Question 5 You and a friend share a pizza cut into 8 equal slices. Suppose you each eat 3 slices. What
fraction of the pizza is left over?

Answer:

false

plz tell me if im wrong i hope i helped

Answer:

6 1/2 cubic feet

Step-by-step explanation:

A carton has a length of 2 1/6 feet

The width is 1 1/5 feet

The height is 2 1/2 feet

Therefore the volume of the carton can be calculated as follows

= length × width × height

= 2 1/6 × 1 1/5 × 2 1/2

= 13/6 × 6/5 × 5/2

= 390/60

= 13/2

= 6 1/2 cubic feet

Hence the volume of the carton is 6 1/2 cubic feet

Answer:

20%

Step-by-step explanation:

100 divided by 5 =20 20x1=20

First, let's get the total amount of coins inside the box.

7 quarters + 4 dimes + 4 nickels + 3 pennies = 18 total coins.

(7 quarters / 18 coins) * 100 = 38.89% chance of picking a quarter

(4 dimes / 18 coins) * 100 = 22.22% chance of picking a dime

(4 nickels / 18 coins) * 100 = 22.22% chance of picking a nickel

(3 pennies / 18 coins) * 100 = 16.67% chance of picking a dime

Since the quarters have a higher percentage of being picked, we can expect to draw $0.25 from the box

Answer:

54

Step-by-step explanation:

Substitute n into the equation:

-2(3)[5+3-8-3(3)]

-6[-9]

+54

Step-by-step explanation:

∫ 9 arctan(1/x) dx

If u = 9 arctan(1/x), then:

du = 9 / (1 + (1/x)²) (-1/x²) dx

du = -9 dx (1/x²) / (1 + (1/x²))

du = -9 dx / (x² + 1)

If dv = dx, then v = x.

∫ u dv = uv − ∫ v du

= 9x arctan(1/x) − ∫ -9x dx / (x² + 1)

= 9x arctan(1/x) + 9/2 ∫ 2x dx / (x² + 1)

= 9x arctan(1/x) + 9/2 ln(x² + 1)

Evaluate from x=1 to x=√3.

[9√3 arctan(1/√3) + 9/2 ln(3 + 1)] − [9 arctan(1) + 9/2 ln(1 + 1)]

[9√3 (π/6) + 9/2 ln(4)] − [9 (π/4) + 9/2 ln(2)]

(3π√3)/2 + 9/2 ln(4) − (9π/4) − 9/2 ln(2)

(6π√3)/4 + 9 ln(2) − (9π/4) − 9/2 ln(2)

(6π√3 − 9π)/4 + 9/2 ln(2)

Answer:

[tex]9\left(\frac{1}{2}\ln \left(2\right)-\frac{\pi }{4}+\frac{\pi }{2\sqrt{3}}\right)[/tex]

Step-by-step explanation:

We are given the integral 9 arctan(1/x)dx on the interval x[ from 1 to √3 ].

Now let's say that u = arctan(1/x). The value of 'du' would be as follows:

du = - x / (1 + x²) * dx

If we apply integration by parts, v = 1, and of course u = arctan(1/x):

=> 9x arctan(1/x) − ∫ -9x dx / (x² + 1)

=> 9[x arctan(1/x) - ∫ - x / (1 + x²) * dx] on the interval x[ from 1 to √3 ]

Let's now simplify the expression ' ∫ - x / (1 + x²) * dx':

=> (Take the constant out, in this case constant = - 1), - ∫ x / (1 + x²) * dx

=> (Apply u-substitution, where u = 1 + x²), - ∫ 1/2u * du

=> (Take constant out again, in this case 1/2), - 1/2 ∫ 1/u * du

=> (Remember that 1/u * du = In( |u| )), - 1/2In( |u| )

=> (Substitute back 'u = 1 + x²), - 1/2In| 1 + x² |

So now we have the expression '9[x arctan(1/x) + 1/2In| 1 + x² |]' on the interval x[ from 1 to √3 ]. Let's further simplify this expression;

[tex]9\left[x\arctan \left(\frac{1}{x}\right)+\frac{1}{2}\ln \left|1+x^2\right|\right]^{\sqrt{3}}_1\\\\=> 9\left[\frac{1}{2}\left(2x\arctan \left(\frac{1}{x}\right)+\ln \left|1+x^2\right|\right)\right]^{\sqrt{3}}_1[/tex]

Now computing the boundaries we have the following answer:

[tex]9\left(\frac{1}{2}\ln \left(2\right)-\frac{\pi }{4}+\frac{\pi }{2\sqrt{3}}\right)[/tex]

Answer:

It's 3.

Step-by-step explanation:

3x2=6

3x4=12

3x5=15

Answer:

416 is your answer

hope this helped you

please mark as the brainliest (ㆁωㆁ)

Answer:

119

Step-by-step explanation:

Following the order of operations as stated in PEMDAS

Given

99 + 5 [ 15 - (17 - 6) ] ← evaluate parenthesis

= 99 + 5 (15 - 11)

= 99 + 5( 4) ← evaluate multiplication

= 99 + 20 ← evaluate addition

= 119

Answer:

D

Step-by-step explanation:

♡ The Question ♡

Graph the solution of 5 ≤ 9 - 4a

A) A

B) B

C) C

D) D

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Answer ♡

-I believe the answer should be the first choice, A!

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*  

♡ The Explanation/Step-By-Step ♡

-No Explanation/Step-By-Step provided!  

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ Tips ♡

-No Tips provided!

Answer:

40/4 shaded in squares

Step-by-step explanation:

for 0.4, since 100 is a whole, multiply by 100.

0.4*100=40

shade in 40 squares

for 0.04, multiply by 100

0.04*100=4

shade in 4 squares

Answer:

x-40%-16%

Step-by-step explanation:

Train A's speed = x

Train B's speed = x + 10

4.5(x + x + 10) = 432

Distribute both sides by 4.5

x + x + 10 = 96

Combine like terms.

2x + 10 = 96

Subtract 10 from both sides.

2x = 86

Divide both sides by 2

x = 43

Train A = x = 43 mph

Train B = x + 10 = 43 + 10 = 53 mph

Speed is the ratio of distance and time.

Speed = Distance /Time

Distance = Speed x Time

If Train B travels 10 mph faster than Train A.

The speed of train A is 48 mph.

The speed of train B is 58 mph.

Speed is the ratio of distance and time.

It shows how fast an object is moving at a given time.

Example:

The speed of a car moving 4km in 2 hours is 2km per hour.

We have,

Train A:

Speed = x

Train B:

Speed = x + 10

Speed = Distance / Time

Distance = Speed x Time

At time = 4.5 hours, the train is 432 miles apart.

This can be written as,

Distance = (Speed of train A + Speed of train B)  x Time

432 = (x + x + 10) x 4.5

Divide both sides by 4.5.

432 / 4.5 = 2x + 10

96 = 2x + 10

Subtract 10 on both sides.

96 - 10 = 2x

86 = 2x

Divide both sides by 2.

2x = 96

x = 96/2

x = 48

Now,

x + 10 = 48 + 10 = 58

Thus,

If Train B travels 10 mph faster than Train A.

The speed of train A is 48 mph.

The speed of train B is 58 mph.

Learn more about speed here:

https://brainly.com/question/7359669

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The equation of a line in slope intercept form with slope (-2/3) and point (10,-5) is y = (-2/3) - 1.

The slope is the rate of change of y-axis with respect to x-axis.

We know that equation of a line in slope intercept form is y = mx + b.

To find the y-intercept b we will substitute the value of m and point (x,y).

∴ The equation of the line in slope intercept form with slope -2/5 and points (10,-5) is,

-5 = -(2/5)×10 + b.

-5 = -4 + b.

b = -1.

So the given equation of the line is y = (-2/3)x - 1.

learn more about slope here :

https://brainly.com/question/3605446

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Answer:

Grams

Step-by-step explanation:

Pencils are pretty light, so they should be measured in grams.

Answer:

grams :)

Step-by-step explanation:

I looked it up

Answer:

Step-by-step explanation:

y - 5 = 4(x - 7)

y - 5 = 4x - 28

y = 4x - 23

The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

The diagonal = 20 in

w = x

l = 2x + 8

Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

0 = 5x^2 + 32x - 336

Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

5x = 28

Divide both sides by 5

x = 28/5

The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

Length = 2(28/5) + 8 = 56/5 + 8 = 96/5

In conclusion,

Length = 96/5 inches

Width = 28/5

Answer:

-3x<12

/-3  /-3

x<-4

Step-by-step explanation:

Answer: Covert the mixed number to an improper fraction for them to be too simple fractions and multiply them.

Step-by-step explanation:

By multiply fraction  by a mixed fraction you will have to rewrite the mixed number as an improper fraction.

For example ,

1  1/2  is a mixed fraction. If you convert it to improper fraction, you will get 3/2 then you multiply.

Answer:

-72

Step-by-step explanation:

-32 + (2-6)(10)

-32 + (-4)(10)

-32 + -40

-72

Answer:

-72

Step-by-step explanation:

Use PEMDAS and solve from left to right.

2 - 6 = -4

Parenthesis means multiplication.

-4 x 10 = -40

Then you add the negatives.

-32 + -40 or

-32 - 40 = -72

Answer:

6

Step-by-step explanation:

10

-6

=6

Adding a negative number is simply subtraction.

10-4=6

Answer:

approximately 21 years

Step-by-step explanation:

-From the problem, we are given the equation I = Prt

-We're also given three numbers

-From that, we can determine which number should be plugged into the equation:

-The only value we are not given is t as we need to solve for this value

-Now plug all these values into the equation:

It takes approximately 21 years for the investment amount to be worth $2308.

Answer:54

4 1/2times 12

Convert 4 1/2 to an improper fraction.

9/2 times 12

Cancel the common factor of 2

9 times 6

Multiply

9 by 6 the you'll get 54

Answer:

i would say c

Step-by-step explanation:

Answer:

$29.16

Step-by-step explanation:

Each gallon of gas is $2.16.

13.5 gallons of gas is 2.16 (13.5) = $29.16.

Looks like the integral should be

[tex]\displaystyle\int\frac{x+2}{\sqrt{x+(2x+3)^2}}\,\mathrm dx[/tex]

Expand the denominator:

[tex]\displaystyle\int\frac{x+2}{\sqrt{4x^2+13x+9}}\,\mathrm dx[/tex]

Notice that

[tex]u=4x^2+13x+9\implies \mathrm du=(8x+13)\,\mathrm dx[/tex]

In order to use this substitution, expand the integral as

[tex]\displaystyle\frac18\int\frac{8x+13}{\sqrt{4x^2+13x+9}}\,\mathrm dx+\frac38\int\frac{\mathrm dx}{\sqrt{4x^2+13x+9}}[/tex]

In the first integral, use the previously mentioned substitution:

[tex]\displaystyle\frac18\int\frac{8x+13}{\sqrt{4x^2+13x+9}}\,\mathrm dx=\frac18\int\frac{\mathrm du}{\sqrt u}=\frac14\sqrt u[/tex]

[tex]=\dfrac14\sqrt{4x^2+13x+9}[/tex]

In the second integral, complete the square in the denominator:

[tex]4x^2+13x+9=4\left(x+\dfrac{13}8\right)^2-\dfrac{25}{16}[/tex]

Now substitute

[tex]x=\dfrac58\sec t-\dfrac{13}8\implies\mathrm dx=\dfrac58\sec t\tan t\,\mathrm dt[/tex]

so that

[tex]\sec t=\dfrac{8x+13}5[/tex]

Then

[tex]4x^2+13x+9=\dfrac{25}{16}(\sec^2t-1)=\dfrac{25}{16}\tan^2t[/tex]

and the integral becomes

[tex]\displaystyle\frac{\frac{15}{64}}{\frac54}\int\frac{\sec t\tan t}{\sqrt{\tan^2t}}\,\mathrm dt=\frac3{16}\int\sec t\,\mathrm dt[/tex]

[tex]=\dfrac3{16}\ln|\sec t+\tan t|[/tex]

[tex]=\dfrac3{16}\ln\left|\dfrac{8x+13}5+\dfrac{\sqrt{(8x+13)^2-25}}5\right|[/tex]

So, the integral is

[tex]\dfrac14\sqrt{4x^2+13x+9}+\dfrac3{16}\ln\left|\dfrac{8x+13}5+\dfrac{\sqrt{(8x+13)^2-25}}5\right|+C[/tex]