thrust coefficient g. If the rocket is fired at sea level, calculate the effective exhaust velocity h. If the rocket is fired at sea level, calculate the specific impulse. i. If the rocket is fired in space, calculate the thrust. j. If the rocket is fired in space, calculate the thrust coefficient k. If the rocket is fired in space, calculate the effective exhaust velocity I. If the rocket is fired in space, calculate the specific impulse]
A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine that the isotope is unstable and half of their sample will decay in 17.0 months. The scientists need a new laboratory to properly conduct measurements on the isotope. If a laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 29.0 months to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00×108 m/s. If they place their sample of the isotope on the spaceship, at what speed u must it travel in order for the new laboratory to be completed on Earth by the time half of the isotope on the spaceship decays? Assume that it took one month for the scientists to actually start construction and launch the spaceship so half the sample will remain in 16.0 months but it will still take 29.0 months to build the new lab.A) At what speed u must the spaceship travel for the scientists to have enough time to complete their laboratory by the time half of the isotope has decayed?
'u' must the spaceship travel for the scientists to have enough time to complete their laboratory by the time half of the isotope has decayed at speed of 2.416*10⁸ m/s .
Calculation :
[tex]29 = \frac{16}{1-\frac{c}{v} ^{2} }[/tex]
v = 0.805 * C
V = 0.805 * 3*10*⁸
= 2.146*10⁸ m/s
Isotopes are two or more types of atoms that have the same atomic number (number of protons in the nucleus) and position in the periodic table (and thus belong to the same chemical element), but that differ because of their nucleon number (mass number). The number of neutrons in the core is different. All isotopes of a particular element have approximately the same chemical properties, but they have different atomic masses and physical properties
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suppose you observe a binary system containing a main-sequence star and a brown dwarf. the orbital period of the system is 1 year, and the average separation of the system is 1 au . you then measure the doppler shifts of the spectral lines from the main-sequence star and the brown dwarf, finding that the orbital speed of the brown dwarf in the system is 23 times greater than that of the main-sequence star.1. How massive is the brown dwarf?
Mdwarf = ? KG
The Mass of the Brown dwarf's star,M₂ = 4.132 * 10²⁷ kg
Let M₁ be the mass of the main-sequence star
M₂ be the Mass of the brown dwarf
v₁ be the speed of the main-sequence star
v₂ be the speed of the brown dwarf
The system's typical separation is 1 AU, where r₁ = r₂
The brown dwarf's orbital speed is 22 times that of the main-sequence star.
Therefore, v₂ = 22 v₁
As a main sequence star, the sun
The Mass of the main-sequence star is 2 * 10³⁰ kg
Centripetal force, F = Mv²/r
M₁v₁²/r₁² = M₂v₂²/r²
M₁v₁² = M₂v₂²
M₂/M₁ = v₁²/v₂²
M₂/M₁ = (1/22)²
M₂/M₁ = 0.002066
M₂ = 0.002066M₁
M₂ = 0.002066 * 2 * 10³⁰
M₂ = 4.132 * 10²⁷ kg
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did theoretical and experimental values agree? if they did not agree, explain why. in newton second law atwoood lab
Conclusion/Discussion In conclusion, we tested the theory of Newton's Second Law of Motion using the Atwood Machine. In order to test the proportionalities the second law suggests, I was able to plot two graphs and successfully calculate the acceleration of each of my trials.
The second law of Newton will be thoroughly investigated in this experiment. According to Newton's second law, force is defined as mass times acceleration (F=mxa). Simply said, his law outlines the connection between an object's mass, acceleration, and required force to move it.
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A 0.45 kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by
x = (12 cm)cos[(17 rad/s)t + p/2 rad]
(a) What is the oscillation frequency (in Hz)? (b) What is the maximum speed acquired by the block? (c) At what value of x does this occur? (d) What is the magnitude of the maximum acceleration of the block? (e) At what positive value of x does this occur? (f) What force, applied to the block by the spring, results in the given oscillation?
Give your answers in centimeter-based units, where applicable.
(a) The angular frequency is 2.7 Hz
(b) The maximum speed is 2.04 m/s
(c) The maximum value is occur at mean position
so the dispalcement is zero
(d) The maximum acceleration is 34.68 m/s^2.
(e) The acceleartion should be maximum at extrem positions
so the position x = A = 12 cm
( f ) The force on the block 15.6 N
Calculation :
The mass of the block m = 0.45 kg
The dispalcement of the block
x = 12cm cos [(17 rad/s) t + (π/2 rad)]
(a) The angular frequency
ω = 17 rad/s
2πf = 17 rad/s
then the frequency
f = 17 / 2π = 2.7 Hz
(b) The maximum speed
v max = Aω = (12 cm) (17 rad/s)
= 2.04 m/s
(c) The maximum value is occur at mean position
so the dispalcement is zero
(d) The maximum acceleration
a max = Aω^2
= (0.12 m) (17)^2 = 34.68 m/s^2
(e) The acceleartion should be maximum at extrem positions
so the position x = A = 12 cm
(f) The force on the block
F = ma = (0.45 kg) (34.68 )
= 15.6 N
Force or Energy Exercised or Applied: Cause of Movement or Change: Active Force. force of nature
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wo identical blocks are pushed up frictionless inclines as shown. consider the portion of the motion of block 1 during which it moves a distance l1 , and the portion of the motion of block 2 during which it moves a distance l2, which is greater than l1. each block is displaced the same vertical distance z.
In terms of work produced, the gravitational force acting on block 2 is equal to that acting on block 1.
The quantity of labor is equal to zero when an object moves a fixed distance. The movement of the item as well as the applied load define the quantity of work. It rises in tandem with displacement and vice versa.
Blocks 2 and 1 are the same and are frictionlessly raised to the identical height, h = Z.
As a result, both blocks will have the same mass and gravitational pull.
m1 = m2
FG = m1g = m2g
Gravitational acceleration (g) is indicated here.
the labor put in while block 2 is subject to the gravitational pull.
W2 = m2gh
When gravity pulls on block 1, what labor is done on block 1?
W1 = m1gh
W1 = m1gZ
W1 = m2gZ , [m1=m2]
W1 = W2
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The question is -
Two identical blocks are pushed up frictionless inclines as shown. Consider the portion of the motion of block 1 during which it moves a distance of L 1 and the portion of the motion of block 2 during which it moves a distance of L 2. Each block is displaced the same vertical distance Z. The hand pushes parallel to the incline with the same magnitude of force F B H in both cases. Block 2 moves at a decreasing speed. Is the absolute value of the work done by the gravitational force on block 2 greater than, less than, or equal to the work done by the gravitational force on block 1? Explain.
cA proton and an electron are held a short distance apart and released from rest. The only nonnegligible forces on the particles are the electrostatic forces they exert on each other. Which of the following statements is true? The magnitude of the electrostatic force exerted on the proton by the electron is greater than that exerted on the electron by the proton. The magnitude of the acceleration of the proton is less than the magnitude of the acceleration of the electron The proton must move a larger distance to have the same magnitude change in potential energy as the electron. The proton must move the same distance to have the same change in speed as the electron.
The magnitude of the electrostatic force exerted on the proton by the electron is greater than that exerted on the electron by the proton.
What kind of force is electrostatic?
The Coulomb's inverse-square law, sometimes known as Coulomb's law, is an observational physical principle that measures the force exerted between two electrically charged particles that are stationary. Common names for the electric created between two charged objects at rest include electrostatic force and Coulomb force.
Electrostatic force, where is it?Between two charges that are separated by a distance, there is an electrostatic force. The size of each charges and the separation between them determine the strength of the electrostatic force. Two charges that are either positive or negative when placed together repel one another.
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