Question 1 of 20
What is an example of a prop that would be helpful for a presentation about
the risks of vaping?
A. A large photo of a lung damaged by vaping
B. A slide show with video of people in a vape store
C. An impassioned plea to not get addicted to vaping
D. A poster with charts showing the increase in teen vaping in the
last ten years

Answers

Answer 1

The correct answer is A. A large photo of a lung damaged by vaping. This prop would be helpful for a presentation about the risks of vaping because it would provide a visual aid to demonstrate the potential physical damage that can be caused by vaping.

Related Questions

What are the letters

Answers

Answer:

Scholastic Aptitude Test

Explanation:

according to the college board, this was the official acronym originally used for the test. The SAT dates back to 1926 and evolved from an Army IQ test. The test has not shown to be an effective means to admit students to college, however, opinions differentiate and all have their own.

what is the degree and leading coefficient of the polynomial 2u^2-u+9u^4+20u^3

Answers

The degree of the polynomial is 4, and the leading coefficient is 9.

Understanding Polynomial

Polynomial is a mathematical expression consisting of unknown variables and coefficients, which are numbers that multiply the variables.

The degree of a polynomial is the highest power of the variable present in it while the leading coefficient of a polynomial is the coefficient of the term with the highest power of the variable.

From the given question, the highest power of u is 4, so the degree of the polynomial is 4 also the term with the highest power of u is 9u^4, and its coefficient is 9. So, the leading coefficient of the polynomial is 9.

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lead your team in a conversation using 4Ds examples

Answers

The team conversation using 4Ds is given below.

What is the explanation for the above response?

Team, we have a new project ahead of us and we'll be using the 4Ds framework to guide us through the process. The first step is Define. Let's start by clearly defining the problem we're trying to solve and what our goals are for this project.

Next, we'll move on to the Discover stage. This is where we'll research and brainstorm potential solutions to the problem we've defined. We'll explore new technologies, best practices, and gather feedback from users.

Once we have a good understanding of our options, we'll move on to the Develop stage. Here, we'll select the best solution and create a prototype, test it, and iterate until we have a final product that meets our goals.

Finally, we'll move on to Deliver, where we'll launch the product to the market and monitor its success. We'll gather feedback from users and make any necessary improvements based on the data. Remember, the 4Ds framework is a powerful tool that will help us make informed decisions and take a thorough approach to problem-solving. Let's use it to our advantage.

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Hi school has 44 players on a football team that some of the players wait is given in the box plot approximately what percentage of the players Wayne less than or equal to two

Answers

Without seeing the box plot, it's difficult to provide an exact answer. However, I can explain how to interpret a box plot and estimate the percentage of players who weigh less than or equal to 200 pounds.

In a box plot, the box represents the middle 50% of the data, with the median (50th percentile) indicated by a line inside the box. The whiskers extend from the box to the minimum and maximum values within 1.5 times the interquartile range (IQR) of the box. Any data points beyond the whiskers are considered outliers.

Assuming the weight data is roughly normally distributed and there are no extreme outliers, we can estimate the percentage of players who weigh less than or equal to 200 pounds by finding the z-score corresponding to 200 pounds and using a standard normal distribution table to find the percentage of data below that z-score. The z-score can be calculated using the formula:

z = (x - μ) / σ

where x is the weight (200 pounds), μ is the mean weight, and σ is the standard deviation of the weight data.

If we assume that the mean weight is around 180-200 pounds and the standard deviation is around 20-30 pounds, then a weight of 200 pounds is around 1 to 2 standard deviations above the mean. Looking at a standard normal distribution table, we can estimate that roughly 84-98% of the data falls below a z-score of 1-2.

Therefore, approximately 84-98% of the football players weigh less than or equal to 200 pounds.

1. Which sentence can be made more readable simply by removing a phrase?
- Jefferson Avenue was crowded with loads of protestors.

-When we got home, we saw ourselves on television.

-We left the rally early because things seemed a little sketchy.

-The crowd grew quiet when the main speaker walked onstage.

Answers

Answer:

Explanation:

The sentence that can be made more readable simply by removing a phrase is:

- We left the rally early because things seemed a little sketchy.

The sentence can be shortened to "We left the rally early." This removes the unnecessary and vague phrase "because things seemed a little sketchy," which does not add any specific detail or clarity to the sentence.

How can I bust a nut with no hands???

Answers

Cracking a nut without hands can be challenging, as hands are typically used for tasks that require fine motor skills and gripping.

What is the nut about?

If you're determined to crack a nut without hands, here are a few potential methods:

Use tools: You may be able to use tools to crack a nut, such as a nutcracker, pliers, or a hammer and chisel. Place the nut in a stable position, and then use the tool to apply pressure and crack the shell.

Use body weight: If the nut is relatively small and the shell is thin, you may be able to crack it by placing it on a hard surface and using your body weight to apply pressure. For example, you can place the nut on the floor or a countertop and press down with your foot or another part of your body.

Use a hard surface: If the nut is large and the shell is thick, you can try placing it on a hard surface, such as a sidewalk or a curb, and then using force to crack it by pressing down or hitting it with another hard object.

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question
7. What element of an architectural drawing clarifies information that may not be clear on the drawing?

Answers

Note that the element of an architectural drawing that clarifies information that may not be clear on the drawing is the section view.

How is this so?

A segment view gives a glance into an item. Sections are used to explain the inner construction of a part that cannot be depicted well by concealed lines in external views. Diagonal section lines represent the chopped material.

The cutout view is analogous to the section view. While the section view displays the complete model being sliced, the cut-out view simply shows a smaller area of the model being cut. This view contributes to a reduction in the number of orthographic views in the drawing.

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One element that is commonly used to clarify information that may not be clear on the drawing is a note or annotation. A note can provide additional information about a particular aspect of the drawing, such as a material specification, a dimension, or a particular detail. This information can help to clarify the drawing and ensure that the design intent is clearly communicated.

Four transformations of the function f(x) = 3 are given below. For each transformation, drag the expression that shows the result of that transformation into the box under it. 3(-41-x) -4 f(x) -4x32 DRAG AND DROP AN ITEM HERE 3(x-4) f(-4x) 32 - 4 DRAG AND DROP AN ITEM HERE --- 3 -4x 1.32 od f(x-4) DRAG AND DROP AN ITEM HERE A -6 -4 -2 8- 6- 4 Ax) 2- -2- -6- -8- 1(x)=3* 2 4 6 CLEAR f(x) - 4 CHECK DRAG AND DROP AN ITEM HERE

Answers

Transformation of a function is a alteration in its formula that impacts its appearance and positioning on a Cartesian plane.

How to explain the function

Modifications incurred onto the horizontal aspect of a function happen when an adjustment is produced for its parameter (the x-value). Several common horizontal transformations consist of:

Translation: Subtracting or adding a definitive value to the input of the equation shifts the chart either right or left respectively.

Reflection: Replacing the sign of the input of the function reflects the graph across the y-axis. As an example, if we have a function f(x), the new one will be depicted as f(-x), which mirrors the visual along the y-axis.

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